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To model with mathematics is to test ideas using math and computer programs to simulate an object or action.

In order to understand a real-life problem, modelling entails developing a set of mathematical equations that accurately reflects a situation.

The model frequently needs to be modified because it does not adequately capture the situation.

By knowing how the system functions, which variables are significant in the system, and how they relate to one another, one can utilise a mathematical model to better understand a real-life situation. Moreover, models can be used to forecast and predict what a system will do in the future or for various parameter values. Finally, a model can be used to estimate variables that are challenging to precisely evaluate.

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Determing how many x intercepts the graph has, as those are the points when y = 0.

The number of touchdowns scored by this professional football team could be: C. 10.

In Mathematics, a percentage simply refers to any number that is expressed as a fraction of hundred (100). This ultimately implies that, a percentage indicates the hundredth parts of any given number.

In order to determine the number of points scored by the defense of this professional football team, we would use the following mathematical expression:

Number of points = 24/100 × 242

Number of points = 0.24 × 242

Number of points = 58.08

For the number of touchdowns, we have:

Number of touchdowns = 58.08/6

Number of touchdowns = 9.68 touchdowns.

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Given : A  = 24 sq feet

A = 0.5 base x height

base = x , height = x+2

A = 0.5 x(x+2)  = 24 sq feet

1) 0.5 x(x+2) = 24 (A)

2) x^2 + 2x - 48 = 0 (D)

To check the rest un-wrap the bracket:

x^2 + (x+2)^2 = 24

x^2 + x^2 + 4 + 4x = 24

2x^2 + 4x - 20 = 0

x^2 + 2x - 10= 0 (NO)

Likewise:

x^2 + (x+2)^2 = 100

x^2 + x^2  +4 + 4x = 100

2x^2 + 4x + 4 = 100

2x^2 + 4x - 96 = 0

3) x^2 + 2x - 48 = 0 (F)

To sum up: that's what apply:

1) 0.5 x(x+2) = 24 (A)

2) x^2 + 2x - 48 = 0 (D)

3) x^2 + 2x - 48 = 0 (F)

Answer: To find the equation of a line parallel to 12x + 8y = -40, we need to first rearrange the equation into slope-intercept form, y = mx + b, where m is the slope and b is the y-intercept.

12x + 8y = -40

8y = -12x - 40

y = -1.5x - 5

So, the slope of the line is -1.5.

Since the line we want is parallel to this line, it will have the same slope, which is -1.5. Now we can use the point-slope form of a line to find the equation:

y - y1 = m(x - x1)

where (x1, y1) is the point through which the line passes, and m is the slope.

Substituting (6,-3) and -1.5 for x1, y1, and m respectively, we get:

y - (-3) = -1.5(x - 6)

y + 3 = -1.5x + 9

y = -1.5x + 6

So the equation of the line parallel to 12x + 8y = -40 through the point (6,-3) is y = -1.5x + 6.

Step-by-step explanation:

Answer:

cos^2 θ/2 = (cos θ + 1)/2.

Step-by-step explanation:

We can use the identity cos 2θ = 2cos^2 θ - 1 to derive an identity for cos^2 θ/2:

cos 2(θ/2) = cos θ

Replacing θ/2 with x:

cos 2x = cos 2(x/2)

Using the double angle formula for cosine:

cos 2x = 2cos^2 x - 1

Substituting θ/2 for x:

cos θ = 2cos^2 (θ/2) - 1

Rearranging this formula, we can solve for cos^2 θ/2:

2cos^2 (θ/2) = cos θ + 1

cos^2 (θ/2) = (cos θ + 1)/2

Therefore, cos^2 θ/2 = (cos θ + 1)/2.

Answer:

It is not possible to form a right triangle with the lengths 4, 8, and 10 because the longest side of the triangle must be shorter than the sum of the other two sides. This is known as the Pythagorean Theorem, which states that in a right triangle, the square of the longest side (the hypotenuse) is equal to the sum of the squares of the other two sides. Since 8² + 10² = 164, and 10 is greater than the sum of 4 + 8, it is not possible to form a right triangle with those three lengths.

In this case, assuming that 10 is the hypotenuse, we have:

10² = 4² + 8²

100 = 16 + 64

This equation is not true, as 100 is not equal to 80. Therefore, we cannot form a right triangle

Answer:

The price of a hot dog is $2.00

The pοssible decimals that satisfy the given cοnditiοns are:5.20, 5.22, 5.24, 5.26, 5.28, 5.60, 5.62, 5.64, 5.66, 5.68, 7.20, 7.22, 7.24, 7.26, 7.28, 7.60, 7.62, 7.64, 7.66, 7.68

Decimals are a way οf expressing numbers that fall between whοle numbers, using a decimal pοint tο separate the whοle number and the fractiοnal part. Each digit tο the right οf the decimal pοint represents a decreasing pοwer οf 10, starting frοm tenths, hundredths, thοusandths, and sο οn.

Since the digit in the tenths place is οdd, it can οnly be 5 οr 7. Similarly, since the digit in the hundredths place is even, it can οnly be 0, 2, 4, 6, οr 8.

Therefοre, the pοssible decimals that satisfy the given cοnditiοns are:

5.20

5.22

5.24

5.26

5.28

5.60

5.62

5.64

5.66

5.68

7.20

7.22

7.24

7.26

7.28

7.60

7.62

7.64

7.66

7.68

Nοte that these are the οnly pοssible decimals that satisfy all the given cοnditiοns.

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Answer:

The given complex number is (-2.5 + i4.2).

To express it in exponential form, we need to find the modulus (r) and argument (θ) of the complex number.

The modulus is given by:

|r| = √((-2.5)^2 + (4.2)^2) = √(6.25 + 17.64) = √23.89 ≈ 4.888

The argument is given by:

θ = tan⁻¹(4.2/(-2.5)) = tan⁻¹(-1.68) ≈ -1.03 radians

Therefore, the exponential form of the complex number is:

(-2.5 + i4.2) = 4.888e^(-i1.03)

The ball may rise height a maximum of [tex]119[/tex] feet.

Height, altitude, and elevation all refer to the vertical distance between something's top and bottom or its base but something above it. Anything that can be measured vertically, whether it is high or low, is referred to as having height.

As the ball hits the quadratic function's vertex, it has grown to its highest point. The position (b, c), wherein b is the vertex's x-coordinate, is where a quadratic function of the type is said to have its vertex.

As the quadratic function in this instance is, the point serves as the vertex (5, 119). The ball therefore reaches its highest point after 5 seconds.

[tex]h=-16(5-5)^{2}+119[/tex]

[tex]h=119[/tex]

Therefore, the maximum height of the ball is [tex]119[/tex] feet.

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Pattern blocks are shapes that are used to illustrate math equations. They can be used to represent addition, subtraction, multiplication and division. If five hexagons are stacked on top of each other, then the equation can be read as 5 x 1.

Pattern blocks are a great visual tool for teaching younger children basic multiplication. They can help children understand the concept of multiplication better, as well as help them to remember the equation. Pattern blocks are also a great way to show the relationship between addition and multiplication, since both equations can be represented using the same shapes. By using pattern blocks to illustrate multiplication equations, children can have a more concrete understanding of the concept.

For multiplication, there are two different ways to use pattern blocks. The first way is to use the number of sides on a pattern block to represent the multiplication equation. For example, if two hexagons are used to represent 2 x 2, then the equation can be read as two times two. The second way is to simply stack the pattern blocks in order to represent the equation. For example, if five hexagons are stacked on top of each other, then the equation can be read as 5 x 1.

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Therefore, the stamp's estimated value is $21.54 considering that when he first got it, it was only worth $14.50.

A mathematical assertion that two expressions are equivalent is known as an equation. The equal symbol (=) separates the two sides, which are labeled as the left-hand side (LHS) and the right-hand side (RHS). The equation must have identical values on both sides, and it is frequently used to determine an unknown variable's value.

Numerous mathematical processes, such as addition, subtraction, multiplication, division, exponents, logarithms, and more, can be used in equations.

given

a. The formula for the stamp's worth V after t years is as follows:

[tex]V = 14.50(1 + 0.02)^t[/tex]

where t is the period of time since Leroy got the stamp, and 0.02 denotes a 2% annual increase in value.

b. We enter t = 18 into the equation to estimate the stamp's value after 18 years:

[tex]V = 14.50(1 + 0.02)^{18[/tex]

[tex]V = 14.50(1.02) (1.02)^{18[/tex]

V = 14.50(1.485) (1.485)

V = 21.54

Therefore, the stamp's estimated value is $21.54 considering that when he first got it, it was only worth $14.50.

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Answer:

18π or

Step-by-step explanation:

To find the area of a semicircle, use the formula of the area of a semicircle.

Area = [tex]\frac{1}{2}[/tex] π r^2

Radius = 6

Area = [tex]\frac{1}{2}[/tex] π 6^2

Area = [tex]\frac{1}{2}[/tex] (36π)
Area = 18π (in terms of π)

Area = 56.52 (in terms of 3.14)

The required population of Algeland 16 years from now will be approximately 524937236.

In essence, percentages are fractions with a 100 as the remainder. We place the percent sign (%) next to the number to indicate that the number is a percentage. For instance, you would have received a 75% grade if you answered 75 out of 100 questions correctly on an examination (75/100).

To find the population of Algeland after 16 years, we can use the formula:

[tex]$P = P_0 \times (1 + r)^n$[/tex]

where P is the population after 16 years, [tex]$P_0$[/tex]is the initial population, r is the annual growth rate, and n is the number of years.

Given that the population of Algeland increases by 33% each year, we can express the annual growth rater as:

[tex]$r = 33% = 0.33$[/tex]% = 0.33

We are also given that the current population [tex]$P_0$[/tex] is 5,476,223.

Thus, the population of Algeland after 16 years can be calculated as:

[tex]$P = 5,476,223 \times (1 + 0.33)^{16}$[/tex]

Simplifying this expression, we get:

P = 524937236

Therefore, the population of Algeland 16 years from now will be approximately 524937236.

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The volume of the figure is 93π

From the question, we have the following parameters that can be used in our computation:

The composite figure

The volume is calculated as

Volume = Cone + Cylinder

Using the above as a guide, we have the following:

Volume = 1/3πr²(H - h) + πr²h

Substitute the known values in the above equation, so, we have the following representation

Volume = 1/3π * 3² * (15 - 8) + π * 3² * 8

Evaluate

Volume = 93π

Hence, the volume is 93π

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Answer: 36 cubes

Step-by-step explanation:

Length x Width x Height

18 x 6 x 9 = 972

3 x 3 x 3 = 27

972 / 27 = 36

Answer:

B) 15 days

Step-by-step explanation:

Total Work = (Number of men) x (Hours worked per day) x (Number of days)

Using this formula, we can find the total amount of work to be done in the scenario given in the question:

Total Work = (20 men) x (6 hours per day) x (10 days) = 1200 hours

(a) To find out how many hours a day the remaining 16 men should work to finish the work in 10 days, we need to subtract the work that was not done due to the absence of the 4 men:

Remaining Work = Total Work - Work not done by 4 men

Remaining Work = 1200 - (4 men) x (6 hours per day) x (10 days)

Remaining Work = 840 hours

To finish the remaining work in 10 days, the 16 men would need to work:

Hours per day = Remaining Work / (Number of men) x (Number of days)

Hours per day = 840 / (16 men) x (10 days)

Hours per day = 5.25 hours

Therefore, the 16 men would need to work 5.25 hours per day to finish the work in 10 days.

(b) To find out how many hours a day the remaining 16 men should work to finish the work in 15 days, we need to calculate the total amount of work that needs to be done each day:

Daily Work = Total Work / Number of days

Daily Work = 1200 / 15

Daily Work = 80 hours

To finish the daily work of 80 hours, the 16 men would need to work:

Hours per day = Daily Work / Number of men

Hours per day = 80 / 16

Hours per day = 5 hours

Therefore, the 16 men would need to work 5 hours per day to finish the work in 15 days.

Step-by-step explanation:

subs8biiisowm9bbbs9 to

Answer:

We can use inequality B to determine the number of sessions Sam needs to conduct. The reason is that he already has $50 and he wants to have enough money, so he needs to earn the remaining amount through tutoring. Thus, we can write the inequality as:

15s + 50 ≥ 125

where s is the number of tutoring sessions he needs to conduct. We can simplify and solve for s as follows:

15s ≥ 75

s ≥ 5

Therefore, Sam needs to conduct at least 5 tutoring sessions to have enough money to buy the video game.

Answer:

974.4

Step-by-step explanation:

Answer:

974.4

Step-by-step explanation:

The tenth place is located the digit to the right of the decimal point, in this case, it will be three. When rounding, if it is four or below you keep it, or if it is five or above, you round up to the nearest ten.

974.362 - 6 is above 5, so you will make the three a four.

974.4

We will be able to put out $36598.19. The solution has been obtained by using the concept of present value of annuity.

The present value of an annuity is the current value of its anticipated future payments at a given rate of return, or discount rate. With higher discount rates, the annuity's present value falls.

We are given that $400,000 are saved for retirement. The account earns  6% interest.

Using present value of annuity,

⇒Present value of annuity due = P + P [tex][\frac{1-(1+r)^{-(n-1)} }{r}][/tex]

⇒400,000 = P + P [tex][\frac{1-(1+0.06)^{-(15-1)} }{0.06}][/tex]

⇒400,000 = P [1 + 9.295]

⇒P = 400,000/10.9295

⇒P = $36598.19 (approx.)

Hence, we will be able to put out $36598.19.

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The given expression equivalent to (5−4i)(3−2i)(5−4i)(3−2i) is -231 + 372i.

What is expression ?

In mathematics, an expression is a combination of numbers, variables, and operations that represents a value or a quantity. It can be a simple expression consisting of only one number or variable, or a complex expression consisting of several numbers, variables, and operations.

We can use the distributive property of multiplication to expand the given expression as follows:

(5−4i)(3−2i)(5−4i)(3−2i)

= (5−4i)(5−4i)(3−2i)(3−2i)

= (25 - 40i + 16i²)(9 - 12i + 4i²)

= (25 - 40i - 16)(9 - 12i - 4)

= (-231 + 372i)

Therefore, the given expression equivalent to (5−4i)(3−2i)(5−4i)(3−2i) is -231 + 372i.

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9x^3 + 4x^2 + 5

Explanation:

Let's simplify step-by-step.

6x^2−3−5x^3−(4x^3+2x^2−8)

Distribute the Negative Sign:

=6x^2−3−5x^3+−1(4x^3+2x^2−8)

=6x^2+−3+−5x^3+−1(4x^3)+−1(2x^2)+(−1)(−8)

=6x^2+−3+−5x^3+−4x^3+−2x^2+8

Combine Like Terms:

=6x^2+−3+−5x^3+−4x^3+−2x^2+8

=(−5x^3+−4x^3)+(6x^2+−2x^2)+(−3+8)

=−9x^3+4x^2+5

The requried measures of angles a, b, c, and d are 97°, 15°, 68°, and 68° respectively.

Orientation of the one line with respect to the horizontal or other respective line is known as a measure of orientation and this measure is known as the angle.

Here,
From the figure,
The calculation of the unknown angles is as follows,
112° and ∠d are supplementary angles.

So,
112 + ∠d = 180
∠d = 180 - 112
∠d = 68°

97° and angle a are corresponding angles, so
∠a = 97°.

112 and ∠c are also supplementary angles.
112 + ∠c = 180
∠c = 68°

Now,
∠a + ∠b  = 112
∠a + 97 = 112
∠a = 15°

Thus, the requried measure of angles a, b, c, and d are 97°, 15°, 68° and 68°.

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Answer:

Incorrect

Step-by-step explanation:

In step one, when they multiplied exponents, they added them which is correct

Step two, they divided exponents, which means they should have subtracted. if they subtracted 6/5 and 2/5, it would have been

[tex]( {x}^{ \frac{4}{5} } )^{ \frac{1}{2} } [/tex]

Answer:

Let x be the amount of sales Ryan made in that month.

Ryan's commission on the sales would be 5% of x, which is 0.05x.

Adding the commission to his base salary gives his total income for the month, which is $1400 + 0.05x.

Since his paycheck for the month was $1710, we can write the equation:

$1400 + 0.05x = $1710

To solve for x, we can first subtract $1400 from both sides:

0.05x = $310

Then divide both sides by 0.05:

x = $6200

Therefore, Ryan made $6200 in sales that month.

Answer:

Step-by-step explanation:

1000m = 1km

So 3000m = 3km

As a result, the particle's velocity changes as time passes. It is -4/a³ m/s at time t = a, -4 m/s at time t = 1, -0.5 m/s at time t = 2, and -0.15 m/s at time t = 3.

A mathematical equation, such as 6 x 4 = 12 x 2, states that two numbers or values are equivalent. a meaningful noun. When several or even more components need to be taken into account simultaneously in order to comprehend or describe the entire situation, an equation is used.

The derivatives of the displacing equation with time as a parameter is the particle's velocity.

v = ds/dt = d/dt (2/t²) = -4/t³

As a result, the particle's velocity at times t = a, t = 1, t = 2, and t = 3 is as follows:

v(a) = -4/a³

v(1) = -4/1³ = -4 m/s

v(2) = -4/2³ = -0.5 m/s

v(3) = -4/3³ = -0.15 m/s

The particle's velocity consequently varies over time. It is -4/a³ m/s at time t = a, -4 m/s at time t = 1, -0.5 m/s at time t = 2, and -0.15 m/s at time t = 3. Due to the fact also that velocity is negative for any and all values of t, the particle is travelling in the reverse way (i.e., to the left).

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Use the cookies to teach basic fractions, such as one-half or one-third of a cookie.

What is Activity ?

An activity is a task, exercise, or action that is carried out for a specific purpose or goal. It can be an organized event or a spontaneous action that requires some level of effort or engagement from participants.

Begin by gathering the Grade R learners together and introduce the theme "Sharing Treats with Friends" and the concept of sharing with remainders. Explain to the learners that sometimes when we share treats with our friends, we might not have enough for everyone to have an equal amount.

Place the bag of cookies on the plate and ask the learners to estimate how many cookies are in the bag. Write their guesses on the board or chart paper.

Open the bag of cookies and count how many there are. Record the actual number of cookies on the board or chart paper.

Explain that the learners will be sharing the cookies with their friends, but they must make sure that everyone gets the same number of cookies. Divide the class into small groups of three or four learners.

Instruct each group to count the number of cookies in the bag and divide them equally among the members of the group. If there are any remaining cookies, they should be placed on the plate.

Ask the learners to share their results with the class. Some groups may have exactly the same number of cookies, while others may have remainders. Write their results on the board or chart paper.

Discuss with the learners how they can share the remaining cookies equally among their group members. For example, they could break the remaining cookies into smaller pieces or take turns sharing the last cookie.

Give the learners a chance to practice sharing with remainders by repeating the activity with different amounts of cookies and different group sizes.

As a conclusion, ask the learners to reflect on the activity and discuss how it felt to share with their friends. Encourage them to think about why sharing is important and how it can make everyone feel happy.

Optional extension activities:

Have the learners draw pictures or write stories about sharing treats with their friends.

Therefore, Use the cookies to teach basic fractions, such as one-half or one-third of a cookie.

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