Answer:
erosion
Explanation:
grows into the eirth each year. the atmosphere and how the worldchanges every year
A bicyclist pedaling up a hill is this a form of kinetic energy or potential energy?
Answer:
Kinetic
Explanation:
Its a moving action
When a bicyclist is pedaling up a hill, it is a form of potential energy. The correct option is option potential energy.
An object's position or configuration in relation to other things might provide it potential energy. The potential energy in this situation is gravitational potential energy.
Because they are being lifted against gravity as they ascend the hill, the cyclist gains gravitational potential energy. The potential energy of the cyclist increases as they ascend.
The potential energy will be transformed into kinetic energy once the cyclist begins pedaling or moving downward.
As a result of their increased height above the ground, cyclists are building up potential energy as they bike up a hill. They gain speed as they cycle downhill, transforming that potential energy into kinetic energy.
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You are playing catch in the front yard and your sister throws a football at you, then your neighbor throws a baseball at
you at the same speed.
Which ball has the greater momentum?
An airfoil is deflected upward as the airflow is deflected downward. Which of Newton's laws does this example best illustrate?
Which statement correctly compares radio waves and microwaves?
A. Radio waves have shorter wavelengths and lower frequencies than microwaves.
B. Radio waves have longer wavelengths and higher frequencies than microwaves.
C. Radio waves have longer wavelengths and lower frequencies than microwaves.
D. Radio waves have shorter wavelengths and higher frequencies than microwaves.
Answer:
C. Radio waves have longer wavelengths and lower frequencies than microwaves.
Explanation:
Radio waves and microwaves are both electromagnetic waves. They do not require a medium for their propagation.
These waves are produced as result of the vibration between electric and magnetic fields perpendicular to one another.
On the electromagnetic spectrum, the waves are listed from left to rightAlong the spectrum, wavelength increases as frequency decreases. Energy also decreases to the right on the spectrum. Since microwaves comes before radio waves, they have shorter wavelength and higher frequency than micro waves.If the radius of an atom is 60 pm and the radius of the Earth is 6000 km, by how many orders of
magnitude is the radius of the Earth larger than an atom?
Answer:
1 x 10¹⁷
Explanation:
Given data:
Radius of the earth = 6000km
Radius of an atom = 60pm
Now, how many orders is the radius of the earth larger than an atom
Solution:
To solve this problem, let us express both quantity as the same unit;
1000m = 1km
6000km = 6000 x 10³m = 6 x 10⁶m
60pm;
1 x 10⁻¹²m = 1pm
60pm = 60 x 1 x 10⁻¹²m = 6 x 10⁻¹¹m
Now;
The order: [tex]\frac{6 x 10^{6} }{6 x 10^{-11} }[/tex] = 1 x 10¹⁷
If a car has a mass of 200 kilograms and produces a force of 500 N, how fast will the car accelerate?
Answer:
2.5m/s²
Explanation:
Given parameters:
Mass of car = 200kg
Force on car = 500N
Unknown:
Acceleration of the car = ?
Solution:
According to Newton's second law of motion:
Force = mass x acceleration
Insert the given parameters and find the acceleration;
500 = 200 x acceleration
acceleration = 2.5m/s²
Explanation:
F = ma
500N = 200 × a
200a. = 500N
a. =. 2.5m/s²
PLEASE GIVE BRAINLIEST.
What is a physical change ?
A. Burning wood
B. Rusting metal
C. Cooking a egg
D. Freezing water
Answer : Freezing water !
please help me will mark u brainiest
Answer:
Answer is A :)))))))))
M A 40.0- cm-diameter circular loop is rotated in a uniform electric field until the position of maximum electric flux is found. The flux in this position is measured to be 5.20 × 10⁵N . m²/C. What is the magnitude of the electric field?
By electric flux, the electric field is 41.36 x 10⁵ N/C
We need to know about electric flux to solve this problem. Electric flux is the measure of the electric field through a given surface, although an electric field in itself cannot flow. It can be determined as
Φ = E . S = E . Scosθ
where Φ is electric flux, E is electric field, θ is angle of surface and S is surface area.
From the question above, we know that
Φ = 5.20 × 10⁵ N.m²/C
d = 0.4 m²
r = 0.2 m²
because of maximum flux, hence (cosθ = 1)
By substituting the following parameter, we get
Φ = E . Scosθ
5.20 × 10⁵ =E . π.r²
5.20 × 10⁵ =E . π.0.2²
E = 41.36 x 10⁵ N/C
Hence, the electric field is 41.36 x 10⁵ N/C
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The effect of gravity on a falling object can be modeled by a ball dropped
from different heights. What is a limitation of this model?
O A. Not all objects bounce, even though balls do.
B. Friction with air also affects the fall of the object.
C. Some balls float in water, while others sink.
O
D. The ball can be dropped from varying heights.
Answer:
B. Friction with air also affects the fall of the object.
Explanation:
The limitation of this experimental design is that friction with air also affects the fall of the object.
Therefore, it is difficult to measure effect of gravity on falling objects. Air resistance cause friction in the movement of an object falling. Frictional force resists the motion of an object subject to free fall.Therefore, the experiment will be biased due to the influence of the frictional force.
the density of aluminum is 2.70 g/cm3. express this value in units of kilogram per cubic meter and pounds per cubic foot.
The density of aluminum in units of kilogram per cubic meter is 2700kg/m³
The density of aluminum in units of pounds per cubic foot is 1.686lb/ft³
unit conversion - conversion of one unit to another unit of measurement of same quantity by using multiplication/division.
the density of aluminum is 2.70 g/cm3.(given)
1 kg = 1000g
1m = 100cm
density of aluminum in kg/m³ is :
2.7×10⁻³kg/10⁻⁶m³
2700kg/m³
density of aluminum in lb/ft³ (ponds per cubic foot) is :
1g = 0.2204lb
1cm = 0.328ft
= 2.7×0.02204/(0.328)³
1.686lb/ft³
The density of aluminum in units of kilogram per cubic meter is 2700kg/m³
The density of aluminum in units of pounds per cubic foot is 1.686lb/ft³
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1. What coefficients would balance the following equation?
_Al + _02 →_Al2O3
2A1 + 302 +1A1,03
2A1+ 302 → 2A1203
3A1 + 302 + 2A1003
4A1 + 302 → 2A1203
Answer:
D. 4Al + 3O2 → 2Al2O3
Explanation:
Chemical reactions involves the chemical combination of two or more substances called REACTANTS to yield other substances called PRODUCTS. However, in accordance with the LAW OF CONSERVATION OF MASS, the amount of reactants must be equal to that of the products.
To accomplish this, the reaction must be BALANCED. A balanced equation is an equation in which the number of atoms of each element in the reactant side equals the number of atoms in the product side. In this reaction involving Aluminum and Oxygen to give Aluminum oxide as follows:
Al + 02 → Al2O3
A coefficient is used to balance the number of atoms on both sides of the equation as follows:
4Al + 3O2 → 2Al2O3
Answer:
here for points
3u3784y297y4ui3t7
Explanation:
a ball is thrown upward at 25 m/s from the ground. what is the average velocity and average speed of the ball after 5 seconds?
Newton's first law of motion: Objects in motion will stay in motion and objects at rest will stay at rest, unless acted on by
a. friction
b. acceleration
c. unbalanced force
d. contact force
Newton's first law states that every object will remain at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force. This is normally taken as the definition of inertia
A sound wave has a velocity of 350 meters/second and a frequency of 430 hertz. what is its wavelength? a. 0.01 meters b. 0.60 meters c. 0.81 meters d. 0.08 meters
The wavelength of a sound wave with a velocity of 350 meters/second and a frequency of 430 Hz is 0.81 meters.
The relation between velocity(v), frequency(f) and wavelength(lambda) of a sound wave is given by the following formula,
V = (f)(λ) equation1
We are given that , v = 350 meters/second
f = 430 hertz
By putting the above values in the equation1 , we will get
350 = 430 x (λ)
350/430 = λ
λ = 0.81 meters
Thus, the wavelength of a sound wave with a velocity of 350 meters/second and a frequency of 430 Hz is 0.81 meters.
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What is the answer please help me!
Answer:
The greatest force of gravity on the ball will occur at the point when the ball is near to hit the ground
Explanation:
We know that the earth's center attracts everything towards its center with an acceleration of 9.8 m/s² so it simply means that the change in velocity must occur to produce acceleration. When the ball comes towards the earth, its speed continuously increases and it is at maximum level when it is about to hit the ground so this is the point where gravitational force is maximum.
I hope this helps ^_^
Ou
A truck starts from rest and accelerates uniformly over a time of 5.5 seconds for a
distance of 130 m. Determine the acceleration (in m/s^2) of the truck.
Please submit your answer with 2 decimal places!
Answer:
8.6m/s²
Explanation:
Given parameters:
Initial velocity = 0m/s
Time = 5.5s
Distance = 130m
Unknown:
Acceleration = ?
Solution:
To solve this problem, we use one of the appropriate motion equations:
S = Ut + [tex]\frac{1}{2}[/tex] at²
S is the distance
U is the initial velocity
t is the time taken
a is the unknown acceleration
t is time taken
Since U = 0m/s
S = [tex]\frac{1}{2}[/tex] at²
130 = [tex]\frac{1}{2}[/tex] x a x 5.5²
130 = 15.13a
a = 8.6m/s²
What unite do scientists use to measure force
A) Newton
B) grams
C) meters
D) meters per second per second
A ball is thrown upward at 25 m/s from the ground. What is the maximum height of the ball?
Answer:
31.25 meters in a time of 2.5 seconds.
Explanation:
Because your question gives a number that is a multiple of 5, that is just begging for us to set a = -g = -10 m/s^2. This is acceleration due to gravity. Then, we have an equation vf = v0 + at where v0 = 25 m/s. Plugging in the earlier known values and letting vf = 0 (when final velocity is zero there is maximum height), we get t = 2.5 s. Then, Delta y = vot - 1/2 gt^2. This gives 62.5 - 31.25 = 31.25 m.
Thus, our answer is 31.25 meters in a time of 2.5 seconds.
*Note: g is more precisely 9.806 m/s^2, but that would lead to more annoying sig figs in our answer so I chose to round to 10 m/s^2 which is common.
How much momentum does a stationary 5500 kg mass have?
Answer:0
Explanation:
All stationary objects have no momentum they do not have any motion to have momentum you need mass and motion
Two Forces 20N and 50N act at a point and at an angle of 120 to each. Draw a force diagram for the system
the resultant force is F=F1-F2.
F1 = 20 N, and F2 = 50 N
In this instance, two different resultant forces are feasible.
when the two are at an angle of A with one another.
See the outcome in case 1 of the image if both are facing the same way. if they are both facing the opposite directions. when both are at a zero-degree angle from one another If they are parallel to one another and moving in the same direction, the resultant force is F=F1+F2. If they are parallel but moving in the opposite direction, the resultant force is F=F1-F2.
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If a bicycle has an average acceleration of -0.44 m/s^2, and its initial forward velocity is 8.2 m/s, how long will it take the cyclist to bring the bicycle to a complete stop
Answer:
The value is [tex]t = 18.6 s[/tex]
Explanation:
From the question we are told that
The average acceleration of the bicycle is [tex]v = -0.44 \ m/s^2[/tex]
The initial forward velocity is [tex]u = 8.2 \ m/s[/tex]
Generally from kinematic equations we have that
[tex]v = u + at[/tex]
Here v is the final velocity of the bicycle and the value is v = 0 m/s
So
[tex]0 = 8.2 + (-0.44)t[/tex]
=> t = 18.6 s
c) The infra-red detectors are made from thermocouples soldered to blackened metal plates. These are connected to galvanometers. In the space below, draw
a labelled diagram of a thermocouple. [2] [Total 6]
The infra-red detectors are made from thermocouples soldered to blackened metal plates. These are connected to galvanometers.
What is galvanometers?A galvanometer measures electric current electromechanically. Early galvanometers were not calibrated, but later models, called ammeters, were, and could measure current flow more precisely.
A galvanometer functions by deflecting a pointer in response to an electric current running through a coil in a steady magnetic field. Galvanometers can be viewed as a particular type of actuator.
The discovery that a magnetic compass needle deflects when near an electric current-carrying wire led to the invention of galvanometers, which was made by Hans Christian rsted in 1820. They were the first tools used to find and gauge minute currents. The apparatus was given the name Luigi Galvani by André-Marie Ampère after the Italian electricity researcher who, in 1791, discovered it.
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Two carts connected by a 0.25 m spring hit a wall, compressing the spring to 0.1 m. The spring constant k is 100 N m . What is the elastic potential energy stored from the spring's compression?
Given that,
Initial position of the spring, x₁ = 0.25 m
Final position of the spring, x₂ = 0.1 m
The spring constant of the spring, k = 100 N/m
To find,
The elastic potential energy stored from the spring's compression.
Solution,
The work done in moving a spring from on position to another is stored in the form of elastic potential energy. It can be given as follows :
[tex]E=\dfrac{1}{2}k(x_2^2-x_1^2)\\\\=\dfrac{1}{2}\times 100\times (0.1^2-0.25^2)\\\\=2.62\ J[/tex]
So, the required energy is 2.62 J.
Answer:
1.125 J
Explanation:
The correct answer is 1.125 J
Scientists study how the continents move. Why might scientists use a model
to show this movement?
O A. It is too slow to observe directly.
O B. It is too fast to observe directly.
O C. It is too dangerous to observe directly.
O D. It is too complex to observe directly.
Answer: A
Explanation: continents move very slowly, about one inch per year
Answer:
A
Explanation:
it takes thousands of years to see the continents progress in it's movement. by the time we see progress of how they are moving you'd have been dead for 50000 years XD
100 POINTS PHYSICS PLEASE HELP
1: Let’s say you drop a 100 kg ball from the top of the stairs and by the
time it reaches the ground it has a velocity of 40 m/s. How much kinetic
energy would it have?
2: If a 63.5 kg person climbs a hill that is 1500 m and stands at the top
looking over the edge, what is their potential energy at that point?
3: If that 63.5 kg person went parachuting, jumped out of an airplane, and
reached a velocity of 80 m/s before opening their parachute, how much
kinetic energy would they have?
4: Look at the formula for potential energy. Why would that 63.5 kg person
have more energy if they walked up a 1500 m hill than if they walked 1500
m on a flat surface?
Answer:
1: The Ball Has 80,000 J
2: Their Potential Energy Is 934,083 J At That Point
3: They Would Have 203,200 Kinetic Energy
4: The Person Would Have More Potential Energy GoingUp A 1500 M Hill Rather Than Walking 1500 M On A Flat Surface Because When You Walk Up Something You Have More Potential Energy Then When You Walk On Flat Ground
Reason:
1: 100kg x 40 m/s = 80,000
2: 63.5 x 1500 M = 934,083
3: 63.5 x 80 M/s = 203,200
A green laser pointer emits light with a wavelength of 532 nm. What is the frequency of this radiation, in hz?.
The frequency of electromagnetic waves is 5.64 x 10¹⁴ Hz.
We need to know about electromagnetic waves to solve this problem. Electromagnetic waves can propagate without media. The speed of electromagnetic in vacuum media is equal to the speed of light. Hence, the wavelength and frequency can be determined as
c = λ . f
where c is the speed of light (3 x 10⁸ m/s), λ is wavelength and f is frequency.
From the question above, we know that
λ = 532 x 10¯⁹ m
By substituting the given parameter, we can calculate the frequency of green laser pointer
c = λ . f
f = c / λ
f = 3 x 10⁸ / 532x10¯⁹
f = 5.64 x 10¹⁴ Hz
Hence, the frequency is 5.64 x 10¹⁴ Hz.
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broglie wavelength of a 231 gg baseball with a speed of 34.0 m/sm/s ? express your answer in meters.
The broglie wavelength is 9.27 x 10¯³⁵ meter.
We need to know about de Broglie's wavelength to solve this problem. Broglie's wave equation is the following :
λ = h / (m.v)
where λ is the wavelength, h is Max Planck constant 6.62x10⁻³⁴ J.s, m is the mass and v is velocity.
From the question above, we know that:
m = 231 gram = 0.231 kg
v = 34 m/s
By substituting the parameter, we get :
λ = h / (m.v)
λ = 6.62x10⁻³⁴ / (0.21 x 34)
λ = 9.27 x 10¯³⁵ m
Hence, the broglie wavelength is 9.27 x 10¯³⁵ meter.
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which statement correctly line graph
a. the x-axis is on the left side of the graph
b. the responding variable is on the y-axis
c. the line graph has 3 axes
d. the manipulated variable is not shown
Answer:
A.
Explanation:
The X-Axis is always on the left side.
A nonconducting ring of radius R is uniformly charged with a total positive charge q. The ring rotates at a constant angular speed \omega about an axis through its center, perpendicular to the plane of the ring. What is the magnitude of the magnetic field on the axis of the ring a distance 1/2 R from its center?
The magnitude of the magnetic field on the axis of the ring (1/2)R from its center is [tex]\frac{\mu_{0} \omega qR^{2}}{2.5(\sqrt{5} )\pi R }[/tex].
The magnetic influence on moving electric currents, electric charges, and magnetic materials is described by a magnetic field, which is a vector field. A force acting on a charge while it travels through a magnetic field is perpendicular to both the charge's motion and the magnetic field.
The radius of the nonconducting ring is R.
The ring is uniformly charged q.
The ring rotates at a speed of ω.
The distance between the ring and its center is x = (1/2)R.
The magnetic field on a current loop's axis is given as follows:
[tex]B = \frac{\mu_{0} IR^{2}}{4 \pi (x^{2}+R^{2})^{\frac{3}{2}} }[/tex]
Now, [tex]I=\frac{q}{2 \pi /\omega}[/tex]
The magnetic field's strength at x = R/2 is:
[tex]B = \frac{\mu_{0} IR^{2}}{4 \pi (x^{2}+R^{2})^{\frac{3}{2}} }[/tex]
[tex]B = \frac{\mu_{0} IR^{2}}{4 \pi ((\frac{R}{2} )^{2}+R^{2})^{\frac{3}{2}} }[/tex]
[tex]B = \frac{\mu_{0} IR^{2}}{4 \pi ((\frac{5}{4} )R^{2})^{\frac{3}{2}} }[/tex]
[tex]B = \frac{\mu_{0} \omega qR^{2}}{2.5(\sqrt{5} )\pi R}[/tex]
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