malia is interested in observing cognitive development in children and wants to design a study that will allow her to observe small changes in how 6 year olds learn to solve problems. she plans to collect data from each child every week for three months
which design is her best choice

Answer:

Explanation: In anyway can you get a better picture just a close picture i cant read it

The capacitor can be used in various home appliances like ceiling fan, electric motor, etc. The total capacitance by connecting a 5.04 µf and 8.02 µf capacitor together in parallel is  13.06 µf.

A two terminal electrical device which is used to store energy in the form of an electric charge is defined as the capacitor. It contains two electrical conductors separated by a distance.

When two capacitors are connected in parallel, then the total capacitance is given as:

C total = C₁ + C₂

C total = 5.04 µf + 8.02 µf

C total = 13.06 µf

Thus the total capacitance is 13.06 µf.

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Answer:

Explanation:

The formula for kinetic energy is K = 1/2mv^2, where K is kinetic energy, m is mass, and v is velocity.

Substituting the given values:

K = 1/2(2.50 kg)(2.00 m/s)^2

K = 1/2(2.50 kg)(4.00 m^2/s^2)

K = 5.00 J

Therefore, the 2.50kg ball traveling at 2.00m/s has 5.00 J of kinetic energy.

Answer:

5000 km

Explanation:

Sure, to calculate the diameter of Vesta, we can use the fact that Vesta's diameter is equal to the diameter of Mercury, which is 5000 km.

Therefore, the diameter of Vesta is also 5000 km.

We can show the working by using the following formula:

Diameter of Vesta = Diameter of Mercury

Diameter of Vesta = 5000 km

Answer: 9.8 J

Explanation:

Since the gravitational potential energy of the object is mgh or mass*acceleration due to gravity*initial height, its [tex]U_{g}[/tex] is 9.8 J. Due to the Law of Conservation of Energy, its kinetic energy will also be 9.8 J. This can be seen in the equation [tex]KE_{i}+ PE_{i}= KE_{f} + PE_{f}[/tex]. Since there is no initial kinetic energy and no final potential energy, its initial potential energy is equal to its final kinetic energy.

A drawing of the electric field lines around a positive charge, then make a second drawing of the electric field lines around a negative charge is mentioned below.

What is electric field ?

According to mathematics, the electric field is described as a vector field that may be connected to each point in space and represents the force per unit charge that is applied to a positive test charge that is at rest at that location. Either the electric charge or time-varying magnetic fields can produce an electric field.

What is electric charge ?

The physical quality of matter—its electric charge—is what causes it to feel a force when exposed to an electromagnetic field. Protons and electrons, the two types of charge carriers, typically carry positive and negative electric charges. Charges moving through a system produce energy.

Therefore, A drawing of the electric field lines around a positive charge, then make a second drawing of the electric field lines around a negative charge is mentioned above.

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Answer:

The wavelength of the photon can be calculated using the equation E = hc/λ, where E is the energy, h is Planck's constant (6.626 ✕ 10^−34 J s), c is the speed of light (2.998 ✕ 10^8 m/s), and λ is the wavelength.

λ = hc/E = (6.626 ✕ 10^−34 J s) (2.998 ✕ 10^8 m/s) / (3.02 ✕ 10^−19 J) = 656.4 nm

Explanation:

The stream's velocity is 1.75 metres per second, and the discharge is 16.8 cubic metres per second.

Discharge has units of feet3/sec or cubic ft per second if length and duration are measured in feet and seconds, respectively (cfs). The cross-sectional area is calculated as Depth times Width. Due to the velocity reduction caused by friction at the channel's edges, the channel's form is crucial.

The cross-sectional area of the stream must be multiplied by the stream velocity in order to determine discharge.

The cross-sectional area of the image is:

A = (8 m) x (1.2 m) = 9.6 m²

1.75 metres per second is listed as the stream velocity.

So the discharge Q is:

Q = A x V

= (9.6 m²) x (1.75 m/s)

= 16.8 m³/s.

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When current flows through a coil of wire, it generates a magnetic field. The direction of the magnetic field can be determined using the right-hand rule. If you point your right thumb in the direction of the current flow, your fingers will curl in the direction of the magnetic field.

In this case, the current is flowing in an anticlockwise sense when viewed from above. Using the right-hand rule, the direction of the magnetic field inside the coil can be determined to be perpendicular to the plane of the coil, and in a clockwise direction when viewed from above.

The diagram below shows the coil of wire lying flat on a horizontal surface with the direction of the magnetic field labelled:

        +-----+-----+-----+-----+-----+

        |                                 |

        |                                 |

        |                                 |

        +    X                    X    +

        |                                 |

        |                                 |

        |                                 |

        +-----+-----+-----+-----+-----+

Therefore, In this diagram, the X's represent the direction of the magnetic field lines inside the coil. As you can see, the magnetic field lines are oriented perpendicular to the plane of the coil and in a clockwise direction when viewed from above.

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Specific heat is a measure of how much energy it takes to raise the temperature of a substance.

Temperature is defined as the measurement of degree of amount of hotness or coldness of a body.

Here,

Specific heat is a measure of how much energy it takes to raise the temperature of a substance. More clearly, specific heat is the amount heat required to raise the temperature of unit mass through one degree.

If an amount of heat Q is given to a body of mass m and ΔT is the rise in temperature. Then specific heat capacity,

      C = Q/mΔT

Its unit is Jkg⁻¹K⁻¹

Specific heat of a substance is a constant but it changes slightly with change in temperature.

The rise in temperature is small for body having large specific heat.

Hence,

Specific heat is a measure of how much energy it takes to raise the temperature of a substance.

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The radius of a water droplet suspended in an electric field can be calculated using the following formula:

r = (3qE/4πρg)^(1/2)

where r is the radius of the droplet, q is the charge on the droplet, E is the strength of the electric field, ρ is the density of the droplet material (assumed to be that of water, which is 1000 kg/m^3), and g is the acceleration due to gravity.

In this case, q = -1.602 × 10^-19 C (the charge on an electron), E = 300 V/m, ρ = 1000 kg/m^3, and g = 9.81 m/s^2.

Plugging in these values, we get:

r = (3(-1.602 × 10^-19 C)(300 V/m)/(4π(1000 kg/m^3)(9.81 m/s^2)))^(1/2)

= 1.83 × 10^-5 m

Therefore, the radius of the water droplet is approximately 1.83 × 10^-5 meters.

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0.16*10^-3m is the distance between two charges according to Coulomb's Law

How does Coulomb's law work?

Coulomb listed the following characteristics of the electric field for charges in a resting state: Unlike charges draw each other while like charges repel one another. As a result, a positive charge pulls a negative charge toward it while two negative charges resist one another.

We can determine the electric force produced between two electrical charges using Coulomb's Law. In particular, it enables the determination of the direction and strength of electric energy. Coulomb's law states that the force of attraction or repulsion between two charged bodies is inversely proportional to the cube of the distance between them and directly proportional to the product of their charges. It operates on the segment connecting the two charges regarded as point charges.

F = kq1q2/r^2

460 = 9*10^9 *2.8*10^-5 *3.1*10^-7 / r^2

r = sqrt ( 9*10^9 *2.8*10^-5 *3.1*10^-7 / 460)

r = 0.16*10^-3m

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Answer:

Explanation:

a) transverse

b)longitudinal waves

The power loss in the bearing is 1.36 W shaft of 100 mm diameter rotates at 120 rad/s in a bearing 150 mm long.

The viscosity of a fluid is a measure of its resistance to flow. A fluid with a high viscosity resists movement because its molecular structure causes a lot of internal friction.

The viscosity of a fluid is a measure of its resistance to flow. A fluid with a high viscosity resists movement because its molecular structure causes a lot of internal friction.

To calculate the power loss in the bearing, we can use the formula:

P = F × V

To calculate the frictional force, we can use the formula:

F = μ × A × P

Where μ is the coefficient of friction, A is the area of the bearing, and P is the pressure of the lubricant.

First, we need to calculate the pressure of the lubricant:

P = μ × Viscosity × (V/D)

Where D is the diameter of the shaft.

P = (0.02) × 20 × (120/0.1) = 480 N/[tex]m^2[/tex]

Next, we can calculate the area of the bearing:

A = π × (D/2)^2 × L

Where L is the length of the bearing.

A = π × (0.1/2)^2 × 0.15 = 0.001178 [tex]m^2[/tex]

Now we can calculate the frictional force:

F = μ × A × P = (0.02) × 0.001178 × 480 = 0.0113 N

Finally, we can calculate the power loss:

P = F × V = 0.0113 × 120 = 1.36 W

Therefore, the power loss in the bearing is 1.36 W.

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The wavelength of maximum intensity for a celestial body with a temperature of 50000 K is approximately 577 nm.

To find the wavelength of maximum intensity for a celestial body with a temperature of 50000 K, we can use Wien's displacement law, which relates the temperature of an object to the wavelength at which it emits the most radiation. The law is given by:

λ_max = b / T

where λ_max is the wavelength of maximum intensity, b is Wien's displacement constant (2.898 × 10⁻³ m·K), and T is the temperature in Kelvin.

We can convert the temperature of 50000 K to Kelvin by adding 273.15 to get:

T = 50000 K + 273.15 = 50273.15 K

Plugging in the values, we get:

λ_max = (2.898 × 10⁻³ m·K) / 50273.15 K

Simplifying, we get:

λ_max = 5.77 × 10⁻⁸ meters

To convert meters to nanometers, we can multiply by 10⁹:

λ_max = 5.77 × 10⁻⁸ meters × 10⁹ nm/m = 577 nm

Therefore, the wavelength of maximum intensity for a celestial body with a temperature of 50000 K is approximately 577 nm.

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Answer:

Explanation:

From  Law of conservation of momentum,

m1u1+m2u2 = m1v1+m2v2 [Law of conservation of momentum]

m1 = 2600kg

u1 = 15m/s

m2 = 1300kg

u2 = -20m/s  [as it is moving in opposite direction]

here, after impact, cars lock with each other so v (final velocity) is the same for both cars, i.e., v1 = v2

(2600)(15)+(1300)(-20) = (2600)v1+(1300)v2

39000-26000 = (2600+1300)v1  [as v1 = v2]

v1 = 13000/3900

v1 = 3.33 m/s

Here, m1v1 = 2600x3.33 = 8658kgm/s

m2v2 = 1300x3.33 = 4329kgm/s

As final momentum of car 1 is higher than that of car 2, both cars will move in direction of car1, that is, west direction.

Answer: Both Chemical and physical changes can be measured, chemical changes can be caused by oxygen since its very reactive. Physical Change: There is no addition or deduction of energy during the physical change, but the energy required for completion of change is released when the change is reversed. Chemical Change: Energy like light, pressure, heat energy is required for chemical changes. When physical or chemical changes occur, they are generally accompanied by a transfer of energy. The law of conservation of energy states that in any physical or chemical process, energy is neither created nor destroyed.

Explanation:

Revolutions per minute are needed for the space station which is at 385m from center of the planet is 1.52 rev/min

Orbital velocity is also called as critical velocity. It is minimum velocity must be given to the satellite or the body, so that it can revolve around the planet. i.e. orbital velocity is minimum velocity of body to revolve in stable orbit around a planet.

Orbital velocity is given by,

[tex]v_{c} = \sqrt{\frac{GM}{R+h}}[/tex] where  G = Gravitational constant (6.673×10⁻¹¹ Nm²/kg²

                               M = Mass of the planet

                               R = Radius of the planet

                                h = height of the object(satellite)

Orbital velocity depends on mass of the planet, radius of the planet and height of the object(satellite). It is independent of mass of the body(satellite).

Given,

Diameter of space station, D = 770m {Radius (R+h) = 385m}

Acceleration due to gravity [tex]g_{h}[/tex]= 9.8 m/s²

our given equation is,

[tex]v_{c} = \sqrt{\frac{GM}{R+h}}[/tex]

[tex]v_{c}^{2} = \frac{GM}{R+h}}[/tex].........1)

we know that v=rω

v²=r²ω²

where r = (R+h) = Radius of planet + height of space station from surface of the planet.

v²=(R+h)²ω²......2)

with equation 2), equation 1 becomes.

(R+h)²ω² = [tex]\frac{GM}{R+h}}[/tex]

ω² = GM÷ (R+h)³.............3)

we know that [tex]g_{h} = \frac{GM}{(R+h)^{2} }[/tex].....4)

equ 3 becomes,

ω² = [tex]\frac{g_{h}}{(R+h)}[/tex]

Putting all values in equation,

ω² = 9.8 ÷ 385

ω² = 0.025454

ω = 0.1595 ≅ 0.16 rad/s

let,

ω = 2πn

n= ω ÷ 2π

n = 0.02547 rev/s

n= 0.02547*60 = 1.52 rev/min

Hence 1.52 rev/min is needed for space station at artificial gravity of 9.8 m/s

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Answer: The direct way that children affect their own acculturation is by peer watching and engagement.

Answer:One direct way in which children impact their own acculturation is through language acquisition. Children who are exposed to a new culture and language at a young age have the opportunity to learn and adopt the new language and cultural norms more easily than adults. As children interact with peers and adults in the new culture and use the new language, they develop their own sense of identity and acculturation, which can be different from that of their parents or other family members. Children may also participate in cultural activities or events, such as holidays or festivals, which further shape their understanding and experience of the new culture. Overall, children can actively participate in and shape their own acculturation process through language acquisition and cultural experiences.

Explanation:

Young’s modulus for each of these five materials from largest to smallest are mentioned below.

What is Young’s modulus?

Many substances lack linearity and elasticity after very minor deformation. Only materials that are linearly elastic are subject to the constant Young's modulus. In this case, the ratio of stress to strain, which corresponds to the material's stress, determines the Young's modulus.

What is data?

Facts such as numbers, words, measurements, observations, or even simple descriptions of objects are grouped together as data. Both qualitative and quantitative data are possible. Qualitative data is information that is descriptive (describes something), whereas discrete data can only take particular values (like whole numbers).

Therefore, Young’s modulus for each of these five materials from largest to smallest are mentioned above.

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The velocity of projection of a stone following projectile motion which is projected vertically upwards from the foot of a vertical cliff 28.8n high so as to just reach the top is 23.75 m/s

When something (a projectile) is launched towards the surface of the Earth and moves along a curved path only under the influence of gravity, it experiences projectile motion (in particular, the effects of air resistance are passive and assumed to be negligible). Galileo showed that although this curved path can also be a straight line when thrown immediately above, it is a parabola in this case.

Gravity is the sole force acting on the item that is mathematically relevant; it acts downward and accelerates the thing towards the mass of the Earth. Due to the object's inertia, the horizontal velocity component of its motion does not require any external force.

According to the equation,

H = [tex]\frac{u^{2} }{2g}[/tex]

where,

H is the maximum height,

u is the velocity of projection and,

g is the acceleration due to gravity.

substituting the values and solving for u,

velocity of projection = 23.75 m/s

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Answer:

a) On the Moon, where the acceleration due to gravity is 0.258g:

First, we need to find the acceleration due to gravity on the Moon:

g_Moon = 0.258g_Earth

g_Moon = 0.258(12.3 m/s^2)

g_Moon = 3.17 m/s^2

Now we can use the range formula for projectile motion to find the distance he could jump:

R = (v^2/g) sin(2θ)

Assuming the same initial velocity and angle of jump, we can rearrange the formula to solve for R:

R = (v^2/g) sin(^2/g_Earth) sin(2θ) * (g_Moon/g_Earth)

R = (1.31 m)^2/ (212.3 m/s^2) * sin(2θ) * (3.17 m/s^2) / (12.3 m/s^2)

R = 0.191 m

Therefore, he could jump approximately 0.191 m on the Moon.

!

a) On the Moon, where the acceleration due to gravity is 0.258g:

First, we need to find the acceleration due to gravity on the Moon:

g_Moon = 0.258g_Earth

g_Moon = 0.258(12.3 m/s^2)

g_Moon = 3.17 m/s^2

Now we can use the range formula for projectile motion to find the distance he could jump:

R = (v^2/g) sin(2θ)

Assuming the same initial velocity and angle of jump, we can rearrange the formula to solve for R:

R = (v^2/g) sin(

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^2/g_Earth) sin(2θ) * (g_Moon/g_Earth)

R = (1.31 m)^2/ (212.3 m/s^2) * sin(2θ) * (3.17 m/s^2) / (12.3 m/s^2)

R = 0.191 m

Therefore, he could jump approximately 0.191 m on the Moon.

b) On Mars, where the acceleration due to gravity is 0.293g:

Similarly, we need to find the acceleration due to gravity on Mars:

g_Mars = 0.293g_Earth

g_Mars = 0.293(12.3 m/s^2)

g_Mars = 3.61 m/s^2

Using the same formula and rearrangement as in part a, we can find the distance he could jump on Mars:

R = (1.31 m)^2/ (212.3 m/s^2) * sin(2θ) * (3.61 m/s^2) / (12.3 m/s^2)

R = 0.223 m

Therefore, he could jump approximately 0.223 m on Mars.

Answer: 12 meters

Explanation:

the rate is 4 meters per second
the rock rolled for 3 seconds
4 x 3 = 12

Answer:

Approximately [tex]2.05 \times 10^{8}\; {\rm m\cdot s^{-1}}[/tex].

Explanation:

The refractive index [tex]n[/tex] of a material is the ratio between the speed of light in vacuum [tex]c[/tex] and the speed of light [tex]v[/tex] in that material. In other words:

[tex]\begin{aligned}n &= \frac{c}{v}\end{aligned}[/tex].

The speed of light in vacuum is [tex]c \approx 3.00 \times 10^{8}\; {\rm m\cdot s^{-1}}[/tex].

It is given that the refractive index is [tex]n = 1.46[/tex]. Rearrange this equation to find [tex]v[/tex], the speed of light in this material:

[tex]\begin{aligned}v &= \frac{c}{n} \\ &\approx \frac{3.00 \times 10^{8}\; {\rm m\cdot s^{-1}}}{1.46} \approx 2.05 \times 10^{8}\; {\rm m\cdot s^{-1}}\end{aligned}[/tex].

Answer:

less than 100-J

Explanation:

The potential energy held in the stretched rubber band is turned into kinetic energy of the rock when it is released, assuming that the rubber band is used to launch a rock from a slingshot.

The mass of the rock and the effectiveness of the slingshot in transmitting the energy from the rubber band to the rock are two elements that affect how much kinetic energy the rock will have. To estimate the kinetic energy, though, we may make certain generalizations.

Assume that no energy is lost as a result of friction or air resistance and that the entire potential energy held in the rubber band is transformed into the kinetic energy of the rock. In this hypothetical situation, the potential energy of the stretched rubber band would be equal to the kinetic energy of the rock.

As a result, the rock will have 100 J of kinetic energy when it exits the slingshot if the rubber band contains 100 J of potential energy. The actual kinetic energy of the rock would be less than 100 J since some energy will be wasted owing to things like friction.

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If the object starts at position 12 on a horizontal line with a reference point of 0, then its initial position relative to the reference point is:

Initial position = Reference point + Object's position = 0 + 12 = 12

If the object then moves 14 units to the left, its new position relative to the reference point is:

New position = Initial position - Distance moved to the left = 12 - 14 = -2

Therefore, the position of the object is -2 units from the reference point, which means that it has moved 2 units to the left of the reference point.

Answer:

B. 1/2mv^2 + 1/2Iw^2

Explanation: