Please help ASAP. The graph of a quadratic function is shown. Which of the numbers below could be the discriminant of the corresponding quadratic equation? a) 10 b) -1 c) 0 d) none of the above

Answer:

y = -x/4 + 9/2

Step-by-step explanation:

The diagonal AC is the perpendicular bisector of BD.

The centre of the square, P, through which both diagonal pass through is at the average of the coordinates of B(2,6) and D(0,-2)

P ((2+0)/2, (6-2)/2) = P(1,2)

The slope of BD,

m = (yd-yb)/(xd-xb) = (-2-6)/(0-2) = -8/-2 =4

Slope of AC

m' = -1 / m = -1/4

Using the point slope form of the line AC, slope m' through P(1,2)

y-yp = m'(x-xp)

y-2 = -(1/4)(x-1)

Simplify and isolate y

y = -x/4 + 1/4 +2 = -x/4 + 9/2

Answer:

1/3(x+5)

Step-by-step explanation:

f(x) = 3x-5

y = 3x-5

Exchange x and y

x = 3y-5

Solve for y

Add 5 to each side

x+5 = 3y

Divide each side by 3

1/3 ( x+5) = 3y/3

1/3 ( x+5) = y

The inverse is 1/3(x+5)

Answer:

[tex]f^{-1}(x)=\frac{x+5}{3}[/tex]

Step-by-step explanation:

[tex]f(x)=3x-5[/tex]

[tex]\mathrm{We \: need \: to \: find \: the \: inverse \: of \: the \: function.} \\ \mathrm{The \: inverse \: of \: a \: function \: reverses \: the \: original \: function.}[/tex]

[tex]\mathrm{Plug \: f(x) \: as \: y.}[/tex]

[tex]y=3x-5[/tex]

[tex]\mathrm{Solve \: for \: x.}[/tex]

[tex]\mathrm{Add \: 5 \: to \: both \: sides \: of \: the \: equation.}[/tex]

[tex]y+5=3x[/tex]

[tex]\mathrm{Divide \: both \: sides \: of \: the \: equation \: by \: 3.}[/tex]

[tex]\frac{y+5}{3} =x[/tex]

[tex]\mathrm{Switch \: variables.}[/tex]

[tex]\frac{x+5}{3} =y[/tex]

[tex]\mathrm{Plug \: y \: as \: f^{-1}(x).}[/tex]

[tex]f^{-1}(x)=\frac{x+5}{3}[/tex]

Answer:

469.42 ft²

Step-by-step explanation:

         w/sin27 = 38/sin40

                   w = sin27*38/sin40

                    w = 26.84 ft

            ∡X = 180 - 27- 40 = 113º

              A = 0.5*(26.84)*(38)*sin(113)

            A = 469.42 ft²

As an approximate decimal, this is 0.5556 which converts to 55.56%

======================================================

Explanation:

Let's say there are 100 households (just for the sake of simplicity). We are told that 90% of them have answering machines. So that means 90 households have answering machines. In addition, 50 households have answering machines and call waiting. Those 50 households are part of the 90 mentioned previously.

We then select a house at random. Someone tells us (or we have some kind of prior knowledge) that whichever house is selected, they have an answering machine. We can ignore the 10 households that don't have an answering machine. Out of those 90 households, 50 have both features. So 50/90 = 5/9 is the probability of getting a household with both features.

The answer would be 1/2 or 50% if we didn't have the prior knowledge of the household having an answering machine. But with this prior knowledge, the conditions change and so does the probability.

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You could also compute 0.50/0.90 to get the same answer.

Answer:

7.1%

The percentage increase is 7.1%

Step-by-step explanation:

Percentage increase %∆P is the percentage change in the price.

Percentage increase %∆P = ∆P/Pr × 100%

Where;

∆P = change in sales price = $241,500-$225,400

Pr = regular price = $225,400

Substituting the given values;

%∆P = (241,500-225,400)/225,400 × 100%

%∆P = 7.142857142857% = 7.1%

The percentage increase is 7.1%

Answer:

2 triangles are possible.

Step-by-step explanation:

Given

a=6

b=10

[tex]\angle[/tex]A=33°

To find:

Number of triangles possible ?

Solution:

First of all, let us use the sine rule:

As per Sine Rule:

[tex]\dfrac{a}{sinA}=\dfrac{b}{sinB}[/tex]

And let us find the angle B.

[tex]\dfrac{6}{sin33}=\dfrac{10}{sinB}\\sinB = \dfrac{10}{6}\times sin33\\B =sin^{-1}(1.67 \times 0.545)\\B =sin^{-1}(0.9095) =65.44^\circ[/tex]

This value is in the 1st quadrant i.e. acute angle.

One more value for B is possible in the 2nd quadrant i.e. obtuse angle which is: 180 - 65.44 = [tex]114.56^\circ[/tex]

For the value of [tex]\angle B = 65.44^\circ[/tex], let us find [tex]\angle C[/tex]:

[tex]\angle A+\angle B+\angle C = 180^\circ\\\Rightarrow 33+65.44+\angle C = 180\\\Rightarrow \angle C = 180-98.44 = 81.56^\circ[/tex]

Let us find side c using sine rule again:

[tex]\dfrac{6}{sin33}=\dfrac{c}{sin81.56^\circ}\\\Rightarrow c = 11.02 \times sin81.56^\circ = 10.89[/tex]

So, one possible triangle is:

a = 6, b = 10, c = 10.89

[tex]\angle[/tex]A=33°, [tex]\angle[/tex]A=65.44°, [tex]\angle[/tex]C=81.56°

For the value of [tex]\angle B =[/tex][tex]114.56^\circ[/tex], let us find [tex]\angle C[/tex]:

[tex]\angle A+\angle B+\angle C = 180^\circ\\\Rightarrow 33+114.56+\angle C = 180\\\Rightarrow \angle C = 180-147.56 = 32.44^\circ[/tex]

Let us find side c using sine rule again:

[tex]\dfrac{6}{sin33}=\dfrac{c}{sin32.44^\circ}\\\Rightarrow c = 11.02 \times sin32.44^\circ = 5.91[/tex]

So, second possible triangle is:

a = 6, b = 10, c = 5.91

[tex]\angle[/tex]A=33°, [tex]\angle[/tex]A=114.56°, [tex]\angle[/tex]C=32.44°

So, answer is : 2 triangles are possible.

Answer:

3/14

Step-by-step explanation:

En esta pregunta, nos preocupa calcular la fracción de los estudiantes que no asisten a los talleres.

Para obtener la fracción que no asiste a los talleres, lo que debemos hacer es sumar las fracciones de cada uno de los talleres y restar el total de 1.

Matemáticamente eso sería;

1- (2/7 + 1/10 + 2/5)

Agregando los términos en el paréntesis, tenemos;

(20+ 7 + 28) / 70 = 55/70 = 11/14

Restando esto de 1, tenemos; 1-11 / 14 = 3/14

Answer:

Step-by-step explanation:

Let the first number be x

Let the second number be y

For the first equation

One number is 7 less than 3 times the second number is written as

x = 3y - 7

For the second equation

The sum of the two numbers is 29

So we have

x + y = 29

Substitute the first equation into the second one

That's

3y - 7 + y = 29

4y = 29 + 7

4y = 36

Divide both sides by 4

Substitute y = 9 into x = 3y - 7

That's

x = 3(9) - 7

x = 27 - 7

The numbers are 20 and 9

Hope this helps you

Answer:

use factoring x (see attachment)

-8 x 7 = -56

-8 + 7 = -1

(x - 8)(x + 7) = 0

x = 8, -7

hope this helps :)

Answer:

1:2

Step-by-step explanation:

The area of ΔFED must be 1/4th of the entire area and so must the area of ΔBCD because B and F are the midpoints. Therefore, the area of ABDF is 1 - 1/4 - 1/4 = 1/2 of ACDE's are so the ratio is 1:2.

Answer:

Graph A is the one that represents the given piecewise function.

Step-by-step explanation:

Notice that the Domain of the given function has been partitioned in three sections:

[tex]-2\leq x<0\,\,; \,\,\,x = 0\,\,;\,\,\,0<x\leq 2[/tex]

in the first section we have that the function responds to [tex]f(x)=x-1[/tex], which is a line of positive slope (ascending line) equal to "1", and y-intercept at y= -1.

This line should therefore start at the point (-2, -3) (when x = -2) and end at y almost equal to -1, when x approaches the value zero; and an empty dot should be seen in the position (0, -1)

For x = 0 we should see a solid dot located at the position (0, 1) on the plane.

And finally for the third section we should see a horizontal segment (that represents a constant value of 3, starting with an empty dot at the point (0, 3), and ending on a solid dot located at (2, 3).

This is what we see represented by the graph labeled A in the list of answer options.

Answer:

B

Step-by-step explanation:

I think it is C. Pls comment right or wrong!

The equation 2(x + 5) = 40 is true for the value x = 15 which is the correct answer would be option (C)

The equation is defined as mathematical statements that have a minimum of two terms containing variables or numbers that are equal.

To determine the required equation which is true for the value x = 15

We have to simplify the given equations and solve for x.

A. 2(x + 3) = 40

⇒ 2x + 6 = 40

⇒ 2x = 40 - 6

⇒ 2x = 34

⇒ x = 34/2

⇒ x = 17

B. 2(x − 5) = 30

⇒ 2x - 10 = 30

⇒ 2x = 30 + 10

⇒ 2x = 40

⇒ x = 20

C. 2(x + 5) = 40

⇒ 2x + 10 = 40

⇒ 2x = 40 - 10

⇒ 2x = 30

⇒ x  = 15

Hence, the equation 2(x + 5) = 40 is true for the value x = 15 which is the correct answer would be option (C)

Learn more about the equations here:

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Answer: 0.49 ± 0.0237

Step-by-step explanation: A interval of a 99% confidence interval for the population proportion can be found by:

[tex]p_{hat}[/tex] ± z.[tex]\sqrt{\frac{p_{hat}(1-p_{hat})}{n} }[/tex]

[tex]p_{hat}[/tex] is the proportion:

[tex]p_{hat}[/tex] = [tex]\frac{1455}{2957}[/tex]

[tex]p_{hat}[/tex] = 0.49

For a 99% confidence interval, z = 2.576:

0.49 ± 2.576.[tex]\sqrt{\frac{0.49(1-0.49)}{2957} }[/tex]

0.49 ± 2.576.[tex]\sqrt{\frac{0.49*0.51}{2957} }[/tex]

0.49 ± 2.576.(0.0092)

0.49 ± 0.0237

For a 99% confidence interval, the proportion will be between 0.4663 and 0.5137 or 0.49 ± 0.0237

Answer:

They are both equal to 7.07

Step-by-step explanation:

Using SohCahToa to find x you use the opposite and the hypotenuse if you use the 45 degree angle.

Now you use sin(45)=x/10

x=7.07

Now using SohCahToa to find y you use hypotenuse and adjacent, if using the 45 degree angle.

Now you use cos(45)=y/10

y=7.07

Answer: side y=7.1

side x= 7.1

Step-by-step explanation:

[tex]sin(45)=\frac{x}{10}[/tex]

[tex]x=7.07...[/tex]

[tex]cos(45)=\frac{y}{10}[/tex]

[tex]y=7.07...[/tex]

To generate a point, you plug in a number for x to get the corresponding y value.

If x = 0 for instance, then the y value is...

y = x^2 - 4

y = 0^2 - 4 ... x is replaced with 0

y = 0 - 4

y = -4

So x = 0 and y = -4 pair up to get the point (0,-4). This is the y intercept as the parabola crosses the y axis here. It turns out that this is also the vertex point as it is the lowest point on the parabola.

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If x = 1, then,

y = x^2 - 4

y = 1^2 - 4

y = 1 - 4

y = -3

meaning (x,y) = (1,-3) is another point on this line.

----------------

Repeat for x = 2

y = x^2 - 4

y = 2^2 - 4

y = 4-4

y = 0

Since we got a y output of 0, we have found an x intercept located at (2,0). The other x intercept is (-2,0).

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The idea is to generate as many points as possible. Plot all of the points on the same xy coordinate grid. Then draw a curve through those points the best you can. You should get what you see in the diagram below. I used GeoGebra to make the graph. Desmos is another handy tool I recommend.

Note: the more points you generate, the more accurate the graph will be

Answer:

Step-by-step explanation:

m1=40

Taking m3

m3=40 ×3

m3= 120

Answer:6/16 or 3/8

Step-by-step explanation:

I did it

Answer: 3/16

Step-by-step explanation:

Answer: [tex]y=\frac{2}{5}, \frac{6}{5}[/tex]

Step-by-step explanation:

When answering a problem like this, you first isolate the absolute value.  TO do this, first subtract 8 from both sides, to get –2|4–5y|=-4.  Then divide both sides of the equation to get |4–5y|=2.  The next thing you do is split the equation into 4-5y=2 and 4-5y=-2, because the contents of the absolute value could be negative or positive, and simplifying both into y = 2/5, and y = 6/5y.

Hope it helps <3

Answer:

[tex]\boxed{\sf Average \ Speed = 54\ km/hr}[/tex]

Step-by-step explanation:

Given:

Distance = S = 18 km

Time = t = 20 min = 20/60 = 0.33 hours

Required:

Average Speed = <v> = ?

Formula:

Average Speed = Total Distance Covered / Total Time Taken

Solution:

A . S = 18 / 0.33

A.S = 54 km/hr

Answer:

0.9km/minute

or

54km/hour

Step-by-step explanation:

18km in 20 minutes = 18km/20min

18km/20min = 0.9km/min

1 hour = 60 minutes

20 minutes = 20/60 = 0.3333 hours

18km/20mins = 18km/0.3333hours = 54km/hour

Answer:

y<=-x+3 and y<=2x+1

Step-by-step explanation:

y=-x+3 is the orange line. The shaded region is below so its y<-x+3

y=2x+1 is the blue line. The shaded region is below so y<2x+1

Answer:

Step-by-step explanation:

Given that:

OA = 7 cm, AB = 6 cm. ∠A = 90°, OA = OC = 7 cm

Using Pythagoras theorem: OB² = OA² + AB²

OB² = 6² + 7²=85

OB = √85 = 9.22 cm

to find ∠O, we use sine rule:

[tex]\frac{AB}{sin(O)}=\frac{OB}{sin(A)}\\ \\sin(O)=\frac{AB*sin(A)}{OB}=\frac{6*sin(90)}{9.22} =0.65 \\\\O=sin^{-1}0.65=40.6^o[/tex]

AOC is a minor sector with radius 7 cm and angle 40.6

The Area of the triangle OAB = 1/2 × base × height = 1/2 × OA × AB = 1/2 × 7 × 6 = 21 cm²

Area of sector OAC = [tex]\frac{\theta}{360}*\pi r^2=\frac{40.6}{360}*\pi *7^2=17.37 \ cm^2[/tex]

Area of shaded region = The Area of the triangle OAB - Area of sector OAC = 21 - 17.37 = 3.63 cm²

Perimeter of arc AC = [tex]\frac{\theta}{360}*2\pi r=\frac{40.6}{360}*2\pi *7=4.96\ cm[/tex]

CB = OB - OC = 9.22 - 7 = 2.22

Perimeter of shaded region = AB + CB + arc AC = 6 + 2.22 + 4.96 = 13.18 cm

Answer:

yes, the base is 4

Step-by-step explanation:

Answer:

1,110

Step-by-step explanation:

calculator

Answer:

2/xy

Step-by-step explanation:

you have to do the math but im not very sure on this

Answer:

Step-by-step explanation:

Given,

Cost price ( CP ) = 12

Selling price ( SP ) = 15

Since, CP < SP , she made a profit

Actual profit = SP - CP

plug the values

[tex] = 15 - 12[/tex]

Subtract the numbers

[tex] = 3[/tex]

Profit = 3

Now,

Profit percent = [tex] \frac{actual \: profit}{cost \: price} \times 100[/tex] %

Plug the values

[tex] = \frac{3}{12} \times 100[/tex] %

Calculate

[tex] = 25[/tex] %

Hope this helps...

Best regards!!

Answer:

25%

Step-by-step explanation:

Cost Price: ₦12

Selling Price: ₦15

Profit: ₦15 - ₦12 = ₦3

Profit Percentage = [tex]\frac{profit}{cost price}[/tex]  ×  [tex]\frac{100}{1}[/tex]

Profit Percentage = [tex]\frac{3}{12}[/tex] × [tex]\frac{100}{1}[/tex]

Profit Percentage = [tex]\frac{1}{4}[/tex] × [tex]\frac{100}{1}[/tex] = 25%

Final Answer = 25%

Answer:

D

Step-by-step explanation:

If you put the equation into a graphing calculator it will give ou a function than is a straight line that is stretched vertically by 3 units

Answer:

The answer to your question is given in the attached photo.

Step-by-step explanation:

To determine the answer to the question,

First, we shall determine the value 3A.

This is obtained by multiplying matrix A by 3 as shown in the attached photo.

Next, we shall carry out the operation 3A – B as shown in the attached photo.

The expression a/b ÷ c/d = ad/bc is A. true.

To show that if a/b and c/d are rational expressions, then a/b ÷ c/d = ad/bc

Rational expressions are expressions of the form a/b where a and b are integers and b ≠ 0

If the rational expression a/b is to be divided by c/d, we take the reciprocal of the expression on the right side of the division sign.

So, L.H.S = a/b ÷ c/d

= a/b × 1/(c/d)

= a/b × d/c

= ad/bc

= R.H.S

Since L.H.S = R.H.S.

a/b ÷ c/d = ad/bc

So, the expression a/b ÷ c/d = ad/bc is A. true.

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