Nose bleeding occurs as we move towards high altitude, why?

Answer:

A. The speed is unchanged.

Explanation:

In the case when the work is to be done on a particle i.e. zero so the change made in KE of the particle would be zero. This represent the work energy theroem. But when the KE remains same or does not change so it should be the same and the particle speed would also the same

Therefore as per the given statement, the first option is correct

And rest of the options are wrong

Answer:

A complexometric indicator is an ionochromic dye that undergoes a definite color change in presence of specific metal ions.[1] It forms a weak complex with the ions present in the solution, which has a significantly different color from the form existing outside the complex. Complexometric indicators are also known as pM indicators.[2]

Answer:

let the coefficient of friction be ß

Explanation:

[tex]from \: third \: law \: of \: solid \: friction \\ friction = \beta \times R \\ where \: R \: is \: the \: normal \: reaction \\ 46 = 0.30 \times R \\ R = \frac{46}{0.30} \\ R = 153.33 \: N \\ but \: R = mg \\ where \: mg \: is \: the \: weight \\ hence \\ weight, W = 153.33 \: N[/tex]

Answer:

156.8 Watts

Explanation:

From the question given above, the following data were obtained:

Mass (m) = 10 kg

Height (h) = 8 m

Time (t) = 5 s

Power (P) =?

Next, we shall determine the energy used by the motor to raise the block. This can be obtained as follow:

Mass (m) = 10 kg

Height (h) = 8 m

Acceleration due to gravity (g) = 9.8 m/s²

Energy (E) =?

E = mgh

E = 10 × 9. 8 × 8

E = 784 J

Finally, we shall determine the power output of the motor. This can be obtained as illustrated below:

Time (t) = 5 s

Energy (E) = 784 J

Power (P) =?

P = E/t

P = 784 / 5

P = 156.8 Watts

Therefore, the power output of the motor is 156.8 Watts

Answer:

[tex]F=3.93\times 10^{-7}\ N[/tex]

Explanation:

Mass of student 1, m₁ = 79 kg

Mass of student 2, m₂ = 93.5 kg

The students are 1.12 m apart, d = 1.12 m

We need to find the force of the gravitational attraction between them. The force of gravitational force is given by :

[tex]F=G\dfrac{m_1m_2}{r^2}\\\\F=6.67\times 10^{-11}\times \dfrac{79\times 93.5}{(1.12)^2}\\\\=3.93\times 10^{-7}\ N[/tex]

So, the force of gravitational attraction between them is [tex]3.93\times 10^{-7}\ N[/tex]. Hence, the correct option is (B).

Answer:

a) [tex] v_{U-235} = 2.68 \cdot 10^{5} m/s [/tex]

[tex]v_{He-4} = -1.57 \cdot 10^{7} m/s[/tex]  

b) [tex] E_{He-4} = 8.23 \cdot 10^{-13} J [/tex]

[tex] E_{U-235} = 1.41 \cdot 10^{-14} J [/tex]

Explanation:

Searching the missed information we have:                                        

E: is the energy emitted in the plutonium decay = 8.40x10⁻¹³ J

m(⁴He): is the mass of the helium nucleus = 6.68x10⁻²⁷ kg  

m(²³⁵U): is the mass of the helium U-235 nucleus = 3.92x10⁻²⁵ kg            

a) We can find the velocities of the two nuclei by conservation of linear momentum and kinetic energy:

Linear momentum:

[tex] p_{i} = p_{f} [/tex]

[tex] m_{Pu-239}v_{Pu-239} = m_{He-4}v_{He-4} + m_{U-235}v_{U-235} [/tex]

Since the plutonium nucleus is originally at rest, [tex]v_{Pu-239} = 0[/tex]:

[tex] 0 = m_{He-4}v_{He-4} + m_{U-235}v_{U-235} [/tex]  

[tex] v_{He-4} = -\frac{m_{U-235}v_{U-235}}{m_{He-4}} [/tex]    (1)

Kinetic Energy:

[tex] E_{Pu-239} = \frac{1}{2}m_{He-4}v_{He-4}^{2} + \frac{1}{2}m_{U-235}v_{U-235}^{2} [/tex]

[tex] 2*8.40 \cdot 10^{-13} J = m_{He-4}v_{He-4}^{2} + m_{U-235}v_{U-235}^{2} [/tex]    

[tex] 1.68\cdot 10^{-12} J = m_{He-4}v_{He-4}^{2} + m_{U-235}v_{U-235}^{2} [/tex]   (2)    

By entering equation (1) into (2) we have:

[tex] 1.68\cdot 10^{-12} J = m_{He-4}(-\frac{m_{U-235}v_{U-235}}{m_{He-4}})^{2} + m_{U-235}v_{U-235}^{2} [/tex]  

[tex] 1.68\cdot 10^{-12} J = 6.68 \cdot 10^{-27} kg*(-\frac{3.92 \cdot 10^{-25} kg*v_{U-235}}{6.68 \cdot 10^{-27} kg})^{2} +3.92 \cdot 10^{-25} kg*v_{U-235}^{2} [/tex]  

Solving the above equation for [tex]v_{U-235}[/tex] we have:

[tex] v_{U-235} = 2.68 \cdot 10^{5} m/s [/tex]

And by entering that value into equation (1):

[tex]v_{He-4} = -\frac{3.92 \cdot 10^{-25} kg*2.68 \cdot 10^{5} m/s}{6.68 \cdot 10^{-27} kg} = -1.57 \cdot 10^{7} m/s[/tex]                        

The minus sign means that the helium-4 nucleus is moving in the opposite direction to the uranium-235 nucleus.

b) Now, the kinetic energy of each nucleus is:

For He-4:

[tex]E_{He-4} = \frac{1}{2}m_{He-4}v_{He-4}^{2} = \frac{1}{2} 6.68 \cdot 10^{-27} kg*(-1.57 \cdot 10^{7} m/s)^{2} = 8.23 \cdot 10^{-13} J[/tex]

For U-235:

[tex] E_{U-235} = \frac{1}{2}m_{U-235}v_{U-235}^{2} = \frac{1}{2} 3.92 \cdot 10^{-25} kg*(2.68 \cdot 10^{5} m/s)^{2} = 1.41 \cdot 10^{-14} J [/tex]

I hope it helps you!                                                                                    

Answer:

The magnitude of the work done by the snake against friction is 402 J.

Explanation:

The work is given by:

[tex] W = F*d [/tex]

Where:

F: is the force

d: is the distance

The distance traveled by the snake is given by the perimeter of the circle:

[tex] P = 2\pi r = 2\pi 3.20 m = 20.1 m [/tex]

Now, the force in the direction of the movement is:

[tex] |\Sigma F| = F_{\mu} = \mu N = \mu W = 0.25*80.0 N = 20 N [/tex]

Finally, the work is:

[tex] W = F*d = 20 N*20.1 m = 402 J [/tex]

Therefore, the magnitude of the work done by the snake against friction is 402 J.

I hope it helps you!                                              

Answer:

theta = 90°

Explanation:

hope it's helpful

Explanation:

A • B = (2i - 3j + k) • (i + j + k)

= (2)(1) + (- 3)(1) + (1)(1)

= 0 = AB cos θ

∴ cos θ = 0 (as A ≠ 0,B ≠ 0)

or θ = 90°

or the vectors A and B are mutually perpendicular.

-TheUnknownScientist

Explanation:

w=F×d 1kg=9.807N

p=w/t 400kg=9.807×400=3922.8N

p=Fd/t

=3922.8×20×1

power=78456 watt

..sorry..if the answer is not right..

Answer:

Fr = 102[N]

Explanation:

We must perform a free body diagram to understand the forces acting on Vin Diesel. In the attached image we see the forces related to his weight and the air resistance force.

We must analyze the forces in the Y axis, we see that we have the force of the air opposing the fall of Vin Diesel, in this way this force is negative since it opposes the movement, the fall.

∑Fy = 0

[tex]F_{weight}-F_{air}=F_{r}\\F_{r}= 184-82\\F_{r}=102[N][/tex]

Answer:

(a) the particle position = 135 m

(b) the velocity of the particle = 44 m/s

(c) the acceleration of the particle = 50 m/s²

Explanation:

Solution to Question 2.

Given;

velocity of a particle, v = 2 - 4t + 2t³

initial position at t = 0, s₀ = 3 m

(a) the particle position at t = 3 s

s = vt

s = (2 - 4t + 2t³)t

s = 2t - 4t² + 2t⁴

s = s₀ + s₃

s = s₀ + 2(3) - 4(3²) + 2(3⁴)

s = s₀ + 6 - 36 + 162

s = s₀ + 132 m

s = 3m + 132 m

s = 135 m

(b) the velocity of the particle at t = 3 s

v = 2 - 4t + 2t³ = 2 - 4(3) + 2(3)³

v = 44 m/s

(c) the acceleration of the particle at t = 3s

v = 2 - 4t + 2t³

[tex]a = \frac{dv}{dt} \\\\a = \frac{d}{dt} (2 -4t + 2t^3)\\\\a = -4 + 6t^2[/tex]

a = -4 + 6(3)²

a = 50 m/s²

Answer:

I believe the answer is D) 4

Explanation:

Subduction is the sideways and downward movement of the edge of a plate of the earth's crust into the mantle beneath another plate.

Answer: point 4

Explanation:

Answer:

Average speed = 46.67 m/s

Explanation:

Given that the time taken in covering first 1000 m = 25 seconds.

The time taken in covering next 2.5 km = 50 seconds.

Total distance covered = 1000 m + 2500 m = 3500 m

Total time taken = 25+50=75 seconds

Average speed = Total distance covered / total time taken

= 3500/75 = 46.67 m/s

Answer:

call me 7164013838 hurry bye

Answer:

D) 60 m

Explanation:

We can use the constant acceleration equation that contains displacement, initial velocity, acceleration, and time. We want to solve for the time that the ball was in the air first.

Let's use this equation in terms of the y-direction.

The vertical displacement will be 0 meters since the ball will be on the floor. The initial vertical velocity is 10 m/s, the vertical acceleration is g = 10 m/s², and we are going to solve for time t.

Let's set the upwards direction to be positive and the downwards direction to be negative. We must use -g to be consistent with our other values.

Plug the known values into the equation.

Simplify the equation.

Factor the equation.

Solve for t by setting both factors to 0.

We get t = 0, t = 2. We must use t = 2 seconds because it is the only value for t that makes sense in the problem.

Now that we have the time that the ball was in the air, we can use the same constant acceleration equation to determine the horizontal displacement of the tennis ball. We will use this equation in terms of the x-direction:

Plug the known values into the equation.

We can eliminate the right side of the equation since anything multiplied by 0 outputs 0.

The horizontal displacement of the ball is 60 meters. Therefore, the answer is D) 60 m.

Answer:

There are 4 liquids in this experiment and red is the least dense of all of them so it should float on top, which it is doing.

The red that you see at the bottom is neither liquid nor is it a part of the experiment.

It is simply the color of the bottom of the container that the experiment was conducted in.

The bottom thing doesn’t matter. That is not meant to be red, it‘s the bottom of the beaker. The star is at the very bottom of the beaker. it’s just the base of the beaker.

Answer:

(a)The final speed of the truck "v"  is 1.76 m/s

(b) The horizontal force exerted on the truck is 178.64 N

Explanation:

Given;

work done by the man, W = 4,465 J

mass of the truck, m = 2.9 x 10³ kg

initial speed of the truck, u = 0

distance the truck was pushed to, d = 25 m

final speed of the truck, = v

The work done in pushing the truck is calculated as;

W = F x d

where;

F is the horizontal force applied

d is the distance in which the truck was pushed to

W = ma x d

[tex]a = \frac{W}{md} \\\\a = \frac{4465}{2.9 \times 10^3 \ \times 25} \\\\a = 0.0616 \ m/s^2[/tex]

(a)The final speed of the truck "v"  is calculated as;

v²= u² + 2ad

v² = 0 + 2(0.0616 x 25)

v² = 3.08

v = √3.08

v = 1.76 m/s

(b) the horizontal force exerted on the truck

F = ma

F = (2.9 x 10³) (0.0616)

F = 178.64 N

Answer:

Option (C) is correct.

Explanation:

Assuming that the hiker starts walking from the origin O as shown in the figure.

First, he walks 200 m west to point A (say), then he walks 100 m north to the final point B (say) as shown in the figure.

The final point B is in the north-west direction, therefore, the resulting point is in the north-west direction.

Hence, option (C) is correct.

Answer:

Explanation:

Maybe start by trying to draw out some transverse waves, longitudinal waves, stationary waves etc. From there you could explain things about each type. For example, particles oscillate in the direction of energy transfer in longitudinal waves or you could include that all electromagnetic waves are examples of transverse waves. Hope this helps you get started :)

Waves are a form of energy transfer through matter or space. Waves can be characters using their amplitude, frequency, wavelength, energy etc.

A wave can be defined as the energy transfer or disturbances in air or matter. Sound and light are two types of waves.

There are broadly two types of waves namely longitudinal waves which vibration parallel  to the direction of the wave and transverse wave vibrating perpendicular to the direction of wave.

A wave is associated with an amplitude. It is the maximum distance that its molecules are displaced or it is the measure of intensity.

Frequency of a wave is the number crests or troughs passing per unit time. Wavelength is the distance between two consecutive crests or throughs.

Each wave is associated with certain amount of energy which is directly proportional to its frequency. High energy wave can easily penetrate through a body.

Hence, by the terms such as amplitude, frequency, wavelength and energy a wave can be characterized.

To find more about waves, refer the link below:

https://brainly.com/question/3639648

#SPJ2

Answer:

Explanation:

They have the same kinetic energy

Answer:

Thus, the object is accelerating to the left

Explanation:

The Net Force

The net force is the result of adding all the forces as vectors acting on a body.

[tex]\vec F=\vec F_1+\vec F_2+...+\vec F_n[/tex]

Each vector can be expressed in its rectangular components Fx and Fy, and the sum is the sum of the rectangular components separately.

Second Newton's law gives the relation between the net force and the acceleration of the body:

[tex]\vec F = m.\vec a[/tex]

We can see the acceleration is a vector with the same direction as the net force.

The diagram shows two vertical forces and two horizontal forces.

The vertical forces are acting in opposite directions and with the same magnitude, thus they cancel out, leaving zero net force in the y-axis.

The horizontal forces are opposite and with different magnitudes. Since the force acting to the left (F3) has a greater magnitude than the force acting to the right (F4), there is a net force directed to the left with a magnitude of 60 N - 20 N = 40 N

Thus, the object is accelerating to the left

Answer:

500J

Explanation:

The arrow will have an energy of 500J after it has been released from its state of rest.

This is compliance with the law of conservation of energy which states that "in every system, energy is neither created nor destroyed but transformed from one form to another".

Answer:

b. melting

Explanation:

it is made of sediments and that is not necessary

Answer:

m = 45 kg

Explanation:

Given that,

Mass of Jadan, m = 45 kg on Earth

Jupiter has more gravity than the Earth.

Mass of an object is the amount of matter contained inside an object. We need to tell about the mass of Jaden on Jupiter. The mass of the object remains same everywhere.It does not change in any of the location.

Hence, Jaden's mass will be 45 kg on Jupiter.

Answer:

[tex]P = -\frac{17978}{1609344}(h)+101.325[/tex]

Explanation:

Given

[tex]h = height[/tex]

[tex]P = Pressure[/tex]

[tex](h_1,P_1) = (0,101.325)[/tex]

[tex](h_2,P_2) = (1609.344 ,83.437 )[/tex]

Required

Determine the linear equation for P in terms of h

First, we calculate the slope/rate (m);

The following formula is used:

[tex]m = \frac{P_2 - P_1}{h_2 - h_1}[/tex]

Substitute values for P's and h's

[tex]m = \frac{83.347 - 101.325}{1609.344- 0}[/tex]

[tex]m = \frac{-17.978}{1609.344}[/tex]

[tex]m = -\frac{17.978}{1609.344}[/tex]

Multiply by 1000/1000

[tex]m = -\frac{17.978 * 1000}{1609.344*1000}[/tex]

[tex]m = -\frac{17978}{1609344}[/tex]

The equation is then calculated using:

[tex]P - P_1 = m(h - h_1)[/tex]

Substitute values for m, h1 and P1

[tex]P - P_1 = m(h - h_1)[/tex]

[tex]P - 101.325 = -\frac{17978}{1609344}(h - 0)[/tex]

[tex]P - 101.325 = -\frac{17978}{1609344}(h)[/tex]

Make P the subject

[tex]P = -\frac{17978}{1609344}(h)+101.325[/tex]

The above is the required linear equation

Answer:

The correct answer is B)

Explanation:

When a wheel rotates without sliding, the straight-line distance covered by the wheel's center-of-mass is exactly equal to the rotational distance covered by a point on the edge of the wheel.  So given that the distances and times are same, the translational speed of the center of the wheel amounts to or becomes the same as the rotational speed of a point on the edge of the wheel.

The formula for calculating the velocity of a point on the edge of the wheel is given as

[tex]V_{r}[/tex] = 2π r / T

Where

π is Pi which mathematically is approximately 3.14159

T is period of time

Vr is Velocity of the point on the edge of the wheel

The answer is left in Meters/Seconds so we will work with our information as is given in the question.

Vr = (2 x 3.14159 x 1.94m)/2.26

Vr = 12.1893692/2.26

Vr = 5.39352619469

Which is approximately 5.39

Cheers!