May I please receive help?

Answer:

11th term is 0

Step-by-step explanation:

30, 27 , 24 ,......0

a = first term = 30

Common difference = second term - first term = 27 - 30 = -3

nth term = a+(n-1)*d

a + (n-1)d = 0

30 + (n - 1) *(-3) = 0

30 + n*(-3) -1*(-3) = 0

30 - 3n + 3 = 0

      -3n + 33 = 0

               -3n = -33

                   n = -33/-3

n = 11

13. M=4/3

14. m=-6

Step-by-step explanation:

Answer its (-2,5)

if its on q2

Answer:

(3,7) is not a solution

Step-by-step explanation:

You fill in the values x=3 and y=7 in both equations and see if you end up with something that is true.

-5·3 - 2·7 = 23 is not true, because it simplifies to -29 = 23

no need to look further, but if you would, the second equation is also false:

3 + 4·7 = -19 is also not true.

The real solution by the way is (-3, -4).

Answer:

Step-by-step explanation:

Answer:

88 blankets

Step-by-step explanation:

5 times 15 = 75

75 + 13 = 88

Answer:

perimeter-3+6+3+10+6+4=32m

area- 10×6=60m²

Answer:

-2

Step-by-step explanation:

It's (x,y)

Here, (3,-2)

-2 is y

:)

Answer:

4(x + 1/4) ≤ 9 + 2x

Step-by-step explanation:

Answer:

25

Step-by-step explanation:

remember that the pythagorean theorem is a²+b²=c²

so this equation would be:

7²+24²=c²

solve the exponents

49 + 576 = c²

combine like terms

625 = c²

take the radical of each number

√625 = √c²

25 = c

have a lovely day <3

[tex] \green{\large\underline{\sf{Solution-}}}[/tex]

Given expression is

[tex]\rm :\longmapsto\:\dfrac{5 \times {25}^{n + 1} - 25 \times {5}^{2n} }{5 \times {5}^{2n + 3} - {25}^{n + 1} } [/tex]

can be rewritten as

[tex]\rm \:  =  \: \dfrac{5 \times { {(5}^{2} )}^{n + 1} - {5}^{2} \times {5}^{2n} }{5 \times {5}^{2n + 3} - {( {5}^{2} )}^{n + 1} } [/tex]

We know,

[tex] \purple{\rm :\longmapsto\:\boxed{\tt{ {( {x}^{m} )}^{n} \: = \: {x}^{mn}}}} \\ [/tex]

And

[tex] \purple{\rm :\longmapsto\:\boxed{\tt{ \: \: {x}^{m} \times {x}^{n} = {x}^{m + n} \: }}} \\ [/tex]

So, using this identity, we

[tex]\rm \:  =  \: \dfrac{5 \times {5}^{2n + 2} - {5}^{2n + 2} }{{5}^{2n + 3 + 1} - {5}^{2n + 2} } [/tex]

[tex]\rm \:  =  \: \dfrac{{5}^{2n + 2 + 1} - {5}^{2n + 2} }{{5}^{2n + 4} - {5}^{2n + 2} } [/tex]

can be further rewritten as

[tex]\rm \:  =  \: \dfrac{{5}^{2n + 2 + 1} - {5}^{2n + 2} }{{5}^{2n + 2 + 2} - {5}^{2n + 2} } [/tex]

[tex]\rm \:  =  \: \dfrac{ {5}^{2n + 2} (5 - 1)}{ {5}^{2n + 2} ( {5}^{2} - 1)} [/tex]

[tex]\rm \:  =  \: \dfrac{4}{25 - 1} [/tex]

[tex]\rm \:  =  \: \dfrac{4}{24} [/tex]

[tex]\rm \:  =  \: \dfrac{1}{6} [/tex]

Hence,

[tex]\rm :\longmapsto\:\boxed{\tt{ \dfrac{5 \times {25}^{n + 1} - 25 \times {5}^{2n} }{5 \times {5}^{2n + 3} - {25}^{n + 1} } = \frac{1}{6} }}[/tex]

Answer:

N=20

Step by Step:

First you add 17 to both of the sides:

N−17+17=3+17

Second, you simplify;

N=20

Brainiest please?

Answer:D

Step-by-step explanation:

Answer:

Your answer is 506.093.

Step-by-step explanation:

Hope this helps!

[tex] \sf \underline{ \red{Solution - }} \\ [/tex]

Given,

[tex] \sf{\quad { \dfrac{-7}{\sqrt{11} - \sqrt{5}} }} \\ [/tex]

The denominator is √11 - √5.

We know that

Rationalising factor of √a-√b is √a+√b.

Therefore, the rationalising factor of √11-√5 is √11+√5.

On rationalising the denominator them

[tex] \longrightarrow \sf{\quad { \dfrac{-7}{\sqrt{11} - \sqrt{5}} \times \dfrac{(\sqrt{11} + \sqrt{5})}{(\sqrt{11} + \sqrt{5})} }} \\ [/tex]

Multiplying (√11 + √5) with both the numerator of the fraction.

[tex] \longrightarrow \sf{\quad { \dfrac{-7(\sqrt{11} + \sqrt{5}) }{(\sqrt{11} - \sqrt{5})(\sqrt{11} + \sqrt{5})} }} \\ [/tex]

Performing multiplication in the numerator and by using identity (a + b)(a - b) = a² - b², solving further in the denominator.

[tex] \longrightarrow \sf{\quad { \dfrac{-7\sqrt{11} -7\sqrt{5}}{(\sqrt{11})^2 - (\sqrt{5})^2} }} \\ [/tex]

Writing the squares of the numbers in the denominator.

[tex] \longrightarrow \sf{\quad { \dfrac{-7\sqrt{11} -7\sqrt{5}}{11 -5} }} \\ [/tex]

Performing subtraction in the denominator.

[tex] \longrightarrow \quad \underline{ \boxed{ \dfrac{ \textbf{ \textsf{-7 }}\sqrt{ \textbf{ \textsf{11 }}} - \textbf{ \textsf{7}}\sqrt{ \textbf{ \textsf{5 }}}}{ \textbf{ \textsf{ 6}}}} } \\ [/tex]

Hence, the denominator is rationalised.

Answer:

the answer is the third one 3

Answer:

y = 2x - 1

Step-by-step explanation:

Slope = (5-1) / (3-1) = 4/2 = 2

y-intercept = 1 - (2)(1) = - 1

y = 2x - 1

[tex]\large\underline{\sf{Solution-}}[/tex]

Given that

[tex] \purple{\rm :\longmapsto\:Dividend = {x}^{3} - {2x}^{2} - x + 2}[/tex]

and

[tex] \purple{\rm :\longmapsto\:Divisor = x + 1}[/tex]

So, By using Long Division Method, we have

[tex]\begin{gathered}\begin{gathered}\begin{gathered} \:\: \begin{array}{c|c} {\underline{\sf{}}}&{\underline{\sf{\:\: {x}^{2} - 3x + 2\:\:}}}\\ {\underline{\sf{x + 1}}}& {\sf{\: {x}^{3}  -  {2x}^{2} - x + 2 \:\:}} \\{\sf{}}& \underline{\sf{- {x}^{3} - {x}^{2} \: \: \:  \:  \:  \:  \:  \:  \:  \: \:\:}} \\ {{\sf{}}}& {\sf{\: \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  - 3{x}^{2} - x +2  \:  \:  \:  \:   \:  \:  \:  \:\:}} \\{\sf{}}& \underline{\sf{\:\: \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  3{x}^{2} + 3x  \:  \:  \:  \:  \:  \: \:\:}} \\ {\underline{\sf{}}}& {\sf{\:\: \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: 2x + 2 \:\:}} \\{\sf{}}& \underline{\sf{\: \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \: - 2x - 2\:\:}} \\ {\underline{\sf{}}}& {\sf{\:\: \:  \: \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: 0\:\:}}  \end{array}\end{gathered}\end{gathered}\end{gathered}[/tex]

So,

[tex]\bf\implies \:Remainder = 0[/tex]

Verification

[tex] \purple{\rm :\longmapsto\:Dividend = {x}^{3} - {2x}^{2} - x + 2}[/tex]

[tex] \purple{\rm :\longmapsto\:Divisor = x + 1}[/tex]

[tex] \purple{\rm :\longmapsto\:Remainder = 0}[/tex]

[tex] \purple{\rm :\longmapsto\:Quotient = {x}^{2} - 3x + 2}[/tex]

Now, Consider

[tex]\rm :\longmapsto\:Divisor \times Quotient + Remainder[/tex]

[tex]\rm \:  =  \: (x + 1)( {x}^{2} - 3x + 2) + 0[/tex]

[tex]\rm \:  =  \: {x}^{3} - {3x}^{2} + 2x + {x}^{2} - 3x + 2[/tex]

[tex]\rm \:  =  \: {x}^{3} - {2x}^{2} - x + 2[/tex]

[tex]\rm \:  =  \: Dividend[/tex]

Hence, Verified

CARRY ON LEARNING

CAN YOU BRAINLEST ME PLEASE

Answer:

hope this helps

Answer:

hope it helps you..........

Answer:

(5,-12)

(-3,0)

(-1,-1)

Step-by-step explanation:

For (4, −12): 2(4) - 12 = 8 - 12 = -4                  [false]

For (−3, 0): 2(-3) = -6 < -4                                [false]

For (5, −12): 2(5) - 12 = 10 - 12 = -2 > -4         [true]

For (0, 1): 2(0) + 1 = 1 > -4                              [true]

For (−1, −1): 2(-1) - 1 = -2 - 1 = -3 > -4            [true]

Therefore, (5, -12), (0, 1) and (-1, -1) satisfies the inequality 2x + y > -4

For (7, 12): 12 - 2(7) = 12 - 14 = -2 > -3                   [false]

For (0, −2): -2 - 2(0) = -2 > -3                                   [false]

For (5, −3): -3 - 2(5) = -3 - 10 = -13 < -3                   [true]

For (−6, −3): -3 - 2(-6) = -3 + 12 = 9 > -3                  [false]

For (1, −1): -1 - 2(1) = -1 - 2 = -3                              [true]

Therefore, (5, -3) and (1, -1) satisfy the inequality y - 2x ≤ -3

The situation is represented by 2.25x + 2.65y ≥ 8

Answer:

207 cm

Step-by-step explanation:

Because ΔPQR ≅ΔSTU and the longest side in the ΔPQR is RP then the longest side in ΔSTU must be SU = 92 cm

Perimeter of triangle PQR is

P(ΔPQR) = 36+48+24 = 108 cm

Because the triangles are are similar their sides are in proportion.

But how much bigger did the second triangle get?...is (92/48) times bigger

P(ΔSTU) = 180*(92/48) = 207 cm

...you can also use proportions to find each side and then find the perimeter

TU = 24*92 /48 = 46

TS = 36*92/48 = 69

SU = 92

P(ΔSTU) = 92+69+46 =207 cm

*the triangles are not drawn to scale

A A equation that’s perpindicular to y = 4x - 1 and passes through the point (2, -9) is…

Answer: y = -3/4x - 15/2

Explanation: Opposite reciprocal slopes and plug in -9 with y and 2 with x then solve for b

-9 = -1.5 + x

x = -15/2

Answer:

y=2.5x

Step-by-step explanation:

We have been given a graph that shows numbers of servings (y) in different amounts (x) of frozen yogurt listed on a carton.

To write an equation that gives the number of servings y in x pints, we will have to find the slope (rate of change) of our given linear function.

Since we know that rate of change of a function can be found by vertical change of the function divided by horizontal change of the function.  

m= Slope (rate of change).

=Difference between two y-coordinates.

=Difference between corresponding x-coordinates of the y-coordinates.    

Upon substituting coordinates of two points (0,0) and (4,10) in slope formula we will get,  

The slope of our given line is 2.5.  

Now we will write equation of our given line is slope-intercept form. The equation of a line in slope-intercept form is: , where m=slope and b = y-intercept (initial value).

Upon substituting m=2.5 and coordinates of point (4,10) in slope-intercept form of equation we will get,

Upon substituting m=2.5 and b=0 in slope-intercept form of equation we will get,

Therefore, the equation  will give the number of servings y in x pints.

Answer:

The answer for the first one is D: Multiply x by 5 and 2 by 5.

The answer for the second one is: A: There are infinitely many solutions.

Step-by-step explanation:

I am doing Linear equations right now in school lol

Answer:

420 seconds is equal to 7 min

So 7 to 10 or 7 : 10

pls brainliest

These are the steps that you should follow in order to make the necessary calculations to convert 420 Seconds to Minutes. In order to convert from [s] to [min], we have to devide the amount of Seconds by 60.

Then the second step, is to substitute the amount of Seconds with the value of 420 and calculate the division. After successfuly calculating it the result should for 420 Seconds to Minutes should be 7

So 7 to 10 or 7 : 10

Hope this helped!

Have a great day

Answer:

(X+1) (x - 4) (x+2)

Step-by-step explanation:

All the coefficients are integers so apply the rational zeros theorem.

The coefficient of x^3 is 1.

Divide (x^3-x2-10x-8)(x+1) = x^2-2x-8 with remainder = 0

The remainder is 0. (x+1) is a factor.

(x + 1) ( x^2 - 2x - 8)

x^2 - 2x - 8 (-4 * 2= 8) and -4 + 2 = -2)

= (x -4) (x+2)

Given :

To Find :-

Solution :-

As we know that,

Hence the required answer is 10.

Answer:

10 neutrons

Step-by-step explanation:

no.of neutrons = atomic mass - Atomic number

no.of neutrons= 22-12

=10