here,
the inner diameter , d = 10 um = 10 * 10^-6 m
radius , r = d/2 = 5 * 10^-6 m
resistivity , p = 0.5 ohm.m
length , l = 6 mm = 0.006 m
the resistance , R = p * l /area
R = p * l /( pi * r^2)
R = 0.5 * 0.006 /(pi * ( 5 * 10^-6)^2) ohm
R = 3.82 * 10^7 ohm (Answer)
the resistance of a wire is 3.82 * 10^7 ohm
Neurons, or nerve cells that transmit nerve impulses, consist of a cell body, an axon, and a few dendrites. Signals travel through synapses, where the axon of one neuron meets the dendrites of another neuron, using chemicals called neurotransmitters.
An electrical signal that travels along a nerve fiber in response to a stimulus and conveys the recording of sensations from receptors or instructions to effectors: Propagation of an action potential along the length of a neuron.
Differential charges across the plasma membrane of neurons generate nerve impulses. How does this charge difference come about? The response contains ions, which are charged atoms or molecules.
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2x²-y if x =3 and y = 8
Answer:
10
Explanation:
2*3^2-8
2*9-8
18-8
10
an elevator is being lifted up an elevator shaft at a constant speed by a steel cable. all frictional effects are negligible. in this situation, forces on the elevator are such that:: *
An elevator is being lifted up an elevator shaft at a constant speed by a steel cable. All frictional effects are negligible. In this situation, forces on the elevator are such that the upward force of the cable is equal to the downward force of gravity.
As per Newton's 2nd regulation F = ma, acceleration needs a force proportional to mass. So when the elevator is accelerating upwards, it has to not handiest oppose gravity however provides greater pressure for the upward acceleration. This calls for an expanded ordinary force
Friction is the pressure resisting the relative motion of strong surfaces, fluid layers, and cloth factors sliding against each other. There are several types of friction: Dry friction is a pressure that opposes the relative lateral movement of two solid surfaces in touch.
The gravitational force is a pressure that draws any gadgets with mass. We call the gravitational pressure attractive as it usually attempts to pull masses collectively, it in no way pushes them apart. In fact, each item, which includes you, is pulling on each other object in the entire universe.
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An object of known mass that can be used to establish uncertainty in measurements made with a balance is best described as a.
Answer:
standard
Explanation:
we sometimes use weights of known mass to balance with an object of unknown mass to determine that objects weight.
Marta gives long, involved answers to every question, even simple ones. She uses technical vocabulary even if the people she is talking to do not understand it. What is the BEST advice Marta’s supervisor could give her?
A.
Use technology to your team’s advantage.
B.
Manage information, not people.
C.
Make sure your networks are strong.
D.
Adapt your communication style.
Please HELP
Answer:
D. Adapt your communication style.
Explanation:
It is quite difficult to gauge the protocol here given the lack of information about the work environment; but as a general answer, communication skills are always handy. Furthermore, it seems that Marta in particular struggles with this. Assuming Marta is providing a specialized service of a sort, she would need to understand that there is a reason why her services are required at all. Through this, hopefull she'll understand that they are most likely outside of this field of work, and ergo [she] must cater and gear her actions towards the interest of the person(s) in question.
It is to be noted that this is merely my surmise.
An object is moving and velocity of 8 m/s and accelerates to 35 m/s or 6.3 seconds. what is the acceleration?
Answer:
4m/s^2
Explanation:
u find the average of the two velocities then place the outcome in the acceleration formula given time as 6.3 seconds .....dividing the average of the velocities
you should begin viewing a bacteria specimen with what objective lens? view available hint(s)for part g you should begin viewing a bacteria specimen with what objective lens? 100x 10x 40x
It is important to choose the appropriate magnification for your needs so that you can properly examine the specimen under study.
Why is the 100x objective lens necessary to see bacteria?Bacteria must, of course, be viewed at the maximum magnification and resolution possible because to their small size. Due to optical restrictions, this is approximately 1000x in a light microscope. To improve resolution, the oil immersion method is performed. This calls for a unique 100x objective.To learn more about bacterial specimen, visit:
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to find the masses of both stars in a binary system, you must find the of each star, the of the orbit, and the average between the stars.
To find the masses of both stars in a binary system, you must find the velocity of each star, the period of the orbit, and the average distance between the stars.
The displacement covered by an object in the unit of time is called velocity.
The formula of velocity is v = d/t and its dimensions are LT-1.
A unit of time in which a particle or object passes through a point to complete its one cycle is called a period. It is related to time.
The time-period is denoted by T and the formula is T = 2 π√ l / g.
In physics, distance is a vector quantity without any direction. It can be calculated as distance = speed x time i.e. d = v.t
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A monochromatic light beam is incident on a barium target that has a work function of 2.50 \mathrm{eV} . If a potential difference of 1.00 \mathrm{~V} is required to turn back all the ejected electrons, what is the wavelength of the light beam? (a) 355 nm(b) 497 nm(c) 744 nm(d) 1.42 pm(e) none of those answers
The wavelength of the light beam required to turn back all the ejected electrons is 497 nm which is option (b).
Work function is a material property defined as the minimum amount of energy required to infinitely remove electrons from the surface of a particular solid. The potential difference required to support all emitted electrons is called the stopping potential which is given by [tex]v_0=\frac{K.E_m_a_x}{e}[/tex] .....(1)where [tex]v_0[/tex] is the stopping potential and e is the charge of the electron given by [tex]1.6\times10^-^1^9[/tex] .It is given that work function (Ф) of monochromatic light is 2.50 eV.
Einstein photoelectric equation is given by:
[tex]K.E_m_a_x=E-\phi[/tex] ....(2)
where K.E(max) is the maximum kinetic energy.
Substituting (1) into (2) , we get
[tex]ev_0=E-\phi\\1.6\times10^{-19} \times1=E-2.50\\E=1.6\times10^{-19}+2.50\\E=2.50eV[/tex]
As we know that [tex]E=\frac{hc}{\lambda}[/tex] ....(3)
where Speed of light,[tex]c = 3\times10^8 m/s[/tex] and Planck's constant , [tex]h = 6.63\times 10^-^1^9Js = 4.14\times 10^-^1^5 eVs[/tex]
From equation (3) , we get
[tex]\lambda=\frac{hc}{E} \\\\\lambda=\frac{ 4.14\times 10^-^1^5 \times 3 \times10^8}{2.50} \\\\\lambda=\frac{1240\times10^-^9}{2.50} \\\\\lambda=496.8\times10^-^9\\\\\lambda=497nm[/tex]
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A stone of mass 0.12 kg is fired from a catapult. The velocity of the stone changes from 0 to 5.0 m / s in 0.60 s. What is the average resultant force acting on the stone while it is being fired?
Answer:
Explanation:
The answer will be the 1.66N
According to the 1 equation of motion:
v=u+at; where v=final velocity, u=initial velocity, a= acceleration, t=time
According to the given value in question
0=5+a*0.60
a= -5/0.60
a=-13.88m/s2
Now according to the Newton’s 2 law
F=ma; where F=force, m=mass
F=0.12*13.88
F=1.66N
So, the average resultant force acting on the stone while it is being fired will be 1.66N.
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a molecule in the air is moving at a speed 459 m/s. how many meters would the molecule move during 7.00 ms (milliseconds) if you didn’t collide with any other molecules?
The molecule in the air that is moving at a speed 459 m/s during a time of 7.00 ms (milliseconds) if it didn’t collide with any other molecules would move a distance of: 3.213 m
The formula and procedure we will use to solve this exercise is:
x = v * t
Where:
x = distancet = timev = velocityInformation about the problem:
v = 459 m/st = 7.00 msx=?By converting the time units from (ms) to (s) we have:
t = 7.00 ms * 1 s/1000 ms
t = 0.007 s
Applying the distance formula we have that:
x = v * t
x= 459 m/s * 0.007 s
x = 3.213 m
What is velocity?It is a physical quantity that indicates the displacement of a mobile per unit of time, it is expressed in units of distance per time, for example (miles/h, km/h).
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Please identify what is the force indicated at the “X” and what would happen if “X” is greater than the pushing force in the diagram? Make sure to include (Quote and define the force at “X”)
Answer:
X is frictional force
Explanation:
when X is greater than pushing force,the object won't move
The correct answer for the nature of force at "X" is frictional force.
What is friction force?
Friction or frictional force is the force that acts when two surface comes in contact with each other. When a body A is resting upon a body B, The force that helps the body to maintain the equilibrium position is static friction.
Kinetic friction slows down a moving object, when their is relative motion between two objects. It always acts in apposite direction to the force applied.
It is denoted by [tex]F[/tex].
The formula to calculate static friction is [tex]F = \mu N[/tex]
[tex]\mu_s =[/tex] Co-efficient of static friction
[tex]\mu_k =[/tex] Co-efficient of Kinematic friction.
The Force indicated at "X" is "Kinetic friction", It will slow down the moving object.
When "X" is greater than the moving object, the object will stop moving and will remain at rest.
The Force Indicated at "X" is Frictional force.
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please help meeeeeeeee
A long, vertical, metallic wire carries downward electric current. (i) What is the direction of the magnetic field it creates at a point 2cm horizontally east of the center of the wire? (a) north (b) south (c) east (d) west (e) up
At a point 2 cm horizontally east of the wire's center, the magnetic field generated by the vertical wire is pointing south. As a result, option B south is the correct answer.
Why are magnetic fields created?There are north and south poles on every magnet. The same poles repel one another whereas opposite poles are attracted to each other. The north-seeking poles of the iron's atoms pairing in the same direction when it is touched against a magnet. A magnetic field is produced by the force that the aligned atoms produce. The iron object has changed into a magnet. An electric current has the ability to magnetize specific materials. A magnetic field results from the flow of electricity through a coil of wire. But as quickly as the electric current is cut off, the field around the coil will disappear.
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Tech A says that pushing on the brake pedal stops the vehicle by converting chemical energy into thermal
energy. Tech B says that brake pedal pressure is transmitted to the brakes hydraulically. Who is correct?
Tech B is correct. The brake pedal pressure is transmitted to the brakes hydraulically.
How does brake pedal stop a vehicle?The energy of the pads clamping against the rotors and brake shoes pushing against drums generates friction and heat.
This heat-friction, along with friction generated between the tire and road surface, slows rotor and axle rotation and ultimately brings the car to a stop.
Thus, Tech B is correct. The brake pedal pressure is transmitted to the brakes hydraulically.
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A student looks up an element on the periodic table. The table says that the atomic number of the element is 12 and the mass number of the element is 40. What information do these two numbers convey about the element? a The element has 40 protons and 12 neutrons b The element has 12 protons and 12 neutrons c The element has 12 protons and has 28 neutrons d The element has 28 protons and 40 neutrons
If the table says that the atomic number of the element is 12 and the mass number of the element is 40, then the element has 12 protons and 28 neutrons, therefore the correct answer is option C.
What is atomic mass?It is the sum of the mass of all the protons as well as the neutrons that are present inside the nucleus.
The addition of protons and neutrons represents the mass number of any element.
The mass number of any element is the sum of the number of protons and the number of neutrons, therefore the correct answer is option C.
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What does weight require?
Responses
gravity and volume
gravity and volume
only mass
only mass
mass and gravity
mass and gravity
mass and volume
Answer:
Mass and gravity
Explanation:
[tex]{ \rm{weight = mass \times gravity}}[/tex]
Weight is the force exerted on an object due to gravity. The correct answer is mass and gravity. The correct option is an option (3).
Weight requires both mass and gravity.
The formula for calculating weight is given by:
Weight = mass × gravitational acceleration
W = m × g
The gravitational acceleration is known by the strength of the gravitational field, which is typically constant at any given point.
The mass of an object and the strength of its gravitational field is its weight. It is the gravitational force that pulls an object toward the center of the Earth.
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Therefore, The correct option is (3).
The complete question is:
What does weight require?
1) gravity and volume
2) only mass
3) mass and gravity
4) mass and volume
PLEASE HELP ME!
as your friend skateboards down a hill, you measure their velocity at 1.0-second intervals. you record the following data: (0.0 s, 0.0m/s), (1.0 s, 2.3 m/s), (2.0 s, 4.6 m/s). Determine your friends acceleration.
Answer:
Explanation:
it should be 3.2 m/s^2
The acceleration is 3.2 m/ s2. Acceleration is change in velocity per time.
What is acceleration?Any procedure where the velocity varies is referred to as acceleration. There are only two ways to accelerate: changing your speed or changing your direction, or changing both. This is because velocity is both a speed and a direction.
A moving object can occasionally alter its velocity by the same amount every second. The data table above depicts an item altering its velocity by 10 m/s every second, as was described in the paragraph above. Since the velocity is changing by a fixed amount every second, this is known as a constant acceleration.
Therefore, The acceleration is 3.2 m/ s2. Acceleration is change in velocity per time.
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Review. A wire having a linear mass density of 1.00 g/cm is placed on a horizontal surface that has a coefficient of kinetic friction of 0.200 . The wire carries a current of 1.50 A toward the east and slides horizontally to the north at constant velocity. What are (a) the magnitude
Magnetic field due to current in wire is 0.1308 Tesla.
Define Coefficient of friction?The friction coefficient is the ratio of the normal force pressing two surfaces together to the frictional force preventing those surfaces from moving. Typically, it is represented by the Greek letter mu.
Given:
[tex]Mass\;per\;unit\;length(\frac{m}{l})=1.0\;g/cm=0.1\;kg/m\\[/tex]
[tex]Coefficient\;of\;friction,\;(\mu)=0.2[/tex]
[tex]Current,\;(I)=1.5\;A[/tex]
[tex]According\;to\;the\;question,\;wire\;is\;moving\;on\;a\;surface\;with\;\mu\;and\;force\;that\;is[/tex][tex]moving\;the\;wire\;is\;magnetic\;force\;f_{m} , then,[/tex]
[tex]f_{m}=\mu f_{N} (f_{N}=normal\;reaction\;of\;wire)[/tex]
[tex]Also, f_{m}=B\;L\;I\;sin\propto[/tex]
Therefore,
[tex]B_{b}=\frac{\mu\;m\;g}{L\;I\;sin\propto}[/tex]
[tex]B=magnetic\;field[/tex]
[tex]f_{N}=mass \times accelaration\;due\;to\;gravity[/tex]
Therefore,
[tex]B_{b}=\frac{0.2\times0.1\times10}{1.5\times sin\propto}[/tex]
[tex]sin \propto = angle\;magnetic\;field\;and\;the\;current\;in\;the\;wire=sin\;90^{\circ}=1[/tex]
Therefore,
[tex]B_{b}=0.1308\;T[/tex]
Now, from the figure shown and using Fleming's Right Hand rule in which the fore finger indicates current that is in east direction and the thumb indicates force that is in north direction and then direction, shown by your middle finger shows the direction of induced magnetic field.
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At a convergent boundary, what is the relative motion of plates on each side of the boundary?.
Answer:
The plates move toward each other
Explanation:
Search this and you can find the rest of answers for the test
GEO 1405 Chapter 2 Quiz
2. Do you think the density of the ice affected the melting rate of the ice, or do you think adding the objects affected the melting rates?
The density of ice does not affect its melting rate. Adding objects will affect the melting rate.
A physical process called melting or fusing causes a substance to change its phase from a solid to a liquid. This happens when the solid's internal energy rises, usually as a result of heat or pressure being applied, which raises the substance's temperature to the melting point.The term "density" refers to an extensive quality, which means that it is independent of the substance's concentration. Every substance in the world demonstrates its distinctive density. Since it does not fluctuate, it would not affect the rate of melting. The addition of the objects could speed up the process, though, as each one generates heat that could act as the mediating force for the melting process.To learn more about density, visit :
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The motion of a transparent medium influences the speed of light. This effect was first observed by Fizeau in 1851. Consider a light beam in water. The water moves with speed v in a horizontal pipe. Assume the light travels in the same direction as the water moves. The speed of light with respect to the water is c / n , where n=1.33 is the index of refraction of water.(b) Show that for v<
It is proved that when v<<c , then speed of the light measured in the laboratory frame is , u = c/n + v -v/n^2 .
Given ,
The motion of a transparent medium influences the speed of light .
The water moves with speed v in a horizontal pipe .
Assume that the light travels in the same direction as the water moves .
The speed of the light with respect to the water is c/n
Where n = 1.33 is the refractive index of water .
Let us assume ,
u' be the speed of light in water , in the frame moving with the water .
u' is related to the refractive index of water ,n as :
u'=c/n
where , c is the speed of light .
let , u be the speed of light in water in the lab frame .
Now , u and u' are related as : u = (u'+ v )/(1+ u'v/c^2)
Here v is the speed of water in the horizontal pipe .
we know the value of u' , so by substituting the value , we will get ,
u= (c/n+ v)/(1+cv/nc^2)
u= c/n(1+ nv/c)/(1+v/nc)
(b) We have , v<<c
v/c<<1 .
so , (1+v/nc )^-1 = (1-v/nc)
Now substituting this , we will get ,
u = c/n(1+nv/c) (1-v/nc)
u≈c/n(1+ nv/c-v/cn)
u≈c/n + v - v/n^2
Hence , it is proved that when v<<c , then speed of the light measured in the laboratory frame is , u = c/n + v -v/n^2 .
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Disclaimer : incomplete question , here is the complete question .
Question: The motion of a transparent medium influences the speed of light. This effect was first observed by Fizeau in1851. Consider a light beam in water. The water moves with speed v in a horizontal pipe. Assume the light travels in the same direction as the water moves. The speed of light with respect to the water is c / n , where n=1.33 is the index of refraction of water.(a) Use the velocity transformation equation to show that the speed of the light measured in the laboratory frame isu = c/n (1 + nv/c / 1+ v/nc) . (b) show that for v<<c , the expression from part (a) becomes , to a good approximation , u ≈ c/n + v - v/n^2 .
Rank the magnitudes of the following magnetic fields from largest to smallest, noting any cases of equality. (a) the field 2cm away from a long, straight wire carrying a current of 3 A (b) the field at the center of a flat, compact, circular coil, 2cm in radius, with 10 turns, carrying a current of 0.3 A (c) the field at the center of a solenoid 2 cm in radius and 200 cm long, with 1000 turns, carrying a current of 0.3A (d) the field at the center of a long, straight, metal bar, 2 cm in radius, carrying a current of 300 A (e) a field of 1 mT
Magnitude of the magnetic fields from largest to smallest is,
[tex]B_{e}\; > \;B_{c}\; > \;B_{b}\; > \;B_{a}\; > \;B_{d}[/tex]
We know that,
[tex]Permeability\;of\;free\;space,\;\mu_{0} = 4 \times \pi \times 10^{-7}\;H/m\\[/tex]
[tex]l=length[/tex]
[tex]I=current[/tex]
(a)
[tex]Radial\;distance,\;r = 2\;cm=0.02\;m[/tex]
[tex]Current,\;I = 3\;A[/tex]
We know that, Magnetic equation,
[tex]B_{a} =\frac{\mu_{0} \times I}{2\times \pi\times r}[/tex]
Substitute the known values in the above magnetic field equation,
[tex]B_{a}=\frac{4 \times \pi \times 10^{-7} \times 3}{2\times \pi\times 0.02}[/tex]
By solving the equation, we get
[tex]B_{a}=3 \times 10^{-5}\;T[/tex]
(b)
[tex]Radius\;of\;the\;coil,\;r = 0.02\;m[/tex]
[tex]Number\;of\;turns,\;N = 10[/tex]
[tex]Current,\;I = 0.3\;A[/tex]
We know that, Magnetic equation,
[tex]B_{b} =\frac{\mu_{0} \times N \times I}{2\times r}[/tex]
Substitute the known values in the above magnetic field equation,
[tex]B_{b}=\frac{4 \times \pi \times 10^{-7} \times 10 \times 0.3}{2 \times 0.02}[/tex]
By solving the equation, we get
[tex]B_{b}=9.425 \times 10^{-5}\;T[/tex]
(C)
[tex]Length\;of\;the\;solenoid,\;l = 2\;m[/tex]
[tex]Number\;of\;turns,\;N = 1000[/tex]
[tex]Current,\;I = 0.3\;A[/tex]
We know that, Magnetic equation,
[tex]B_{c} =\frac{\mu_{0} \times N \times I}{l}[/tex]
Substitute the known values in the above magnetic field equation,
[tex]B_{c}=\frac{4 \times \pi \times 10^{-7} \times 1000 \times 0.3}{2}[/tex]
By solving the equation, we get
[tex]B_{c}=18.85 \times 10^{-5}\;T[/tex]
(d)
[tex]Current\;through\;the\;bar,\;I = 300\;A[/tex]
At the center of the conductor if we consider an Amperian loop of zero radius, no current will be enclosed by this loop.
Hence, At the center of the conductor magnetic field will be zero
[tex]B_{d}=0[/tex]
(e)
[tex]1 mT=1 \times 10^{-3}[/tex]
Therefore,
[tex]B_{e}=1 \times 10^{-3}\;T[/tex]
Therefore, Magnitude of the magnetic fields from largest to smallest is,
[tex]B_{e}\; > \;B_{c}\; > \;B_{b}\; > \;B_{a}\; > \;B_{d}[/tex]
What is permeability?When placed inside a magnetic field, a material's permeability—which is defined as the number of magnetic lines of force that may pass through a specific surface—allows magnetic flux to pass through it.
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Some towns depend on water from snow that falls high up in the mountains, melts, and flows down the mountain. Some years, spring comes early and the snow begins to melt earlier than usual. What is one problem of early water runoff that engineers might be asked to solve? What criteria and constraints might need to be considered for concerns such as materials, space, and cost?
The problem of early water runoff that engineers might be asked to solve is the issue of Impervious surfaces, or surfaces that are unable to absorb water.
What criteria and constraints might need to be considered are?They are:
RoadsSidewalks, Parking lots are impervious surfaces. Car-washing soapsLitterSpilled gas, etc.In the water cycle, runoff is known to be when water just "streaming off" the surface of the ground. The rain need to also drains downhill, just like the water a person use to wash their car does as a person work are all part of runoff.
Therefore, The problem of early water runoff that engineers might be asked to solve is the issue of Impervious surfaces, or surfaces that are unable to absorb water.
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An interstate highway has been built through a neighborhood in a city. In the afternoon, the sound level in an apartment in the neighborhood is 80.0 dB as 100 cars pass outside the window every minute. Late at night, the traffic flow is only five cars per minute. What is the average latenight sound level?
The level of sound intensity at the late-night is β₂ = 67.0dB
What is a sound level meter?Acoustic measurements are made with a sound level metre, often known as a sound pressure level metre (SPL). A hand-held device with a microphone is the most typical type. The condenser microphone is the best kind of microphone for sound level metres because it combines accuracy with stability and dependability. Sound waves generate changes in air pressure, which the microphone's diaphragm reacts to. The device is sometimes referred to as a sound pressure level metre because of this (SPL).
We are given:
The level of sound intensity in the afternoon is β₁ = 80dB
No. of cars per min in the afternoon = 100
No. of cars per min in late night = 5
The level of sound intensity in the late night β₂ =?
The level of sound intensity in the late night I² =?
Reference sound intensity, I₀ = 10⁻¹²W/m²
The sound intensity level is given by: β = 10Log(I/I₀)
Numerically evaluating,
β₂ = 10 log (5X10⁻⁶/10⁻¹²)
β₂ = 67.0dB
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what is the repulsive force between two pith balls that are 13.5 cm apart and have equal charges of 44.0 nc?
One pith ball's charge, q1, is equal to 30 nC, or 30x10-9C.
the second pith ball's charge, q2 = -30n c= -30x 10-9 c
They are separated by d=8 cm, or 8x10-2 metres.
They repel one another by a force of F = (81/64) x 10-3.
F = 1.266x10^-3 N
Is the force of gravity repellent?The gravitational force is solely an attracting one in both the General Theory of Relativity and Newton's theory of gravity. But quantization of gravity demonstrates that there are opposing gravitational forces as well.
A force between two or more opposite or different charges is called attraction. Two charges that are at odds with one another are attracted to one another. A force between two or more like or comparable charges is called repulsion. Two identical charges separate themselves.
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A football player pushes a 590 n tackling sled. his coach observes this and believes that this is too light and wants to present the player with a greater physical challenge. he asks two players (player a weighs 100 kg and player b weighs 125 kg). the coefficient of static friction between the sled and grass is 0.70. how much force must the player exert to start the tackling sled in motion with players a and b on it
The player has to apply a force of 1956.5N to start tackling sled in motion.
Coefficient of static friction μ[tex]_{s}[/tex] = 0.70
Weight of sled = mg
= 590N
Weight of Player A = [tex]m_{a}g[/tex]
= 100 × 9.8
= 980N
Weight of Player B = [tex]m_{b}g[/tex]
= 125 × 9.8
= 1225N
Combined weight of sled:
W = (590+980+1225)N
= 2795N
Now, friction on sled:
f = μ[tex]_{s}[/tex]R
= 0.70 × 2795
= 1956.5N
Therefore, the player has to apply force equal to static friction to start tackling sled in motion.
∴ Force = Static friction = 1956.5N
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a car with a velocity of 22 m/s is accelerated uniformly at the rate of 1.6 m/s'' for 6.8 s. what is its final velocity?
The final velocity of the car, given the data is 32.88 m/s
What is acceleration?This is defined as the rate of change of velocity which time. It is expressed as
a = (v – u) / t
Where
a is the acceleration v is the final velocity u is the initial velocity t is the time How to determine the final velocityThe following data were obtained from the question:
Initial velocity (u) = 22 m/sAcceleration (a) = 1.6 m/s²Time (t) = 6.8 s Final velocity (v) = ?The final velocity of the car can be obtained as follow:
a = (v – u) / t
1.6 = (v – 22) / 6.8
Cross multiply
v – 22 = 1.6 × 6.8
v – 22 = 10.88
Collect like terms
v = 10.88 + 22
v = 32.88 m/s
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Air (a diatomic ideal gas) at 27.0°C and atmospheric pressure is drawn into a bicycle pump (see the chapteropening photo on page 599 ) that has a cylinder with an inner diameter of 2.50 cm and length 50.0 cm . The downstroke adiabatically compresses the air, which reaches a gauge pressure of 8.00×10⁵ Pa before entering the tire. We wish to investigate the temperature increase of the pump.(g) What is the volume of steel in this 4.00-cm length?
The volume of the 4.00 cm length of the, 1.85 mm thick cylinder pump, that comes to thermal equilibrium with the air is approximately 6.24 cm³.
Which formula can be used to find the volume of the cylindrical pump?Parameters of the question found in a similar question found online are as follows;
Thickness of the steel cylinder, t = 1.85 mm
Length of steel cylinder that comes to thermal equilibrium with the air, l = 4.00 cm
Given parameters;
Inner diameter of the cylinder, d = 2.50–cm
Length of the cylinder = 50.0–cm
Required; Volume of the steel in the 4.00–cm length
Solution;
1.85 mm = 0.185 cm
Volume of the cylinder, V, is found as follows;
V = π•(D² - d²)/4 × l
Where;
D = The outer diameter of the cylindrical pump
d = The inner diameter
l = Length of the cylinder
Therefore;
D = d + 2•t
Which gives;
D = 2.5 + 2 × 0.185 = 2.87
V = (π•(2.87² - 2.5²)/4) × 4 ≈ 6.24
Therefore;
The volume of steel in the 4.00 cm length is 6.24 cm³Learn more about finding the volume of regular shapes here:
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A ball is rolled at a velocity of 2.0 m/s. After 3.6 seconds, it comes to a stop. What is the
acceleration of the ball?
Answer: Given -
Initial velocity of the ball, u = 0 m/sfinal velocity of the ball, v = 12 m/sTime taken = 36 secTo find -
Acceleration of the ball.Solution -
[tex]A=\frac{v-u}{t}\\A=\frac{12-0}{36} \\A=\frac{12}{36} \\A=0.33m/s^2[/tex]
Therefore, the acceleration of the ball is 0.33 m/s².
I hope this helps.
when an object that is moving slows down, which action must be occurring? unbalanced forces unbalanced forces frictional force frictional force gravity gravity balanced forces balanced forces
When a moving thing slows down, gravity action must be taking place on the object.
What is gravity?
Every item is subject to the gravitational pull of the earth, which pulls everything in the atmosphere toward the planet's surface.
Since there is no gravity nor a vacuum in space, the only reason the item is traveling is due to the attraction of the earth's gravitational field.
Therefore, when an item slows down while in motion, gravitational force must be at work. The moon's gravitational pull causes ocean tides, and on Earth, gravity gives weight to physical objects. Additionally, gravity is a key factor in a variety of biological processes, such as gravitropism, which controls plant development, and the fluid movement in multicellular organisms.
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