The initial velocity with which the ball must be thrown upwards in order for it to take 6 seconds to return to its initial level is 29.4 meters/second.
Assuming negligible air resistance, the time taken by a ball to go up and come down after being thrown vertically upwards is given by:
t = 2*v/g
where:
t = time taken for the ball to go up and come down (in seconds)
v = initial velocity with which the ball is thrown upwards (in meters/second)
g = acceleration due to gravity
In this case, the time taken for the ball to return to its initial level is given as 6 seconds. Therefore, we can write:
6 seconds = 2*v/g
Rearranging the equation, we get:
v = (6 seconds * g)/2 = 29.4 m/s
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Two charged spheres electron and proton are 10 cm apart attract each other.
The charge of the spheres are 9. 11 x 10-31 C and 1. 67 x 10-27 C. What force results
from each other? What will be the force if the separation is increased to 30 cm?
Force when The seperation is 10 cm= 1.36 x 10^-45 N and when it is 30 cm= 1.51 x 10^-46 N
To answer your question, we will use Coulomb's Law to calculate the force between the charged spheres (electron and proton). Coulomb's Law states:
F = k * (q1 * q2) / r^2
Where F is the force, k is the electrostatic constant (8.99 x 10^9 Nm^2/C^2), q1 and q2 are the charges of the spheres, and r is the distance between them.
Given the charges q1 = 9.11 x 10^-31 C (electron) and q2 = 1.67 x 10^-27 C (proton), and the initial distance r = 10 cm = 0.1 m, we can calculate the force:
F = (8.99 x 10^9 Nm^2/C^2) * (9.11 x 10^-31 C) * (1.67 x 10^-27 C) / (0.1 m)^2
F ≈ 1.35 x 10^-45 N
Now, let's calculate the force when the separation is increased to 30 cm = 0.3 m:
F_new = (8.99 x 10^9 Nm^2/C^2) * (9.11 x 10^-31 C) * (1.67 x 10^-27 C) / (0.3 m)^2
F_new ≈ 1.50 x 10^-46 N
So, the force between the charged spheres when they are 10 cm apart is approximately 1.35 x 10^-45 N, and when the separation is increased to 30 cm, the force becomes approximately 1.50 x 10^-46 N.
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(b) The aluminium wire will break if the tension in the wire exceeds 350N.
The wire is attached to the flagpole at B, 0. 8 m from the wall.
The wire is at an angle of 20° to the flagpole.
Assess whether the wire will break. You should use the principle of moments, taking
moments about 0.
length of flagpole = 1. 2m
mass of flagpole and flag = 15 kg
The wire won't break because the tension is less than 350N. To assess whether the wire will break, we need to calculate the tension in the wire using the principle of moments to do this, taking moments about point 0.
First, we need to calculate the weight of the flagpole and flag. We know that mass = 15 kg, so we can use the formula weight = mass x gravity, where gravity = 9.8 m/s^2. Therefore, weight = 15 x 9.8 = 147 N.
Next, we need to calculate the force exerted by the wire. We can use trigonometry to find the horizontal and vertical components of this force. The horizontal component is given by F_h = F x cos θ, where F is the tension in the wire and θ is the angle between the wire and the flagpole. In this case, F_h = F x cos 20°.
The vertical component is given by F_v = F x sin θ. In this case, F_v = F x sin 20°.
Now, we can take moments about point 0. The weight of the flagpole and flag acts vertically downwards at a distance of 0.8 m from point 0, so its moment is 147 x 0.8 = 117.6 Nm (clockwise).
The force exerted by the wire acts at an angle of 20° to the flagpole, so its horizontal component acts perpendicular to the flagpole and its vertical component acts parallel to the flagpole. The horizontal component has no moment about point 0, so we only need to consider the vertical component. This acts at a distance of 1.2 m from point 0, so its moment is F_v x 1.2 (anticlockwise).
Setting the moments equal to each other, we get:
147 x 0.8 = F_v x 1.2 x sin 20°
Simplifying this equation, we get:
F_v = 78.7 N
To find the tension in the wire, we can use Pythagoras' theorem:
F = √(F_h^2 + F_v^2) = √((F x cos 20°)^2 + 78.7^2)
Simplifying this equation, we get:
F = 87.6 N
Since the tension in the wire is less than 350N, the wire will not break.
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For the next three questions: A bungee jumper of mass m stands on a platform of height h over a canyon attached to a bungee cord with un-stretched length L and spring constant k.19) Determine the energies and use energy bar charts to illustrate them at the positions a, b, and c (see the figure), as the jumper goes through from the time he starts to jump until the time he stops (at the end of the stretched bungee cord). 20) Determine the energy transfers from position a to b and b to c. 21) Write the energy conservation equation from the start of the jump to the stopping point, which will allow you to find the stretched length AL of the bungee cord. 22) Solve the equation for the stretched length (no numbers, just the variables).
A bungee jumper is a person who jumps off a platform or a tall structure while attached to a bungee cord. The un-stretched length of the bungee cord refers to its length when it is not stretched or extended. Energy transfers refer to the transfer of energy from one form to another, such as from potential energy to kinetic energy or vice versa.
19) When the bungee jumper starts to jump, he has potential energy due to his position above the ground. As he jumps, this potential energy is converted into kinetic energy, which is the energy of motion. At position a, the jumper has all potential energy and no kinetic energy. At position b, he has some potential energy and some kinetic energy. At position c, he has no potential energy and all kinetic energy. The energy bar charts would show the amount of potential and kinetic energy at each position.
20) The energy transfer from position a to b is the transfer of potential energy to kinetic energy. The energy transfer from position b to c is the transfer of kinetic energy back to potential energy as the bungee cord stretches and slows the jumper down.
21) The energy conservation equation is: Potential energy at start = Kinetic energy at stopping point + Potential energy stored in the stretched bungee cord. This equation takes into account that the potential energy is converted into kinetic energy during the jump, and then back into potential energy as the bungee cord stretches and slows the jumper down.
22) Solving for the stretched length AL of the bungee cord would involve using the equation for the potential energy of the bungee cord, which is given by: Potential energy = (1/2)k(AL-L)^2. We would need to use the energy conservation equation to find the total potential energy at the stopping point and then equate it to the potential energy of the bungee cord. We would then solve for AL, the stretched length of the bungee cord.
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a wire of radius with 3.0 mm and length 200 m is melted into a sphere calculate the radius of the sphere in metres
The volume of wire can be calculated as follows:
V_wire = πr²l
where r is the radius of the wire, and l is the length of the wire.
Substituting the given values, we get:
V_wire = π(3.0 mm)²(200 m) = 1.8 x 10⁶ mm³
To calculate the radius of the sphere, we need to use the formula for the volume of a sphere:
V_sphere = (4/3)πr³
Equating the volume of the wire to the volume of the sphere, we get:
(4/3)πr³ = 1.8 x 10⁶ mm³
Solving for r, we get:
r = (3V_wire/4π)^(1/3)
r = [(3 x 1.8 x 10⁶)/(4π)]^(1/3)
r ≈ 20.15 m
Therefore, the radius of the sphere is approximately 20.15 meters.
How does a van de graaff generator create static electricity?.
Answer:
The generator makes static electricity the same way you do when you rub your feet on the carpet and then touch a doorknob.
Explanation:
. Inside the generator is a giant rubber band that rubs across a piece of felt, stealing its electrons. The rubber band then spins around and the electrons travel up to the big metal ball on top.
If the current in a circuit is 3. 2 mA and the resistance of the wire used in the circuit is 250 Ω, what is the voltage of the fuel cell being used?
Formula;
Calculation;
Answer:
If the current in a circuit is 3. 2 mA and the resistance of the wire used in the circuit is 250 Ω, the voltage of the fuel cell being used in the circuit is 0.8 volts.
To calculate the voltage of the fuel cell being used in a circuit, we can use Ohm's law, which states that the voltage (V) equals the current (I) multiplied by the resistance (R): V = I x R.
In this case, the current is 3.2 mA (milliamperes), and the resistance of the wire used in the circuit is 250 Ω (ohms). We first need to convert the current to amperes by dividing it by 1000: 3.2 mA ÷ 1000 = 0.0032 A.
Next, we can substitute these values into the formula to calculate the voltage: [tex]V = 0.0032 \;A \times 250 \;\Omega = 0.8 \;volts.[/tex]
Therefore, the voltage of the fuel cell being used in the circuit is 0.8 volts.
In summary, to calculate the voltage of a fuel cell being used in a circuit, we can use Ohm's law, which states that voltage equals current multiplied by resistance.
By converting the current from milliamperes to amperes and substituting the values into the formula, we can determine the voltage of the fuel cell in volts.
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Why do expanding, aging stars become cooler and more luminous? an overproduction of energy causes the outer layers of gas to expand, whereby the energy is absorbed and the temperature increases. the resulting increase in radiated energy leads to increased luminosity. a decrease in energy causes the outer layers of gas to expand and the temperature to decrease. the resulting increase in radiated energy leads to increased luminosity. a decrease in energy causes the outer layers of gas to expand and the temperature to decrease, and the resulting increase in surface area leads to increased luminosity. an overproduction of energy causes the outer layers of gas to expand. when this happens, the surface area increases rapidly while the temperature decreases rather slowly, and therefore the luminosity increases.
Expanding, aging stars become cooler and more luminous because an overproduction of energy causes the outer layers of gas to expand, whereby the energy is absorbed and the temperature increases. the resulting increase in radiated energy leads to increased luminosity
Define luminosity.
The radiant power that a light-emitting device emits over time is known as luminosity, which is an absolute measure of radiated electromagnetic power. The entire quantity of electromagnetic energy that a star, galaxy, or other celestial object emits over the course of one unit of time is known as luminosity in astronomy.
While the star's core contracts, the outer layers expand, and as the expansion continues, the luminosity rises. The radius and luminosity of a star with the mass of the sun expand 100 times throughout this expansion, which takes place over the course of around a billion years.
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a guitar string 61 cm long vibrates with a standing wave that has three antinodes. part a which harmonic is this?
This standing wave corresponds to the third harmonic. The fundamental frequency of a guitar string is determined by the length of the string, which in this case is 61 cm.
When a standing wave is produced on the string, the nodes (points where the wave has zero displacement) and antinodes (points of maximum displacement) can be counted to determine the harmonic number. In this case, the number of antinodes is 3, which corresponds to the third harmonic.
The fundamental frequency of the string is determined by the equation f = 1/2L√T/m, where L is the length of the string, T is the tension, and m is the mass per unit length of the string. The third harmonic frequency is three times the fundamental frequency, which is calculated by multiplying the fundamental frequency by 3. Therefore, the third harmonic frequency of the guitar string is three times the fundamental frequency.
In addition, the wavelength of the third harmonic is one-third of the wavelength of the fundamental frequency. This is because the wavelength of a wave is inversely proportional to its frequency. The wavelength of the third harmonic is one-third of the wavelength of the fundamental frequency, and the distance between the antinodes is one-third of the wavelength. Therefore, the standing wave with three antinodes corresponds to the third harmonic.
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(g) two masses mand m2(mı > m2) slide down a rough inclined surface of the same
length and inclination. which of the masses would be the first to get to the bottom? give
reasons for your answer.
The first mass with a smaller mass would reach the bottom first due to its greater acceleration and less resistance from friction.
According to Newton's second law of motion, the acceleration of an object is directly proportional to the force applied on it and inversely proportional to its mass. Therefore, the object with the smaller mass would experience a greater acceleration than the object with the larger mass. In the scenario presented in the question, both masses are sliding down the same inclined surface with the same length and inclination. However, since the first object has a smaller mass, it would experience a greater acceleration and would therefore reach the bottom first.
Moreover, since the inclined surface is described as rough, there would be friction acting against the motion of the masses, slowing them down. However, the frictional force is also directly proportional to the normal force acting on the object. The normal force is the force exerted by the surface perpendicular to the object's surface. Therefore, the larger object would experience a greater normal force and consequently a greater frictional force, further slowing it down.
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Write an expression for the speed of the heavier mass as a function of their separation distance, r, which is measured cm to cm and decreases over time as the masses move toward each other due to their gravitational attraction.
The speed of the heavier mass as a function of their separation distance, r, can be expressed using the conservation of energy principle.
As the masses move toward each other due to gravitational attraction, their potential energy decreases and their kinetic energy increases, such that the total energy remains constant.
Therefore, we can write: 1/2 * m1 * [tex]v^{2}[/tex] = G * m1 * m2 / r
where m1 is the mass of the heavier object, m2 is the mass of the lighter object, v is the velocity of m1, r is the separation distance between the two objects, and G is the gravitational constant.
Solving for v, we get:
v = sqrt(2 * G * m2 / r)
This expression shows that as the separation distance r decreases, the velocity v of the heavier object increases due to the increasing gravitational attraction between the two masses.
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15. True or flase: Condensation is the change of state from a liquid to a gas.._______
16. For a gas to become a liquid, large numbers of particles must clump together.
Particles clump together when the attraction between thm overcomes their_________
Throughly explain how all organisms are connected and need each other
Throughly explaining how all organisms are connected and need each other: involves understanding the concept of ecosystems and the various relationships among organisms.
All organisms on Earth are connected through a complex network of interactions in ecosystems. These ecosystems are composed of biotic factors (living organisms) and abiotic factors (non-living elements such as air, water, and soil). Organisms are linked through relationships like predation, competition, and symbiosis, which help maintain a balance in these ecosystems.
In a food chain, organisms are connected as they depend on one another for nutrition. Producers (such as plants) use sunlight to create energy through photosynthesis. Consumers (such as animals) consume the producers or other consumers to obtain energy. Decomposers (such as fungi and bacteria) break down dead organic matter and recycle nutrients back into the ecosystem.
Symbiotic relationships, such as mutualism, commensalism, and parasitism, further illustrate the interdependence of organisms. In mutualism, both species benefit from the relationship, such as bees pollinating flowers while collecting nectar. Commensalism involves one species benefiting without affecting the other, like a barnacle living on a whale's skin. In parasitism, one species benefits at the expense of another, such as a tick feeding on a mammal's blood.
Lastly, all organisms contribute to maintaining the delicate balance within an ecosystem. They help control population levels, recycle nutrients, and maintain overall biodiversity. A disruption in one organism's population can have cascading effects on the entire ecosystem, demonstrating the importance of their interconnectedness.
In summary, all organisms are connected and need each other through their roles in ecosystems, food chains, symbiotic relationships, and their contributions to maintaining balance.
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12) A girl of mass 50 Kg transports a box of mass 20 Kg up a flight of 10 steps, each step 20 cm
high. She takes 16 Seconds to climb up the steps.
a. What is her weight?
b. What is the weight of the box?
c. When she reaches the top what vertical height has she traveled?
Pls help its urgent and I will mark you brainliest
A girl carrying a 20 Kg box climbs up 10 steps, each 20 cm high, in 16 seconds. Her own mass is 50 Kg. Her weight is 490.5N. The weight of the box is 196.2 N. When the girl reaches the top, she has traveled a vertical height of 2 meters.
a. The girl's weight is given by the product of her mass and the acceleration due to gravity. Thus, her weight is:
Weight = mass x acceleration due to gravity
Weight = [tex]50 \;kg \times 9.81 \;m/s^2[/tex]
Weight = 490.5 N
b. The weight of the box is also given by the product of its mass and the acceleration due to gravity. Thus, its weight is:
Weight = mass x acceleration due to gravity
Weight = [tex]20 \;kg \times 9.81 \;m/s^2[/tex]
Weight = 196.2 N
c. The vertical height of each step is given as 20 cm or 0.2 m. Therefore, the total vertical height traveled by the girl is:
Total height = number of steps x height of each step
Total height = 10 steps x 0.2 m/step
Total height = 2 m
Hence, when the girl reaches the top, she has traveled a vertical height of 2 meters.
In summary, we calculated the weight of the girl and the box, and determined the vertical height traveled by the girl when she climbed a flight of 10 steps, each step 20 cm high, in 16 seconds.
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An electron moves with an unknown velocity through a magnetic field of 1. 56 T that points directly east. The electron experiences a force of 6. 24 x 10-15 N directly south. What is the magnitude and direction of the velocity? Show your work. (The charge of an electron is -1. 6 x 10-19 C)
The magnitude of the velocity is 0.0246 m/s and the direction of the velocity is directly north.
The magnetic force on a charged particle is the force experienced by a moving charged particle when it interacts with a magnetic field. When a charged particle moves through a magnetic field, it experiences a force that is perpendicular to both its velocity and the magnetic field direction. This force is known as the magnetic force or the Lorentz force.
The magnitude of the magnetic force is proportional to the charge of the particle, the magnitude of its velocity, and the strength of the magnetic field. The direction of the force is perpendicular to both the velocity vector and the magnetic field vector, following the right-hand rule.
It is given by the formula:
F = qvB
Where F is the force, q is the charge, v is the velocity, and B is the magnetic field.
F = 6.24 x 10⁻¹⁵ N (force)
q = -1.6 x 10⁻¹⁹ C (charge)
B = 1.56 T (magnetic field)
v = F / (qB)
v = (6.24 x 10⁻¹⁵ N) / (-1.6 x 10⁻¹⁹ C) / (1.56 T)
v = -0.0246 m/s
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Dolphins communicate using various sounds, including whistles, clicks, and squeaks. Lower-frequency vocalizations are likely used in social communication, and high-frequency vocalizations are likely used in echolocation. If a dolphin is producing a vocalization with a frequency of 35 Hz traveling at 1,500 m/s, what is the wavelength of the sound?
The wavelength of the sound wave, given that wave has a frequency of 35 Hz and travelling at 1500 m/s is 42.86 m
How do i determine the wavelength?First, we shall list out the given parameters from the question. This is given below:
Frequency of sound wave (f) = 35 HzSpeed of sound wave (v) = 1500 m/sWavelength of sound wave (λ) = ?The wavelength of the sound wave can be obtained as illustrated below:
Velocity (v) = wavelength (λ) × frequency (f)
1500 = wavelength × 35
Divide both sides by 35
Wavelength = 1500 / 35
Wavelength = 42.86 m
Thus, from the above calculation, we can conclude that the wavelength of the sound wave is 42.86 m
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The radium isotope 223Ra, an alpha emitter, has a half-life of 11. 43 days. You happen to have a 1. 0 g cube of 223Ra, so you decide to use it to boil water for tea. You fill a well-insulated container with 460 mL of water at 16∘ and drop in the cube of radium.
How long will it take the water to boil?
Express your answer with the appropriate units
It will take about 11.8 days for the water to boil.
The first step is to find the decay constant (λ) of the radium isotope using the half-life equation:
t1/2 = 0.693/λ
where t1/2 is the half-life.
So, rearranging the equation, we get:
λ = 0.693/t1/2
= 0.693/11.43 days
= 0.0605 day⁻¹
Next, we need to calculate the number of radium atoms in the 1.0 g cube using Avogadro's number and the molar mass of 223Ra:
Number of atoms [tex]= (1.0 g)/(223 g/mol) * (6.022 * 10^{23} atoms/mol)[/tex]
= 2.7 x 10²⁰ atoms
Since each radium atom emits an alpha particle during decay, we can calculate the activity of the radium sample:
Activity = (2.7 x 10²⁰ atoms) x (1 decay/atom) x (1 alpha particle/decay)
= 2.7 x 10²⁰ alpha particles per second
Now, we need to calculate the energy released per alpha particle. The energy (E) released per alpha particle can be calculated using the equation:
E = (Q/m) x Na
where
Q is the energy released per decay,
m is the mass of the radionuclide per decay, and
Na is Avogadro's number.
For 223Ra,
Q = 5.69 MeV,
m = 223/2 = 111.5 g/mol, and
Na = 6.022 x 10^23 atoms/mol.
Therefore,
E = (5.69 MeV/decay)/(111.5 g/mol) x (6.022 x 10²³ atoms/mol)
= 3.84 x 10⁻¹³ J/alpha particle
Finally, we can calculate the rate of energy transfer to the water by multiplying the activity of the radium sample by the energy released per alpha particle:
Rate of energy transfer = (2.7 x 10²⁰ alpha particles/s) x (3.84 x 10⁻¹³ J/alpha particle)
= 1.04 W
To boil the water, we need to transfer enough energy to raise its temperature from 16°C to 100°C and to vaporize it.
The specific heat capacity of water is 4.18 J/g°C, and the heat of vaporization of water is 40.7 kJ/mol, or 2257 J/g. The mass of the water is 460 g, so the total energy required is:
Energy required = (460 g) x (4.18 J/g°C) x (100°C - 16°C) + (460 g) x (2257 J/g)
= 1.06 x 10⁶ J
Finally, we can calculate the time required to transfer this amount of energy to the water using the formula:
Energy transferred = Rate of energy transfer x time
Solving for time, we get:
time = Energy required/Rate of energy transfer
= (1.06 x 10⁶ J)/(1.04 W)
= 1.02 x 10⁶ s
= 11.8 days
Therefore, it will take about 11.8 days for the water to boil.
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How much heat, in joules, is transferred into a system when its internal energy decreases by 125 J while it was performing 30. 5 J of work
94.5 J of heat was transferred out of the system. The first law of thermodynamics states that the change in the internal energy of a system is equal to the heat added to the system minus the work done by the system.
Mathematically, ΔU = Q - W, where ΔU is the change in internal energy, Q is the heat added to the system, and W is the work done by the system.
Given that the internal energy decreases by 125 J while performing 30.5 J of work, we can find the heat transferred into the system as follows:
ΔU = Q - W
-125 J = Q - 30.5 J
Q = -125 J + 30.5 J
Q = -94.5 J
The negative sign indicates that heat was transferred out of the system. Therefore, 94.5 J of heat was transferred out of the system.
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The particles ejected from the sun during a coronal mass ejection, if directed at earth, will reach us.
The statement is true.
If the particles ejected from the Sun during a coronal mass ejection (CME) are directed towards Earth, they can reach our planet.
Coronal mass ejections are powerful eruptions of plasma and magnetic field from the Sun's corona. These ejections can release a large amount of highly energetic particles, including protons, electrons, and ions, into space.
When a CME is Earth-directed, it can travel through the interplanetary medium, which includes the solar wind, and reach our planet. The time it takes for the CME to reach Earth can vary, but typically it ranges from a day to a few days.
When the CME particles interact with the Earth's magnetic field, they can cause a variety of effects, including geomagnetic storms and enhanced auroral displays. The charged particles from the CME can also interact with the Earth's magnetosphere, leading to disturbances in the ionosphere and potential disruptions in satellite communication, power grids, and other technological systems.
Scientists and space agencies closely monitor CMEs and their potential impact on Earth using spacecraft and ground-based observatories to provide early warnings and forecasts of their arrival.
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In a typical lightning strike, 2. 5 c flows from cloud to ground in 0. 20 ms.
The average current during the lightning strike is approximately 12,500 amperes (A). It's important to note that lightning strikes involve extremely high currents and voltages, making them potentially dangerous and capable of causing significant damage.
When a lightning strike occurs, it involves a rapid discharge of electrical energy between a cloud and the ground. The statement you provided indicates that 2.5 coulombs (C) of charge flows from the cloud to the ground in 0.20 milliseconds (ms).
To calculate the average current during this time interval, we can use the formula:
Average current (I) = Charge (Q) / Time (t)
In this case, the charge is 2.5 C, and the time is 0.20 ms (which is equivalent to 0.20 x [tex]10^{(-3)[/tex] seconds). Plugging these values into the formula, we get:
I = 2.5 C / (0.20 x [tex]10^{(-3)[/tex] s)
I = 2.5 C / 2 x [tex]10^{(-4)[/tex]s
I = 12,500 A
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If I make a tortilla by mixing 55 grams of flour and 20 grams of water how much mass should my tortilla have
Answer:
Your tortilla would weigh 75 grams total.
Explanation:
55 grams of flour + 20 grams of water = 75 grams total
The tortilla should have a mass of 75 grams.
What is a mixture?A mixture is a combination of two or more substances that are not chemically bonded and can be separated by physical means. In a mixture, each substance retains its own chemical identity and properties. The properties of a mixture can vary depending on the relative amounts of the substances that are mixed together.
There are two main types of mixtures: homogeneous and heterogeneous.
1. Homogeneous mixtures: These are also called solutions, and they have a uniform composition throughout. The components of a homogeneous mixture are not visible to the bare eye and cannot be separated by simple mechanical means. Examples of homogeneous mixtures include salt water, sugar in water, and air.
2. Heterogeneous mixtures: These are mixtures that do not have a uniform composition throughout. The components of a heterogeneous mixture are visible to the bare eye, and they can be separated by mechanical means such as filtration, sedimentation, or decantation. Examples of heterogeneous mixtures include a mixture of oil and water, a salad, and a mixture of sand and pebbles.
Here in the Question,
The total mass of the tortilla will be the sum of the mass of flour and the mass of water used to make it. So, the tortilla should have a mass of:
55 grams (flour) + 20 grams (water) = 75 grams.
Therefore, the Total mass of the tortilla is 75 Grams.
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You are using power pivot for the first time, but you do not see the power pivot tab. what is the most likely reason
The most likely reason for not seeing the Power Pivot tab is that the add-in is not enabled in Excel.
By default, the Power Pivot add-in is not enabled in Excel, and it needs to be enabled manually.
To enable the Power Pivot add-in, go to the File tab in Excel, select Options, and then select Add-Ins. In the Manage box, select COM Add-ins, and then select Go.
In the COM Add-Ins dialog box, select Microsoft Power Pivot for Excel, and then select OK.
After enabling the add-in, the Power Pivot tab should now be visible in Excel.
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an 82-kg skater is pushed on a frictionless surface through a straight line displacement
of = (13.2m) î + (18.9m) û by a force = (182n) î + (121n) û .
how much work does the force do on the skater during this displacement?
The force does 4688.3 joules of work on the skater during this displacement.
The work done by a force on an object is defined as the product of the force and the displacement of the object in the direction of the force. In this problem, the displacement vector and the force vector are given.
To calculate the work done on the 82-kg skater during the displacement, you need to find the dot product of the force vector and the displacement vector. Here are the given vectors:
Force vector (F) = (182N) î + (121N) û
Displacement vector (d) = (13.2m) î + (18.9m) û
Work (W) = F • d = (182N * 13.2m) + (121N * 18.9m)
W = (2402.4 J) + (2285.9 J)
W = 4688.3 J
It is important to note that since the surface is frictionless, there is no loss of energy due to friction. This means that the work done by the force is equal to the change in the kinetic energy of the skater.
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Jose does push-ups by applying a force to elevate his body 10 cm off the ground. he does 50 j of work. if jose does each push-up in two seconds, what is the power delivered?
physical science.
help please
Answer:
The power delivered by Jose when doing push-ups is 25 watts.
Step-by-step explanation:
The power delivered by Jose is:
[tex]\sf\qquad\dashrightarrow Power = \dfrac{Work}{Time}[/tex]
We know that Jose did 50 J of work in 2 seconds, so we can substitute these values into the equation:
[tex]\sf:\implies Power = \dfrac{50\: J}{2\: s}[/tex]
[tex]\sf:\implies \boxed{\bold{\:\:Power = 25\: W\:\:}}\:\:\:\green{\checkmark}[/tex]
Therefore, the power delivered by Jose when doing push-ups is 25 watts.
The orbit of the moon about the earth is approximately circular, with mean radius of 3,84. 108m. It takes 27,3 days for the moon to complete one revolution about the earth. Find: a) the mean orbital speed of the moon; b) its centripetal acceleration
The centripetal acceleration of the moon is approximately 0.0027 m/s².
To find the mean orbital speed of the moon and its centripetal acceleration, we'll use the given information of the moon's orbit radius and revolution time.
a) To find the mean orbital speed (v) of the moon, we'll use the formula v = 2 * π * r / T, where r is the orbit radius (3.84 x 10^8 m) and T is the revolution time (27.3 days, converted to seconds).
v = 2 * π * (3.84 x 10^8 m) / (27.3 days * 24 hours/day * 3600 s/hour) ≈ 1022 m/s
The mean orbital speed of the moon is approximately 1022 m/s.
b) To find the centripetal acceleration (a_c) of the moon, we'll use the formula a_c = v² / r.
a_c = (1022 m/s)² / (3.84 x 10⁸ m) ≈ 0.0027 m/s²
The centripetal acceleration of the moon is approximately 0.0027 m/s².
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let us recall what is a magnet? How does it work?
Answer:
The magnets are surrounded by an invisible magnetic field that contains stored-up, or potential, energy. When attempting to push two like-sided poles together, the stored-up energy becomes movement, or kinetic energy, and forces them apart. The same principle happens when two unlike poles come together.
Not far from the mirror showcase (the figure shows a top view) there is a person (indicated by point H in the figure), and closer to the showcase there is a lamppost (point C). By building, find the positions at which the observer (points H, which are indicated for example and are not the answer) will see in the window: a person to the left of the pillar; the person to the right of the pillar; a pole blocking a person
The observer (point H) must be positioned to the right of the person and to the left of the lamppost, to the left of the person and to the right of the lamppost, or behind the lamppost to see the person obstructed by it.
To determine the possible positions of the observer (point H) relative to the mirror showcase, we need to consider the given information about the position of the person and the lamppost.
If the person is to the left of the lamppost (point C) as seen in the window, then the observer (point H) must be positioned to the right of the person and to the left of the lamppost. This is because the mirror will reflect the image of the person to the right, and the observer must be positioned to the right of the reflected image to see it.
If the person is to the right of the lamppost (point C) as seen in the window, then the observer (point H) must be positioned to the left of the person and to the right of the lamppost. This is because the mirror will reflect the image of the person to the left, and the observer must be positioned to the left of the reflected image to see it.
If the lamppost (point C) obstructs the view of the person as seen in the window, then the observer (point H) must be positioned behind the lamppost, either to the left or to the right of it. This is because the mirror will not be able to reflect the image of the person due to the obstruction caused by the lamppost.
In summary, the possible positions of the observer (point H) relative to the mirror showcase are:
To the right of the person and to the left of the lamppost, to see the person to the left of the lamppost. To the left of the person and to the right of the lamppost, to see the person to the right of the lamppost. To the left or right of the lamppost, behind it, to see the obstruction of the person caused by the lamppost.
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Complete question:
Using the given information, determine the possible positions of the observer (point H) relative to the mirror showcase such that the following are observed:
1 - The person is to the left of the lamppost (point C) as seen in the window.
2 - The person is to the right of the lamppost (point C) as seen in the window.
3 - The lamppost (point C) obstructs the view of the person as seen in the window.
The arrows in this diagram are meant to show how gravitational equilibrium works in the sun. What do the different colors and different arrow lengths represent?.
In the context of the Sun, gravitational equilibrium refers to the balance between the inward gravitational force and the outward pressure force that acts within the Sun's interior. This equilibrium is crucial for maintaining the Sun's stability and preventing its collapse or runaway expansion.
In a simplified explanation, the gravitational force in the Sun's core is responsible for pulling matter inward. At the same time, the high temperatures and pressures in the core generate intense radiation pressure and gas pressure, pushing matter outward. The combination of these inward and outward forces creates a balance.
Different regions within the Sun contribute to this equilibrium, with variations in temperature, density, and pressure. These variations can result in different colors and arrow lengths in a diagram, which may represent the following:
1. Colors: Different colors might be used to represent different regions or layers within the Sun, each with its specific characteristics and properties. For example, the core, radiative zone, and convective zone of the Sun have distinct temperature and pressure profiles, which could be depicted using different colors.
2. Arrow Lengths: Arrow lengths might be used to illustrate the strength or magnitude of the forces involved. Longer arrows could indicate stronger forces, such as higher pressure or greater gravitational forces. Shorter arrows may represent weaker forces or areas where the forces balance each other.
It's important to note that the specific colors and arrow lengths used in a diagram can vary depending on the particular representation and the context of the diagram you are referring to. It would be helpful to provide a description or more specific details about the diagram for a more accurate interpretation.
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How many grams are in 0. 02mol of Mg (25. 3g/mol)
There are 0.486 grams of magnesium in 0.02 moles of magnesium.
To calculate the grams of magnesium, you multiply the given moles (0.02 mol) by the molar mass (24.3 g/mol):
0.02 mol Mg × 24.3 g/mol Mg = 0.486 g Mg
Therefore, there are 0.486 grams of magnesium in 0.02 moles of magnesium.
It's important to note that molar mass allows us to convert between moles and grams. By multiplying the number of moles by the molar mass, we can determine the mass of the substance in grams.
This conversion is commonly used in chemistry to relate the quantity of a substance in moles to its corresponding mass in grams.
In this case, by multiplying the given moles (0.02 mol) of magnesium by the molar mass of magnesium (24.3 g/mol), we obtain the mass of magnesium in grams (0.486 g).
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A stretched wire vibrates in its fundamental mode at a frequency of 235 hz. What would the fundamental frequency be if the wire was half as long, with twice the diameter and four times the tension?
If the wire were half as long, had twice the diameter, and four times the tension, its fundamental frequency would be 332.2 Hz.
The fundamental frequency of a vibrating stretched wire is determined by several factors, including the length, diameter, tension, and mass per unit length of the wire. In this case, we are given that the wire vibrates at a frequency of 235 Hz in its fundamental mode. We are also given that if the wire were half as long, had twice the diameter, and four times the tension, what would be the new fundamental frequency
First, let's consider the effect of halving the length of the wire. The fundamental frequency of a wire is inversely proportional to its length, so halving the length would double the frequency to 470 Hz.
Next, let's consider the effect of doubling the diameter of the wire. The fundamental frequency of a wire is inversely proportional to the diameter, so doubling the diameter would halve the frequency to 235/2 = 117.5 Hz.
Finally, let's consider the effect of quadrupling the tension in the wire. The fundamental frequency of a wire is directly proportional to the square root of its tension, so quadrupling the tension would double the frequency to 235*sqrt(2) = 332.2 Hz.
Combining all these effects, the new fundamental frequency of the wire would be:
[tex]$117.5 \text{ Hz} \times 2 \times \sqrt{2} = 332.2 \text{ Hz}$[/tex]
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A gas has a temperature of 14 °C, and a volume of 4. 5 L. If the temperature is raised to 29 °C and the pressure is not changed, what is the new volume of the gas? A. 4. 7 L B. 4. 9 L C. 5. 3 L D. 5. 5 L
The new volume of the gas when the temperature is raised to 29°C and the pressure is not changed is approximately :4.73 L. The correct option is A.
To determine the new volume of a gas when its temperature is changed, we can use Charles' Law. Charles' Law states that the volume of a gas is directly proportional to its temperature, provided that the pressure remains constant. Your initial temperature (T1) is 14°C, and the initial volume (V1) is 4.5 L.
The final temperature (T2) is 29°C, and we need to find the new volume (V2). Remember to convert the temperatures from Celsius to Kelvin by adding 273.15 to each value (T1 = 287.15 K, T2 = 302.15 K).
Using Charles' Law, we have:
V1/T1 = V2/T2
Now, we can plug in the values:
(4.5 L)/(287.15 K) = V2/(302.15 K)
To find V2, multiply both sides by 302.15 K:
V2 = (4.5 L x 302.15 K) / 287.15 K
V2 ≈ 4.73 L
The new volume of the gas when the temperature is raised to 29°C and the pressure is not changed is approximately 4.73 L. The correct option is A.
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Complete question:
A gas has a temperature of 14 °C, and a volume of 4. 5 L. If the temperature is raised to 29 °C and the pressure is not changed, what is the new volume of the gas?
A. 4. 7 L
B. 4. 9 L
C. 5. 3 L
D. 5. 5 L