On average, a clothing store gets 120 customers per day. What is the probability that the store will have fewer than 12 customers in the first two hours? (Assume the store is open 12 hours each day. Round your answer to four decimal places. )

Answer:

7 ft is 84 inches, 3ft is 36 inches

84 - 36 = 48

cuts off 18 more inches

48 - 18 = 30 inches of rope remain

Step-by-step explanation:

Answer:

7.5 feet

Step-by-step explanation:

Divide the length value by 12 for your answer

90/12 = 7.5

There are 12 inches in a foot, so to convert inches to feet, you can divide the number of inches by 12.

Therefore, a 90-inch cage is equivalent to:

90 inches ÷ 12 inches/foot = 7.5 feet

So the bird cage is 7.5 ft.

Answer:

mine either hahahahahaha

Answer:

-2

Step-by-step explanation:

Whenever you see f(x), for any number x, you plug x into the function. In your function, f(x) = -x - 1, you want to find f(1).

So, f(1) = -(1) - 1, which equals -2

From the given information provided, A is crest, B is wavelength, C is  trough, D is amplitude, E is equilibrium line in the transverse wave.

Amplitude: The maximum displacement of wave from its equilibrium position. In other words, it is the height of the wave measured from the midpoint (or equilibrium position) to the crest or trough.

Wavelength: The distance between two consecutive crests or troughs of a wave. It is usually denoted by Greek letter lambda (λ) and measured in meters.

Crest: The highest point or peak of a wave. It is the point on the wave with maximum positive displacement from the equilibrium position.

Trough: The lowest point of a wave. It is the point on the wave with maximum negative displacement from the equilibrium position.

Equilibrium: The position where there is no net force acting on an object. In the context of waves, the equilibrium position is the position where there is no displacement of the medium through which the wave is travelling.

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In answering the question above, the solution is Zany thus has 1,533.75 expressions pounds more apples than Peter does.

In mathematics, you can multiply, divide, add, or take away. The following is how an expression is put together: Numeric value, expression, and math operator The elements of a mathematical expression include numbers, parameters, and functions. It is feasible to use contrasting words and expressions. Any mathematical statement containing variables, numbers, and a mathematical action between them is known as an expression, often known as an algebraic expression. As an example, the expression 4m + 5 is composed of the expressions 4m and 5, as well as the variable m from the above equation, which are all separated by the mathematical symbol +.

There are 412 bags of apples in all, with 10 apples in each bag, at Zany. Zany thus has a total of:

412 bags multiplied by 10 bags is 4,120 apples.

24,720 ounces is equal to 4,120 apples at 6 ounces each.

16,080 pounds divided by 24,720 ounces is 1,545 pounds.

Peter has a total of three bags of apples, or:

30 apples are equal to 3 bags times 10 bags

Each of Peter's apples weighs 6 ounces, making his total apple weight:

30 apples divided by 6 ounces each equal 180 ounces.

160 ounces / 16 ounces per pound equals 11.25 pounds.

After deducting Peter's weight from Zany's weight, we can determine how many pounds more apples Zany possesses than Peter:

11 pounds less than 1,545 pounds is 1,533.75 pounds.

Zany thus has 1,533.75 pounds more apples than Peter does.

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Set B, which contains the elements 11, 15, 19, 23, 27, 31, 4n+7 and so on, is an infinite set because there exists a one-to-one correspondence between set B and a proper subset of itself, namely set F, which contains the odd integers greater than or equal to 15.

To expose that set b is infinite, we want to set up a one-to-one correspondence among set B and A proper subset of itself. Allow F to be the set of odd integers greater than or equal to 15, i. E., F = {15, 19, 23, 27, ...}.We are able to outline a characteristic f from set b to set f as follows:

f(11) = 15

f(15) = 19

f(19) = 23

f(23) = 27

f(27) = 31

f(4n+7) = 4(n+2) + 3

the first five factors of set b are mapped to the primary 5 factors of set f. For any detail 4n+7 in set b, the corresponding detail in set f is 4(n+2)+3, which is the next peculiar integer after 4n+7. It may be shown that this function is a one-to-one correspondence between set b and set f.

Consequently, given that set f is a proper subset of set b and there exists a one-to-one correspondence among them, set b should be infinite.

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This is the appropriate set notation for the set J, which includes all integers between -5 and -3.

The set J can be rewritten by listing its elements in the appropriate set notation. Since the set J contains all integers between -5 and -3, we can list the elements as follows:

An integer is the number zero, a positive natural number or a negative integer with a minus sign. The negative numbers are the additive inverses of the corresponding positive numbers.

J = {-5, -4}

In set notation, this can be written as:

J = {x | x is an integer and -5 <= x < -3}

Therefore, the set J can be rewritten as:

J = {-5, -4}

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We have shown that ∫_((a,b])▒〖G(x)dF(x)=F(b)G(b)-F(a)G(a)-∫_((a,b])▒〖F(x)dG(x)〗〗 as required.

The given statement is that F and G are two cumulative distribution functions on the real line, and they have no common points of discontinuity in the interval (a, b). We need to show that ∫_((a,b])▒〖G(x)dF(x)=F(b)G(b)-F(a)G(a)-∫_((a,b])▒〖F(x)dG(x)〗〗

First, we can use the fact that F and G are cumulative distribution functions to write the integral of G(x)dF(x) as the difference of the product of F and G at the endpoints of the interval:

∫_((a,b])▒〖G(x)dF(x)=F(b)G(b)-F(a)G(a)〗

Similarly, we can write the integral of F(x)dG(x) as the difference of the product of F and G at the endpoints of the interval:

∫_((a,b])▒〖F(x)dG(x)=F(b)G(b)-F(a)G(a)〗

Subtracting the second equation from the first gives us:

∫_((a,b])▒〖G(x)dF(x)-∫_((a,b])▒〖F(x)dG(x)=F(b)G(b)-F(a)G(a)-F(b)G(b)+F(a)G(a)〗

Simplifying the right-hand side of the equation gives us:

∫_((a,b])▒〖G(x)dF(x)-∫_((a,b])▒〖F(x)dG(x)=0〗

Therefore, we have shown that ∫_((a,b])▒〖G(x)dF(x)=F(b)G(b)-F(a)G(a)-∫_((a,b])▒〖F(x)dG(x)〗〗 as required.

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The equatiοn οf the least squares regressiοn line which mοst clοsely matches the data set is y = 3.5 x + 43.8

Tο sοlve fοr the data set, lets lοοk at the table,

X            1190         1992          1994         1996           1998

Y             45             51               57            61               75

Let the equatiοn that shοws the abοve data be

y = b + a x ---------(1)

Where, a = Σy Σx² - Σx Σxy

And, b = (Σxy - Σx Σy) / n Σx² -(Σx)²

By the abοve table,

Σx=20

Σxy = 1296

Σx² = 120

Σy=289

By substituting these values in the abοve value οf a and b,

We get b = 43.8 and a = 3.5

Substitute this value in equatiοn (1)

We get, the equatiοn that shοws the given data is,

y = 3.5 x + 43.8

Therefοre, οptiοn 3 is cοrrect.

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The two integer values of a for which the quadratic equation x² + ax + 8a = 0 have integer solutions are

A quadratic equation is an polynomial in which the highest power of the variable is 2.

Since we have the equation x² + ax + 8a = 0, we desire to find how many integer values of a that will make the equation have integer solution.

To do that, we use the discriminant of a quadratic equation

D = b² - 4ac where

Now, for a quadratic equation to have real solutions D ≥ 0

So, b² - 4ac ≥ 0

Now from the equation we have that

So, substituting the values of the variables into D, we have that

D = b² - 4ac

a² - 4(1)(8a) ≥ 0

a² - 32a ≥ 0

For integer values of a

a² - 32a = 0

a(a - 32) = 0

a = 0 or a - 32 = 0

a = 0 or a = 32

So, we have two integer values of a which are

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Answer:

a) 7

b) 0.1

Step-by-step explanation:

a)

The width must be able to go up to 35.

Each square is 5 units wide.

35/5 = 7

The grid must be at least 7 squares wide.

b)

The highest y-coordinate is 1.7.

The highest point on the grid should be 2.

There are 20 vertical squares on the grid.

2/20 = 0.1

Each vertical square should be 0.1

A = 0.1

Answer:

12xphjzjhsgwghdghehdhhez7uehdyegd

a. The average velocity between 1s and 5s is -30 m/s.
b. The average velocity between 5s and 9s is -70 m/s
c. The velocity at -5 is -50 m/s.

A. The average velocity between 1 s and 5 s can be calculated by finding the displacement divided by the time interval. The displacement is the difference between the final and initial positions, which can be found by plugging in the values of t into the equation s(t) = 500 - 5t^2.
So, s(1) = 500 - 5(1)^2 = 495 m and s(5) = 500 - 5(5)^2 = 375 m.

The displacement is 375 - 495 = -120 m. The time interval is 5 - 1 = 4 s.

Therefore, the average velocity is -120 m / 4 s = -30 m/s.

B. The average velocity between 5 s and 9 s can be calculated in the same way. s(5) = 375 m and s(9) = 500 - 5(9)^2 = 95 m.

The displacement is 95 - 375 = -280 m. The time interval is 9 - 5 = 4 s.

Therefore, the average velocity is -280 m / 4 s = -70 m/s.

C. The velocity at t = 5 can be found by taking the derivative of the position function s(t) = 500 - 5t^2.

The derivative is s'(t) = -10t. Plugging in t = 5 gives s'(5) = -10(5) = -50 m/s.

So the velocity at t = 5 is -50 m/s.

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As per the difference concept, the bearing of Q from P is 132°.

To find the bearing of Q from P, we need to calculate the difference between the bearing of P from Q and 180 degrees. This is because the bearing from P to Q is the opposite direction of the bearing from Q to P.

Let's use some notation to make this clearer. Let the bearing from P to Q be denoted by B(PQ), and the bearing from Q to P be denoted by B(QP). We are given that B(PQ) = 312°. To find B(QP), we use the following formula:

B(QP) = B(PQ) - 180°

We know that B(PQ) is 312°, so we can substitute this value into the formula to get:

B(QP) = 312° - 180°

B(QP) = 132°

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a) The probability that a person spent more than $28 is of: 0.2033 = 20.33%.

b) The probability that a person spent between $9 and $21 is given as follows: 0.3608 = 36.08%.

c) The middle 95% of the amounts falls between $11.24 and $34.76.

The z-score of a measure X of a variable that has mean symbolized by [tex]\mu[/tex] and standard deviation symbolized by [tex]\sigma[/tex] is obtained by the rule presented as follows:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The mean and the standard deviation for the problem are given as follows:

[tex]\mu = 23, \sigma = 6[/tex]

The probability of a person spending more than $28 is one subtracted by the p-value of Z when X = 28, hence:

Z = (28 - 23)/6

Z = 0.83

Z = 0.83 has a p-value of 0.7967

1 - 0.7967 = 0.2033.

The probability of a person spending between $9 and $21 is given by the p-value of Z when X = 21 subtracted by the p-value of Z when X = 9, hence:

Z = (21 - 23)/6

Z = -0.33

Z = -0.33 has a p-value of 0.3707

Z = (9 - 23)/6

Z = -2.33

Z = -2.33 has a p-value of 0.0099.

0.3703 - 0.0099 = 0.3608 = 36.08%.

The middle 95% of amounts is between the 2.5th percentile(Z = -1.96) and the 97.5th percentile, Z = 1.96, hence:

-1.96 = (X - 23)/6

X - 23 = -1.96 x 6

X = 11.24.

1.96 = (X - 23)/6

X - 23 = 1.96 x 6

X = 34.76.

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Answer: A

Step-by-step explanation:

A best represents the graph

Using quadratic formula we get, Part A: The solutions for x are: x = (3 + √(57))/(3/2) and x = (3 - √(57))/(3/2). Part B: The first system solution is: ((3 + √(57))/(3/2), -(76 + 6√(57))/(9) + 5)  and second system solution is:                                                 ((3 - √(57))/(3/2), -(76 - 6√(57))/(9) + 5)

Part A: To solve for x, we need to first rearrange the equation so that all terms are on one side of the equal sign.  Adding (1/4)x^(2) to both sides of the equation:
-x^(2) + (1/4)x^(2) + 3x + 14 = 5

Next, combining like terms:
-(3/4)x^(2) + 3x + 14 = 5

Now, subtracting 5 from both sides:
-(3/4)x^(2) + 3x + 9 = 0

Finally, using quadratic formula to solve for x:
x = (-3 ± √(3^(2) - 4(-3/4)(9)))/(2(-3/4))

Simplifying:
x = (-3 ± √(57))/(2(-3/4))
x = (-3 ± √(57))/(-3/2)
x = (3 ± √(57))/(3/2)

Part B: To determine the system solutions, we need to plug in the values of x into the original equation and solve for y. For the first solution:
y = -(1/4)((3 + √(57))/(3/2))^(2) + 5
y = -(1/4)((9 + 6√(57) + 57)/(9/4)) + 5
y = -(1/4)((76 + 6√(57))/(9/4)) + 5
y = -(19 + (3/2)√(57))/(9/4) + 5
y = -(76 + 6√(57))/(9) + 5

For the second solution:
y = -(1/4)((3 - √(57))/(3/2))^(2) + 5
y = -(1/4)((9 - 6√(57) + 57)/(9/4)) + 5
y = -(1/4)((76 - 6√(57))/(9/4)) + 5
y = -(19 - (3/2)√(57))/(9/4) + 5
y = -(76 - 6√(57))/(9) + 5

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Answer:

5 and 35

Step-by-step explanation:

It's going up in tens so it must start from 5, therefore the one between 25 and 45 must be 35.

The expression (18)(-3)(-3) is not equivalent to others.

-7+(-3) is equivalent of the expression -7 - 3.

What is an expression?

A mathematical operation such as subtraction, addition, multiplication, or division is used to combine terms into an expression. In a mathematical expression, the following terms are used:

An absolute numerical value is referred to as a constant.

Variable: A symbol without a fixed value is referred to as a variable.

Term: A term can be made up of a single constant, a single variable, or a mix of variables and constants multiplied or divided.

Coefficient: In an expression, a coefficient is a number that is multiplied by a variable.

Take the first option:

(-9)(-3 × -6)

= (-9)(18)

= (18)(-9)  [Commutative property]

= -(-18)(-9)

Apply the associative property on (-9)(-3 × -6):

(-9)(-3 × -6)

= (-9× - 3)(-6)

= (27) (-6)

= (-6)(27)   [Commutative property]

The given expression is -7 - 3

Rewrite the above expression:

-7+(-3)

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The ordered pairs for the linear equation, y=3x-13 is (0,-13), (1,-10), and (2,-7).

To complete the table of ordered pairs for the linear equation y=3x-13, we need to substitute different values of x into the equation and solve for y. This will give us the ordered pairs (x,y) for the equation.

Step 1: Choose a value for x. Let's start with x=0.

Step 2: Substitute the value of x into the equation and solve for y.
y=3(0)-13
y=-13

Step 3: Write the ordered pair (x,y) for this solution. In this case, the ordered pair is (0,-13).

Step 4: Repeat steps 1-3 for different values of x. Let's try x=1 and x=2.

For x=1:
y=3(1)-13
y=-10
The ordered pair is (1,-10).

For x=2:
y=3(2)-13
y=-7
The ordered pair is (2,-7).

Step 5: Complete the table with the ordered pairs that we found.

   x        y
   0      -13

   1       -10
 
   2        -7
 

So, the table of ordered pairs for the linear equation y=3x-13 is:
(0,-13), (1,-10), and (2,-7).

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As a result, 6% sales tax is applied.

%, which is a relative figure used to denote hundredths of any quantity. Since one percent (symbolized as 1%) is equal to one hundredth of something, 100 percent stands for everything, and 200 percent refers to twice the amount specified. percentage. Percentile in mathematics is a related topic.

The price of the snowboarder with tax compared to the price of the snowboarders without tax is the differential in the sales tax.

Sales tax therefore equals $848 - $800 = $48.

We need to multiply the result by 100 to get the sales percentage of tax, which we can then divide by the price of the snowboard before taxes.

Sales tax percentage = (Sales tax / Cost without tax) x 100

= ($48 / $800) x 100

= 0.06 x 100

= 6%

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As a result, 6% sales tax is applied.

%, which is a relative figure used tο denοte hundredths οf any quantity. Since οne percent (symbοlized as 1%) is equal tο οne hundredth οf sοmething, 100 percent stands fοr everything, and 200 percent refers tο twice the amοunt specified. percentage. Percentile in mathematics is a related tοpic.

The price οf the snοwbοarder with tax cοmpared tο the price οf the snοwbοarders withοut tax is the differential in the sales tax.

Sales tax therefοre equals $848 - $800 = $48.

We need tο multiply the result by 100 tο get the sales percentage οf tax, which we can then divide by the price οf the snοwbοard befοre taxes.

Sales tax percentage = (Sales tax / Cοst withοut tax) x 100

= ($48 / $800) x 100

= 0.06 x 100

= 6%

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The expected value of the number of tests taken is 1.92 an the variance of the number of tests taken is 1.5852 and the standard deviation is 1.259.

The expected value, variance, and standard deviation can be calculated using the following formulas:
Expected value (E) = ΣxP(x)
Variance (Var) = Σ(x - E)² P(x)
Standard deviation (SD) = √Var

a. To find the expected value of the number of tests taken, we can use the formula E = ΣxP(x), where x is the number of tests taken and P(x) is the probability of taking x tests.
E = (1)(22/50) + (2)(15/50) + (3)(8/50) + (4)(5/50)
E = 0.44 + 0.6 + 0.48 + 0.4
E = 1.92


b. To find the variance and standard deviation, we can use the formulas Var = Σ(x - E)² P(x) and SD = √Var.
Var = (1 - 1.92)²(22/50) + (2 - 1.92)² (15/50) + (3 - 1.92)² (8/50) + (4 - 1.92)^2 (5/50)
Var = 0.8464 + 0.0104 + 0.2928 + 0.4356
Var = 1.5852
SD = √1.5852
SD = 1.259

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Hence, the sum of the fixed expenses ($75 + $25 = $100) and the expressions variable charges ($15 per person) would equal the total cost for catering.

Mathematically speaking, you can multiply, divide, add, or subtract. This is how an expression is constructed: Math operation, expression, and numerical value Functions, parameters, and numbers make up a mathematical expression. It is feasible to use opposing words and phrases. An expression, sometimes referred to as an algebraic expression, is any mathematical statement that includes variables, numbers, and a mathematical operation between them. As an instance, the phrase 4m + 5 is made up of the phrases 4m and 5, as well as the variable m from the provided equation, which are all separated by the mathematical symbol +.

Finding the slope of the line will allow you to compute the rate of change for Smokey Joe's catering. The slope in this instance is $15, which indicates that the price will rise by $15 for each extra person served. The variable cost that Smokey Joe's incurs every person served is represented by this rate of change.

If Smokey Joe's charges a $25 delivery fee, this will be an extra set expense that they will pay no matter how many customers they serve. Hence, the sum of the fixed expenses ($75 + $25 = $100) and the variable charges ($15 per person) would equal the total cost for catering.

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Using basic arithmetic operations, we concluded that a) Bryony wrote more words in total than Arthur.

b) Bryony wrote 220 more words than Arthur.

The four basic mathematical operations are addition, subtraction, multiplication, and division.

a) In order to establish who wrote more words overall, we must total the words that each participant wrote. By dividing the typical words per minute by the total number of minutes each person worked, we may determine this:

Arthur: 65 minutes × 16 words/minute = 1040 words

Bryony: 90 minutes × 14 words/minute = 1260 words

Therefore, Bryony wrote more words in total than Arthur.

b) To find out how many more words Bryony wrote than Arthur, we can subtract Arthur's total from Bryony's total:

1260 words - 1040 words = 220 words

Hence, Bryony wrote 220 more words than Arthur.

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The figure represented here is a square pyramid.

With a square base and fοur triangular sides that are cοnnected at a vertex, a square pyramid is a three-dimensiοnal geοmetric οbject. It has a pentahedrοn shape with five faces.

Fοur triangles are jοined at each vertex tο a square fοundatiοn tο fοrm a square pyramid. It has a square fοundatiοn, and triangles with a shared vertex make up its side faces.

We can get the squared pyramidal figure by fοlding the triangles οf equal size frοm all the sides.

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1. True. The CPI is not just one index, but includes a large number of groups, subgroups and selected items, such as a food index, a medical care index and an entertainment index.

2. True. An index number is a percent that measures the change in price, quantity, value, or some other item of interest from one time to another.

The Consumer Price Index (CPI) is actually a collection of indices that measure the changes in prices of a wide range of goods and services.

The CPI includes several different groups, subgroups, and selected items, such as a food index, a medical care index, and an entertainment index.

Each of these indices is used to track the changes in prices of specific goods and services within that category.

An index number is a statistical measure that is used to compare the changes in prices, quantities, values, or other items of interest from one time period to another.

Index numbers are typically expressed as a percentage, with a base value of 100 representing the initial time period. Any changes in the index number from one time period to another reflect the percentage change in the item of interest over that time period.

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To find all the values of b that will make the trinomial 3x^(2)-bx+12 factorable, we need to use the discriminant of the quadratic formula. The discriminant is the part of the quadratic formula under the square root: b^(2)-4ac. If the discriminant is a perfect square, then the trinomial will be factorable.

So we plug in the values of a, b, and c from the trinomial: b^(2)-4(3)(12) = b^(2)-144.

We want this to be a perfect square, so we can set it equal to a perfect square and solve for b:

b^(2)-144 = 36

b^(2) = 180

b = sqrt(180)

b = 6sqrt(5)

So one value of b that will make the trinomial factorable is 6sqrt(5).

Now we can plug this value of b back into the trinomial and factor it:

3x^(2)-6sqrt(5)x+12 = 0

(3x-6)(x-sqrt(5)) = 0

So the factors of the trinomial are (3x-6) and (x-sqrt(5)).

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24 buckets of gravel are needed for 4 buckets of cement when making concrete tiles using the given ratio.

What is the ratio?

The ratio is a mathematical concept that represents the relationship between two quantities or values. It is defined as the comparison of two numbers by division, where the first number is called the "antecedent" and the second number is called the "consequent."

According to the given ratio, the amount of gravel needed is 6 times the amount of cement, or 6/1.

To find out how many buckets of gravel are needed for 4 buckets of cement, we can set up a proportion:

6/1 = x/4

where x is the number of buckets of gravel needed.

To solve for x, we can cross-multiply:

6 x 4 = 1 x x

24 = x

Hence, 24 buckets of gravel are needed for 4 buckets of cement when making concrete tiles using the given ratio.

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To solve the inequality -12x - 5 > 1 + 18x, we need to isolate the variable x on one side of the inequality. Here are the steps to do so:

1. Add 12x to both sides of the inequality to eliminate the -12x on the left side:
-5 > 1 + 30x

2. Subtract 1 from both sides of the inequality to eliminate the 1 on the right side:
-6 > 30x

3. Divide both sides of the inequality by 30 to isolate the variable x:
-6/30 > x

4. Simplify the fraction on the left side:
-1/5 > x

Therefore, the solution to the inequality is x < -1/5. The correct value of A is -1/5.

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