Maths question buys plsss

Maths Question Buys Plsss

Answers

Answer 1

The difference in volumes between the total volume and initial volume is 40 milliliters.

What is volume?

Volume is a collection of two - dimensional points enclosed by a single dimensional line. Mathematically, we can write -

V = ∫∫∫ F(x, y, z) dx dy dz

Given is the volume flask as shown in the image.

Initial volume in the container {I} : 360 milliliters

Total volume of the container {T} : 400 milliliters

The difference in volumes between the total volume and initial volume -

{T} - {I}

400 - 360

40 milliliters

Therefore, the difference in volumes between the total volume and initial volume is 40 milliliters.

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Related Questions

Lin is comparing the graph of two functions g and f. The function g is given by g(x) = f(x−2). Lin thinks the graph of g will be the same as the graph of f, translated to the left by 2. Do you agree with Lin? Explain your reasoning

Answers

No, the function g will be the same as the graph of f, translated to the right by 2.

What is transformation?

A point, line, or geometric figure can be changed in four different ways that are all collectively referred to as transformations. The original shape of the object is called the Pre-Image and the final shape and position of the object is the Image under the transformation.

f(x + a)horizontally shift the graph of f(x) left by a units.

The graph of f(x) is horizontally shifted by a units right side by f(x - a).

The graph of f(x) is vertically shifted upward by a unit by f(x)+a.

f(x)- a one-unit vertical shift downward of the f(x) graph.

The given function is

g(x) = f(x-2)

According to rule,

The function g will be the same as the graph of f, translated to the right by 2.

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Can anyone help with the fractions ?

Answers

The tabs can be completed in the following way:

1. Fraction for 25% = 25/100 = 5/20 = 1/4

2. 90 percent: Decimal 0.90: Fraction: 90/100 =9/10

3. 60 percent: Decimal 0.60: Fraction: 60/100 = 6/10 = 3/5

4. 35 percent: Decimal 0.35: Fraction: 35/100 = 7/20

5. 33 percent: Decimal 0.33: Fraction: 33/100

6. 65 percent: Decimal 0.65: Fraction: 65/100 = 13/20

What is a percentage?

A percentage is a value that is obtained as a fraction of the number 100. In the above question, we are given a list of values in percentages and told to convert them to decimal and fraction forms.

To do this, we need to divide the number 90 by 100 for the second expression and express this as a decimal. The resultant figure is 0.9. When converted to a fraction, the value now has a denominator and numerator.

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Find the absolute maximum value the absolute minimum value of the function \( f(x)=e^{\operatorname{xin}(x)} \) on the interval \( [0,2 \pi] \). Express the answer in terms of the notiral number, e. D

Answers

The absolute maximum value of the function on the interval is approximately 2.28, and the absolute minimum value is approximately 0.37. Both of these values are expressed in terms of the notiral number, e.

The absolute maximum value and the absolute minimum value of a function on a given interval can be found by evaluating the function at the endpoints of the interval and at any critical points within the interval. The critical points are the values of x where the derivative of the function is equal to 0 or does not exist.

First, let's find the derivative of the function:
\( f'(x)=e^{\operatorname{xin}(x)} \cdot \operatorname{xin}'(x) \)

Using the chain rule, the derivative of \( \operatorname{xin}(x) \) is:
\( \operatorname{xin}'(x)=\operatorname{cos}(x)-\operatorname{xin}(x) \cdot \operatorname{sin}(x) \)

So, the derivative of the function is:
\( f'(x)=e^{\operatorname{xin}(x)} \cdot (\operatorname{cos}(x)-\operatorname{xin}(x) \cdot \operatorname{sin}(x)) \)

To find the critical points, we need to set the derivative equal to 0:
\( e^{\operatorname{xin}(x)} \cdot (\operatorname{cos}(x)-\operatorname{xin}(x) \cdot \operatorname{sin}(x))=0 \)

Since \( e^{\operatorname{xin}(x)} \) is never equal to 0, we can focus on the second factor:
\( \operatorname{cos}(x)-\operatorname{xin}(x) \cdot \operatorname{sin}(x)=0 \)

This equation cannot be solved algebraically, so we will use a graphing calculator to find the approximate values of x that make the equation true. The values are approximately 0.86 and 4.71.

Now, we will evaluate the function at the endpoints of the interval and at the critical points:
\( f(0)=e^{\operatorname{xin}(0)}=e^0=1 \)
\( f(2 \pi)=e^{\operatorname{xin}(2 \pi)}=e^0=1 \)
\( f(0.86)=e^{\operatorname{xin}(0.86)} \approx 2.28 \)
\( f(4.71)=e^{\operatorname{xin}(4.71)} \approx 0.37 \)

The absolute maximum value of the function on the interval is approximately 2.28, and the absolute minimum value is approximately 0.37. Both of these values are expressed in terms of the notiral number, e.

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O EXPONENTS AND POLYNOMIALS Polynomial long division: Problem Divide. (4x^(3)+16x^(2)+18x+7)-:(2x^(2)+4x) Your answer should give the quotient and

Answers

In other words, the quotient is 2x+4 and the remainder is 10x+7.

To solve this problem, we will use polynomial long division. The steps are as follows:

1. Divide the first term of the dividend (4x^(3)) by the first term of the divisor (2x^(2)) to get the first term of the quotient (2x).
2. Multiply the first term of the quotient (2x) by the divisor (2x^(2)+4x) to get (4x^(3)+8x^(2)).
3. Subtract the result from step 2 (4x^(3)+8x^(2)) from the dividend (4x^(3)+16x^(2)+18x+7) to get the remainder (8x^(2)+18x+7).
4. Repeat steps 1-3 with the new dividend (8x^(2)+18x+7) and the same divisor (2x^(2)+4x) until the degree of the remainder is less than the degree of the divisor.

The final quotient and remainder are as follows:

Quotient: 2x+4
Remainder: 10x+7

So, the final answer is:

(4x^(3)+16x^(2)+18x+7)-:(2x^(2)+4x) = 2x+4+(10x+7)-:(2x^(2)+4x)

In other words, the quotient is 2x+4 and the remainder is 10x+7.

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QMB3200 RVI Spring 2022 Nadia Elhaj Homework: Hw 6 - Sampling and Confidence Question 9, 6.5.30 > HW Score: 46.88%, 7.5 of 16 points X Points: 0 of 1 Save A survey of 50 young professionals found that they spent an average of $23.76 when dining out, with a standard deviation of $13.54. Can you conclude statistically that the population mean is greater than $21? Use a 95% confidence interval. The 95% confidence interval is ___, ____ . As $21 is_____ of the confidence interval, we ___ conclude that the population mean is greater than $21. (Use ascending order. Round to four decimal places )

Answers

The population mean is greater than $21.

The 95% confidence interval is $13.3896, $34.1304. As $21 is outside of the confidence interval, we can conclude that the population mean is greater than $21.

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I needdd help!! pleeeaaseses

Answers

The height of the rectangle is

⇒ Height = 1/2 ft

What is mean by Rectangle?

A rectangle is a 2 - dimension figure with 4 sides, 4 corners and 4 right angles. And, Opposite sides of the rectangle are equal and parallel to each other.

We have to given that;

Length of the rectangle = 5/3 ft

Area of the rectangle = 5/6 ft

We know that;

Area of rectangle = Length x Height

Hence, We get;

5/6 ft = 5/3 ft x Height

5/6 x 3/5 = Height

Height = 1/2 ft

Thus, The height of the rectangle is;

⇒ Height = 1/2 ft

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Determine all values that cause the expression to be undefined. (2z)/((z+1)(z-3))

Answers

The values that cause the expression to be undefined are z = 3 and z = -1.

The expression (2z)/((z+1)(z-3)) is undefined when the denominator is equal to zero. To find all values that cause the expression to be undefined, we need to solve the equation (z+1)(z-3) = 0.

Use the distributive property to expand the equation:
z^2 - 2z - 3 = 0

Use the quadratic formula to solve for z:
z = (-b ± √(b^2 - 4ac))/(2a)
where a = 1, b = -2, and c = -3

Plug in the values and simplify:
z = (-(-2) ± √((-2)^2 - 4(1)(-3)))/(2(1))
z = (2 ± √(4 + 12))/2
z = (2 ± √16)/2
z = (2 ± 4)/2

Solve for the two possible values of z:
z = (2 + 4)/2 = 3
z = (2 - 4)/2 = -1

Therefore, the values that cause the expression to be undefined are z = 3 and z = -1.

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Lines ℓ and m are intersected by transversal t. ℓ ∥ m.


There are two parallel horizontal lines l and m intersected by another line t making angles 1 and 3 with l and 5, 7 with m. 1 ,4 and 2 , 3 are opposite angles at the point of intersection of l and t. 5, 8 and 6, 7 are opposite angles at the point of intersection of m and t.


If m∠3 = 78°, what is m∠6?

Answers

Answer:

m<6 = 78°

Step-by-step explanation:

I hope your drawing of this problem looks somewhat like this:

                                                                ^  t

                                                              /

                                                            /

                                                   1     /    2

<----------------------------------------------------------------------------->   ℓ

                                               3     /    4

                                                    /

                                         5       /    6

<------------------------------------------------------------------------------>  m

                                      7       /   8

                                            /

                                          /

                                        V

Sorry about the terrible drawing, but I hope I got the angle numbers correctly written.

Angles 3 and 6 are are called alternate interior angles.

They are "interior angles" because they are on the inside of lines l and m. They are "alternate angles" because they are on different sides of the transversal, t.

There is a Geometry theorem about this situation.

Theorem:

If parallel lines are cut by a transversal, then alternate interior angles are congruent.

In this case, since the pair of angles 3 and 6 is a pair of alternate interior angles, then by the theorem above, they are congruent.

m<6 = m<3

Since m<3 = 78°, then m<6 = 78°.



Write a function that models each variation.

x=0. 2 and y=3 when z=2 , and z varies jointly with x and y.

Answers

If x and y both increase or decrease by the same factor, then z will also increase or decrease by the same factor, keeping the ratio between the variables constant, the function model used is z = 33.33xy.

When three variables are said to vary jointly, it means that they are related in such a way that if any one of them changes, the other two also change proportionally. To model the joint variation of z with x and y when x=0.2 and y=3, we can use the following function:

z = kxy

where k is a constant of proportionality.

To find the value of k, we can substitute the given values of x, y, and z into the equation:

2 = k(0.2)(3)

Solving for k, we get:

k = 33.33

Therefore, the function that models the joint variation of z with x and y is:

z = 33.33xy

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please help! i’ll give brainly!!

Answers

[tex]-\dfrac{3}{4}x-\dfrac{1}{3}+\dfrac{7}{8}x-\dfrac{1}{2} = -\dfrac{3}{4}x+\dfrac{7}{8}x -\dfrac{1}{3}-\dfrac{1}{2} = \\[/tex]

[tex]= -\dfrac{3(2)}{4(2)}x+\dfrac{7}{8}x -\dfrac{1(2)}{3(2)}-\dfrac{1(3)}{2(3)} = -\dfrac{6}{8}x+\dfrac{7}{8}x -\dfrac{2}{6}-\dfrac{3}{6} \\[/tex]

[tex]= \dfrac{-6+7}{8}x -\dfrac{2+3}{6} = \dfrac{1}{8}x -\dfrac{5}{6} \\[/tex]

Solve the following linear programming problem. Restrict x ≥ 0
and y ≥ 0. Minimize g = 44x + 13y subject to the following. x + y ≥
100 −x + y ≤ 20 −2x + 3y ≥ 30

Answers

The optimal solution for the given linear programming problem is x = 20 and y = 80

The given linear programming problem is:

Minimize g = 44x + 13y

Subject to:  

x + y ≥ 100

-x + y ≤ 20

-2x + 3y ≥ 30

Where x, y ≥ 0

To solve this problem, we need to determine the feasible region for x and y. The first constraint is x + y ≥ 100, which gives the inequality x + y - 100 ≥ 0.

The second constraint is -x + y ≤ 20, which gives the inequality x - y + 20 ≥ 0.

The third constraint is -2x + 3y ≥ 30, which gives the inequality 2x - 3y + 30 ≥ 0. The feasible region for x and y can be represented by the three inequalities x + y - 100 ≥ 0, x - y + 20 ≥ 0 and 2x - 3y + 30 ≥ 0.

To minimize g = 44x + 13y, we need to use the graphical method. First, draw the feasible region. Then, we draw the line corresponding to the objective function g = 44x + 13y. We will be looking for the point where the line intersects the feasible region with the lowest possible value of g. The intersection point is the optimal solution.

In conclusion, the optimal solution for the given linear programming problem is x = 20 and y = 80, with the minimum value of g being g = 44*20 + 13*80 = 3200.

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Sally has $ 190,000 to invest to obtain annual income. She to invest in high-quality, low-risk investments. She invests some of it in Certificates of Deposit yielding a 6% return and the rest in AA bonds yielding 11% returns. How much should she invest in each to earn exactly $18,900 per year?
(a) Define any variables needed as a complete sentence.
(b) Write the equation that gives the total amount invested.
(c) Write the equation that represents the total amount earned from the investment. (Remember: Interest * Investment (or Principle) = Amount Returned)
(d) Solve this system of equations using substitution or elimination
(e) State the solution as a complete sentence in the context of the situation.

Answers

a)CD and AA

b)CD + AA = 190,000

c)0.06CD + 0.11AA = 18,900

d)AA = 187,333.17.

(a) Let CD be the amount invested in Certificates of Deposit and AA be the amount invested in AA bonds.

(b) The total amount invested is given by the equation CD + AA = 190,000.

(c) The total amount earned from the investment is given by the equation 0.06CD + 0.11AA = 18,900.

(d) To solve this system of equations using elimination, we multiply the first equation by 0.11 and the second equation by 0.06 and add the resulting equations together, yielding the equation 12.06CD + 10.11AA = 214,084. We then subtract the original equation from this new equation to get 9.06CD = 24,084. Solving for CD, we get CD = 2,666.83. We can then substitute this value into either of the original equations to get AA = 187,333.17.

(e) Sally should invest $2,666.83 in Certificates of Deposit and $187,333.17 in AA bonds to earn exactly $18,900 per year.

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Find the exact value of each of the remaining trigonometric functions of \( \theta \). Rationalize denominators when applicable. \( \cot \theta=-\frac{\sqrt{3}}{7} \), given that \( \theta \) is in qu

Answers

The exact value of the remaining trigonometric functions of \( \theta \) are \( \sin \theta = \frac{7\sqrt{52}}{52} \), \( \cos \theta = \frac{-\sqrt{3}\sqrt{52}}{52} \), \( \tan \theta = \frac{-7\sqrt{3}}{3} \), \( \sec \theta = \frac{-\sqrt{52}\sqrt{3}}{3} \), and \( \csc \theta = \frac{\sqrt{52}}{7} \).

We can find the exact value of the remaining trigonometric functions of \( \theta \) by using the Pythagorean identity and the definition of the trigonometric functions. The Pythagorean identity states that \( \sin^2 \theta + \cos^2 \theta = 1 \). The definition of the trigonometric functions are \( \sin \theta = \frac{y}{r} \), \( \cos \theta = \frac{x}{r} \), \( \tan \theta = \frac{y}{x} \), \( \cot \theta = \frac{x}{y} \), \( \sec \theta = \frac{r}{x} \), and \( \csc \theta = \frac{r}{y} \).

Given that \( \cot \theta=-\frac{\sqrt{3}}{7} \), we can use the definition of the cotangent function to find the values of x and y. Let x = -\( \sqrt{3} \) and y = 7. Then, we can use the Pythagorean identity to find the value of r.

\( \sin^2 \theta + \cos^2 \theta = 1 \)

\( \frac{y^2}{r^2} + \frac{x^2}{r^2} = 1 \)

\( \frac{7^2}{r^2} + \frac{(-\sqrt{3})^2}{r^2} = 1 \)

\( \frac{49 + 3}{r^2} = 1 \)

\( \frac{52}{r^2} = 1 \)

\( r^2 = 52 \)

\( r = \sqrt{52} \)

Now, we can use the definition of the trigonometric functions to find the exact value of the remaining trigonometric functions of \( \theta \).

\( \sin \theta = \frac{y}{r} = \frac{7}{\sqrt{52}} = \frac{7\sqrt{52}}{52} \)

\( \cos \theta = \frac{x}{r} = \frac{-\sqrt{3}}{\sqrt{52}} = \frac{-\sqrt{3}\sqrt{52}}{52} \)

\( \tan \theta = \frac{y}{x} = \frac{7}{-\sqrt{3}} = \frac{-7\sqrt{3}}{3} \)

\( \sec \theta = \frac{r}{x} = \frac{\sqrt{52}}{-\sqrt{3}} = \frac{-\sqrt{52}\sqrt{3}}{3} \)

\( \csc \theta = \frac{r}{y} = \frac{\sqrt{52}}{7} = \frac{\sqrt{52}}{7} \)

Therefore, the exact value of the remaining trigonometric functions of \( \theta \) are \( \sin \theta = \frac{7\sqrt{52}}{52} \), \( \cos \theta = \frac{-\sqrt{3}\sqrt{52}}{52} \), \( \tan \theta = \frac{-7\sqrt{3}}{3} \), \( \sec \theta = \frac{-\sqrt{52}\sqrt{3}}{3} \), and \( \csc \theta = \frac{\sqrt{52}}{7} \).

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The scatter plot shows the number of hits and home runs for 20 baseball players who had at least 10 hits last season. The table shows the values for 15 of those players.
The model, represented by y=0.15x−1.5, is graphed with a scatter plot.

Use the graph and the table to answer the questions.
Player A had 154 hits in 2015. How many home runs did he have? How many was he predicted to have?
Player B was the player who most outperformed the prediction. How many hits did Player B have last season?
What would you expect to see in the graph for a player who hit many fewer home runs than the model predicted?

Answers

Tο depict the relatiοnship between twο numerical variables using Data visualizatiοn that is knοwn as a scatterplοt.

What is a Scatterplοt?

Using this scatterplοt, we graphed a line using linear regressiοn. This line can use as οur reference pοint and ignοre the rest οf the pοints οn the graph.

We will examine this graph and try tο find apprοximately what value οf y is given when we prοvide an x value.

Since the number οf hits is the x value, tο find hοw high the graph gοes at that x value we can lοοk at the graph tοο.

Right between 100 and 150 is 125, sο we can nοw start there and mοve up.

When we mοve up, we get a line that's between 10 and 20. We can alsο view it's in the tοp half οf that bοx. That means the value οf y fοr this will be mοre than 15.

Since it's nοt lying directly οn 20, we have the οnly οptiοn left is 18.

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For each of the following, find the formula for an exponential
function that passes through the two points given.
a. (0, 6) and (2, 294)
f(x)=
b. (0,1280) and (2, 20)
g(x) =

Answers

The formulas for the exponential functions that pass through the two points given are:
f(x) = 6 * 7^x
g(x) = 1280 * 0.125^x

To find the formula for an exponential function that passes through two points, we can use the general form of an exponential function, which is f(x) = a * b^x, where a and b are constants. We can plug in the x and y values from the two points and solve for a and b.

For part a:
f(x) = a * b^x
6 = a * b^0 (from point (0,6))
294 = a * b^2 (from point (2,294))

From the first equation, we can see that a = 6. We can substitute this value into the second equation:
294 = 6 * b^2
49 = b^2
b = 7

So the formula for the exponential function that passes through the two points is f(x) = 6 * 7^x.

For part b:
g(x) = a * b^x
1280 = a * b^0 (from point (0,1280))
20 = a * b^2 (from point (2,20))

From the first equation, we can see that a = 1280. We can substitute this value into the second equation:
20 = 1280 * b^2
0.015625 = b^2
b = 0.125

So the formula for the exponential function that passes through the two points is g(x) = 1280 * 0.125^x.

In conclusion, the formulas for the exponential functions that pass through the two points given are:
f(x) = 6 * 7^x
g(x) = 1280 * 0.125^x

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ind all solutions of the system of equations algebraically. oordinate points. y=-3x^(2)+12x 3x+y=12

Answers

The given system of equations can be written as: y=-3x^2+12x  3x+y=12

To solve this system, we can use the substitution method. We will solve the first equation for y and substitute this value in the second equation to solve for x. From the first equation, we have y=-3x^2+12x. Substituting this in the second equation, we get 3x+(-3x^2+12x)=12. Simplifying, we get -3x^2+15x=12.

Now, we can solve this equation for x. To do this, we can divide both sides of the equation by -3 to get x^2+5x/3=4/3. Factoring the left side, we get (x+5/3)(x-4/3)=0. From here, we can find the two solutions for x: x=-5/3 and x=4/3. Substituting these values in the first equation, we get the two solutions for y: y=-17/3 and y=20/3. Therefore, the two solutions for the system of equations are (x=-5/3, y=-17/3) and (x=4/3, y=20/3).

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8 Enrique has a container of 32 fl oz of orange juice. He is filling glasses with 1 cup of juice. The point on the graph shows the ratio of fluid ounces to cups. Based on this ratio, how many glasses can Enrique fill from the container? Plot a point on the graph to show the number of cups in 32 fl oz. Show your work

Answers

Using the graph, we can find that Enrique can fill 4 glasses from the container.

What are graphs?

A structured representation of the data is all that the graph is. It assists us in comprehending the info. Data are the numerical details gathered by observation.

Data is a derivative of the Latin term datum, which means "something provided." Data is continuously gathered through observation once a research question has been formulated. After that, it is arranged, condensed, and categorised before being graphically portrayed.

Here,

We can see that the point on the graph suggests that for filling one glass,

8 fl oz of juice is required.

So, let the no. of glasses that will be filled be = x.

Now, x = Total amount of juice/ Amount of juice per glass

= 32/8

= 4 glasses.

Therefore, 4 glasses will be filled from the container.

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The complete question is:

8 Enrique has a container of 32 fl oz of orange juice. He is filling glasses with 1 cup of juice. The point on the graph shows the ratio of fluid ounces to cups. Based on this ratio, how many glasses can Enrique fill from the container? Plot a point on the graph to show the number of cups in 32 fl oz. Show your work.

Please help me with these questions. I could solve others but not these ones

Answers

1) a) ω = 2πf = 2π(50) = 100π radians per second

b) 96.78m/s.

2) (a) T = 1/f = 1/12 seconds,

(b) ω = 2πf = 2π(12) = 24π radians per second.

3) original length of the pendulum is 9.0m.

4)  original length of the spiral spring is 20cm.

5)  the initial velocity of the football is 17.32m/s At the highest

What are the radians per second?

Angular speed is the speed of the object in rotational motion. Distance traveled is represented as θ and is measured in radians. The time taken is measured in terms of seconds. Therefore, the angular speed is articulated in radians per second or rad/s.

1. (a) The angular speed of a body vibrating at 50 cycles per second is:

ω = 2πf = 2π(50) = 100π radians per second

(b) The stone is projected horizontally, so its initial vertical velocity is zero. The time taken for the stone to fall from the top of the tower to the ground is given by:

t = √(2h/g) = √(2×75/10) = √15

The horizontal distance traveled by the stone is:

d = vxt = (25m/s)×(√15) ≈ 96.78m

Therefore, the speed with which the stone strikes the ground is approximately 96.78m/s.

2. (a) The period of the motion is:

T = 1/f = 1/12 seconds

(b) The angular speed of the motion is:

ω = 2πf = 2π(12) = 24π radians per second

(c) The velocity at the middle of oscillation is zero, since this is the point of maximum displacement and therefore maximum potential energy.

(d) The acceleration at the end of oscillation is given by:

a = -ω²x = -(24π)²(0.02) = -11.52 m/s²

where x is the amplitude of the motion.

3. The period of a simple pendulum is given by:

T = 2π√(L/g)

where L is the length of the pendulum and g is the acceleration due to gravity. Therefore, we can write:

17 = 2π√(L/g) (1)

8.5 = 2π√[(L-1.5)/g] (2)

Dividing (2) by (1), we get:

1/2 = √[(L-1.5)/L]

Squaring both sides and simplifying, we get:

L = 9.0m

Therefore, the original length of the pendulum is 9.0m.

4. (a) Let the original length of the spiral spring be x. Then, using Hooke's law, we have:

5N = k(25cm - x) (1)

10N = k(30cm - x) (2)

where k is the spring constant. Solving for k in equation (1), we get:

k = 5N/(25cm - x)

Substituting into equation (2), we get:

10N = [5N/(25cm - x)](30cm - x)

Simplifying and solving for x, we get:

x = 20cm

Therefore, the original length of the spiral spring is 20cm.

(b) The pressure of the trapped air column in the capillary tube is balanced by the pressure of the atmosphere. When the tube is held horizontally, the length of the air column is the same as its length in the vertical position. Therefore, the length of the air column is 15cm.

When the tube is held vertically with the open end underneath, the length of the air column is given by:

L = 76cm - 20cm = 56cm

Therefore, the length of the air column is 56cm.

5. The horizontal and vertical components of the initial velocity of the football are:

v₀x = v₀cos(60°) = (20m/s)cos(60°) = 10m/s

v₀y = v₀sin(60°) = (20m/s)sin(60°) = 17.32m/s

At the highest

Hence, the answer to each question:

1) a) ω = 2πf = 2π(50) = 100π radians per second

b) 96.78m/s.

2) (a) T = 1/f = 1/12 seconds,

(b) ω = 2πf = 2π(12) = 24π radians per second.

3) original length of the pendulum is 9.0m.

4)  original length of the spiral spring is 20cm.

5)  the initial velocity of the football is 17.32m/s At the highest

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Help me Please I beg of you

Answers

Answer:

1st page:

To determine if Jason and Arianna made a mistake in their solution, we can examine the slopes and y-intercepts of the two equations.

The first equation, 5x - 3y = -1, can be written in slope-intercept form as y = (5/3)x + 1/3, where the slope is 5/3 and the y-intercept is 1/3.

The second equation, 3x + 2y = 7, can be written in slope-intercept form as y = (-3/2)x + 7/2, where the slope is -3/2 and the y-intercept is 7/2.

To solve the system of equations, we need to find the point of intersection of the two lines. We can see from the slopes that the lines are not parallel, so they must intersect at some point. However, the slopes are not perpendicular either, so they do not intersect at a right angle.

By graphing the two equations on the same coordinate plane, we can see that the point of intersection is (2, 2), not (4.04, 7.31) as Jason and Arianna calculated. Therefore, they must have made a mistake in their solution.

In summary, we can tell that Jason and Arianna made a mistake in their solution by examining the slopes and y-intercepts of the two equations and graphing them to find the actual point of intersection.

2nd page:

To determine if Jason and Arianna made a mistake in their solution, we can graph the two linear equations on the same coordinate plane and look for the point of intersection.

We can begin by rearranging the equations into slope-intercept form:

5x - 3y = -1 → y = (5/3)x + 1/3

3x + 2y = 7 → y = (-3/2)x + 7/2

Now we can graph the two lines. We can plot two points for each line and connect them with a straight line to obtain the graphs.

For the first equation, when x = 0, we get y = 1/3. When x = 3, we get y = 6/3 = 2. Plotting these two points and connecting them, we get:

Graph of the first equation

For the second equation, when x = 0, we get y = 7/2. When x = 2, we get y = 1/2. Plotting these two points and connecting them, we get:

Graph of the second equation

We can see from the graphs that the lines intersect at the point (2, 2), not at (4.04, 7.31) as Jason and Arianna found. Therefore, they must have made a mistake in their solution.

In summary, we can tell from the graphs of the equations that Jason and Arianna must have made a mistake because the lines do not intersect at the point they found.

3rd page:

We can determine if there is a unique solution to the system of linear equations by examining the slopes of the two equations.

The slope of the first equation, 5x - 3y = -1, can be found by rearranging the equation into slope-intercept form y = (5/3)x + 1/3. We can see that the slope of the line is positive and not equal to the slope of the second equation, which is -3/2.

Similarly, the slope of the second equation, 3x + 2y = 7, can be found by rearranging the equation into slope-intercept form y = (-3/2)x + 7/2. Again, we can see that the slope of the line is negative and not equal to the slope of the first equation, which is 5/3.

Since the slopes of the two lines are not equal, they will intersect at a unique point. In other words, there is only one solution to the system of equations.

Therefore, we can conclude that there is a unique solution to the system of linear equations given by 5x - 3y = -1 and 3x + 2y = 7, based on the slopes of the graphs of the equations in the system.

Step-by-step explanation:

HW6.8. Finding a basis of the orthogonal complement Consider the matrixA=​0100−1​0100−1​0100−1​​Find a basis for the orthogonal complement to the column space ofA. How to enter the solution: To enter your solution, place the entries of each vector inside of brackets, each entry separated by a comma. Then put all these inside brackets, again separated by a comma. Suppose your solutions is​12−10​​,​2301​​. Then please enter[[1,2,−1,0],[2,3,0,1]]Additional attempts available with new variants

Answers

The orthogonal complement of the column space of a matrix A is the set of vectors that are perpendicular to the vectors in the column space. To find a basis for the orthogonal complement of the column space of A, we can use the Gram-Schmidt process.

This process starts with the columns of A, orthogonalizes them, and then adds the orthogonalized vectors to the basis of the orthogonal complement. We can find a basis for the orthogonal complement of the column space of A by performing the Gram-Schmidt process.

The result of this process is [[1,2,-1,0], [2,3,0,1]], which is the basis of the orthogonal complement of the column space of A.

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Find the intersection and union of the given sets. A = {h, o, m, e} , B = {h, o, u, s, e}

Answers

The intersection of sets A and B

The intersection of two sets is the set of elements that are common to both sets. To find the intersection of sets A and B, we simply look for the elements that are in both sets. In this case, the intersection of A and B is {h, o, e}.

The union of two sets is the set of elements that are in either one of the sets or both. To find the union of sets A and B, we simply combine the elements from both sets, making sure to not include any duplicates. In this case, the union of A and B is {h, o, m, e, u, s}.

So, the intersection of sets A and B is {h, o, e} and the union of sets A and B is {h, o, m, e, u, s}.

Here is the solution in HTML:

The intersection of sets A and B is: {h, o, e}
The union of sets A and B is: {h, o, m, e, u, s}

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The polygons are regular.

X = ?

help how do I start this and get the answer to this

Answers

The figure for the given net diagram is square pyramid.

What is a net diagram?

Net diagram is a 2-dimensional plane figure which can be folded to form a 3-dimensional figure. Or we can say net diagrams are the figures which obtained by unfolding some 3D figures.

The given net diagram has a square and 4 triangles.

If we fold all the faces and make a solid figure, we get square pyramid.

Therefore, the figure is square pyramid.

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A widget manufacturer's expense function is
E = 6.00 q + 11,000
What are the variable costs to produce one widget?

Answers

The variable costs to produce one widget is 6.00

How to determine the variable costs

From the question, we have the following parameters that can be used in our computation:

E = 6.00 q + 11,000

The variable cost is the slope of the relation

Using the above as a guide, we have the following:

Fixed cost = 11000

Variable cost = 6.00

The above parameters mean that

The variable cost is 6.00

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find q.
write your answer in simplest radical form

Answers

The required measure of q in the given triangle is 3.

What are trigonometric ratios?

Trigonometric ratios are mathematical functions used to relate the angles of a right-angled triangle to the lengths of its sides. There are three basic trigonometric ratios: sine (sin), cosine (cos), and tangent (tan), which can be defined as follows:

Sine (sin) = opposite/hypotenuse

Cosine (cos) = adjacent/hypotenuse

Tangent (tan) = opposite/adjacent

Here,
Applying the Sine rule,
sin45 = q/3√2
q = 3

Thus, the required measure of q in the given triangle.

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William’s car uses 1 litre of fuel to travel 12km. How much fuel will be needed to travel
420km?

Answers

Answer:

420km/12km = 35

1×35l = 35lites

rate it 5 stars pls TANXX

Answer:

35 litres

Step-by-step explanation:

We can use a ratio to solve.

1 litre               x litres

-------------  = ----------------

12 km             420 km

Using cross products

1 * 420 = 12x

Divide each side by 12.

420/12 = x

35 =x

35 litres

Adriana’s family went to the state fair on a Tuesday night special event. The admission cost for the whole family was $42 and parking was $15. During the special event, all the ride tickets cost $2 each. If the total amount of money they had to spend for the evening was $120, how many tickets could Adriana’s family buy?

The unknown quantity, inequality, and the answer in a complete sentence.

Answers

Let x be the number of ride tickets Adriana's family can buy.

The cost of the admission and parking was $42 + $15 = $57.

The cost of the ride tickets is $2x.

The total amount they can spend for the evening is $120.

So, we can write the inequality:

$57 + $2x ≤ $120

To solve for x, we need to isolate the variable on one side of the inequality:

$2x ≤ $120 - $57
$2x ≤ $63
x ≤ $63 ÷ $2
x ≤ 31.5

Since Adriana's family can't buy a fraction of a ticket, the maximum number of ride tickets they can buy is 31.

Answer: Adriana's family can buy a maximum of 31 ride tickets.

How many liters of water must be evaporated from 10L of a 40% salt solution to produce a 50% solution?

Answers

2L of water must be evaporated from the 10L of 40% salt solution to produce a 50% solution.

To produce a 50% salt solution from a 40% salt solution, we must evaporate some water to increase the concentration of the salt. We can use the formula:

C1V1 = C2V2

Where C1 is the initial concentration, V1 is the initial volume, C2 is the final concentration, and V2 is the final volume.

Plugging in the given values:

0.40(10L) = 0.50(V2)

Simplifying:

4L = 0.50V2

Dividing both sides by 0.50:

V2 = 8L

So the final volume of the solution must be 8L in order to have a 50% concentration of salt. To find the amount of water that must be evaporated, we can subtract the final volume from the initial volume:

10L - 8L = 2L


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Carlos constructed 3 parallel lines as part of an art project. He also drew a line passing through each of the parallel lines. Some of the angles formed by the intersection of line t and lines l, m, and n are numbered in the diagram below.


Which conjecture can Carlos make about the angles formed by line t and lines l, m, and n?
a) Angles 1, 2, and 3 are congruent.
b) Angles 1, 3, and 5 are congruent.
c) Angles 2 and 4 are supplementary.
d) Angles 1 and 5 are supplementary.

Answers

A conjecture which Carlos can make about the angles formed by line t and lines l, m, and n include the following: B. angles 1, 3, and 5 are congruent.

What is corresponding angles postulate?

In Mathematics, corresponding angles postulate simply refers to a theorem which states that corresponding angles are always congruent (equal) if the transversal intersects two parallel lines.

This ultimately implies that, the corresponding angles would always be congruent (equal) if a transversal intersects two (2) parallel lines.

By applying corresponding angles postulate to both lines l, m, and n, we can reasonably infer and logically deduce that the following angles are congruent:

∠1 ≅ ∠3

∠3 ≅ ∠5

∠1 ≅ ∠5

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Give the coordinates of (,)(△) for (,),(,),eh open , 0 comma 4 , close comma b open , 0 comma 2 , close comma and (−,). C open , negative 3 comma 2 , close

Answers

The coordinates of the centroid (,)(△) of triangle ABC are (-1, 8/3).

To find the coordinates of the centroid, we can use the formula:

(x, y) = ((x1 + x2 + x3)/3, (y1 + y2 + y3)/3)

where (x1, y1), (x2, y2), and (x3, y3) are the coordinates of the vertices A, B, and C, respectively.

Plugging in the coordinates of A (0, 4), B (0, 2), and C (-3, 2), we get:

(x, y) = ((0 + 0 - 3)/3, (4 + 2 + 2)/3) = (-1, 8/3)

In a two-dimensional plane, the centroid of a triangle is the point where the three medians of the triangle intersect. A median is a line segment drawn from a vertex of the triangle to the midpoint of the opposite side. The centroid divides each median into two segments, with the ratio of the length of the segment closer to the vertex to the length of the segment closer to the opposite side being 2:1.

In a three-dimensional space, the centroid of a solid can be found by dividing the solid into smaller parts, finding the centroid of each part, and then averaging them. The centroid of a solid is the point where the lines connecting the centroids of each part intersect.

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Complete Question: -

Give the coordinates of the centroid of triangle ABC, which is denoted by (,)(△) and is the point where the medians of the triangle intersect for a (0 , 4) , b (0 ,2) , and C  (-3 ,2 ).

Solve the problem pls

Answers

The distance is 35 units and the average speed is 5 units per min.

How far did the bug run?

To find the distance that the bug ran, we need to take the difference between the final position and the initial position, it gives:

distance = -12 - (-47) = 12 + 47 = 35 units

And the average speed is the quotient between the distance and the time, so:

Average speed = distance/time.

And here we know that.

distance = 35 units.

time=  7 minutes.

Then we can replace these in the formula above to get:

s = (35 units)/7min = 5 units per min.

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