Please help!!!!!! I will make you brainly!!!!!!!!!!!!

After t minutes, Tank A contains

6000 gal - (2 gal/min) t

while Tank B contains

8250 gal - (3 gal/min) t

The two tanks hold the same amount of water when these quantities are equal. Solve for t :

6000 gal - (2 gal/min) t = 8250 gal - (3 gal/min) t

(1 gal/min) t = 2250 gal

t = (2250 gal) / (1 gal/min) = 2250 min

Answer:

4

Step-by-step explanation:

Mode is the number used most often in a data set. Four shows up the most here. If there are two numbers that occur the same amount of times, they are both the mode etc.

Given expressions:

 5x -2 > 19 - 2x  

 3x -5 < 5x - 3

Simplifying;

a.   5x -2 > 19 - 2x  ;

  Collect like terms;

        5x + 2x > 19 + 2

            7x > 21

  Divide both sides by 7 to give;

            x > 3

Not if we divided by a negative value, the sign of the inequality changes.

b. 3x -5 < 5x - 3

 Collect like terms;

       3x - 5x < -3 + 5

          -2x < 2

 Divide both sides by (-2), note, the sign of the inequality changes;

          x > -1

Step-by-step explanation:

Given the function

f(x, y) = 5 + x ln(xy − 9) at the point (5, 2)

For the function to be differentiable at the given point, the differential of the function with respect to x and y must be continuous at the point.

Fx is the differential of the function with respect to x.

Using product rule to get f(x):

fx = 0 + x(1/(xy-9)y) + ln(xy-9)

fx = xy(1/(xy-9)) + ln(xy-9)

Substitute point (5, 2) into fx

fx = 5(2)(1/5(2)-9) + ln(5(2)-9)

fx = 10(1/(10-9)) + ln(10-9)

fx = 10(1/1) + ln1

fx = 10 + 0

fx = 10

For fy:

fy = 0 + x²(1/(xy-9))+ 0

fy = x²(1/(xy-9))

Substitute point (5, 2) into fy

fy = 5²(1/(5(2)-9))

fy = 25(1/10-9)

fy = 25(1/1)

fy = 25

Next is to calculate f(5,2)

f(5,2) = 5 + 5 ln(2(5) − 9)

f(5,2) = 5 + 5 ln(10− 9)

f(5,2) = 5 + 5 ln1

f(5,2) = 5 + 5(0)

f(5,2) = 5

Since fx ≠ fy, hence the function is not differentiable at the given point

Answer:

firstly covert it like 7   1/4

= 4x7+1 = 29 so 29/4

Step-by-step explanation:

and then find difference by making denominators same

Answer:

c

Step-by-step explanation:

Answer:

C. No because the height of 151 cm is paired with two wrist circumferences.

Step-by-step explanation:

Answer:

-5x + 8y = -21

3x - 4y = 15

8y = 5x - 21

y = 5/8x - 21/8

3x - 4y = 15

-4y = -3x + 15

y = 3/4x - 15/4

5/8x - 21/8 = 3/4x - 15/4

-1/8x = -9/8x

x = 9

3x - 4y = 15

3(9) - 4y = 15

27 - 4y = 15

-4y = -12

y = 3

(9, 3)

Answer:

  (9, 3)

Step-by-step explanation:

My favorite way to solve equations like this is using a graphing calculator. For Desmos, one only needs to type the equations into the input column, click on one of them, and highlight the point of intersection to see the coordinates there.

__

The usual ways to solve these are by substitution or elimination. Another way they can be solved is using Cramer's rule, which provides a formula for the solution based on the coefficients.

  ax +by = c

  dx +ey = g

__

  x = (bg -ec)/(bd -ea) . . . . . . note the crossing pattern of the values in the products

  y = (cd -ga)/(bd -ea) . . . . . . the denominator is the same as above

__

Using these formulas, we get ...

  x = (8(15) -(-4)(-21))/(8(3) -(-4)(-5)) = (120 -84)/(24 -20) = 36/4 = 9

  y = (-21(3) -15(-5))/4 = (-63 +75)/4 = 12/4 = 3

The solution is (x, y) = (9, 3).

Doing the same by elimination involves the same amount of math and a lot more writing.

Answer:

y=78.4

Step-by-step explanation:

78.4/11.2 is 7

Answer:

(2x100,000)(7x10,000)(9x100)(5x10)

Step-by-step explanation:

Answer:

(2 x 100,000) + (7 x 10,000) + (9 x 100) + (5 x 10)

Answer:

1. A. You allow the passenger to board his flight when the passenger has a weapon.

2. B. You select the passenger for further inspection when the passenger has no weapon.

Explanation:

1. Remember, a Type I error in simple words means that the assumption "the passenger has a weapon" (null hypothesis) is actually true, but the airport security screener incorrectly concluded it is false. In other words, he assumed the passenger had no weapon and allowed the passenger to board his flight when he actually did have one.

2. While, a Type II error means that the assumption "the passenger has a weapon" (null hypothesis) is actually false, but the airport security screener incorrectly concluded it is true. In other words, he assumed the passenger had a weapon and selected the passenger for further inspection when he actually didn't have one.

Answer: 1.8%

Step-by-step explanation:

The annual interest rate is 1.8% if Moira borrowed $4,500 from her grandfather to pay for her first year of college.

It is defined as the interest based on the principal amount, it does not include the compounded amount. The interest calculates on the initial amount or borrowed amount.

It is given that:

Moira borrowed $4,500 from her grandfather to pay for her first year of college.

Three years later, she repaid the $4,500 along with an interest of $243.

Using the formula:

I = Prt

P = $4500

I = $243

t = 3

243 = 4500(r)(3)

243 = 13500r

r = 0.018

r = 1.8%

Thus, the annual interest rate is 1.8% if Moira borrowed $4,500 from her grandfather to pay for her first year of college.

Learn more about the simple interest here:

brainly.com/question/22621039

#SPJ2

Answer:

4

Step-by-step explanation:

cause 2/4=1/2 which is greater than 4/12

Answer:

4

Step-by-step explanation:

Because if you plug in four then you reduce both 1/2 is greater then 1/4.

Answer:

0.53 x 10^ -8

Step-by-step explanation:

Just move the decimal over to the right and add 1 to the exponent.

Answer: The △PQR is reflected across the y-axis and option 2 is correct.

Step-by-step explanation:1. The reflection across the x-axis is defined as

2. The reflection across the y-axis is defined as

3. The reflection across the y=x is defined as

4. The reflection across the y=-x  is defined as

It is given that the vertices of ​ △PQR ​ are P(1,1) , Q(−1,−2) , and R(4,−2) . The vertices of ​ △P′Q′R′ ​ are P′(−1,1) , Q′(1,−2) , and R′(−4,−2) .

The relation between prerimage and image is defined as

Therefore the △PQR is reflected across the y-axis and option 2 is correct.

Answer:

A foot is 12 inches and 4 is closer to 0 than 12 meaning 13 ft 4 in simplified is 13 ft

Step-by-step explanation:

Answer:

Try this but I am not 100% sure:

246173

Step-by-step explanation:

Answer: -6x + 15 < 10-5x and the numberline with the 5---->

Step-by-step explanation:

Solving -3(2x-5) < 5(2-x)

Distribute the -3 to the 2x giving you -6x and -3 to the -5 giving you 15.

Distribute 5 to 2 giving you 10 and 5 to -x ginving you -5x.

Then just solve -6x+15 < 10-5x

                          +6x             +6x

10+x > 15

-10     -10

x>5

The numberline with the postive 5 is the correct answer.

Answer: c d

Step-by-step explanation:

Answer:

4p – 7 = 13

Step-by-step explanation:

Answer:

$0.48

Step-by-step explanation:

2.40/5 = 0.48

Answer:

120

Step-by-step explanation:

360 combined, 2/3 is cheese, so 1/3 is hamburger, 1/3 of 360 is 120.

Answer:

-√4. is ur ans babes ok

and h r u

Answer:Side C H

Step-by-step explanation:

Ans

C

Step-by-step explanation:

took the test made 100

(a) The number of guest per night=p,

and the cover charge for one night per person=q.

Let the liner demand equation be [tex]q(p)=mp+c\cdots(i)[/tex],

where m and c are constants.

Given that for the first week: q=345 and p=$7 and

for the second night: q=300 and p=$10.

Put these values in equation (i), we have

345=7m+c

[tex]\Rigntarrow c=345-7m\cdots(ii)[/tex]

and

300=10m+c

[tex]\Rightarrow 300=10m+(345-7m)[/tex] [from equation (ii)]

[tex]\Rightarrow 3m=-45[/tex]

[tex]\Rightarrow m=-15[/tex]

and from equation (ii),

[tex]c=345-7\times(-15)=450[/tex].

Hence, the required demand equation is:

[tex]q(p)=-15p+450\cdots(iii)[/tex]

(b) Revenue = (Number of guests) x (Cover charge)

R=qp

[tex]\Rightarrow R(p)=(-15p+450)p[/tex] [from equation (iii)]

[tex]\Rightarrow R(p)=-15p^2+450p\;\cdots(iv)[/tex]

(c) The costs per night for drinks for the number of guest p is  $2p and the nightly overheads is $2000.

So, the required cost function is

[tex]C(p)=2p+2000\;\cdots(v)[/tex]

(d) Profit=(Revenue)-(Total costs)

i.e [tex]P(p)=R(p)-C(p)[/tex]

Using equations (iv) and (v), we have

[tex]\Rightarrow P(p)=(-15p^2+450p)-(2p+2000)[/tex]

[tex]\Rightarrow P(p)=-15p^2+448p-2000.[/tex]

Now we have the profit function as function of cover charge (entry fee) per person.

So, to get the maximum profit, P, differentiate the profit function with respect to the cover charge, q and equate it to zero to get the eqtremum point.

[tex]\frac {dP}{dq}=0[/tex]

[tex]\Rightarrow -30p+448=0[/tex]

[tex]\Rightarrow p=14.93[/tex]

This point is either maxima or minima, so differentiate the profit function twice to to ensure the value of p corrosponding to what.

[tex]\frac {d^2P}{dq^2}=-30[/tex]

This the second deravitive is negative, so p=14.93 is the value for maximum profit.

Hence, for the maximum profit, the cover charge per guest is $14.93.

Answer:

Claimed 4 allowances at a rate of $76.90 per allowance for weekly payroll.

Taxable income is therefore;

= 3,500 - (76.90 * 4 )

= $‭3,192.4‬0

Federal Income Tax (FIT).

With taxable income of $‭3,192.4‬0, Pat falls into the $3,073 to $4,597 bracket where tax is $565.15 plus 28% of anything above $‭3,073. Status is married.

= 565.15 + (28% * (‭3,192.4‬0 - 3,073))

= 565.15 + 33.43

= $‭598.58

Social Security

= Gross pay * 6.2%

= 3,500 * 6.2%

= $‭217‬

Medicare

= 3,500 * 1.45%

= $‭50.75‬

Net Pay

= 3,500 - 598.58 - 217 - 50.75

= $‭2,633.67‬

Answer:

[tex]e^{2n}x + C[/tex] (since n is assumed to be a constant when integrating with respect to x)

Step-by-step explanation:

You are integrating with respect to x, but [tex]e^{2n}[/tex] has no x-terms. Thus, it is considered a constant. The integral of any constant is equal to the constant multiplied by x.

Example: the integral of 2 is 2x, since the derivative of 2x is 2.

[tex]\int {e^{2n}} \, dx = e^{2n}x + C[/tex]

If you were integrating [tex]e^{2x}[/tex] with respect to x, it would look like this:

Since...

[tex]\frac{d}{dx} (e^{ax}) = ae^{ax}[/tex]

The integral of [tex]e^{ax}[/tex] is:

[tex]\int{e^{ax}} \, dx = \frac{e^{ax}}{a} + C[/tex]

[tex]\int {e^{2x}} \, dx = \frac{e^{2x}}{2} + C[/tex]

Note: C is a constant. It can be any number.

Answer: [tex]e^{2n}x + C[/tex] (since n is assumed to be a constant)