On a coordinate plane, 3 lines are shown. Line a has points (negative 3, 3) and (3, negative 3). Line b has points (negative 3, negative 2) and (2, 3). Line c is parallel to line b. If line b is perpendicular to line a, and line c is perpendicular to line a, what is the slope of line c? mc =

Answer:

The slope of line c is 1

Step-by-step explanation:

The given information are;

The coordinates of the points on the line a are; (-3, 3) and (3, -3)

The coordinates of the points on the line b are; (-3, -2) and (2, 3)

Line c ║ line b

Line b ⊥ line a

Line c ⊥ line a

Therefore, we have

The slope, [tex]m_c[/tex] of line c is equal to the slope, [tex]m_b[/tex], of line b Definition of parallel lines (The slopes of parallel lines are equal)

[tex]m_c[/tex] = [tex]m_b[/tex]

Therefore, the slope, m, of the line b is given as follows;

[tex]Slope, \, m =\dfrac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]

Where, for line b, (x₁, y₁) = (-3, -2) and  (x₂, y₂) = (2, 3), we have;

[tex]Slope, \, m_b =\dfrac{3-(-2)}{2-(-3)} = \dfrac{3 + 2}{2 + 3} = 1[/tex]

From [tex]m_c[/tex] = [tex]m_b[/tex] = 1, the slope of line c = 1.

Answer:

its 1

Step-by-step explanation:

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