Please help I reallllly need the help

The inequality is solved and the number is x ≥ 12

Given data ,

Let the number be represented as x

Now , sum of three times a number and -4 is at least twice the number plus 8

And , 3x - 4 ≥ 2x + 8

To solve for "x", we can start by isolating the "x" term on one side of the inequality

3x - 4 ≥ 2x + 8

Subtract 2x from both sides , we get

3x - 2x - 4 ≥ 2x - 2x + 8

x - 4 ≥ 8

Add 4 to both sides , we get

x - 4 + 4 ≥ 8 + 4

x ≥ 12

Hence , the inequality is x ≥ 12

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The upper bound of the volume of water left in the fish tank is 20 liters.

In the given statement is :

A fish tank contains 60 liters of water, rounded to 1 significant figure. 40 liters of water, rounded to 1 significant figure, are removed from the tank.

Work out the upper bound of the volume of water left in the fish tank.

Now, According to the question:

Initial water in tank = 60 liters

Amount of water removed = 40 liters

Hence, To calculate the upper bound of the volume of water left in the fish tank;

= 60 - 40

= 20 liters

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The domain of the function is (-∞, ∞.)

The range of the function is {3, ∞}.

We have,

From the given quadratic function,

We see that,

The x-values are -∞ to ∞

The y-values are from 3 to ∞

Now,

The x-values are called the domain.

The y-values are called the range.

Thus,

The domain of the function is (-∞, ∞.)

The range of the function is {3, ∞}.

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As the class sizes range from 22 to 34 students, the answer must be 30,

Let the number of girls in the class "3x" and the number of boys "7x".

Then the total number of students in the class is:

Total students = 3x + 7x = 10x

We don't know the value of "x" yet, but we do know that the total number of students is between 22 and 34.

So we can set up an inequality:

22 ≤ 10x ≤ 34

Divide both sides of the inequality by 10:

2.2 ≤ x ≤ 3.4

Therefore, x can be either 3 or 4.

If x = 3, then the total number of students is:

Total students = 3x + 7x = 30

If x = 4, then the total number of students is:

Total students = 3x + 7x = 40

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Using a standard normal distribution table or calculator, we can find the p-value associated with z = 4.39 to be less than 0.0001.

For test the claim that half of all teens have made new friends online, we can use a hypothesis test.

Null hypothesis:

The proportion of teens who have made new friends online is equal to 0.5.

Alternative hypothesis:

The proportion of teens who have made new friends online is not equal to 0.5.

We will use a one-sample proportion test with a significance level of 0.01.

For calculate the test statistic, we can use the formula:

z = (p - P₀) / sqrt(P₀ * (1 - P₀) / n)

where p is the sample proportion, P₀ is the hypothesized proportion (0.5), and n is the sample size.

Using the given information, we have:

p = 0.57

P₀ = 0.5

n = 1060

Plugging these values into the formula, we get:

z = (0.57 - 0.5) / sqrt(0.5 x 0.5 / 1060)

z = 4.39

Hence, Using a standard normal distribution table or calculator, we can find the p-value associated with z = 4.39 to be less than 0.0001.

Since the p-value is less than the significance level of 0.01, we reject the null hypothesis and conclude that there is sufficient evidence to suggest that more than half of all teens have made new friends online.

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x at the vertex would help Charlie to find out how long it takes his basketball to reach the highest point.

When a quadratic function is in vertex form, the vertex (h, k) represents the highest or lowest point of the parabola.

In this case, the time it takes for the basketball to reach the highest point can be found by finding the x-value of the vertex of the function that represents the height of the basketball over time.

Therefore, option (A) x at the vertex would help Charlie to find the time at which the basketball reaches the highest point.

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The equation which correctly represents the given situation as required to be determined is; Choice C; w = 5 × 15.

It follows from the task content that the equation which correctly represents the Given situation is to be determined.

Since the intention is to buy 5 tickets in which case; each ticket costs 15 dollars; we have that;

Since the total amount of dollars they have is w dollars; The equation which holds true for the situation is; w = 5 × 15.

Consequently, answer choice C; w = 5 × 15 is correct.

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The area of the triangle is 2√2 square units.

This is a right triangle, and the base (the side opposite the right angle) has a length of 2√2.

We can use the Pythagorean theorem to find the length of the other two sides:

x² + x²  = (2√2)²

2x²  = 8

x²  = 4

x = 2

So the two other sides have a length of 2.

Now we can use the formula for the area of a triangle:

Area = (1/2) × base × height

In this case, the base is 2√2 and the height is 2, so we have:

Area = (1/2)×2√2 ×2

Area = 2√2

Therefore, the area of the triangle is 2√2 square units.

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The requried, justification for the given function has been shown below.

(a) Yes, R₁ defines a function. Each element in the domain is mapped to a unique element in the codomain, which is 0 in this case.

(b) No, R₂ does not define a function. For some values of n, there may be multiple animals with n legs, so there is no unique output for each input.

(c) Yes, R₃ defines a function. Each element in the domain is mapped to a unique element in the codomain, which is the remainder of n divided by 5.

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Answer:480 minutes

Step-by-step explanation:

119-47=72

72/3=24

24*20=480

Answer:

D) 4

Step-by-step explanation:

Since g(x) is the inverse of f(x), g(f(x))=x. Therefore, we need to find the value of x such that f(x) = 1. Looking at the table, we can see that f(4) = 1, so g(1) = 4.

Therefore, the correct answer is (D) 4.

The number of coupon codes that can be generated is given as follows:

247,808 coupon codes.

The Fundamental Counting Theorem states that if there are m ways to do one thing and n ways to do another, then there are m x n ways to do both.

This can be extended to more than two events, where the number of ways to do all the events is the product of the number of ways to do each individual event, according to the equation presented as follows:

[tex]N = n_1 \times n_2 \times \cdots \times n_n[/tex]

The codes are composed as follows:

Thus the total number of codes is obtained as follows:

N = 22² x 8³

N = 247,808 coupon codes.

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The solution is, 7980 times greater is the value represented by the digit 8 in the number 8,342 than the value represented by the digit 8 in the number 284.

Here, we have,

given that,

the value represented by the digit 8 in the number 8,342

and, the value represented by the digit 8 in the number 284.

now, we have to find that how many times greater is the value.

so, we have to differentiate the value represented by the digit 8 in the number 8,342 with the value represented by the digit 8 in the number 284.

so, we get,

the value represented by the digit 8 in the number 8,342  is 8000

and, the value represented by the digit 8 in the number 284 is 80

so, difference between them is:

8000 - 80

=7980

Hence, The solution is, 7980 times greater is the value represented by the digit 8 in the number 8,342 than the value represented by the digit 8 in the number 284.

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Answer:

[tex]m = \frac{ - 9 - 7}{3 - ( - 3)} = \frac{ - 16}{6} = - \frac{8}{3} [/tex]

[tex]7 = - \frac{8}{3} ( - 3) + b[/tex]

[tex]7 = 8 + b[/tex]

[tex]b = - 1[/tex]

[tex]y = - \frac{8}{3} x - 1[/tex]

The y-intercept is -1.

The expression that uses the commutative property to make it easier to evaluate is (-1/3)  × (-9) × 2/5.

The commutative property is derived from the word "commute" which implies moving around or swapping numbers. The commutative property involves moving the numbers around while the result still remains the same.

Mathematically, if switching the arrangement of the operands does not alter the result of the arithmetic operation then that certain arithmetic operation is commutative.

From the given information, the commutative property that can be used for (-1/3) × 2/5 × (-9) to make it easier to solve is (-1/3)  × (-9) × 2/5.

This is because the commutative property follows the analogy:

In addition, it will be easier to solve (-1/3) × (-9) first, then multiply it with 2/5.

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Step-by-step explanation:

Given the circ , you can find the diameter....then the radius

circ = pi * d

17.584 = pi * d

d = 5.597 in     then radius =   1/2 d = 2.798

AREA = pi r^2 =  pi * 2.798^2 = 24.6 in^2

The value of x is 17.

Given that, two parallel lines cut by a transversal, forming one interior angle has a measure of 75 degrees; the alternate interior angle has a measure of 4x + 7 degrees.

Since, we know that, the alternate interior angles between parallel lines are equal so,

4x+7 = 75

4x = 68

x = 17

Hence the value of x is 17.

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The measures of the angles are 33°, 105° and 42°

We can call the top angle P, the bottom left angle Q, and the bottom right angle R. We are also given that angle P is (x - 9) degrees, angle Q is (x + 63)  degrees, and angle R is x degrees.

Now, we can use the fact that the sum of the angles in a triangle is 180 degrees to set up an equation:

Angle P + Angle Q + Angle R = 180

To find Angle, we can use the fact that the sum of the angles in a straight line is 180 degrees. We can see that Angle and Angle A are on a straight line, so we have:

(x – 9) + ( x + 63) +  x = 180

=> 3x + 54 = 180

=> 3x = 126

=> x = 42

We can now use this value to find the measures of the angles.

Angle P is (x -9) degrees, so Angle P = 42 - 9 = 33 degrees.

Angle Q is (x + 63) degrees, so Angle Q = 42 + 63 = 105 degrees.

Angle R is x degrees, so Angle R = 42 degrees.

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Answer: 11

Step-by-step explanation:

-3 x 11 = -33

The requried class average is 83.2 points.

To find the class average, we need to calculate the total number of points earned by all the students and divide by the total number of students.

The 12 students who scored 80 points earned a total of 12 × 80 = 960 points.

The 8 students who scored 88 points earned a total of 8 × 88 = 704 points.

The total number of points earned by all the students is 960 + 704 = 1664 points.

The total number of students is 12 + 8 = 20.

To find the class average, we divide the total number of points by the total number of students:

average = total points / total students

average = 1664 / 20

average = 83.2

Therefore, the class average is 83.2 points.

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Answer:

The answer is (d) 10 lbs.

Step-by-step explanation:

Let's start by using the weighted average formula:

weighted average price = (price of first item x weight of first item + price of second item x weight of second item) / total weight

Let x be the number of pounds of walnuts needed.

The total weight of the mixture is x + 8 pounds.

The price of the walnuts is $0.80 per pound, and the price of the cashews is $1.25 per pound.

We want the mixture to cost $1.00 per pound.

Using the formula, we get:

1.00 = (0.80x + 1.25(8)) / (x + 8)

Simplifying, we get:

1.00(x + 8) = 0.80x + 10

1.00x + 8.00 = 0.80x + 10.00

0.20x = 2.00

x = 10

Therefore, Jordan needs to mix 10 pounds of walnuts with 8 pounds of cashews to make a mixture that costs $1.00 per pound.

The volumes of smaller container and larger container are 10.6 in³ and 166.22 in³ respectively.

Given that are two containers in a conical shape and cylindrical shape,

Volume of conical shape = 1/3 × π × radius² × height

= 1/3 × 3.14 × 1.5² × 4.5

= 10.6 in³

Volume of cylindrical shape = π × radius² × height

= 3.14 × 2.75² × 7

= 166.22 in²

When we pour water from smaller container to larger container = 10.6 / 166.22 × 100 = 6.4 % of larger container will be filled.

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The maximum height of the ball can reach is 49 feet high.

We know that the height is modeled by the quadratic equation:

h(t) = -16t² + 56t

Remember that for the general quadratic equation is written as:

y = ax² + bx +c

The vertex is at the value x of:

x = -b/2a

The maximum height is at the vertex, which in this case is at the value:

t = -56/(2*-16)

t = 1.75

Evaluating  the height equation in that time, we get:

h = -16*(1.75)² + 56*1.75

h = 49

The maximum height that the ball can reach is 49ft

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The measure of arc and angle in the given circle are as follow,

Measure of arc CA = 144°

Measure of arc AD  = 98°

Measure of ∠C = 90°

In the circle ,

Center of the circle = Q

m∠ABC = 72°

Measure of arc CD = 46°

Measure of arc CA

Measure of ∠ABC = 72°

In a circle angle at the center is double of angle at the circumference of the circle in the same arc.

Measure of ∠CQA = 2 ×∠ABC

                               =  2× 72°

                               = 144°

measure of arc CA = measure of ∠CQA

                                = 144°

Measure of arc AD ,

m ∠AQD + m ∠CQD = m ∠CQA

⇒m ∠AQD  = 144° - 46°

⇒m ∠AQD  =  98°

⇒ Measure of arc AD  = 98°

Measure of angle C = ( 1/2) times of measure of BQD

                                 = ( 1/2) × 180°

                                 = 90°

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The test statistic is z₀ = 2.65 and the P-value is 0.004. The null hypothesis is rejected at the 5% level of significance, and we conclude that there is sufficient evidence to suggest that the true proportion is greater than 0.8.

To test the hypothesis using the P-value approach, we can follow these

Check whether the sample size is large enough for the normal approximation to the binomial distribution. The requirements are satisfied if np₀ >= 10 and n(1-p₀) >= 10,

where p₀ is the hypothesized proportion under the null hypothesis. In this case, p₀ = 0.8, n = 125, so np₀ = 100 and n(1-p₀) = 25, both of which are greater than 10.

The null hypothesis is H₀: p = 0.8 (the true proportion is 0.8).

The alternative hypothesis is H₁: p > 0.8 (the true proportion is greater than 0.8).

Under the null hypothesis, the test statistic follows a standard normal distribution.

The test statistic is calculated as:

z₀ = (x - np₀) / sqrt(np₀(1-p₀))

where x is the number of successes in the sample.

Plugging in the values, we get:

z₀ = (105 - 1250.8) / √(1250.8 x 0.2)

z₀ = 2.65

Calculate the P-value.

The P-value is the probability of observing a test statistic as extreme or more extreme than the one calculated from the sample, assuming the null hypothesis is true.

Since this is a right-tailed test (H₁: p > 0.8), we calculate the area to the right of the test statistic.

Using a standard normal table or calculator, we find that the area to the right of z₀= 2.65 is 0.004.

Therefore, the P-value is 0.004.

Make a decision and interpret the results.

Using a significance level of α = 0.05, we compare the P-value to α.

Since the P-value (0.004) is less than α (0.05), we reject the null hypothesis.

We conclude that there is sufficient evidence to suggest that the true proportion is greater than 0.8 at a 5% level of significance.

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