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Movies generally lose 23% of it's audience for each week in the theatre. A movie STARTED with an audience of 196 people per viewing.



NO LINKS!!!Movies Generally Lose 23% Of It's Audience For Each Week In The Theatre. A Movie STARTED With

Answers

Answer 1

Answers:

a) The equation is [tex]y = 196(0.77)^x[/tex]

b) See image attachment below

c) See image attachment below

d) Week 10

=======================================================

Explanation:

a)

One common template for an exponential equation is [tex]y = a*b^x[/tex] where 'a' is the starting amount and b is the growth or decay factor.

a = 196 is the starting amount of people who saw the movie per showtime

b = 1-0.23 = 0.77 is the decay factor. If the view count goes down by 23%, then we keep the remaining 77%

Therefore we go from [tex]y = a*b^x[/tex] to [tex]y = 196(0.77)^x[/tex]

x = number of weeks

y = number of people, per viewing, who saw the movie for the particular week

--------------------

b)

Plug in x = 0 to find that y = 196

Plug in x = 1 to get y = 150.92 which rounds to y = 151 since we're talking about the number of people

Repeat for x = 2 all the way up to x = 9 to account for the first ten weeks. We stop at 9 instead of 10 because we started at x = 0.

The table is shown in the attachment below next to the graph.

I'm not sure why your teacher put a dollar sign over the second column of the table when it should be the number of people. It might be a typo. If they meant to do it, then there's missing information about ticket prices.

--------------------

c)

The graph is shown below. You can plot each (x,y) point on the same grid and then draw a curve through them. A much quicker way is to use software like GeoGebra (which is what I used) or Desmos or a pocket calculator. There are tons of many options to pick from. Feel free to choose your favorite.

The blue dashed segments on the graph visually help verify the result of part (d). We have y = 20 lead to an x value somewhere between x = 8 and x = 9. When submitting the graph to your teacher, you'll leave out the blue dashed segments.

--------------------

d)

Refer to the table we made in part (b). We have x = 9 lead to y = 19 approximately which is when y is below 20 people. Recall that x = 0 refers to week 1, so x = 9 refers to week 9+1 = 10. Week ten is where the view count drops below 20 people per showing.

If you wanted to use the graph in part (c), then you'd follow the blue dashed line mentioned earlier. Start at the y axis at y = 20. Trace the blue dashed line until reaching the curve. Then drop straight down to arrive somewhere between x = 8 and x = 9. Round up to x = 9. Then make the adjustment to go from x = 9 to week ten.

If you want an algebraic method, then follow the steps below.

Plug in y = 20 and solve for x. We'll need to involve logarithms to isolate the exponent.

[tex]y = 196(0.77)^x\\\\20 = 196(0.77)^x\\\\20/196 = (0.77)^x\\\\0.1020408 \approx (0.77)^x\\\\(0.77)^x \approx 0.1020408\\\\\text{Log}\left((0.77)^x\right) \approx \text{Log}(0.1020408) \\\\x*\text{Log}\left(0.77\right) \approx \text{Log}(0.1020408) \\\\x \approx \text{Log}(0.1020408)/\text{Log}\left(0.77\right) \\\\x \approx 8.7325564 \\\\[/tex]

This rounds up to x = 9 leading to week ten as the answer.

As confirmation

[tex]y = 196(0.77)^x = 196(0.77)^8 \approx 24.22 \approx 24\\\\y = 196(0.77)^x = 196(0.77)^9 \approx 18.65 \approx 19\\\\[/tex]

NO LINKS!!!Movies Generally Lose 23% Of It's Audience For Each Week In The Theatre. A Movie STARTED With
Answer 2

Answer:

Part (a)

We can model this as an exponential equation.

General form of an exponential equation: [tex]y=ab^x[/tex]

where:

a is the initial valueb is growth factorx is the independent variabley is the dependent variable

If b > 1 then it is an increasing function

If 0 < b < 1 then it is a decreasing function

As the movie theatre lost 23% of its audience each week, the growth (decay) factor will be 100% - 23% = 77%  →  0.77

Given:

a = 196b = 0.77x = times (in weeks)y = audience (in number of people)

Substitute the given values into the formula to create the exponential equation:

[tex]y=196(0.77)^x[/tex]

Part (b)

[tex]\begin{tabular}{| c | r |}\cline{1-2} \bf weeks & \bf audience \\\cline{1-2} 1 & 150.92\\\cline{1-2} 2 & 116.21\\\cline{1-2} 3 & 89.48\\\cline{1-2} 4 & 68.90\\\cline{1-2} 5 & 53.05\\\cline{1-2} 6 & 40.85\\\cline{1-2} 7 & 31.46\\\cline{1-2} 8 & 24.22\\\cline{1-2} 9 & 18.65\\\cline{1-2} 10 & 14.36\\\cline{1-2}\end{tabular}[/tex]

**all values rounded to 2 dp**

Part (c)

see attached for graph

Part (d)

Set y < 20 and solve for x:

[tex]\begin{aligned}196(0.77)^x & < 20\\\\(0.77)^x & < \dfrac{5}{40}\\\\\ln (0.77)^x & < \ln\left(\dfrac{5}{49}\right)\\\\x\ln (0.77) & < \ln\left(\dfrac{5}{49}\right)\\\\x & > \dfrac{\ln\left(\dfrac{5}{49}\right)}{\ln (0.77)}\\\\x & > 8.732555795\end{aligned}[/tex]

Therefore, the movie audience will fall below 20 people per viewing during the 9th week.

NO LINKS!!!Movies Generally Lose 23% Of It's Audience For Each Week In The Theatre. A Movie STARTED With

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Answers

Answer:

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Answer:

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Answer:

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Step-by-step explanation:

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To Solve: 4X + B = C

[tex]\implies 4X + \begin {bmatrix} 8 & -2\\-1 & 6\\-8 & -10\end{bmatrix}=\begin {bmatrix} -12 & 6\\-1 & 38\\24 & -6\end{bmatrix}[/tex]

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[tex]\implies 4X =\begin {bmatrix} -12-8 & 6+2\\-1 +1 & 38-6\\24+8 & -6+10\end{bmatrix}[/tex]

[tex]\implies 4X =\begin {bmatrix} -20 & 8\\0& 32\\32 & 4\end{bmatrix}[/tex]

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Answers

Answer:

58π mi.

Step-by-step explanation:

The diameter of the circle = the hypotenuse of the right triangle ( by the angle subtended by a diameter theorem).

By Pythagoras:

diameter^2 = 40^2 + 42^2

=  3364

Diameter = 58 mi.

Now the circumference

= diameter * π

= 58π mi.

Identify the lateral area and surface area of a regular square pyramid with base edge length 11 cm and slant height 15 cm, rounded to the nearest tenth.

Answers

The surface area of the square pyramid is: 451 cm²

The lateral surface area of the square pyramid = 330 cm²

What is the Lateral Surface Area and Surface Area of a Square Pyramid?

Surface area = a² + 2al, where a is the base edge and l is the slant height.

Lateral Surface Area =  2al.

Given the following:

a = 11 cml = 15 cm

Surface area = a² + 2al = 11² + 2(11)(15)

Surface area = 451 cm²

Lateral Surface Area =  2al = 2(11)(15)

Lateral Surface Area = 330 cm²

Learn more about square pyramid on:

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The lateral and surface area of a square base pyramid with side length of 11 cm and slant height of 15 cm are 330 cm² and 451 cm².

Surface area of a pyramid

surface area = A + 1 / 2 ps

where

A = area of the basep = perimeter of the base s = slant height

Therefore,

surface area = 11² + 1 / 2 × (11 × 4) × 15

surface area = 121 + 1 / 2 × 44 × 15

surface area = 121 + 330

surface area = 451 cm²

Lateral area of a square pyramid

lateral area = 1 / 2 ps

lateral area = 1 / 2 × 44 × 15

lateral area = 330 cm²

learn more on lateral and surface area here; https://brainly.com/question/23857644

What are the solutions of this quadratic equation? 9x^2+10=5

Answers

Answer:

No solution

Step-by-step explanation:

9x² + 10 = 5

⇔ 9x² = 5 - 10

⇔ 9x² = -5

This is impossible because 9x² > 0 and -5 < 0

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Answers

Answer:

  (d)  112 m²

Step-by-step explanation:

The area of a parallelogram is given by the formla ...

  A = bh . . . . . . where b is the base length and h is the height

__

Here, the base is divided into parts, but their total length is 5m+9m = 14m. The height is given as 8m, so the area is ...

  A = (14 m)(8 m) = 112 m²

The area of the parallelogram is 112 square meters.

__

Alternate solution

You can also figure this as the sum of the areas of the two triangles and that of the center rectangle.

  A = 2(1/2bh) +bh

  A = 2(1/2(5 m)(8 m)) +(9 m)(8 m) = 40 m² +72 m² = 112 m²

what is the sum of 9+10?

Answers

Answer:

19.

Step-by-step explanation:

ANSWERS THESEEESS!!!!

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Número 13 es A
Número 14 es B

a radioactive substance that has half-life lof 32 years. Find the constant k in the decay formula for the substance

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Answers

Answer:

[tex]\displaystyle k = \frac{1}{32}\ln\frac{1}{2} \approx -0.02166[/tex]

Step-by-step explanation:

The decay formula is given by:
[tex]\displaystyle P(t) = P_0e^{kt}[/tex]

Where k is some constant, P₀ is the initial population, and t is the number of years.

Because the substance has a half-life of 32 years, P(t) = 1/2P₀ when t = 32. Substitute:
[tex]\displaystyle \frac{1}{2}P_0 = P_0 e^{k(32)}[/tex]

Solve for k:

[tex]\displaystyle \begin{aligned} \frac{1}{2} & = e^{32k} \\ \\ \ln\left(e^{32k}\right) & = \ln\left(\frac{1}{2}\right) \\ \\ 32k & = \ln\frac{1}{2} \\ \\ k & = \frac{1}{32}\ln\frac{1}{2} \\ \\ &\approx -0.02166\end{aligned}[/tex]

In conclusion, the value of k is about -0.02166.

The value of k in the exponential decay formula is k = 0.022

How to find the value of k?

To find the constant k in the decay formula for the radioactive substance, we can use the formula for exponential decay, which is given by:

N(t) = N₀*exp(-kt)

where:

N(t) is the amount of the radioactive substance at time t.N₀ is the initial amount of the substance at t = 0 (time of measurement).e is the base of the natural logarithm (approximately 2.71828).k is the decay constant we need to find.t is the time elapsed (in this case, t is measured in years since the half-life is given in years).

The half-life of the substance is the time it takes for half of the substance to decay, which is 32 years in this case. So, after one half-life, N(t) = N₀ / 2.

Now, let's set up the equation for one half-life:

N(t) = N₀ * exp(-k * 32)

Since N(t) = N₀ / 2 after one half-life, we can write:

N₀ / 2 = N₀ * e^(-k * 32)

Now, divide both sides by N₀:

1/2 = exp(-k * 32)

To solve for k, take the natural logarithm (ln) of both sides:

ln(1/2) = -k * 32

k = ln(1/2) / -32

k = 0.022

Learn more about half-life at:

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A rectangle has sides that are 7 and 2/5 inches wide and 11 and 2/3 inches long. What is the perimeter of the rectangle?

Answers

Answer:

38.1333333334

Step-by-step explanation:

Perimeter of rectangle:

2 × (length + width) inches

2 × (7 2/5 + 11 2/3) inches

2 × 19.0666666667 inches

38.1333333334

if you were to flip the coin 15, how many times will the coin land on tails based on experimental probability? jordan flipped a count of 45 times.His result are below: heads: 24 tails: 21

Answers

Answer:

It will land 7.5 times on tails, which is rounded up to 8 times

Step-by-step explanation:

there are 2 possibilities, heads or tails

so you divide 15 in 2 and get 7.5

The coin will land 7 times tail based on the experimental probability.

What is Probability?

Probability refers to potential. A random event's occurrence is the subject of this area of mathematics.

The range of the value is 0 to 1. Mathematics has incorporated probability to forecast the likelihood of various events.

The degree to which something is likely to happen is basically what probability means.

Given:

When the coin tossed 45 times.

Head= 24, tail = 21

So, fraction of appearing tail will be

= 21 / 45

= 0.466667

Now, if the coin tossed 15 times then the coin land on tails

= 15 x 0.466667

= 7

Learn more about Probability here:

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