Answer:
To create the sketch of a polynomial function there are key features are necessary and these are the vertex, axis of symetry, x and y intercepts
Step-by-step explanation:
To create the sketch of a polynomial function there are key features are necessary and these are the vertex, axis of symetry, x and y intercepts
One of the key features arte the vertex and this shows where it changes concativity.
While the x and y intercepts give you a couple of points of reference.
Also, the axis of symetry is only applicable to even degree polynomials
Find the area of the shape shown below.
Answer:
12 is the total areaStep-by-step explanation:
A of triangle = 1/2 * b * h
b = 6
h = 2
2 * 6 * 0.5
= 12 * 0.5
= 6A of square = l * w
2 * 2
= 4A of Triangle = 1/2 * b * h
2 * 2 * 0.5 =
4 * 0.5
= 22 + 4 + 6
= 6 + 6
= 12A polynomial has a leading coefficient of 1 and the
following factors with multiplicity1:
x-(2 + i)
X - V2
What is the factored form of the polynomial?
Answer:
(A)[tex][x-(2+i)][x-(2-i)][x-\sqrt{2}][x+\sqrt{2}][/tex]
Step-by-step explanation:
A polynomial has a leading coefficient of 1 and the following factors with multiplicity 1:
[tex]x-(2+i)\\x-\sqrt{2}[/tex]
We apply the following to find the factored form of the polynomial.
If a complex number is a root of a polynomial with real coefficients, its complex conjugate is also a root of that polynomial.If the polynomial has an irrational root [tex]a+\sqrt{b}[/tex], where a and b are rational and b is not a perfect square, then it has also a conjugate root [tex]a-\sqrt{b}[/tex].[tex]\text{Complex conjugate of }x-(2+i)=x-(2-i)\\\\\text{Complex conjugate of }x-\sqrt{2}=x+\sqrt{2}[/tex]
Therefore, the factored form of the polynomial is:
[tex][x-(2+i)][x-(2-i)][x-\sqrt{2}][x+\sqrt{2}][/tex]
Answer:
A
Step-by-step explanation:
EDGE 2021
In a newspaper, it was reported that yearly robberies in Springfield were down 10% to 90 in 2014 from 2013. How many robberies were there in Springfield in 2013?
Answer:
100.
Step-by-step explanation:
Let the number of robberies be x ( in 2013).
Then x - 0.10x = 90
0.90x = 90
x = 90 / 0.90
= 100.
Solve the equation for all exact solutions where appropriate. Round approximate answers in degrees to the nearest tenth. Write answers using the least possible nonnegative angle measures. sine theta cosine theta minus sine theta equals 0
A. {270 degree - 360 degree n, where n is any integer}
B. {270 degree + 180 degree n, where n is any integer}
C. {270 degree + 180 degree n, 315 degree + 180 degree n, where n is any integer}
D. {270 degree + 360 degree n, 315 degree + 360 degree n, where n is any integer}
Step-by-step explanation:
The equation is sinθ * cosθ - sinθ = 0
sinθ * cosθ -sinθ = 0sinθ * cosθ = sinθcosθ = sinθ/sinθcosθ = 1θ = 0 + 2kπ
θ = 2kπ where k is any integer
The solutions to the equation are: {0 degree, 180 degree, 360 degree, 360 degree + 180 degree n, where n is any integer}
Hence, the correct option is C.
The given equation is:
sin theta × cos theta - sin theta = 0
We can factor out the sine theta:
sin theta (cos theta - 1) = 0
This means that either sin theta = 0 or cos theta - 1 = 0.
If sin theta = 0, then theta = 0, 180 degrees, 360 degrees, etc.
If cos theta - 1 = 0, then cos theta = 1, which means that theta = 0 degrees and 360 degrees.
Therefore, the solutions to the equation are:
{0 degree, 180 degree, 360 degree, 360 degree + 180 degree n, where n is any integer}
So the answer is C.
Learn more about solutions here: brainly.com/question/30665317
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Simplify this problem. |3r−15| if r<5
Answer:
We have the problem:
|3r−15| if r<5
First we see the equality, if r = 5 we have:
I3r - 15I = I3*5 - 15I = I0I = 0.
Then the only restriction that we have is:
I3r - 15I > 0.
now, we could simplify it a bit further:
if r < 5, then the thing inside the absolute value will always be negative:
Then we can write:
I3*r - 15I = -(3*r -15) > 0
multiplying by -1 in both sides
(3r - 15) < 0.
if we keep simplifying this, we will get our initial restriction:
3r - 15 < 0
3r < 15
r < 15/3 = 5
r < 5
I would REALLY appreciate if you could help me with this question. I am REALLY stuck...
Answer: D) Construct the perpendicular bisectors for AB and AC.
The intersection of all three perpendicular bisectors will form the circumcenter, which is the center of the circumcircle. This circle goes through all three corner points of the triangle. At minimum, you only need two perpendicular bisectors to get the job done. Choice B is close, but is missing that second perpendicular bisector.
The angle bisectors intersect to form the incenter, which is the center of the incircle (it's the largest possible circle to fit inside the triangle without spilling over).
Answer:
D. Construct the perpendicular of ab and ac
Step-by-step explanation:
Circumscribe a Circle on a Triangle
Construct the perpendicular bisector of one side of the triangle.
Construct the perpendicular bisector of another side.
Where they cross is the center of the Circumscribed circle.
Place compass on the center point, adjust its length to reach any corner of the triangle, and draw your Circumscribed circle
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Assume that the random variable X is normally distributed, with mean p = 100 and standard deviation o = 15. Compute the
probability P(X > 112).
Answer:
P(X > 112) = 0.21186.
Step-by-step explanation:
We are given that the random variable X is normally distributed, with mean [tex]\mu[/tex] = 100 and standard deviation [tex]\sigma[/tex] = 15.
Let X = a random variable
The z-score probability distribution for the normal distribution is given by;
Z = [tex]\frac{X-\mu}{\sigma}[/tex] ~ N(0,1)
where, [tex]\mu[/tex] = population mean = 100
[tex]\sigma[/tex] = standard deviaton = 15
Now, the probability that the random variable X is greater than 112 is given by = P(X > 112)
P(X > 112) = P( [tex]\frac{X-\mu}{\sigma}[/tex] > [tex]\frac{112-100}{15}[/tex] ) = P(Z > 0.80) = 1- P(Z [tex]\leq[/tex] 0.80)
= 1 - 0.78814 = 0.21186
The above probability is calculated by looking at the value of x = 0.80 in the z table which has an area of 0.78814.
Please help if you are correct you get brainlyest
Answer:
did you already try A???
Answer:
Probability : [tex]\frac{5}{33}[/tex]
Step-by-step explanation:
The probability of drawing an orange on the first attempt would be 5 / 12, considering that in this first attempt their are 5 oranges present out of a total of 12 fruits. Now after that fruit is chosen their are 4 out of 11 oranges present, such that the probability of drawing an orange on the second attempt would be 4 / 11.
Probability of choosing an orange on the first try : [tex]5 / 12[/tex]
Probability of choosing an orange on the second try : [tex]4 / 11[/tex]
Probability of selecting two oranges in a row ( blindfolded ) : [tex]5 / 12 * 4 / 11[/tex]
[tex]\frac{5}{12}\cdot \frac{4}{11}[/tex] ( cross cancel common factor 4 )
[tex]\frac{5}{3}\cdot \frac{1}{11}[/tex] ( multiply fractions )
[tex]\frac{5\cdot \:1}{3\cdot \:11}[/tex] = [tex]\frac{5}{3\cdot \:11}[/tex] = [tex]\frac{5}{33}[/tex] - the probability of selecting two oranges in a row blindfolded, is [tex]\frac{5}{33}[/tex].
PLEASE help me with this question! I really need help...
Answer:
The third: [tex]\bold{\dfrac{x+5}{x+15}}[/tex]Step-by-step explanation:
[tex]x^2+19x+70\ \implies a=1\,,\ b=19\,,\ c=70\\\\x=\frac{-19\pm\sqrt{19^2-4\cdot1\cdot70}}{2\cdot1}=\frac{-19\pm\sqrt{361-280}}{2}=\frac{-19\pm9}{2}\ \Rightarrow\ x_1=-14\,,\ x_2=-5\\\\x^2+19x+70=(x+14)(x+5)\\\\\\x^2-225=x^2-(15)^2=(x-15)(x+15)\\\\\\x^2-5x-150\ \implies a=1\,,\ b=-5\,,\ c=-150\\\\x=\frac{-(-5)\pm\sqrt{(-5)^2-4\cdot1\cdot(-150)}}{2\cdot1}=\frac{5\pm\sqrt{25+600}}{2}=\frac{5\pm25}{2}\ \Rightarrow\ x_1=-10\,,\ x_2=15\\\\x^2-5x-150=(x+10)(x-15)[/tex]
[tex]x^2+24x+140\ \implies a=1\,,\ b=24\,,\ c=140\\\\x=\frac{-24\pm\sqrt{24^2-4\cdot1\cdot140}}{2\cdot1}=\frac{-24\pm\sqrt{576-560}}{2}=\frac{-24\pm4}{2}\ \Rightarrow\ x_1=-14\,,\ x_2=-10\\\\x^2-5x-150=(x+14)(x+10)[/tex]
[tex]\dfrac{x^2+19x+70}{x^2-225}\,\cdot\,\dfrac{x^2-5x-150}{x^2+24x+140}=\dfrac{(x+14)(x+5)}{(x-15)(x+15)}\cdot\dfrac{(x+10)(x-15)}{(x+14)(x+10)}=\\\\\\=\dfrac{(x+14)(x+5)}{(x-15)(x+15)}\cdot\dfrac{x-15}{x+14}=\dfrac{x+5}{x+15}\cdot\dfrac11=\boxed{\dfrac{x+5}{x+15}}[/tex]
Answer:
The answer is option 3.
Step-by-step explanation:
First, you have to factorize the expressions :
[tex] \frac{ {x}^{2} + 19x + 70 }{ {x}^{2} - 225 } \times \frac{ {x}^{2} - 5x - 150}{ {x}^{2}24x + 140 } [/tex]
[tex] = \frac{(x + 5)(x + 14)}{(x + 15)(x - 15)} \times \frac{(x - 15)(x + 10)}{(x + 10)(x + 14)} [/tex]
Next, you have to cut out the common terms like (x + 14), (x - 15) and (x + 10):
[tex] \frac{(x + 5)(x + 14)}{(x + 15)(x - 15)} \times \frac{(x - 15)(x + 10)}{(x + 10)(x + 14)} [/tex]
[tex] = \frac{x + 5}{x + 15} [/tex]
Find the intercepts and graph the following linear equations: 2y − 6 = 0
The y-intercept is [tex](0,\frac{6}{2})=(0,3)[/tex] and there is no x-intercept since the equality can simplified to the point of obtaining a constant function [tex]y=3[/tex] which does not depend on x.
Hope this helps.
The city park department is planning to enclose a play area with fencing. One side of the area will be against an existing building, so no fence is needed there. Find the dimensions of the maximum rectangular area that can be enclosed with 800 meters of fence. Include the units.
Answer:
The maximum rectangular area will have the length 400 meters and width 200 meters with one side of the length against an existing building.
Step-by-step explanation:
From the given information;
The perimeter of a rectangle = 2 (L+B)
here;
L = the length of the side of the fence
B = the width of the fence
So; The perimeter of a rectangle = 2L+2B
we are also being told that;
One side of the area will be against an existing building
i.e
The perimeter of a rectangle is now = L + 2B = 800 meters
L = 800 - 2B
Similarly; Area of a rectangle = L × B
Area of a rectangle = ( 800 - 2B) × B
Area of a rectangle = 800B - 2B²
assuming A(B) to represent the Area;
Then the maximum area A'(B) = 0 ;
Thus,
A'(B) = 800 - 4B = 0
-4B = - 800
4B = 800
B = 200
Therefore; the maximum area have a width = 200 meters and a length 800 - 2(200) = 800 - 400 = 400 meters
Austin walks 2/3 of the way to school and stopped to rest. Devyn walks 4/6 of the way to school and stops for a rest. Where are they in their route to school? Who has traveled further?
Answer:
both are at the same distance
Step-by-step explanation:
Answer:
Austin and Devyn both have 1/3 of the way left on their way to school. They both also have walked the same amount.
Step-by-step explanation:
If Austin has to walk to his school, which could be said as 3/3 and Austin has already walked 2/3. Then if we conduct the equation 3/3-2/3=x. x=1/3. Now Devyn has already walked 4/6 of the way to school. If she has to walk a total of 6/6, then we can again make an equation 6/6-4/6=2/6. Now if we take the distance that they both have left to their school, its 1/3 and 2/6. These are both equavalent fractions because if you scale up 1/3, it equals to 2/6. Since they both have an equal amount of distance to travel, that must mean that they both have covered the same amount of distance already. We can double check to be sure. 2/3 *2/2=4/6. The reason we used 2/2 is because4/2=2 and 6/3=2.
A car travels 120m along a straight road that is inclined at 8° to the horizontal. Calculate the vertical distance through which the car rises. (Sin 8°= 0.1392)
Answer:
16.704m
Step-by-step explanation:
To solve the above question, we are going to use the Trigonometric function of Sine.
sin θ = Opposite side/Hypotenuse
Where are given θ = 8°
Sin 8° = 0.1392
In the question, we are told that ,
A car travels 120m along a straight road that is inclined at 8° to the horizontal, hence,
Hypotenuse = 120m
We are asked to calculate the vertical distance through which the car rises hence,
Opposite side = vertical distance.
Therefore,
Sin 8° = Opposite/ 120m
Opposite = Sin 8° × 120m
Opposite = 0.1392 × 120m
Opposite = 16.704m
Therefore, the vertical distance through which the car rises is 16.704m
please help I will give brainiest I need your help!!!!
Answer:
Step-by-step explanation:
∠OAB is 90 degrees, tangent and a radius met at 90 degree angle
∠OCB=90 degrees, tan and radius meet at 90 degrees angle
OB=12
find angle BOC:
triangle BOA is right angle triangle:
cos(AOB)=adj/hyp=7/12=54.33
angle B= 180-(90+54.33)=35.67
angle COB=54.33 equal to angle AOB
angle AOC=54.33+54.33=108.66
the sum of angles of circle =360
360-108.66= 251.34( exterior angle at the center AOC)
length of the arc= angle (251.34 degrees*7)
convert degrees to radians=4.386 (251.34/π)
length=r*angle in radian=4.386*7=30.71
( i hope this is the answer)
A pound is approximately 0.45 kilogram. A person weighs 87 kilograms. What is the person’s weight, in pounds, when rounded to the nearest whole number?
Answer:
190
Step-by-step explanation:
the weight is 191 lbs rounded is 190
01:14:29 The Schwartz family spent a total of $111.75 for Internet service for 3 months. Each month they received $5.50 as a credit on the bill. Which equation and solution shows the cost of their monthly Internet service before the credit? 3 (x + 5.50) = 111.75; the monthly Internet service is $31.75 3 (x minus 5.50) = 111.75; the monthly Internet service is $42.75 One-third (x minus 5.50) = 111.75; the monthly Internet service is $42.75 One-third (x + 5.50) = 111.75; the monthly Internet service is $31.75
Answer: 3(x minus 5.50) = 111.75; the monthly Internet service is $42.75
Step-by-step explanation:
Given the following :
Total amount spent on internet for 3 months = $111.75
Monthly credit received on bill = $5.50
Monthly Credit of $5.50 means $5.50 is deducted from the amount being paid on thir bill monthly.
Assume their monthly internet service fee = x
The amount paid before the credit deduction each month:
Amount paid - credit
(x - $5.50)
For 3 months :
3 × (x - $5.50) = $117.75
3(x - $5.50) = $117.75
Monthly fee paid before credit deduction:
3(x - $5.50) = $117.75
3x - $16.50 = $117.75
3x = $117.75 + $16.50
3x = $128.25
x = $128.25 / 3
x = $42.75
Answer:
It's b !! :o]
Step-by-step explanation:
Latesha’s mother puts $85 in Latesha’s lunch account at school. Each day Latesha uses $3 from her account for lunch. The table below represents this situation. Latesha’s Lunch Account Day Amount Left in Account ($) 0 $85 1 2 3 4 5 How much is left in Latesha’s lunch account after she has had lunch for 5 days? $15 $67 $70 $82
Answer: it 70
Step-by-step explanation:
Latesha’s mother puts $85 in Latesha’s lunch account at school. Each day Latesha uses $3 from her account for lunch. The table below represents this situation.
How much is left in Latesha’s lunch account after she has had lunch for 5 days?
$15
$67
$70 is correct$82
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Find the value of x in the triangle
shown below.
X
85
67
Answer:
x = 28 degrees. 180 degrees in a triangle, 180-85-67=28
Answer:
28 degrees
Step-by-step explanation:
The interior angles of a triangle add up to 180 degrees.
The three angles given are: x, 85, and 67.
Therefore, these three angles must add to 180.
x+85+67=180
Combine like terms on the left. Add 85 and 67.
x+ (85+67)=180
x+152=180
We want to find x. We need to get x by itself. 152 is being added to x. The inverse of addition is subtraction. Subtract 152 from both sides.
x+152-152=180-152
x=180-152
x=28
x is 28 degrees.
What is the solution to the system of equations graphed below?
Answer:
( 3 , -2 )Option B is the correct option.
Step-by-step explanation:
[tex]y = - 2x + 4...........(i)[/tex]
[tex]y = x - 5..........(ii)[/tex]
Equate ( i ) and ( ii ),
[tex] - 2x + 4 = x - 5[/tex]
Move variable to L.H.S and change its sign
Similarly, Move constant to R.H.S and change its sign
[tex] - 2x - x = - 5 - 4[/tex]
Calculate
[tex] - 3x = - 9[/tex]
Divide both sides of the equation by -3
[tex] \frac{ - 3x}{ - 3} = \frac{ - 9}{ - 3} [/tex]
Any expression divided by itself equals 1
[tex]x = \frac{ - 9}{ - 3} [/tex]
Dividing two negatives equals a positive [tex]( - ) \div ( - ) = ( + )[/tex]
[tex]x = \frac{9}{3} [/tex]
calculate the quotient
[tex]x = 3[/tex]
Value of X is 3
Now, put the value of X in equation ( i ) in order to find the value of y
[tex]y = x - 5[/tex]
plug the value of X
[tex] = 3 - 5[/tex]
Calculate
[tex] = - 2[/tex]
Value of y is -2
So, ( 3 , -2 ) is the solution of the given equation.
Hope this helps ....
Best regards!!
Instructions: Find the missing length indicated.
Answer:
? = 3
Step-by-step explanation:
The parallel segments shown divide the sides in the ratio
[tex]\frac{6}{4}[/tex] = [tex]\frac{?}{2}[/tex] ( cross- multiply )
4? = 12 ( divide both sides by 4 )
? = 3
tate the postulate that verifies is in plane Q when points A and B are in Q.
Answer:
Postulate 3: Through any three points that are not one line, exactly one plane exists. State the postulate that verifies line segment AB is in plane Q when points A and B are in Q.
Step-by-step explanation:
Postulate 4: If two points lie in a plane, the line containing them lies in that plane. hope this helps you :)
what is the domain of the function represented by the graph.?
Answer:
all real numbers
Step-by-step explanation:
There is nothing on the graph to indicate the function is undefined for any values of x. The domain is all real numbers.
Answer:
Domain is all real numbers.
Step-by-step explanation:
The domain of a quadratic function in standard form is always all real numbers, meaning you can substitute any real number for x.
(i) The third and the seventh terms of an A.P. are 20 and 36 respectively. Find the first
term and the common difference,
Answer:
The first term is 12. The common difference is 4.
Step-by-step explanation:
[tex] a_n = a_1 + d(n - 1) [/tex]
The difference between the third and seventh terms is
36 - 20 = 16
The 7th term is the 4th term after the 3rd term, so the common difference is
16/4 = 4
[tex] a_3 = a_1 + 4(3 - 1) [/tex]
[tex] 20 = a_1 + 4(3 - 1) [/tex]
[tex] 20 = a_1 + 8 [/tex]
[tex] a_1 = 12 [/tex]
Answer: The first term is 12. The common difference is 4.
I'm marking answers as brainliest. The solution to the following system is ________. -9x + 6y = -30, -7x + 12y = -16 * I I (0,2) (4,1) (-4,7) (2,1)
Answer:
Step-by-step explanation:
-9x + 6y = -30
-7x + 12y = -16
18x - 12y = 60
-7x + 12y = -16
11x = 44
x = 4
-36 + 6y = -30
6y = 6
y = 1
(4,1)
Answer:
(4,1)
Step-by-step explanation:
-9x + 6y = -30.............(1)
-7x + 12y = -16 ............(2)
(2) - 2(1)
-7x+12y - 2(-9x+6y) = -16 - 2(-30)
simplify
11x = 44
or
x = 4 .......................(3a)
substitute (3) in (1)
-9(4) + 6y = -30
6y = -30 + 36
6y = 6
y = 1 ......................(3b)
Using results from (3a) and (3b), we have
solution : (4,1)
Alonso went to the market with $55 to buy eggs and sugar. He knows he needs a package of 12 eggs that costs $2.75. After getting the eggs, he wants to buy as much sugar as he can with his remaining money. The sugar he likes comes in boxes that each cost $11.50 Write an inequality. Also, after getting the eggs, how many boxes of sugar can Alonso afford? Thanks.
Answer:
1) The inequality is $55 ≥ $11.50 × S + $2.75
2) Alonso can afford 4 boxes of sugar
Step-by-step explanation:
The given information are;
The total amount with Alonso = $55
The amount of eggs Alonso needs = 12 eggs
The costs of the pack of 12 eggs = $2.75
The number of packs of eggs Alonso buys = 1
The cost of each box of sugar = $11.50
Let the number of boxes of sugar Alonso buys = S
Given that the total amount of money with Alonso is $55, then the inequality will be such that $55 will be equal to or larger than the expression for items bought
Therefore, the inequality is given as follows;
$55 ≥ $11.50 × S + $2.75
2) To find out how many boxes of sugar Alonso can afford, we have;
$55 ≥ $11.50 × S + $2.75
$55 - $2.75≥ $11.50 × S
$52.25 ≥ $11.50 × S
∴ S ≤ $52.25/$11.50 = 4.54
S ≤ 4.54 boxes of sugar
As the sugar comes in whole boxes, Alonso can therefore afford only 4 whole boxes of sugar.
Alonso can afford to buy 4 boxes of sugar.
An inequality to represent how many boxes of sugar can Alonso afford is 55 ≥ 2.75 + 11.50s
Given:
Amount with Alonso = $55
Package of 12 eggs = $2.75
Cost of each box of sugar = $11.50
let
s = number of boxes of sugar Alonso can afford
The inequality:
55 ≥ 2.75 + 11.50s
solve for s
55 - 2.75 ≥ 11.50s
52.25 ≥ 11.50s
divide both sides by 11.50
52.25 / 11.50 ≥ s
4.5434782608695 ≥ s
Alonso can only buy a whole box of sugar
Therefore, the number of boxes of sugar Alonso can afford is 4 boxes
Read more:
https://brainly.com/question/11067755
find tan(a) in the triangle
Answer:
tan (a) = 24/7Step-by-step explanation:
tan∅ = opposite / adjacent
From the question
AC is the adjacent
BC is the opposite
So we have
tan (a) = BC / AC
tan (a) = 24/7
Hope this helps you
A lake has a small patch of lily pads and every day the patch grows to double its size. It takes 32 days for the patch to cover the lake – how long would it take the patch to cover half the lake?
Answer:
It took 31 days for the patch to cover half the lake
Step-by-step explanation:
The patch grows to double its size everyday
the patch completely covers the lake in 32 days
Since the patch doubles itself everyday, this means that the previous day before the 32nd day, the lake was just half covered.
Therefore, the the patch covered half the lake on the 31st day, i.e it took 31 days for the patch to cover half the lake
What interval includes all possible values of x, where –3(6 – 2x) ≥ 4x + 12? (–∞, –3] [–3, ∞) (–∞, 15] [15, ∞) SORRY THIS IS THE FULL QUESTION
Answer:
[15, ∞).
Step-by-step explanation:
–3(6 – 2x) ≥ 4x + 12
-18 + 6x ≥ 4x + 12
6x - 4x ≥ 12 + 18
2x ≥ 30
x ≥ 15
This means that the minimum of x is 15, and the most is infinity, which is the same thing as [15, ∞).
Hope this helps!
A theater group made appearances in two cities. The hotel charge before tax in the second city was $500 higher than in the first. The tax in the first city was 4.5%, and the tax in the second city was 3.5% . The total hotel tax paid for the two cities was $317.50. How much was the hotel charge in each city before tax? First city: Second city:
Answer:
$3750 and $4250
Step-by-step explanation:
x + 500 = y
.045x + .035y = 317.50
.045x + .035(x + 500) = 317.50
.045x + .035x + 17.5 = 317.50
.08x = 300.00
x = 3750
y = 4250
3 over 3 fourths divided by 5 over 7
Answer:
5.6
Step-by-step explanation:
(3÷3/4)÷5/7
[tex] \frac{3 \times 4}{3} \div \frac{5}{7} [/tex]
[tex]4 \div \frac{5}{7} [/tex]
[tex]4 \times \frac{7}{5} [/tex]
[tex] \frac{28}{5} [/tex]
=5.6
use "keep, change, flip " when dividing a number by a fraction.
keep the whole number
flip the divide sign to multiply
change the placement of number e.g. 5/7 becomes 7/8
then solve