PLEASE HELP ME!!!!!Invasive species spread to new environments by all of the following ways except through
A. Cargo ships
B. Wood products
C. Pet trade
D. Quarantine
E. Ornamental plants

Answer:

Decimal: -0.5

Fraction: - 1/2

Step-by-step explanation:

Answer:

i think -50

Step-by-step explanation:

im not 100% sure tho

The value of x = 2, the length of AB is 13 and BC is 8.

A, B and C are collinear with point B between points A and C.

   A___________.__________C

                             B

AC = 21 , AB = 15 -x and BC = 4 + 2x

As the point, B is the mid-point of the line AC

Therefore we get

AC = AB + BC

AC = 2AB = 2BC

Therefore we get

AC = AB + BC

21 = 15 -x + 4 + 2x

21 = 19 + x

x = 2

As AB = 15 - x

Now put the value of x in the equation, by putting the value of x = 2.

AB = 15 - 2

    = 13

BC = 4 + 2x

     = 4 + 2×2

     = 4 + 4

     = 8

Therefore the value of x = 2, and the length of AB = 13 and BC = 8.

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Answer:

we can't see the words clearly

Step-by-step explanation:

Answer:

chance of wanted outcome/all possible outcomes

Step-by-step explanation:

Answer:

4.

.....................

Answer: Option 4

Step-by-step explanation:

2x+5y=20

5y=-2x+20

y=-2x/5 + 4 ==> y-int: (0, 4) ==> Option 4

The percentage of the surface light :

[tex]\frac{I}{I_0} \times 100=27.25 \%[/tex]

[tex]$\frac{I}{I_0} \times 100=7.43 \%$[/tex]

This is further explained below.

Generally, the equation for is  mathematically given as

We have; the intensity of light d ft below the surface given by

I=I_0 [tex]e^{-0.26 d}[/tex]

Where; I_0= Intensity of the light at the surface.

d= depth (in feet).

A)

d=5 \mathrm{ft}:

[tex]\quad I=I_0 \cdot e^{-0.26 \times 5} \\\\I=I_0 \times e^{-1 \cdot 30}$[/tex]

[tex]$\left(\frac{I}{I_0}\right)=e^{-1.30}=0.27253[/tex]

In of form:

[tex]\frac{I}{I_0} \times 100=27.25 \%[/tex]

b)

[tex]$d=10 \mathrm{ft}:[/tex]

[tex]\quad \mathrm{J}=\mathrm{I}_0 e^{-0.26 \times 10}\\\\=I_0 e^{-2.60}$[/tex]

[tex]$\left(\frac{I}{I_0}\right)[/tex]=e^{-2.60}

[tex]$\left(\frac{I}{I_0}\right)[/tex]=0.07427

In form: [tex]$\frac{I}{I_0} \times 100=7.43 \%$[/tex]

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CQ

Marine life is dependent upon the microscopic plant life that exists in the photic zone, a zone that goes to a depth where about 1% of the surface light remains. In some waters with a great deal of sediment, the photic zone may go down only 15 or 20 feet. In some murky harbors, the intensity of light d feet below the surface is given by I=Ioe^-0.26d,Where Io is the intensity of light at the surface. What percentage of the surface light will reach a depth of (A) 5 feet? (B) 10 feet?

Answer:

Step-by-step explanation:

25.

x + 2x -75 = 90

3x = 90+75

3x = 165

x = 55

Measure of A = 55

Measure of B = 2(55) - 75 = 110 - 75 = 35

28.

2x+10-x+55 = 90

x = 90-65

x = 25

measure of A = 2(25) +10 = 60

measure of B = -25+55 = 30

31.

2x+3+3x - 223 = 180

5x -220 = 180

5x = 400

x = 80

measure of A = 163

measure of B = 17

32.

-4x+40+x+50 = 180

-3x +90 = 180

-3x = 90

x= -30

measure of A = -4(-30) +40 = 160

measure of B = -30+50 = 20

Answer:

x =23

Step-by-step explanation:

ok first, the full degree of a straight line is 180°

subtract 38° out of 180°

180-38= 142

so 6x+4= 142°

subtract 4 from both sides of the equation

6x +4 -4= 142-4

6x=138

divide 6 from 6x and 138

x=23

Answer:

property of equality that justifies the missing step is Division property of equality

Step-by-step explanation:

We need to Identify the property of equality that justifies the missing step

[tex]28=4x-8\\28+8=4x\\36=4x[/tex]

Now, we divide both sides by 4 using division property of equality as it states that [tex]\frac{a}{c}=\frac{b}{c}[/tex]

[tex]\frac{36}{4}=\frac{4x}{4}\\9=x[/tex]

So, The property of equality that justifies the missing step is Division property of equality

Answer:

AD = 100

Step-by-step explanation:

50/cos60 = 100

Answer:

Answer is 261

Step-by-step explanation:

You have to plug in the number into the variable.

* 3(-3-6)^2 -(-3) (6)

> 3(-9)^2 +3 (6)

> 3(81) + 18

> 243 + 18

> 261

I hope this is the right answer.

Answer:

of course

Step-by-step explanation:

On the surface, it seems easy. Can you think of the integers for x, y, and z so that x³+y³+z³=8? Sure. One answer is x = 1, y = -1, and z = 2. But what about the integers for x, y, and z so that x³+y³+z³=42?

That turned out to be much harder—as in, no one was able to solve for those integers for 65 years until a supercomputer finally came up with the solution to 42. (For the record: x = -80538738812075974, y = 80435758145817515, and z = 12602123297335631. Obviously.)

Answer: The answer is everytime you mutiply in by 0.6

Step-by-step explanation:

Answer:

-2 3/4

Step-by-step explanation:

i gotchu

Answer:

Do you have any numbers?

Answer:

See below

Step-by-step explanation:

Anything with an ODD number of negatives  makes a negative

A   TWO negatives <<<<nope

B   two negatives

C    FIVE negatives   <<<<< yep

D    Three negatives  <<<<<< yep

E     Four negatives <<<<< nope

Remember ....a negative sign in front

                            - (6)(-4)(3)       is just like  (-1)(6)(-4)(3)

Answer:

SAS Translation

Step-by-step explanation:

The triangle just moved over, it didn't rotate or flip.

[tex] \Large{\boxed{\sf x = 4}} [/tex]

[tex] \\ [/tex]

Solving this equation means finding the value of 'x' that makes the equality true.

[tex] \\ [/tex]

Given equation:

[tex] \sf -12 + 5x - x = x - 7 + 7 [/tex]

[tex] \\ [/tex]

Combine like terms:

[tex] \sf -12 + (5x - x) = x + (-7 + 7) \\ \\ \sf -12 + 4x = x [/tex]

[tex] \\ [/tex]

Now, we move the variables to the right side of the equation by subtracting 4x from both sides:

[tex] \sf -12 + 4x - 4x = x - 4x \\ \\ \sf -12 = -3x [/tex]

[tex] \\ [/tex]

Finally, divide both sides of the equation by the coefficient of the variable, -3:

[tex] \sf \dfrac{-12}{-3} = \dfrac{-3x}{-3} \\ \\ \\ \boxed{\boxed{\sf x = 4}} [/tex]

[tex] \\ \\ [/tex]

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Answer:

X:1 2 3 4 5 Y:7 11 15 19 23.

Step-by-step explanation:

We just need to put in the values of x into the equation: y = 4x + 3.

x = 1:

y = 4(1) + 3

  = 4 + 3

y = 7

x = 2:

y = 4(2) + 3

  = 8 + 3

y = 11

x = 3:

y = 4(3) + 3

  = 12 + 3

y = 15

x = 4:

y = 4(4) + 3

  = 16 + 3

y = 19

x = 5:

y = 4(5) + 3

  = 20 + 3

y = 23

Answer:

approximately glof glorf hundred

Step-by-step explanation:

if u subtract eighty from gloof glife you get glof glorf hundred

Step-by-step explanation:

There are 11 prime numbers : 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31

Answer:−589.86

Step-by-step explanation:

let unknown number be x

Solve for x

655.4+x=65.54

Subtract 655.4 from both sides.

x=65.54−655.4

Subtract 655.4 from 65.54 to get −589.86.

x=−589.86

The CD will earn $459.375 interest in 30 months and the balance at maturity will be $10,959.375.

Here, we are given that Ralph deposited $10,500 in an CD account that pays 1.75% simple interest for 30 months.

Simple interest can be calculated using the following formula-

Simple interest = Principle(P) × Time(t) × Rate(r)/ 100

Here,

P = 10,500

t = 30/12

r = 1.75

Thus,

Simple interest = 10,500 × 30/12 × 1.75/ 100

= 10,500 × 5/2 × 175/ 10000

= 10,500 × 5/2 × 7/ 400

= 26,250 × 7/ 400

= $459.375

Thus, the CD will earn $459.375 interest in 30 months.

Balance on maturity will be-

$10,500+ $459.375 = 10,959.375

Thus, the balance at maturity will be $10,959.375.

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Answer:

I believe you cancel out values if there are the same ones for the numerator and dominator.

For example:

[tex]\frac{x^4+x^2+x-3}{x^4+x^3-3}[/tex]

Since both the numerator and dominator have [tex]x^4[/tex] and -3, you are able to cancel them out.

This would leave you with [tex]\frac{x^2+x}{x^3}[/tex]

Notes: the exponents have to be the same number in order to cancel out the values.

Answer:

  11.  C) x +1

  12.  B) x -1

Step-by-step explanation:

You want the simplified form of a couple given rational expressions.

Each of the polynomials can be factored by pairs. Common factors can be cancelled.

Factoring numerator and denominator pairwise, we have ...

  [tex]\dfrac{x^3+2x^2-x-2}{x^2+2x-x-2}=\dfrac{x^2(x+2)-1(x+2)}{x(x+2)-1(x+2)}=\dfrac{(x^2-1)(x+2)}{(x-1)(x+2)}\\\\=\dfrac{x^2-1}{x-1}=\dfrac{(x+1)(x-1)}{(x-1)}=\boxed{x+1}[/tex]

Factoring the numerator pairwise,, we have ...

  [tex]\dfrac{x^5-x^4+x^3-x^2+x-1}{x^4+x^2+1}=\dfrac{x^4(x-1)+x^2(x-1)+1(x-1)}{x^4+x^2+1}\\\\=\dfrac{(x^4+x^2+1)(x-1)}{(x^4+x^2+1)}=\boxed{x-1}[/tex]

Answer:

both equations are the same

Step-by-step explanation:

please look at the images

Answer:

1 / 3 is the answer

hope this answer will help you.

have a great time

Answer:

1/3

Step-by-step explanation:It's pretty easy, if you look, there is only three(3)

boxes, and one of them is shaded. Soo, you can do that you can solve this question!!!

Answer:

There are 12 combinations.

Step-by-step explanation:

Options:

1. Silver or Leather

2. Cat or Dog

3. Basketball, baseball, or soccer

Now we need to multiply the options together, so 2 × 2 × 3 = 12.

Answer:48

Step-by-step explanation: