Need help plz with the code

Typically, external fragmentation wastes one-third of memory. Internal fragmentation occurs when space inside a designated region is wasted. Thus, option D is correct.

The mounted-sized block is allotted to a method whenever a request for memory is made. Internal fragmentation is the term used to describe the situation where the memory allotted to the method is a little bigger than the amount requested.

Normally, memory is allocated in uniformly sized blocks, but sometimes a process doesn't use the entire block, leading to internal fragmentation.

Memory fragmentation occurs when a memory allocation request can be satisfied by the whole amount of accessible space in a memory heap, but no single fragment (or group of contiguous fragments) can.

Therefore,  when the three subroutines are loaded into memory using each of the following page sizes 900 words.

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Answer:

D Mark as Unread

Explanation:

I just took the test

the variable a & b and A & B are different. So the only program that work is at #main program.

Hence that A = 8 and B = 4 and the result is A * B so 8*4=32.

Sorry if im wrong

32  will be the output of this question

An industry's output is the total amount of goods and services generated within that industry over a specific time period and sold to customers or other firms. An industry's annual production of boxes of cookies or tons of sugar, for instance, can be considered output.

The quantity a person produces in a particular period of time. d.: energy or power given or produced by a device or system (as for storage or for conversion in kind or in characteristics)Here is how we might define these two phrases in business terms: The results are what the business requires or wants to accomplish. The acts or things that help achieve an outcome are called the outputs.

Variables a and b and A and B are distinct. Thus, the #main program is the only program that functions. Because A = 8 and B = 4, the outcome is A * B, which equals 8*4=32.

Therefore,  the output of this question

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Answer:

see picture

Explanation:

There are several syntax errors in the program that need to be fixed:

So the actual answer would be: the compiler will report syntax errors.

Answer:

the no is20

Hello#######

Bye:

Reason: Programming, hoped this is right!

Answer:

a. True

Explanation:

The above listed information are part of the reasons why so many IT projects are abandoned by the business entities after a given period of time frame.

Answer:

b. 0001100

Explanation:

1100

Answer:

its is 810000

Explanation:

hope this helps

Answer:

Alaric Saltzman.

The Originals.

Car crash, ran off Wickery bridge.

Explanation:

Answer:

okkk I got this TVD since forever

Explanation:

Alaric Saltzman

They are called the original vampires (Mikael, Finn, Elijah, Klaus, Kol, and Rebekah)

Elena parents died on the way back home from picking up Elena from a party. They end up driving off the Wickery Bridge. Stefan saved Elena though he was going to save Elena dad first however her dad told Stefan to get Elena.

Answer:

Removes characters behind (or to the left of) the insertion point.

Explanation:

Answer:

In Python:

doorLength = float(input("Door Length: "))

doorWidth = float(input("Door Width: "))

windowLength1 = float(input("Window 1 Length: "))

windowWidth1 = float(input("Window 1 Width: "))

windowLength2 = float(input("Window 2 Length: "))

windowWidth2 = float(input("Window 2 Width: "))

shelfLength = float(input("Bookshelf Length: "))

shelfWidth = float(input("Bookshelf Width: "))

totalarea = doorLength * doorWidth + windowLength1 * windowWidth1 + windowLength2 * windowWidth2 + shelfLength*shelfWidth

gallons = totalarea/120

print("Gallons: "+str(gallons))

Explanation:

The next two lines get the dimension of the door

doorLength = float(input("Door Length: "))

doorWidth = float(input("Door Width: "))

The next two lines get the dimension of the first window

windowLength1 = float(input("Window 1 Length: "))

windowWidth1 = float(input("Window 1 Width: "))

The next two lines get the dimension of the second window

windowLength2 = float(input("Window 2 Length: "))

windowWidth2 = float(input("Window 2 Width: "))

The next two lines get the dimension of the shelf

shelfLength = float(input("Bookshelf Length: "))

shelfWidth = float(input("Bookshelf Width: "))

This calculates the total area of the door, windows and bookshelf

totalarea = doorLength * doorWidth + windowLength1 * windowWidth1 + windowLength2 * windowWidth2 + shelfLength*shelfWidth

This calculates the number of gallons needed

gallons = totalarea/120

This prints the number of gallons

print("Gallons: "+str(gallons))

Answer:

1024 bytes in a megabyte and there are 8000000 bits in a megabyte. They are different.

Explanation:

There are 8000000 bits and 1024 bytes in one megabyte. They are unique.

The megabyte is a multiple of the digital informational unit byte. The suggested unit sign for it is MB. The International System of Units unit prefix mega is a multiplier of 1000,000. As a result, one megabyte is equal to one million bytes of data.

About a million bytes make up a megabyte (or about 1000 kilobytes). Typically, a few megabytes might be required for a 10-megapixel digital camera photograph or a brief MP3 music clip.

1000000 bytes make up one megabyte (decimal). In base 10, 1 MB equals 106 B. (SI). 1048576 bytes make up a megabyte (binary). A megabyte can imply either 1,000,000 bytes or 1,048,576 bytes, according to the Microsoft Press Computer Dictionary. Apparently, Eric S.

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Answer:

In Java:

import java.util.*;

public class Main{

public static boolean isArrayEven(int[] arrayValues, int arraySize){

   boolean val = true;

   int odd = 0;

   for(int i =0;i<arraySize;i++){

       if(arrayValues[i]%2!=0){

           odd++;        }}

   if(odd>0){

       val = false;}

   return val;

}

public static boolean isArrayOdd(int[] arrayValues, int arraySize){

   boolean val = true;

   int even = 0;

   for(int i =0;i<arraySize;i++){

       if(arrayValues[i]%2==0){

           even++;}}

   if(even>0){

       val = false;}

   return val;

}

public static void main(String[] args) {

 Scanner input = new Scanner(System.in);

 System.out.print("Array Length: ");

 int n = input.nextInt();

 int[] array = new int[n];

 System.out.print("Array Elements: ");

 for(int i = 0;i<n;i++){

     array[i] = input.nextInt();  }

boolean even = isArrayEven(array,n);

 boolean odd = isArrayOdd(array,n);  

 if(even == true && odd == false){

     System.out.print("all even");  }

 else if(even == false && odd == true){

     System.out.print("all odd");  }

 else{

     System.out.print("not even or odd");  }

}

}

Explanation:

This declares the isArrayEven method

public static boolean isArrayEven(int[] arrayValues, int arraySize){

This initializes the return value to true

   boolean val = true;

This initializes the frequency of odd numbers to 0

   int odd = 0;

This iterates through the array

   for(int i =0;i<arraySize;i++){

This checks if the current array element is odd

       if(arrayValues[i]%2!=0){

If yes, the frequency of odd numbers is incremented by 1

           odd++;        }}

If the frequency of odd is greater than 1, then the array is not an even array

   if(odd>0){

       val = false;}

This returns true or false

   return val;

}

This declares the isArrayOdd method

public static boolean isArrayOdd(int[] arrayValues, int arraySize){

This initializes the return value to true

   boolean val = true;

This initializes the frequency of even numbers to 0

   int even = 0;

This iterates through the array

   for(int i =0;i<arraySize;i++){

This checks if the current array element is even

       if(arrayValues[i]%2==0){

If yes, the frequency of even numbers is incremented by 1

           even++;}}

If the frequency of even is greater than 1, then the array is not an odd array

   if(even>0){

       val = false;}

This returns true or false

   return val;

}

The main method begins here

public static void main(String[] args) {

 Scanner input = new Scanner(System.in);

This prompts for length of array:  System.out.print("Array Length: ");

This gets input for length of array  int n = input.nextInt();

 int[] array = new int[n];

This prompts for array elements: System.out.print("Array Elements: ");

This gets input for the array

 for(int i = 0;i<n;i++){

     array[i] = input.nextInt();

 }

This calls the isArrayEven method and the result is stored in even

boolean even = isArrayEven(array,n);

This calls the isArrayOdd method and the result is stored in odd

 boolean odd = isArrayOdd(array,n);  

The following prints the result of the methods

 if(even == true && odd == false){

     System.out.print("all even");  }

 else if(even == false && odd == true){

     System.out.print("all odd");  }

 else{

     System.out.print("not even or odd");  }

Answer:

A

Explanation:

Answer:

Defined Expression

Explanation:

This will be your answer

Its easy that moderators that see this answer can think that my answer isn't without explanation.

• Type of atom C (Carbon)

C = 1

• Type of atom H (Hydrogen)

H = 4

You dont understand? JUST SEE THE FORMULA C MEANS ONLY HAVE 1 CARBON ATOM AND H4 MEANS 4 ATOM OF HYDROGEN

oK. have a nice day hope you understands

Answer:

the answer is in the image below:

Explanation:

Answer:

Answer choice 4

Explanation:

If Josh sends an e-mail to his... co-worker.... wouldn't that be... workplace communication?

Answer:

As long as it works like a game and not a book i would say its a game.

Explanation:

Answer: Find the app you want to close, then go to the moveable panel and click the X.

Answer: Sequence

Brainliest me and reply if im right!

Answer: False

Reason: There's a lot more then 10 thousand computers on the internet.

Answer:

to make a name for themselves

Explanation:

isljgaek jadkghdkjhasdkjfhadskj afhdsfkjdahk dh

Answer:

I never knew that, thank you for telling me! I'll note that down

Answer:

#include <iostream>//header file

#include <string>//header file

using namespace std;

string integer_to_reverse_binary(int integer_value)//defining a method integer_to_reverse_binary  

{

   string ret = "";//defining string variable

   while (integer_value > 0) //using while loop to check integer_value value is greater than 0

   {

       ret += '0' + (integer_value % 2);//adding zeros in remainder value

       integer_value /= 2;//holding quotient value

   }

   return ret;//return string value

}

string reverse_string(string input_string)//defining a method reverse_string that holds a parameter user_String  

{

   string result;//defining a string variable  

   for (int i = 0; i < input_string.length(); ++i)//use for loop to calculate value  

   {

       result += input_string[input_string.length()-i-1];//add value in result variable

   }

   return result;//result result variable value

}

int main()//defining main method  

{

   int num;//defining integer variable

   string str;//defining string variable

   cin >> num;//input num value

   str = integer_to_reverse_binary(num);//use str variable to call the integer_to_reverse_binary method

   cout << reverse_string(str) << endl;//printing the reverse_string method value

   return 0;

}

Output:

6

110

Explanation:

In this code two string method "integer_to_reverse_binary and reverse_string" is defined that holds one parameter "integer_value and input_string".

In the first method a string variable is defined, that use the while loop to check integer value is greater than 0 and add zeros in the value and return its value as a string.

In the second it reverse the string value and store into the result variable, and in the main method the "num and str" variable is defined, and in the num it takes integer value and pass into the above method and print its return value.    

Answer:

Following are the solution to this question:

Explanation:

Its complexity of both the pseudo-code described is indeed proportional to the number of digits. So, how often number there are in this specific number is the query. Whenever a number is considered, the d digit would be between [tex]10^{(d-1)}.[/tex] inclusive exclusive [tex]10^d[/tex] That would be as, let d become the number of digits at N, and the inequalities, They can tell

[tex]10^{(d-1)} \leq N < 10^d[/tex]

We get, we take a logarithm,

[tex]d-1 \leq \log(N) < d[/tex]

The increase of 1 to the left inequality, [tex]d \leq \log(N)+1[/tex], and Combining the previous outcome, we got, [tex]\log(N) < d \leq \log(N) + 1[/tex]. That's would be to say, that number of number d by [tex]O(\log(N))[/tex] is higher and lower. Consequently, the number of transactions in the code is [tex]O(\log(N))[/tex]

We have that the number of operations that are executed in the code in terms of n  is mathematically given as

The quantity of operations done in the code is O(log(N))

Generally the equation for the   is mathematically given as

If we think about a number,

with d digits is between 10^(d-1) inclusive and 10^d exclusive.

Let d be the wide variety of digits in N

10^(d-1) <= N < 10^d

d-1 <= log(N) < d

d <= log(N) + 1,

The Inequality

log(N) < d <= log(N) + 1.

Therefore

The quantity of operations done in the code is O(log(N))

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Answer:

it depend on the software the computer has along with how much data it can hold

Explanation:

Answer:

Depends on the software code the computer has

Explanation: