Mercury tends to build up in fish
tissues, and is present in larger
quantities in large predatory fish
than in small, herbivorous fish.
This phenomenon is known as
A. corrosivity
B. non-persistence
C. bioremediation
D. biomagnification

Answers

Answer 1

Answer:

D biomag

Explanation:

Answer 2

Mercury tends to build up in fish tissues and is present in larger quantities in large predatory fish than in small, herbivorous fish. This phenomenon is known as biomagnification. The correct option is D.

What is Biomagnification?

Biomagnification is the process by which certain substances, such as heavy metals like mercury, become increasingly concentrated in the tissues of organisms as they move up the food chain. In other words, the higher up an organism is in the food chain, the more likely it is to accumulate higher levels of these substances. This is because predators consume many smaller prey, each of which may have accumulated small amounts of the substance, leading to a build-up of the substance in the predator's tissues over time. This phenomenon has been well-documented in aquatic ecosystems, where mercury and other pollutants can accumulate in large predatory fish.

The other options are not correct:

Option A. Corrosivity refers to the ability of a substance to corrode or eat away at other materials. It is not relevant to the accumulation of mercury in fish tissues.

Option B. Non-persistence refers to the short-term or temporary nature of a substance or effect. It does not describe the long-term accumulation of mercury in fish tissues.

Option C. Bioremediation refers to the use of living organisms, such as bacteria or plants, to help clean up polluted environments. While this process may be used to reduce the levels of mercury in contaminated areas, it does not explain the process of biomagnification in fish.

Therefore, The correct option is D. biomagnification.

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Related Questions

A 3.0-kg block moves up a 40° incline with constant speed under the action of a 26-N force acting up and parallel to the incline. What magnitude force must act up and parallel to the incline for the block to move down the incline at constant velocity?

Answers

Explanation:

Sooooo, first,

Constant Speed means that the body isn't accelerating.

a= 0

Let the force that causes it to move up the incline be P and Q be the force that causes the body to move down the incline. Let Fr be the frictional force.

The force that pulls the body downwards is given by,

F = mgsin40°

F= 18.898N

P -(F+Fr) = ma, but, a= 0

P = F + Fr

Fr = 26-18.898

= 7.102N

If the block must move down the incline, Q and Fr will act in the same direction.

Q + Fr = F

Q = 11.796N

Identify a scenario from
gym class that has an action-reaction force. Describe the situation

Answers

Answer:

A person is doing push-ups against a wall (action force), and the wall exerts an equal and opposite force against the person (reaction force).

Explanation:

An 80.0 kg merry-go-round of radius 1.20 m is accelerating horizontally from rest by a constant force of 70.0 N applied tangentially to the merry-go-round. Find the kinetic energy of the merry-go-round after 5.00 s. (Assume it is a solid cylinder.)

Answers

The kinetic energy of the merry-go-round after 5.00 s, when a constant force is applied tangentially to it, is determined as 3,069.5 J.

Conservation of angular momentum

The kinetic energy of the merry-go-round is determined by applying the principle of conservation of angular momentum as follows;

Iα = rF

where;

I is moment of inertia of the merry-go-round (solid cylinder)

I = ¹/₂mr²

I = ¹/₂ x 80 x (1.2)²

I = 57.6 kgm²

α = (rF)/I

α = ( 1.2 x 70) / (57.6)

α = 1.46 rad/s²

Tangential acceleration of the merry-go-round

a = αR

a = 1.46 x 1.2

a = 1.752 m/s²

Velocity of the merry-go-round

The velocity of the merry-go-round after 5 s is calculated as follows;

v = u + at

v = 0 + (1.752x 5)

v = 8.76 m/s

Kinetic energy of the merry-go-round

K.E = ¹/₂mv²

K.E = ¹/₂ x 80 x 8.76²

K.E = 3,069.5 J

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if every Galaxy have black hole in center than is that mean there used to humongous star that collapsed that formed galaxy and supermassive black hole?​

Answers

Answer:

Yes, It does mean that there was a Red Giant in the middle of the galaxy.

Explanation:

The star at the middle of the galaxy will forever stay at the middle from the gravity it has on itself and it implodes and turns into a black hole with a mass equal to at least 10 suns

Why is cellular reproduction important for homeostasis?
It helps cells make oxygen.
It helps cells make glucose.
It removes waste from cells.
It splits a cell into new cell

Answers

It helps cells make glucose

I got it right in odyssey ware

Answer:

(It was a remove waste from cells)

Explanation:

the cell produces carbon dioxide and water, which are released as waste.

Calculate the solar angle for the day at 10am and 2pm individually for the location of 21.23 south latitude on the 18th march 1993 (Assume it is non leap year)

Answers

Based on the latitude and time of the place, the solar angle for the day at 10am and 2pm is 51.6° and 73.0°.

What is the solar hour angle?

The solar hour angle of a point on the earth’s surface is the angle through which the earth would turn to bring the meridian of the point directly under the sun.

The rotation of the earth on its axis is 15° per hour where before noon is negative and after noon is positive. For example, at 10:00 a.m. local apparent time the hour angle is −30°.

Therefore, based on the latitude and time, the solar angle for the day at 10am and 2pm is 51.6° and 73.0°.

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Oxygen is needed by all cells of most organisms for the release of
energy from what in photosynthesis?

Answers

Answer:

From the SUN

Explanation:

Hope it helps!!!

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A car starts moving from rest; If it gains avelocity of 72km/ht after to seconds what is the acceleration of the car.​

Answers

Answer:

10 m/s²

Explanation:

Given

u = 0 (initial velocity as it is at rest)v = 72 km/h x 5/18 = 20 m/st = 2s

Solving

v = u + at20 = 0 + 2a2a = 20a = 10 m/s²

The correct answer is 10 m/s² .

Multiple choices. 1)when two groups are playing tug of war the forces of the two groups are:- A)same direction B)opposite direction C)different direction but not possible D)A and B

Answers

Answer:

Explanation:

Multiple choices. 1)when two groups are playing tug of war the forces of the two groups are:- A)same direction B)opposite direction C)different direction but not possible D)A and B

please solve the given question

I know the answer but I need explanation also

PLEASE help ​

Answers

R² = F1² + F2² + 2 F1.F2 cos α ⇒cosinus

F1 and F2 perpendicular, α = 90°, cos 90° = 0

[tex]\tt R=\sqrt{3^3+4^2}=5[/tex]

brainly an andean condor with a wingspan and a mass soars along a horizontal path. model its wings as a rectangle with a width. determine the difference between the pressure at the top surfaces of the condor's wings and the pressure at the bottom surfaces brainly

Answers

The difference between the pressure at the top surfaces of the condor's wings and the pressure at the bottom surfaces is 101,204 Pa.

Difference in pressure between the top and bottom of the wingspan

The difference in pressure between the top and bottom of the wingspan is calculated as follows;

ΔP = P(top) - P(bottom)

Area of the wingspan

A = bh

A = 2.7 m x 0.27 m

A = 0.729 m²

Weight of the Andean condor

W = mg

W = 9 x 9.8

W = 88.2 N

Pressure at the top surface of condor's wings

The pressure at the top surface of condor's wings is due to atmospheric pressure

P(top) = 14.7 Psi = 101,325 Pa

Pressure at the bottom surface of condor's wings

The pressure at the bottom surface is due to weight of andean condor.

P = W/A

P(bottom) = 88.2/0.729

P(bottom) = 120.99 Pa

The difference between the pressure at the top surfaces of the condor's wings and the pressure at the bottom surfaces is calculated as;

ΔP = P(top) - P(bottom)

ΔP = 101,325 Pa - 120.99 Pa

ΔP = 101,204 Pa

The complete question is below;

An Andean condor with a wingspan of 270 cm and a mass of 9.00 kg soars along a horizontal path. Model its wings as a rectangle with a width of 27.0 cm.

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Which definition refers to electrical power?
A. The rate at which an electric charge flows past a point in a circuit
B. The energy of an electric charge minus the resistance in a circuit
C. The energy of an electric charge due to its position in an electric
field
D. The rate at which electrical energy is transferred in a circuit

Answers

pretty sure it’s B



sorry if i’m wrong it’s just a guess

in the diagram, q1,q2, and q3 are in a straight line. each of these particles has a charge of -2.35x10^-6 C. particles q1 and q2 are separated by 0.100 m and particles q2 and q3 are separated by 0.100 m. what is the net force on particle q3?

Answers

The magnitude of the net force that is acting on particle q₃ is equal to 6.2 Newton.

Given the following data:

Charge = [tex]-2.35 \times 10^{-6}[/tex] C.

Distance = 0.100 m.

Scientific data:

Coulomb's constant = [tex]8.988\times 10^9 \;Nm^2/C^2[/tex]

How to calculate the net force.

In this scenario, the magnitude of the net force that is acting on particle q₃ is given by:

F₃ = F₁₃ + F₂₃

Mathematically, the electrostatic force between two (2) charges is given by this formula:

[tex]F = k\frac{q_1q_2}{r^2}[/tex]

Where:

q represent the charge.r is the distance between two charges.k is Coulomb's constant.

Note: d₁₃ = 2d₂₃ = 2(0.100) = 0.200 meter.

For electrostatic force (F₁₃);

[tex]F_{13} = 8.988\times 10^9 \times \frac{(-2.35 \times 10^{-6} \times [-2.35 \times 10^{-6}])}{0.200^2}\\\\F_{13} = \frac{0.0496}{0.04}[/tex]

F₁ = 1.24 Newton.

For electrostatic force (F₂₃);

[tex]F_{13} = 8.988\times 10^9 \times \frac{(-2.35 \times 10^{-6} \times [-2.35 \times 10^{-6}])}{0.100^2}\\\\F_{13} = \frac{0.0496}{0.01}[/tex]

F₂ = 4.96 Newton.

Therefore, the magnitude of the net force that is acting on particle q₃ is given by:

F₃ = 1.24 + 4.96

F = 6.2 Newton.

Read more on charges here: brainly.com/question/14372859

Answer:

6.2

Explanation:

acellus

the base is a polygon and its faces are triangles (cone, cube, cylinder, pyramid, rectangular prism​

Answers

Pyramid. A pyramid can have any polygon as its base, but the faces have to be triangles

T F
Organisms get energy from food

Answers

Answer:

It's true that organisms get energy from food.

Answer:

Explanation:

Organisms ingest large molecules, like carbohydrates, proteins, and fats, and convert them into smaller molecules like carbon dioxide and water. This process is called cellular respiration, a form of catabolism, and makes energy available for the cell to use

PLSSSS HELPPPP ASAPPP

A fluorescent light bulb produces just as much light in the same electrical circuit as an incandescent bulb , but requires much less energy to produce it. Which of the following is the most logical explanation for this?

A. The incandescent bulb produces more forms of energy than just light, like heat.
B. The fluorescent light bulb produces more light than any other bulb.
C. The incandescent bulb has to be connected to another circuit.
D. The fluorescent light bulb generates more current than any other type.

Answers

Answer:

The most logical explanation is A.

Explanation:

because we are explaining why the incandescent bulb uses less energy we can eliminate answers B and D then, because we are talking about energy efficiency which has nothing to do with connecting to another circuit we can go with, A because Ultraviolet light generated by fluorescent light bulbs is nothing compared to the heat of an incandescent light bulb because it was engineered to be so.

What is the average velocity if the initial velocity of an object is 10 and the a final velocity is 28

Answers

Answer:

19

Explanation:

Avg. Vel = (28 + 10)/2

= 19

BTW, don't forget your units!

A 2.8 F capacitor and a 3,440
Ω
resistor are connected to a battery of voltage 5 V as shown in the circuit. After
closing the switch, how long will it take for the capacitor voltage to be 45 % of
the battery voltage?
Express your answer in seconds (s)

Answers

The time taken for the capacitor voltage to be 45 % of the battery voltage is 5,750.3 s.

Discharge of the capacitor voltage

The rate at which the capacitor voltage discharges is given by the following formula;

[tex]V = V_0(1 - e^{-t/RC})[/tex]

Where;

V₀ is the initial voltageV is the final voltaget is the time of dischargeR is resistanceC is capacitance

The final voltage = 0.45 x 5 V = 2.25 V

[tex]2.25 = 5(1 - e^{-t/RC})\\\\(1 - e^{-t/RC}) = \frac{2.25}{5} \\\\(1 - e^{-t/RC}) = 0.45\\\\e^{-t/RC} = 1- 0.45\\\\e^{-t/RC} = 0.55\\\\\frac{-t}{RC} = ln(0.55)\\\\\frac{-t}{RC} = -0.597\\\\t = 0.597 (RC)\\\\t = 0.597(3440 \times 2.8)\\\\t = 5,750.3 \ s[/tex]

Thus, the time taken for the capacitor voltage to be 45 % of the battery voltage is 5,750.3 s.

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A rugby player sits on a scrum machine that weighs 200 Newtons. Given that the coefficient of static friction is 0.67, the coefficient of kinetic friction is 0.56 and the force required to push both the scrum machine and the player into motion is 850 Newtons, calculate the following: a)      The mass of the player ( 4marks) b)      The magnitude of the force required to keep both the scrum machine and the player in motion?​

Answers

a. 850 N is the minimum force needed to get the machine/player system moving, which means this is the maximum magnitude of static friction between the system and the surface they stand on.

By Newton's second law, at the moment right before the system starts to move,

• net horizontal force

∑ F[h] = F[push] - F[s. friction] = 0

• net vertical force

∑ F[v] = F[normal] - F[weight] = 0

and we have

F[s. friction] = µ[s] F[normal]

It follows that

F[weight] = F[normal] = (850 N) / (0.67) = 1268.66 N

where F[weight] is the combined weight of the player and machine. We're given the machine's weight is 200 N, so the player weighs 1068.66 N and hence has a mass of

(1068.66 N) / g ≈ 110 kg

b. To keep the system moving at a constant speed, the second-law equations from part (a) change only slightly to

∑ F[h] = F[push] - F[k. friction] = 0

∑ F[v] = F[normal] - F[weight] = 0

so that

F[k. friction] = µ[k] F[normal] = 0.56 (1268.66 N) = 710.45 N

and so the minimum force needed to keep the system moving is

F[push] = 710.45 N ≈ 710 N

When a potential difference of 2 volt is applied across the ends of a wire of 5 metre length a current of 1 ampere flows through it,calculate :-
(i) the resistance per unit length of the wire
(ii) the resistance of 2 metre length of the wire
(iii) the resistance across the ends of the wire if it is doubled on itself

Answers

[tex]\huge\underline{\red{A}\green{n}\blue{s}\purple{w}\pink{e}\orange{r} ⟿}[/tex]

(i) 0.4 Ω m^-1

(ii) 0.8 Ω

(iii) 0.5 Ω

Explanation:

(i) Given, V = 2 volt, I = 1 A

Resistance of 5 m length of wire :-

[tex] = > R = \frac{V}{I} = \frac{2}{1} = 2 \: Ω [/tex]

Resistance per unit length of the wire :-

[tex] = > \frac{R}{l} = \frac{2}{5} = 0.4 \: Ω \: {m}^{ - 1} [/tex]

(ii) Resistance of 2m length of the wire~

[tex] = \: 0.4 \: Ω \: {m}^{ - 1} \times 2 \: m = 0.8 \: Ω [/tex]

(iii) When the wire is doubled on itself, its area of cross section becomes twice and the length becomes half. Let a be the initial cross section and ρ be the specific resistance of the material of wire. Then,

[tex]from \ relation \: \: ➪ \: R = ρ \times \frac{1}{a}. \\ \\ we \: have, \\ \\ initial \: resistance \:➪ \: 2 = ρ\times \frac{5}{a}....eqn(i) \\ \\ new \: resistance \: ➪ \: R` = ρ\times \frac{2.5}{2a}....eqn(ii) \\ \\ on \: dividing \: eqn(ii) \: by \: eqn(i)... \\ \\ \frac{R`}{2} = \frac{2.5ρ}{2a} \div \frac{5ρ}{a} = \frac{1}{4} \\ \\ R` = \frac{2}{4} = 0.5 \: Ω[/tex]

Thus, on doubling the wire on itself, its resistance becomes one-fourth.

Hope it helps you!!

The diagram shows a box being pulled along a horizontal surface with a force of 200.0 N.
Calculate the work done on the box to pull it a distance of 5.0 m.

Answers

Answer:

The formula for work is

W= fd

work= force X distance

so, this is

200 X 5 =1,000

and the unit for work is Joules

so.. 1,000 joules

Explanation:

hope that helps!

Which of the following is true about how pressure varies with depth in a fluid? a. Pressure decreases with depth because it must support the fluid weight above it. b. Pressure increases with depth because it must support the fluid weight above it. c. Pressure decreases with depth because it is supported by the fluid weight below it. d. Pressure increases with depth because it is supported by the fluid weight below it.

Answers

Answer:

b)    pressure increases with depth because of the weight of the fluid  above

P = ρ g H        density * gravity * fluid depth

(Note - force from the fluid below is an example of Newton's Third Law - for every action there is an equal and opposite reaction)

To reduce auto emissions in the United States, modifications to automobile engines have been required since the 1960s.
a) true
b) false

Answers

Answer:

True

Explanation:

Which of the following is not part of the control system? steering wheel exhaust pipe brake accelerator

Answers

Answer:

Brakes unevenly adjusted: Brakes pulling in one direction or the other can lead to a skid. Tires with worn tread: Tread is necessary for traction in wet weather

Explanation:

Answer: exhaust pipe

Explanation: It doesn't really control anything so I'm assuming this is the answer

Obtain the potential on the x-axis at x = 0 for the following point charge distributions on the x-axis: 200 μC at x = 20 cm, -300 μC at x = 30 cm and -400 μC at x = 40 cm.

Answers

The eletric potential on the x - axis at x = 0 cm for the given three charges is determined as 9 x 10⁶ V.

Electric potential

The electric potential at a point is the work done in moving a test charge from infinity to a certain point.

Eletric potential at x = 0 cm

V(net) = V1 + V2 + V3

[tex]V = - \frac{kq}{r} \\\\V(net) = V_1 + V_2 + V_3\\\\V_{(net)} = -\frac{9\times 10^9 \times 200\times 10^{-6}}{0.2} + \frac{9\times 10^9 \times 300\times 10^{-6}}{0.3}+ \frac{9\times 10^9 \times 400\times 10^{-6}}{0.4}\\\\V_{(net)} = -9\times 10^6 \ + \ 9\times 10^6 \ + \ 9\times 10^6 \\\\V_{(net)} = 9\times 10^6 \ V[/tex]

Thus, the eletric potential on the x - axis at x = 0 cm for the given three charges is determined as 9 x 10⁶ V.

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In which of the following situations would an electromagnet be more useful than a magnet? *
1 point
A teacher uses a magnet to attach their name tags to her shirt.
B child is linking magnetic balls together to make a necklace.
C parent is hanging up a good grade on a refrigerator.
D scrapyard worker is sorting car parts.

Answers

The answer to your question is: C                                    

The marble has its maximum gravitational potential energy when it is at the starting point: the
highest point on the roller coaster. How much of this potential energy is converted to the
marble's kinetic energy?

Answers

Answer:

Explanation:

This depends on the height.

Using the formula mgh + 1/2mv^2 = total mechanical energy, we can determine the amount of kinetic and potential energy. I'm assuming your talking about if the marble goes all the down, then all of the energy is converted.

how do i turtle answer fast

Answers

Answer:

Take your TIme maaaaaan

Explanation:

Chillax

Here's a question for you Care to go bowling?

Answer:

By taking it Slow.

Don't go too fast


PLEASE HELP
Which statement about matter is true?

Matter is anything that is made of atoms and that has mass (and volume).

Matter is anything that is made of organic substances and is found on the earth.

Matter is an element.

Matter is a compound

Answers

Answer: Matter is anything that is made of atoms and that has mass (A)

Explanation: All everyday objects that can be touched are ultimately composed of atoms. Even you are made of atoms. Anything that you can touch has moving particles unless the object is at absolute zero, which is not possible.

Hope this helps!

4. An object has a mass in air of 0.0832 kg, apparent mass in water of 0.0673 kg, and apparent mass in another liquid of 0.0718 kg. What is the specific gravity of the other liquid

Answers

Question

4. An object has a mass in air of 0.0832 kg, apparent mass in water of 0.0673 kg, and apparent mass in another liquid of 0.0718 kg. What is the specific gravity of the other liquid

Hold on, our servers are swamped. Wait for your answer to fully load.

Answer:

Explanation:4. An object has a mass in air of 0.0832 kg, apparent mass in water of 0.0673 kg, and apparent mass in another liquid of 0.0718 kg. What is the specific gravity of the other liquid

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