If you flip three fair coins, what is the probability that you'll get at least two heads?
Answer:
1/8
Step-by-step explanation:
I've done this before.
Select the correct answer.
Which limit does not exist?
Answer:
B
Step-by-step explanation:
(look up limit calculator)
a has a limit
b does not exist
c has a limit
d has a limit
e has a limit
Option D is correct one. Limit doesn't exist for [tex]\lim_{x\to \ 2} \frac{x^{2}-6x +8 }{x-2}[/tex].
When a limit is said to be exist?
The limit of f(x) at x = a is said to be exist if the function approaches the same value from both the sides i.e. LHL =RHL (left hand limit = right hand limit)
According to the question we have,
A. [tex]\lim_{x \to \ 1} \frac{2-x}{x+1}[/tex]
at x =1
LHL = [tex]\lim_{h \to \ 0 } \frac{2- (1-h)}{(1-h)+1}[/tex] = [tex]\frac{1}{2}[/tex]
RHL = [tex]\lim_{h \to \0} \frac{(2-(1+h) }{(1+h)+1)} =\frac{1}{2}[/tex]
Here, RHL = LHL
Hence, limit exist.
B. [tex]\lim_{x \to \ 2} \frac{x^{2} -8}{x-2}[/tex]
at x =2
LHL = [tex]\lim_{h \to \ 0} \frac{(2-h)^{2}-9 }{(2-h)-2}[/tex] =[tex]\lim_{h \to \ 0} \frac{4+h^{2} -9-4h}{2-h-2}[/tex] = [tex]\lim_{h \to \ 0 }\frac{2h-4}{-1} =\frac{-4}{-1} =4[/tex]
RHL = [tex]\lim_{h \to \ 0} \frac{(2+h)^{2} -9}{(2+h)-2}[/tex] = [tex]\lim_{h \to \ 0} \frac{4h +4 +h^{2}-9 }{h} = \lim_{h \to \ 0} \frac{2h+4}{1}[/tex]=4
Here, RHL = LHL
Hence, the limit exist.
C. [tex]\lim_{x \to \ 1} (x^{2} -2x-5)[/tex]
at x =1
LHL = [tex]\lim_{h \to \ 0} (( 1-h)^{2} -2(1-h)-5)= \lim_{h \to \ 0} (1 -2-5)=-6[/tex]
RHL = [tex]\lim_{h \to \ 0} ((1+h)^{2} -2(1+h)-5) = (1-2-5)=-6[/tex]
Here, LHL = RHL = -6
Hence, the limits exist.
D. [tex]\lim_{x \to \ 2} \frac{x^{2}-6x + 8 }{x - 2}[/tex]
at x =2
LHL = [tex]\lim_{h \to \0} \frac{(2-h)^{2} -(2-h)+8}{(2-h)-2} = \lim_{h \to \ 0} \frac{4+h^{2}-4h-2+h+8 }{(2-h)-2}[/tex] =[tex]\lim_{h \to \ 0} \frac{2h-4+1}{1} =-3[/tex]
RHL = [tex]\lim_{h \to \ 0} \frac{(2+h)^{2} -(2+h) +8}{(2+h)-2} = \lim_{h \to \ 0} \frac{4+h^{2}+4h -2-h+8}{h} = \lim_{h \to \ 0} \frac{2h+4-1}{1} =3[/tex]
Here, RHL≠LHL
Hence, the limit doesn't exist.
E. [tex]\lim_{x \to \ 3} (x^{2} -3x-1)[/tex]
at x = 3
LHL = [tex]\lim_{h \to \ 0} ((3-h)^{2} -3(3-h)-1)[/tex] = [tex]9-9-1=-1[/tex]
RHL= [tex]\lim_{h \to \ 0} ((3+h)^{2} -3(3+h)-1)= 9-9-1 =-1[/tex]
Here, RHL = LHL
Hence, the limit exist.
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Which number is prime?
58
74
84
41
Emily is a pharmacist. She earns $45.80 per hour. If she works on a holiday, she gets paid double the
hourly rate. Last week she worked for 38 hours and 8 of those hours on a holiday. Emily's salary is her only
source of income.
If her net income was $1,783.62, then how much was her payroll tax?
Her payroll tax was $
Write the polynomial in standard form.
8g- 9g3 +4g2 - 10
a. 9g3+4g2 + 8g - 10
B.-10 + 8g + 4g2 -9g3
c. 4g3 -9g2 + 8g - 10
d: 9g3 +4g2 + 8g - 10
Number 3
Soccer
Enter the ratio of hockey players to soccer players in the form and then as a decimal showing up to four
decimal places. Tell whether the decimal is a terminating or a repeating decimal.
10
The ratio is
The decimal form is
The decimal is terminating
Answer:
Ratio: [tex]=\mathbf{\frac{6}{11}}[/tex]
The decimal form (showing up to four decimal places): 0.5454
The decimal is a repeating decimal i.e 0.54545454..
Step-by-step explanation:
We need to find ratio of hockey players to soccer players
Number of players playing Hockey= 6
Number of players playing Soccer = 11
Ratio: [tex]\frac{Hockey\:Players}{Soccer\:Players} =\mathbf{\frac{6}{11}}[/tex]
The decimal form (showing up to four decimal places): 0.5454
Tell whether the decimal is a terminating or a repeating decimal.
The decimal is a repeating decimal i.e 0.54545454..
PLEASE HELP IF YOU ANSWER CORRECTLY I WILL GIVE BRAINLYIST (sorry if I spelled it wrong) BUT PLEASE ANSWER FAST!
Answer:
The first option
Step-by-step explanation:
Answer:
1st one
Step-by-step explanation:
Opposite of positive 3 is negative 3.
Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the correct position in the answer box. Release your mouse button when the item is place. If you change your mind, drag the item to the trashcan. Click the trashcan to clear all your answers.
Prove: The segment joining the midpoints of the diagonals of a trapezoid is parallel to the bases.
Slopes are equal; therefore, segments are parallel
The segment joining the midpoints of the diagonals of a trapezoid is parallel to the bases
How to prove: The segment joining the midpoints of the diagonals of a trapezoid is parallel to the bases?From the figure, we have the following coordinates
B = (a, 0)
D = (d, c)
The midpoint of line segment BD is calculated as
BD = 1/2 * (x1 + x2, y1 + y2)
So, we have
BD = 1/2 * (a + d, 0 + c)
This gives
BD = ((a + d)/2, c/2)
Also, we have:
Lines MN and AB are horizontal lines
This means that they have a slope of 0
i.e.
Slope of AB = Slope of MN = 0
Parallel lines have equal slope
Hence, the segment joining the midpoints of the diagonals of a trapezoid is parallel to the bases
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1 and 1/4 - 1/3=
please give the right answer
Answer:
11/12
Step-by-step explanation:
15/12-4/12= 11/12
Answer:
11/12
Step-by-step explanation:
5/4 -1/3 first make the equation easier to look at so take the 1 and add it as 4/4
15/12-4/12 then make the bottom the same with multipulcation and tops are multiples as well
11/12 subtract
help me please i need help
Answer: yes they are equivalent
Step-by-step explanation: When you distribute both equations, you end up with 5m-10.
write down the relation between mass and inerti
Answer:
The mass of an object is directly proportional to its inertia.
[tex]m\alpha I[/tex]
Where
m = mass
I = inertia
Step-by-step explanation:
We can first of all start by defining the two key terms present here - mass and inertia.
The mass of an object is the quantity of matter contained in the object.
The inertia of an object is the resistance of an object which is in a state of rest to motion
The mass of an object is directly proportional to its inertia.
The heavier an object is, the more inertia it has. To put things into perspective, you can easily push a bicycle because it does not really have a lot of mass, as opposed to pushing an eighteen-wheeler trailer.
Find three consecutive
integers whose sum is 351
Help please
Answer:
116, 117, 118
Step-by-step explanation:
Consecutive numbers are numbers that come after each other, such as 1, 2 and 3.
Find the expressions for the integers:
Let the smallest integer be x.
2nd integer= x +1
3rd integer= x +1 +1= x +2
Form an equation:
x +x +1 +x +2= 351
Solve for x:
3x +3= 351
3x= 351 -3
3x= 348
x= 348 ÷3
x= 116
Find the other 2 integers:
2nd integer= 116 +1= 117
3rd integer= 117 +1= 118
Hence, the three consecutive integers are 116, 117 and 118.
Calculate the product below and give your answer in scientific notation.
(3.3 x 10-4) × (8.0 × 10⁰) = ?
X
Answer:
goood luccccccckkkk...
During a basketball game, Kevin made a total of 14 shots. Each basketball shot is worth either 2 points or 3 points. Kevin scored a total of 34 points. Let a represent the number of 2 point shots and let y represent the number of 3 point shots.
Answer:
following is the answer for your question this can be done in the manner
WILL GIVE BRAINLIEST IF CORRECT!!
Coco flips a penny, a nickel, and a quarter. Each coin is fair (meaning that heads and tails are equally likely to come up). What is the probability that at least one of the coins comes up heads?
Enter your answer as a fraction in simplified form.
Answer:
7/8
Step-by-step explanation:
Using the binomial distribution, it is found that there is a [tex]\frac{7}{8}[/tex] probability that at least one of the coins comes up heads.
What is the binomial distribution formula?The formula is:
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
The parameters are:
x is the number of successes.n is the number of trials.p is the probability of a success on a single trial.In this problem:
A coin is fair, hence p = 1/2.Three coins are thrown, hence n = 3.The probability that at least one of the coins comes up heads is given by:
[tex]P(X \geq 1) = 1 - P(X = 0)[/tex]
In which:
[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]
[tex]P(X = 0) = C_{3,0}.\left(\frac{1}{2}\right)^{0}.\left(\frac{1}{2}\right)^{3} = \frac{1}{8}[/tex]
Then:
[tex]P(X \geq 1) = 1 - P(X = 0) = \frac{8}{8} - \frac{1}{8} = \frac{7}{8}[/tex]
[tex]\frac{7}{8}[/tex] probability that at least one of the coins comes up heads.
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Four positive whole numbers add up to 93
One of the numbers is a multiple of 19
The other three numbers are equal.
Write the four numbers in ascending order.
Answer:
Let the numbers be a, b, c, d
[tex] { \tt{a + b + c + d = 93}}[/tex]
Let a be the multiple of 19, a = 57
And b = c = d
[tex]{ \tt{57+ 3b= 93}} \\ { \tt{3b = 36}} \\ { \tt{b = 12}}[/tex]
[tex]{ \tt{a = 57}} \\ { \tt{b = c = d = 12}} \\ \\ { \boxed{ \rm{12}}} \: \: { \boxed{ \rm{12}}} \: \: { \boxed{ \rm{12}}} \: \: { \boxed{ \rm{57}}}[/tex]
Answer:
12, 12, 12, 57
Step-by-step explanation:
Given:
Four positive whole numbers add up to 93.One of the numbers is a multiple of 19.The other three numbers are equal.If one of the four numbers is a multiple of 19 and the other three numbers are equal, then the sum of the other three numbers will be a multiple of 3.
Multiples of 19:
19, 38, 57, 76, 95, ...
Subtract each multiple of 19 (that is less than 93) from 93:
⇒ 93 - 19 = 74 → not divisible by 3
⇒ 93 - 38 = 55 → not divisible by 3
⇒ 93 - 57 = 36 → divisible by 3
⇒ 93 - 76 = 17 → not divisible by 3
The only result that is a multiple of 3 is 36.
Therefore, the multiple of 19 is 57.
To find the other three numbers, simply divide the result of the total less the found multiple of 19 by 3:
⇒ (93 - 57) ÷ 3 = 36 ÷ 3 = 12
Therefore, the four numbers in ascending order are:
12, 12, 12, 57
Step sis need a new dryer. Her thicc ahss couldn't fit
Answer:
HAHAHAHH
Step-by-step explanation:
Find the of the slope of the line through (6,-10) and (4,-8)
Answer:
-1
Step-by-step explanation:
y = mx + c
m is the slope/gradient
to find slope = y2 - y1 / x2 - x1
= -8 - -10 / 4 - 6
m = -1
ill give brainlest help please
Answer:
it's c i did this a week ago
you add all the prime numbers between 2 and 33 and then multiply it by itself what you get?
Answer:
24964
Step-by-step explanation:
hope this works : ) - btw this is not including 2 and 33
What is the next fraction in this sequence? 2/477, 2/159, 2/53, 6/52
Answer:
9/26
Step-by-step explanation:
2/159÷2/477=2/53÷2/159=6/52÷2/53=3
x÷6/52=3
x=18/52
x=9/26
Name a point on this line.
y + 2 = 3(x – 4)
Question 3 options:
(4,-2)
(-2,4)
(2,-4)
(-4,2)
Two numbers each have one decimal place. Is it possible for their product to be a whole number? Explain.
Answer: No.
Step-by-step explanation: Unless the tenth place is a 0, a product of a 2 numbers with 1 decimal place cannot have a product for a whole number, even if you went on forever.
When two decimal places add up to one whole, the total of the two decimal places is a whole number. The addition of relocating the decimal point after the multiplication when multiplying decimals is the only difference between multiplying whole numbers and multiplying decimals.
What does the decimal number system mean?The accepted method for representing both integer and non-integer numbers is the decimal numeral system. It is the expansion of the Hindu-Arabic numeral system to non-integer values. Decimal notation is the term used to describe the method of representing numbers in the decimal system.A decimal is a number that is divided into two parts: a whole and a fraction. Between integers, decimal numbers are used to express the numerical value of complete and partially whole quantities.Decimals are numbers that have two components, a whole number component and a fractional component, which are separated by a decimal point. 12.5 is a decimal number, for instance.In mathematics, the decimal system—also known as the Hindu-Arabic number system or the Arabic number system—is a positional numeral system that uses 10 as its base and calls for the use of 10 different numbers, including 0, 1, 2, 3, 4, 5, 6, 7, and 8. To indicate decimal fractions, a dot (decimal point) is also necessary.To learn more about decimal refer to:
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In 2000, the enrollment at a college is 20,700 students. Each year, the enrollment decreases by 300 students. Let f(t) represent the enrollment at t years since 2000. Find an equation for f.
I will give Brainliest!!!!
Answer:
f(t) = -300t + 20,700
Step-by-step explanation:
2000 is the starting year, so 20,700 is our y-intercept or our constant.
Each year, represented by t, student enrollment decreases by 300. This is the slope of the equation.
diameter of the circle whose radius is given
a) 3.5cm
what 1/4 in index form?
Answer:
Step-by-step explanation:
4^-1
Sidney took a cash advance of $150 by using checks linked to her credit card account. The bank charges a cash advance fee of 2 percent on the amount borrowed and offers no grace period on cash advances. Sidney paid the balance in full when the bill arrived.
The cash advance fee for the credit card account is $3.00
What is the basis for computing cash advance fee?
The basis for determining the cash advance fee is on the amount borrowed not that 2% is charged annually on the credit card account, in other words, the cash advance fee in this case is the cash advance multiplied by the advance fee of 2% as shown explicitly below:
cash advance fee=cash advance*cash advance fee %
cash advance=$150
cash advance %=2%
cash advance fee=$150*2%
cash advance fee=$3.00
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Full question:
Sidney took a $150 cash advance by using checks linked to her credit card account. The bank charges a 2 percent cash advance fee on the amount borrowed and offers no grace period on cash advances. Sidney paid the balance in full when the bill arrived.
What was the cash advance fee? (Round your answer to 2 decimal places.)
Decide whether the relation is a function:
{(-3, 7), (1, -8), (6, -6), (7-8), (12, 2)}
Answer:
It is a function
Step-by-step explanation:
A function is of the form:
[tex]\left[\begin{array}{c}x_1&x_2&x_3\\-&-&-\\x_n\end{array}\right][/tex] [tex]\left[\begin{array}{c}y_1&y_2&y_3\\-&-&-\\y_n\end{array}\right][/tex]
Where each of the x values must be distinct.
The x values are referred to as domain while the y values are called range.
Having said that, the given data can be represented as follows:
[tex]\left[\begin{array}{c}-3&1&6\\7&12\end{array}\right][/tex] ----------- [tex]\left[\begin{array}{c}7&-8&-6\\-8&2\end{array}\right][/tex]
From the representation above, none of the x values are repeated.
Hence, it is a function
Part A: A graph passes through the points (0, 2), (2, 6), and (3, 12). Does this graph represent a linear function or a non-linear function? Explain your answer in words.
Part B: Write one example of a linear function and one example of a non-linear function. (Use x and y as the variables) (10 points)
Answer:
Step-by-step explanation:
Part A: No. The line would have to be straight in order for the graph to be linear.
Part B:
Linear: y=2x-4.
Nonlinear: y=x^2-6.
please help me? :( I really need it!
Answer:
D
Step-by-step explanation:
Answer:
D
Step-by-step explanation: