Margy is trying to improve her cardio endurance by performing an exercise in which she alternates walking and running 100.0 m each. If Margy is walking at 1.4 m/s and accelerates at 0.20 m/s2 during one of the running portions, what is her final velocity at the end of the 100.0 m

Answers

Answer 1

She moves at 6.5 m/s as her final speed after running 100 meters.

Acceleration or velocity, according to m/s 2?

The velocity change of an object per unit of time is known as acceleration. Amounts of acceleration are measured in meters per second squared (m/s2), the SI unit of acceleration. For instance, due to Earth's gravity, a falling object accelerates at a rate of 9.8 m/s2.

A straight-line motion issue looks something like this. These formulas are used to determine the final velocity:

s = Vo*t + (1/2)*a*at2, and Vf = Vo + at

Where:

Vf = = final speed =?

1.4 m/s is the initial velocity, and 0.20 m/s is the acceleration.

100m displacement in 2 seconds.

the first equation is changed by:

100 = 1.4t + (1/2)*0.2*t^2\st = 25.388s

Vf = 1.4 + 0.2 can be used as a replacement in the second equation.

Vf = 6.5m/s

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Related Questions

A wheel rotates at 2 rad/s. What is its period and frequency?

Answers

(1) The frequency of the oscillation is 0.32 Hz.

(2) The period of the oscillation is 3.13 seconds.

What is the period of the wheel's oscillation?

The period of the wheel's oscillation is the time taken for the wheel to make one complete oscillation.

The period of an oscillatory motion is the reciprocal of the frequency of the oscillation.

The frequency of the oscillation is the number of cycles completed by the oscillatory object in a given second.

The frequency of the wheel undergoing oscillatory motion is calculated by using the following formula.

f = ω / 2π

where;

ω is the angular speed of the wheelf is the frequency

f = ( 2 rad/s ) / 2π

f = 0.32 Hz

The period of the oscillation is calculated as follows;

T = 1 / f

T = 1 / 0.32 s

T = 3.13 seconds

Thus, the period of oscillation and frequency of the oscillation are inversely proportional.

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Question 10 of 10
A 200 N force is applied to an object, which then accelerates at 2 m/s2 What
is the mass of the object?
A. 100 kg
B. 400 kg
C. 25 kg
O D. 50 kg

Answers

Answer:

a

Explanation:

f=ma

200=2*m

divide both sides by 2

m=100

Help! again lol ‍‍‍‍‍‍‍‍‍‍‍

Answers

Answer:

The weather is just the state of the atmosphere at any time, including things such as temperature, precipitation, air pressure and cloud cover.

Explanation:

Daily changes in the weather are due to winds and storms. Seasonal changes are due to the Earth revolving around the sun.

atmosphere:The atmosphere covers the Earth. It is a thin layer of mixed gases which make up the air we breathe. This thin layer also helps the Earth from becoming too hot or too cold

Ocean:Oceans cover about 70 percent of Earth's surface. Their large size and thermal properties allow them to store a lot of heat.

ice: Ice is the world's largest supply of freshwater. It covers the remaining 3 percent of Earth's surface including most of Antarctica and Greenland. Ice plays an important role in regulating climate, because it is highly reflective.

:]

The ECG waveform has various components such as waves, segments, and intervals; when these components differ from the expected norm, this indicates:

Answers

The ECG waveform has many components such as segments,  waves, and intervals; when these components differ from the expected forms, this indicates dysrhythmia.

An abnormal or irregular heartbeat is referred to as cardiac dysrhythmia. Your heart may beat too slowly or too fastly if you have dysrhythmia. Or your heart's rhythm may be disturbed, giving you the sensation that your heart missed a beat.

Thus, when the ECG waveform is different than normally it is expected, it shows a sign of dysrhythmia. When a person experiences dysrhythmia, and the rate of their heartbeat becomes irregular but still, it lies within the normal range.

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In the definition of weight, W = mg, the mass m refers to an inertial mass.
True or false

Answers

Answer:

True

Explanation:

In the definition of weight, W = mg, the mass m refers to an inertial mass.

From the viewpoint of an alien astronomer, how does Jupiter affect observations of our Sun?
a) It causes the Sun to move in a small ellipse with an orbital period of about 12 years.
b) It makes the Sun periodically get somewhat brighter.
c) It makes the Sun appear dimmer when viewed with infrared light.
d) It causes the Sun to move in a small ellipse in the sky, with the same ellipse repeated every night.

Answers

Jupiter affect observations of the Sun, from the viewpoint of an alien astronomer, by causing the Sun to move in a small ellipse with an orbital period of about twelve years. The correct option is option a.

Being the fifth closer planet to our Sun, Jupiter is the biggest planet in our Solar System. Jupiter is one of the gas giants in the Solar System.

From the Sun, Jupiter's average distance is about 480 million miles, and it takes nearly twelve years for Jupiter to make one revolution. Jupiter has a ring, albeit flat and small, like the rest of the gas giants. Jupiter's rotation is the fastest of all planets in the Solar System, rotating once on its axis every ten hours.

From the viewpoint of an alien astronomer outside our Solar System, the Sun will look as if it orbits Jupiter and takes 12 years to complete a revolution. Planets in general have orbits that are elliptical.

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Suppose a cart is being moved by a force. If suddenly a load is dumped into the cart so that the cart's mass is doubled, what happens to the cart's acceleration

Answers

According to the given statement  If suddenly a load is dumped into the cart so that the cart's mass is doubled The acceleration slows.

Give an explanation of acceleration.

which speaks of the rate of change in time of the speed and direction of motion. Something is said to be accelerating when it starts to move faster or slower. Even if the speed slows down, motion on a circle accelerates because the direction is constantly changing.

Does accelerating mean going faster?

Any process in which the velocity changes is referred to as acceleration. There are only two ways to speed up because velocity consists of both a speed and a direction.

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If A and B are non-zero vectors, is it possible for A×B and A·B both to be zero?

Answers

It is important to note that the dot product and cross product of any two non-zero vectors cannot both be zero therefore  A×B and A·B cannot both be zero.

What are non-zero vectors?

In vector space, a non-zero vector. V is a vector that differs from the zero vector in V. If u is a non-zero vector in V and an is a scalar, i.e. an element of the field over which V is defined, then au=0 is only possible if a=0.

The product of any two non-zero vectors is non-zero in this vector context. It is referred to as Hamilton's Quaternions. Over the real numbers, quaternions form a four-dimensional vector space, and their multiplication is a combination of dot product and cross product.

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An air puck of mass 0.304 kg is tied to a string and allowed to revolve in a circle of radius 0.44 m on a horizontal, frictionless table. The other end of the string passes through a hole in the center of the table and a mass of 1.15 kg is tied to it. The suspended mass remains in equilibrium while the puck revolves. 0.44 m v 1.15 kg 0.304 kg What is the tension in the string

Answers

The tension in the string can be found by using the equation for centripetal force. which is equal to 150.

This equation states that the centripetal force (Fc) is equal to the mass of the object (m) multiplied by the square of the velocity (v) and divided by the radius (r). Therefore,

Fc = m x v²/r.

In this case, the centripetal force is equal to the tension in the string, so the tension in the string (T) can be found by rearranging the centripetal force equation to

T = m x v²/r.

Substituting in the given values for mass (m) and radius (r) gives

T = 0.304 kg x (2.83 m/s)²/0.44 m

T= 150N

Therefore the tension of the string is 150N

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Running at 2. 0 m/s, Burce, the 45. 0 kg quarterback, collides with Max, the 90. 0 kg tackle, who is traveling at 7. 0 m/s in the other direction. Upon collision, Max continues to travel forward at 1. 0 m/s.

What is the new velocity of Bruce?(list unknown variable and known variables, write an equation, plug in numbers, and get answer with unit. )

Answers

Burce, a 45-kg quarterback, collides with Max, a 90-kg tackle, who is moving at 7.0 m/s in the opposite direction, as he runs at 2.0 m/s. This results in Bruce's new speed being 14 m/s.

Max hits the ground moving forward at a speed of 1.0 m/s. A moving object's velocity is a function of time and measures how quickly its position changes in relation to a frame of reference. When an object is moving, its speed and direction are specified by its velocity. A collision in physics is referred to as an elastic collision when the combined kinetic energy of the two bodies stays constant. A collision that is ideal and absolutely elastic

V1 = (720 - (90)(1))/45

V1 = 14m/s

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2.) What would the force of friction be between the surface and wood block if there was no
gravity?

Answers

Answer:

The coefficient of friction between the surface of the block is 1/4

Which of the following statements regarding heat is accurate? NEED ASAP

Answers

Heat is a form of energy

The piton in fig 2. 1. 15 i pulled out of the cylinder from piton x to piton y without changing the temperature of the air encloed if the original preure in the cylinder wa 1. 0 multiply by 10 calculate the air preure when the piton i at poition y

Answers

The pressure at position y to be 10.0, which is the air pressure when the piston is at position y.

If the original pressure in the cylinder was 1.0, and the piston is pulled out from position x to position y without changing the temperature of the enclosed air, the air pressure at position y will be increased. This is due to the change in volume of the cylinder as the piston is pulled out. As the volume increases, the number of air molecules inside the cylinder also increases, which causes an increase in the air pressure.

To calculate the air pressure when the piston is at position y, we can use the gas law known as Boyles' Law, which states that the pressure and volume of a gas are inversely proportional. Therefore, if the volume increases, the pressure will decrease, and if the volume decreases, the pressure will increase.

P₁V₁=P₂V₂

Where P₁ is the initial pressure, V₁ is the initial volume, P₂ is the final pressure, and V₂ is the final volume.

By substituting the given values, we have:

1.0V₁ = P₂(V₁+V)

Where V is the change in volume due to the movement of the piston.

Solving for P₂:

P₂= 1.0*V₁/(V₁+V)P₂= 1.0*1.0/(1.0+V)

As we know, the original pressure is 1.0, and if we multiply it by 10, we will get the final pressure at position y to be 10.0, which is the air pressure when the piston is at position y.

This question is not written in a proper manner. The corrections are:

The piston in fig. 2. 1.15 is pulled out of the cylinder from piston x to piston y without changing the temperature of the air enclosed. If the original pressure in the cylinder was 1.0, multiply by 10 to calculate the air pressure when the piston is at position y.

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If an amount of heat Q is needed to increase the temperature of a solid metal sphere of

diameter D from 4°C to 7°C, the amount of heat needed to increase the temperature of a solid

sphere of diameter 2D of the same metal from 4°C to 7°C is

A. 8Q

B. 40

C. 20

D. Q

Answers

As a result, X heat required = 27Q is the amount of heat needed to raise the temperature.

Calculation

first case

Q = Specific Heat * Density of Sphere* (4/3*pi*D^3) * (7-4)     -1

Second case

X = Specific Heat * Density of Sphere* (4/3*pi*(3D)^3) * (7-4)    -2

Dividing 1 and 2 we get

Q/X = 1/27

27

How does the heat equation's Q work?

where Q is the amount of heat that is transported to or from the item, m is the object's mass, C is the material's specific heat capacity, and T is the resultant temperature change of the object.

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A 1. 25 in. By 3 in. Rectangular steel bar is used as a diagonal tension member in a bridge truss. The diagonal member is 20 ft long, and its modulus of elasticity is 30,000,000 psi. If the strain in the diagonal member is measured as 0. 001200 in. /in. , determine:

Answers

The length of the diagonal member is 20 ft, and if its modulus of elasticity is 30,000,000 psi. If the strain in the diagonal member is measured as 0. 001200 in, the elongation of the member is 29 inches.

What is a truss?

A truss is constructed of a number of components, such as beams, connected at nodes to create a rigid framework. According to engineering definition, a truss is a structure that "consists of merely two-force members, where the members are placed so that the assembly as a whole behaves as a single entity."

A truss is a piece of furniture comprised of components arranged into linked triangles that function as a single unit. Trusses are most typically used in towers, roofs, and bridges. If a truss' members essentially lie on a single plane, it is referred to as a plane truss.

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How much weight is generated by an 80 kg person on planet earth? On the moon?

Answers

It will be 133 on the moon

People under going physical therapy after an injury often find it helpful to perform exercise in water? Why?
(No links please)

Answers

Because water puts less weight on the joints helping prevent more pain and potentially problems

Also if you could give me Brainily that would be amazing

What happens to the particles of a matter when heat is released and temperature becomes lower?

Answers

In the particles of a substance when heat is released and the temperature becomes lower are the particles will move more slowly.

A particle can vibrate due to heating so that the particle can be said to have kinetic energy. Kinetic energy itself is affected by the mass and speed of objects. The smaller the mass of an object, the greater its kinetic energy. The faster the particles vibrate, the greater their kinetic energy.

When a particle is heated, its temperature will rise and the particle will move fast because it gains kinetic energy. Meanwhile, when a particle loses heat, the temperature of the particle will decrease, this causes a decrease in the kinetic energy of the particle due to heat loss so that the particle moves slower.

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If the Barbie had a mass of 0.23kg and the Barbie was dropped 11ft 11inches (assuming there was no rubber bands) how fast would the Barbie be moving at the bottom of the path?

Answers

The Barbie would be moving with speed 27.69 ft/s at the bottom of the path.

What is speed?

Speed is distance travelled by the object per unit time. Due to having no direction and only having magnitude, speed is a scalar quantity With SI unit meter/second.

Mass of the Barbie = 0.23 kg.

Initial height of the Barbie: h= 11 ft 11 inches = ( 11 + 11/12) feet = 11.92 feet.

Acceleration due to gravity: g = 32.17 ft/s²

Hence, the speed of the Barbie at the bottom of the path = √(2gh)

= √( 2 × 32.17 ×11.92) ft/s

= 27.69 ft/s.

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Two friends A and B started at different times and covered 30km as shown in the graph.
Identify the correct statement from the following.


option 1 - A and B move with the same speed
option 2 - B moves with non-uniform speed
option 3 - A completes his journey early
option 4 - B overtakes A at 11:10 a.m.

Answers

Answer:

Explanation:

option 1 - A and B move with the same speed INCORRECT because the lines have different slopes

option 2 - B moves with non-uniform speed  INCORRECT because the line for B is straight

option 3 - A completes his journey early INCORRECT because A ends his journey at about 11:45 after going about 42 km. B finishes his journey at about 11:35.

option 4 - B overtakes A at 11:10 a.m.  CORRECT.  They meet at the 30 km mark at 11:10, which is where the lines intersect.

Contrast the force of gravity between these
pairs of objects: a 1-kg mass and a 2-kg
mass that are 1 m apart; a 1-kg mass and a
2-kg mass that are 2 m apart; and two 2-kg
masses that are 1 m apart.

Answers

The force of gravity between these pairs of objects: a 1-kg mass and a 2-kg mass that are 1 m apart is 13.[tex]10^{-11}[/tex]34N.

For  2 m apart 6.67[tex]10^{-11}[/tex]N.

For 2-kg mass that are 2 m apart; and two 2-kg masses that are 1 m apart is 26.68N.

How many gravitational forces are there?

The resultant (vector sum) of two forces is the force of gravity on Earth: (a) the gravitational pull according to Newton's universal law of gravitation; and (b) the centrifugal force, which is the outcome of choosing an earthbound, rotating frame of reference.

Force between two object is calculated f=Gmm/r^2.

G=6,67*10^-7

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When a satellite is a distance d from the center of Earth, the magnitude of the gravitational force that the satellite exerts on Earth is F. What is the magnitude of the gravitational force that the satellite exerts on Earth when the satellite's distance from the center of Earth is 3d?
plsss help

Answers

According to Newton's law of gravitation, the new gravitational force will be F/9

Newton's Law of Gravitation

It states that, the force of attraction between two masses is directly proportional to the product of the masses and inversely proportional to the square of the distance between them.

When a satellite is a distance d from the center of Earth, the magnitude of the gravitational force that the satellite exerts on Earth is F. That is,

F = GMm/d²

Where

M = mass of the earthm = mass of the satelliteG = universal gravitational constant

The magnitude of the gravitational force that the satellite exerts on Earth when the satellite's distance from the center of Earth is 3d can be expresses as follow

f = GMm/(3d)²

f = GMm/9d²

f = GMm/d² × 1/9

Since GMm/d² = F

f = F × 1/9

f = F/9

Therefore, the magnitude of the gravitational force that the satellite exerts on Earth when the satellite's distance from the center of Earth is 3d is F/9 Newton

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What is the major difference between static and dynamic stretching ?

Answers

Explanation:

This intense stretching method uses bouncing movements to push your body beyond its normal range of motion. Whereas static stretches are performed slowly and gradually, the ballistic method stretches muscles much farther and faster. You can do many of the same stretches as ballistic or static stretches.

light waves with a frequency of 7.26 x 10^14 HZ lies in the violet region of the visible spectrum. what is the wavelength of this frequency of light?

Answers

Answer:

4.13×10⁻⁷ m

Explanation:

Applying

v = λf................... Equation 1

Wherfe v = speed of light, λ = wavelength of light, f = frequency of light.

make λ the subject of the equation

λ = v/f....................... Equation 2

Note: Light is an electromagnetic wave, and all electromagnetic wave moves with thesame speed which is 3×10⁸ m/s.

From the question,

Given: f = 7.26×10¹⁴ Hz

Constant: v = 3×10⁸ m/s

Substitute these values into equation 2

λ = (3×10⁸)/(7.26×10¹⁴)

λ = 4.13×10⁻⁷ m

How does a simmering pot of spaghetti sauce illustrate convection currents

Answers

Answer:

1: As the substance’s thermal energy increases, the kinetic energy of its particles increases, and vice versa.

2: Its molecules move around more quickly, so there is more space between them, making it less dense than the air above it.

3: Warmer sauce at the bottom of the pot is less dense, so it rises, forcing cooler sauce down, where it is warmed.

4: Hot soup warms the bowl where it sits.

5: transfer of thermal energy through infrared waves

Explanation:

This is correct for the Thermal Energy Transfer Quick Check

A simmering pot of spaghetti sauce provides an excellent illustration of convection currents because the process of heating the sauce causes hot molecules to rise and cool molecules to sink. This creates a circular motion known as a convection current.

When the pot is placed on a hot stove, the heat from the burner is transferred to the bottom of the pot, which in turn heats the sauce. As the sauce heats up, the molecules nearest to the heat source become hotter and lighter. These hot, lighter molecules rise to the top of the pot, creating a convection current. As they reach the surface, they cool down, become heavier, and then sink back down to the bottom of the pot.

This process of hot molecules rising and cool molecules sinking creates a circular motion that evenly distributes the heat throughout the sauce, ensuring that it cooks evenly. The convection currents in the pot are also responsible for the bubbles that rise to the surface of the sauce, releasing trapped steam and preventing the pot from boiling over.

In conclusion, a simmering pot of spaghetti sauce illustrates convection currents because it shows how hot molecules rise and cool molecules sink, creating a circular motion that evenly distributes heat and ensures that the sauce cooks evenly.

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If a building is 44 m tall, how long would it take to fall off it?

Answers

Answer:

2.995 seconds

Explanation:

We can use this kinematics equation to evaluate time.

[tex]y=v_0t-\frac{1}{2}gt^2[/tex]

Lets solve for [tex]t.[/tex]

Combine [tex]\frac{1}{2}[/tex] and [tex]gt^2[/tex].

[tex]y=v_0t-\frac{gt^2}{2}[/tex]

Subtract [tex]y[/tex] from both sides.

[tex]0=v_0t-\frac{gt^2}{2}-y[/tex]

[tex]0=-\frac{gt^2}{2} -v_0t-y[/tex]

Multiply both sides of the equation by -1.

[tex]0=\frac{gt^2}{2} -v_0t+y[/tex]

Multiply both sides of the equation by 2.

[tex]0=gt^2 -2v_0t+2y[/tex]

Use the quadratic formula to solve for t.

[tex]\frac{-b+\sqrt{b^2-4ac} }{2a}[/tex]

[tex]\frac{-b-\sqrt{b^2-4ac} }{2a}[/tex]

[tex]a=-g\\b=2v_0\\c=-2y[/tex]

Solution 1 Steps

[tex]t=\frac{-2v_0+\sqrt{(2v_0)^{2} -4*-g*-2y} }{2*-g}[/tex]

[tex]t=\frac{-2v_0+\sqrt{4v_0^2 -4*-g*-2y} }{2*-g}[/tex]

[tex]t=\frac{-2v_0+\sqrt{4v_0^2 -8gy} }{-2g}[/tex]

Solution 2 Steps

[tex]t=\frac{-2v_0-\sqrt{(2v_0)^{2} -4*-g*-2y} }{2*-g}[/tex]

[tex]t=\frac{-2v_0-\sqrt{4v_0^2 -4*-g*-2y} }{2*-g}[/tex]

[tex]t=\frac{-2v_0-\sqrt{4v_0^2 -8gy} }{-2g}[/tex]

One of these solution will most likely lead to a negative answer. The solution that gives a positive answer is correct. Lets enter our values into both equations to see which one is correct.

We can assume the initial velocity is 0.

We are given

[tex]v_0=0\\g=-9.81\\y=44[/tex]

Lets try the first solution.

[tex]t=\frac{-2*0+\sqrt{(4*0^2) -(8*-9.81*44)} }{-2*-9.81}[/tex]

[tex]t=\frac{0+\sqrt{0 -(8*-9.81*44)} }{-2*-9.81}[/tex]

[tex]t=\frac{0+\sqrt{0 --3453.12} }{-2*-9.81}[/tex]

[tex]t=\frac{\sqrt{3453.12} }{19.62}[/tex]

[tex]t=2.995[/tex]

Our first solution was positive so there is no need to check the second solution.

An antelope of mass 55 kg that is running at a speed of 10 m/s

and a tiger of mass 140 kg that is running at a speed of 15 m/s.

What's the total linear momentum of the antelope and the

tiger?

Answers

The total linear momentum of the antelope and the tiger is 2650 Kg m/s.

Linear momentum: what is it?

The result of a system's mass x its velocity is its linear momentum. Linear momentum is denoted by the sign p = m v. The relationship between momentum and an object's mass and speed is straightforward.

Given -

mass of antelope = 55 Kg

mass of tiger = 140 Kg

speed of antelope = 10 m/s

speed of tiger = 15 m/s

from linear momentum formula

P = m × v

For antelope-

P = 55 × 10

P = 550 Kg m/s

For tiger-

P = m × v

P = 140 × 15

P = 2100 Kg m/s

Hence, total momentum is-

550 + 2100

2650 Kg m/s

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On a wheel and axle, if the large wheel has a radius of 20 cm and the small wheel has a radius of 4 cm, what is the ideal mechanical advantage

Answers

The ideal mechanical advantage is 5.

Here, we have value larger radius , R = 20 cm and smaller radius = 4 cm

So, as per the problem, mechanical advantage will be 20/4 = 5.

A wheel and axle must be permanently joined in order to be considered a simple machine, and the wheel must by definition have a bigger radius than the axle. A point on the wheel moves a distance of 2 R whereas a point on the axle moves a distance of 2 r when you turn the wheel through a full revolution, which likewise causes the axle to turn through a full revolution.

The force you apply F R times the distance the point moves equals the effort W required to move a point on the wheel through one full revolution. Work is energy, and since energy must be conserved, a point on the axle must be subjected to a larger force F r because it moves a shorter distance.

The mathematical relationship is:

W = Fr (subscript) ×2πr/θ =F r(subscript) ×2πR/θ

Where ​θ​ is the angle that the wheel is turned.

And therefore:

Fr(r in subscript) / FR(R in subscript) = R/r

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A 50.0-kg child stands at the rim of a merry-go-round of radius 2.70 m, rotating with an angular speed of 3.95 rad/s. What minimum coefficient of static friction is required

Answers

A 50.0-kg child stands at the rim of a merry-go-round of radius 2.70 m, rotating with an angular speed of 3.95 rad/s. Minimum coefficient of static friction is required 13.56.

To find the minimum coefficient of static friction required, we need to calculate the centrifugal force acting on the child and compare it to the force of friction.

The centrifugal force acting on the child is given by:

= Fc

= m * r * w^2

where

= m

= 50.0 kg (mass of child)

= r

= 2.70 m (radius of the merry-go-round)

= w

= 3.95 rad/s (angular velocity)

So, Fc = 50.0 kg * 2.70 m * (3.95 rad/s)^2

= 6629.775 N

The force of friction acting on the child is given by:

= Ff

= friction coefficient * normal force

where

friction coefficient = minimum coefficient of static friction required (unknown)

= normal force

= m * g

The normal force is equal to the weight of the child, which is

= m * g

= 50.0 kg * 9.8 m/s^2

= 490 N

So, Ff = friction coefficient * 490 N

To find the minimum coefficient of static friction, we need to set Ff equal to Fc and solve for the friction coefficient:

friction coefficient = Ff / N

friction coefficient = 6629.775 N / 490 N

= 13.56

So the minimum coefficient of static friction required is 13.56.

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please answer as soon as possible. How does the gravitational pull of different objects in space affect other objects in space?

Answers

Answer:

Every object in space exerts a gravitational pull on every other

explanation :  gravity influences the paths taken by everything traveling through space. It is the glue that holds together entire galaxies. It keeps planets in orbit. It can also cause life-destroying asteroids to crash into planets..

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