Math is not my thing helpppppppppppppppppp

Kevin's assertion is untrue. The perimeter of two rectangles can be the same although their lengths and widths differ.

The area of a planar figure is the space enclosed by its perimeter. An enclosed figure's area is the total number of unit squares that completely encircle its surface. Cm2 and m2 are two square measures. Only two dimensions are available for measuring a shape's area.

Kevin's claim is incorrect. Two rectangles can have the same perimeter but different lengths and widths.

For example, consider two rectangles with perimeters of 26 meters:

Rectangle A: Length = 8 meters, Width = 5 meters

Rectangle B: Length = 9 meters, Width = 4 meters

Both rectangles have a perimeter of 26 meters (8+5+8+5=26 and 9+4+9+4=26), but they have different lengths and widths.

Kevin's claim is not true in general.

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Answer:

We can start by using the slope formula to find the equation of the line:

slope = (change in y) / (change in x)

We know the slope is 4, so we can plug in the coordinates (-10, 15) and (x/2, 7) to solve for x:

4 = (15 - 7) / (-10 - x/2)

Multiplying both sides by (-10 - x/2) gives:

-40 - 2x = 8

Solving for x, we get:

x = -24

Therefore, the missing x-value for the coordinate point is -24.

Step-by-step explanation:

Cοrmac cοuld use 1/3 cup οf milk and 1 1/2 cups οf water, a mixture with a tοtal οf 1 5/6 cups, where the amοunt οf milk is less than 1/2 the amοunt οf water, represented by the sοlutiοn pοint (1/3, 1 1/2) tο the system οf inequalities x + y <= 2 and x < 1/2 * y.

An inequality is a mathematical statement that cοmpares twο values, expressing the relatiοnship between them using οne οf several symbοls, such as "<" (less than), ">" (greater than), "<=" (less than οr equal tο), ">=" (greater than οr equal tο), οr "!=" (nοt equal tο).

The pοint (1/3, 1 1/2) is a sοlutiοn tο Cοrmac's system οf inequalities, which means that it satisfies bοth inequalities. In this case, the inequalities are:

x + y <= 2

x < 1/2 * y

If we plug in x = 1/3 and y = 1 1/2, we can check if it satisfies bοth inequalities:

1/3 + 1 1/2 = 2 (satisfies x + y <= 2)

1/3 < 1/2 * (1 1/2) (satisfies x < 1/2 * y)

Therefοre, the sοlutiοn is (1/3, 1 1/2) since it satisfies bοth inequalities.

Sο, the statement that explains what the pοint (1/3, 1 1/2) represents is:

Cοrmac cοuld use 1/3 cup οf milk and 1 1/2 cups οf water, a mixture with a tοtal οf 1 5/6 cups, where the amοunt οf milk is less than 1/2 the amοunt οf water.

Hence, Cοrmac cοuld use 1/3 cup οf milk and 1 1/2 cups οf water, a mixture with a tοtal οf 1 5/6 cups, where the amοunt οf milk is less than 1/2 the amοunt οf water, represented by the sοlutiοn pοint (1/3, 1 1/2) tο the system οf inequalities x + y <= 2 and x < 1/2 * y.

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The sum of two exponentials is given by:

A e^(jφ) + B e^(jψ) = (Acosφ + Bcosψ) + j(Asinφ + Bsinψ)

Applying this formula to the given problem:

[tex]33.65 e^{j(377t-25.5)} + 31.39 e^{j(377t+172.8)}[/tex]

[tex]= (33.65cos(377t-25.5) + 31.39cos(377t+172.8)) + j(33.65sin(377t-25.5) + 31.39sin(377t+172.8))[/tex]

This is the final answer, expressed in rectangular form with real and imaginary parts.

In words, the sum of the two exponentials is a complex number with a real part equal to the sum of the cosines of the two phases and an imaginary part equal to the sum of the sines of the two phases. The phase angle of the resulting complex number is determined by the weighted sum of the two original phase angles.

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Answer:

Step-by-step explanation:

its is 192 ft2

The difference from part (b) is that Beth has a much higher initial wealth, so the negative expected value of the gamble has a smaller impact on her overall utility.

This is not a fair gamble because the expected value of the gamble is negative. The expected value of a gamble is calculated by multiplying the probability of each outcome by the value of that outcome and summing the results. In this case, the expected value is 0.4(-$100) = -$40. Since the expected value is negative, the gamble is not fair.

Anh will not join this gamble because her expected utility from the gamble is lower than her utility from her initial wealth. Her expected utility from the gamble is

0.4u(-$100) = 0.4v(-$100) = -40v.

Her utility from her initial wealth is

u($100) = v($100) = 100v.

Since -40v < 100v, her expected utility from the gamble is lower than her utility from her initial wealth, so she will not join the gamble.

Chris will not join this gamble because his expected utility from the gamble is lower than his utility from his initial wealth. His expected utility from the gamble is

0.4u(-$100) = 0.4e^(-100c) = -40e^(-100c).

His utility from his initial wealth is

u($0) = e^(0c) = 1.

Since -40e^(-100c) < 1, his expected utility from the gamble is lower than his utility from his initial wealth, so he will not join the gamble.

Beth will not join this gamble because her expected utility from the gamble is lower than her utility from her initial wealth. Her expected utility from the gamble is

0.4u(-$100) = 0.4v(-$100) = -40v.

Her utility from her initial wealth is

u($10000) = v($10000) = 10000v.

Since -40v < 10000v, her expected utility from the gamble is lower than her utility from her initial wealth, so she will not join the gamble.

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The coordinate of P is ( 14/5, 23/5, 28/5)

For the line AB, the direction vectors are

l= 2-1= 1, m=3-1= 2 and n= 4-2= 2

so, the equation of the line AB can be given by

[tex]  \text{$\frac{x-1}{1}$ = $\frac{y-1}{2}$ = $\frac{z-2}{2}$ } [/tex]

let a point be P (x,y,z). lying on the line AB.

coordinate of the general point in AB can be given by

[tex]  \text{$\frac{x-1}{1}$ = $\frac{y-1}{2}$ = $\frac{z-2}{2}$ = t } [/tex]

so, x= t+1, y= 2t+1, z= 2t+2

so, P (x,y,z) can be P (t+1, 2t+1, 2t+2). Another point is C ( 4, 2, 2 ).

the direction ratios of the line CP is

l1= t+1-4 = t-3

m1= 2t+1-2 = 2t-1

n1 = 2t+2-2 = 2t

Dot product of the direction ratios of two orthogonal lines are 0.

so, 1(t-3)+2(2t-1)+2(2t)=0

or, t=9/5

so, x= (9/5)+1 = 14/5

     y= (9/5)*2 + 1= 23/5

     z= (9/5)*2 + 2 = 28/5

so, the coordinate of P is ( 14/5, 23/5, 28/5).

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13. The reasonable domain for the function V(w) = (60-4w)w^2 is when the volume is greater than 0.

14. The graph will look like a parabola with a maximum point at w = 7.5.

15.The coordinates of the maximum point are (7.5, 506.25).
16. The width of the box that produces the maximum volume is 7.5 inches, as found in the previous question.

17. a. The expression for the height of the tube in terms of the radius is h = 60 - 2r.

This means that the values of w must be between 0 and 15, since the volume becomes negative when w is greater than 15. Therefore, the domain can be expressed as an inequality as 0 < w < 15, in interval notation as (0, 15), and in set notation as {w | 0 < w < 15}.

14. To sketch a graph of the function V(w) = (60-4w)w^2 over the domain (0, 15), we can plot points at different values of w and connect them with a smooth curve. The scale on each axis can be 1 unit per grid line.

15. Using a graphing calculator, we can find the coordinates of the maximum point of the function V(w) = (60-4w)w^2 by using the maximum function.

b. The expression for the volume of the tube in terms of the radius is V = πr^2h = πr^2(60 - 2r).

c. To find the radius that produces the maximum volume, we can take the derivative of the volume function and set it equal to 0. This gives us 2πr(60 - 4r) = 0. Solving for r, we get r = 7.5 cm.

d. The maximum volume of the tube is V = π(7.5)^2(60 - 2(7.5)) = 1265.49 cm^3.

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The 12th term of the geometric sequence 2, -12, 8, ... is -111,974,400.

A geometric progression is a sequence of numbers in which each term after the first is found by multiplying the preceding term by a fixed number, called the common ratio.

To find the 12th term of the geometric sequence, we need to use the formula:

[tex]an = a1 * r^{(n-1)[/tex]

where:

an = the nth term

a1 = the first term

r = the common ratio

We can see that the common ratio is -6, since:

-12/2 = 8/-12 = -6

So, we have:

[tex]a12 = 2 * (-6)^{(12-1)[/tex]

[tex]a12 = 2 * (-6)^{11}[/tex]

a12 = -111,974,400

Therefore, the 12th term of the geometric sequence 2, -12, 8, ... is -111,974,400.

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The point of maximum growth rate is approximately (1.76, f'(1.76)) or (5.54, f'(5.54)) so the answer is (C) (5.54, 9).

What is the rate?

In mathematics, the rate is a measure of the change in one quantity with respect to another quantity. It is typically expressed as a ratio between the two quantities.

To find the point of maximum growth rate, we need to find the maximum value of the derivative of the function f(x).

First, we need to find the derivative of f(x):

[tex]f'(x) = (20 * 27e^{(-3x)}) / (1 + 9e^{(-3x)})^2[/tex]

To find the maximum value of f'(x), we set f''(x) = 0, where f''(x) is the second derivative of f(x):

[tex]f''(x) = (20 * 81e^{(-6x)} * (81e^{(-6x)} - 18e^{(-3x)} + 1)) / (1 + 9e^{(-3x)})^3[/tex]

Solving f''(x) = 0, we get:

[tex]81e^{(-6x)} - 18e^{(-3x)} + 1 = 0[/tex]

Letting [tex]y = e^{(-3x)}[/tex], we can rewrite the equation as:

81y² - 18y + 1 = 0

Using the quadratic formula, we get:

y = (18 ± √(18² - 4 * 81)) / (2 * 81) = 0.069 or 0.012

So,  [tex]y = e^{(-3x)}[/tex] = 0.069 or 0.012

Solving for x, we get:

x = ln(0.069) / (-3) ≈ 1.76 or x = ln(0.012) / (-3) ≈ 5.54

Therefore, the point of maximum growth rate is approximately (1.76, f'(1.76)) or (5.54, f'(5.54)).

Now we need to calculate f'(1.76) and f'(5.54) to find the answer.

[tex]f'(1.76) = (20 * 27e^{(-5.28)}) / (1 + 9e^{(-5.28)})^2 = 9.62[/tex]

[tex]f'(5.54) = (20 * 27e^{(-16.62)}) / (1 + 9e^{(-16.62)})^2 = 1.01[/tex]

Rounding these values to the nearest hundredth, we get:

(1.76, 9.62) and (5.54, 1.01)

Therefore, the point of maximum growth rate is approximately (1.76, f'(1.76)) or (5.54, f'(5.54)) so the answer is (C) (5.54, 9).

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Answer:

Step-by-step explanation:

i dk

As a result, the balance in the account at the end of seven years is, to the closest cent, $116177.20.

The term "amount" in mathematics typically denotes a sum, total, or quantity. It could be a numerical value or some other kind of measurement. Depending on the context, the word "amount" may also be used to refer to quantity, total, sum, volume, or magnitude. \

The term "amount" is used in algebra and calculus to describe the outcome of an operation, such as the amount of change in a function or the quantity of a variable needed to satisfy an equation. In many disciplines, including finance, science, and engineering, the word "amount" is frequently used to refer to quantities or measurements.

given

The amount of money in the account after 7 years can be calculated using the formula V = Pe(rt), where V is the value of a account in t years, P is the principal implementation, e is the base of a natural log, and r is the rate of interest:

V = P*e(rt) = 67700*e(0.077*7)

[tex]V = 67700 * e^{(0.539) (0.539)[/tex]

V = 67700 * 1.716

V = 116177.20

As a result, the balance in the account at the end of seven years is, to the closest cent, $116177.20.

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The dealer bought the car, which he sold to a man and made a profit of 15 percent at $209,000.

To compute the dealer's purchase price, we use backward calculations and percentages.

First, the man's purchase price is determined as $240,350 since he incurred a loss of 50% amounting to $120,175.

By equating the proportional loss to the selling price, we can determine the purchase price paid by the man as $240,350.

Since the dealer generated a profit of 15% on $240,350, we determine his cost as $209,000 based on the profit percentage.

The dealer's profit percentage = 15%

The man's loss percentage = 50%

The selling price by the man to the woman = $120,175

The purchase price by the man = $240,350 ($120,175/50%)

The dealer's purchase price = $209,000 ($240,350/1.15)

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The vertex of the function is (2 , -5), the axis of symmetry is x = 2, and the intercepts are (2 + √(5) , 0), (2 - √(5) , 0), and (0 , -1).

To find the vertex, axis of symmetry, and intercepts of the function f(x) = x² - 4x - 1, we can use the following formulas:

Vertex: (-b/2a, f(-b/2a))

Axis of symmetry: x = -b/2a

Intercepts:

x-intercept: set f(x) = 0 and solve for x

y-intercept: set x = 0 and solve for y

Using these formulas, we can find the vertex, axis of symmetry, and intercepts of the function:

f(x) = x² - 4x - 1

a = 1, b = -4, c = -1

Vertex: (-b/2a , f(-b/2a)) = (-(-4)/(2)(1) , f(-(-4)/(2)(1))) = (2 , f(2)) = (2 , (2)² - 4(2) - 1) = (2 , -5)

Axis of symmetry: x = -b/2a = -(-4)/(2)(1) = 2

Intercepts:

x-intercept: 0 = x² - 4x - 1

use the quadratic formula to solve for x: x = (-b ± √(b² - 4ac))/(2a) = (-(-4) ± √((-4)² - 4(1)(-1)))/(2(1)) = (4 ± √(20))/2 = (4 ± 2√(5))/2 = 2 ± √(5)

so the x-intercepts are (2 + √(5) , 0) and (2 - √(5) , 0)

y-intercept: f(0) = (0)² - 4(0) - 1 = -1; so the y-intercept is (0 , -1)

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Instead of regular six-sided dice, some games use dodecahedronal - or 12-sided - dice. If you rolled a pair of dodecahedronal dice (each label 1 through 12) 100 times, you would expect the values on the two dice to add up to 4about 3 times. The correct answer is c) 3.


When rolling two dodecahedronal dice, there are a total of 12 x 12 = 144 possible outcomes. To find the probability of rolling a sum of 4, we need to look at the possible combinations that can result in a sum of 4:

1 + 3

2 + 2

3 + 1

There are a total of 3 possible combinations that can result in a sum of 4. Therefore, the probability of rolling a sum of 4 is 3/144 = 1/48.


If we roll the dice 100 times, we would expect to get a sum of 4 about (1/48) x 100 = 2.08333 times. Since we can't roll a fraction of a time, we can round this to the nearest whole number, which is 3. So, we would expect to roll a sum of 4 about 3 times out of 100 rolls.The correct answer is c) 3.

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Answer:

There are 500 total people. 215 gave blood and 159 helped set up, giving a total of 374. However, since 89 people did both, we counted those 89 people twice. So we subtract 89 to get 285 total volunteers.

500-285=215 did not volunteer

There were 220 people that neither donated nor helped.

To find out how many people neither donated nor helped, we can use the formula for the union of two sets:

  A∪B = A + B - A∩B.

In this case, A is the number of people who donated, B is the number of people who helped, and A∩B is the number of people who both donated and helped.

Plugging in the given values, we get:

  A∪B = 217 + 156 - 93 = 280

This tells us that there were 280 people who either donated or helped. To find out how many people neither donated nor helped, we can subtract this number from the total number of people surveyed:

  500 - 280 = 220

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The number of bacteria or the number of all the other animals in the table put together is 7.8 x 10⁶.

To compare the number of bacteria to the number of all other animals in the world, we need to use some mathematical estimates. It's important to note that it's almost impossible to count the exact number of bacteria and animals in the world since they are found in vast numbers and diverse environments.

According to some scientific estimates, the number of bacteria on Earth is around 5 x 10³⁰, which is a massive number. In comparison, the total number of all other animals, including insects, birds, and mammals, is estimated to be around 7.8 x 10⁶.

In conclusion, the number of bacteria is much greater than the number of all other animals in the world. Although bacteria are tiny microorganisms, they are present in vast numbers and can be found in almost every environment.

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Taking the given functions, we will obtain the following inverse functions

To find the inverse of each function, we need to switch the x and y values and solve for y. This will give us the inverse function.

1) [tex]y = log5 (4x + 1)[/tex]
Switch x and y:
[tex]x = log5 (4y + 1)[/tex]
Solve for y:
[tex]5^x = 4y + 1\\4y = 5^x - 1\\y = (5^x - 1)/4[/tex]
Inverse function:

2) [tex]y = log3 (2^x + 8)[/tex]
Switch x and y:
[tex]x = log3 (2^y + 8)[/tex]
Solve for y:
[tex]3^x = 2^y + 8\\2^y = 3^x - 8\\y = log2 (3^x - 8)[/tex]
Inverse function: [tex]f^-1(x) = log2 (3^x - 8)[/tex]

3) [tex]y = log4 (-2x + 9)[/tex]
Switch x and y:
[tex]x = log4 (-2y + 9)[/tex]
Solve for y:
[tex]4^x = -2y + 9\\-2y = 4^x - 9\\y = (9 - 4^x)/2[/tex]
Inverse function: [tex]f^-1(x) = (9 - 4^x)/2[/tex]

4) [tex]y = 5^x + 9/2[/tex]
Switch x and y:
[tex]x = 5^y + 9/2[/tex]
Solve for y:
[tex]5^y = x - 9/2\\y = log5 (x - 9/2)[/tex]
Inverse function: [tex]f^-1(x) = log5 (x - 9/2)[/tex]

5) [tex]y = 10^x + 3/ -3[/tex]
Switch x and y:
[tex]x = 10^y + 3/ -3[/tex]
Solve for y:
[tex]10^y = x - 3/ -3\\y = log10 (x - 3/ -3)[/tex]
Inverse function: [tex]f^-1(x) = log10 (x - 3/ -3)[/tex]

6) [tex]y = log5 (-4x + 10)[/tex]
Switch x and y:
[tex]x = log5 (-4y + 10)[/tex]
Solve for y:
[tex]5^x = -4y + 10-4y = 5^x - 10y = (10 - 5^x)/4[/tex]
Inverse function: [tex]f^-1(x) = (10 - 5^x)/4[/tex]

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x1 = 0.75, x2 = 5, x3 = 0, x4 = 12

To transform the augmented coefficient matrix to echelon form using elementary row operations:

1. Subtract twice the first row from the second row.

2. Subtract the first row from the third row.

3. Subtract the first row from the fourth row.

4. Subtract the third row from the fourth row.

The resulting augmented coefficient matrix in echelon form is:

4x1 - 2x2 - 3x3 + x4 = 3

0x1 - 4x2 - 8x3 = -16

0x1 + x2 + 2x3 + x4 = 17

0x1 + 0x2 + x3 + x4 = 12

To solve the system by back substitution:

1. x4 = 12 (from the last equation)

2. x3 = 12 - x4 = 0 (substitute x4 from step 1 into the third equation)

3. x2 = (17 - x4) / (1) = 5 (substitute x4 from step 1 into the second equation)

4. x1 = (3 - 2*5 - 3*0) / (4) = 0.75 (substitute x2 and x3 from steps 2 and 3 into the first equation)

The solution is x1 = 0.75, x2 = 5, x3 = 0, x4 = 12.

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14) all triangles add up to 180 degrees.

for example: c - 40 + 40 = 80; 180-80 = 100

16)

a. EF

b. E

c. A

Mmaximum number of apples produced per year is 98000 when 70 apple trees are planted in the farm.

To find the maximum number of apples per year, we need to find the vertex of the quadratic equation y=-20x^(2)+2800x. The x-coordinate of the vertex can be found using the formula x=-b/(2a), where a=-20 and b=2800.

Plugging in the values for a and b, we get:
x=-2800/(2*-20)
x=-2800/(-40)
x=70

So, the maximum number of apples per year will be produced when 70 apple trees are planted in the farm. We can find the y-coordinate of the vertex by plugging x=70 back into the equation:

y=-20(70)^(2)+2800(70)
y=-20(4900)+196000
y=-98000+196000
y=98000

Therefore, the maximum number of apples produced per year is 98000 when 70 apple trees are planted in the farm.

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Answer: AD/DB = {AB/BD} = {DA/DB}

AD/AB = {DB/AB} = {DA/DB}

DB/AB = {AD/AB} = {BD/DA}

Assuming this is a simple interest situation:

The 8.75% account will earn (0.0875)(5000) each year.
     $437.5 earned per year

The 9.5 % account will earn (0.095)(7000) each year

     $665 earned per year

Together, these accounts earn $1102.5 per year.

If x is the number of years until the desired interest is earned, then you need to solve 1102.5x = 8820.  Dividing by 1102.5 on both sides, you find x=8.

Again, assuming this is simple interest and not compound interest, it will take 8 years.

Answer:

To find f(-2), we substitute -2 for x in the expression for f(x) and simplify:

f(x) = x³ - 3x

f(-2) = (-2)³ - 3(-2)

f(-2) = -8 + 6

f(-2) = -2

Therefore, f(-2) = -2.

Step-by-step explanation:

2023

In the following question, Starting time: 9:55 A. M. Elapsed time: 27 minutes provide a snapshot of a specific moment in time and the amount of time that has passed since a particular event or task began.

You have provided two pieces of information: the starting time and the elapsed time.

The starting time is 9:55 A.M., which means that an event or task began at that time. The time is given in the 12-hour clock format, where A.M. stands for "ante meridiem" and refers to the period between midnight and noon.

The elapsed time is 27 minutes, which means that 27 minutes have passed since the event or task started. "Elapsed time" refers to the amount of time that has passed since the start of an event or task.

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The fully factored form of 8v - 6vw + 4 - 3w is (2v + 1)(4 - 3w).

From the question, we have the following parameters that can be used in our computation:

8v - 6vw + 4 - 3w​

To factor by grouping, we'll group the first two terms and the last two terms:

(8v - 6vw) + (4 - 3w)

Next, we'll factor out the greatest common factor (GCF) from each group:

2v(4 - 3w) + 1(4 - 3w)

Notice that both groups now have a common factor of (4 - 3w), which we can factor out:

(2v + 1)(4 - 3w)

Hence, the factored expression is (2v + 1)(4 - 3w)

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The each of two individuals will get 54 and 27 sweets according to provided ratio.

Let us assume the amount of sweets each get be 2x and x. Now we know the sum is 81, so representing the information in equation form.

2x + x = 81

Performing addition on Left Hand Side of the equation

3x = 81

Rewriting the equation

x = 81/3

Performing division on Right Hand Side of the equation

x = 27

So, first person will get amount of sweets = 2×27

First person = 54

Amount of sweets for second person = 27

Thus, each will get 54 and 27 sweets.

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We have proven that in given triangle ∠BACB is congruent to ∠DECD, as required.

Similarity of triangles refers to the property of having the same shape but not necessarily the same size. Two triangles are similar if their corresponding angles are congruent and their corresponding sides are proportional.

To prove: ∠BACB = ∠DECD

We know that, BD ∥ AE and C is the midpoint of AE.

Therefore, triangle ACE and triangle BCD are similar by the Converse of the Corresponding Angles Postulate. Hence, we have:

∠CAB = ∠CBD .... (1) (corresponding angles)

∠CAE = ∠CDB .... (2) (corresponding angles)

Also, we know that in triangle ACE, angles 3 and 4 are alternate interior angles formed by a transversal. Therefore, angles 3 and 4 are congruent. Similarly, in triangle BCD, angles 1 and 2 are congruent.

Therefore, we can write:

∠ACB = ∠BCD .... (3) (angles of similar triangles)

Adding equations (1) and (3), we get:

∠BACB = ∠DECD

Hence, we have proven that ∠BACB is congruent to ∠DECD, as required.

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Maximum [184] Angles that this occurs [π/32 + nπ/4]
Minimum [116] Angles that this occurs [π/32 + (2n+1)π/8]

The maximum and minimum values of a trig function can be found by using the amplitude and the vertical shift of the function. The amplitude of the function is the absolute value of the coefficient of the cosine function, which is |-34| = 34. The vertical shift of the function is the constant term, which is 150. Therefore, the maximum value of the function is 34 + 150 = 184 and the minimum value of the function is 150 - 34 = 116.

To find an angle in the interval [0, π/4) where the maximum value occurs, we can use the fact that the cosine function has a maximum value of 1 when the angle is 0. Therefore, we can set the argument of the cosine function, 8x - π/4, equal to 0 and solve for x:

8x - π/4 = 0
8x = π/4
x = π/32

Since π/32 is in the interval [0, π/4), this is one of the angles where the maximum value occurs.

Therefore, the maximum value of the function is 184 and it occurs at angles x = π/32 + nπ/4, where n is an integer. The minimum value of the function is 116 and it occurs at angles x = π/32 + (2n+1)π/8, where n is an integer.

Maximum [184] Angles that this occurs [π/32 + nπ/4]
Minimum [116] Angles that this occurs [π/32 + (2n+1)π/8]

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