Mr.E.Terry, an engineer, runs a small business. The accounts for the firm are:

* Bank Automobile HST Payable Miscellaneous Expense
* A/R—Various Equipment E. Terry, Capital Rent Expense
* Office Supplies A/P—Various E. Terry, Drawings Telephone Expense
* Office Furniture HST Recoverable Fees Earned

* Journalize the following transactions, using the general journal page below. Calculate and add the HST on any transactions that need it. The rate for HST is 13%. Do not provide explanations.

Jul. 3 Cheque Copy

No. 105, Chambers Bros., payment for monthly rent $450 plus HST of $58.50,
total $508.50.
5 Purchase Invoice
From Glen Printing, $86.50 for office supplies plus HST
8 Sales Invoice
No. 50 to J. Greenley, $250 for services performed, plus taxes.
10 Cash Receipt
From R. Grieve, $200 payment on account.
18 Cash Sales Slip
No. 100 to E. Webb, $85.50 plus taxes.
20 Cheque Copy
No. 106 to E. Terry, $490 for personal use.
24 Bank Debit Memo
Bank deducted $25.00 for a bank service charge.
29 Cheque Copy
No. 107 to Star Blueprinting, $500 on account.
29 Cheque Copy

No. 108 to Municipal Telephone for payment of telephone bill, $200 plus HST of
$26, total $226.
31 Cheque Copy
The balances in the HST accounts for the previous period were: HST Recoverable
$890 and HST Payable $1410. Cheque 109 was written to the Receiver General
for $520 to clear the accounts for that period.

Journalizing these transactions.

Answers

Answer 1

Journalizing the transactions in the accounts of Mr. E. Terry's firm are as follows:

Debit Rent Expense $450

Debit HST Recoverable $58.50

Credit Cash $508.50

Debit Supplies $76.55

Debit HST Recoverable $9.95

Credit Accounts Payable (Glen Printing) $86.50

Debit Accounts Receivable (J. Greenley) $250

Credit Service Revenue $221.24

Credit HST Payable $28.76

Debit Cash $200

Credit Accounts Receivable (R. Grieve) $200

Debit Cash $85.50

Credit Service Revenue $76.66

Credit HST $9.84

Debit Drawings, Terry $490

Credit Cash $490

Debit Bank Charges $25

Credit Cash $25

Debit Accounts Payable (Star Blueprinting) $500

Credit Cash $500

Debit Utilities Expense $200

Debit HST Recoverable $26

Credit Cash $226

Debit HST Payable $1,410

Credit HST Recoverable $890

Credit Cash $520

Data Analysis:

a. Rent Expense $450 HST Recoverable $58.50 Cash $508.50

b. Supplies $76.55 HST Recoverable $9.95 Accounts Payable (Glen Printing) $86.50

c. Accounts Receivable (J. Greenley) $250 Service Revenue $221.24 HST Payable $28.76

d. Cash $200 Accounts Receivable (R. Grieve) $200

e. Cash $85.50 Service Revenue $76.66 HST $9.84

f. Drawings, Terry $490 Cash $490

g. Bank Charges $25 Cash $25

h. Accounts Payable (Star Blueprinting) $500 Cash $500

i. Utilities Expense $200 HST Recoverable $26 Cash $226

j. HST Payable $1,410 HST Recoverable $890 Cash $520

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newton's second law of motion States that the acceleration of an object is directly proportional to the force exerted on the object. if an object accelerates at a rate of 3 m/s2 , it will exert a force of 15 N. how much force will the same object exert if it accelerates at a rate of 7 m/s2?

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Answer:

Step-by-step explanation:

F=(2kg)×(3ms2). ∴F=6kgms2=6 Newton. =6N. Therefore, Force required to accelerate the body is 6N

The force the same object will exert if it accelerates at a rate of 7 m/s² is 35 N

From the question,

We have that,

Newton's second law of motion states that the acceleration of an object is directly proportional to the force exerted on the object

Let a represent the acceleration and F represent the force exerted

Them we can write that

F ∝ a

Introducing a constant, m, which is the mass of the object

Then, we get

F = ma

From the question,

If an object accelerates at a rate of 3 m/s² , it will exert a force of 15 N

We will the determine the mass, m, of the object using the above formula

F = ma

We have that

a = 3 m/s²

F = 15 N

Using

F = ma

Then,

15 = m × 3

m = 15÷3

∴ m = 5kg

Now, we can determine the force the same object would exert if it accelerates at at rate of 7 m/s²

Using the same formula

F = ma

a = 7 m/s²

m = 5 kg

∴ F = 5 × 7

F = 35 N

Hence, the force the same object will exert if it accelerates at a rate of 7 m/s² is 35 N

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Can someone please show a piece of paper or ex’s plum how you do h point?

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Answer:

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Step-by-step explanation:

well a square has four sides and they are all equal so it would have to be (-1,-1) for the sides to be equal

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Answer:

12

Step-by-step explanation:

0.5 = 1/2

6 ÷ 0.5 = 12

or

6 : 1/2 =

6 × 2 = 12

Which number line correctly shows the graphing of point A,2 1/2 point b -2.75 and point c -0.25

Answers

Answer:

C

Step-by-step explanation:

There are two negative numbers must be before zero and one positive number must be after zero

A = 2 1/2 = 2.5 between 2 and 3

B = -2.75 between -2.5 and -3

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Simplify 5b4×4b3 what is the answer for it ​

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Answer:

[tex]{ \rm{ {5b}^{4} \times {4b}^{3} }}[/tex]

• from laws of indices:

[tex] \hookrightarrow \: { \boxed{ \rm{ {rx}^{n} + {px}^{m} = (r \times p) {x}^{(n + m)} }}} \\ [/tex]

• substitute:

[tex]{ \rm{ {5b}^{4} \times {4b}^{3} = (5 \times 4) {b}^{(4 + 3)} }} \\ \\ = { \boxed{ \boxed{ \rm{ \: 20 {b}^{7} \: \: }}}}[/tex]

How many minutes is it before 12 noon if 68 minutes ago it was three times as many minutes past 10 a.m.?​

Answers

if 68 minutes ago it (then) was three times as many minutes past 10 am (now)

x + 68 = 3 ×
×
(120 - x) →

x = 73 min
… if 68 minutes ago it (now) was three times as many minutes past 10 am (then)

x = 3 ×
×
[120 - (x + 68)] →

x = 39 min
… if 68 minutes ago it (then) was three times as many minutes past 10 am (then)

x + 68 = 3 ×
×
[120 - (x + 68)] →

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Answer:4

Step-by-step explanation:


<1 and <2 are complementary. Solve for the measure of <1.

<1 = 12x + 4
<2 = 9x + 2

A. 52
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Answer:

A) 52

Step-by-step explanation:

If < 1 and < 2 are complementary angles, then it means that the sum of their measures add up to 90°.

< 1 + < 2 = 90°

12x + 4 + 9x + 2 = 90°

21x + 6 = 90°

21x + 6 - 6 = 90° - 6

21x = 84°

21x/21 = 84°/21

x = 4

Substitute the value of x = 4 into < 1 and < 2:

m < 1: 12x + 4 = 12(4) + 4 = 52°

m < 2: 9x + 2 = 9(4) + 2 = 38°

Therefore, the correct answer is A) m < 1 = 52°.

as part of a campaign to promote it's annual clearance sale


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Answer:

is this a question or not?

Step-by-step explanation:

Use the IQR to determine if any of the data in the data set are outliers.

{23,80,43,23,0,20,23,23,20,28}

Answers

Using the IQR, the only outlier in the data set is: 0.

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IQR = upper quartile (Q3) - lower quartile (Q1).

Given the data set, 23,80,43,23,0,20,23,23,20,28:

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And data values that are above:

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Gabe's bill at Colton's was $25. If he decided to leave his server a 20% tip, how muc
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$31.25

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The first choice

Step-by-step explanation:

h=-3

hope it helps

Solution:

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Option d. 3

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The following can be deduced from the expressions

m ∠ D = 4 × m ∠ A
m ∠ B = 3 × m ∠ A-12

Please note that the sum of angles in a triangle is 180 degress. Therefore,

M∠ A + m ∠ B + m ∠ D = 180equation(3)

Substitute for equation 1 and 2 in equation 3 as shown below

m ∠ A + 3 × m ∠ A - 12^0 + 4 x m ∠ A =180^0
m ∠ A + 3 × m ∠ A + 4 x m ∠ A = 180^0+12^0
8m ∠ A = 192^0
m ∠ A= 192^0/8
m ∠ A=24^0

Substitute for m∠A= 24 in equation 1 and 2 as shown below

m ∠ D = 4 × m ∠ A
m ∠ D = 4 × 24^0
m ∠ D = 96^0
m ∠ B = 3 × mA - 12^0
m ∠ B = 3 × 24^0 - 12
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∠= °

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C. HI my other account:P

Step-by-step explanation:

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Answer:

5 bracelets

Step-by-step explanation:

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5 Bracelets

Step-by-step explanation:

the common factor of the numbers 10 25 and 30 is 5

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8

Step-by-step explanation:

Let,

x1 = 0

x2 = 1

y1 = 18

y2 = 26

Formula : -

Slope = ( y2 - y1 ) / ( x2 - x1 )

Slope = ( 26 - 18 ) / ( 1 - 0 )

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Step-by-step explanation:

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Step-by-step explanation:

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is 3 points behind zero, this make more distance from 75 so…

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[tex] - 3 log_{3}(x - 2) = - 25 \\ = > log_{3}(x - 2) = \frac{ - 25}{ - 3} \\ = > log_{3}(x - 2) = \frac{25}{3} \\ = > (x - 2) = ( \frac{25}{3} ) ^{3} \\ = > x - 2 = \frac{15625}{27} \\ = > x = \frac{15625}{27} + 2 \\ = > x = \frac{15625 + 54}{27} \\ = > x = \frac{15679}{27} \\ = > x = 5226.33[/tex]

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5226.33 (approximate value)

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