Please help me find the magnitude and direction of the resultant force​

Please Help Me Find The Magnitude And Direction Of The Resultant Force

Answers

Answer 1
1.41 is the magnitude and -45° is the direction
Please Help Me Find The Magnitude And Direction Of The Resultant Force

Related Questions

state the law of conversation of momentum​

Answers

The total momentum before a collision is equal to the total momentum after the collision if no external forces act on the system.
Hope this helps

Why is the level of glycerin initially decreases when heated ?​

Answers

Because glucerin is hotter so it decreases faster

What is an electricity?

Answers

Explanation:

Electricity is the flow of electrical power or charge.

in the same viewing window. Compare the magnitudes of f (x) and g(x) when x is close to 0. Use the comparison to write a short paragraph explaining why

Answers

Answer:

Due to inertia of restttttttrestrestrestrest

Give reason

It is more difficult to climb a vertical slope than a slanted slope because ​

Answers

Answer:

because in vertical slope force of gravity is more than compared to slanted slope

Answer:

because gravity is always pulling objects down so when you climb upward gravity weighs you down, you have to use effort to move yourself in the opposite direction that gravity is pulling you that is why it is harder to climb up a slope.

1.what are the types of matter?
2.what are the states of matter?​

Answers

Answer:

1) Ans= Pure substances and mixtures are the two types of matter.

2)Ans=solid ,liquid and gas are the states of matter

Displacement vs. Time
80.0
60.0
40.0
20.0
Displacement (m)
0.0
-20.0
-40.0
-60.0
4.0
6.0
18.0
22.0
0.0 2.0
8.0 10.0 12.0 14.0 16.0 20.0
Time (s)
What is the velocity of the objected represented by the graph between 0.0 s and 4.0 s?
O 7.5 m/s
240 m/s
15 m/s
120 m/s

Answers

Please find attached photograph for your answer. Hope it helps. Please do comment. The option is c. 15m/s.

in complete sentnces write down everything you know about maps. What are they for?
how Do you use them?​

Answers

maps are for locating an area or a country

Explanation:

they are really beneficial because u will have the advantage to know every country and its location and lines of longitude and latitudes

¿Qué valor de voltaje se requiere para que pasen 35 mA a través de una resistencia de 15 kΩ? Si se aplica ese mismo voltaje a una resistencia de 500Ω, ¿Cuál será la nueva corriente?

Answers

Answer:

perdón yo no hablo inglés

Question 1 of 10
Rays bend as they pass through a boundary between two media. This is
called:
A. indention.
B. reflection.
C. refraction.
D. diffraction.

Answers

c because it passed through
C.) refraction

The rays bend during refraction so

1. An MR-2 starts from rest and accelerates westward to a speed of 27 m/s in
11.8 seconds.
a) What is its acceleration?
b) What is the displacement it covered?

Answers

Answer:

a) 2.28 m/s²

b) 159.86 m

Explanation:

Part A:

u = 0 m/s

v = 27 m/s

t = 11.8 seconds

a = ?

Formula:

v = u + at

=> 27 = 0 + a(11.8)

=> 27 = a(11.8)

=> a(11.8) = 27

=> a = 27/11.8

=> a = 2.28 m/s²

Part B:

s = ?

Formula:

s = (v² - u²)/2a

s = (27² - 0²) /2(2.28)

  = 729/4.56

  = 159.86 m

Question 4 A car of mass 820 kg has a maximum power of 30 kW and moves against a constant resistance of motion to 910 N. Calculate the maximum speed of the car in the following situation; b)Up an incline (hill) of 8.75° to the horizontal?​

Answers

Answer:

P = W / t = m g s / t = m g v       where work by auto = m g s

30 kw = 30000 watts = 30000 J / s

Work wasted = F v       as shown above relating work and power

Work done against incline = m g s sin 8.75  and power against incline

= m g v sin 8.75 = 1222 v Joules / sec

power in moving auto = power available - power lost to friction

power in moving auto = 30000 - resistance = 30000 - 910 v

1222 v = 30000 - 910 v

v = 30000 / 2132 = 14 m/s

Note: constant resistance to motion must mean P = W / t = F s / t = F v

Maximum speed will be v = 14.07 m/s

What is power ?

Power is defined time rate of doing work or delivering energy.

Work done = Force * displacement

Power = work done / time

           = (Force * displacement ) / time

since , displacement / time = velocity

Power  = force * (displacement / time ) = force  * velocity

Power = mass * acceleration * velocity (  as force = mass * acceleration)

since , car is travelling up in an incline of 8.75° to the horizontal

hence , it will have two components of velocity

vertical component = v sin (theta ) = v sin(8.75°)

horizontal component = v cos (theta)= v cos (8.75°)

Power = m* a * v sin (theta )

          = 820 * 9.8  * v *sin (8.75°)                        ( a = g = 9.8 m[tex]/s^{2}[/tex])

         = 1221.472 v

Power lost due to resistance in motion  = 910 * velocity = 910 v

Power = Total power - power lost due to resistance in motion

           = 30 * [tex]10^{3}[/tex]  - 910 v

     

30 * [tex]10^{3}[/tex]  - 910 v = 1221.472 v  

v = 14.07 m/s

Maximum speed will be v = 14.07 m/s

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Electromagnetic waves transport energy.

a. True
b. Fasle

Answers

Answer:

a

Explanation:

energy is transferred in electromagnetic waves

A mass of 20kg which moved vertically produced a momentum of 300kg.m/s, how much power was needed to move the mass?

Answers

Answer:

Power is 3000 W

Explanation:

Momentum = mass × velocity

[tex]300 = 20 \times v \\ velocity = 15 \: {ms}^{ - 1} [/tex]

For power:

[tex]P = \frac{force \times distance}{time} \\ \\ P = force \times ( \frac{distance}{time} )[/tex]

but distance/time is velocity, so:

[tex]P = force \times velocity[/tex]

but force = mass × acceleration:

[tex]P = (mass \times acceleration) \times velocity \\ P = (20 \times 10) \times 15 \\ P = 3000 \: \: watts[/tex]

[ taken acceleration to be 10 m/s² ]

how to determine the volume of a human body ​

Answers

Answer:

Determine the volume of a human body to use the mass and density of water displaced to calculate the volume of the water displaced.

Answer:

According to me the volume of a human body can me determined by means of the displacement method

Explanation:

if you immerse you body in a drum of water of a known volume, the water displaced is equal to your volume

What does a food chain show?"

why plant and animal matter break down

O where resources are found in a habitat

O how producers use sunlight to make food energy

O how living things depend on each other for food

Answers

Answer:

All

Explanation:

Answer:

3rd = how living things depend on each other for food

A car starts from rest and is moving at 51 9 m/s after 120 seconds. What is the cat's
average acceleration?

Answers

Answer:

the cats acceleration is 4.25m/s2

As many as _____ neurons throughout the body are involved in the control of behavior

Answers

about 1 trillion neurons

millions of neurons throughout the body are involved

(a) A pendulum that has a period of 3.00000 s and that is located where the acceleration due to gravity is 9.79m/s2 is moved to a location where the acceleration due to gravity is 9.82m/s2. What is its new period

Answers

I assume this is the motion of the simple pendulum

T = 2π × [tex]\sqrt{\frac{L}{g } }[/tex]

=> [tex]\frac{T1}{T2 }[/tex] = [tex]\sqrt{\frac{g2}{g1} }[/tex]

Given T1= 3s g1= 9.79 g2= 9.82

=> T2 = 3.00459 s

the
four particles form a square of edge
length a 5.00 cm and have charges
q1 10.0 nC, q2 20.0 nC, q3
20.0 nC, and q4 10.0 nC. In unitvector notation, what net electric field
do the particles produce at the square’s
center

Answers

Answer:

500 in unitivector notion

What is the correct clases for this drugs

‏Compazine
heelp me please

Answers

Explanation:

Compazine belongs to class of drugs called Antiemetic Agents, Antipsychotics, Phenothiazine.

Suppose 2kg of glycerine have a temperature of 30°C. Heat is supplied to a steady rate of 100W. The temperature after 35 minutes is 75°C.
Calculate the specific heat capacity of glycerine.

Answers

Answer:

210000.................

The specific heat capacity of glycerine is 2333.3 J/(kg·K).

We can use the formula for heat (Q) absorbed by a substance:

Q = mcΔT

Where Q is the heat absorbed, m is the mass of the substance, c is the specific heat capacity of the substance, and ΔT is the change in temperature.

We know the mass of glycerine (m = 2 kg), the time for which heat is supplied (t = 35 minutes = 2100 seconds), the rate of heat supply (P = 100 W), the initial temperature (T1 = 30°C = 303 K), and the final temperature (T2 = 75°C = 348 K).

First, we need to calculate the total heat absorbed by the glycerine:

Q = Pt

Q = 100 W × 2100 s

Q = 210000 J

Next, we can calculate the change in temperature:

ΔT = T2 - T1

ΔT = 348 K - 303 K

ΔT = 45 K

Finally, we can calculate the specific heat capacity of glycerine:

c = Q/(mΔT)

c = 210000 J/(2 kg × 45 K)

c = 2333.3 J/(kg·K)

Therefore, the specific heat capacity (c) = 2333.3 J/(kg·K).

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Your spaceship lands on an unknown planet. To determine the characteristics of this planet, you drop a wrench from 3.50 m above the ground and measure that it hits the ground 0.809 s later.
Assuming that the planet has the same density as that of earth (5500 kg/m3), what is the radius of the planet?

Answers

Explanation:

By the formula,

[tex]s=ut+\frac12at^2[/tex]

[tex]-3.5=0+\frac12a(0.809)^2[/tex]

[tex]a=-10.659 ms^{-2}[/tex]

where a is the acceleration of objects by gravity.

We also know that by the Law of Gravitation,

[tex]F=-\frac{GMm}{r^2}=ma[/tex]

[tex]a=-\frac{GM}{r^2}[/tex]

The mass of the planet is given by

[tex]M=\rho V=\rho(\frac 43\pi r^3)[/tex]

So

[tex]a=-\frac{G(\rho\frac 43\pi R^3)}{r^2}= - \frac{(6.67 \times 10^{-11})(5500)(\frac43)\pi R^3}{(R+3.5)^2} = -10.659[/tex]

Since R>>3.5, so we approximate

[tex](R+3.5)^2\approx R^2[/tex]

Solving the last equation,

[tex]R=6936.483 km[/tex]

The length, breadth and height of a box is 50cm, 20cm and 10cm respectively then find surface area of its base and volume.

Answers

Surface area of base: 1000cm^2
When calculating surface area of just the base, we ignore the height. Therefore, we just multiply the length and height values.
50cm x 20cm = 1000cm^2

Volume = 10,000cm^3
Volume of a box is calculated by multiplying length by breadth by height.
50cm x 20cm x 10cm = 10,000cm^3

Hope this helped!

I just hope this pic will help you

intermolecular forces in liquid and solid

Answers

the IMF in liquids are weaker due to how far the molecules are apart from each other, whereas the IMF in solids are stronger due to how tightly packed the molecules are together.

The most suitable unit for expressing nuclear radius is

A) micro B) nanometre
C) fermi D) angstrom

Answers

Answer:

Fermi is used to express nuclear radius

Answer:

the most suitable unit for expressing nuclear radius is Fermi.


two projectile are thrown at the same intial velocity the angle of the one is theta ,the angle of the oher is 90-theta /can both projectile strict the ground at the distance and time interval of both when they are in arir?​

Answers

Answer:

Yes, if θ = 45°

Explanation:

I need someone smart!
why is the multiverse considered a theory if it has no observational or experimental evidence?
shouldn't it be considered a plausible hypothesis instead, sense it has no evidence but is lickely the case?

Answers

Answer:

It is a theory

Explanation:

There’s no form or proof or anything even tho it is a hypothesis it’s common and has no evidence due towards it

What is it called when a skydiver is no longer accelerating downward?

Answers

Explanation:

Once the force of air resistance is as large as the force of gravity, a balance of forces is attained and the skydiver no longer accelerates. The skydiver is said to have reached a terminal velocity.

50 POINTS!

Motion Diagrams: Observe each motion and describe how to object is moving. If the motion diagrams show more than one kind, highlight and label each kind. Please thoroughly explain. Thank you so much!

Answers

No:1

The object is moving with constant or uniform acceleration and in average speed

No:-2

The object is de accelerating

No:-3

The object deaccelerated and came to rest so fast.

No:-4

The object moves slowly first then accelerated.

No:-5

The object accelerated at first so fast then move with constant acceleration then again accelerated .

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