Please answer this in two minutes

Answer:

Step-by-step explanation:

The sum of angles in a triangle is always 180°, even if all are acute or one is obtuse or a right angle. That means their sum will always produce a straight line. Thus, the following statements are true

Answer:

B,E,G,H

Step-by-step explanation:

i got 100% on edge!

Answer:

58 square units.

Step-by-step explanation:

From the graph attached,

Area of the figure = Area of the rectangle A + Area of two squares B and C

Area of rectangle A = Length × width

                                 = 10 × 5

                                 = 50 square units

Area of the square B = (Side)²

                                   = (2)²

                                   = 4 square units

Similarly area of the square C = 2² = 4 square units

Area of the total figure = 50 + 4 + 4

                                      = 58 square units

Therefore, 58 square units will be the answer.

Answer:

The option B, perfectly gives it to the target, because if you think about it, four less, means 4-, but backwards, and three times, means 3x, and if you put that together, that perfectly matches the one you are looking for. Hope that this would help you!

Step-by-step explanation:

Answer:

b

Step-by-step explanation:

Answer:

Step-by-step explanation:

P (m) = a (m + 1) + b (m + 1) - c (m + 1)

P (m) = (a + b - c) (m + 1)

There are 2 prime factors

Answer:

Step-by-step explanation:

eliminate either vraible, here it is easy to eleimate y, by just subtacting, then solve for x. When you get the value of x, plug in one of the equation and find y. ther you go

Answer:

x= 3.8

y= -29.3

Step-by-step explanation:

Answer:

9 squares

Step-by-step explanation:

An equilateral has three equal sides.  You can have two squares on each side: AB, one in which the triangle, ABC, falls within the square and the other where the square does not contain the triangle, ABC.  You can also have two squares on each side - BC, one in which the triangle, ABC, falls within the square and the other where the square does not contain the triangle, ABC.  Again, you can have two squares on each side - CA, one in which the triangle, ABC, falls within the square and the other where the square does not contain the triangle, ABC.  In addition, AB, BC and CA can be a diagonal of squares.  

TL;DR

In conclusion, you have 9 squares in all - 3 as diagonals of squares and 6 as sides of squares. Brainliest appreciated!

No square shares more than two vertices with the equilateral triangle, so we can find the number of squares having two of their vertices at two given points and triple the result. Given 2 points, 3 squares may be drawn having these points as vertices. The figure below shows a red equilateral triangle with the 3 squares that correspond to one of the sides of the triangle. Therefore, 9 squares share two vertices with the equilateral triangle.

Answer: A

Step-by-step explanation

2.167x10^4 = 21,670

                   = 9,978

1.1x10^6      = 1100,000

                   = 56,344,000

2.468x10^5 =  246,800

Answer: A. 9,978

Based on the power, move the decimal point that many spaces to the right. (E.g., If it's 4.2 × 10^3, then move the decimal three spaces to the right, and you'd get 4200.)

2.167 × 10^4 = 21670

1.1 × 10^6 = 1100000

2.468 × 10^5 = 246800

Out of all the numbers mentioned in the question, 9,978 is the only one that's less than 2.167 × 10^4 = 21670.

Answer:

[tex] f = 12.7 [/tex]

Step-by-step explanation:

Given:

<H = 94°

FG = h = 15

<F = 58°

GH = f = ?

Use the law of sines to find f:

[tex] \frac{f}{sin(F)} = \frac{h}{sin(H)} [/tex]

[tex] \frac{f}{sin(58)} = \frac{15}{sin(94)} [/tex]

[tex] \frac{f}{0.848} = \frac{15}{0.998} [/tex]

[tex] \frac{f}{0.848} = 15.03 [/tex]

Multiply both sides by 0.848

[tex] \frac{f}{0.848}*0.848 = 15.03*0.848 [/tex]

[tex] f = 15.03*0.848 [/tex]

[tex] f = 12.74544[/tex]

[tex] f = 12.7 [/tex] (nearest tenth)

Answer:

p²q³ + pq and pq(pq² + 1)

Step-by-step explanation:

Given

3p²q² - 3p²q³ +4p²q³ -3p²q² + pq

Required

Collect like terms

We start by rewriting the expression

3p²q² - 3p²q³ +4p²q³ -3p²q² + pq

Collect like terms

3p²q² -3p²q² - 3p²q³ +4p²q³ + pq

Group like terms

(3p²q² -3p²q²) - (3p²q³ - 4p²q³ ) + pq

Perform arithmetic operations on like terms

(0) - (-p²q³) + pq

- (-p²q³) + pq

Open bracket

p²q³ + pq

The answer can be further simplified

Factorize p²q³ + pq

pq(pq² + 1)

Hence, 3p²q² - 3p²q³ +4p²q³ -3p²q² + pq is equivalent to p²q³ + pq and pq(pq² + 1)

Answer:

Proved.

Step-by-step explanation:

The functions are:

1.) f(x) = 3x - 27 (* I am giving an answer using this equation. Perhaps you did't copy the question well!)

2.) g(x) = [tex]\frac{1}{3} x[/tex] + 9

If two functions are inverses of each other, then:

f(g(x)) = x and g(f(x)) = x situation must be satisfied.

f(g(x)) = 3([tex]\frac{1}{3}x + 9[/tex]) + 27

We simply it to get;

f(g(x)) = x - 27 + 27 = x (*This is correct)

g(f(x)) = [tex]\frac{1}{3}[/tex](3x - 27) + 9 = x - 9 + 9 = x (* This is also correct!)

Answer: About 99.74% of births would be expected to occur within 24 days of the mean pregnancy length.

Step-by-step explanation:

Complete question is attached below.

Given: The lengths of pregnancy terms for a particular species of mammal are nearly normally distributed about a mean pregnancy length with a standard deviation of 8 days.

i.e. [tex]\sigma= 8[/tex]

let X denotes the random variable that represents the lengths of pregnancy.

The probability of births would be expected to occur within 24 days of the mean pregnancy​ length:

[tex]P(\mu-24<X<\mu+24)=P(\dfrac{\mu-24-\mu}{8}<\dfrac{X-\mu}{\sigma}<\dfrac{\mu+24-\mu}{8})\\\\=P(\dfrac{-24}{8}<Z<\dfrac{24}{8})\ \ \ [\because Z=\dfrac{X-\mu}{\sigma}]\\\\=P(-3<Z<3)\\\\=P(Z<3)-P(Z<-3)\\\\=P(Z<3)-(1-P(Z<3))\\\\=2P(Z<3)-1[/tex]

[tex]= 2(0.9987)-1\ \ \ [\text{ By z-table}]\\\\=0.9974[/tex]

=99.74%

Hence, about 99.74% of births would be expected to occur within 24 days of the mean pregnancy length.

Answer:

Un número entero es un número entero que puede ser positivo, negativo o cero. Ejemplos de enteros son: -5, 1, 5, 8, 97 y 3,043. Ejemplos de números que no son enteros son: -1.43, 1 3/4, 3.14,. 09 y 5.643,1.

Answer:

Step-by-step explanation:

[x/2-2/1] × [2x^2 + x -3]

we can solve this very simply by multiplication

Answer:

x=6

Step-by-step explanation:

Take -2 and add it to 10 and get 12. So then the equation is 2x=12. Divide 2 by 12 and get x=6.

Answer:

For this case we know that [tex]\frac{2\pi}{3}= 120 degrees[/tex]. For this case we want to find:

[tex] arctan(tan(\frac{2\pi}{3}))[/tex]

Since the tan and arctan functions are inverse when we apply bth at the same time we got the identity function so then we got for this case:

[tex]  arctan(tan(\frac{2\pi}{3})) = I(\frac{2\pi}{3}) = \frac{2\pi}{3}[/tex]

Step-by-step explanation:

For this case we know that [tex]\frac{2\pi}{3}= 120 degrees[/tex]. For this case we want to find:

[tex] arctan(tan(\frac{2\pi}{3}))[/tex]

Since the tan and arctan functions are inverse when we apply bth at the same time we got the identity function so then we got for this case:

[tex]  arctan(tan(\frac{2\pi}{3})) = I(\frac{2\pi}{3}) = \frac{2\pi}{3}[/tex]

Answer: 36

Step-by-step explanation:

From the question, we are informed that six numbers has an average of 42. This means that the total number will be equal to:

= 42 × 6

= 252

When three of this numbers were removed the remaining three numbers had an average of 72. The total of this will be:

= 72 × 3

= 216

The sum of the removed numbers will be the difference between the two numbers above. This will be:

= 252 - 216

= 36

Answer:

15.7 yd

Step-by-step explanation:

Arc length is given as 2πr(θ/360).

Where,

Radius (r) = 10 yd,

Measure of arc (θ) = 90°

π = 3.142

Arc length = 2*3.142*10(90/360)

Arc length = 62.84(¼)

Arc length = 62.84/4

Arc length = 15.71 yd

The act length is approximately 15.7 (to the nearest tenth)

Answer:

My conclusion about Quadrilaterals ABCD and EFCD is that both quadrilaterals are similar to each other.

THE REASON IS BECAUSE THE SIDES OF QUADRILATERAL ABCD ARE THE SAME AS THE SIDES OF QUADRILATERAL EFCD.

Step-by-step explanation:

When we are given vertices, (x1, y1) , (x2 ,y2), we use the formula:

√(x2 - x1)² + (y2 - y1)²

For quadrilateral ABCD are A(4, 8), B(10, 10), C(10, 4), and D(4, 4)

Side AB: A(4, 8), B(10, 10)

√(x2 - x1)² + (y2 - y1)²

√(10 - 4)² + (10 - 8)²

= √6² + 2²

= √40

Side BC: B(10, 10), C(10, 4)

√(x2 - x1)² + (y2 - y1)²

= √(10 - 10)² + ( 4 - 10)²

= √ 0² + (-6)²

= √36

= 6

Side CD: C(10, 4), D(4, 4)

√(x2 - x1)² + (y2 - y1)²

= √ (4 - 10)² + ( 4 - 4)²

= √-6² + 0²

= √36

= 6

Side AD: A(4, 8), D(4, 4)

=√(x2 - x1)² + (y2 - y1)²

= √(4 - 4)² + (4 - 8)²

= √0² + (-4²)

= √16

= 4

Therefore, for Quadrilateral ABCD

Side AB = √40

Side BC = 6

Side CD = 6

Side AD = 4

For quadrilateral EFCD are E(4, 0), F(10, -2), C(10, 4), and D(4, 4).

Side EF: E(4, 0), F(10, -2)

√(x2 - x1)² + (y2 - y1)²

= √(10 - 4)² + (-2 - 0)²

= √6² + 2²

= √40

Side FC: F(10, -2), C(10, 4)

√(x2 - x1)² + (y2 - y1)²

= √(10 - 10)² + (4 -(-2))²

= √ 0² + 6²

= √36

= 6

Side CD: C(10, 4), D(4, 4)

√(x2 - x1)² + (y2 - y1)²

= √(10 - 4)² + (4 - 4)²

= √6² + 0²

= √36

= 6

Side ED: E(4, 0), D(4, 4)

√(x2 - x1)² + (y2 - y1)²

= √(4 - 4)² + (4 - 0)²

= √0² + 4²

= √16

= 4

Therefore, for Quadrilateral EFCD

Side EF = √40

Side FC = 6

Side CD = 6

Side ED = 4

My conclusion about Quadrilaterals ABCD and EFCD is that both quadrilaterals are similar to each other.

THE REASON IS BECAUSE THE SIDES OF QUADRILATERAL ABCD ARE THE SAME AS THE SIDES OF QUADRILATERAL EFCD.

Answer:

Surface area of the roof of the kennel, including the bottom face is 58.96 ft^2

Step-by-step explanation:

The image is attached below

For the triangular sides of the roof, area is

A = [tex]\frac{1}{2}bh[/tex]

where b is the base = 4 ft

h is the vertical height = 2.24 ft

A =  [tex]\frac{1}{2}*4*2.24 =[/tex] 4.48 ft^2

for the two faces we have 2 x 4.48 ft^2 = 8.96 ft^2

For the rectangular sections of the roof, area is

A = [tex]lh[/tex]

where [tex]l[/tex] is the length of the rectangle = 5 ft

h is the height of the rectangle = 3 ft

A = 5 x 3 = 15 ft^2

For the two rectangular faces, we have 2 x 15 ft^2 = 30 ft^2

For the bottom face, area is

A = [tex]lw[/tex]

where [tex]l[/tex] is the length of the house = 5 ft

w is the width of the house = 4 ft

A = 5 x 4 = 20 ft^2

Surface area of the roof of the dog kennel is

8.96 ft^2 + 30 ft^2 + 20 ft^2 = 58.96 ft^2

Answer:

fourth option

Step-by-step explanation:

Given

3x³ + 3x² - 18x ← factor out 3x from each term

= 3x(x² + x - 6) ← factor the quadratic

Consider the factors of the constant term (- 6) which sum to give the coefficient of the x- term (+ 1)

The factors are + 3 and - 2, since

3 × - 2 = - 6 and 3 - 2 = + 1, thus

x² + x - 6 = (x + 3)(x - 2) and

3x³ + 3x² - 18x = 3x(x + 3)(x - 2) ← in factored form

Answer:

when t is increased , h will increased too

Answer:

Th relationship is linear because  H increases by 30 each time t increases by 1.

Step-by-step explanation:

H is linear if it changes at a constant rate per unit interval. In other words, constant differences in t should correspond to constant differences in H.

Answer:  x + 2x + x-40 = 180

First angle= 55º

Second angle= 110º

Third angle= 15º

​Step-by-step explanation:  The sum of the angles of a triangle is 180º

Take the values given and  use x as the unknown first angle. then create terms for the other two angles based on that:

The second angle of a triangle is double the first angle  becomes 2x

The third angle is 40 less than the first angle becomes x-40

x + 2x + x-40 = 180  Solve by adding like terms . x + 2x + x = 4x

4x -40 = 180   Add 40 to both sides to "cancel" the -40 on the left

4x + 40 -40 = 180 + 40   becomes  

4x = 220  Divide both sides by 4 to "cancel" the 4 on the left side

4x/4 = 220/4

x = 55   This is the first angle. Substitute 55 for the  "x" in the original terms

2(55) = 110   The second angle

(55) -40 = 15   the third angle

Answer:

The last option

Step-by-step explanation:

Source: Trust bro

Answer:

d) y sqrt 5

Step-by-step explanation:

radicals are like if they have the same index and radicand, here they are both square roots and have a radicand of five

Answer:

∠A=123°.

Step-by-step explanation:

From the given figure it is clear the CD and CE are two tangent lines on circle with center A.

Radius is perpendicular to the tangent at the point of tangency.

[tex]\angle ADC=90^{\circ}[/tex]

[tex]\angle AEC=90^{\circ}[/tex]

Smaller arc DE = (5x-2)°

It means central angle DAE is (5x-2)°.

[tex]\angle DAE=(5x-2)^{\circ}[/tex]

Now, ADCE is a quadrilateral and sum of all angles of a quadrilateral is 360 degrees.

[tex]\angle ADC+\angle DCE+\angle AEC+\angle DAE=360^{\circ}[/tex]

[tex]90^{\circ}+(2x+7)^{\circ}+90^{\circ}+(5x-2)^{\circ}=360^{\circ}[/tex]

[tex](7x+5)^{\circ}+180^{\circ}=360^{\circ}[/tex]

[tex](7x+5)^{\circ}=360^{\circ}-180^{\circ}[/tex]

[tex](7x+5)^{\circ}=180^{\circ}[/tex]

[tex]7x+5=180[/tex]

[tex]7x=175[/tex]

[tex]x=25[/tex]

The value of x is 25.

[tex]\angle A=5x-2=5(25)-2=125-2=123^{\circ}[/tex]

Therefore, the measure of ∠A is 123°.

Answer:

10x^2 + 8x

Step-by-step explanation:

Area of the outer rectangle = 5x(3x + 2) = 15x^2 + 10x

Area of the inner rectangle = x(5x - 2) = 5x^2 - 2x

Area of the shaded region = (15x^2 + 10x) - (5x^2 - 2x)

= 10x^2 + 8x

5x(3x + 2) - x(5x - 2) required expression.

Step-by-step explanation:

I get there are 2 rectangles in figure.

How can I get the area of shaded region? What if, I subtract the area of inner rectangle from outer rectangle. Ya It will surely work (⌒o⌒).

Now,

Area of outer rectangle = [tex]\sf length \times breadth[/tex]

[tex]5x \times (3x + 2)[/tex]

[tex]5x(3x + 2)[/tex]

Again,

Area of inner rectangle = [tex]\sf length \times breadth[/tex]

[tex]=x \times (5x - 2)[/tex]

[tex]=x(5x - 2)[/tex]

[tex] \sf Area \:of \:Shaded\: region = \: Area_{\:outer}-Area_{\:inner}[/tex]

[tex] \sf \: 5x(3x + 2) - x(5x - 2)[/tex]

If We simplify further then,

= 15x² + 10x - 5x² + 2x

= 10x² + 12x

Area of shaded region is 10x² + 12x in a simple way.

Answer:

18.5

Step-by-step explanation:

In the above question, we are given the following values

Cumulative probability ( confidence interval) = 0.95 = 95%

Mean = 10.5

Standard deviation = 4.10

We are asked to find the value of x.

To solve for x , we would be using the z score formula.

z score = (x-μ)/σ,

where x is the raw score,

μ is the population mean

σ is the population standard deviation

z score was not given in the question, but we have our cumulative probability as 95%(0.95).

Using the appropriate table,

the z score for 95% confidence is z = 1.96.

Therefore,

z score = (x-μ)/σ,

1.96 = x - 10.5/4.10

Cross multiply

1.96×4.10 = x - 10.5

x = (1.96 × 4.10) + 10.5

x = 8.036 + 10.5

x = 18.536

Approximately to 1 decimal place

x = 18.5

Answer:

22.5 cm

Triangle area is (L x W) / 2

7.5 x 6 = 45

45 / 2 = 22.5

Step-by-step explanation:

brainlist plzzzz

Answer:

(1,-2)

Step-by-step explanation

y = -3x + 1

y = 2x - 4

-3x + 1 = 2x - 4

-5x + 1 = -4

-5x = -5

x = 1

y= 2(1) - 4

y = 2 - 4

y = -2

(1,-2)

Answer:

1/2

Step-by-step explanation:

Answer:

Step-by-step explanation:

1. We can clear fractions and solve the resulting quadratic. We clear fractions by multiplying the equation by the product of the denominators.

  [tex]\dfrac{2x+1}{2x-1}-\dfrac{2x-1}{2x+1}=\dfrac{8}{3}\\\\3((2x+1)^2-(2x-1)^2)=8(2x-1)(2x+1)\\\\3(8x) = 8(4x^2 -1)\\\\4x^2 -3x -1 = 0\qquad\text{factor out 8, subtract 3x}\\\\x=\dfrac{-(-3)\pm\sqrt{(-3)^2-4(4)(-1)}}{2(4)}=\dfrac{3\pm\sqrt{25}}{8}\\\\x=\dfrac{3\pm5}{8}=\left\{-\dfrac{1}{4},1\right\}[/tex]

__

2. Using the same idea here, we get ...

  [tex]\dfrac{2}{x-2}+\dfrac{3}{x}=\dfrac{9}{x+3}\\\\2(x)(x+3)+3(x-2)(x+3)=9(x-2)(x)\\\\2x^2+6x+3(x^2+x-6)=9x^2-18x\\\\4x^2-27x+18=0\\\\x=\dfrac{-(-27)\pm\sqrt{(-27)^2-4(4)(18)}}{2(4)}=\dfrac{27\pm\sqrt{441}}{8}\\\\x=\dfrac{27\pm21}{8}=\left\{\dfrac{3}{4},6\right\}[/tex]