please help. i’ve been gone for school for 1 week and half and i’m totally lost.

Please Help. Ive Been Gone For School For 1 Week And Half And Im Totally Lost.

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Answer 1
hi do you need help with all of them

Related Questions

A compound containing only carbon, hydrogen, and oxygen is analyzed using combustion analysis. When 55.5 g of the compound is burned, 98.9 g of carbon dioxide and 40.5 g of water are collected.

Given that there are 2.25 moles of carbon and 4.50 moles of hydrogen produced in the reaction, calculate the mass of oxygen in the original compound. You will need to subtract the mass of the carbon that ended up in the carbon dioxide and the mass of the hydrogen that ended up in the water from the mass of the original compound.

Answers

Answer:

Determining an Empirical Formula from Combustion Data

Explanation:

Step 1: Identify the mass of carbon dioxide and water produced by the combustion.

Step 2: Find how many moles of carbon are in carbon dioxide.

Step 3: Find how many moles of hydrogen are in water.

To create water from its component atoms, a bond must form between each of the hydrogens and the oxygen. Given that hydrogen is not able to donate its single electron, how does the water molecule form? Could u simple it after you explain it?

Answers

Given that hydrogen is not able to donate its single electron,  the water molecule forms by the sharing of electrons between two hydrogen atoms and an oxygen atom.

What is Covalent bond?

This is the type of bond which occurs when the electrons of an atom are shared unlike electrovalent bond which is formed when the electrons are transferred from one atom to another.

In this case, since hydrogen can't transfer electron and oxygen needs two electrons to achieve its stable configuration then two hydrogen atoms will share one electron each with the oxygen atom which results in the formation of water.

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Select all that are "exact numbers" and therefore have an unlimited number of significant figures


A)

12 inches= 1 foot


B)

60 min= 1 hour


C)

1 pig= 88 kg


D)

my car speed= 55 mi per hour


E)

pie= 3.14

Answers

Answer:

b.

i hope is help

The image shows the products of a decomposition reaction. The larger, red spheres represent oxygen atoms, and the smaller, blue spheres represent nitrogen atoms.

In this image, there are 6 molecules composed of two red atoms bound together, and 3 molecules composed of two blue atoms bound together.
Determine the empirical formula of the reactant based on these products.

Answers

The empirical formula of the compound that decomposes is [tex]N_{2} O[/tex]

What is decomposition?

The term decomposition refers to a type of reaction in which a substance is broken down into its components. We know that a compound is composed of atoms. When there is a decomposition reaction, the atoms of the compound break down.

We can see that the products of the decomposition reaction are nitrogen and oxygen. The red spheres represent oxygen atoms, and the smaller, blue spheres represent nitrogen atoms.

We know that nitrous oxide decomposes to give nitrogen and oxygen. Thus the empirical formula of the compound is [tex]N_{2} O[/tex].

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How does the potential energy of a double bond (like oxygen-oxygen) compare to a weak interaction or single bond (like argon-oxygen)?

Answers

Answer:

Potential energy in a double bond is going to be higher than the potential energy of a single bond due to the force needed to break a double bond as opposed to a single. Single bond is weaker, which means less energy is needed to break it. Double bonds are stronger, requiring more energy to break the bond.

Explanation:

Write 3.0 x 108 in standard form.
A) 30000000
B) 300000000
C) 3000000000
D) 3000000

Answers

It’s B, 3.0 * 10^8 is 300,000,000.

I need help on part 3b please?

Answers

The answer to this question is 4.1509%.

Why? —> % error = (V observed - V true) divided by V true.

You would then get:

(2.54-2.65)/2.65 —> -.11/2.65 = —> -4.1509.

Round the following number to the nearest hundredth: 4.482?

Answers

Answer: 4.48

Explanation: If the last digit in the fractional part of 4.482 is less than 5, then simply remove the last the digit of the fractional part.

A reaction vessel contains 4.800 g of CO and 4.800 g of O2. What is the maximum number of moles of CO2 recovered, based on the number of moles of the given reactants?

Answers

The maximum number of moles of [tex]CO_2[/tex] that can be recovered from the reaction vessel would be 0.17 moles.

Stoichiometric calculation

The reaction vessel contains:

4.800 g  CO4.800 g [tex]O_2[/tex]

The equation of the reaction would be as follows:

[tex]2CO + O_2 --- > 2CO_2[/tex]

The mole ratios of the reactants to the product are as follows:

CO to  [tex]CO_2[/tex] = 1:1[tex]O_2[/tex] to  [tex]CO_2[/tex] = 1:2

4.800 g of CO = 4.8/28

                        = 0.17 moles

4.800 g of [tex]O_2[/tex] = 4.8/32

                      = 0.15 moles

Since the mole ratio of CO to  [tex]O_2[/tex] is 2 to 1, 0.17 of CO is limiting.

The mole ratio of CO to  [tex]CO_2[/tex] is 1 to 1. Thus, the equivalent mole of  [tex]CO_2[/tex] that can be recovered is also 0.17.

In other words, the maximum number of moles of  [tex]CO_2[/tex] that can be recovered from the reaction vessel is 0.17 moles.

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How does a physical change take place in making a s’more

Answers

Answer: The Marshmellow

Explanation

The marshmallow turns from a solid to a gooey texture.

The marshmallow would be gooey and melted.

You have a solution of 0.250 M NaCl. If you boil away 2/3 of the volume of water, what is the concentration of this solution in moles?

Answers

The concentration of this solution in moles is 0.75 M.

What is concentration of a solution?

The concentration of a solution is a measure of the amount of solute that has been dissolved in a given amount of solvent or solution.

Mathematically. concentration is given as;

C = n/V

where;

n is the number of molesV is the volume of the solutionC is concentration

At a constant number of moles;

C1V1 = C2V2

When you boil away 2/3 volume, the new volume becomes 1/3

So V1  = V

V2 = 1/3V = 0.3333V

Substitute the given parameters and solve for the new concentration.

C2 = (C1V1)/V2

C2 = (0.25 x V) / (0.3333V)

C2 = 0.75 M

Thus, the concentration of this solution in moles is 0.75 M.

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You have a solution of 0.250 MNaCl. If you boil away 2/3 of the volume of water, what is the concentration of this solution?

Answers

The concentration of the new solution, given that 2/3 of it's initial volume was boiled away is 0.758 M

The following data were obtained from the question:

Concentration of stock solution (M₁) = 0.250 MVolume of stock solution (V₁) = 1 mL Volume of water boiled away = 2/3 = 0.67 mL Volume of new solution (V₂) = 1 - 0.67 = 0.33 mL Concentration of new solution (M₂) =?

How to determine the concentration of the new solution

The molarity of the new solution can be obtained as follow:

M₁V₁ = M₂V₂

0.250 × 1 = M₂ × 0.33

0.250 = M₂ × 0.33

Divide both side by 0.33

M₂ = 0.250 / 0.33

M₂ = 0.758 M

Thus, the concentration of the new solution is 0.758 M

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How are bat forelimbs different from other mammals’ forelimbs?

Answers

Answer:

The forelimbs of a bat are different from other mammals as they are modified into wings for the purpose of flying.

What site is located in the structure of tRNA

Answers

The structure of tRNA resembles cloverleaf. 

 tRNA is called transfer RNA, which is a small RNA molecule which plays important role in protein synthesis.-It serves as link between messenger RNA and the growing chain of amino acids that make up protein.

 tRNA molecules fold into structure resembling cloverleaf  with four important sites:-

•The acceptor stem (3’-CCA) have an amino acid

•The anticodon  attaches  with the mRNA codon (via complementary base pairing)

•The T arm attaches  with the ribosome (via the E, P and A binding sites)

•The D arm of tRNA activating enzyme (help in adding the amino acid to the acceptor stem).

CCA is codon codes for  prolein amino acid in polypeptide chain.

AUG is initiator codon codes for methionine.

UAG, UAA and UGA are stop codons.

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Why must scientists always communicate their results​

Answers

Answer: To Know That They Did Nothing Wrong

Explanation:

For Example, They Maybe Put The Wrong Thing
Or They Made The Different One Instead Of What They Were Supposed To Do

The frequency of a radio wave was measured to be (9.3x10^8) Hz What is the energy of the radio wave in kilojoules (kJ)?
1 Hz = 1 s–1
h = 6.626 x 10-34 J.s

Answers

The energy of the radio wave in kilojoules is obtained as 6.2 * 10^-25 J.

What is a wave?

The term wave has to do with a disturbance along a medium which transfers energy. There are different kinds of wave. In this case, a radio wave is a type of electromagnetic wave. The electromagnetic waves do not require a medium for their propagation. This implies that they are able to move on their own with no medium.

Thus;

We know that;

Frequency of the wave = 9.3x10^8 Hz

Plank's constant =  6.626 x 10^-34 J.s

E = hf

E = energy of the wave

h = Plank's constant

f = frequency of the waves

E = 9.3x10^8 Hz *  6.626 x 10^-34 J.s

= 6.2 * 10^-25 J

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State how are the elements of a period arranged in the modern periodic table, from left to right.
a:In order of increasing atomic mass
b:In order of increasing atomic number
c:In order of decreasing atomic mass

Answers

Answer: B

Explanation:

The atomic number of an element is the number of protons in the nucleus of an atom of that element. Changing the number of neutrons means you get an isotope of the same element. Changing the number of electrons does not affect the atom but affects the charge of the atom. So the periodic table is arranged by increasing the number of protons or atomic numbers.

Ethanol (CH3CH2OH), the intoxicant in alcoholic beverages, is also used to make other organic compounds. In concentrated sulfuric acid, ethanol forms diethyl ether and water:
2CH3CH2OH(l) → CH3CH2OCH2CH3(l) + H2O(g)
In a side reaction, some ethanol forms ethylene and water:
CH3CH2OH(l) → CH2═CH2(g) + H2O(g)
(a) If 54.0 g of ethanol yields 28.8 g of diethyl ether, what is the percent yield of diethyl ether?
%
(b) During the process, 45.0% of the ethanol that did not produce diethyl ether reacts by the side reaction. What mass of ethylene is produced?

Answers

The percent yield of the ether is 66.5% and the mass of ethylene produced is 4.9 g.

What are the products?

We know that in a reaction, we are only able to obtain the parameter of the reactions by the use of stoichiometry. This is the relationship between the reactants and the products in the process.

The reaction is given as shown in the reaction equations in the question above.

Number of moles of ethanol =  54.0 g /46 g/mol = 1.17 moles

Since 2 moles of ethanol yields 1 mole of ether

1.17 moles of ethanol yields 1.17 moles * 1 mole /2 moles

= 0.585 moles

Mass of the ether = 0.585 moles * 74 g/mol = 43.29 g

Percent yield = 28.8 g/ 43.29 g * 100/1

= 66.5 %

Amount of unreacted ethanol = (100 - 66.5)/100 * 1.17 moles = 0.39 moles

Amount that participates in the side reaction  45.0/100 * 0.39 moles = 0.1755 moles

Given that the reaction is 1:1

Mass of ethylene produced = 0.1755 moles * 28 g/mol = 4.9 g of ethylene

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. KMnO4 oxidizes ethyl benzene to benzoic acid. If this reaction generally results in a 40 % experimental yield, how many grams of ethyl benzene are required to obtain 244 g of benzoic acid

Answers

Answer:

530.835 g

Explanation:

First we convert 244 g of benzoic acid (C₇H₆O₂) to moles, using its molar mass:

244 g benzoic acid ÷ 122.12 g/mol = 2.00 moles benzoic acid

Theoretically, one mol of ethyl benzene would produce one mol of benzoic acid. But the experimental yield tells us that one mol of ethyl benzene will produce only 0.4 moles of benzoic acid.

With the above information in mind we convert 2.00 moles of benzoic acid into moles of ethyl benzene:

2.00 moles benzoic acid * [tex]\frac{1molEthylBenzene}{0.4molBenzoicAcid}[/tex] = 5.00 moles ethyl benzene

Finally we convert moles of ethyl benzene (C₈H₁₀) into grams, using its molar mass:

5.00 moles ethyl benzene * 106.167 g/mol = 530.835 g ethyl benzene

A 2.45M of sulphiric acid solution has a density of 1.15g/ml at 20degree celesius.what is the molality of the solution in that temprature?​

Answers

The Molarity of solution if a 2.45M of sulphiric acid solution has a density of 1.15g/ml at 20degree celesius is 2.69M.

Given,

Density of the solution = 1.15 g/mL

Molarity of the sulphiric acid = 2.45M

Molar mass of sulphuric acid = 98 g

Density is given as:

[tex]Molarity(\frac{1}{molarity} +\frac{mol.wt}{1000} )\\\\=2.45(\frac{1}{molarity} + \frac{98}{1000} )\\\\(\frac{1}{molarity} = (\frac{1.15}{2.45} + \frac{98}{1000} \\\\(\frac{1}{molarity} = 0.469 - 0.098\\\\(\frac{1}{molarity} = 0.371\\\\Molarity = 2.69m\\\\[/tex]

The Molarity of solution if a 2.45M of sulphiric acid solution has a density of 1.15g/ml at 20degree celesius is 2.69M.

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20 g of sugar is there than to 150 g of 50 what is the mass of the solution formed​

Answers

The mass of the solution formed when 20 g of sugar dissolved in 150 g of tea is 170 g.

The net mass of solution is calculated as the algebraic addition of the mass of the solute which is stirred into the mass of the solvent.

During the formation of solution, the sugar molecules are dissolved into tea in which sugar molecules fitted into the intermolecular spaces present between the water molecules of the tea and form a homogenous mixture.

What is solvent?

Solvent is the substance or mixture which present in large amount in the solution.

What is solute?

Solute is the substance or mixture which present in small amount in the solution.

Given,

Mass of solute (sugar) = 20g

Mass of solvent (tea) = 150g

Total mass of solution = 20 + 150

= 170g.

Thus we concluded that the mass of the solution formed when 20 g of sugar dissolved in 150 g of tea is 170 g.

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A solution has a hydronium or hydrogen ion concentration of 3.16×10^-8M. What is the ph of the solution?

Answers

Answer:

7.50

Explanation:

The pH of a solution can be found by using the formula

[tex]pH = - log [ {H}^{+} ][/tex]

From the question we have

[tex]pH = - log(3.16 \times {10}^{ - 8} ) \\ = 7.500312...[/tex]

We have the final answer as

7.50

Hope this helps you

a piece of magnesium in the shape of a cube measures with a height of 5.62 cm. If the magnesium sample has a mass of 14.1 g, what is the density of the sample

Answers

A piece of magnesium in the shape of cube measuring with height of 5.62 cm, and this magnesium sample having mass of 1.41 g has a density of 1.78 g/cm³.

What is Density?

Density is known as the mass of substance per unit volume. Density is denoted by a Greek symbol ρ. Density is equal to the mass substance divided by its volume. The SI unit of Density is g/cm ³or kg/m³.

                                     ρ = m

                                             v

where,

ρ = density

m = mass

v  = volume

Given :

Height of the cylinder is 5.62 cm ,

Diameter of the cylinder is 1.34 cm

Radius = D/2 = 1.34/2 cm

Radius = 0.67 cm

Volume of cylinder = πr²h

Volume of cylinder = 3.14 × (0.67)² × 5.62

                                = 7.92 cm³

 Density =   Mass  

                 Volume

Density = 14.1

                 7.92

 Density = 1.78 g/cm³

Hence, the density of sample = 1.78 g/cm³ .

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Which type of energy does alpha decay generate?
O kinetic
O potential
O sound
O electromagnetic

Answers

Answer: kinetic or A :)

Explanation: kinetic energy Alpha particles have typical kinetic energy of 5 MeV (or ≈ 0.13% of their total energy 110 TJ/kg) and have a speed of about 15 000 000 m/s or 5% of the speed of light.

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Perform the following operations and express the answers in scientific notation: SHOW YOUR WORK

1) (1.2 * 10^5) + (5.35*10^6)


2) (6.91*10^-2) + (2.4* 10^-3)


3) (9.70*10^6) + (8.3*10^5)

Answers

The given operations are performed

and the expressions are presented

in scientific notation as follows;

1) (1.2 × 10⁵) + (5.35 × 10⁶) = 5.47 × 10⁶

2) (6.91 × 10^(-2) + (2.4 × 10^(-3)) = 7.15 × 10^(-2)

3) (9.70 × 10⁶) + (8.3 × 10⁶) = 1.053 × 10⁷

How can the given operations be performed and results presented in scientific notation?

1) (1.2 × 10⁵) + (5.35 × 10⁶)

(1.2 × 10⁵) + (5.35 × 10⁶) = (1.2 × 10⁵) + (53.5 × 10⁵)

(1.2 × 10⁵) + (53.5 × 10⁵) = (1.2 + 53.5) × 10⁵

(1.2 + 53.5) × 10⁵ = 54.7 × 10⁵

54.7 × 10⁵ = 5.47 × 10⁶

Therefore;

(1.2 × 10⁵) + (5.35 × 10⁶) = 5.47 × 10⁶

2) (6.91 × 10^(-2) + (2.4 × 10^(-3))

(6.91 × 10^(-2) + (2.4 × 10^(-3)) = (69.1 × 10^(-3) + (2.4 × 10^(-3))

(69.1 × 10^(-3) + (2.4 × 10^(-3)) = (69.1 + 2.4) × 10^(-3)

(69.1 + 2.4) × 10^(-3) = 71.5 × 10^(-3)

71.5 × 10^(-3) = 7.15 × 10^(-2)

Therefore;

(6.91 × 10^(-2) + (2.4 × 10^(-3)) = 7.15 × 10^(-2)

3) (9.70 × 10⁶) + (8.3 × 10⁵)

(9.70 × 10⁶) + (8.3 × 10⁵) = (97.0 × 10⁵) + (8.3 × 10⁵)

(97.0 × 10⁵) + (8.3 × 10⁵) = (97.0 + 8.3) × 10⁵

(97.0 + 8.3) × 10⁵ = 105.3 × 10⁵

105.3 × 10⁵ = 1.053 × 10⁷

Therefore;

(9.70 × 10⁶) + (8.3 × 10⁵) = 1.053 × 10⁷

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In Act IV of Romeo and Juliet, how do the Musicians feel about Peter?A. They are scared of him.
B. They find him annoying.
C. They think he is funny.
D. They feel sorry for him.

Answers

D. Is the answer can i get brainliest?

Which of the following is NOT a way that chemists use to measure that a reaction has taken place?

Select one:

a.
Changes in the concentrations of reactants and products.


b.
Color change.


c.
By manually counting the actual atoms and molecules in the reaction.


d.
Change in pH.

Answers

Answer: a

Explanation:

i hope is help

What amount of the excess reagent remains when 0.30 mol NH3 reacts with 0.40 mol O2 to produce NO and H2O? 4NH3 +502 + 4NO + 6H20
(A) 0.10 mol NH,
(B) 0.10 mol
(C) 0.025 mol NH
(D) 0.025 mol O2

Answers

Answer: (D) 0.025 mol [tex]O_2[/tex]

Explanation:

The given balanced equation is :

[tex]4NH_3+5O_2\rightarrow 4NO+6H_2O[/tex]

According to stoichiometry :

4 moles of ammonia [tex](NH_3)[/tex] reacts with = 5 moles of oxygen [tex](O_2)[/tex]

Thus 0.30 moles of  ammonia  [tex](NH_3)[/tex]  reacts with = [tex]\frac{5}{4}\times 0.30=0.375[/tex] moles of oxygen [tex](O_2)[/tex]

Now as given moles of oxygen are more than the required amount, oxygen is the excess reagent.

moles of oxygen [tex](O_2)[/tex] left = 0.40 - 0.375 = 0.025

Thus 0.025 mol [tex]O_2[/tex] excess reagent remains.

The amount of excess reagent remaining when 0.30 mole NH3 reacts with 0.40 mole O2  is 0.025 mole of O2

An excess reagent is a reactant which is left and can keep reacting after whole reaction.

A limiting reagent is a reactant that is totally consumed in the whole process of the reaction.

The chemical equation for the reaction is represented as:

[tex]\mathbf{4NH_3 + 5O_2 \to 4NO + 6H_2O}[/tex]

From the above reaction,

4 moles of ammonia reacts with 5 moles of oxygen molecule;

If 0.30 moles of ammonia reacts, then the numbers of moles of oxygen required can be computed as:

[tex]\mathbf{= \dfrac{0.3 \times 5}{4}}[/tex]

= 0.375 moles of oxygen.

But, we are given that 0.40 moles of oxygen is present.

Therefore, the amount of oxygen in excess is

= 0.40 moles - 0.375 moles

= 0.025 moles of O2

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1. Sketch a periodic table by labeling the s, p, d and f blocks?​

Answers

s block - group 1 and 2 , p block - group 13 to 18 , d block - group 3 to 12, f block - group 3

The s-block in the periodic table of elements occupies the alkali metals and alkaline earth metals ,thus known as groups 1 and 2.D block elements are also known as Transition elementsF block elements are divided into two series as lanthanoids and actinoids. This block of elements are referred to as inner transition metals. s and p block elements are together known as representative elements

Thus we can conclude that ,they are names as s,p,d and f blocks because the last electrons enter s, p , d and f orbitals respectively.

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Which of the following contains as many atoms as 18 g of water, H₂O?

Answers

The correct answer is option c) Three moles of sodium, Na.

We know that

18g of H₂O = 1 mol

So, no. of atoms in H₂O = 3 x 6.022 x 10²³

                                           = 1.81 x 10²⁴ atoms(both H&O atoms combined)

Now,

No. of atoms in 1 mol of H₂ = 2 x 6.022 x 10²³

                                             = 1.2044 x 10²⁴ atoms.

No. of atoms in 2 mol of NaCl = 2 x 6.022 x 10²³

                                                  = 1.2044 × 10²⁴ atoms.

No. of atoms in 2 mol of O₂ = 2 x 6.022 x 10²³

                                              = 1.2044 × 10²⁴ atoms.

No. of atoms in 3 mol Na  = 3 x 6.022 x 10²³  

                                              = 1.81 x 10²⁴ Na atoms.

Therefore, 3 mol of Na contains as many atoms as 18g of H₂O i.e., 1.81 x 10²⁴ atoms.

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Which Of The Following Contains As Many Atoms As 18 G Of Water, H2O?

a) One mole of hydrogen, H₂

b) Three moles of sodium, Na

c) Two moles of sodium chloride, NaCl

d) Two moles of oxygen, O₂

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