okay please help me I’m timed!

Answer:

a. T₂ = 60 N

b. W = 25.98 N

Explanation:

a.

Taking right side as positive x direction, the equation for sum of forces in x-direction can be written as follows:

[tex]T_{2}Sin\ 30^o - T_{1} = 0\\T_{2}Sin\ 30^o = T_{1}\\T_{1} = (T_{2})(Sin\ 30^o)\\where,\\T_{2} = 30\ N\\Therefore,\\T_{1} = (30\ N)(Sin\ 30^o)\\[/tex]

T₁ = 15 N

b.

Taking upward direction as positive y direction, the equation for sum of forces in y-direction can be written as follows:

[tex]T_{2}Cos\ 30^o - W = 0\\T_{2}Cos\ 30^o = W\\W = (30\ N)Cos\ 30^o\\[/tex]

W = 25.98 N

Answer:

created, destroyed, transforms

Explanation:

Energy cannot be created nor destroyed.

Energy is transformed from one form to another form.

Energy is neither created nor destroyed simply implies that energy is not produce in any system. Nor is it destroyed.

What we have is energy transformation from one form to another.

Answer:

3.68 m/s².

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 9.4 ms¯¹

Maximum height (h) reached = 12 m

Final velocity (v) = 0 (at maximum height)

Acceleration of free fall (g) =?

v² = u² – 2gh (since the rock is going against gravity)

0 = 9.4² – 2 × g × 12

0 = 88.36 – 24g

Collect like terms

0 – 88.36 = –24g

–88.36 = –24g

Divide both side by –24

g = –88.36 / –24

g = 3.68 m/s²

Thus, the acceleration of free fall near the surface of Mar is 3.68 m/s².

The  acceleration of free fall near the surface of Mars is [tex]3.68 \;\rm m/s^{2}[/tex].

Given data:

The magnitude of initial velocity of rock is, u = 9.4 m/s.

The height raised up by rock is, h = 12 m.

Here, we need to find the acceleration of free fall, which is nothing but the gravitational acceleration. So we will use the Third kinematic equation of motion, which is given as,

[tex]v^{2}=u^{2}+2gh[/tex]

Solving as,

[tex]0^{2}=9.4^{2}+(2 \times -g \times 12)\\\\g = 3.68 \;\rm m/s^{2}[/tex]

Thus, we can conclude that the  acceleration of free fall near the surface of Mars is [tex]3.68 \;\rm m/s^{2}[/tex].

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The three considerations diamond discusses as he ponders Yali's question in guns, germs and steel are:

The stage of human social and cultural development and organization that is considered the most advanced is termed as civilization.

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Answer:

water seeping through a pot of soil

Explanation:

All the others permanently change the chemical structure of the element so they are chemical reactions

Answer:

A

Explanation:

Hopefully this helps

Answer:

A

Explanation:

Answer:

6m/s

Explanation:

A=d÷t

A=60÷10

6

The displacement at a constant acceleration of 3.0[tex]m/s^{2}[/tex] is 526.5m.

Distance, which is a scalar quantity, describes "how much ground an object has covered" while moving. The term "how far out of place an object is" relates to displacement, a vector number that describes the total change in position of the object.

For constant acceleration, displacement is:

[tex]d = (\frac{1}{2} ) (\frac{v_{f}^{2} - v_{i} ^{2} }{a} )[/tex]

[tex]d = \frac{60^{2}-21^{2} }{2*3}[/tex]

[tex]d = \frac{3600-441}{6}[/tex]

[tex]d = \frac{3159}{6}[/tex]

d = 526.5m

Therefore, the displacement at a constant acceleration of 3.0[tex]m/s^{2}[/tex] is 526.5m.

The complete question is: An airplane accelerates with a constant rate of 3.0m/s^2 starting at a velocity of 21m/s. If the final velocity is 60m/s what is the displacement during this period?

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There would no longer be seasons if Earth's axis was perpendicular to the Sun because the variation in the seasons happens due to the tilt of the earth which results in unequal distribution of the sunlight on the earth's surface throughout the year.

Therefore the correct answer is option B.

The Equator is an imaginary line passing through the middle of a globe. It is equidistant from the North Pole and the South Pole, Its is a horizontal line residing at 0 degrees latitude.

As given in the problem we have to find what happens if Earth's axis was perpendicular to the Sun,

If the Earth's axis were perpendicular to the Sun, there wouldn't be any seasons since the tilt of the planet causes an uneven distribution of sunlight on its surface throughout the year, which causes seasonal fluctuation.

Thus, the correct answer is option B.

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Have an amazing day you are an amazing person:)

Answer:

The Vacuole

Explanation:

The Vacuole

Answer:

The gravitational potential energy of the ball is 39,200 J

Explanation:

Gravitational Potential Energy

It is the energy stored in an object because of its vertical position or height in a gravitational field.

It can be calculated with the equation:

U=m.g.h

Where m is the mass of the object, h is the height with respect to a fixed reference, and g is the acceleration of gravity or [tex]9.8 m/s^2[/tex].

The wrecking ball is hung at a height of h=20 m and has a mass of m=200 Kg. Substituting in the formula:

U=200*9.8*20

U = 39,200 J

The gravitational potential energy of the ball is 39,200 J

The obvious differences between the beam observations and cylinder observations are that the maximum value of the cylinder observations is higher and the observations for cylinders are more variable or spread out.

In the above case, the material strength observations in Mega Pascals for cylinder and beams are given.

The values for cylinders are as follows

6.1, 5.8, 7.8, 7.1, 7.2, 9.2, 6.6, 8.3, 7.0, 8.3, 7.8, 8.1, 7.4, 8.5, 8.9, 9.8, 9.7 14.1, 12.6 11.2, 8.1, 7.4, 8.5, 8.9, 9.8, 9.7, 14.1, 12.6, 11.2

And the values for beams are

5.9, 7.2, 7.3, 6.3, 8.1, 6.8, 7.0, 7.6, 6.8, 6.5, 7.0, 6.3, 7.9, 9.0, 8.2 , 8.7, 7.8, 9.7, 7.4, 7.7, 9.7,7.8, 7.7, 11.6 11.3 11.8 10.7,8.2, 8.7, 7.8, 9.7, 7.4, 7.7, 9.7, 7.8, 7.7, 11.6, 11.3, 11.8, 10.7

From the above-given values, we can calculate the mean/average value of the observations.

The average value for cylinders comes out to be 8.57.

The average value for beams comes out to be 8.14.

Among the given values, the maximum value is 14.1 for cylinder observations.

The values of beam observations range from 5.9 to 11.8 while the values for cylinder observations range from 5.8 to 14.1. Therefore, the observations for the cylinder are more variable or spread out.

Thus, the maximum value of the cylinder observations is higher and the observations for cylinders are more variable or spread out.

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This question is incomplete. The data used for solving the question is given in the adjoining image.

Answer:

v₃ = 6.67 [m/s]

Explanation:

To solve this problem we must use the linear momentum conservation theorem, which tells us that momentum is preserved before and after the collision.

Let's take the ball movement of 8 [kg] as positive.

Therefore we can built the following equation:

[tex](m_{1}*v_{1})+(m_{2}*v_{2})=(m_{1}+m_{2})*v_{3}[/tex]

where:

m₁ = mass of the 8 [kg] ball

m₂ = mass of the 4 [kg ] ball

v₁ = velocity of the 8 [kg} ball before the colllision = 10 [m/s]

v₂ = velocity of the 4 [kg] ball before the colllision = 0 [m/s] (at rest)

v₃ = velocity of the two balls after the collision [m/s]

[tex](8*10)+(4*0)=(8+4)*v_{3}\\80 = 12*v_{3}\\v_{3}=6.67 [m/s][/tex]

Answer:

"The sun releases energy at a mass–energy conversion rate of 4.26 million metric tons per second, which produces the equivalent of 384.6 septillion watts (3.846×1026 W)."

Explanation:

This might help you, also this is searched.

A particle with charge q is a very small distance from the centre of a very large square on the line perpendicular to the square and going through its centre.

Since the distance between the charge and the centre of the square is very small, the square contains the field lines emerging from the charge.

[tex]\Phi_{E,square} = \frac{q}{2_{\in_{0} } }[/tex]

A particle is a small localized object which can be ascribed to several physical or chemical properties, such as volume, density, or mass.[1][2] They vary greatly in size or quantity, from subatomic particles like the electron to microscopic particles like atoms and molecules, to macroscopic particles like powders and other granular materials. Particles can also be used to create scientific models of even larger objects depending on their density, such as humans moving in a crowd or celestial bodies in motion.

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By utilising a galaxy model that accurately explains all of the data that has been collected thus far.

In other words, while every star is a star, not every star is a Sun. Since the Sun is bigger than most stars, it is also more brighter. In our galaxy alone, there are billions of Suns, and as was already established, many of the stars we can see are Suns. However, a lot of what you see while gazing up into space is not a star.

The sizes of stars range from neutron stars, which can be about 12 miles (20 kilometres) across, to supergiants, which have a diameter that is 1,000 times larger than the sun. The brightness of a star is influenced by its size. Particularly, brightness and radius are related.

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Answer:

b. 364 [N]

Explanation:

We must remember that the gravitational force can be calculated by means of the product of mass by acceleration. In this case, the acceleration corresponds to the gravitational acceleration of the moon.

[tex]F=m*g\\[/tex]

where:

F = force [N]

m = mass = 225 [kg]

g = moon gravity acceleration = 1.62 [m/s²]

[tex]F = 225*1.62\\F = 364.5[N][/tex]

The weight is 364 N

The calculation can be done as follows

mass= 225 kg

gravitational field= 1.62 N/Kg

Formula is

F= mg

= 225 ˣ 1.62

= 364

= 364 N

Hence the weight of the probe on the moon is 364N

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Answer:

Explanation:

H

Answer:

Average: 22.142857142857  

Average =  

Sum

Count

=  

155

7

=  22.142857142857

Sum 155

Count 7

Median 23

Geometric Mean 16.412764443111

Largest 38

Smallest 2

Range 36

Answer:

15.4

Explanation:

Answer:

-14.2m/s

Explanation:

Given parameters:

Initial velocity of the ball  = 25m/s

Time  = 4s

Unknown:

Final velocity of the ball  = ?

Solution:

To solve this problem, we use the expression below;

               v  = u - gt

v is the final velocity

u is the initial velocity

g is the acceleration due to gravity

t is the time

             v = 25  - (9.8 x 4)  = -14.2m/s

Answer:

Neutral arguments avoid using "you" statements and, therefore, can assist in avoiding being perceived as offensive or indicating that you believe your opponent is unreasonable. It is best to use "I" statements rather than "you" statements, because it helps keep the tone of statements neutral, which avoids escalating the conflict.

Explanation:

Answer:

the person above is correct ^^^^^^^^^^^

Explanation:

There are 90 degrees directly overhead. Barnard is at 74 degrees at Sam's position, 1300.0 kilometers south. The part of the 360 degree circle that corresponds to Hua's circumference is the difference between 90 and 74, or 16 degrees. 1300.0 km is therefore 16/360 of the circle, or 0.044 times the circumference. 29.250 km is the circumference (1300 divided by 0.044). Radius divided by two gives the circumference equation. Therefore, 2r=29250 and the radius of Hua=4655.3 km

Astronomy is a scientific science that examines celestial objects and phenomena (from the Ancient Greek "o" (astronoma), "science that investigates the laws of the stars"). In order to describe their creation and evolution, it makes use of mathematics, physics, and chemistry. Planets, moons, stars, nebulae, galaxies, and comets are among the interesting celestial bodies. Supernova explosions, gamma ray bursts, quasar, blazar, pulsar, and cosmic microwave background radiation are examples of relevant phenomena. Astronomy is the study of everything that comes from outside the atmosphere of the Earth. Astronomical cosmology is the study of the cosmos as a whole.

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Answer:

magnet, gravity

Explanation:

Answer:

well I mean it would depend on where u live for this question that's the only reason I am confused.. I'm pretty sure it's A thi

(a) If we consider the waves to travel in a straight line (x = 0), according to their wave speed,

(b) The waves are ranked according to the tension in the strings along which they travel, with the greatest first,

The linear density of the string and the tension in the string both affect the wave's speed. The linear density is the mass divided by the string's length. In general, the square root of the ratio of the medium's elastic to inertial properties determines a wave's speed.

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Answer:

[tex] \sf t = \dfrac{V_f - V_i}{a} [/tex]

Explanation:

[tex] \rm V_f = V_i + at \\ \rm V_f - V_i = at \\ \rm at = V_f - V_i \\ \rm t = \dfrac{V_f - V_i}{a} [/tex]

Answer:

Nuclear energy, also called atomic energy, energy that is released in significant amounts in processes that affect atomic nuclei, the dense cores of atoms. It is distinct from the energy of other atomic phenomena such as ordinary chemical reactions, which involve only the orbital electrons of atoms.

Explanation:

Answer: Nuclear energy, also called atomic energy, energy that is released in significant amounts in processes that affect atomic nuclei, the dense cores of atoms. It is distinct from the energy of other atomic phenomena such as ordinary chemical reactions, which involve only the orbital electrons of atoms.

Explanation: please give brainliest and thanks :)

Answer:

The value of the horizontal velocity when the pumpkin is thrown is approximately 17.619 m/s

Explanation:

The height from which the pumpkin is thrown = 14 meters

The velocity with which the pumpkin is thrown = 23 m/s

The direction in which the pumpkin is thrown = 40° above the horizontal

The horizontal component of the velocity = 23 × cos(40) ≈ 17.619

Therefore, the value of the horizontal velocity when the pumpkin is thrown ≈ 17.619 m/s