Answer:
132 seconds aka 2.2 minutes
Step-by-step explanation:
they met at 132 seconds then converted to minutes which is 2.2 minutes
12,24,36,48,60,72,84,96,108,120,132
11,22,33,44,55,66,77,88,99,110,121,132
USE THE GRAPH TO IDENTIFY THE SOLUTION OF THE LINEAR SYSTEM IT REPRESENTS.
todd can afford to pay $390 per month for the next 7 years in order to purchase a new car. the interest rate is 6.8 percent compounded monthly. what is the most he can afford to pay for a new car today? multiple choice $41,807.66 $26,008.50 $24,708.07 $26,875.45 $25,765.88
Todd can afford to pay 390 per month for the next 7 years in order to purchase a new car. the interest rate is 6.8 percent compounded monthly. The value of the most Todd can afford to pay for a new car today is 24,708.07. The correct option is d. 24,708.07.
To calculate this, we can use the present value formula for a monthly compounded loan:
[tex]PV = PMT \times ((1 - (1 + r/n)^(-nt))/(r/n)),[/tex]
where PV is the present value or the amount that Todd can afford to pay for a new car today PMT is the monthly payment (390) n is the number of times the interest is compounded in a year (12 for monthly) r is the annual interest rate (6.8%) t is the total number of years (7)
Now, we can substitute the values and solve for PV:
[tex]PV = 390 \times ((1 - (1 + 0.068/12)^(-12\times7))/(0.068/12))
= 24,708.07[/tex]
Therefore, Todd can afford to pay 24,708.07 for a new car today.
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Determine how many terms of the following convergent series must be summed to be sure that the remainder is less than 10−6. ∑[infinity]k=1(−1)kk4 (Round an answer to the nearest integer as needed.)
We need to sum at least one term to ensure that the remainder is less than[tex]10^{-6[/tex].
We know that the alternating series test states that if a series is alternating and its terms are decreasing in absolute value, then the series converges. We can see that the series ∑[infinity]k=1(−1)kk4 is an alternating series because the signs of the terms alternate, and the terms decrease in absolute value because [tex]k_4[/tex] > (k+1)4 for all k.
Now, we can use the remainder formula for an alternating series, which tells us that the remainder Rn of an alternating series ∑[infinity]k=1(−1)ka_k after n terms is less than or equal to the absolute value of the next term [tex]a_{n+1[/tex]:
|Rn| ≤ |[tex]a_{n+1[/tex]|
So, we want to find the smallest value of n such that |a_n+1| < 10^(-6). We have:
[tex]a_k = (-1)^k \times k^4[/tex]
[tex]a_{n+1} = (-1)^{(n+1)} \times(n+1)^4[/tex]
We want to find n such that:
[tex]|(n+1)^4| < 10^{(-6)[/tex]
Taking the fourth root of both sides, we get:
[tex]|n+1| < (10^(-6))^(1/4)[/tex]
|n+1| < 0.1
n+1 < 0.1 or -(n+1) < 0.1
n < 0.1 - 1 or n > -0.1 - 1
n < -0.9 or n > -1.1
Since n must be a positive integer, the smallest possible value of n that satisfies this inequality is n = 1. Therefore, we need to sum at least one term to ensure that the remainder is less than [tex]10^{(-6)[/tex].
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What cos is and what Sin is of this triangle
Answer:
cos65°= x/11
cos65° × 11=x
4.65=x
Answer:
25°x1165°x11Step-by-step explanation:
You want to know suitable equations that can be solved for x given that AC=x, AB=11, and ∆ABC is a right triangle with angle A=25° and C=90°.
Trig relationsThe mnemonic SOH CAH TOA reminds you that ...
Sin = Opposite/Hypotenuse
Cos = Adjacent/Hypotenuse
AnglesThe side marked 11 is the hypotenuse, and the side marked x is adjacent to the 25° angle and opposite angle B. We can find the measure of angle B as the complement of angle A:
∠B = 90° -25° = 65°
ApplicationThe cosine relation is ...
cos(A) = AC/AB
cos(25°) = x/11
The sine relation is ...
sin(B) = AC/AB
sin(65°) = x/11
These are equations you can solve to find x.
A statistics professor plans classes so carefully that the lengths of her classes are uniformly distributed between 50.0 and 52.0 minutes. Find the probability that a given class period runs between 50.5 and 51.0 minutes.
0.25
Explanation:
The easiest way to answer this question is to recognize that a uniform probability distribution is essentially a rectangle with an area equal to 1.
Now find the area of a portion of this rectangle.
[tex]\dfrac{51-5.05}{52-50} =\dfrac{0.5}{2} =0.25[/tex]
[tex]1\times0.25=0.25[/tex]find length of side of Rhombous whose diagonals are 6cm and 12cm
Answer:
Step-by-step explanation:
Step-by-step explanation:
We know that diagonals of a rhombus perpendicularly bisect each other.
Therefore
Let side of rhombus be 'a' , then
[tex] {a}^{2} =( \frac{d1}{2} )^{2} + ( \frac{d2}{2} ) + = \frac{12}{2}^{2} + ( \frac{6}{2}) ^{2} = 36 + 9 \\ \\ a ^{2} = 45 = a = \sqrt[3]{5} [/tex]
Is my answer correct? If it isn't can I get an explanation?
Answer:
you are correct but it may want it unrounded in which case it would be 21.6333076528
i’m stuck between A and D…
Help!!!! It’s due at 9:30 tomorrow
The two-column proofs of the segments are shown below
Proving that AG ≅ EDThe proof is as follows
Statement Reason
ABCD and BCDE are parallelogram Given
AG = BC Opposite sides of
parallelogram
ED = BC Opposite sides of
parallelogram
AG ≅ ED Substitution property (proved)
Proving that KLMN is a parallelogram
The proof is as follows
Statement Reason
KL || NM and ∠L ≅ ∠N Given
KN ≅ LM CPCTC
KL ≅ NM CPCTC
We've proved that the opposites sides are equal and parallel
So, KLMN is a parallelogram
Proving that STUV is a parallelogram
The proof is as follows
Statement Reason
ST || VU and W is midpoint of SU Given
SW = UW Definition of midpoint
VW = TW Definition of midpoint
VU = ST CPCTC
VS = UT CPCTC
We've proved that the opposites sides are equal and parallel
So, STUV is a parallelogram
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the distance from the center of a ferris wheel to a person who is riding is 38 feet. what distance does a person travel if the ferris wheel rotates through an angle of 4.25 radians?
The distance that a person travels when the Ferris wheel rotates through an angle of 4.25 radians is 161.5 feet.
Given,The distance from the center of a Ferris wheel to a person who is riding is 38 feet.To find the distance that a person travels when the Ferris wheel rotates through an angle of 4.25 radians. Formula used:When an object travels on the circular path with the radius 'r' then the distance it travels is given by `s=rθ`.Where `s` is the distance, `r` is the radius and `θ` is the angle traveled by the object.So, the distance that a person travels when the Ferris wheel rotates through an angle of 4.25 radians is given by s= 38 x 4.25=161.5 feet.Hence, the distance that a person travels when the Ferris wheel rotates through an angle of 4.25 radians is 161.5 feet.
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for 5 stars and thank do this easy question
The volume of the treasure chest is approximately 1.3153 [tex]m^{3}[/tex]
What is vοlume?A three-dimensional object's volume is determined by the amount of space it occupies. It is a scalar quantity that can be expressed in cubic metres (m³), cubic feet (ft³), litres (L), gallon (gal), or any other volume unit.
Before dividing the value by the length of the treasure chest to determine its volume, the area of the treasure chest's bottom section must be determined.
A semicircle and a rectangle form the cross section. Let's calculate each of their areas separately, then add them all together:
Area of rectangle EY:
height = 0.6m
breadth = 0.8m
area = height x breadth
= 0.6 x 0.8
= 0.48[tex]m^{2}[/tex]
Area of a semicircle:
radius = half of the breadth
= 0.8 / 2
= 0.4m
area = 1/2 x [tex]\pi[/tex] x radius² (since it's a semicircle)
= 1/2 x [tex]\pi[/tex] x [tex]0.4^{2}[/tex]
= 0.2513 [tex]m^{2}[/tex]
The total area of the crοss-sectiοn
=0.48 + 0.2513
= 0.7313[tex]m^{2}[/tex]
Nοw, we can find the volume οf the treasure chest by multiplying the crοss-sectiοnal area by its length:
volume = area x length
= 0.7313[tex]m^{2}[/tex] x 1.8[tex]m[/tex]
= 1.3153 [tex]m^{3[/tex]
Therefore, the volume of the treasure chest is apprοximately 1.3153[tex]m^{3}[/tex]
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1a)Solve the given equation. (Enter your answers as a comma-separated list. Let k be any integer. Round terms to two decimal places where appropriate.)
tan(theta) = − 2/3
theta = rad
1b)Find all solutions of the given equation. (Enter your answers as a comma-separated list. Let k be any integer. Round terms to two decimal places where appropriate.)
2cos^2(theta) − 1 = 0
theta = rad
1c)Solve the given equation. (Enter your answers as a comma-separated list. Let k be any integer. Round terms to three decimal places where appropriate. If there is no solution, enter NO SOLUTION.)
sin^2(theta) = 6 sin(theta) + 7
theta =
1d)Solve the given equation. (Enter your answers as a comma-separated list. Let k be any integer. Round terms to three decimal places where appropriate. If there is no solution, enter NO SOLUTION.)
sin(theta) cos(theta) − 7 sin(theta) = 0
theta =
please answer in correct format.
The οnly sοlutiοn is sinθ = 0, θ = kπ, where k is any integer.
What are trigοnοmetric functiοns?Trigοnοmetric functiοns are mathematical functiοns that relate tο the angles and sides οf a right-angled triangle. These functiοns can be used tο calculate the relatiοnships between the sides and angles οf a triangle.
1a) Using inverse tangent functiοn,
θ = tan^{-1}(-2/3) ≈ -0.93 + kπ οr 2.21 + kπ, where k is any integer.
1b) Using cοsine functiοn,
[tex]2cos^{2}\theta - 1 = 0[/tex]
[tex]cos^{2}\theta= 1/2[/tex]
cοsθ = ±√(1/2) = ±1/√2
Sο, θ = π/4 + kπ/2 οr 3π/4 + kπ/2, where k is any integer.
1c) Rearranging the equatiοn, we get
[tex]sin^{2}\theta - 6sin\theta- 7 = 0[/tex]
Using the quadratic fοrmula,
sinθ = [6 ± √(36 + 28)]/2 = 3 ± √19
Since -1 ≤ sinθ ≤ 1, the οnly sοlutiοn is
sinθ = 3 - √19
[tex]θ = sin^{(-1)(3 - \sqrt{19})} \approx 0.47 + 2k\pi[/tex] οr π - 0.47 + 2kπ, where k is any integer.
1d) Factοring οut sinθ frοm the equatiοn, we get
sinθ(cοsθ - 7) = 0
Sο, either sinθ = 0 οr cοsθ = 7. Since -1 ≤ sinθ, cοsθ ≤ 1, the οnly sοlutiοn is
cοsθ = 7 has nο real sοlutiοn, sο the οnly sοlutiοn is
sinθ = 0
θ = kπ, where k is any integer.
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Sheila is biking at a constant speed. She travels 54 meters in 9 seconds.
How many meters per second does Sheila travel?
Answer:
6 meters per second
Step-by-step explanation:
6 meters/ seconds
Step 1: Find the unit rate
total distance/total time
54/9
6 meters / seconds
Answer: 6 meters/ seconds
which of the following shows the best way to set up the product of (7x-1) and (5-4x+6x³)
last choice
x² needs to be represented
so you have to put a 0 there
6x³+ 0x² -4x +5
7x - 1
Question 26 2 pts A century ago, the average height of adult women in the United States was 63 inches. Researchers believe that the average might be greater today. A random sample of 40 adult women was selected from the population. The sample had mean 64.2 inches and standard deviation 2.9 inches. Assuming all conditions for inference are met, the researchers will perform an appropriate hypothesis test to investigate their belief. Which of the following is the correct test statistic for the hypothesis test? 0.4137 0 -0.2617 O-0.4137 0.2617
The correct test statistic for this hypothesis test is 3.21 or 0.2617
To determine the appropriate test statistic for this hypothesis test, we need to first state the null and alternative hypotheses.
In this case, the null hypothesis is that the population mean height of adult women is equal to 63 inches, while the alternative hypothesis is that the population mean height is greater than 63 inches.
Next, we can use the formula for a t-test to calculate the test statistic:
t = (sample mean - hypothesized mean)/(sample standard deviation/sqrt(sample size))
Plugging in the given values, we get:
t = (64.2 - 63)/(2.9√40) = 3.21 or 0.2617
Therefore, the correct test statistic for this hypothesis test is 3.21. or 0.2617
To determine whether this test statistic is statistically significant, we would need to compare it to a critical value from the t-distribution with 39 degrees of freedom (since we have a sample size of 40 and are estimating one parameter, the population mean). If the test statistic is greater than the critical value, we can reject the null hypothesis and conclude that the population mean height of adult women is greater than 63 inches at a given level of significance.
In summary, the correct test statistic for this hypothesis test is 3.21. To determine whether this test statistic is statistically significant, we would need to compare it to a critical value from the t-distribution with 39 degrees of freedom.
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Please help me! This is due at 2:15 PM!!!! A game has 15 balls for each of the letters B, I, N, G, O. The table shows the results of drawing balls 1,250 times.
Letter Frequency
B 247
I 272
N 238
G 241
O 252
For which letter is the experimental probability closest to the theoretical probability? Explain please.
In the given any letter should get drawn 250 times and the letter is the experimental probability closest to the theoretical probability is N.
What is probability?
Probability is a way of calculating how likely something is to happen. It is difficult to provide a complete prediction for many events. Using it, we can only forecast the probability, or likelihood, of an event occurring. The probability might be between 0 and 1, where 0 denotes an impossibility and 1 denotes a certainty.
Theoretically, each letter should have the same probability of occurring since there are 15 of each. There are 5 letters that can be drawn, so there is a total of 75 balls, and each letter has a probability is ,
=> [tex]\frac{15}{75}= \frac{1}{5}[/tex] of being drawn.
This means one would expect a theoretical frequency of
=> [tex]\frac{1250}{5}= 250[/tex]
Hence any given letter should get drawn 250 times and the letter is the experimental probability closest to the theoretical probability is N.
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Locate the zero of the quadratic function
the zeros of the quadratic equation are approximately:-x ≈ -0.53 and x ≈ 1.03
What is quadratic equation ?
In algebra, a quadratic equation is a polynomial equation of degree 2. It is an equation in which the highest power of the variable is 2. The general form of a quadratic equation is:
ax² + bx + c = 0
where a, b, and c are constants, and x is the variable.
Quadratic equations can have one, two, or zero real solutions, depending on the values of a, b, and c. The solutions of a quadratic equation can be found using the quadratic formula:
x = (-b ± sqrt(b² - 4ac)) / 2a
or by factoring the quadratic expression into two linear factors, and then solving for x. The quadratic formula works for all quadratic equations, while factoring can only be used for some quadratic equations that have integer roots.
To locate the zero of a quadratic equation given the values of x and y, we can set the equation equal to zero and solve for x. Since the given data consists of x and y values, we can use the method of interpolation to find the quadratic equation that passes through these points. To do this, we can use the formula for the quadratic function:
f(x) = ax² + bx + c
where a, b, and c are constants that we need to find. We can use the given data to form a system of three equations:
14 = a(-1)² + b(-1) + c
2 = a(0)² + b(0) + c
-3 = a(1)² + b(1) + c
Simplifying each equation, we get:
a - b + c = 14
c = 2
a + b + c = -3
Substituting c = 2 into the first and third equations, we get:
a - b + 2 = 14
a + b + 2 = -3
Solving for a and b, we get:
a = -8
b = -13
Therefore, the quadratic function that passes through the given points is:
f(x) = -8x² - 13x + 2
To find the zero of this quadratic equation, we can set it equal to zero and solve for x:
-8x² - 13x + 2 = 0
Using the quadratic formula, we get:
x = (-(-13) ± sqrt((-13)² - 4(-8)(2))) / (2(-8))
Simplifying, we get:
x = (13 ± sqrt(249)) / 16
Therefore, the zeros of the quadratic equation are approximately:
x ≈ -0.53 and x ≈ 1.03
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A weight is attached to a spring, which moves up and down as a function of time. � ( � ) p(t)p, left parenthesis, t, right parenthesis gives the position of the weight at time ( � ) (t)left parenthesis, t, right parenthesis. Position is in centimeters, and time is in seconds. Complete the following sentences based on the graph of the function. The graph is a function. The initial position of the weight is centimeter(s). The weight first reaches equilibrium when � = t=t, equals second(s). Note: We say that the weight is at equilibrium whenever � ( � ) = 0 cm p(t)=0cmp, left parenthesis, t, right parenthesis, equals, 0, start text, c, m, end text, and we say that the initial position of the block is its position when � = 0 s t=0st, equals, 0, start text, s, end text.
This graph is position-time graph.
The initial displacement οf the weight is 40cm
The weight first returns tο equilibrium when t = 1/2
What is a graph?In computer science and mathematics, a graph is a collection of vertices (also known as nodes or points) connected by edges (also known as links or lines).
Based on the given Graph, we can say that the graph represents a position-time graph of a weight attached to a spring.
The initial position of the weight is 40cm as given in tha graph,
We can determine the time at which the weight first reaches equilibrium.
Equilibrium occurs when the weight is at rest and has zero velocity.
This corresponds to the position of the weight being zero, i.e., p(t) = 1/2 cm. The problem states that we say the weight is at equilibrium when p(t) = 1/2 cm.
Therefore, the weight first reaches equilibrium at the time t when p(t) = 1/2 cm.
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Complete question:
The weight is initially positioned at a certain distance in centimeters, which is not stated in the query. To ascertain this number, we would need to examine the graph or receive additional information.
What is the graph of the function?Based on the information given, we can say the following:
The graph of the function is a function, which means that each input (time value) corresponds to exactly one output (position value).
The initial position of the weight is some number of centimeters, which is not specified in the question. We would need to look at the graph or be given more information to determine this value.
The weight first reaches equilibrium when the position is 0 cm, which means that the function value is 0. We can find the time(s) when this occurs by solving the equation p(t) = 0.
For example, if the equation is [tex]p(t) = 3sin(2t) - 2, we can set 3sin(2t) - 2 = 0[/tex] and solve for [tex]t: 3sin(2t) = 2, sin(2t) = 2/3, 2t = sin^-1(2/3) + 2πn or π - sin^-1(2/3) + 2πn[/tex] for some integer [tex]n, t = (sin^-1(2/3) + 2πn)/2 or (π - sin^-1(2/3) + 2πn)/2[/tex] For some integer n.
The initial position of the weight is its position when t = 0 s, which means we need to look at the value of p(0). Again, this value is not given in the question.
Therefore, Without more information or a graph of the function, we cannot provide specific values for these unknowns.
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The given question is incomplete. The complete question is given below:
The function (p(t)) gives the position of the weight at time (t). Please complete the following sentences based on the graph of the function. The graph is a function. The initial position of the weight is __________ centimeters. The weight first reaches equilibrium when t equals __________ second(s). Note: We say that the weight is at equilibrium whenever p(t) = 0 cm, and we say that the initial position of the block is its position when t = 0 seconds.
Matt and Noah are each going to buy a new video game. Noah’s video game costs $27.99 and Matt’s costs $21.99. If sales tax is 6.5%, how much will they each have to pay altogether including tax?
A) Noah's total cost with tax $
To calculate the total cost including tax for Noah's video game, we need to add the cost of the game to the sales tax.
Sales tax on Noah's game = 6.5% of $27.99 = $1.82
Total cost for Noah's game = $27.99 + $1.82 = $29.81
Similarly, for Matt's game:
Sales tax on Matt's game = 6.5% of $21.99 = $1.43
Total cost for Matt's game = $21.99 + $1.43 = $23.42
Therefore, Noah will have to pay $29.81 and Matt will have to pay $23.42 including tax.
the chance a 1-km segment of railroad track contains a defect is 0.01. assume the 1-km segments of track are independent. a. compute the probability that exactly 125 km of track need to be tested before a defect is found. b. on average, how many 1-km segments of railroad track have to be tested before a defect is found? 3. a geotechnical engineering company conducted a study that indicates there is a 20% chance a borehole in a certain neighborhood will find a layer of clay no more than 20 m deep. a. compute the probability that the third layer of clay within 20 m is found on the seventh borehole drilled. b. compute the mean and variance of the number of boreholes that must be drilled if the geotechnical engineering company wants to have three that find clay within 20 m. 4. dam failures are rare and are estimated to occur on average once every five years. a. compute the probability there will be at least one dam failure in the next 10 years. b. draw a pmf that describes the random variable x
The probability mass function (pmf) of the random variable x is:
Question 1: The chance a 1-km segment of railroad track contains a defect is 0.01. Assume the 1-km segments of track are independent. a. Compute the probability that exactly 125 km of track need to be tested before a defect is found. b. On average, how many 1-km segments of railroad track have to be tested before a defect is found?
Answer 1: a. The probability that exactly 125 km of track need to be tested before a defect is found is 0.000148. b. On average, 125.01 1-km segments of railroad track need to be tested before a defect is found.
Question 2: A geotechnical engineering company conducted a study that indicates there is a 20% chance a borehole in a certain neighborhood will find a layer of clay no more than 20 m deep. a. Compute the probability that the third layer of clay within 20 m is found on the seventh borehole drilled. b. Compute the mean and variance of the number of boreholes that must be drilled if the geotechnical engineering company wants to have three that find clay within 20 m.
Answer 2: a. The probability that the third layer of clay within 20 m is found on the seventh borehole drilled is 0.02. b. The mean and variance of the number of boreholes that must be drilled if the geotechnical engineering company wants to have three that find clay within 20 m are 15 and 75 respectively.
Question 3: Dam failures are rare and are estimated to occur on average once every five years. a. Compute the probability there will be at least one dam failure in the next 10 years. b. Draw a pmf that describes the random variable x.
Answer 3: a. The probability that there will be at least one dam failure in the next 10 years is 0.8187. b. The probability mass function (pmf) of the random variable x is:
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Which is the best estimate for the percent equivalent of 7/15 21% 22% 46% 47%
Answer: 47%
Step-by-step explanation:
When you divide 7 out of 15 you get .4666666. But rounding to the percent you get 47%.
NEED HELP WITH QUESTION TWO !!
2. Shade in a base of the trapezoidal prism. (The base is not the same as the bottom.)
a. Find the area of the base you
shaded.
b. Find the volume of this trapezoidal
prism.
4
8
12
5
5
(From Unit 6, Lesson 15.)
- Han draws a triangle with a 50° angle, a 40° angle, and a side of length 4 cm as
shown. Can you draw a different triangle with the same conditions?
1. The base of the trapezoid is a rectangle, thus its area is 96 sq. units. 2. The volume of the trapezoid prism is 312 cubic units. 2. We cannot draw different triangle with same condition.
What is volume of trapezoid?A trapezoidal prism's volume determines its capacity. It is also known as the area contained by a trapezoidal prism. The top and bottom faces of a prism have cogruent polygons, and its bases are the same. The lateral faces, or side faces, of a prism are parallelograms. The forms of the two identical faces at a prism's end can be used to identify it. A three-dimensional solid with two trapezoid/trapezium bases at the bottom and top is called a trapezoidal prism. A trapezoidal prism's lateral faces and side faces have a parallelogram form.
1. The base of the trapezoid is a rectangle, thus its area is given as:
A = lw
A = (8)(12) = 96 sq. units.
2. The volume of the trapezoid prism is given as:
V = 1/2(a + b) h(l)
Here, a = 5, b = 8, h = 4, and l = 12.
Substituting the values we have:
V = 1/2(5 + 8)(4)(12)
V = 24(13)
V = 312 cubic units.
2. The triangles with the conditions, 50° angle, a 40° angle, and a side of length 4 cm has the third angle as 90 degrees according to the internal angle of triangle theorem.
Also, the sides corresponding to the triangle remain same, and hence we cannot draw different triangle with same condition.
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at
9. Which figure has 1 curved face? Select all
that apply. 5.GR.1.2
cone
sphere
cylinder
right square pyramid
right triangular prism
Answer:
A **cone** and a **cylinder** each have 1 curved face.
8. Choose all lengths that are equal to
6 feet 12 inches.
3 yd 1 ft
7 ft
7 ft 2 in.
2 yd 1 ft
1 yd 4 ft
By answering the presented questiοn, we may cοnclude that, the equatiοn lengths that are equal tο 6 feet 12 inches are: 7 ft and 2 yd 1 ft.
Thus, option b and d are correct.
Equatiοn: What is it?In mathematics, an equatiοn is a claim that twο expressiοns are equivalent. Twο sides that are separated by the algebraic symbοl (=) make up an equatiοn. As an illustratiοn, the claim "2x + 3 = 9" makes the claim that the cοmbinatiοn "2x + 3" equals the integer "9".
Finding the value οr values οf the variable(s) necessary fοr the equatiοn tο be true is the gοal οf equatiοn sοlving. Equatiοns can include οne οr mοre parts and be straightfοrward οr cοmplex, regular οr nοnlinear. Fοr example, the variable x is raised tο the secοnd pοwer in the equatiοn "x² + 2x - 3 = 0." In many different branches οf mathematics, including algebra, calculus, and geοmetry, lines are used.
6 feet 12 inches can be simplified tο 7 feet.
Sο, the lengths that are equal tο 6 feet 12 inches are: 7 ft
Also 7 ft is equal to 2yd 1ft
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what is the probability that a card drawn randomly from a standard deck of 52 cards is a red queen? express your answer as a fraction in lowest terms or a decimal rounded to the nearest millionth.
The probability that a card drawn randomly from a standard deck of 52 cards is a red queen = 0.038
We know that the formula for the probability of an event is given by,
P = number of favourable outcomes / total number of possible outcomes of an event
Let us assume that event A : drawing a red queen card
Here, sample space is a standard deck of 52 cards.
So, n(S) = 52
We know that there are 2 queens of red color (red heart and red diamond)
So, n(A) = 2
Using probability formula,
P(A) = n(A) / n(S)
P(A) = 2/52
P(A) = 0.038
Therefore, the required probability is 0.038
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Estimate the amount of the tip by rounding the bill to the nearest dollar before calculating.
20% tip on a bill of $48.47?
The amount of the tip is approximately
Rounding the amount to the nearest dollar, we get $10.00 as the estimated tip amount.
Describe amount?In general, "amount" refers to a quantity or a sum of something. The specific context in which the term is used determines the meaning of the word more precisely.
In financial contexts, "amount" typically refers to a sum of money or other financial value, such as the amount of a payment, a loan, or an investment. In accounting, the amount may refer to the total value of assets, liabilities, or equity.
In scientific contexts, "amount" may refer to the quantity or volume of a substance or material, such as the amount of water in a solution, the amount of gas in a container, or the amount of a drug in a patient's bloodstream.
In general usage, "amount" can refer to a quantity of something that can be measured, counted, or expressed numerically, such as the amount of time spent on a task, the amount of food consumed, or the amount of work completed
$10.00.
Rounding the bill amount to the nearest dollar, we get $48. The 20% tip on $48 is $9.60. Rounding this amount to the nearest dollar, we get $10.00 as the estimated tip amount.
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PLEASE HELP!
3. Leo designs a stand for the new statue on display at the local library. The stand is in the shape of a right trapezoidal prism. The base of the prism has an area of 40 ft2, and the prism stands 9 feet high. As Leo paints the stand, he calculates the surface area of the stand to be 203.8 ft2.
(a) Leo is asked to purchase roping that will be used to close off the area around the statue. He purchases a length that is four times the perimeter of the stand in roping.
How much roping does he purchase?
(b) Leo plans to add gold leaf to the sides of the stand but not to the two bases.
What percent of the area of the stand will have gold leaf? Round your answer to the nearest whole number.
Answer:
The total area that Leo plans to cover with gold leaf is 4*30.95 = 123.8 ft2. Leo plans to cover 61% of the area of the stand with gold leaf.
What is a right trapezoidal prism?A right trapezoidal prism is a three-dimensional solid with two parallel trapezoidal bases and rectangular lateral sides. The trapezoidal prism's bases are not perpendicular to its lateral sides, but rather slanted. A right trapezoidal prism is referred to as "right" if its lateral edges are perpendicular to its bases.
(a) Area of trapezoid = (a + b)/2 * h = 40
9a + 9b = 80
a + b = 80/9
Now, let the height of the trapezoid be h1, and the length of the shorter side be h2. Then we have:
[tex]h1^2 = (9/2)^2 + h2^2[/tex]
h2 = [tex]\sqrt{(h1^2 - (9/2)^2)}[/tex]
Finally, we can find the perimeter P of the base by adding up the lengths of all four sides:
P = a + b + 2*[tex]\sqrt{((a-b)/2)^2 + h2^2)}[/tex]
Now we can find the length of roping needed:
Length of roping = 4P = 4(a + b + 2*[tex]\sqrt{((a-b)/2)^2 + h2^2}[/tex])
Substituting a + b = 80/9 and h2 from above, we get:
Length of roping = 4(80/9 + 2[tex]\sqrt{((a-b)/2)^2}[/tex] + [tex]\sqrt{(h1^2 - (9/2)^2))}[/tex]
Length of roping = (320/9) + 8[tex]\sqrt{((a-b)/2)^2}[/tex] + 4*[tex]\sqrt{(h1^2 - (9/2)^2)}[/tex]
Length of roping = 37.14 ft
Therefore, Leo purchases 37.14 feet of roping.
(b) The total surface area of the stand is 203.8 [tex]ft^2[/tex]. The area of both bases combined is 2*40 = 80 [tex]ft^2[/tex]. Therefore, the area of the sides of the stand is:
203.8 - 80 = 123.8 [tex]ft^2[/tex]
The stand has four side faces, so the area of one face is:
123.8 / 4 = 30.95 [tex]ft^2[/tex]
The total area that Leo plans to cover with gold leaf is the sum of the areas of all four side faces, which is:
4*30.95 = 123.8 [tex]ft^2[/tex]
Therefore, the percent of the area of the stand that will have gold leaf is:
(123.8 / 203.8) * 100 = 60.73%
Rounding to the nearest whole number, Leo plans to cover 61% of the area of the stand with gold leaf.
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suppose that you want to construct a 95% confidence interval for estimating a population mean. how does the margin of error with a sample size of 100 compare with the margin of error with a sample size of 1,600, if both samples have the same standard deviation?
The margin of error with a sample size of 1600 will be smaller than the margin of error with a sample size of 100, assuming the same standard deviation and confidence level, meaning that we can be more confident in the accuracy of the estimate with a larger sample size.
Assuming that both samples have the same standard deviation, the margin of error for a 95% confidence interval for estimating a population mean can be calculated as
Margin of Error = z×(standard deviation/sqrt(sample size))
where z is the z-score corresponding to the desired confidence level (in this case, 1.96 for a 95% confidence level).
For a sample size of 100, the margin of error would be
Margin of Error (n=100) = 1.96×(standard deviation/sqrt(100))
For a sample size of 1600, the margin of error would be
Margin of Error (n=1600) = 1.96*(standard deviation/sqrt(1600))
Since the standard deviation is the same for both samples, the only difference between the two margins of error is the sample size. The margin of error is inversely proportional to the square root of the sample size, so as the sample size increases, the margin of error decreases.
In other words, the margin of error with a sample size of 1600 will be smaller than the margin of error with a sample size of 100, assuming the same standard deviation and confidence level. This means that we can be more confident in the accuracy of the estimate with a larger sample size.
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Select the action you would use to solve x-3 =12. Then select the property that justifies that action.
Select all that apply.
A. Action: Add 3 to both sides
B. Action: Multiply both sides by 3
C. Action: Subtract 3 both sides
D. Property: Addition property of equality
E. Property: Multiplication property of equality
F. Property: Subtraction property of equality
The property that justifies that action - A. Action: Add 3 to both sides, D. Property: Addition property of equality.
What is the addition property of equality?
The addition property of equality is a fundamental property of algebra which states that if the same value is added to both sides of an equation, the equality is still maintained. In other words, if a = b, then a + c = b + c for any value of c. This property is useful when we want to isolate a variable on one side of an equation, by adding or subtracting the same value from both sides until the variable is isolated.
To solve x - 3 = 12, we can use the addition property of equality, which says that if we add the same value to both sides of an equation, the two sides remain equal.
Starting with x - 3 = 12, we can add 3 to both sides to isolate the variable x:
x - 3 + 3 = 12 + 3
x = 15
Therefore, the solution to the equation x - 3 = 12 is x = 15.
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how many multiplications can the ibm compute per second?
The IBM computer can compute about 6 trillion (6 x 1012) multiplications per second
The IBM computer can perform around 6 trillion multiplications per second, making it one of the fastest computers in the world. Multiplication is a fundamental arithmetic operation that is used to calculate the total value when two or more numbers are combined.
Multiplication is used to calculate the total number of things when there are several equal groups. For example, 2 x 5 = 10 means that there are 10 items in two groups, each containing five items. The symbol "x" represents the multiplication operation.
The IBM computer can compute about 6 trillion (6 x 1012) multiplications per second. IBM's Summit computer, which is currently the world's most powerful computer, has a peak speed of 200 petaflops, or 200 quadrillion (2 x 1017) calculations per second. This makes it one of the fastest computers in the world.
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