The amount that the would be paid after 40% discount is $27
Word ProblemGiven Data
Cost of a shirt = $15Discount = 40%Let us find the cost of three shirt
= 15*3
= $45
Let us find 40% discount of $45
= 40/100*45
= 0.4*45
= $18
Let us find the amount after discount
= 45-18
= $27
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Matrices
[tex]\mathfrak{\huge{\orange{\underline{\underline{AnSwEr:-}}}}}[/tex]
Actually Welcome to the concept of Scalar factor Multiplication in Matrix.
So from the above matrix, -3A , is just simply multiplying the -3 to every element of the matrix, so we get as,
===> -3A = | -9 -18 |
| -24 -21 |
| -6 6 |
hence the correct option is B.
Problem Situation: Gabi buys tickets to the movies.
She buys 1 adult ticket for $14 and 3 youth tickets.
She pays a total of $35.
What is the cost of each youth ticket?
Complete the equation to represent this situation.
The letter t represents the cost of a youth ticket.
Let that be y
14+3y=35Now solve
3y=35-143y=21y=21/3y=7Each youth ticket costs 7$
Answer So you can add a number with the letter t and then add and then you can 35 dollers
HELP PLS 50 PTS! To the nearest 50 square feet, what is the area of the actual store?
Question 1 options:
2,350 square feet
2,450 square feet
2,500 square feet
2,400 square feet
○ 2,350 square feet
○ 2,450 square feet
○ 2,500 square feet
● 2,400 square feet answer
Step-by-step explanation:
wellcome
rip
Find the exact circumference of each circle using the given inscribed or circumscribed polygon.
Answer:
58π mi.
Step-by-step explanation:
The diameter of the circle = the hypotenuse of the right triangle ( by the angle subtended by a diameter theorem).
By Pythagoras:
diameter^2 = 40^2 + 42^2
= 3364
Diameter = 58 mi.
Now the circumference
= diameter * π
= 58π mi.
B form.
Given the system of equations below, write the system in AX
- 112 - 13y = - 62
72 - 3y = 25
[3]
Il
Answer:
[tex]X=\left[\begin{array}{cc}-5&2\\0&8\\8&1\end{array}\right][/tex]
Step-by-step explanation:
Solving the given matrix equation, we find ...
X = (1/4)(C - B)
These operations, subtraction and multiplication by a scalar, are done on a term-by-term basis. A calculator or spreadsheet can do these for you.
For example, the middle right term (row 2, col 2) is ...
(38 -6)/4 = 32/4 = 8
Answer:
[tex]X =\begin {bmatrix} -5 & 2\\0 &8\\8 & 1\end{bmatrix}[/tex]
Step-by-step explanation:
[tex] Given \:\: B=\begin {bmatrix} 8 & -2\\-1 & 6\\-8 & -10\end{bmatrix} \: and\: C=\begin {bmatrix} -12 & 6\\-1 & 38\\24 & -6\end{bmatrix}[/tex]
To Solve: 4X + B = C
[tex]\implies 4X + \begin {bmatrix} 8 & -2\\-1 & 6\\-8 & -10\end{bmatrix}=\begin {bmatrix} -12 & 6\\-1 & 38\\24 & -6\end{bmatrix}[/tex]
[tex]\implies 4X =\begin {bmatrix} -12 & 6\\-1 & 38\\24 & -6\end{bmatrix}- \begin {bmatrix} 8 & -2\\-1 & 6\\-8 & -10\end{bmatrix}[/tex]
[tex]\implies 4X =\begin {bmatrix} -12-8 & 6-(-2)\\-1 -(-1)& 38-6\\24-(-8) & -6-(-10)\end{bmatrix}[/tex]
[tex]\implies 4X =\begin {bmatrix} -12-8 & 6+2\\-1 +1 & 38-6\\24+8 & -6+10\end{bmatrix}[/tex]
[tex]\implies 4X =\begin {bmatrix} -20 & 8\\0& 32\\32 & 4\end{bmatrix}[/tex]
[tex]\implies X =\frac{1}{4}\begin {bmatrix} -20 & 8\\0& 32\\32 & 4\end{bmatrix}[/tex]
[tex]\implies X =\begin {bmatrix} \frac{-20}{4} & \frac{8}{4}\\\\\frac{0}{4}& \frac{32}{4}\\\\ \frac{32}{4} & \frac{4}{4}\end{bmatrix}[/tex]
[tex]\implies X =\begin {bmatrix} -5 & 2\\0 &8\\8 & 1\end{bmatrix}[/tex]
A repair company charges a one-time service fee and an hourly rate for the time needed to complete each job. The
table shows the amounts the company used for these charges over four consecutive years.
Charges for Repair Jobs
Year
12 3 4
Service Fee $20 $25 $30 $35
Hourly Rate $52$55 $58 $61
Part A
Using the data in the table, what would the company's service fee and hourly rate, in dollars, be in year 8? Enter
your answers in the first and second response boxes.
Part B
What total amount, in dollars, would the company charge for a job that requires 3 hours of work in year 9? Enter
your answer in the third response box.
Part A: Service Fee
Part 1: Hourly Rate
Answer:
A: Service Fee = $55
Hourly Rate = $ 73
B: $288
Step-by-step explanation:
A: the service rate increases by $5 per year, so year 8 would be $20 more than year 4 (5*4)
The hourly rate increases by $3 per year, so year 8 would be $12 more than year 4 (3*4)
B. Service fee for year 9 would be $60 ($5 more than year 8) and the hourly rate would be $76 per hour ($3 more than year 8). This gives you Service Fee + (Hourly rate * 3) = $60 + ($73*3) = $60 + $228 = $288
a radioactive substance that has half-life lof 32 years. Find the constant k in the decay formula for the substance
I put up 50 PTS if you just say a random word I will report you
Answer:
[tex]\displaystyle k = \frac{1}{32}\ln\frac{1}{2} \approx -0.02166[/tex]
Step-by-step explanation:
The decay formula is given by:
[tex]\displaystyle P(t) = P_0e^{kt}[/tex]
Where k is some constant, P₀ is the initial population, and t is the number of years.
Because the substance has a half-life of 32 years, P(t) = 1/2P₀ when t = 32. Substitute:
[tex]\displaystyle \frac{1}{2}P_0 = P_0 e^{k(32)}[/tex]
Solve for k:
[tex]\displaystyle \begin{aligned} \frac{1}{2} & = e^{32k} \\ \\ \ln\left(e^{32k}\right) & = \ln\left(\frac{1}{2}\right) \\ \\ 32k & = \ln\frac{1}{2} \\ \\ k & = \frac{1}{32}\ln\frac{1}{2} \\ \\ &\approx -0.02166\end{aligned}[/tex]
In conclusion, the value of k is about -0.02166.
The value of k in the exponential decay formula is k = 0.022
How to find the value of k?To find the constant k in the decay formula for the radioactive substance, we can use the formula for exponential decay, which is given by:
N(t) = N₀*exp(-kt)
where:
N(t) is the amount of the radioactive substance at time t.N₀ is the initial amount of the substance at t = 0 (time of measurement).e is the base of the natural logarithm (approximately 2.71828).k is the decay constant we need to find.t is the time elapsed (in this case, t is measured in years since the half-life is given in years).The half-life of the substance is the time it takes for half of the substance to decay, which is 32 years in this case. So, after one half-life, N(t) = N₀ / 2.
Now, let's set up the equation for one half-life:
N(t) = N₀ * exp(-k * 32)
Since N(t) = N₀ / 2 after one half-life, we can write:
N₀ / 2 = N₀ * e^(-k * 32)
Now, divide both sides by N₀:
1/2 = exp(-k * 32)
To solve for k, take the natural logarithm (ln) of both sides:
ln(1/2) = -k * 32
k = ln(1/2) / -32
k = 0.022
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Identify the lateral area and surface area of a regular square pyramid with base edge length 11 cm and slant height 15 cm, rounded to the nearest tenth.
The surface area of the square pyramid is: 451 cm²
The lateral surface area of the square pyramid = 330 cm²
What is the Lateral Surface Area and Surface Area of a Square Pyramid?Surface area = a² + 2al, where a is the base edge and l is the slant height.
Lateral Surface Area = 2al.
Given the following:
a = 11 cml = 15 cmSurface area = a² + 2al = 11² + 2(11)(15)
Surface area = 451 cm²
Lateral Surface Area = 2al = 2(11)(15)
Lateral Surface Area = 330 cm²
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The lateral and surface area of a square base pyramid with side length of 11 cm and slant height of 15 cm are 330 cm² and 451 cm².
Surface area of a pyramidsurface area = A + 1 / 2 ps
where
A = area of the basep = perimeter of the base s = slant heightTherefore,
surface area = 11² + 1 / 2 × (11 × 4) × 15
surface area = 121 + 1 / 2 × 44 × 15
surface area = 121 + 330
surface area = 451 cm²
Lateral area of a square pyramidlateral area = 1 / 2 ps
lateral area = 1 / 2 × 44 × 15
lateral area = 330 cm²
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round to nearest tenth. Please solve
0.48 divide 9.23
8 divide 6.43
0.4 divide 28.08
3.5 divide 2.29
.072 divide 345
2.1 divide 1.488
thank you
Answer:
.1, 1.2, 0, 1.5, 0, 1.4 // 19.2, .8, 70.2, .7, 4791.7, .7
Step-by-step explanation:
The first set is if you meant the first number divided BY the second and the second set of numbers is if you meant it vice versa. If it was worded better I could understand better.
Identify the range of the function shown in the graph.
Answer:
B.
Step-by-step explanation:
the range is the y values of the line.
so it would be [3, 6]
Circle the exponent
are positive 4 and negative 4 equal to each other?
Answer:
Step-by-step explanation:
no, because positive 4 is 8 more than negative 4.
Answer:
one positive n one negative equals a positive
Step-by-step explanation:
no?
Note: Enter your answer and show all the steps that you use to solve this problem in the space provided.
Find the value of x. Round to the nearest tenth. The diagram is not drawn to scale.
11
220
X
Answer: X is 11,
Step-by-step explanation:
Hope it helps you
ANSWERS THESEEESS!!!!
Find the length of the second base of a trapezoid with one base measuring 15 feet, a height of 7.6 feet, and an area of 98.8 square feet
answer choices
9 ft
10 ft
11 ft
12 ft
Answer:
11 feet
Explanation:
area of trapezoid: 1/2 * (a + b) * hHere given:
a = 15 feetheight = 7.6 feetarea = 98.8 feet²====================
Solving steps:
⇒ 1/2 * (15 + b) * 7.6 = 98.8
⇒ (15 + b) * 7.6 = 197.6
⇒ (15 + b) = 26
⇒ b = 11 ft
Let unknown be x
1/2(x+15.5)(7.6)=98.83.8(x+15.5}=98.8x+15.5=26x=26 .03-15.5x=10.53x≈11ftI WILL GIVE YOU 20 POINTS TO THOSE WHO ANSWER THIS QUESTION RIGHT NOOOO SCAMS AND EXPLAIN WHY THAT IS THE ANSWER
Calculus Problem
1. Find the volume of the solid whose base is bounded by the graphs of y = 8 - x^2and y = x^2,
with the indicated cross sections perpendicular to the x-axis:
a. Squares
b. Semi-Circles
C. Equilateral Triangles
The two parabolas intersect for
[tex]8-x^2 = x^2 \implies 2x^2 = 8 \implies x^2 = 4 \implies x=\pm2[/tex]
and so the base of each solid is the set
[tex]B = \left\{(x,y) \,:\, -2\le x\le2 \text{ and } x^2 \le y \le 8-x^2\right\}[/tex]
The side length of each cross section that coincides with B is equal to the vertical distance between the two parabolas, [tex]|x^2-(8-x^2)| = 2|x^2-4|[/tex]. But since -2 ≤ x ≤ 2, this reduces to [tex]2(x^2-4)[/tex].
a. Square cross sections will contribute a volume of
[tex]\left(2(x^2-4)\right)^2 \, \Delta x = 4(x^2-4)^2 \, \Delta x[/tex]
where ∆x is the thickness of the section. Then the volume would be
[tex]\displaystyle \int_{-2}^2 4(x^2-4)^2 \, dx = 8 \int_0^2 (x^2-4)^2 \, dx \\\\ = 8 \int_0^2 (x^4-8x^2+16) \, dx \\\\ = 8 \left(\frac{2^5}5 - \frac{8\times2^3}3 + 16\times2\right) = \boxed{\frac{2048}{15}}[/tex]
where we take advantage of symmetry in the first line.
b. For a semicircle, the side length we found earlier corresponds to diameter. Each semicircular cross section will contribute a volume of
[tex]\dfrac\pi8 \left(2(x^2-4)\right)^2 \, \Delta x = \dfrac\pi2 (x^2-4)^2 \, \Delta x[/tex]
We end up with the same integral as before except for the leading constant:
[tex]\displaystyle \int_{-2}^2 \frac\pi2 (x^2-4)^2 \, dx = \pi \int_0^2 (x^2-4)^2 \, dx[/tex]
Using the result of part (a), the volume is
[tex]\displaystyle \frac\pi8 \times 8 \int_0^2 (x^2-4)^2 \, dx = \boxed{\frac{256\pi}{15}}}[/tex]
c. An equilateral triangle with side length s has area √3/4 s², hence the volume of a given section is
[tex]\dfrac{\sqrt3}4 \left(2(x^2-4)\right)^2 \, \Delta x = \sqrt3 (x^2-4)^2 \, \Delta x[/tex]
and using the result of part (a) again, the volume is
[tex]\displaystyle \int_{-2}^2 \sqrt 3(x^2-4)^2 \, dx = \frac{\sqrt3}4 \times 8 \int_0^2 (x^2-4)^2 \, dx = \boxed{\frac{512}{5\sqrt3}}[/tex]
whats the value of 6.4•(8 + 15)
Answer: 147.2
Step-by-step explanation:
(8+15) = 23
23 x 6.4= 147.2
Answer: 147.2
Step-by-step explanation: 8+15= 23 so 23*6.4 is 147.2
PLEASE HELP
What can you say about the y-values of the two functions f(x) = 3x2 -3 and
g(x) = 2* -3?
A. f(x) and g(x) have equivalent minimum y-values.
B. f(x) has the smallest possible y-value.
C. The minimum y-value of g(x) approaches -3.
D. g(x) has the smallest possible y-value.
Answer:
g(x) has the smallest possible y-value of -3
Step-by-step explanation:
f(x) = 3ˣ - 3 This is an exponential graph shifted down three units. So, it has an asymptote at y = -3, which means it approaches -3 but does not touch it.Range: y > 3 (-3, ∞) g(x) = 7x² - 3 ⇒ g(x) = 7(x - 0)² - 3 This is a parabola with vertex at (0, -3) Range: y ≥ 3 [-3, ∞)
i need some help here... pls help 8th grade
help with geometry pleaseeee will mark the brainiest!
Answer:
384.29 in²
Step-by-step explanation:
The radius of these circles is 5 in.
- As the radii are equal, and 4 of them are used to make up the side of the square. [20 ÷ 4 = 5]
To find the area of circle, you use the formula [tex]\pi r^{2}[/tex]
[tex]\pi[/tex] · (5)² = 25[tex]\pi[/tex]
The area of the square equals the length x width
20 · 20 = 400
To find the area of the shaded region, subtract these values.
400 - 25[tex]\pi[/tex] ≈ 389.29 in²
NEED HELP STAT if you dont know the answer for sure then dont say it, 100 POINTS
Which statements include two quantities in the real world that are additive inverses?
Select each correct answer.
A rock climber ascends 19 feet and then descends 9 feet.
A child runs 10 feet to the right and then runs 10 feet to the left.
A person removes 14 cans from a shelf and puts 15 cans back on the shelf.
A person deposits $430 in to a bank account and then withdraws $430 from the account.
B
&
D
Step-by-step explanation:
Answer:
The Answers are A and D
Step-by-step explanation:
I took the test and got em right!
Huuuurrry plllzzzzzz. Determine the equation of the line that passes through the given points (2,6) and (4,16)
Linear equations are typically organized in slope-intercept form:
[tex]y=mx+b[/tex]
m is the slope of the lineb is the y-intercept (the value of y when the line passes through the y-axis)To find linear equations in slope-intercept form:
Determine the slopePlug the slope into the general formDetermine the y-intercept by isolating bPlug the b back into the equationSolving the QuestionWe're given:
The line passes through the points (2,6) and (4,16)First, determine the slope of the line.
[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex] where [tex](x_1,y_1)[/tex] and [tex](x_2,y_2)[/tex] are points that fall on the line
⇒ Plug in the given points (2,6) and (4,16):
[tex]m=\dfrac{16-6}{4-2}\\\\m=\dfrac{10}{2}\\\\m=5[/tex]
⇒ Therefore, the slope of the line is 5. Plug this back into the general form:
[tex]y=5x+b[/tex]
Now, determine the y-intercept.
[tex]y=5x+b[/tex]
⇒ Plug in one of the given points:
[tex]6=5(2)+b\\6=10+b\\b=-4[/tex]
⇒ Therefore, the y-intercept is -4. Plug this back into our original equation:
[tex]y=5x-4[/tex]
Answer[tex]y=5x-4[/tex]
All change 5. Three friends collected aluminum cans from the neighborhood to recycle. In total they collected 300 cans. Manny collected 90, Jim collected 100, and Bib collected 110. What percentage did each collect?
A. Manny 30% Jim 25% Bob 45%
B. Manny 30% Jim 33.3% Bob 36.7%
C. Manny 20% Jim 33.3% Bob 46.7%
D. Manny 18% Jim 42% Bob 50%
Please help I'll mark brainliest
Answer:
i think it b i dont know for sure
Step-by-step explanation:
I WILL GIVE 20 POINTS TO THOSE WHO ANSWER THIS QUESTION RIGHT NOOOO SCAMS PLEASE AND PLEASE EXPLAIN WHY THAT IS THE ANSWER
Answer:
x = 108 , y = 72
Step-by-step explanation:
x and 108 are alternate exterior angles and are congruent , then
x = 108
x and y are same- side exterior angles and sum to 180° , that is
x + y = 180
108 + y = 180 ( subtract 108 from both sides )
y = 72
Please help me! Thank you
Answer: 4
Step-by-step explanation: how i know by guessing
This equation shows the relationship between the amount of water (w), in liters, filled in Tank A and the number of minutes (m) it took to fill it.
w = 100 + 80.5m
This table shows the relationship between the amount of water, in liters, filled in Tank B and the number of minutes it took to fill the tank
Amount of water filled in Tank B:
Minutes: Amount of water: (liters)
0 154
2 384
6 844
What is the difference, in liters, between the total amount of water filled in Tank A and Tank B after 4 minutes?
Answer:
192 liters
Step-by-step explanation:
Tank A
w = 100 + 80.5m
where:
w = water in litersm = time in minutesTherefore, when m = 4:
⇒ w = 100 + 80.5(4) = 422 liters
Tank B
Given ordered pairs: (0, 154) (2, 384) (6, 844)
[tex]\sf slope\:(m)=\dfrac{change\:in\:y}{change\:in\:x}=\dfrac{384-154}{2-0}=115[/tex]
Point-slope form of linear equation: [tex]\sf y-y_1=m(x-x_1)[/tex]
(where m is the slope and (x₁, y₁) is a point on the line)
[tex]\sf \implies y-154=115(x-0)[/tex]
[tex]\sf \implies y=115x+154[/tex]
Therefore, the equation for Tank B is:
w = 115m + 154
Therefore, when m = 4:
⇒ w = 115(4) + 154 = 614 liters
Difference
614 - 422 = 192 liters
Find equation for tank B
(0,154)(2,384)Slope:-
m=384-154/2=230/2=115Equation in point slope form
w-154=115(m)w=115m+154For tank B
w=100+80.5mPut 4on both
Tank A:-
w=100+80.5(4)w=100+322w=422LTankB
w=115(4)+154w=460+154w=614LDifference:-
614-422192LPlease help me as soon as posable!! In hurry!!(24 points)
In a geometric sequence, a_ 2 = 2, a_ 3 = 20, and a_4 = 200.
Which equation can be used to find the nth term of the sequence, a_n?
A) a_n =2^n-1
B) a_n =2 · 18^n-1
C) a_n =10 · 2^n-1
D) a_n =1/5 · 10^n-1
The sequence is geometric, so
[tex]a_n = r a_{n-1}[/tex]
for some constant r. From this rule, it follows that
[tex]a_3 = r a_2 \implies 20 = 2r \implies r = 10[/tex]
and we can determine the first term to be
[tex]a_2 = r a_1 \implies 2 = 10 a_1 \implies a_1 = \dfrac15[/tex]
Now, by substitution we have
[tex]a_n = r a_{n-1} = r^2 a_{n-2} = r^3 a_{n-3} = \cdots[/tex]
and so on down to (D)
[tex]a_n = r^{n-1} a_1 = 10^{n-1} \cdot \dfrac15[/tex]
(notice how the exponent on r and the subscript on a add up to n)
pleaseeee helpp!!!! Nowwww
Answer:
ITS B because sqrt 11 is 3.something
Step-by-step explanation:
A globe on Fred’s desk
is shaped like a sphere
with a volume of 14,130
cubic inches. Find the
radius of the globe
Answer: 18,840*pi
Step-by-step explanation:
The volume of a globe would be 4/3*pi*radius^3 so that would be 4/3*14,130= 18840*pi or approximately 59,187.6055