Luis takes 35 minutes to ride his bike 3 miles. He rode his bike 25 miles


last week. Which equation can be used to find t, the number of minutes


that Luis rode his bike last week?

The main types of markets are:

So, the correct answer is "consumer" and "industrial".

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The perimeter of the base of the triangular prism =

The area of the base of the triangular prism =

The total surface area of the triangular prism =

A triangular prism is a three-dimensional geometric shape that consists of two parallel triangular bases connected by three rectangular or parallelogram faces. The faces that connect the two bases are called lateral faces. The lateral edges are the edges that connect the lateral faces, and the base edges are the edges that form the triangles.

The perimeter of the base of the triangular prism

p = 10cm + 10cm + 12cm = 32cm

The area of the base of the triangular prism =

base area = (1/2) bh

= 1/2 × b × h = 1/2 × 12 × 8 = 48cm².

The total surface area of the triangular prism =  (Perimeter of the base × Length of the prism) + (2 × Base Area)

= (32 + 34) + (2 × 48) = 66 + 96 = 162cm².

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The component of b onto a is (-1/3, 2/3, -1/3).

To find the component of b onto a, we first need to find the projection of b onto a. The projection of b onto a is given by the formula:

proj_a(b) = (b dot a / ||a||^2) * a

where dot represents the dot product and ||a|| represents the magnitude of vector a.

We can calculate the dot product of a and b as follows:

a dot b = (-2*1) + (4*0) + (2*3) = 4

We can calculate the magnitude of a as follows:

||a|| = sqrt((-2)^2 + 4^2 + 2^2) = sqrt(24) = 2sqrt(6)

Now we can plug these values into the formula for the projection of b onto a:

proj_a(b) = (b dot a / ||a||^2) * a
proj_a(b) = (4 / (2sqrt(6))^2) * (-2, 4, 2)
proj_a(b) = (4 / 24) * (-2, 4, 2)
proj_a(b) = (-1/3, 2/3, -1/3)

Finally, the component of b onto a is simply the projection of b onto a:
comp_a(b) = (-1/3, 2/3, -1/3)
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A. The partial derivatives are not equal, F is not conservative, potential function f(x, y) = N

B. The partial derivatives are equal, F is conservative, potential function f(x, y) = -3xy - [tex]x^2[/tex] + C

C. The partial derivatives are not equal, F is not conservative, potential function f(x, y, z) = N

D. The partial derivatives are not equal, F is not conservative, potential function f(x, y, z) = N

E. The partial derivatives are not equal, F is not conservative, potential function f(x, y, z) = N

A. F(x, y) = (-6x – 7y) i +(-7x + 14y)j

To check if F is conservative, we compute the partial derivatives:

∂F/∂y = -6i - 7j

∂F/∂x = -7i + 14j

Since the partial derivatives are not equal, F is not conservative.

Potential function f(x, y) = N

B. F(x, y) = -3yi – 2xj

To check if F is conservative, we compute the partial derivatives:

∂F/∂y = -3i

∂F/∂x = -2j

Since the partial derivatives are equal, F is conservative.

Potential function f(x, y) =[tex]-3xy - x^2 + C[/tex], where C is a constant.

C. F(x, y, z) = -3xi – 2yj+k

To check if F is conservative, we compute the partial derivatives:

∂F/∂x = -3i

∂F/∂y = -2j

∂F/∂z = k

Since the partial derivatives are not equal, F is not conservative.

Potential function f(x, y, z) = N

D. F(x, y) = (-3 sin y)i + (-14y – 3x cosy)j

To check if F is conservative, we compute the partial derivatives:

∂F/∂y = -3cosy j - 14i

∂F/∂x = -3cosy j

Since the partial derivatives are not equal, F is not conservative.

Potential function f(x, y) = N

E. [tex]F(x, y, z) = -3xi - 7yj + 7z^2k[/tex]

To check if F is conservative, we compute the partial derivatives:

∂F/∂x = -3i

∂F/∂y = -7j

∂F/∂z = 14zk

Since the partial derivatives are not equal, F is not conservative.

Potential function f(x, y, z) = N

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The area of the triangle is 6 cm².

Let's denote the width of the triangle as "w." According to the given information, the length of the triangle is three times its width, so the length can be expressed as "3w."

The perimeter of a rectangle is given by the formula: Perimeter = 2(length + width). In this case, the perimeter of the rectangle is given as 24 cm.

We can set up the following equation based on the given information:

24 = 2(3w + w)

Simplifying the equation:

24 = 2(4w)

12w = 24

w = 24/12

w = 2 cm

Now that we have the width of the triangle, we can find the length:

Length = 3w = 3 * 2 = 6 cm

The area of a triangle is given by the formula: Area = (base * height) / 2. In this case, the base of the triangle is the width (2 cm) and the height is the length (6 cm).

Area = (2 * 6) / 2

Area = 12 / 2

Area = 6 cm²

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By using Mai’s method, the skirt will cost $21.67, By using Elena’s method, the skirt will cost $21 and I think Mai’s method is correct.

(1) We need to find out how much the skirt cost if we use the Mai method. the Mai method is to multiply $30 by 0.80 and then we need to again multiply it with the result which can be given as,

= 30 × 0. 85 × 0. 85

= 21.67

Therefore, By using Mai’s method, the skirt will cost $21.67.

(2) We need to find out how much the skirt cost if we use Elena’s method. Elena’s method is to  multiply $30 by 0. 70 it can be given as,

= 30 × 0. 70

=$21

Therefore, By using Elena’s method, the skirt will cost $21.

(3) I think Mai’s method is correct because she took one 15% discount first and then considered the second discount which is given by the shop. whereas  Elena considered the two discounts at once and calculated it as 30% where the shop offered a 15% discount on the dress and then added a second discount on the purchase cost or bill amount that is why Mai’s method is correct.

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The center of mass is given by:
(xbar, ybar, zbar) = (Mx/m, My/m, Mz/m)
                  = (0, 16/(3π), 16/(3π))

To find the mass of the wire, we need to integrate the density function over the length of the wire. The length of the wire can be found using the arc length formula:

ds = sqrt(dx^2 + dy^2 + dz^2)
  = sqrt(1 + 4sin^2(t) + 4cos^2(t)) dt
  = sqrt(5) dt

Integrating this from 0 to 2π gives us the length of the wire:

L = ∫_0^(2π) sqrt(5) dt
 = 2πsqrt(5)

Now we can find the mass of the wire:

m = ∫_0^(2π) ρ ds
 = ∫_0^(2π) (x^2 + y^2 + z^2) ds
 = ∫_0^(2π) (t^2 + 4cos^2(t) + 4sin^2(t)) sqrt(5) dt
 = 4πsqrt(5)

To find the center of mass, we need to find the moments about each coordinate axis:

Mx = ∫_0^(2π) ρ x ds
  = ∫_0^(2π) t(t^2 + 4cos^2(t) + 4sin^2(t)) sqrt(5) dt
  = 0 (due to symmetry)

My = ∫_0^(2π) ρ y ds
  = ∫_0^(2π) 2cos^2(t) (t^2 + 4cos^2(t) + 4sin^2(t)) sqrt(5) dt
  = 32π/(3sqrt(5))

Mz = ∫_0^(2π) ρ z ds
  = ∫_0^(2π) 2sin^2(t) (t^2 + 4cos^2(t) + 4sin^2(t)) sqrt(5) dt
  = 32π/(3sqrt(5))

Finally, the center of mass is given by:

(xbar, ybar, zbar) = (Mx/m, My/m, Mz/m)
                  = (0, 16/(3π), 16/(3π))

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a. Sin A = opposite/hypotenuse = √15/4

b.  (Sin A + Cos B) ÷ 2 = (Sin A + Cos B)/2

c.  Tan A  = 1/5

The both angle could be of same size

Since Cos A = adjacent/hypotenuse,

Applying  the Pythagorean theorem,

we can find the opposite side:

opposite^2 + 1^2 = 4^2

opposite^2 = 16 - 1

opposite = √15

Now we can find the value of Sin A:

Sin A = opposite/hypotenuse = √15/4

b.

Sin A + Cos B = (Sin A) + (Cos B)

(Sin A + Cos B) ÷ 2 = (Sin A + Cos B)/2

c. Since Tan B = opposite/adjacent,  

we use  Pythagorean theorem to  find the hypotenuse:

hypotenuse^2 = 5^2 + 1^2

hypotenuse = √26

Tan A = opposite/adjacent = 1/5

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The temperature are the times  indicated are:

T( 0) =   5.800°

T( 0.22) = -4.9094 °

T (0.44) = -2.6792 °

T(0.66) = 2.3244°

T(0.88)  = 4.8184°

T(1.1) = -4.1686 °

To solve the above, we need to use the formuala that we given which is T(x) = 5.8cos(3.8πx)

Entering the various values of x, can can obtain

T(0) = 5.8 cos (3.8π  (0) )  = 5.8cos(0) = 5.800

T(0.22) = 5.8 cos (3.8  π(0.22)) ≈ -4.9094

T(0.44) = 5.8cos (3.8π (0.44) ) ≈ -  2.6792

T(0.66) = 5.8cos(3.8π (0.66)) ≈ 2.3244

T(0.88) = 5.8cos(3.8π(0.88)) ≈ 4.8184

T(1.1) = 5.8 cos(3.8π(1.1  )) ≈ -4.1686

So the above answers are correct.

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It takes about 1.5 seconds for the ball to hit the ground.

To find how long it takes for the ball to hit the ground, we need to find the value of x when h(x) = 0, since the height of the ball is 0 when it hits the ground. We can set -16x²+36 = 0 and solve for x:

-16x²+ 36 = 0

Dividing both sides by -16:

x² - 2.25 = 0

Adding 2.25 to both sides:

x²= 2.25

Taking the square root of both sides (we can ignore the negative root since time cannot be negative):

x = √(2.25) ≈ 1.5

Therefore, it takes about 1.5 seconds for the ball to hit the ground.

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In this scenario, the domain would be the set of all possible values for the amount of time it takes Sammy Speedster to drive from Houston to San Antonio. Since he is driving on a daily basis, the domain could be considered a continuous range from zero to some maximum value, perhaps 10 hours.

It's possible that Sammy could complete the trip in less than 3 hours if he were driving at a very high speed, but this would not be a common occurrence. Therefore, a reasonable domain could be considered to be between 3 and 10 hours.

The range, on the other hand, would be the set of all possible distances that Sammy could drive in the allotted time. Since we know that the distance is a constant 200 miles, the range would simply be 200 miles. It's possible that Sammy could drive more than 200 miles in a day if he were assigned additional routes, but this would not be relevant to this scenario.

In summary, a reasonable domain for Sammy's logbook would be between 3 and 10 hours, and the range would be a constant 200 miles.

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The linearization of the function f(x, y) = e-¹⁰x-⁸y - 8y at (0, 0) is L(x, y) = -10x - 8y + 1. The correct option is C.

To find the linearization of the given function at the point (0, 0), we need to compute the partial derivatives with respect to x and y and then evaluate them at the given point.

The function is f(x, y) = [tex]e^{(-10x-8y)[/tex] - 8y.

First, find the partial derivative with respect to x:
∂f/∂x = [tex]-10e^{(-10x-8y).[/tex]

Now, evaluate ∂f/∂x at (0, 0):
∂f/∂x(0, 0) = [tex]-10e^{(0)[/tex] = -10.

Next, find the partial derivative with respect to y:
∂f/∂y = [tex]-8e^{(-10x-8y)[/tex] - 8.

Now, evaluate ∂f/∂y at (0, 0):
∂f/∂y(0, 0) = [tex]-8e^{(0)[/tex] - 8 = -8 - 8 = -16.

Now, we can form the linearization:
L(x, y) = f(0, 0) + ∂f/∂x(0, 0)(x - 0) + ∂f/∂y(0, 0)(y - 0).

Evaluate f(0, 0):
f(0, 0) = [tex]e^{(-10(0)-8(0))} - 8(0) = e^{(0)} - 0 = 1.[/tex]

Finally, substitute the values into the linearization formula:
L(x, y) = 1 - 10x - 16y.

Comparing to the given options, the answer is:
C) L(x, y) = -10x - 8y + 1

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The solution set for the equation 1/2 = 1/3 - |(x-3/6)+x| is {1/12, -1/12}.

To solve the equation 1/2 = 1/3 - |(x-3/6)+x|, we need to isolate the absolute value expression and solve for x in two cases.

Case 1: (x-3/6)+x is nonnegative, which means the absolute value can be removed.

1/2 = 1/3 - (x-3/6)-x

1/2 = 1/3 - 2x + 1/2

2x = 1/6

x = 1/12

Case 2: (x-3/6)+x is negative, which means the absolute value must be flipped.

1/2 = 1/3 + (x-3/6)+x

1/2 = 1/3 + 2x - 1/2

2x = -1/6

x = -1/12

Therefore, the solution set is {1/12, -1/12}.

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The equation that represents the Ferrells' savings after x months is y = 150x

In this equation, x represents the number of months that the Ferrells have been saving, and y represents the amount of money they have saved after x months.

The coefficient 150 represents the amount of money the Ferrells save each month, and it is multiplied by the number of months x to get the total savings y. For example, after 5 months of saving, the Ferrells would have saved:

y = 150(5) = $750

This equation can be used to calculate their savings at any point in time, as long as they continue to save $150 each month.

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The length and width of the chocolate bar is 14.5 feet and 7.6 feet.

What is length?

Length is a measure of the size of an object or distance between two points. It refers to the extent of something along its longest dimension, or the distance between two endpoints.

What is width?

Width refers to the measure of the distance from one side of an object to the other side, perpendicular to the length. In geometry, width is usually measured in units such as meters, feet, or inches.

According to the given information:

Let's start by assigning variables to represent the length and width of the chocolate bar. Let x be the width of the chocolate bar in feet. Then, according to the problem:

The length of the chocolate bar is 0.3 feet shorter than twice its width, which means the length is (2x - 0.3) feet.

The base area of the chocolate bar is given as 61.04 square feet. We can use this information to set up an equation:

x(2x - 0.3) = 61.04

Expanding the left side of the equation:

2x^2 - 0.3x = 61.04

Moving all the terms to one side of the equation:

2x^2 - 0.3x - 61.04 = 0

Now we can solve for x using the quadratic formula:

x = (-b ± sqrt(b^2 - 4ac)) / 2a

where a = 2, b = -0.3, and c = -61.04. Substituting these values and simplifying:

x = (0.3 ± sqrt(0.3^2 + 4(2)(61.04))) / (2(2))

x ≈ 7.6 or x ≈ -4.0

Since the width of the chocolate bar cannot be negative, we can discard the negative solution. Therefore, the width of the chocolate bar is approximately 7.6 feet.

To find the length, we can use the equation we set up earlier:

length = 2x - 0.3

Substituting x = 7.6:

length = 2(7.6) - 0.3

length ≈ 14.5

Therefore, the length of the chocolate bar is approximately 14.5 feet and the width is approximately 7.6 feet.

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Let's first calculate the total cost of using Green Lawns for 30 weeks. We can use the formula for the sum of a geometric series to do this:

Total cost of Green Lawns =[tex]2(1 - 0.9^30) / (1 - 0.9) + 0.9^30 * 2[/tex]

Total cost of Green Lawns = [tex]2(1.7379) / 0.1 + 0.0359[/tex]

Total cost of Green Lawns = 38.8179

Now let's calculate the total cost of using Green Thumbs for 30 weeks:

Total cost of Green Thumbs = [tex]400 + 40 * 29[/tex]

Total cost of Green Thumbs = 1160

Therefore, the Yert family would save:

$1160 - $38.8179 = $1121.18

So the Yert family would save $1,121.18 by choosing Green Lawns over Green Thumbs for 30 weeks.

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The probability of getting a number less than 5 or greater than 9 is:

P = 0.583

The probability is equal to the quotient between the number of outcomes for the given event and the total number of outcomes.

The numbers that are less than 5 or greater than 9 are:

{1, 2, 3, 4, 10, 11, 12}

So 7 out of the total of 12 outcomes make the event true, then the probability we want to get is the quotient between these numbers:

P = 7/12 = 0.583

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The probability that four boys are given the first four seats on the first teacup is approximately equal to 0.004.

To determine the probability that four boys are given the first four seats on the first teacup.

The total number of ways to distribute 12 tickets among 12 seats is 12! (12 factorial), which is equal to 479,001,600.

We need to find the number of ways that four boys can be selected from the seven boys, multiplied by the number of ways that eight people (including the remaining three boys and five girls) can be selected from the ten remaining people,

multiplied by the number of ways that the selected people can be arranged on the teacup ride.

The number of ways to select four boys from seven boys is 7C4, which is equal to 35. The number of ways to select eight people from the remaining ten people is 10C8, which is equal to 45.

Finally, the number of ways to arrange the selected twelve people on the teacup ride is 4!, which is equal to 24.

Therefore, the probability that four boys are given the first four seats on the first teacup is (35 x 45 x 24) / 12!, which is approximately equal to 0.004.

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The missing angle for x by the measures add up to 90° is 53°

Complementary angles are pairs of angles whose measures add up to 90°. In this problem, we are given two angles, one of which measures 37°, and the other of which has an unknown measure that we will call x. We are also told that these angles are complementary, which means that their measures add up to 90°.

So, we can set up an equation to represent this relationship:

37 + x = 90

We can simplify this equation by subtracting 37 from both sides:

x = 90 - 37

x = 53

Now we know that the measure of the second angle is 53°. But we can go further and solve for x to get a more complete solution.

In the problem statement, we are also given an expression for the second angle in terms of x:

5x + 3

We know that this angle measures 53°, so we can set up another equation to represent this relationship:

5x + 3 = 53

We can solve for x by first subtracting 3 from both sides:

5x = 50

Then, we can divide both sides by 5 to isolate x:

x = 10

Now we know that x has a value of 10, and we can substitute this value back into the expression for the second angle to find its measure:

= 5x + 3

= 5(10) + 3 = 53

Therefore, the missing angle is 53°, and x has a value of 10.

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In order to evaluate h'(9), we need to use the product rule, which states that the derivative of a product of two functions is equal to the first function times the derivative of the second function, plus the second function times the derivative of the first function. Mathematically, this can be expressed as:

(h(x))' = f(x)g'(x) + g(x)f'(x)

Using the given values, we can substitute them into the formula and solve for h'(9):

h'(x) = f(x)g'(x) + g(x)f'(x)
h'(9) = f(9)g'(9) + g(9)f'(9)
h'(9) = 9(2) + 3(-1.5)
h'(9) = 18 - 4.5
h'(9) = 13.5

Therefore, the value of h'(9) is 13.5.

In simpler terms, the product rule tells us that when we have a function that is the product of two other functions, we can find the derivative of that function by multiplying one function by the derivative of the other and adding it to the other function multiplied by the derivative of the first. In this case, we have two functions f(x) and g(x), and we use their respective values and derivatives to find the derivative of their product h(x).

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The percent of the phosphorus-32 decays each day is 0.56%.

The formula for the amount of radioactive isotope remaining after t days is given as:

y = a(0.5)^(t/14)

To find the percent of phosphorus-32 that decays each day, we need to find the fraction of the initial amount that decays each day. This can be found by subtracting the amount remaining after one day from the initial amount, and then dividing by the initial amount:

fraction decayed in one day = (a - a(0.5)^(1/14)) / a

Simplifying this expression gives:

fraction decayed in one day = 1 - (0.5)^(1/14)

To find the percent decayed in one day, we multiply by 100:

percent decayed in one day = 100(1 - (0.5)^(1/14))

Using a calculator, we get:

percent decayed in one day ≈ 0.56%

Therefore, the percent of phosphorus-32 that decays each day is approximately 0.56%.

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Answer: x ≅ -0.9 or -1.8

Step-by-step explanation:

[tex]3(3x+4)^2 - 6 = 0[/tex]

[tex]3(3x+4)^2 = 6[/tex]

[tex]3(9x^2+24x+16) = 6[/tex]

[tex]9x^2+24x+16 = 2[/tex]

[tex]9x^2+24x+14 = 0[/tex]

Use the quadratric formula to get:

x ≅ -0.9 or -1.8

Answer:

Modise is right.

This diagram does not represent a function because each input value does not correspond to exactly one output value. The input value 5 corresponds to two outputs, 2 and 9.

Answer:

$7973.26

Step-by-step explanation:

PV = $6700

i = 5.8% ÷ 365

n = 3 years · 365

Compound formula

FV = PV (1 + i)^n

FV = 6700 (1 + 5.8% ÷ 365)^(3 · 365)

FV = $7973.26 (rounded to the nearest cent)

Answer:

The value of Eva's investment after 3 years will be approximately $8,108.46. Rounded to the nearest cent, this is $8,108.45.

Step-by-step explanation:

We can use the formula for compound interest:

where:

In this case, we have:

Plugging these values into the formula, we get:

Therefore, the value of Eva's investment after 3 years will be approximately $8,108.46. Rounded to the nearest cent, this is $8,108.45.

The function f(x) = –2x^3 + 39x^2 -216x + 6 has one local minimum at x = 4 and one local maximum at x = 9.

To determine if the function f(x) = –2x^3 + 39x^2 -216x + 6 has a local minimum or maximum, we need to find the critical points of the function and then determine the nature of those critical points.

First, we take the derivative of the function to find the critical points:

f(x) = –2x^3 + 39x^2 -216x + 6

f'(x) = –6x^2 + 78x - 216

f'(x) = –6(x^2 - 13x + 36)

f'(x) = –6(x - 4)(x - 9)

Setting f'(x) = 0, we get:

–6(x - 4)(x - 9) = 0

This gives us two critical points at x = 4 and x = 9.

To determine the nature of these critical points, we need to look at the sign of the derivative on either side of each critical point.

When x < 4, we have:

f'(x) = –6(x^2 - 13x + 36) < 0

When 4 < x < 9, we have:

f'(x) = –6(x^2 - 13x + 36) > 0

When x > 9, we have:

f'(x) = –6(x^2 - 13x + 36) < 0

This means that f(x) is decreasing on the interval (–∞, 4), increasing on the interval (4, 9), and decreasing on the interval (9, ∞). Therefore, we have a local minimum at x = 4 and a local maximum at x = 9.

To confirm this, we can evaluate the function at these critical points:

f(4) = –2(4)^3 + 39(4)^2 -216(4) + 6 = –26

f(9) = –2(9)^3 + 39(9)^2 -216(9) + 6 = 603

Therefore, the function f(x) = –2x^3 + 39x^2 -216x + 6 has one local minimum at x = 4 and one local maximum at x = 9.

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If your rate of pay is $36 per hour and you bill by the quarter hour, you would bill $162 for 4 hours and 30 minutes project.

Based on the given information, your rate of pay is $36 per hour, and you bill by the quarter hour. You spent 4 hours and 30 minutes on a client project.

To calculate the bill, first convert the 30 minutes into quarter hours: 30 minutes = 2 quarter hours. In total, you worked for 4 hours and 2 quarter hours (18 quarter hours).

Now, multiply your rate of pay ($36) by the number of quarter hours (18) and divide by 4 to account for the quarter hour billing: ($36 * 18) / 4 = $162. Therefore, you would bill the client $162 for the project.

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x = -5, dx/dt is equal to -2/25.

To find dx/dt, we need to use the chain rule of differentiation.

We know that dy/dt = -4 and we have the equation y = -5x^2 + 2.

Taking the derivative of both sides with respect to t, we get:

dy/dt = d/dt (-5x^2 + 2)

Using the chain rule, we can write this as:

dy/dt = (-10x) (dx/dt)

Now, we can plug in x = -5 and dy/dt = -4:

-4 = (-10(-5)) (dx/dt)

Simplifying, we get:

-4 = 50 (dx/dt)

Dividing both sides by 50, we get:

dx/dt = -4/50

Simplifying further, we get:

dx/dt = -2/25

Therefore, at x = -5, dx/dt is equal to -2/25.

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To determine this family's annual medical aid tax credit, we need to consider their medical aid expenses for the year. Medical aid expenses are expenses related to medical services that are not covered by the government or medical insurance.

This family can claim a tax credit of up to R310 per month for the main member and the first dependent, and R209 per month for each additional dependent. This tax credit is only applicable to registered medical schemes and is deducted from the tax payable.

In addition to medical aid expenses, this family will also need to consider the 15% VAT payable on all goods and services, except for sanitary pads, fresh produce, and a few other staple food items. This means that if this family spends R10,000 on goods and services, they will need to pay an additional R1,500 in VAT.

However, the good news is that they won't have to pay VAT on their fresh produce and staple food items. This will help to reduce their overall expenditure on food, which is an essential expense for every family.

In conclusion, while this family will need to pay VAT on most goods and services, they can claim a tax credit for their medical aid expenses. Additionally, they won't have to pay VAT on fresh produce and staple food items, which will help to reduce their overall food expenditure.

By carefully managing their expenses and taking advantage of tax credits and exemptions, this family can ensure that they are able to provide for their essential needs while also managing their financial obligations.

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This system represents the purchase made by Muriel (2 boxes of pencils and 4 erasers for $11) and Ramon (1 box of pencils and 3 erasers for $7).

The correct system of equations to find the price of one box of pencils (p) and one eraser (e) is:

2p + 4e = 11

p + 3e = 7

This system represents the purchase made by Muriel (2 boxes of pencils and 4 erasers for $11) and Ramon (1 box of pencils and 3 erasers for $7).

By solving this system of equations, you can determine the individual prices for a box of pencils and an eraser.

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