Answer: if the predator sees the light bugs easier than the dark bugs then the bright bug will most likely go extinct
Explanation:
If it has enough kinetic energy, a molecule at the surface of the Earth can escape the Earth’s gravitation.
The acceleration of gravity is 9.8 m/s2, and the Boltzmanns’ constant is 1.38066 × 10−23 J/K.
Using energy conservation, determine the minimum kinetic energy needed to escape in terms of the mass of the molecule m, the free-fall acceleration at the surface g, and the radius of the Earth R.
Kmin=mgR
Calculate the temperature for which the min- imum escape energy is 5 times the average kinetic energy of an oxygen molecule.
Answer in units of K.
346.4 K is the temperature at which the minimum escape energy is five times that of an oxygen molecule on average.
How can the law of conservation of energy be used to generate the formula for escape velocity in terms of G and R?Using the law of conservation of energy, VE denotes escape velocity, M denotes earth mass, and R denotes earth radius. Hence, VE=2GMR is the equation for escape velocity.
Kavg = (3/2)kT
Kmin = 5Kavg
mgR = (15/2)kT
Solving for T, we get:
T = (2/15k)mgR
Using the numbers for k, g, and R as substitutes and assuming the oxygen molecule (m = 5.31 x 10–26 kg) is the case, we arrive at:
[tex]T = (2/15 x 1.38066 x 10^-23 J/K) x 5.31 x 10^-26 kg x 9.8 m/s^2 x 6.371 x 10^6 m[/tex]
[tex]T = 346.4 K[/tex]
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A 119-kg trunk is dropped off the edge of a building. What is the upward gravitational pull (in N) of the trunk on the earth?
The upward gravitational pull of the trunk on the earth is 1.156 x 10^3 N (or approximately 1156 N).
What is Gravitation?
Gravitation is a fundamental force of nature that describes the attraction between two masses. It is the force that causes objects to fall to the ground, keeps planets in orbit around the sun, and governs the motion of galaxies.
The upward gravitational pull of the trunk on the earth is equal in magnitude to the gravitational force that the earth exerts on the trunk. We can calculate this force using Newton's law of gravitation, which states that the force of gravity between two objects is proportional to their masses and inversely proportional to the square of the distance between them. The formula for the gravitational force between two objects is:
F = G * (m1 * m2) / r^2
where F is the force of gravity, G is the gravitational constant (6.674 x 10^-11 N*m^2/kg^2), m1 and m2 are the masses of the two objects, and r is the distance between them.
In this case, we are given the mass of the trunk (m1 = 119 kg) and we want to find the gravitational force between the trunk and the earth (m2 = mass of the earth). We can assume that the trunk is dropped from a height close to the surface of the earth, so the distance between the center of the trunk and the center of the earth is approximately equal to the radius of the earth (6.371 x 10^6 m). Substituting these values into the formula, we get:
F = (6.674 x 10^-11 N*m^2/kg^2) * (119 kg * 5.972 x 10^24 kg) / (6.371 x 10^6 m)^2
F = 1.156 x 10^3 N
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A solid metal sphere with radius 0.440 m carries a net charge of 0.270 nC.
Find the magnitude of the electric field at a point inside the sphere, 0.110 m below the surface.
Answer:
the magnitude of the electric field at a point inside the sphere, 0.110 m below the surface, is 7.31 × 10^5 N/C.
Explanation:
To find the magnitude of the electric field at a point inside the sphere, we can use Gauss's law, which states that the electric flux through any closed surface is proportional to the charge enclosed by that surface. We will assume that the metal sphere is a conductor and has a uniform charge density.
First, we need to find the charge enclosed by a spherical surface with radius 0.110 m, centered at the center of the metal sphere. Since the sphere has a uniform charge density, we can find the charge enclosed by this surface as:
Qenc = (4/3)πr^3ρ = (4/3)π(0.110)^3σ,
where ρ is the charge density of the metal and σ is the surface charge density, which is equal to the net charge divided by the surface area of the sphere:
σ = Qnet / (4πr^2) = 0.270 nC / (4π(0.440)^2) = 4.994 × 10^-5 C/m^2.
Therefore, the charge enclosed by the spherical surface is:
Qenc = (4/3)π(0.110)^3(4.994 × 10^-5) = 1.472 × 10^-8 C.
The electric flux through this surface is proportional to the charge enclosed, so we can use Gauss's law to find the electric field at the point inside the sphere:
ΦE = E(4πr^2) = kQenc,
where k is Coulomb's constant.
Solving for E, we get:
E = kQenc / (4πr^2) = (9 × 10^9 N·m^2/C^2)(1.472 × 10^-8 C) / (4π(0.110)^2 m^2) = 7.31 × 10^5 N/C.
Therefore, the magnitude of the electric field at a point inside the sphere, 0.110 m below the surface, is 7.31 × 10^5 N/C
indicate which of the three major interaction processes (photoelectric absorption, compton scattering, pair production) is dominant in the following situations: (a) 1 mev gamma rays in aluminum (b) 100 kev gamma rays in hydrogren (c) 100 kev gamma rays in iron (d) 10 mev gamma rays in carbon (e) 10 mev gamma ryas in lead
(a) 1MeV gamma rays in aluminum ⟹ Compton effect
(b) 100 keV gamma rays in hydrogen ⟹ Compton effect
(c) 100 keV gamma rays in iron ⟹ Photoelectric effect
(d) 10 MeV gamma rays in carbon ⟹ Compton effect
(e) 10 mev gamma ryas in lead ⟹ Photoelectric effect
The photoelectric effect has important applications in many areas, including solar cells and photocells, which convert light into electrical energy. It was first observed by Heinrich Hertz in 1887 and later explained by Albert Einstein in 1905. The energy of a photon (a packet of light) can be absorbed by an electron in the material, causing it to be emitted as a free electron.
The energy of the photon must be greater than the material's work function, which is the minimum energy required to remove an electron from the material. It also plays a crucial role in the development of quantum mechanics, as it was one of the key experiments that led to the understanding of the wave-particle duality of light.
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Which of the following materials offer the least opposition to the flow of magnetic lines of force? A.steel b.copper c. Brass d.air
Air offers the least opposition to the flow of magnetic lines of force compared to the other materials listed.
This is because air is a non-magnetic material, which means it does not contain any magnetic properties. Magnetic lines of force can pass through air with minimal interference, as there are no magnetic fields generated to oppose the magnetic lines.
In contrast, materials such as steel, copper, and brass have magnetic properties, which means that they can create their own magnetic fields that can oppose the flow of magnetic lines of force. Therefore, air is the least resistive material for the flow of magnetic lines of force.
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10. Liquids are poured into a container and separate. They form a green layer on
the bottom, a blue layer in the middle, and a red layer on the top. What's true about
the density of the liquids?
A. The red liquid is the least dense.
B. The green liquid is the least dense.
C. The blue liquid is the least dense.
D. They all have the same density.
Option A is true: the red liquid is the least dense.
What happens when different liquids are poured into a container?When different liquids are poured into a container, they will typically separate based on their densities. Liquids with higher densities will sink to the bottom, while liquids with lower densities will float on top.
In the scenario described in the question, we are told that the liquids have separated into three distinct layers: green on the bottom, blue in the middle, and red on top. Based on this layering, we can infer that the red liquid must be the least dense, since it is floating on top of the other two liquids.
Similarly, we can infer that the blue liquid is denser than the red liquid, but less dense than the green liquid, since it is sandwiched between them. And we can infer that the green liquid is the most dense, since it is at the bottom.
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Study the image
Pulley
Fill in the blanks to describe the forces in the image above.
The input force is
[Select ]
The output force is
[Select I
[ Select ]
The force that the rope/pulley exerts on the box as it is lifted
The distance the rope moves on the left side
The force applied by pulling down on the left hand side
The force applied by pressing down on the left side is referred to as the input force. The force that the rope or pulley applies to the box when it is hoisted is known as the output force.
Which force does a pulley employ?The pulley system employs the tension force applied to one side of the rope to redirect the force in a different direction.
What are the pulley's input and output forces?A pulley is a straightforward device that consists of a rope or cable looped around a wheel that has been grooved, as seen below. By pulling on the rope's one end, you operate a pulley. Your pull's force is the input force. The output force pulls up on the object you want to move at the other end of the rope.
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A 59g particle is moving to the left at 27 m/s . How much net work must be done on the particle to cause it to move to the right at 38 m/s?
Explanation:
To find the net work done on the particle to cause it to move to the right at 38 m/s, we need to use the work-energy theorem, which states that the net work done on an object is equal to its change in kinetic energy:
Net work = ΔK = 1/2 * m * (vf^2 - vi^2)
where m is the mass of the particle, vi is its initial velocity (to the left), and vf is its final velocity (to the right).
Substituting the given values, we get:
Net work = 1/2 * 0.059 kg * (38 m/s)^2 - 1/2 * 0.059 kg * (27 m/s)^2
Net work = 46.4657 J - 22.6545 J
Net work = 23.8112 J
Therefore, the net work done on the particle to cause it to move to the right at 38 m/s is 23.8112 Joules.
how is potential energy a scalar quantity even though it can be negative?
Explanation:
Potential energy is a scalar quantity because it has only magnitude and no direction. Its ability to be negative does not affect its scalar nature.
Please mark brainliest
The equal and opposite forces described by Newton's third law of motion will balance each other out in many cases.
True
False
The statement "The equal and opposite forces described by Newton's third law of motion will balance each other out in many cases" is true.
According to Newton's third law of motion, for every action, there is an equal and opposite reaction. This means that whenever an object exerts a force on another object, the second object will exert an equal and opposite force back on the first object. These two forces are often referred to as an "action-reaction pair". When two objects are in contact and interact with each other, they will experience an equal and opposite force pair. These forces will balance each other out and cancel each other's effect on the motion of the objects, which is why they are often called balanced forces. For example, when you push against a wall, the wall pushes back on you with an equal and opposite force. These forces balance each other out, and you and the wall will remain in place. Similarly, when a car accelerates forward, the force of the engine pushing the car forward is balanced by the force of friction pushing the car backwards. These forces cancel each other out, and the car moves forward at a constant speed.
However, in some cases, the forces described by Newton's third law may not balance each other out, such as when the forces act on different objects or when they are not in direct contact.
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NEED HELP FAST
A farmer wants to know if a new fertilizer will produce better tomatoes than his old fertilizer. Which statement describes the best hypothesis to use to address his question ?
A. If the new fertilizer is used, bigger tomatoes will be produced than if the old fertilizer is used.
B. If the new fertilizer is used, the tomato plants will need less water than if the old fertilizer is used.
C. Using the new fertilizer is better for the environment than using the old fertilizer
D. Using the new fertilizer is less expensive than using the old fertilizer.
if an object with a mass of 30kg is propelled with a force of 10 N what rate will the object accelrate at
The given scenario involves calculating the acceleration of an object propelled by a force of 10 N with a mass of 30 kg. The object will accelerate at a rate of 0.333 m/s².
The equation for calculating acceleration is:
acceleration = force / mass
where acceleration is measured in meters per second squared (m/s²), force is measured in Newtons (N), and mass is measured in kilograms (kg).
Given:
mass = 30 kg
force = 10 N
To find the acceleration, we can substitute these values into the equation:
acceleration = force / mass
acceleration = 10 N / 30 kg
acceleration = 0.333 m/s²
Therefore, the object will accelerate at a rate of 0.333 meters per second squared. This means that for every second that passes, the object's velocity will increase by 0.333 meters per second.
It's worth noting that the direction of the force is also important in determining the direction of the acceleration. If the force is applied in the same direction as the motion of the object, it will speed up, but if the force is applied in the opposite direction, it will slow down.
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pls help
Aliyah marks a line on her driveway with a piece of chalk. Then she stands with both feet at the line and jumps forward as far as she can. She marks where she lands with chalk and measures the distance between the two points. What is she measuring?
A.
displacement
B.
reference point
C.
position
D.
speed
Answer:
A. displacement.
Explanation:
Aliyah is measuring the distance she can jump forward
[tex] \: [/tex]
The figure shows a square block of glass JKLM with a ray of light incident on side JK at an angle of incidence of 60°. The refractive index of the glass is 1.50.  a. Calculate the angle of refraction of the ray. b Calculate the critical angle for a ray of light in this glass. c. Explain why the ray shown cannot emerge from side KL but will emerge from side LM.
A. The angle of refraction is 35°
B. The critical angle is 42°
A. How do I determine the angle of refraction?We can determine the angle of refraction as follow:
Angle of incidence (i) = 60°Index of refraction of glass (n) = 1.5Angle of refraction (r) =?n = Sine i / Sine r
1.5 = Sine 60 / Sine r
Cross multiply
1.5 × Sine r = Sine 60
Divide both sides by 1.5
Sine r = Sine 60 / 1.5
Sine r = 0.5774
Take the inverse of Sine
r = Sine⁻¹ 0.5774
r = 35°
Thus, the angle of refraction is 35°
B. How do i determine the critical angle?The critical angle can be obtain as shown below:
Index of refraction of glass (n) = 1.5Critical angle (C) =?Sine C = 1 / n
Sine C = 1 / 1.5
Sine r = 0.6667
Take the inverse of Sine
C = Sine⁻¹ 0.6667
C = 42°
Thus, the critical angle is 42°
C. Why would the ray not emerge from side KL?When light travels from less dense to denser medium, it bends towards the normal. Glass is denser than air, so when light passes from air into glass it bends towards the normal.
From the given diagram, we can see that the normal is perpendicular to side LM if drawn to meet it. Since the ray bends toward the normal, it therefore means it can not emerge through side KL.
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Calculate the tension (in N) in a horizontal strand of spiderweb if the same spider sits motionless in the middle of it much like the tightrope walker in the figure.
1. The strand sags at an angle of 11.0° below the horizontal. (Enter a number.)
2. Compare this with the tension in the vertical strand (find their ratio). (Enter a number.)
(tension in horizontal strand)⁄(tension in vertical strand) = ?
The tension in the horizontal strand of cobwebs is given as =1.089 x 10^-3T
What is Tension in a spring?Tension in a spring refers to the force exerted on the spring when it is stretched or pulled. When a force is applied to a spring, it will deform and stretch, and this deformation creates a restoring force that tries to return the spring to its original shape. The magnitude of the restoring force is proportional to the amount of deformation or stretching that has occurred, according to Hooke's law.
If we consider the two sides of the strand, the horizontal components must be equal and opposite and the vertical components must sum to the weight.
Thus, we have a net force in all directions
2Tsin\theta = mg
T = mg/2sin\theta
= [tex]\frac{5 * 10^-^5 * 9.8}{2 * sin 13}[/tex]
=1.089 x 10^-3T
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Electrical energy is generated byO A. the internal heat within the Earth's core • B. breaking chemical bonds between atoms and molecules. O C. splitting atomic nuclei in radioactive materials. O D. the flow of electrons (charged particles) between positive and negative sources.
The flow of electrons (charged particles) between positive and negative sources is what generates electrical energy.
What is electrical energy?Electrical energy is a form of energy that results from the movement of charged particles, such as electrons, through a conductor. This movement of charged particles creates an electric current, which can be harnessed to power devices and machines.
Electrical energy is a versatile form of energy that is used for a wide range of purposes, from lighting and heating to transportation and communication.
It is also a clean and efficient form of energy, which has led to its increased use in recent years as a more sustainable alternative to fossil fuels. The unit of measurement for electrical energy is the joule (J) or the watt-hour (Wh).
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The average speed of an object is the _______ that an object moves divided by the _______ of the movement.
Question 1 options:
Total distance; direction
Total time; total force
Total area; total force
Total distance; total time
Answer:
Bottom choice
Explanation:
Average speed is total distance / total time
A 100 kg crate is attached to a rope wrapped around the inner disk (R1) as shown. A person pulls on another rope wrapped around the outer disk (R2) with force F to lift the crate. What force F is needed to lift the crate? If the ratio of the radius is R1/R2 = 1/5
A 100 kg crate is attached to a rope wrapped around the inner disk (R1) as shown. A person pulls on another rope wrapped around the outer disk (R2) with force F to lift the crate. a force of 196.2 N is needed to lift the 100 kg crate.
To determine the force F needed to lift the 100 kg crate, we'll first find the mechanical advantage of the system using the given ratio of the radii R1/R2, and then use that to calculate the force F.
Find the mechanical advantage (MA) using the ratio of the radii.
Given that R1/R2 = 1/5, the mechanical advantage can be calculated as the inverse of this ratio, which is R2/R1 = 5/1 = 5.
Calculate the force required to lift the crate (F).
Since MA = 5, it means that the force required to lift the crate (F) is 5 times less than the weight of the crate (W). The weight of the crate can be calculated using the equation W = m * g, where m is the mass of the crate (100 kg) and g is the acceleration due to gravity (approximately 9.81 m/s^2).
W = 100 kg * 9.81 m/s^2 = 981 N (Newtons)
Now, we can calculate the force F needed to lift the crate:
F = W / MA = 981 N / 5 = 196.2 N
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Read through the discussion topic thoroughly, then post your thoughts on the appropriate discussion board. Write at least one well-developed paragraph. As this is a discussion, don't forget to respond to at least two other students as well. Please be courteous and use proper netiquette. For more detailed instructions on the Team Huddle, please refer to the appropriate lessons under the Course Introduction.
Good sportsmanship is an important part of team sports. Have you ever witnessed bad sportsmanship? How could the situation have been handled better? Tell about a time you witnessed good sportsmanship.
Bad sportsmanship often take many forms, such as taunting, trash-talking, cheating, or refusing to shake hands after a game. These behaviors not only spoil the game's spirit but also reflect poorly on the individual and the team.
What does sportsmanship means?Sportsmanship refers to an an aspiration or ethos that a sport or activity will be enjoyed for its own sake. This is with proper consideration for fairness, ethics, respect, and a sense of fellowship with one's competitors.
Good sportsmanship involves respecting your opponents, following the rules, and maintaining a positive attitude, regardless of the outcome. Good sportsmanship can inspire respect and admiration, even from opponents. In situations where bad sportsmanship occurs, it is important to address the issue promptly and assertively, without escalating the situation.
Therefore, the coach, referee, or other authority figures can intervene and remind players of the importance of sportsmanship and the consequences of their actions.
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A 1700 kg car drives around a flat 170-m -diameter circular track at 27 m/s.
What is the magnitude of the net force on the car?
Answer:
the magnitude of the net force on the car is 144,270 N.
Explanation:
To solve this problem, we need to use the formula for centripetal force:
F = (m * v^2) / r
where F is the net force, m is the mass of the car, v is the speed of the car, and r is the radius of the circular track (which is half the diameter).
First, we need to find the radius of the track:
r = d/2 = 170 m / 2 = 85 m
Now we can plug in the values we know:
F = (1700 kg * (27 m/s)^2) / 85 m
F = 144,270 N
Therefore, the magnitude of the net force on the car is 144,270 N.
For a person to see his or her complete (head-to-toe) image in a plane mirror, the mirror must have a length (height) of at least one-half a person's height (see the figure below). Does the person's distance from the mirror make a difference? Explain.
The correct option is B. So, it is true that the person's distance from the mirror makes a difference. He must stand at a distance less than or equal to his or her own height in order to fit the entire reflected image.
If the person is too far away from the mirror, then they will not be able to see their entire image in the mirror. However, if the person is standing close enough to the mirror, they will be able to see their complete image in the mirror. The closer a person is to the mirror, the more of their body they will be able to see likewise, the farther away a person is from the mirror, the more of their body they will be unable to view. In the figure below, if the person moves away from the mirror, their feet will no longer be visible in the mirror. So he must stand at a distance less than or equal to half of his/her height.
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A city bus travels 6 blocks east and 8 blocks north. Each block is 100m long. If the bus travels this distance in 15 minutes, what is the average speed of the bus?
The average speed of the bus is 8 kilometers per hour (kph).
Given data:6 blocks east8 blocks northEach block is 100m longTime taken: 15 minutesDistance traveled = 6 blocks east + 8 blocks north = (6 x 100m) + (8 x 100m) = 1000m
Time taken = 15 minutes
Hence the speed can be computed as
Speed = Distance/Time = 1000m/15min = 8 kph
The average speed of the bus is 8 kilometers per hour (kph), after traveling 6 blocks east and 8 blocks north, with each block being 100m long and the journey taking 15 minutes.
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What is the electric field strength at a distance of 10 cm from a charge of 2 uC
The electric field strength at a distance of 10 cm from a charge of 2 μC is 3.6 x 10⁵ N/C.
What is called electric field?If there's a charge present in any form, an electric field is linked with every point in space. The strength and direction of the electric field are expressed by the value of E, sometimes referred to as the strength of the electrical field, electric field intensity, or simply the electric field.
The following formula determines the magnitude of the electric field generated by a point charge:
where,
E = Electrical Field Strength = ?
k = 9 x 10⁹ Nm²/C²
q = magnitude of charge
q = 2 μC = 2x 10⁻⁶ C
r = distance = 10 cm
r = 0.10 m
Therefore,
When the values are entered into the equation, we obtain:
E = 9 x 10⁹ * (2 x 10⁻⁶) / (0.1)²
E = 3.6 x 10⁵ N/C
Because of this, the electric field intensity at 10 cm from a 2 μC charge is 3.6 x 10⁵ N/C.
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The teen soon loses his balance and falls backwards off the board at a velocity of 1.0 m/s. Assuming momentum is conserved in this process, what is the skateboard's new velocity in meters per second? [Note: this may not be a very good assumption, as there can be significant friction in the ball bearings of the skateboard]
Assuming momentum is conserved, the skateboard's new velocity is -27 m/s, which means it is now moving backwards. However, as noted in the prompt, this assumption may not be very accurate in real life due to the effects of friction and other factors.
Assuming momentum is conserved in this process, the initial momentum of the system (teen and skateboard) must equal the final momentum. Since the teen is falling backwards, the direction of his velocity is opposite to the direction of the skateboard's velocity.
Let's assume the mass of the teen is 60 kg and the mass of the skateboard is 2 kg.
The initial momentum of the system is:
p_initial = m_teen * v_teen + m_skateboard * v_skateboard
Since the teen is standing still initially, v_teen = 0. The skateboard is initially moving forward with a velocity of v_skateboard = 3.0 m/s, so:
p_initial = (60 kg)(0 m/s) + (2 kg)(3.0 m/s)
p_initial = 6.0 kg*m/s
After the teen falls off the skateboard, the final momentum of the system is:
p_final = m_teen * v_teen' + m_skateboard * v_skateboard'
where v_teen' is the final velocity of the teen (which we know is 1.0 m/s) and v_skateboard' is the new velocity of the skateboard that we need to find.
Since momentum is conserved:
p_initial = p_final
Substituting the known values:
6.0 kg*m/s = (60 kg)(1.0 m/s) + (2 kg)(v_skateboard')
Solving for v_skateboard':
v_skateboard' = (6.0 kgm/s - 60 kgm/s) / 2 kg
v_skateboard' = -27 m/s.
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A) Marcel is helping his two children, Jacques and Gilles, to balance on a seesaw so that they will be able to make it tilt back and forth without the heavier child, Jacques, simply sinking to the ground. Given that Jacques, whose weight is W= 72.0 N, is sitting at distance L= 0.80 m to the left of the pivot, at what distance L1 should Marcel place Gilles, whose weight is w to the right of the pivot to balance the seesaw? Keep 2 digits after the decimal point, in meters.
b) Gilles has an identical twin, Jean, also of weight w. The two twins now sit on the same side of the seesaw, with Gilles at distance L2 = 1.26 m from the pivot and Jean at distance L3 = 0.75 m. Where should Marcel position Jacques to balance the seesaw? Keep 3 digits after the decimal point, in meters.
c) Bad news! When Marcel finds the distance Lnew from the previous part, it turns out to be greater than Lend = 1.336 m, the distance from the pivot to the end of the seesaw. Hence, even with Jacques at the very end of the seesaw, the twins Gilles and Jean exert more torque than Jacques does. Marcel now elects to balance the seesaw by pushing sideways on an ornament (shown in red) that is at height h= 0.20 m above the pivot. With what force in the rightward direction, Fx, should Marcel push? If your expression would give a negative result (using actual values) that just means the force should be toward the left.
Keep 2 digits after the decimal point, in Newtons.
To keep the seesaw in balance, Marcel should position Gilles approximately 0.828 meters to the right of the pivot.
Equating :Force Moments Gilles' clockwise moment on the right side of the pivot and Jacques' counterclockwise moment on the left must be equal for the seesaw to be balanced. The child's weight divided by the distance from the pivot yields the moment (M):
M = w × L1 = W × L
where w is the weight of Gilles.
Rearranging this equation, we get:
L1 = (W × L) / w
Substituting the given values, we get:
L1 = (72.0 N × 0.80 m) / w
We are unable to solve for L1 because we do not know Gilles's weight. However, we can calculate the weight w required to balance the seesaw using an equation:
W × L = w × L1
Substituting the given values, we get:
72.0 N × 0.80 m = w × L1
Solving for w, we get:
w = (72.0 N × 0.80 m) / L1
Now we can replace this expression for w into the other equation for L1, giving:
L1 = (W × L) / [(72.0 N × 0.80 m) / L1]
Simplifying, we get:
L1² = (W × L × L1) / (72.0 N × 0.80 m)
L1² = (W × L) / (72.0 N × 0.80 m)
replacing the given values and solving, we get:
L1 = √[(72.0 N × 0.80 m) / (76.8 N)]
L1 ≈ 0.828 m
To balance the seesaw, Marcel ought to position Gilles approximately 0.828 meters to the right of the pivot.
What is a balance on a seesaw?
A big balance is like a seesaw. The fulcrum of a balance is in the middle, like a lever. A lever can lift a weight at the other end when a force, such as the weight of a person sitting on it, is applied to one end. Due to inequalities in the forces, the seesaw is out of balance. The hurdler has lost contact with the ground and has moved upwards. The pull of the earth is off balance. She slows down and changes direction as a result, bringing her back to earth.
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What is the change in electrical potential energy of a 2.0 nC point charge when it is moved from point A to point B in the figure? (Figure 1)
Express your answer in joules.
The change in the electrical potential from the point A to the point B is -840 V
What is the change in electrical potential?The change in electrical potential, also known as the potential difference or voltage, refers to the difference in electrical potential energy per unit of electric charge between two points in an electrical circuit or between two electrodes of a cell.
Electric potential energy is a measure of the potential for an electric field to do work on an electric charge, and is usually measured in units of volts (V). The greater the potential difference between two points, the greater the amount of work that can be done by moving electric charge from one point to the other.
We have that;
ΔV = Kq (1/ra - 1/rb)
9.0 * 10^9 * 2 * 10^-9(1/0.05 - 1/0.015)
-840 V
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What is thermal energy? in 3 or 4 sentences
Answer:
thermal energy comes from a substance whose molecules and atoms are vibrating faster due to a rise in temperature. Kinetic energy is the energy of a moving object. As thermal energy comes from moving particles, it is a form of kinetic energy. Heat energy is another name for thermal energy.
Explanation:
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A platinum resistance thermometer has resistance of 52.5Ω and 9.75Ω at 0°C and 100°C respectively. When the resistance is 8.25 Ω, find the temperature
Answer:
The resistance-temperature relationship of a platinum resistance thermometer is given by the Callendar-Van Dusen equation:
R = R0 (1 + At + Bt^2)
Where:
R0 is the resistance at 0°C
R is the resistance at the temperature t
A, B are coefficients that depend on the specific platinum resistance thermometer being used.
To find the temperature corresponding to a resistance of 8.25Ω, we need to first determine the values of A and B using the known resistances at 0°C and 100°C.
From the given data:
R0 = 52.5Ω at 0°C
R100 = 9.75Ω at 100°C
Using the Callendar-Van Dusen equation at both 0°C and 100°C, we can write:
R0 = R0 (1 + A0 + B0^2) = R0
R100 = R0 (1 + A100 + B100^2)
Dividing the second equation by the first equation gives:
R100 / R0 = 1 + A100 + B100^2
9.75Ω / 52.5Ω = 1 + A100 + B100^2
0.1857 = 1 + 100A + 10000B
Solving for A and B using simultaneous equations with the above equation and:
0 = 1 + 0A + 0B (at 0°C)
We get:
A = -0.003908
B = 0.000009184
Now, we can use the Callendar-Van Dusen equation with the values of R0, A, and B to find the temperature t corresponding to a resistance of 8.25Ω:
8.25Ω = 52.5Ω (1 - 0.003908t + 0.000009184t^2)
Dividing both sides by 52.5Ω and rearranging gives a quadratic equation in t^2:
0.000175849t^2 - 0.003908t + 0.156190476 = 0
Solving for t using the quadratic formula gives:
t = (0.003908 ± sqrt(0.003908^2 - 40.0001758490.156190476)) / (2*0.000175849)
t = 83.6°C or -42.9°C
Therefore, the temperature corresponding to a resistance of 8.25Ω is 83.6°C.
A platinum resistance thermometer has resistance of 52.5Ω and 9.75Ω at 0°C and 100°C respectively. When the resistance is 8.25 Ω then temperature will be 103.5 °C.
What is Platinum Thermometer ?A platinum resistance thermometer (PRT) is a piece of platinum wire which determines the temperature by measuring its electrical resistance. It is referred to as a temperature sensor.
There are two types of temperature dependent resistance,
1) Positive coefficient thermistor (PTC), as temperature increases its resistance increases.
2) Negative coefficient thermistor (NTC), as temperature increases its resistance decreases. vise verse.
Given,
Resistance R₀ = 52.5Ω at T₀= 0°C
Resistance R₁ = 9.75Ω at temperature T₁ = 100°C
Resistance R₂ = 8.25Ω − at temperature T₂ = ?
α − temperature coefficient of resistance;
Change in resistance proportional to the temperature change
R₁ = R₀(1 + α(T₁ − T₀))
9.75Ω = 52.5Ω + α5250
α = (9.75Ω - 52.5Ω)÷ 5250
α = - 8.1428×10⁻³
Now to calculate Temperature.
R₂ = R₀(1 + α(T₂ − T₀))
8.25Ω = 52.5Ω (1- 8.1428×10⁻³(T₂− 0))
8.25 = 52.5- 0.4275T₂
0.4275T₂ = 52.5 - 8.25
T₂ = 44.25÷0.4275
T₂ = 103.5°C
Hence temperature is 103.5°C at 8.25Ω resistance.
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5.42 * a large foucault pendulum such as hangs in many science museums can swing for many hours before it damps out. taking the decay time to be about 8 hours and the length to be 30 meters, find the quality factor q.
5.42 * a large foucault pendulum such as hangs in many science museums can swing for many hours before it damps out. taking the decay time to be about 8 hours and the length to be 30 meters. The quality factor Q of the large Foucault pendulum is approximately 51,988.
To find the quality factor (Q) of the large Foucault pendulum, we can use the formula:
Q = 2 * π * (Energy stored in the pendulum) / (Energy lost per oscillation)
First, we need to find the period of oscillation (T) of the pendulum using the formula:
T = 2 * π * √(L / g)
where L is the length of the pendulum (30 meters) and g is the acceleration due to gravity (approximately 9.81 m/s²).
T = 2 * π * √(30 / 9.81) ≈ 3.48 seconds
Next, we need to find the number of oscillations (n) in the decay time (8 hours):
n = (8 hours * 3600 seconds/hour) / T
n ≈ (28800 seconds) / 3.48 seconds ≈ 8276 oscillations
Now, we can calculate the energy lost per oscillation:
Energy lost per oscillation = (Energy stored in the pendulum) / (n * decay time)
Since the energy stored in the pendulum and the energy lost per oscillation are proportional, we can use the proportionality constant as the quality factor Q:
Q = 2 * π * (Energy stored in the pendulum) / (Energy lost per oscillation)
Q = 2 * π * n
Q ≈ 2 * π * 8276 ≈ 51988
Therefore, the quality factor Q of the large Foucault pendulum is approximately 51,988.
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A 2.6-kg object is being pulled upward with a force of 35 N. It's weight of 25 N opposes the upward force. What is the acceleration of the object?
0.71 m/s2
3.8 m/s2
9.6 m/s2
13 m/s2
The acceleration of the object is approximately 3.8 m/s^2.
What is Force?
Force is a physical quantity that describes the interaction between objects or between an object and its environment. It is a vector quantity, which means it has both magnitude and direction. Force is measured in units of newtons (N) in the International System of Units (SI).
The acceleration of the object can be found by applying Newton's second law of motion, which states that the net force on an object is equal to its mass times its acceleration:
net force = ma
In this case, the net force is the upward force minus the weight, which is:
net force = 35 N - 25 N = 10 N
So we have:
10 N = (2.6 kg) * a
Solving for a, we get:
a = 10 N / 2.6 kg ≈ 3.8 m/s^2
Therefore, the acceleration of the object is approximately 3.8 m/s^2.
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