Maryam scored 86. 7% on a test with 30 questions on


it. How many questions did Maryam get wrong?


Help!

The number of students who took the test on Monday is found to be 15, hence the correct option is B.

Let us assume that the number of student taking test on Monday is n. The total score for Monday's test is n times the average score of 80.4,

Monday's total score = 80.4n

When the student who missed the test on Monday took the test on Tuesday and scored 90, the total score became,

Total score = 80.4n + 90

The new average score of 81 can be expressed as,

81 = Total score / (n+1)

Substituting the value of the total score, we get,

81 = (80.4n + 90)/(n+1)

Multiplying both sides by n+1, we get,

81(n+1) = 80.4n + 90

Expanding the brackets,

81n + 81 = 80.4n + 90

Simplifying,

0.6n = 9

n = 15, so, the number of students who took the test on Monday is 15.

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Answer: f(t) = 2.4t - 500

Step-by-step explanation:

So first of all, we need how much she actually profits from each taco. She charges $3.25 per taco, but we cannot forget that it is not free to make a taco in the first place. It costs her $0.85 to make a taco. This means we have to subtract the 85 cents from the 3 dollars 25 cents, which means it ends up being $2.40, or as the answer choices have it, 2.4.

So now we know what the number of tacos is being multiplied by: 2.4.

2.4t is now the profit per taco multiplied by the number of tacos.

But we're not quite done yet.

She has a fixed expense of $500 a month, which means this has to be subtracted from her taco profits to find her true profit.

Putting all of this together, we get f(t)=2.4t - 500.

(t)= (profit per taco)(amount of tacos sold) - (fixed expenses)

The expression of linear inequalities that represents Tami's earnings is as follows: 6x + 12y ≥ 150.

A linear inequality is a mathematical expression that involves a linear function and a relational operator such as <, >, ≤, ≥, or ≠ and it can be used to compare two expressions or values. It defines a range of values that satisfy inequality.

For the scenario painted above, we see that Tani is meant to earn a minimum of $150 Thus, the greater than or equal to symbol  ≥ should be used for the expression. $6 per hour and $12 per hour are also well represented in the equation.

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Answer:

8.5y

Step-by-step explanation:

you add what's in the parentheses, 0.5+8, it's 8.5

You then do 8.5*y, and you get

8.5y

1 x 10⁻⁹ expresses a very small number i.e. nanosecond using a negative power of 10. The correct answer is option b).

Computer calculation speeds are incredibly fast, and they are usually measured in very small units of time. One of these units is a nanosecond, which is equal to one billionth of a second, or 0.000000001 seconds. This unit is used to measure the time it takes for a computer to perform basic operations such as adding two numbers or accessing data from memory.

To express 0.000000001 in scientific notation using a negative power of 10, we need to determine the number of decimal places to the right of the decimal point until we reach the first non-zero digit. In this case, we count nine decimal places to the right of the decimal point before we reach the first non-zero digit, which is 1. This means that 0.000000001 can be written as 1 x 10⁻⁹.

In scientific notation, any number can be expressed as the product of a number between 1 and 10, and a power of 10. The power of 10 tells us how many places we need to move the decimal point to the left or right to express the number in standard form. In the case of 0.000000001, we need to move the decimal point nine places to the right to express the number in standard form.

By writing this number in scientific notation as 1 x 10⁻⁹, we can easily perform calculations with it and compare it to other values measured in nanoseconds. Hence option b) is the correct option.

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To compute the direct labor rate and efficiency variances, we will use the given terms: Actual Hours (AH), Standard Hours (SH), Actual Rate (AR), and Standard Rate (SR). Here's a step-by-step explanation:

Step 1: Calculate the Actual Labor Cost
Actual Labor Cost = AH * AR

Step 2: Calculate the Standard Labor Cost
Standard Labor Cost = SH * SR

Step 3: Calculate the Labor Rate Variance
Labor Rate Variance = (AR - SR) * AH

Step 4: Classify the Labor Rate Variance
If the Labor Rate Variance is positive, it is unfavorable. If it is negative, it is favorable. If it is zero, there is no variance.

Step 5: Calculate the Standard Labor Cost for Actual Hours
Standard Labor Cost for Actual Hours = AH * SR

Step 6: Calculate the Labor Efficiency Variance
Labor Efficiency Variance = (AH - SH) * SR

Step 7: Classify the Labor Efficiency Variance
If the Labor Efficiency Variance is positive, it is unfavorable. If it is negative, it is favorable. If it is zero, there is no variance.

By following these steps, you can compute the direct labor rate and efficiency variances for the period and classify each as favorable, unfavorable, or no variance.

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The divergence of the vector field div((2[tex]x^2[/tex]L - sin(xz)) i + 5j - (sin(xz)) k) at all points where it is defined is: div(F) = 4x - z*cos(xz) - x*cos(xz).

To find the divergence of the given vector field, we need to apply the divergence operator to the vector field.

The divergence operator is given by the following formula:
div(F) = ∂Fx/∂x + ∂Fy/∂y + ∂Fz/∂z
Where F = (Fx, Fy, Fz) is the vector field.
Let's apply this formula to the given vector field:
F = (2[tex]x^2[/tex] - sin(xz)) i + 5j - (sin(xz)) k
div(F) = ∂Fx/∂x + ∂Fy/∂y + ∂Fz/∂z
      = (4x - zcos(xz)) + 0 + (-xcos(xz))
Therefore, the divergence of the given vector field is:
div(F) = 4x - zcos(xz) - xcos(xz)
This expression gives the divergence of the vector field at all points where it is defined.
In this case, the vector field is defined for all values of x, y, and z, so the divergence is defined for all points in space.
It is worth noting that the divergence of a vector field represents the rate at which the vector field flows out of a small volume of space surrounding a point.

If the divergence is positive, the vector field is flowing out of the volume; if it is negative, the vector field is flowing into the volume and if it is zero, the vector field is not flowing into or out of the volume.

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The divergence of the given vector field is div(F) = 4x - z × cos(xz) - x × cos(xz).

To find the divergence of the given vector field div( (2[tex]x^2[/tex] - sin(xz)) i + 5j - (sin(xz)) k), follow these steps:

Identify the components of the vector field:

F(x, y, z) = (2[tex]x^2[/tex]- sin(xz), 5, -sin(xz))

Compute the partial derivatives with respect to each variable:

∂F1/∂x = ∂(2[tex]x^2[/tex] - sin(xz))/∂x

∂F2/∂y = ∂(5)/∂y

∂F3/∂z = ∂(-sin(xz))/∂z

Calculate each partial derivative:

∂F1/∂x = 4x - z × cos(xz)

∂F2/∂y = 0

∂F3/∂z = -x × cos(xz)

Add the partial derivatives to find the divergence:

div(F) = ∂F1/∂x + ∂F2/∂y + ∂F3/∂z

div(F) = (4x - z × cos(xz)) + 0 + (-x × cos(xz))

Simplify the expression:

div(F) = 4x - z × cos(xz) - x × cos(xz)

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As the number of trials gets larger, the experimental probability of an event approaches the theoretical probability of the event.

The Law of Large Numbers, a key idea in probability theory, holds that as trials or experiments are conducted, the experimental probability of an occurrence tends to converge toward the theoretical or predicted probability of that event.

In other words, the experimental results improve in accuracy and reliability as the sample size grows when forecasting the actual course of an event. This is because a bigger sample size reduces the significance of random changes or data errors and increases the likelihood that the experimental results will accurately reflect the true underlying probability of the event.

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Here are the base five numerals from 1 to 100

1, 2, 3, 4, 10, 11, 12, 13, 14, 20, 21, 22, 23, 24, 30, 31, 32, 33, 34, 40, 41, 42, 43, 44, 100.

With the base five, every number can only take on the values of 0, 1, 2, 3, or 4.

After the number 4, we carry over to the following place value and start again with 0. So, for instance, the number after 4 in base five is 10, because we've carried over to the next place value and started with 0 again.

In this way, we can count all the way up to 100 in base five, using these 25 unique numerals.

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The given ordered pairs (4, 0.5), (2.5, 4.5), (0.5,3), and (2, 0) are plotted on the coordinate plane as shown in the graph below.

From the question, we are to plot the given ordered pairs on the coordinate plane

To plot the given ordered pairs, we will determine the location of the point on the coordinate plane

We will look at the first number in the ordered pair (the x-coordinate) and find that value on the x-axis. Also, we will look at the second number (the y-coordinate) and find that value on the y-axis.

Now, we will plot the point where the x-coordinate and y-coordinate intersect. The point is represented by a dot.

The ordered pairs are plotted on the coordinate plane as shown in the graph below.

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The simplified expression is (n - 3) / (n - 2).

The expression is simplified as follows;

(n² - 5n + 6) / (n² - 4n + 4)

n² - 5n + 6 can be factored as (n - 2) (n - 3)

n² - 4n + 4 can be factored as (n - 2) (n - 2)

Therefore, the expression becomes:

[(n - 2) (n - 3)] / [(n - 2) (n - 2)]

We can cancel the (n - 2) factor in the numerator and denominator, leaving us with:

(n - 3) / (n - 2)

So the simplified expression is (n - 3) / (n - 2).

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The z-score for the 90th percentile is approximately 1.28, for the 62nd percentile is approximately 0.31, and for the first quartile (25th percentile) is approximately -0.67.

To calculate the percentiles for this dataset, we need to use the z-score formula. Unfortunately, I cannot directly provide you the responses for the 90th, 62nd, and first quartile percentiles without more information.

However, I can help you understand the process of finding these percentiles:

1. Determine the z-score corresponding to the desired percentile using a z-score table or calculator. For example, the z-score for the 90th percentile is approximately 1.28, for the 62nd percentile is approximately 0.31, and for the first quartile (25th percentile) is approximately -0.67.

2. Use the following formula to find the response corresponding to the z-score:

  Response = Mean + (Z-score × Standard Deviation)

For example, to find the 90th percentile:

  Response = 5.7 + (1.28 × 2.3)

Calculate this for each percentile using their respective z-scores, and you will find the responses you are looking for.

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Step-by-step explanation:

4% tax is .04 in decimal:

($  50  + 30 ) * .04    = 3.20 tax    

The length of the fabric piece is 5 cm.

We are given the width and area of the fabric piece and need to find its length. Here are the steps:

1. The terms involved in this problem are width, length, and area.
2. The formula to calculate the area of a rectangle is Area = Width × Length.
3. We are given the width (6 cm) and area (30 cm²) of the fabric piece.
4. To find the length, we'll rearrange the formula: Length = Area ÷ Width.
5. Plug in the given values: Length = (30 cm²) ÷ (6 cm).
6. Perform the calculation: Length = 5 cm.

So, the length of the fabric piece is 5 cm.

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The critical points of f(x) on the interval 0 < x < 10 are: (2, max), (7.5, min)

To estimate the critical points of f(x) on the interval 0 < x < 10, we need to look for points where the derivative, f'(x), equals zero or is undefined. However, we are given a table of values for f(x) instead of f'(x), so we need to first estimate f'(x) using these values.

One way to do this is to use finite differences. We can calculate the first finite difference for each pair of adjacent values in the table, which gives an estimate of the derivative at the midpoint of the interval:

f'(x) ≈ (f(x+1) - f(x)) / (1)

Using this formula, we can calculate the following table of values for f'(x): 0123456789 23-2.79-8-5

Now we can look for critical points of f(x) by finding where f'(x) equals zero or is undefined: - f'(x) = 0 when x = 2 or x = 7.5 (approximately) - f'(x) is undefined at x = 0 and x = 10 (endpoints of the interval)

To classify each critical point, we need to look at the sign of the derivative near the point. If f'(x) changes sign from positive to negative at a critical point, then it is a local maximum. If it changes from negative to positive, then it is a local minimum. If it does not change sign, then it is neither a maximum nor a minimum.

Using the values in the table for f'(x), we can see that: -

Near x = 2, f'(x) changes sign from positive to negative, so it is a local maximum. - Near x = 7.5, f'(x) changes sign from negative to positive, so it is a local minimum. - At the endpoints x = 0 and x = 10, f'(x) is undefined, so there are no critical points.

Therefore, the critical points of f(x) on the interval 0 < x < 10 are: (2, max), (7.5, min)

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The area covered by a sprinkler that sprays water in a circle of an 8-foot radius is 200.96 square feet.

Circle is a 2-Dimensional shape. It has no vertex and edges. It has a center point which equidistant from any point of boundary or circumference of a circle.

Radius refers to the distance between the center and any point on the boundary or circumference of the circle.

The area of a circle is given as the product of a constant pi and the square of the radius.

A =  π[tex]r^2[/tex]

A is the area

r is the radius

r = 8 feet

A = π * 8 * 8

= 3.14 * 8 * 8

= 200.96 square feet

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,Based on the information, we need to consider 5 terms in the series for the sum to exceed 1507.

Substituting the given values, we get:

1507 < -3(1 - (-4)^n)/(1 - (-4))

Simplifying this inequality, we get:

-4^n < 502

Taking the logarithm of both sides, we get:

n*log(4) > log(502)

n > log(502)/log(4)

n > 4.29

n = 5

Therefore, we need to consider 5 terms in the series for the sum to exceed 1507.

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S = lim[n → ∞] sn
 = lim[n → ∞] (306n^2 + 35n + 306)
 = ∞
So unfortunately, the series (n + 16)(n + 18) diverges to infinity and does not have a finite sum.To find the sum S of the series (n + 16)(n + 18), we need to take the limit of the sequence of partial sums as n approaches infinity. So let's first find the formula for the nth partial sum sn:

sn = (1 + 16)(1 + 18) + (2 + 16)(2 + 18) + ... + (n + 16)(n + 18)
  = ∑[(k + 16)(k + 18)] (from k = 1 to n)

Using the formula for the sum of squares, we can expand each term in the sum:

(k + 16)(k + 18) = k^2 + 34k + 288

So now we have:

sn = ∑(k^2 + 34k + 288) (from k = 1 to n)
  = ∑k^2 + 34∑k + 288n (from k = 1 to n)
  = n(n + 1)(2n + 1)/6 + 34n(n + 1)/2 + 288n
  = 306n^2 + 35n + 306

Now we can take the limit of sn as n approaches infinity to find S:

S = lim[n → ∞] sn
 = lim[n → ∞] (306n^2 + 35n + 306)
 = ∞

So unfortunately, the series (n + 16)(n + 18) diverges to infinity and does not have a finite sum.

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After 5 years with 8% depreciation, the Audi R8's value will be around $81,249.36.

To determine how much money you must have in your account now, you can use the formula A = Pe^(rt), where A is the final amount, P is the principal (the initial amount invested), e is the constant 2.71828, r is the annual interest rate expressed as a decimal, and t is the time in years. We will calculate using this formula.Plugging in the given values, we get:
A = $23,000
r = 0.068 (6.8% expressed as a decimal)
t = 5 years
So, $23,000 = P*e^(0.068*5)
Solving for P, we get:
P = $16,376.59
Therefore, you must have $16,376.59 in your account now to reach your goal of $23,000 in 5 years with 6.8% continuous compounding interest. To determine how much the Audi R8 will be worth in 5 years, you can use the formula A = P(1 - r)^t, where A is the final amount, P is the initial amount, r is the annual depreciation rate expressed as a decimal, and t is the time in years. Plugging in the given values, we get:
P = $148,700
r = 0.08 (8% expressed as a decimal)
t = 5 years
So, A = $148,700*(1 - 0.08)^5
Simplifying, we get:
A = $81,249.36
Therefore, the Audi R8 will be worth approximately $81,249.36 in 5 years with 8% depreciation.

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The lateral surface area about x-axis is 114.1 square units.

To find the lateral surface area of the cone generated by revolving the line segment y=9/2x, 0≤x≤9 about the x-axis, we first need to find the length of the slant height of the cone.

We can think of the cone as being formed by rotating a right triangle about the x-axis.

The line segment y=9/2x intersects the x-axis at (0,0) and (9,81/2).

This forms a right triangle with base 9 and height √(81/2) = (9/2)√2.

The slant height of the cone is the hypotenuse of this right triangle, which can be found using the Pythagorean theorem:

l = √(9² + (9/2√2)²) = √(81 + 81/8) = (9/√2)√(9/8) = (9/2)√2

The lateral surface area of the cone can then be found using the formula:

L = πrl

where r is the radius of the base of the cone (which is equal to half the base of the right triangle, or 9/2) and

l is the slant height we just found.

Substituting in the values, we get:

L = π(9/2)(9/2)√2 = (81/4)π√2 ≈ 114.1

Therefore, the lateral surface area of the cone generated by revolving the line segment y=9/2x, 0≤x≤9 about the x-axis is approximately 114.1 square units.

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The answer would be

A = $8,650

P = $5,000

t = 5 years

To solve this problem, we can use the formula for compound interest:

A = P(1 + r/n)^(nt)

Where:

A = the amount of money after t years

P = the principal (initial deposit)

r = the annual interest rate

n = the number of times the interest is compounded per year

t = the number of years

We know that Allen opened a retirement savings account with an initial deposit of $5,000 and made annual contributions. After 5 years, the account grew to $8,650. We don't know the annual interest rate or how the interest is compounded, so we can use the formula to find out.

Let's assume that Allen made no additional contributions to the account after the initial deposit. Then:

A = $8,650

P = $5,000

t = 5 years

We can rearrange the formula to solve for r:

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The image of P under a 270° counterclockwise rotation about the origin is (2, -8) .

Transformations are changes done in the shapes on a coordinate plane by rotation, reflection or translation.

Translation, rotation, reflection, and dilation are the four common types of transformations.

Rotation simply means turning. If a point P, whose position vector is (x,y), is rotated  270° counterclockwise rotation about the origin, the position of the image P' is (y, -x).

We have: P(8, 2)

Thus, the image of P will be:

P'(2, -8)

Therefore, the image of P under a 270° counterclockwise rotation about the origin is (2, -8).

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Check the picture below.

Answer:

250 degrees

Step-by-step explanation:

For any circle tangent to line FG at point F, as shown in the diagram, and for any point E on the circle, the relationship between the measure of angle GFE and the arclength of FE is given by [tex]m~\text{arc}~FE=2m \angle GFE[/tex].

So, the measure of the arc FE is 110 degrees.  Since a circle is fully 360degrees, the missing arc represented by the question mark is given by the following equation:

? + 110 = 360

Solving for the ?

? = 250 degrees

The ordered pair that is a reflection over the x-axis for the point shown include the following: A. (6, 4)

In Mathematics and Geometry, a reflection over or across the x-axis is represented by this transformation rule (x, y) → (x, -y).

This ultimately implies that, a reflection over or across the x-axis would maintain the same x-coordinate while the sign of the y-coordinate changes from positive to negative or negative to positive.

Next, we would apply a reflection over or across the x-axis to the point;

(x, y)                →      (x, -y)

(6, -4)                →      (6, -(-4)) = (6, 4)

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Answer:

6

Step-by-step explanation:

The measure of arc DF is given as follows:

mDF = 58º.

We have two secants in this problem, and point E is the intersection of the two secants, hence the angle measure of 52º is half the difference between the angle measure of the largest arc of 162º by the angle measure of the smallest arc.

Then the measure of arc DF is obtained as follows:

52 = 0.5(162 - mDF)

52 = 81 - 0.5mDF

0.5mDF = 29

mDF = 58º.

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The rate of return should an investor expect to earn if he or she purchases these bonds is equal to 4.184%.

Annual coupon rate = 6.35%

Maturity time = 20 years

To calculate the rate of return an investor should expect to earn if they purchase the Taussig Corp. S bonds,

Consider the cash flows from the bond and the purchase price.

Determine the cash flows from the bond,

The bond has a 6.35% annual coupon rate,

which means it pays $63.50 per year 6.35% of $1,000 face value.

The bond has a 20-year maturity, so there will be 20 coupon payments of $63.50 each.

If the bond is not called, the investor will receive the face value of $1,000 at maturity.

Calculate the purchase price of the bond,

The bonds are currently selling for $960.

Calculate the yield to maturity (YTM) on the bond,

Assume the yield curve is horizontal, so the yield to maturity will be the same as the coupon rate.

Calculate the rate of return using the following formula,

Rate of Return = [tex](Total Cash Flows / Purchase Price)^{(1 / Holding Period)}[/tex] - 1

Let us calculate the rate of return step by step,

Total Cash Flows,

Coupon payments,

$63.50 × 20 years = $1,270

Face value at maturity = $1,000

Total Cash Flows = $1,270 + $1,000

                            = $2,270

Rate of Return = [tex]($2,270 / $960)^{(1 / 20)}[/tex] - 1

Using a financial calculator , Attached calculation.

solve for the rate of return:

Rate of Return ≈ 4.184%

Therefore, an investor should expect to earn approximately a 4.18% rate of return if they purchase these bonds.

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According to the 68-95-99.7 rule, approximately 68% of the distribution falls within one standard deviation of the mean, 95% falls within two standard deviations, and 99.7% falls within three standard deviations.

In this case, the mean is 7.06 minutes and the standard deviation is 0.75 minutes. Therefore, the range of times that covers the middle 95% of the distribution would be from the mean minus two standard deviations (7.06 - 2 x 0.75 = 5.56 minutes) to the mean plus two standard deviations (7.06 + 2 x 0.75 = 8.56 minutes).

In other words, 95% of the male college students' mile run times are expected to fall between 5.56 and 8.56 minutes. This means that most of the students' mile run times will be within this range, and only a small percentage will be outside of it.

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