Math step by step answer

Answer: It will take him 6 hours

Step-by-step explanation: 4 lawns = 120 min

                                              1 lawn = 30 min

                                                12 lawn = 360 min = 6 hours

To mow 12 lawns, the student will spend 6 hours.

To predict the time the student will spend mowing 12 lawns, we can use the information given in the question. The student takes 120 minutes to mow 4 lawns. We can calculate the time the student will take to mow 1 lawn by dividing 120 minutes by 4, which equals 30 minutes per lawn. Since the student has 12 lawns to mow, we multiply 30 minutes by 12 to get the total time. The student will spend 360 minutes, or 6 hours, mowing 12 lawns.

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Answer:

21.5 m^2

Step-by-step explanation:

Area of circle A = πr^2 = 3.14(10/2)^2 = 78.5

Area of square A = 10^2 = 100

Area of shaded area: 100 - 78.5 = 21.5 m^2

Answer:

dont understand 14+14=π

a. The percentage of persons (p) who would permit the pressure to increase to its highest point is what we are predicting.

What is the statistics

b.the pressure to build to its highest point (75/264).

c. Sample statistic's value is 0.2835.

d. Estimate's standard error is 0.0255.

e. Its highest level, the 95% confidence interval, is (0.2326, 0.3344).

A subfield of mathematics called statistics is concerned with the gathering, examination, interpretation, presentation, and arrangement of data.

Several disciplines, including business, economics, sociology, psychology, epidemiology, and public health, employ it. Statistic uses a variety of techniques to gather and analyse data to better understand.

(A) The percentage of persons (p) who would permit the pressure to increase to its highest point is what we are predicting.

(b) The sample statistic, given as p, is the percentage of subjects that allowed the pressure to build to its highest point (75/264).

(c) The sample statistic's value is 0.2835.

(d) The estimate's standard error is 0.0255.

(e) For the percentage of people who would permit the pressure to reach its highest level, the 95% confidence interval is (0.2326, 0.3344).

Therefore, Overall, the findings of this study indicate that a significant majority of high school pupils will tolerate pressures up to 300 mmHg without ever complaining about the discomfort. The range of values inside the 95% confidence.

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The problem can be translated into an equation as follows: 8x = (1/3)(x+2)

the answer that represents this situation is: 8x = (1/3)(x+2)

Simplifying the right side of the equation:

8x = (1/3)x + (2/3)

Multiplying both sides of the equation by 3 to eliminate the fraction:

24x = x + 2

Subtracting x from both sides of the equation:

23x = 2

Dividing both sides of the equation by 23:

x = 2/23

Therefore, the answer that represents this situation is:

8x = (1/3)(x+2)

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The projectile will attain a height of 85 feet at approximately 0.775 seconds or 3.225 seconds.

Given that

Velocity = 64 feet per second --- v

Initial height = 45 feet --- h

The height function can be represented as

h(t) = -16t² + vt + h

So, we have

h(t) = -16t² + 64t + 45

where h is the height in feet and t is the time in seconds.

To find when the projectile will attain a height of 85 feet, we need to solve the equation for t

So, we have

-16t² + 64t + 45 = 85

-16t² + 64t - 40 = 0

Using a graphing tool, we have

t = 0.775 and t = 3.225

Therefore, the projectile will attain a height of 85 feet at approximately t = 0.775 seconds or t = 3.225 seconds.

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Answer: 156

Step-by-step explanation:

Annual Salary = $35, 000

Subtract anual salary from 46, 700. ---> 46,700-35,000= 11,700

One sale = $75

To find out how many sales, divide the remaining 11,700 by 75.

11,700/75= 156

156 sales.

The Area οf the shaded pοrtiοn is given by (16 π -32) inch², the cοrrect οptiοn is A.

A circIe is a rοund shaped figure whοse aII pοints Iie in οne pIane and the distance between the center οf the circIe and aII the pοints οn the circIe is cοnstant.

The area οf the shaded pοrtiοn is equaI tο the difference οf the area οf the arc and  Area οf the TriangIe.

Area οf an Arc =(θ /360) × π r²

Area = (90/360) × π × (8)²

Area οf the arc = 16 π in²

Area οf the triangIe = (1/2) × base × height

Area οf the triangIe = (1/2) × 8 × 8 = 32 in²

Area οf the shaded pοrtiοn = (16 π -32) inch²

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Answer:

25 + 5√29

Step-by-step explanation:

(I added a photo below)

First, let's find BC using the Pythagorean theorem (from ∆BCD):

[tex] {bc}^{2} = {25}^{2} + {10}^{2} = 625 + 100 = 725[/tex]

[tex]725 > 0[/tex]

[tex]bc = \sqrt{725} =5 \sqrt{29} [/tex]

Then we see, that AB = 25 + x

So, now we can find AC:

[tex] {ac}^{2} = ({25 - x})^{2} - ({5 \sqrt{29} })^{2} = 625 - 50x + {x}^{2} - 25 \times 29 = 625 - 50x + {x}^{2} - 725 [/tex]

Now we have a quadratic equation:

[tex] {x}^{2} - 50x - 100 = 0[/tex]

[tex]d = {b}^{2} - 4 \times a \times c = ({ - 50})^{2} - 4 \times 1 \times ( - 100) = 2500 + 400 = 2900 > 0[/tex]

[tex]x1 = \frac{ - b - \sqrt{d} }{2a} = \frac{50 - 10 \sqrt{29} }{2} = 25 - 5 \sqrt{29} [/tex]

This is a negative number and we cannot use it, since x has to be a natural number

[tex]x2 = \frac{ - b + \sqrt{d} }{2 a} = \frac{50 + 5 \sqrt{29} }{2} = 25 + 5 \sqrt{29} [/tex]

Thus, the obtained expression for the perimeter of the rectangle in centimeters is found as: P =  2(11v + 5w) cm.

The perimeter of a rectangle is the length measured around the edge of the rectangle. Although a rectangle has two dimensions, its perimeter only has one and is expressed in linear distances like feet or meters.

The perimeter calculation can be used, for instance, to calculate that many ft of brick border are required overall if somehow the rectangle depicts a garden which needs a brick border.

The sum of the lengths of a rectangle's four sides is known as its perimeter.

Rectangle perimeter = 2L + 2W.

Length = (6v+7w)

width = (5v - 2w)

P = 2 (length  + width)

P = 2(6v+7w + 5v - 2w)

On simplifying:

P =  2(11v + 5w)

Thus, the obtained expression for the perimeter of the rectangle in centimeters is found as: P =  2(11v + 5w) cm.

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Compete question:

The width of a rectangle measures (5v - 2w) centimeters, and its length measures (6v+7w) centimeters. Which expression represents the perimeter, in centimeters, of the rectangle?​

(a) f'(7) = 9. The derivative of the function f(x) evaluated at x=7, is 9.

(b) The instantaneous rate of change of y with respect to x at x = 7 is 9.

Given that the tangent line to the graph of y = f(x) at point (7, 56) has the equation y = 9x - 7, we can use the slope-intercept form of the equation of a line to find the slope of the tangent line.

The slope of the tangent line is 9. This is also equal to the derivative of the function f(x) evaluated at x=7, which gives us the answer to part (a).

The instantaneous rate of change of y with respect to x at x = 7 is also given by the derivative of the function at x=7. Therefore, the answer to part (b) is also f'(7) = 9.

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The missing values in the figure are solved to be

angle KLI = 111

angle LIJ = 129 degrees

The missing angles are solved using the inscribed angle theorem and the knowledge of cyclic quadrilateral

arc KLI = 138 degrees = 2 * angle KJI (inscribed angle theorem)

angle KJI = 138 / 2

angle KJI = 69 degrees

angle KLI + angle KJI = 180 degrees (cyclic quadrilateral property)

where angle KJI = 69

angle KLI = 180 - 69

angle KLI = 111 degrees

angle LIJ + angle LKJ = 180 degrees (cyclic quadrilateral property)

angle LKJ = 51 degrees (given)

angle LIJ = 180 - 51

angle LIJ = 129 degrees

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The height of the building is 160 ft

Proportion is an equation that defines that the two given ratios are equivalent to each other. In other words, the proportion states the equality of the two fractions or the ratios.

Types of  proportion :

Direct Proportion

Inverse Proportion

Continued Proportion

Comparing the heights and shadows using ratio proportions

Sam Height = 8 ft

Sam Shadow = 10 ft

Building Height = x ft

Building Shadow = 200 ft

Sam Height/Sam Shadow = Building Height/Building Shadow

AB/BC = PQ/QR

8/10 = x/200

8*200 = 10*x

1600/10 = x

x = 160 ft

The height of the building is 160 ft

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The correct graph is Option D - the bottom left graph.

Given function is f(x)=ceil(x+1)

To plot graph of f(x) in interval of(-3,3) :

ceil(x+1) is ceiling function

The output of ceil(x) is least integer greater than x

for example ceil(5.5)=6

For an interval of (-3,-2):

Take x=(-2.4)

x+1=(-1.4)

y=f(x)=ceil(x+1)=(-1)

Similarly,

For an interval of (-2,-1):

Take x=(-1.4)

x+1=(-0.4)

y=f(x)=ceil(x+1)=(0)

For an interval of (-1,0)

y=f(x)=1

For an interval of (0,1)

y=f(x)=2

For an interval of (1,2)

y=f(x)=3

For an interval of (2,3)

y=f(x)=4

Thus, The correct graph is the bottom left graph.

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Answer:

25/4 quarts of cranberry juice

40/3 quarts of apple juice

25/8 quarts of lemonade

Step-by-step explanation:

just multiply everything by 5

:)

Answer:

[tex]31+4x > 63[/tex]

To reach her fitness goal, she needs to run for more than 8 days.

Step-by-step explanation:

She has already run 31 miles and runs 4 miles per day:

This means that after x days, the distance she will have run is:

[tex]D(x)=31+4x[/tex]

Tammy must run more than 63 miles total to reach her fitness goals.

This means that:

[tex]D(x) > 63[/tex]

[tex]31+4x > 63[/tex]

The inequality is:

[tex]31+4x > 63[/tex]

Solution:

[tex]4x > 32[/tex]

[tex]x > \dfrac{32}{4}[/tex]

[tex]x > 8[/tex]

To reach her fitness goal, she needs to run for more than 8 days.

The revenue is maximized for a value p = 100, and the maximum revenue is:

R =  23,500

We know that the number of items sold for a prize p is:

-2.35p + 470

Then the revenue will be:

R = (-2.35p + 470)*p

So we need to find the value of p that maximizes that quadratic equation, we can see that the maximum will be at the vertex, then let's write:

R = -2.35p² + 470p

The vertex is at:

p = -470/(2*2.35)

p = 100

Finally, the maximum revenue is:

R =  -2.35*100² + 470*100

R = 23,500

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The probability models that represents a probability of winning of 1/6 are given as follows:

A) a fair six-sided number cube.

D) a spinner with 6 equal sections.

E) a bag of 12 black chips and 60 red chips.

A probability is calculated as the division of the desired number of outcomes by the total number of outcomes in the context of a problem/experiment.

For this problem, we want a probability of 1/6 of winning each trial, hence the events are given as follows:

A) a fair six-sided number cube. -> One out of the six numbers is equivalent to winning.

D) a spinner with 6 equal sections. -> One out of the six regions is equivalent to winning.

E) a bag of 12 black chips and 60 red chips. -> 12/(12 + 60) = 12/72 = 1/6.

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Answer:

Step-by-step explanation:

Answer:

-8

Step-by-step explanation:

f(3) = -4(3) + 4 = -12 + 4 = -8

Answer:

Step-by-step explanation:

[tex]\boxed{\sf f(x) = -4x + 4 \;\: when \;\; x=3}[/tex]

For f(x) -4x+4 substitute x with 3:-

[tex]\sf f\left(3\right)\:=\:-4(3)\:+\:4[/tex]

[tex]\sf f\left(3\right)\:=\:-4\times 3\:+\:4[/tex]

[tex]\sf f(3)=-12+4[/tex]

[tex]\sf f(3)=-8[/tex]

Therefore, f(x) = -8.

______________________

Hope this helps!

Solution,

CP for rajan=180 rs

Sp for rajan=(20%+1)×180

=216

Cp for niranjan=216

And, Sp=.8×216

=172.8

Cp for niranjan=172.8

For 5% profit,

Sp for Niranjan=(5%+1)×172.8

=181.44

Hence, for Niranjan to gain 5% profit, he must sell it for 181.44 rs

Answer - 181.44

Explanation - For Rajan,

Cost Price = Rs 180

Profit Percent = 20%

Profit Percent = (S.P - C.P/C.P)*100

20 = (S.P - 180/180) *100

S.P = Rs 216

For Sajan,

C.P = Rs 216

Loss Percent= 20%

Loss = (C.P - S.P/C.P)*100

20 = (216-S.P/216)*100

S.P = Rs 172.8

For Niranjan to Sell Book and get 5% profit,

C.P = Rs 172.8

Profit Percent = (S.P - C.P/C.P)*100

5 = (S.P-172.8/172.8)*100

S.P = 181.44

Answer:

Step-by-step explanation:

16 × 19 = 304

1/2(19×9)=85.5

304-85.5= 218.5

The minor arc in the given diagram as required to be determined is; arc TU and it's measure is; 116°.

The major arc in the given diagram as required to be determined is; arc TVU and it's measure is; 244°.

It follows from the task content that the minor and major arcs are to be named and their measures determined as required.

The minor arc in a circle is usually subtended by an angle less than 180° while the major arc is subtended by an angle greater than 180°.

Ultimately, the minor arc is; arc TU and it's measure is; 116° while the major arc is; arc TVU and it's measure is; 244°.

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Answer:

Step-by-step explanation:

[tex]y=\frac{1}{2} x+2[/tex]

[tex]y=(x-h)^2+k[/tex]

[tex]y=(x+3)^2-2=x^2+6x+7[/tex]

Answer:

-3x+7 < -5

Step-by-step explanation:

Lets set x as the number of hours since the time it was 7 degrees.

This means that the expression 7-3x would represent the temperature after x hours.

To find the inequality that represents when it would be below -5 degrees, we just set this less than -5:

-5 > 7-3x.

If you want, you can also rearrange this to -3x+7 < -5.

Answer:

4 hours

Step-by-step explanation:

Inequality:

[tex]7-3x < -5[/tex]

[tex]7-7-3x < -5-7[/tex]

[tex]-3x < -12[/tex]

[tex]\frac{-3x}{-3} < \frac{-12}{-3}[/tex]

[tex]x > 4[/tex]

Hope this helps

The length of FG is equal to the length of F'G'.

The perimeter of pentagon CDEFG is equal to the perimeter of pentagon C'D'E'F'G.

The properties of a translated shape are the shape and size of the translated shape are the same as that of the original shape. The orientation of the translated shape is the same as that of the original shape. The distance between the corresponding points of the translated shape and the original shape is constant.

The area and perimeter of the translated shape are the same as that of the original shape. The interior angles of the translated shape are the same as that of the original shape. The coordinates of the vertices of the translated shape are obtained by adding a constant value to the corresponding coordinates of the vertices of the original shape.

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Image transcribed:

Pentagon CDEFG is translated 7 units up and 5 units left, resulting in pentagon C'D'E'F'G' (not shown).

Part A

Select from the drop-down menu to correctly complete this sentence:

The length of FG is ___ the length of  F'G'.

Part B

The perimeter of pentagon CDEFG is ____ the perimeter of pentagon C'D'EF'G.