Nadia says figure A id dilated to form figure A' using a scale factor of 2 and point B as the center of dilation. What mistake did Nadia make? What is the correct scale factor?

Answer:

its B

Step-by-step explanation:

I did this in class

Answer:

x = 27°

Step-by-step explanation:

Given the lines are parallel you have a pair of same-side interior angles and these angles = 180°

x + 72 + 3x = 180

4x + 72 = 180

4x = 108

x  = 108/4

x = 27°

The value of x will be 27 degree

Given the lines are parallel you have a pair of same-side interior angles and these angles = 180°

x + 72 + 3x = 180

4x + 72 = 180

4x = 108

x  = 108/4

x = 27°

The value of x will be 27 degree

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Answer:

8 nine tenths

Step-by-step explanation:

Answer:

y=x-5

Step-by-step explanation:

Answer:

2+y over 5

Step-by-step explanation:

5x + y =2

5x=2+y

x=2+y over t

The Drink cost $1.75 each, and candy bars cost $0.75 each.

let

The price of a drink = x

The price of a candy bar  = y

Bart total purchase

Claudia total purchase

The cost of each can be calculated by combining the equations. Therefore,

2x + 2y  = 5

x + 4y = 4.75

x = 4.75 - 4y

2(4.75 - 4y) + 2y = 5

9.5 - 8y + 2y = 5

9.5 - 6y = 5

-6y = -4.5

y = -4.5/-6

y = 0.75

2(0.75) + 2x  = 5

1.5 + 2x = 5

2x = 5 - 1.5

2x = 3.5

x = 3.5/2

x = 1.75

Cost of a drink = $1.75

Cost of a candy bars = $0.75

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Answer:

2 (-3 - 1) = 6 (-1)?? If thats the equation you were trying to type then the answer is: -8 = -6

Step-by-step explanation:

Answer:

75.72

Step-by-step explanation:

Answer:

(x-2)(x-2) or (x-2)^2

Step-by-step explanation:

Hope this helps!

Hello logan693616!

[tex] \huge \boxed{\mathbb{QUESTION} \downarrow}[/tex]

A positive plus a negative will (always, sometimes, never) be negative.

Give an example that proves your answer:

[tex] \large \boxed{\mathbb{ANSWER\: WITH\: EXPLANATION} \downarrow}[/tex]

A positive plus a negative will sometimes be negative.

__________________

Hope it'll help you!

ℓu¢αzz ッ

Answer:

B

hope this helps

Answer:

the slope is 2 and a=8 b=6

Step-by-step explanation:

Answer:

its 0

Step-by-step explanation:

yea i made that up I NEED POINTS ALR

60 + (3x - 13) = (5x + 1)

60 + 3x - 13 = 5x + 1

3x - 5x = 1 - 60 + 13

-2x = -46

-2x / -2 = -46 / -2

x = 23

Answer: x = 23

The length of the bacteria should be written in scientific notation.

0.00365 in scientific notation = 3 × 10^-3

Given.

length of the bacteria in decimal = 0.00365 cm long

Scientific notation is written in the format x × 10ⁿ

where,

x = any number between digit 1 and 10

n = exponent (positive or negative).

In this case, the nearest significant value is 3

So move the decimal point three times to where 3 is

That is,

0.00365 = 3.65

Since the decimal point is moved to the right 3 times, n = - 3

we have 10^-3

Therefore,

0.00365 in scientific notation = 3 × 10^-3

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Answer:

p = 10.9

Step-by-step explanation:

Answer:

In Celsius the degree is 50°

Step-by-step explanation:

Put the 122° into the equation given.

Answer:

57.6......

Step-by-step explanation:

v=lxbxh...........

9514 1404 393

Answer:

  567

Step-by-step explanation:

The multiplier each year is 1 -5% = 0.95. Applying that multiplier 9 times gives ...

  900(0.95^9) ≈ 567

About 567 voters are expected to vote 9 years from now.

[tex] \Large{\boxed{\sf (10 + 6i)(-2 - 4i) = 4 - 52i}} [/tex]

[tex] \\ [/tex]

To find the algebraic form, also called 'a + bi form', of the given complex number, we will have to expand its expression using FOIL method.

[tex] \\ [/tex]

[tex] \Large{ \sf \: \underline{FOIL \: method \text{:}}} \\ \\ \Large{\boxed{\sf (A + B)(C + D) = AC + AD + BC + BD}} [/tex]

[tex] \\ [/tex]

Let's identify our coefficients and expand the given expression:

[tex] \sf (\underbrace{\sf 10}_{A} + \overbrace{\sf 6i}^{B})(\underbrace{\sf -2}_{C} \overbrace{\sf -4i}^{D}) = 10 \times (-2) + 10 \times (-4i) + 6i \times (-2) + 6i \times (-4i) \\ \\ \\ \sf = -20 - 40i - 12i - 24i^2 = -20 - 52i - 24i^2 [/tex]

[tex] \\ [/tex]

In the complex number system, i² = -1. Therefore, our final answer is:

[tex] \sf (10 + 6i)(- 2 - 4i) = -20 - 52i - 24(-1)= \boxed{\boxed{\sf 4 - 52i}} [/tex]

[tex] \\ \\ [/tex]

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Answer:

8 divided by 9/10

= 8.8888... = 8 8/9

7 divided by 5/8

= 11.2 = 11 1/5

8 divided by 1/2

= 16

9 divided by 2/3

= 13.5 = 13 1/2

8 divided by 5/8

= 12.8 = 12 4/5

8 divided by 1/4

= 32

1 divided by 5/10

= 2

8 divided by 1/3​

= 24

Step-by-step explanation:

Answer:

try a or b hope this helps

Answer:

top right

Step-by-step explanation:

Answer:

Step-by-step explanation:

[tex] \large\underline{\sf{Solution-}}[/tex]

Given that,

[tex]\rm \longmapsto\: {(x + iy)}^{3} = y + iv[/tex]

[tex]\rm \longmapsto\: {x}^{3} + 3 {x}^{2}(iy) + 3x {(iy)}^{2} + {(iy)}^{3} = y + iv[/tex]

[tex]\rm \longmapsto\: {x}^{3} + 3 {x}^{2}yi + 3x {i}^{2} {y}^{2} + {i}^{3} {y}^{3} = y + iv[/tex]

We know,

[tex] \purple{\rm \longmapsto\:\boxed{\tt{ {i}^{2} = - 1 \: \: \: and \: \: \: {i}^{3} = - i }}} \\ [/tex]

So, using this, we get

[tex]\rm :\longmapsto\: {x}^{3} + 3 {x}^{2}yi - 3x{y}^{2} - i{y}^{3} = y + iv[/tex]

[tex]\rm \longmapsto\: ({x}^{3} - 3x {y}^{2}) + i(3{x}^{2}y- {y}^{3})= y + iv[/tex]

On comparing real and Imaginary parts, we get

[tex]\rm \longmapsto\:y = {x}^{3} - 3 {xy}^{2} [/tex]

and

[tex]\rm \longmapsto\:v = {3x}^{2}y - {y}^{3} [/tex]

Now, Consider

[tex]\rm \longmapsto\:\dfrac{y}{x} + \dfrac{v}{y} [/tex]

[tex]\rm \:  =  \: \dfrac{ {x}^{3} - {3xy}^{2}}{x} + \dfrac{ {3yx}^{2} - {y}^{3} }{y} [/tex]

[tex]\rm \:  =  \: \dfrac{ x({x}^{2} - {3y}^{2})}{x} + \dfrac{y({3x}^{2} - {y}^{2})}{y} [/tex]

[tex]\rm \:  =  \: {x}^{2} - {3y}^{2} + {3x}^{2} - {y}^{2} [/tex]

[tex]\rm \:  =  \: 4{x}^{2} - {4y}^{2}[/tex]

[tex]\rm \:  =  \: 4({x}^{2} - {y}^{2})[/tex]

Hence, Proved

Answer:

x=13

Step-by-step explanation:

See attached image. If you have any questions, let me know!

Answer:

y = -1/2c - 8

Step-by-step explanation:

2c - y = 6

2c -6 = y

Slope: 2. Slope of the perpendicular line: -1/2

Point (-4,-6)

y-intercept = -6 - (-1/2)(-4)

b = -6 -2 = -8

The equation of the line that passes through the point [tex](-4,-6)[/tex]  and is

perpendicular to the line [tex]2c - y = 6[/tex] is [tex]2x_{2} -y_{2} +2=0[/tex].

Equation of the line: The general equation of a straight line is [tex]y = mx + c[/tex]. This variable [tex]'c'[/tex] is called the intercept on the [tex]y-axis[/tex].  And [tex]y = c[/tex] is the value where the line cuts the [tex]y-axis[/tex].

Here,

[tex]m=[/tex] the gradient,

[tex]c=[/tex]  the intercept on the y-axis

We have,

An equation of the line that passes through the point [tex](-4,-6)[/tex]  and is

perpendicular to the line [tex]2c - y = 6[/tex] .

So,

Line [tex]2c - y = 6[/tex]  

[tex]2c - y = 6[/tex]

⇒ [tex]y=2c-6[/tex]

and  [tex]y = mx + c[/tex]

On comparing above two equations

[tex]m=2[/tex]

and Slope [tex]=-\frac{1}{m}[/tex]

So, Slope [tex]=-\frac{1}{2}[/tex]

Now,

Slope of the equation [tex](m)=\frac{y_{2} -y_{1} }{x_{2} -x_{1} }[/tex]

Slope of required equation [tex]=\frac{-1}{Slope \ of \ 2c-y=6}[/tex]

                                              [tex]=\frac{-1}{\frac{(-1)}{2} }=2[/tex]

Now,

Equation of line with slope [tex]2[/tex] and passing through point [tex](-4,-6)[/tex] ,

Slope of the equation [tex](m)=\frac{y_{2} -y_{1} }{x_{2} -x_{1} }[/tex]

[tex]2=\frac{y_{2} -(-6) }{x_{2} -(-4) }[/tex]

[tex]2x_{2} +8=y_{2} +6[/tex]

[tex]2x_{2} -y_{2} +2=0[/tex]

So, the equation of the line is  [tex]2x_{2} -y_{2} +2=0[/tex] .

Hence, we can say that the equation of the line that passes through the point [tex](-4,-6)[/tex]  and is perpendicular to the line [tex]2c - y = 6[/tex] is [tex]2x_{2} -y_{2} +2=0[/tex].

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Answer:

Step-by-step explanation:

Answer:

-63 that should help

Step-by-step explanation:

Answer:

at y = 7

Step-by-step explanation:

When the line cross at the y-axis, x = 0

y = 2*0 + 7

y = 0 +7

y = 7