PLEASE HELP ME WITH THESE!!!

Using a subtraction operation, the overall temperature change over those five days that Joe tracked the temperature in his town was a decrease of 3°C.

The temperature change can be computed by determining the differences in temperature from one day to the next and summing the differences.

The temperature change can also be computed by finding the difference between the ending period's temperature and the beginning period's temperature.

Days         Temperature     Change

Monday          23°C                  0

Tuesday          14°C (23 - 9)    -9

Wednesday    21°C (14 + 7)    +7

Thursday       25°C (21 + 4)    +4

Friday            20°C (25 - 5)    -5

Overall change =                  -3°C

= 20°C - 23°C = -3°C

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The polynomial 4 · x³ is a monomial of degree 3.

In algebra there are two types of numbers: constants and variables. Constants are constant real numbers, while variables are real numbers that may represent more than a real number.

Polynomials are the result of combination of constants, variables and fundamental operators (addition, multiplication) and can be classified according to the number of terms:

Monomial - Polynomial with one term.

Binomial - Polynomial with two terms.

Trinomial - Polynomial with three terms.

Polynomial - Polynomial with four or more terms.

The grade of the polynomial is the maximum power that accompany a term in a polynomial in standard form. Then, we can bring an example of polynomial with a degree 3 below:

p(x) = 4 · x³

This is a monomial (polynomial with one term) with degree 3.

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[tex]\huge\text{Hey there!}[/tex]

[tex]\mathsf{3.5 + (1 + 4)\times (6.5 + 1.5)}\\\mathsf{1 + 4 = \bf 5}\\\mathsf{6.5+1.5=\bf 8}\\\mathsf{3.5+5\times8}\\\mathsf{5\times8=\bf 40}\\\mathsf{3.5+40}\\\large\text{= \bf 43.5}[/tex]

[tex]\boxed{\boxed{\large\textsf{Answer: \huge \bf 43.5}}}\huge\checkmark[/tex]

[tex]\large\textsf{Good luck on your assignment and enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

Answer: try 5 it is most likly right

Step-by-step explanation:

N/A

On solving the provided question, we can say that - the value of the following polynomial will be 3x^2 = 5 => x^2 = 5/3

A polynomial is a mathematical statement made up of coefficients and uncertainty that exclusively uses additions, subtractions, multiplications, and positive integer powers of variables. A single indeterminate x polynomial is represented by the expression x2 4x + 7. A polynomial is an expression in mathematics that consists of variables (sometimes referred to as indeterminates) and coefficients that may be added, subtracted, multiplied, and raised to negative integer powers of non-variables. A polynomial is an algebraic expression made up of coefficients and variables. The only operations that an expression can contain are addition, subtraction, multiplication, and non-negative integer exponents. These expressions are known as polynomials.

here,

[tex]3x^{-2}-5[/tex]

3x^2 = 5

x^2 = 5/3

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Answer:

4n - 16.

Step-by-step explanation:

nth term = a1 + d(n-1)

= -12 + 4(n - 1)

= -12 + 4x + 4*-1

= -12 + 4x - 4

= 4n - 16,

Answer:

0.0208

Step-by-step explanation:

Using the formula for calculating margin of error is expressed as;

M = z * √p(1-p)/n

z is the z score at 90 % interval

p is the proportion

n is the sample size

p = 0.2

n = 1000

z = 1.645

M = 1.645 * √0.2(1-0.2)/1000

M = 1.645 * √0.2(0.8)/1000

M = 1.645 *  0.01264

M = 0.0208

Hence the margin of error is 0.0208

The data represented by the steam-leaf plot is 115, 138, 145, 145, 156, 166, 168, 168, 175, and 187.

A stem and leaf plot, also known as a stem and leaf diagram, is a way to arrange data so that it is simple to see how frequently various sorts of values occur. It is a graph that displays ordered numerical data. A stem and a leaf are divided into each piece of data.

A stem and leaf plot is shown as a customized table with the first or final digit of each data value divided into a stem and the remaining digit in a leaf.

9 I 0 ⇒ 9 on the stem and 0 on the leaf read as 90.

Given, A stem leaf plot and the leaf represents the tens digit.

As the leaf represents tens digits the data set can be represented by,

115, 145, 145, 175, 156, 166, 187, 138, 168, 168.

Representing the data set in ascending order we have,

115, 138, 145, 145, 156, 166, 168, 168, 175, 187.

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Answer:

6 is the correct answer

Step-by-step explanation:

If you distribute you will get 4-3+5

Which is equal to 6

the answer is 12

I just took the test and the hypotenuse is always 2 times the smaller leg

Answer:

Area of trapezoid:

12 + 6<-- your two bases of the trapezoid = 18

18 x 4 = 72, 72 divided by 2 = 36

now we multiply by 2 since there are 2 trapezoids:

36 x 2 = 72

Area of rectangle in front:

6 x 3 = 18

Area of the 2 rectangles on the sides:

5 x 3 = 15

(multiply by 2 since there are two rectangles on both sides)

15 x 2 = 30

Area of rectangle on the back:

12 x 3 = 36

Now lets add up all the areas:

72 + 18 + 30 + 36 = 156 in2 is your answer.

Answer:

3√6

Step-by-step explanation:

[tex]\sqrt{54} =\sqrt{9*6}=\sqrt{9} *\sqrt{6}=3*\sqrt{6} =3\sqrt{6}[/tex]

Answer:

3/6 i cant use the weird symbol bc my keyboard

Step-by-step explanation:

Answer:

87.5%

Step-by-step explanation:

350 ÷ 400 = 0.875 = 87.5%

Answer:

350 is 87.5% or 7/8 of 400.

(Hope this helps! Btw, I answered first. Brainliest please!! :D)

Answer:

2. (8, 5) and (2,9)

3. I don’t know how to show this to you.

Answer:

Step-by-step explanation:

Answer:

0.910

Step-by-step explanation:

since it'snot perfect it can't be one and since it a positive slope it is 0.9102.

Answer:

Step-by-step explanation:

h(t)=16t²+144t +4

=16(t²+9t+(9/2)²)-16(9/2)²+4

check your problem statement.

Answer:

last one

Step-by-step explanation:

Answer:

Melanie get $1

Step-by-step explanation:

let the money that Melanie gets be x

4.1:20.5=x:$5.00

4.1/20.5=x/$5.00

20.5x=4.1*$5.00

x=$20.5/20.5

x=1

therefore,Melanie will get $1

The number of students at the open house is B. 468.

A fraction is written in the form of p/q, where q ≠ 0.

Fractions are of two types they are proper fractions in which the numerator is smaller than the denominator and improper fractions where the numerator is greater than the denominator.

We know if a and b are two quantities in a total quantity (ax + bx) the amount of a single quantity can be obtained by [a/(a+b)]× (ax + bx).

Given, The ratio of students to adults at the open house is 9 : 7 and the total number of students and adults at that place is 832.

Therefore,

The number of students is,

= (9/9+7)×832.

= (9/16)×832.

= 9×52.

= 468.

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Need photo of the segment.

The central theme of Arachne is human limitation and hubris.The center of the ellipse is located midway between the foci .

The center of the ellipse is located midway between the foci. The minor axis is the line segment going through the center and perpendicular to the major axis, with both endpoints on the ellipse. The length of the ellipse's major axis is equal to the bigger of 2a or 2b, while the length of its minor axis is equal to the smaller. The major axis, which is the largest distance between any two points on the ellipse, is the line that connects both foci and runs from one end to the other. The minor axis, which is the shortest path between two points on the ellipse, is the line that passes through the center of the major axis in a perpendicular direction.

given

The central theme of Arachne is human limitation and hubris. Arachne, a young girl who is a remarkably gifted weaver, thrives on the adulation of her customers.

As a result of her youth and inexperience as well as her awareness of her exceptional talents, Arachne eventually boasts that her weaving is even greater than Athena's.

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9514 1404 393

Answer:

Step-by-step explanation:

The external angle at A is half the difference of the arcs it intercepts. The inscribed angle y is half the measure of arc CD. The sum of the arcs of a circle is 360°. These relations let us write some equations.

  (BC -x°)/2 = ∠A

  BC + CD + x° = 360°

  y° = CD/2

__

Given that BC = 120° and ∠A = 20°, we can use the first equation to find x.

  (120 -x)/2 = 20

  120 -x = 40 . . . . . multiply by 2

  120 -40 = x = 80 . . . . add x-40

Using known values in the second equation gives ...

  120 +CD +80 = 360

  CD = 160 . . . . . . . subtract 200

Then y is found from the third equation.

  160/2 = y = 80

Answer:

To find Q1, Q2, Q3, and the interquartile range (IQR) of a data set, we need to first arrange the data in numerical order. For the given data set, the ordered data is:

7, 8, 10, 12, 12, 14, 15, 15, 16, 19, 21, 23, 24

To find Q1, we need to find the median (Q2) of the lower half of the data. The lower half of the data is:

7, 8, 10, 12, 12, 14

There are 6 values in the lower half of the data, so the median (Q2) is the average of the 3rd and 4th values, which is (10 + 12) / 2 = 11. Therefore, Q1 = 11.

To find Q3, we need to find the median (Q2) of the upper half of the data. The upper half of the data is:

15, 15, 16, 19, 21, 23, 24

There are 7 values in the upper half of the data, so the median (Q2) is the fourth value, which is 19. Therefore, Q3 = 19.

To find the IQR, we need to subtract Q1 from Q3. The IQR is equal to Q3 - Q1 = 19 - 11 = 8.

The correct answers are:

1.  Interquartile Range = 8

2.  Q3 = 19

3.  Q2 = 11

4.  Q1 = 8

Therefore, the correct answer choices are:

a. 15 (incorrect)

b. 9 (incorrect)

c. 20 (incorrect)

d. 11 (correct)

Answer:

The probability of choosing a professor or an instructor is 47.22%.

Step-by-step explanation:

Given that the mathematics faculty at a college consists of 11 professors, 12 associate professors, 7 assistant professors, and 6 instructors, if a faculty member is selected, to find the probability of choosing a professor or an instructor the following calculation must be performed:

11 + 12 + 7 + 6 = 100

11 + 6 = X

36 = 100

17 = X

17 x 100/36 = X

1700/36 = X

47.22 = X

The probability of choosing a professor or an instructor is 47.22%.

Answer

A(-10, 9), A'(-4, 9)

B(-4, 2), B'(-10, 2)

C(-7, 9), C'(-7, -4)

Example 3:

A(-3, 5), A'(3, 5)

B(-3, 0), B'(3, 0)

C(-3, 5), C'(-3, -10)