Name 3 different ways of reducing the effect of sound waves.

The work done on the ship by the tugboat is calculated as 15,000,000 joules.

Force can be a push or a pull but always with magnitude and direction.

The work done on the ship is given by the equation as : work = force × distance × cos(Ф)

force is the constant horizontal force applied by tugboat, distance is  distance moved by ship, and theta is angle between force and direction of motion of the ship. In this case, Ф is zero because the force is in same direction as the motion of ship.

Thus, we calculate the work done on the ship as: work = 5000 N × 3000 m × cos(0)

work = 15,000,000 joules

Therefore, the work done on the ship by the tugboat is 15,000,000 joules.

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The second mass will have a velocity of v² = 4√F of the force, F. Since the displacement and the force are the same in both cases

Frictional force is a force that opposes motion between two surfaces in contact. When two surfaces are in contact, there are microscopic irregularities that prevent them from sliding over each other easily. As a result, a force is required to overcome this resistance and move one surface over the other.

The frictional force between two surfaces depends on several factors, including the type of surfaces in contact, the force pressing the surfaces together (normal force), and the presence or absence of lubrication.

According to the work-energy principle, the work done by a force on an object is equal to the change in the object's kinetic energy. This principle can be used to solve the problem.

For the first case, the work done by the force F is:

                           W = Fd

where d is the displacement of the mass. This work is equal to the change in kinetic energy of the mass:

                                W = ΔK

where ΔK = (1/2)mv² - 0 is the change in kinetic energy, since the mass starts from rest.

Combining these equations, we get:

                                 Fd = (1/2)mv²

For the second case, the work done by the force 2F is:

                            W = 2Fd

This work is equal to the change in kinetic energy of the mass:

                                 W = ΔK

where ΔK = (1/2)(1/2)m v₂² - 0 is the change in kinetic energy, since the mass starts from rest.

Combining these equations, we get:

2Fd = (1/4)mv₂²

Solving for v², we get:

v² = √(8Fd/m)

Since the displacement and the force are the same in both cases, we can substitute the first equation into the expression for v²:

                             v² = √(8F(1 m)/(1/2m))

                                   v² = √(16F)

                                      v² = 4√F

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Answer:

speed

Explanation:

speed

The final velocity of block A is -2 m/s to the left ( in the opposite direction of its initial velocity).

Quantity that designates how fast and in what direction a point is moving is known as velocity.

As we know, m_A * v_Ai + m_B * v_Bi = m_A * v_Af + m_B * v_Bf

m_A and m_B are the masses of blocks A and B, v_Ai and v_Bi are their initial velocities, and v_Af and v_Bf are their final velocities.

5 kg * 10 m/s + 10 kg * 0 m/s = 5 kg * v_Af + 10 kg * 6 m/s

50 kgm/s = 5 kg * v_Af + 60 kgm/s

-10 kg*m/s = 5 kg * v_Af

So, v_Af = -2 m/s

Therefore, the final velocity of block A is -2 m/s to the left (i.e., in the opposite direction of its initial velocity).

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Answer:

the answer can be A because based on what I know every increasing stars from 1 to the biggers numbers

In a genetic cross Rr x rr the percentage of offspring will be round will be 50% since this trait is associated with the recessive genotype (rr).

The recessive genotype in a genetic cross is the proportion of offspring that will be homozygous recessive and therefore will express the recessive trait such as in this case round plants that are produced by the combination of recessive and heterozygous parents.

Therefore, with this data, we can see that recessive genotypes in a genetic cross are generated by the combination of two recessive gametes.

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Answer:

The correct answer is: 361 W

Explanation:

The comet will disintegrate at a height of 70,479,900 m.

To find the height at which the comet would disintegrate, we need to determine Earth's Roche limit with respect to the comet.

Roche limit = 2.5 [(density of planet)/(density of moon or other object)]^(1/3) (radius of planet)

Let's assume that the moon has a similar density to the comet, so we can use the Roche limit formula with the following values:

density of planet = 5500 kg/m^3

density of moon or other object = 500 kg/m^3

radius of planet = 6378 km = 6,378,000 m

Roche limit = 2.5 [(5500 kg/m^3)/(500 kg/m^3)]^(1/3) (6,378,000 m)

Roche limit = 76,857,900 m

This means that any object that comes closer to Earth than 76,857,900 m would be torn apart by tidal forces.

Therefore, the comet would disintegrate at a height of 76,857,900 m - 6,378,000 m = 70,479,900 m above Earth's surface.

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The density of the rod is 3.0 kg/m at the origin,then the center of mass of the rod is located 2.15 m from the origin.

The center of mass is the point in an object or system of objects where the mass of the object or system can be considered to be concentrated. In other words, it is the point in which an object or system can be balanced and behaves as if all the mass is concentrated at that point.

To find the center of mass of the rod, we need to integrate the product of the density and position of each infinitesimal element of the rod, divided by the total mass of the rod.

We can express the position of each element as x, where x=0 at the origin and x=4.5 m at the other end of the rod.

Let's start by finding the total mass of the rod. We can divide the rod into two parts: one from the origin to the midpoint, and the other from the midpoint to the other end. The mass of each part can be found by integrating the density over its length:

m₁ = ∫(0 to 2.25) 3x² dx = 15.19 kg

m₂ = ∫(2.25 to 4.5) (22.5x - 45.375) dx

                                = 95.63 kg

The total mass of the rod is then derived as follows:

                 m = m₁ + m₂ = 110.82 kg

We can now evaluate the location of the centre of mass. We can express the position of the center of mass as xcm, where x=0 at the origin and x=4.5 m at the other end of the rod.

We can use the formula:

xcm = (1/m) ∫(0 to 4.5) ρ(x) x dx

where (x) represents the density at position x.

We can express the density as a quadratic function of x:

                          ρ(x) = ax² + bx + c

Using the given values of density at the origin, midpoint, and other end, we can solve for the coefficients a, b, and c:

                               c = 3

                         a + b + c = 11/4.5

                           = 2.44

4a + 2b + c = 3

Solving these equations gives:

a = -1.96 kg/m³

b = 7.33 kg/m²

Now we can plug in the expression for ρ(x) and evaluate the integral:

xcm = (1/m) ∫(0 to 4.5) (-1.96x⁴ + 7.33x³ + 3x) dx

Evaluating this integral gives:

                                       xcm = 2.15 m

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The acceleration on a body that approached the earth and comes within 6 earth radii of the earth’s surface is 0.2 m/s².

The acceleration of the body can be calculated using the equation-

g = g0 R/(R + H)².

In the question, we have, h = 6R

g = 9.8 x R/(R + 6R)²

By putting in the values and calculating, we get,

g = 0.2 m/s².

Where g' = Gravitational Acceleration at Height, R = Earth's Radius, and g = Gravitational Acceleration at Earth's Surface. As a result, at a distance of 2R from the earth's surface, the acceleration of a body caused by the earth's attraction is equal to g/9.

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All of the following describe the region in which an electron is most likely to be found except an isotope. Thus, the correct option is B.

Isotopes can be defined as the distinct nuclear species of the same element. They have the same atomic number and the position in the periodic table as the main atom, however they differ in number of nucleons due to different numbers of neutrons in their nucleus.

Orbital is a volume of space present within an atom where an electron is most likely to be found. The s-orbitals are spherical in shape.

Cloud is the region present near the nucleus where the probability of finding an atom is highest. Cloud are the region of negative charge.

Path can also be defined as orbital. It is the exact route in which the electrons travel in an atom.

Therefore, the correct option is B.

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Answer:

Equal to

Explanation:

work output is equal to the work input, so the efficiency is equal to 1 ( or 100% ) and the mechanical advantage is numerically equal to the velocity ratio. So, M.A. = V.R.

E. Vital Functions of a Team. Developing camaraderie is an important part of creating a team atmosphere, as it helps team members to learn to trust and rely on each other.

Atmosphere is the layer of gases that surrounds the Earth. It is composed of roughly 78% nitrogen, 21% oxygen, and 1% other gases, such as argon, carbon dioxide and water vapor. The atmosphere protects the Earth from harmful ultraviolet radiation from the sun, shelters us from extreme temperatures, and creates the air pressure that allows us to breathe. The air we breathe is a mixture of gases, and the atmosphere also contains dust, smoke and other particles.

Paying attention during training helps to ensure that team members have all the necessary information to be able to perform their duties, while taking part in team activities and training helps to strengthen team bonds and create a sense of unity.

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The final momentum of the artist-clay system immediately after collision is -82 kgm/s.

Assuming that the initial momentum of the clay was 3.0 kgm/s and the initial momentum of the potter was -85 kgm/s, we can use the law of conservation of momentum to find the final momentum of the artist-clay system immediately after the collision:

Initial momentum = Final momentum

(3.0 kgm/s) + (-85 kgm/s) = Final momentum

-82 kg×m/s = Final momentum

Therefore, the final momentum of the artist-clay system immediately after the collision is -82 kgm/s.

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The magnitudes of the vectors (A+1B) and (2A - B) would be 6.71 and 10.25 respectively

a) The vector A + B can be found by adding the corresponding components of A and B:

A + B = (3i - 1j + 4k) + (2i + 3j - 0k) = 5i + 2j + 4k

The magnitude of A + B is:

|A + B| = sqrt((5)^2 + (2)^2 + (4)^2) = sqrt(45) ≈ 6.71

b) The vector 2A - B can be found by multiplying the components of A and B by the appropriate scalar values and then subtracting:

2A - B = 2(3i - 1j + 4k) - (2i + 3j - 0k) = 6i - 2j + 8k - 2i - 3j = 4i - 5j + 8k

The magnitude of 2A - B is:

|2A - B| = sqrt((4)^2 + (-5)^2 + (8)^2) = sqrt(105) ≈ 10.25

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Answer:  NEWTONS FIRST LAW

One's body moves to the side when a car makes a sharp turn.

Tightening of seat belts in a car when it stops quickly.

A ball rolling down a hill will continue to roll unless friction or another force stops it.

If pulled quickly, a tablecloth can be removed from underneath dishes.

                                NEWTONS SECOND LAW

1· Try to move an object.

2· Pushing a car and a truck.

3· Racing Cars.

4· Rocket launch.

5· Kick the ball.

6· Car crash.

7· Two people walking.

8· Object thrown from a height

   Newton's Second Law of Motion says that acceleration (gaining speed) happens when a force acts on a mass (object). Riding your bicycle is a good example of this law of motion at work. Your bicycle is the mass. Your leg muscles pushing on the pedals of your bicycle is the force.

                                     NEWTONS THIRD LAW

                  Examples

The recoil of a Gun. ...

Swimming. ...

Pushing the Wall. ...

Diving off a Raft. ...

Space Shuttle. ...

Throwing a Ball. ...

Walking. ...

Hammering a Nail.

More items...

Common examples of newton's third law of motion are: A horse pulls a cart, a person walks on the ground, a hammer pushes a nail, and magnets attract paper clips. In all these examples a force is exerted on one object and that force is exerted by another object.

Angle of 5.61° should  be banked so that car running at 50 Km/hr be safe to go round the circular turn of 200 m radius.

The process of raising outer edge of the road over its inner edge through certain angle θ is called as banking of road. Banking of road is nothing but the process of making the angle between the surface of road to horizontal surface of the road. The angle made by this two surfaces is called as angle of banking. Banking of road is done for safe turn at high speed.

Angle of banking is given by the formula,

tanθ = v²÷Rg

Where θ = angle of banking

           R = Radius of circular turn

           g = acceleration due to gravity

Given,

velocity of the car v = 50km/hr = 13.88 m/s

Radius of the circular orbit = 200 m

From formula,

tanθ = 13.88² ÷ (200×9.8)

tanθ = 0.09829

θ = tan⁻¹(0.09829)

θ = 5.61°

Hence angle must be backed at 5.61° to have safe turn.

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The object's kinetic energy, in contrast to potential energy, is relative to other fixed and moving things that are present inside its immediate vicinity.For instance, if the item is positioned at a higher height, its kinetic energy will be higher.

As height is reduced, potential energy is reduced as well.If height lowers, the kinetic energy for a freefall similarly reduces.That is as a result of the shorter distance to be traveled.

A doubling in height will lead to a doubling in gravitational potential energy since an object's gravitational potential energy is directly proportionate to its height above the zero point.The potential energy of gravity will triple with a tripling of height.

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The potential energy of the mass is 0.0452 J when it is at a distance of

0.0600 m from equilibrium.

How to calculate potential energy?

The potential energy stored in a spring when it is stretched or compressed by a displacement x is given by:

[tex]$PE = \frac{1}{2}kx^2$[/tex]

where k is the spring constant.

In this problem, the spring constant is given as 26.6 N/m, and the displacement of the mass from equilibrium is

[tex](0.120 m - 0.0600 m) = 0.0600 m.[/tex]

Therefore, the potential energy stored in the spring when the mass is at a distance of 0.0600 m from equilibrium is:

[tex]$PE = \frac{1}{2}kx^2 = \frac{1}{2}(26.6 N/m)(0.0600 m)^2 = 0.0452 J$[/tex]

So the potential energy of the mass is 0.0452 J when it is at a distance of 0.0600 m from equilibrium.

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Answer: 0.0479

Explanation: This answer works for Acellus! :D

hope this helps!

It is not possible for a tree to survive if the inner part of the tree is missing. This is because, the inner part of the tree is vital for survival and health.

Trees are the plants which carry out the life processes that all plants share on the planet. It is not possible for a tree to survive without the inner part. If the entire inner part is missing, including the heartwood and sapwood, is missing. The inner part of a tree is vital to the survival as well as the health, as it is responsible for the transportation of water, nutrients, and sugars between the root and the leaves.

However, it is possible for a tree to survive if only some part of the inner part is missing. Trees have a remarkable ability to compartmentalize the damage and decay, which means that they can wall off or can isolate the injured or infected parts of the tree for the prevention of the spread of damage to the rest of the tree.

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Answer:131s

Explanation:

time = 5.15*10^5 J / 3940

1.18∗10^24 kg is the mass of the planet where a 4950 kg rock weighs 22,030 N with planet having a radius of 4200 km.

Define Newton's law of gravitation.

According to Newton's law of gravitation, every particle of matter in the universe is attracted to every other particle with a force that varies directly as the product of their masses and inversely as their distance from one another.

The universal power of attraction acting on all matter is known as gravity, also known as gravitation. It has no impact on defining the internal characteristics of common matter because it is by far the weakest known force in nature.

The object weighs m = 4950 kg.

The planet's radius is 4200 km, or 4200*1000 meters.

F= 22030 N, the object's weight

That which we are aware of is G the gravitational constant 6.674x10-11.

We must ascertain: planet's mass is given by M =?

F= GMm/r2

22030 = 6.674x10-11[(4950M)/(42001000)2]

⇒ M =1.18∗10^24 kg

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The movement of plates is explained by the theory of plate tectonics, which proposes that the Earth's lithosphere (made up of rigid plates) moves slowly over the underlying, more fluid asthenosphere due to the circulation of heat from the Earth's interior

What is Tectonics Plates?

Tectonic plates are large pieces of the Earth's lithosphere (made up of the crust and uppermost part of the mantle) that move around on the underlying asthenosphere, a more fluid layer of the mantle. The lithospheric plates are rigid and brittle, and they move in response to forces generated by the circulation of heat in the Earth's interior. The movement of the plates causes many geological features such as mountains, volcanoes, earthquakes, and oceanic trenches.

There are several major and minor tectonic plates, including the Pacific Plate, the North American Plate, the African Plate, the Eurasian Plate, and the Antarctic Plate. These plates interact with each other at their boundaries, which can be divergent (moving apart), convergent (moving towards each other), or transform (sliding past each other).

The lithospheric plates move apart at divergent boundaries, collide at convergent boundaries, and slide past each other at transform boundaries. These interactions at the boundaries cause many geological features such as volcanoes, mountain ranges, and earthquakes. The plate tectonics theory has been supported by various lines of evidence, including the study of earthquakes, magnetic anomalies, and the distribution of fossils and rocks around the world.

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Answer:

F = G M1 M2 / R^2      attraction between 2 masses

M1 = F R^2 / (G M2)

M1 = 2.20E4 * (4.2E6)^2 / (6.67E-11 * 4.95E3) kg

M1 = 2.2 * 4.2^2 / (6.67 * 4.95) E24

M1 = 1.18E24 kg

Answer:

Explanation:

Force = mass*acceleration

15=mass*5

mass=3kg

Answer:

3 second is the answer of your question

The rotation per second of the spin of the tube is 1200 rps. The diameter of the tube is 35 cm or 0.35 m. Then, its velocity is 1308 m/s.

Angular velocity is a physical quantity that is the rotational analogue of the linear velocity. The angular velocity of an object is the velocity of rotation that is distance covered by one rotation per second.

Given  number of rotations  = 1200 rotation per second

circumference of the tube  = 2 π r = πd

c = 3.14 × 0.35 m = 1.09 m.

It means that, for one rotation, the tube covers a distance of 1.09 m. In one second it spins 1200 times.

Hence, the total distance travelled in one second = 1200/s × 1.09 m = 1308 m/s.

Therefore, the velocity of the 1 m tube is 1308 m/s.

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