Please help me I am doing NC math 1

The missing vertex is located at (-14,20).

To find the missing vertex, let's assume that the third vertex is located at (x,20) and the coordinates of the other two vertices are (6,0) and (5,10). Then the coordinates of the two sides of the triangle are:

Side AB: (6,0) to (5,10)

Side AC: (6,0) to (x,20)

Using the formula for the area of a triangle, which is:

Area = 1/2 * base * height

Where the base is one of the sides of the triangle and the height is the perpendicular distance from the third vertex to the base, we can set up an equation to solve for x:

60 = 1/2 * |(6-5)*20 - (x-6)*10|

60 = 1/2 * |200 - 10x + 60|

120 = |260 - 10x|

120 = 10x - 260 or 120 = -(10x - 260)

x = -14 or x = -2

Since x has to be a negative value, the missing vertex is located at (-14,20). Therefore, the three vertices of the triangle are:

A = (6,0)

B = (5,10)

C = (-14,20)

We can verify that the area of the triangle with these vertices is indeed 60 square units using the same formula:

Area = 1/2 * |(6-5)(20-10) - (-14-6)(20-0)|

Area = 1/2 * |10 - (-400)|

Area = 1/2 * 410

Area = 205 square units

Therefore, the missing vertex is located at (-14,20).

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Answer:

7 ft is 84 inches, 3ft is 36 inches

84 - 36 = 48

cuts off 18 more inches

48 - 18 = 30 inches of rope remain

Step-by-step explanation:

Step-by-step explanation:

Using the formula V = Pe^(rt), where P is the principal initially invested, e is the base of a natural logarithm, r is the rate of interest, and t is the time in years:

V = Pe^(rt)

We are given that P = $8290, r = 0.06 (since the annual interest rate is 6%), and t = 12 (since we want to find the value of the account after 12 years). Therefore, we can plug in these values and solve for V:

V = 8290 * e^(0.06*12)

V = 8290 * e^(0.72)

V = $17,936.34

Therefore, the amount of money in the account after 12 years, to the nearest cent, is $17,936.34.

Exploratory Factor Analysis (EFA) is a data analysis technique used to uncover underlying relationships among variables in a dataset. It is a multivariate statistical technique that examines the correlations among multiple observed variables in order to identify underlying latent variables, or "factors". These factors are latent, meaning they are not directly observable or measurable.

EFA helps researchers to understand how the relationships between variables can be organized and explained by underlying latent factors. Specification of EFA includes the following steps:

Exploratory Factor Analysis is a powerful data analysis technique that can uncover the underlying relationships among variables in a dataset. It helps researchers to understand how the relationships between variables can be organized and explained by underlying latent factors. By following the above steps, researchers can appropriately specify and interpret EFA to gain insights from their data.

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Answer:

12xphjzjhsgwghdghehdhhez7uehdyegd

The rate charged per hour by the first mechanic and the second mechanic.

The total number of hours worked by the two mechanics is 10 hours + 15 hours = <<10+15=25>>25 hours. The total amount charged by the two mechanics is $2400. If we let x be the rate charged per hour by the first mechanic, and y be the rate charged per hour by the second mechanic, we can write the following equations:

x + y = 195 (the sum of the two rates is $195 per hour)
10x + 15y = 2400 (the total amount charged is $2400)

We can use the first equation to solve for one of the variables in terms of the other. For example, we can solve for y in terms of x:

y = 195 - x

We can then substitute this expression for y into the second equation:

10x + 15(195 - x) = 2400

Simplifying this equation gives us:

10x + 2925 - 15x = 2400

-5x = -525

x = 105

We can then substitute this value of x back into the first equation to find the value of y:

105 + y = 195

y = 90

Therefore, the rate charged per hour by the first mechanic is $105 per hour, and the rate charged per hour by the second mechanic is $90 per hour.

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The required four values of θ that satisfy the equation tan θ = -√3 are:

θ = 4π/3 radians (or 240 degrees)
θ = 7π/3 radians (or 420 degrees)
θ = π/3 radians (or 60 degrees)
θ = 2π/3 radians (or 120 degrees)

These are the equation that contains trigonometric operators such as sin, cos.. etc. In algebraic operations.

Here,
Since the tangent function has a period of π, we can find the angles θ that satisfy the equation tan θ = -√3 by adding or subtracting multiples of π until we find all possible solutions in the desired range.

For θ < 0,

Therefore, one solution for θ in the fourth quadrant is:

θ = π + π/3 = 4π/3 radians (or 240 degrees)

To find another solution, we can add one full period of π to 4π/3 to get:

θ = 4π/3 + π = 7π/3 radians (or 420 degrees)

For θ > 2,

One solution for θ in the first quadrant is,

θ = π/3 radians (or 60 degrees)

One solution for θ in the fifth quadrant is:

θ = 2π - π/3 = 5π/3 radians (or 300 degrees)

To find another solution in the fifth quadrant, we can subtract one full period of π from 5π/3 to get:

θ = 5π/3 - π = 2π/3 radians (or 120 degrees)

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The Degree of the polynomial 6, Leading Coefficient of the polynomial -7 .

A polynomial is an expression consisting of variables and coefficients, that involves only the operations of addition, subtraction, multiplication, and non-negative integer exponents of the variables. It can have constants and/or variables, and can represent equations, functions, or graphs.

The degree of a polynomial is the highest exponent of the variable in the polynomial. The leading coefficient is the coefficient of the term with the highest degree.

In the polynomial -8y⁴+12y-7y⁶-6y²+, the highest exponent is 6, so the degree of the polynomial is 6. The coefficient of the term with the highest degree is -7, so the leading coefficient is -7.

Therefore, the degree of the polynomial is 6 and the leading coefficient is -7.

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The correct option for this question is B. There has been a rise in three-point shots, and players tend to score more points now.

Why it is?

The factor that makes it challenging to make a fair comparison between a current NBA star and an NBA star from the 1990s is:

B. There has been a rise in three-point shots, and players tend to score more points now.

The increase in three-point shots has significantly changed the way the game is played and the strategies used by teams, which makes it difficult to compare the performance of players from different eras.

Players in the current NBA tend to score more points because of the increased emphasis on the three-point shot, while players from the 1990s may have had different strengths and styles of play that were more effective in that era. Therefore, it is challenging to make a fair comparison between players from different eras based solely on their statistics.

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The scale factor of dilation for the given shape are:

For A : (0,0)

For B : (2,2)

For C : (2,2)

Magnification is defined as the ratio of the size of the new image to the size of the old image. The center of expansion is a fixed point in the plane. A dilation transform is defined based on the scale factor and dilation center. If the scale factor is greater than 1, the image will be stretched. 

Formula: Scale factor = Dimension of the new shape ÷ Dimension of the original shape.

Solution:

Given, A = A' = (0,0)

           B= (2,2) , B' = (4,4)

           C=(3,2) , C' = (6,4)

Scale factor for A = (0,0), it is because that's the center of dilation.

Scale factor for B = (4/2 , 4/2) = (2,2)

Scale factor for C = (6/3 , 4 /2) = (2,2)

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We can infer from the results that Overall, students are less interested in reading magazines than comics.

A random sample is a portion of a larger population that is selected so that each person has an equal probability of being included in the sample. In statistics and scientific research, random sampling is a frequent practise since it helps to guarantee that the sample is representative of the population as a whole and reduces the possibility of bias. There are several ways to choose random samples, such as cluster sampling, stratified random sampling, and basic random sampling. The required sample size is dependent on a number of variables, including the population's size, the level of accuracy wanted, and the population's amount of variability.

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The CFD shows that 17 observations (56.7%) fall between 15.8 and 16.0.

A histogram is a graph that displays the frequency of data in a given range. The cumulative frequency distribution (CFD) is a graph that displays the cumulative total of frequencies. The histogram and CFD of the given data are shown below:

The data shows a skewed distribution with most of the observations falling between 15.8 and 16.0. The data is highest at 16.0, with 11 observations falling in this range.

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As per the difference concept, the bearing of Q from P is 132°.

To find the bearing of Q from P, we need to calculate the difference between the bearing of P from Q and 180 degrees. This is because the bearing from P to Q is the opposite direction of the bearing from Q to P.

Let's use some notation to make this clearer. Let the bearing from P to Q be denoted by B(PQ), and the bearing from Q to P be denoted by B(QP). We are given that B(PQ) = 312°. To find B(QP), we use the following formula:

B(QP) = B(PQ) - 180°

We know that B(PQ) is 312°, so we can substitute this value into the formula to get:

B(QP) = 312° - 180°

B(QP) = 132°

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Answer:

5 and 35

Step-by-step explanation:

It's going up in tens so it must start from 5, therefore the one between 25 and 45 must be 35.

Using quadratic formula we get, Part A: The solutions for x are: x = (3 + √(57))/(3/2) and x = (3 - √(57))/(3/2). Part B: The first system solution is: ((3 + √(57))/(3/2), -(76 + 6√(57))/(9) + 5)  and second system solution is:                                                 ((3 - √(57))/(3/2), -(76 - 6√(57))/(9) + 5)

Part A: To solve for x, we need to first rearrange the equation so that all terms are on one side of the equal sign.  Adding (1/4)x^(2) to both sides of the equation:
-x^(2) + (1/4)x^(2) + 3x + 14 = 5

Next, combining like terms:
-(3/4)x^(2) + 3x + 14 = 5

Now, subtracting 5 from both sides:
-(3/4)x^(2) + 3x + 9 = 0

Finally, using quadratic formula to solve for x:
x = (-3 ± √(3^(2) - 4(-3/4)(9)))/(2(-3/4))

Simplifying:
x = (-3 ± √(57))/(2(-3/4))
x = (-3 ± √(57))/(-3/2)
x = (3 ± √(57))/(3/2)

Part B: To determine the system solutions, we need to plug in the values of x into the original equation and solve for y. For the first solution:
y = -(1/4)((3 + √(57))/(3/2))^(2) + 5
y = -(1/4)((9 + 6√(57) + 57)/(9/4)) + 5
y = -(1/4)((76 + 6√(57))/(9/4)) + 5
y = -(19 + (3/2)√(57))/(9/4) + 5
y = -(76 + 6√(57))/(9) + 5

For the second solution:
y = -(1/4)((3 - √(57))/(3/2))^(2) + 5
y = -(1/4)((9 - 6√(57) + 57)/(9/4)) + 5
y = -(1/4)((76 - 6√(57))/(9/4)) + 5
y = -(19 - (3/2)√(57))/(9/4) + 5
y = -(76 - 6√(57))/(9) + 5

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The inequality is given as 12x ≥ 15,000

An inequality in mathematics is a statement that compares two quantities or expressions using inequality symbols such as "<" (less than), ">" (greater than), "<=" (less than or equal to), ">=" (greater than or equal to), or "≠" (not equal to).

The least number of rides needed for 15000 people is given as 12x ≥ 15,000.

12x ≥ 15,000.

x ≥ 15,000 / 12

x  ≥ 1250

The least number of rides needed for 15000 people is 1250.

If the park is open for 12 hours. 15000 / 12 is the number of persons that can ride in 1 hour

Hence it is not possible for the ride to have 15000 persons in a day

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The scale factor that Sidney used for the drawing is approximately 0.00333.

To determine the scale that Sidney utilised for the drawing, we can put up a proportion. The ratio will compare the drawing's shown volleyball court's width to the actual court's width:

Scale factor = width in drawing / real width

The scaling factor will be x. Next, we have:

3 cm / 900 cm = x

By multiplying 9 metres by 100, we may convert them to centimetres:

9 metres equals 9 times 100, or 900 centimetres.

By condensing the proportion, we obtain:

x = 0.00333

Thus, Sidney utilised a scale factor for the drawing that is roughly 0.00333. As a result, each centimetre on the drawing corresponds to 0.00333 metres, or 3.33 millimetres, on the volleyball court in real life.

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In linear equation, 24 wide is the actual kitchen .

What in mathematics is a linear equation?

An algebraic equation with simply a constant and a first-order (linear) term, such as y=mx+b, where m is the slope and b is the y-intercept, is known as a linear equation.

                               Sometimes, the aforementioned is referred to as a "linear equation of two variables," where x and y are the variables.

We are given that Luther drew a scale drawing of an Italian restaurant. He used a scale on which 8 millimetre equals 3 meters. We need to find the width of the kitchen if in the drawing it is 24 mm wide.

So,

8mm = 3m

24 mm =?

24 mm = 8 * 3

3 mm = 24 m

The actual width of the kitchen is 18 m.

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Answer:

a) 7

b) 0.1

Step-by-step explanation:

a)

The width must be able to go up to 35.

Each square is 5 units wide.

35/5 = 7

The grid must be at least 7 squares wide.

b)

The highest y-coordinate is 1.7.

The highest point on the grid should be 2.

There are 20 vertical squares on the grid.

2/20 = 0.1

Each vertical square should be 0.1

A = 0.1

25. The inverse of f(x) = 1 + √2 + 3x is f-1(x) = (x - 1 - √2)/3.

26. The inverse of f(x) = e2x - 1 is f-1(x) = (ln(x) + 1)/2.

27. The inverse of y = In(x + 3) is y-1(x) = ex - 3.

28. Log2³² = 5

29. Log8² = 1/3

30.Log5^{1/125}  = -3

31. In(1/e2) = -2

32. Log10⁴⁰ + log10² = 1.6

33. log8 60 - log8 3 - log8 5 = 0

34. In10 + 2In5 = In10 + log10 5

35. 1/3In(x+2)3 + 1/2[Inx - In(x2 + 3x + 2)2] = In[(x+2)3/[(x2 + 3x + 2)2x]]

25. To find the inverse of the function f(x)=1+ √2+ 3x, we need to swap the x and y variables and solve for y.
So, x = 1 + √2 + 3y
Subtract 1 and √2 from both sides:
x - 1 - √2 = 3y
Divide both sides by 3:
y = (x - 1 - √2)/3
Therefore, the inverse of the function is f^-1(x) = (x - 1 - √2)/3

26. To find the inverse of the function f(x) = e^2x-1, we need to swap the x and y variables and solve for y.
So, x = e^2y-1
Add 1 to both sides:
x + 1 = e^2y
Take the natural log of both sides:
ln(x + 1) = 2y
Divide both sides by 2:
y = ln(x + 1)/2
Therefore, the inverse of the function is f^-1(x) = ln(x + 1)/2

27. To find the inverse of the function y=In(x+3), we need to swap the x and y variables and solve for y.
So, x = ln(y + 3)
Take the exponential of both sides:
e^x = y + 3
Subtract 3 from both sides:
y = e^x - 3
Therefore, the inverse of the function is f^-1(x) = e^x - 3

28. log2^32 = 5, because 2^5 = 32

29. log8^2 = 1/3, because 8^(1/3) = 2

30. log5 1/125 = -3, because 5^-3 = 1/125

31. In(1/e^2) = -2, because e^-2 = 1/e^2

32. log10 40 + log10 2.5 = log10 (40 * 2.5) = log10 100 = 2, because 10^2 = 100

33. log8 60 - log8 3 - log8 5 = log8 (60/3/5) = log8 4 = 2/3, because 8^(2/3) = 4

34. In10 + 2in5 = ln(10 * 5^2) = ln(250)

35. 1/3in(x+2)^3 + 1/2 [inx - in(x^2+3x+2)^2] = ln((x+2)^(1/3) * x^(1/2) * (x^2+3x+2)^(-1))

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The line of intersection of the 3x+2y+z=−1  and 2x−y+4z planes is the set of all points (4t-7s-11, t, s), where t and s are parameters. And The line of intersection of the 4x+y+z=0 and 2x−y+3z=2 planes is the set of all points ((-3/6)t+(1/6)s-(1/3), t, s), where t and s are parameters.

The line of intersection of the given planes can be found by solving the system of equations formed by the equations of the planes.

For Exercise 45, we have the system of equations:
3x+2y+z=−1
2x−y+4z=5

To solve this system, we can use the elimination method. We can multiply the second equation by 2 and subtract it from the first equation to eliminate the x variable:

3x+2y+z=−1
-(4x-2y+8z=10)
______________
-x+4y-7z=-11

Now we can express one variable in terms of the other two variables. For example, we can solve for x in terms of y and z:

-x+4y-7z=-11
x=4y-7z-11

The line of intersection of the given planes is the set of all points (x, y, z) that satisfy this equation. We can write the equation of the line in parametric form by letting y=t and z=s:

x=4t-7s-11
y=t
z=s

The line of intersection of the given planes is the set of all points (4t-7s-11, t, s), where t and s are parameters.

For Exercise 46, we have the system of equations:
4x+y+z=0
2x−y+3z=2

We can use the elimination method again to solve this system. We can multiply the first equation by 2 and subtract the second equation from it to eliminate the x variable:

8x+2y+2z=0
-(2x−y+3z=2)
______________
6x+3y-z=-2

Now we can express one variable in terms of the other two variables. For example, we can solve for x in terms of y and z:

6x+3y-z=-2
6x=-3y+z-2
x=(-3/6)y+(1/6)z-(1/3)

The line of intersection of the given planes is the set of all points (x, y, z) that satisfy this equation. We can write the equation of the line in parametric form by letting y=t and z=s:

x=(-3/6)t+(1/6)s-(1/3)
y=t
z=s

The line of intersection of the given planes is the set of all points ((-3/6)t+(1/6)s-(1/3), t, s), where t and s are parameters.

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Answer:

Let's first define our variables:

Let x be the number of students in each van and bus.

Using substitution:

From the problem, we know that:

High School A rented 8 vans and 8 buses, with a total of 240 students. So we can write the equation:

8x + 8x = 240

High School B rented 4 vans and 1 bus, with a total of 54 students. So we can write the equation:

4x + 1x = 54

Now, we can solve for x in one of the equations and then substitute that value into the other equation to solve for the other variable. For example, let's solve for x in the second equation:

5x = 54

x = 10.8

Now, we can substitute this value of x into the first equation to solve for the number of students in each van and bus for High School A:

8x + 8x = 240

8(10.8) + 8(10.8) = 172.8

So each van and bus for High School A has 10.8 students in it.

Using elimination:

We can rewrite the equations we used above in standard form:

8x + 8y = 240

4x + y = 54

We can eliminate y by multiplying the second equation by -8 and adding it to the first equation:

8x + 8y = 240

-32x - 8y = -432

-24x = -192

x = 8

Now, we can substitute this value of x into either equation to solve for y:

4(8) + y = 54

y = 22

So each van and bus for High School A has 8 students in it and each van and bus for High School B has 22 students in it.

Using graphing:

We can graph the two equations on the same coordinate plane and find the point where they intersect, which represents the solution:

8x + 8y = 240

4x + y = 54

To graph these equations, we can first solve for y in each equation:

y = -x + 30

y = -4x + 54

Then, we can plot these two lines on the same coordinate plane and find their intersection:

(6, 24)

So each van and bus for High School A has 6 students in it and each van and bus for High School B has 24 students in it.

The slope of the pattern A is 1/4

The equation of the pattern is y = 1/4x

It is important to note that the general equation of  a line is expressed as;

y = mx + c

Given that the parameters are;

From the graph shown, we have that the point where the line meets the y - axis is at point 0 which is the origin.

Also, the formula for calculating the slope of a line is expressed as;

Slope,  m = y₂ - y₁/x₂ - x₁

Now, substitute the values, we have;

Slope, m = 2 - 1/8 - 4

subtract the values, we get;

Slope, m = 1/4

The equation of the pattern A:

y = 1/4x

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To find all the values of b that will make the trinomial 3x^(2)-bx+12 factorable, we need to use the discriminant of the quadratic formula. The discriminant is the part of the quadratic formula under the square root: b^(2)-4ac. If the discriminant is a perfect square, then the trinomial will be factorable.

So we plug in the values of a, b, and c from the trinomial: b^(2)-4(3)(12) = b^(2)-144.

We want this to be a perfect square, so we can set it equal to a perfect square and solve for b:

b^(2)-144 = 36

b^(2) = 180

b = sqrt(180)

b = 6sqrt(5)

So one value of b that will make the trinomial factorable is 6sqrt(5).

Now we can plug this value of b back into the trinomial and factor it:

3x^(2)-6sqrt(5)x+12 = 0

(3x-6)(x-sqrt(5)) = 0

So the factors of the trinomial are (3x-6) and (x-sqrt(5)).

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The area of the triangular piece of property is approximately 63,121.75 square feet.

The area is the entire amount of space occupied by a flat (2-D) surface or an object's form. On a sheet of paper, draw a square using a pencil. It has two dimensions. The area of a form on paper is the area that it occupies.

Starting at the first corner, the surveyor walks 480 ft in the direction N36°W. We can break this down into its northward and westward components:

Northward component = 480 cos(36°)

≈ 388.75 ft

Westward component = 480 sin(36°)

≈ 295.42 ft

This takes the surveyor to the second corner of the property.

From the second corner, the surveyor walks S21°W to get to the third corner. We can again break this down into its southward and westward components:

Southward component = 480 cos(21°)

≈ 435.89 ft

Westward component = 480 sin(21°)

≈ 168.75 ft

Finally, the surveyor walks N82°E to get back to the starting point.

We can break this down into its northward and eastward components:

Northward component = 388.75 ft

Eastward component = 435.89 sin(82°)

≈ 426.04 ft

Now we have the lengths of all three sides of the triangular property:

Side 1 = 480 ft

Side 2 = √[(295.42 - (-168.75))^2 + (388.75 - 435.89)^2]

≈ 421.66 ft

Side 3 = √[(426.04 - 295.42)^2 + (388.75 - 0)^2]

≈ 296.13 ft

calculate the area of the triangular property, we can use Heron's formula:

Area = √[s(s - a)(s - b)(s - c)]

where s is the semiperimeter (half the perimeter) of the triangle,

and a, b, and c are the lengths of its sides.

s = (480 + 421.66 + 296.13)/2 ≈ 598.40

Area = √[598.40(598.40 - 480)(598.40 - 421.66)(598.40 - 296.13)]

Area ≈ 63,121.75 sq ft

Therefore, the area of the triangular piece of property is approximately 63,121.75 square feet.

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The highest value assumed by the loop counter in a correct "for statement" with the given header is (b) 70.

The "for-statement" is ⇒for(i = 7; i <= 72; i += 7) ,

The loop starts with i = 7 and increases by 7 in each iteration until i becomes greater than 72.

So we can find the highest value of "i" assumed by the loop counter by solving the inequality i <= 72 for i.

⇒ i <= 72

Starting with i = 7 and increasing by 7 in each iteration,

We have,

⇒ i = 7, 14, 21, 28, 35, 42, 49, 56, 63, 70, 77

The last value of i in the sequence, 77, is greater than 72, so the loop counter stops before reaching 77.

So, the highest value assumed by the loop counter in this for statement is : 70.

Therefore, the highest value assumed by the loop counter is (b) 70.

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Answer:

7.5 feet

Step-by-step explanation:

Divide the length value by 12 for your answer

90/12 = 7.5

There are 12 inches in a foot, so to convert inches to feet, you can divide the number of inches by 12.

Therefore, a 90-inch cage is equivalent to:

90 inches ÷ 12 inches/foot = 7.5 feet

So the bird cage is 7.5 ft.

The transformations that would occur to the parent function are a vertical translation, a horizontal translation to the right, and a vertical compression with a reflection over the x-axis.

The parent function of f(x)=-(1)/(3)(x-5)^(3)+3 is f(x)=x^(3). There are several transformations that would occur to the parent function in order to obtain the given function.

1. Vertical translation: The "+3" at the end of the given function indicates that the parent function is shifted up 3 units.

2. Horizontal translation: The "(x-5)" inside the parentheses indicates that the parent function is shifted to the right 5 units.

3. Vertical stretch/compression: The "-(1)/(3)" in front of the parentheses indicates that the parent function is vertically compressed by a factor of 1/3 and reflected over the x-axis.

Therefore, the transformations that would occur to the parent function of f(x)=-(1)/(3)(x-5)^(3)+3 are a vertical translation of 3 units up, a horizontal translation of 5 units to the right, and a vertical compression by a factor of 1/3 with a reflection over the x-axis.

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The estimate volume of the box holding the tissue boxes is 1125 cubic inches.

Let the Volume of each tissue box be 'v'

Number of tissues be 'n'

The estimate volume of the box holding the tissue boxes be V.

As given in Question:

Volume of each tissue box v = 125 cubic inches

Number of tissues n from the attached image (given below);

                                          n = 3×3

                                          n = 9 tissue boxes

The estimate volume of the box holding the tissue boxes V;

                                         V = nv

                                         V = 9 × 125

                                         V = 1125 cubic inches.

The estimate volume of the box holding the tissue boxes is 1125 cubic inches.

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Answer:

it means if the given sides are approximately equal then the triangles are equal too

Step-by-step explanation:

if the the sides are equal then the triangles are equal too