Answer:
2.64g of CO₂ are produced
Explanation:
The reaction of hexane with O₂ is:
C₆H₁₄ + 19/2O₂ → 6CO₂ + 7H₂O
To solve this question, we must convert each mass of reactant to moles in order to find limiting reactant and, with the chemical reaction we can find the moles of carbon dioxide produced and the maximum mass produced:
Moles hexane -Molar mass: 86.18g/mol-:
0.862g * (1mol / 86.18g) = 0.01 moles
Moles Oxygen -Molar mass: 32g/mol-:
5.1g * (1mol / 32g) = 0.16 moles
For a complete reaction of 0.01 moles of hexane there are required:
0.01moles hexane * (19/2 Oxygen / 1mol Hexane) = 0.095 moles oxygen
As there are 0.16moles, limiting reactant is hexane.
0.01 moles of hexane produce:
0.01 moles * (6 moles carbon dioxide / 1 mole hexane) = 0.06 moles of CO₂.
The mass is -Molar mass CO₂: 44g/mol-:
0.06 moles of CO₂ * (44g/mol) =
2.64g of CO₂ are producedEthanol (CH3CH2OH), the intoxicant in alcoholic beverages, is also used to make other organic compounds. In concentrated sulfuric acid, ethanol forms diethyl ether and water:
2CH3CH2OH(l) → CH3CH2OCH2CH3(l) + H2O(g)
In a side reaction, some ethanol forms ethylene and water:
CH3CH2OH(l) → CH2═CH2(g) + H2O(g)
(a) If 54.0 g of ethanol yields 28.8 g of diethyl ether, what is the percent yield of diethyl ether?
%
(b) During the process, 45.0% of the ethanol that did not produce diethyl ether reacts by the side reaction. What mass of ethylene is produced?
The percent yield of the ether is 66.5% and the mass of ethylene produced is 4.9 g.
What are the products?We know that in a reaction, we are only able to obtain the parameter of the reactions by the use of stoichiometry. This is the relationship between the reactants and the products in the process.
The reaction is given as shown in the reaction equations in the question above.
Number of moles of ethanol = 54.0 g /46 g/mol = 1.17 moles
Since 2 moles of ethanol yields 1 mole of ether
1.17 moles of ethanol yields 1.17 moles * 1 mole /2 moles
= 0.585 moles
Mass of the ether = 0.585 moles * 74 g/mol = 43.29 g
Percent yield = 28.8 g/ 43.29 g * 100/1
= 66.5 %
Amount of unreacted ethanol = (100 - 66.5)/100 * 1.17 moles = 0.39 moles
Amount that participates in the side reaction 45.0/100 * 0.39 moles = 0.1755 moles
Given that the reaction is 1:1
Mass of ethylene produced = 0.1755 moles * 28 g/mol = 4.9 g of ethylene
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You have a solution of 0.250 MNaCl. If you boil away 2/3 of the volume of water, what is the concentration of this solution?
The concentration of the new solution, given that 2/3 of it's initial volume was boiled away is 0.758 M
The following data were obtained from the question:
Concentration of stock solution (M₁) = 0.250 MVolume of stock solution (V₁) = 1 mL Volume of water boiled away = 2/3 = 0.67 mL Volume of new solution (V₂) = 1 - 0.67 = 0.33 mL Concentration of new solution (M₂) =? How to determine the concentration of the new solutionThe molarity of the new solution can be obtained as follow:
M₁V₁ = M₂V₂
0.250 × 1 = M₂ × 0.33
0.250 = M₂ × 0.33
Divide both side by 0.33
M₂ = 0.250 / 0.33
M₂ = 0.758 M
Thus, the concentration of the new solution is 0.758 M
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Convert 7.27 m^3 to ft^3
256.73 ft
Convert 7.27 [tex]m^3[/tex] to[tex]ft^3[/tex]
as per above , we have to convert [tex]m^3[/tex] into [tex]ft^3[/tex]
now:
1 [tex]m^3[/tex] = 35.31 [tex]ft^3[/tex]
7.27 [tex]m^3[/tex] = 35.31 [tex]\times[/tex] 7.27 [tex]m^3[/tex]
= 256.73 ft
meter cubic and feet both are volumetric unit
Volume is the amount of space an object take upV = Length x Wide x Height is the formula to find the volume of a regular shaped object or 3 dimensional objectCubic Feet is the Volume of a cube is one foot on each sideCubic Meteris the Volume of a cube is one meter on each side.To know more about Volume visit :
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HELP!!
Calculate the heat absorbed by 50.00 g of iron when its temperature is raised from 10.00 0 C to 60.00 C. The specific heat of iron is 0.449J/g C.
Heat absorbed by 50 g of iron is 898 Joule.
Heat transfer between two bodies, which can take place through conduction, convection, or radiation, is referred to as heat absorption.
Specific heat - The amount of heat needed to raise a substance's temperature by one degree Celsius in one gram, also known as specific heat. The units of specific heat are usually expressed in terms of calories or joules per gram per degree Celsius. The specific heat of water, for instance, is 1 calorie (or 4.186 joules) per gram per degree Celsius.
The formula of specific heat-
q = mc ΔT
where Q is heat absorbed, m is mass and ΔT is change in temperature.
m = 50 g
c = 0.449 J/g C
ΔT = 60 - 10
= 40 °C
∴q = 50 x 0.449 x 40
q = 898 J
Hence, heat absorbed by 50 g of iron is 898 Joule.
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Perform the following operations and express the answers in scientific notation: SHOW YOUR WORK
1) (1.2 * 10^5) + (5.35*10^6)
2) (6.91*10^-2) + (2.4* 10^-3)
3) (9.70*10^6) + (8.3*10^5)
The given operations are performed
and the expressions are presented
in scientific notation as follows;
1) (1.2 × 10⁵) + (5.35 × 10⁶) = 5.47 × 10⁶
2) (6.91 × 10^(-2) + (2.4 × 10^(-3)) = 7.15 × 10^(-2)
3) (9.70 × 10⁶) + (8.3 × 10⁶) = 1.053 × 10⁷
How can the given operations be performed and results presented in scientific notation?1) (1.2 × 10⁵) + (5.35 × 10⁶)
(1.2 × 10⁵) + (5.35 × 10⁶) = (1.2 × 10⁵) + (53.5 × 10⁵)
(1.2 × 10⁵) + (53.5 × 10⁵) = (1.2 + 53.5) × 10⁵
(1.2 + 53.5) × 10⁵ = 54.7 × 10⁵
54.7 × 10⁵ = 5.47 × 10⁶
Therefore;
(1.2 × 10⁵) + (5.35 × 10⁶) = 5.47 × 10⁶
2) (6.91 × 10^(-2) + (2.4 × 10^(-3))
(6.91 × 10^(-2) + (2.4 × 10^(-3)) = (69.1 × 10^(-3) + (2.4 × 10^(-3))
(69.1 × 10^(-3) + (2.4 × 10^(-3)) = (69.1 + 2.4) × 10^(-3)
(69.1 + 2.4) × 10^(-3) = 71.5 × 10^(-3)
71.5 × 10^(-3) = 7.15 × 10^(-2)
Therefore;
(6.91 × 10^(-2) + (2.4 × 10^(-3)) = 7.15 × 10^(-2)
3) (9.70 × 10⁶) + (8.3 × 10⁵)
(9.70 × 10⁶) + (8.3 × 10⁵) = (97.0 × 10⁵) + (8.3 × 10⁵)
(97.0 × 10⁵) + (8.3 × 10⁵) = (97.0 + 8.3) × 10⁵
(97.0 + 8.3) × 10⁵ = 105.3 × 10⁵
105.3 × 10⁵ = 1.053 × 10⁷
Therefore;
(9.70 × 10⁶) + (8.3 × 10⁵) = 1.053 × 10⁷
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What site is located in the structure of tRNA
The structure of tRNA resembles cloverleaf.
tRNA is called transfer RNA, which is a small RNA molecule which plays important role in protein synthesis.-It serves as link between messenger RNA and the growing chain of amino acids that make up protein.
tRNA molecules fold into structure resembling cloverleaf with four important sites:-
•The acceptor stem (3’-CCA) have an amino acid
•The anticodon attaches with the mRNA codon (via complementary base pairing)
•The T arm attaches with the ribosome (via the E, P and A binding sites)
•The D arm of tRNA activating enzyme (help in adding the amino acid to the acceptor stem).
CCA is codon codes for prolein amino acid in polypeptide chain.
AUG is initiator codon codes for methionine.
UAG, UAA and UGA are stop codons.
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Why must scientists always communicate their results
Answer: To Know That They Did Nothing Wrong
Explanation:
For Example, They Maybe Put The Wrong Thing
Or They Made The Different One Instead Of What They Were Supposed To Do
How does a physical change take place in making a s’more
Answer: The Marshmellow
Explanation
The marshmallow turns from a solid to a gooey texture.
Which type of energy does alpha decay generate?
O kinetic
O potential
O sound
O electromagnetic
Answer: kinetic or A :)
Explanation: kinetic energy Alpha particles have typical kinetic energy of 5 MeV (or ≈ 0.13% of their total energy 110 TJ/kg) and have a speed of about 15 000 000 m/s or 5% of the speed of light.
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A 2.45M of sulphiric acid solution has a density of 1.15g/ml at 20degree celesius.what is the molality of the solution in that temprature?
The Molarity of solution if a 2.45M of sulphiric acid solution has a density of 1.15g/ml at 20degree celesius is 2.69M.
Given,
Density of the solution = 1.15 g/mL
Molarity of the sulphiric acid = 2.45M
Molar mass of sulphuric acid = 98 g
Density is given as:
[tex]Molarity(\frac{1}{molarity} +\frac{mol.wt}{1000} )\\\\=2.45(\frac{1}{molarity} + \frac{98}{1000} )\\\\(\frac{1}{molarity} = (\frac{1.15}{2.45} + \frac{98}{1000} \\\\(\frac{1}{molarity} = 0.469 - 0.098\\\\(\frac{1}{molarity} = 0.371\\\\Molarity = 2.69m\\\\[/tex]
The Molarity of solution if a 2.45M of sulphiric acid solution has a density of 1.15g/ml at 20degree celesius is 2.69M.
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I need help on part 3b please?
The frequency of a radio wave was measured to be (9.3x10^8) Hz What is the energy of the radio wave in kilojoules (kJ)?
1 Hz = 1 s–1
h = 6.626 x 10-34 J.s
The energy of the radio wave in kilojoules is obtained as 6.2 * 10^-25 J.
What is a wave?The term wave has to do with a disturbance along a medium which transfers energy. There are different kinds of wave. In this case, a radio wave is a type of electromagnetic wave. The electromagnetic waves do not require a medium for their propagation. This implies that they are able to move on their own with no medium.
Thus;
We know that;
Frequency of the wave = 9.3x10^8 Hz
Plank's constant = 6.626 x 10^-34 J.s
E = hf
E = energy of the wave
h = Plank's constant
f = frequency of the waves
E = 9.3x10^8 Hz * 6.626 x 10^-34 J.s
= 6.2 * 10^-25 J
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The image shows the products of a decomposition reaction. The larger, red spheres represent oxygen atoms, and the smaller, blue spheres represent nitrogen atoms.
In this image, there are 6 molecules composed of two red atoms bound together, and 3 molecules composed of two blue atoms bound together.
Determine the empirical formula of the reactant based on these products.
The empirical formula of the compound that decomposes is [tex]N_{2} O[/tex]
What is decomposition?The term decomposition refers to a type of reaction in which a substance is broken down into its components. We know that a compound is composed of atoms. When there is a decomposition reaction, the atoms of the compound break down.
We can see that the products of the decomposition reaction are nitrogen and oxygen. The red spheres represent oxygen atoms, and the smaller, blue spheres represent nitrogen atoms.
We know that nitrous oxide decomposes to give nitrogen and oxygen. Thus the empirical formula of the compound is [tex]N_{2} O[/tex].
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A compound containing only carbon, hydrogen, and oxygen is analyzed using combustion analysis. When 55.5 g of the compound is burned, 98.9 g of carbon dioxide and 40.5 g of water are collected.
Given that there are 2.25 moles of carbon and 4.50 moles of hydrogen produced in the reaction, calculate the mass of oxygen in the original compound. You will need to subtract the mass of the carbon that ended up in the carbon dioxide and the mass of the hydrogen that ended up in the water from the mass of the original compound.
Answer:
Determining an Empirical Formula from Combustion Data
Explanation:
Step 1: Identify the mass of carbon dioxide and water produced by the combustion.
Step 2: Find how many moles of carbon are in carbon dioxide.
Step 3: Find how many moles of hydrogen are in water.
A rectangular painting has an area of 2890square centimeters. What is its area in square inches? Round to the nearest square inch. Do not include the units in your answer.
The area of the rectangular painting which is 2890 square centimeters is equivalent to 447.95 square inches
How to convert cm² to in²?Square inch (in²) is a unit of area equal to the area of a square the sides of which are each one inch long.
Square centimeter (cm²) is another unit of area equal to that of a square of sides 1 centimeter.
The conversion factor of square centimeter to square inches is as follows:
1 square centimetre = 0.155 square inch
2890 square centimeters = 447.95 square inches
Therefore, the area of the rectangular painting which is 2890 square centimeters is equivalent to 447.95 square inches.
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1. Sketch a periodic table by labeling the s, p, d and f blocks?
s block - group 1 and 2 , p block - group 13 to 18 , d block - group 3 to 12, f block - group 3
The s-block in the periodic table of elements occupies the alkali metals and alkaline earth metals ,thus known as groups 1 and 2.D block elements are also known as Transition elementsF block elements are divided into two series as lanthanoids and actinoids. This block of elements are referred to as inner transition metals. s and p block elements are together known as representative elementsThus we can conclude that ,they are names as s,p,d and f blocks because the last electrons enter s, p , d and f orbitals respectively.
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Hydrogen reacts with chlorine according to
the equation:
H₂(g) + Cl₂(g) → 2HCl(g)
What is the total volume of gas present in
the container at the end of the experiment if
100 cm³ of hydrogen is reacted with 200 cm³
of chlorine?
When the total number of reactants and products are the same in the reaction it is called a balanced chemical equation. The balanced chemical equation of H2+ Cl2 → 2HCl(g)
What is a balanced chemical equation?When the total number of reactants and products are the same in the reaction it is called a balanced chemical equation. In the given reaction one mole of 70 g of hydrogen reacts with 2 moles of Cl.
100 g of chlorine reacts with 2/ 70 * 100 = 2.86 gram of hydrogen.
70 grams of chlorine will produce 73 g of HCl.
100 gram of chlorine produce 73/ 70 * 100 = 104.28 g of HCl.
Therefore, When the total number of reactants and products are the same in the reaction it is called a balanced chemical equation. The balanced chemical equation of H2+ Cl2 → 2HCl(g).
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What amount of the excess reagent remains when 0.30 mol NH3 reacts with 0.40 mol O2 to produce NO and H2O? 4NH3 +502 + 4NO + 6H20
(A) 0.10 mol NH,
(B) 0.10 mol
(C) 0.025 mol NH
(D) 0.025 mol O2
Answer: (D) 0.025 mol [tex]O_2[/tex]
Explanation:
The given balanced equation is :
[tex]4NH_3+5O_2\rightarrow 4NO+6H_2O[/tex]
According to stoichiometry :
4 moles of ammonia [tex](NH_3)[/tex] reacts with = 5 moles of oxygen [tex](O_2)[/tex]
Thus 0.30 moles of ammonia [tex](NH_3)[/tex] reacts with = [tex]\frac{5}{4}\times 0.30=0.375[/tex] moles of oxygen [tex](O_2)[/tex]
Now as given moles of oxygen are more than the required amount, oxygen is the excess reagent.
moles of oxygen [tex](O_2)[/tex] left = 0.40 - 0.375 = 0.025
Thus 0.025 mol [tex]O_2[/tex] excess reagent remains.
The amount of excess reagent remaining when 0.30 mole NH3 reacts with 0.40 mole O2 is 0.025 mole of O2
An excess reagent is a reactant which is left and can keep reacting after whole reaction.
A limiting reagent is a reactant that is totally consumed in the whole process of the reaction.
The chemical equation for the reaction is represented as:
[tex]\mathbf{4NH_3 + 5O_2 \to 4NO + 6H_2O}[/tex]
From the above reaction,
4 moles of ammonia reacts with 5 moles of oxygen molecule;
If 0.30 moles of ammonia reacts, then the numbers of moles of oxygen required can be computed as:
[tex]\mathbf{= \dfrac{0.3 \times 5}{4}}[/tex]
= 0.375 moles of oxygen.
But, we are given that 0.40 moles of oxygen is present.
Therefore, the amount of oxygen in excess is
= 0.40 moles - 0.375 moles
= 0.025 moles of O2
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Which of the following contains as many atoms as 18 g of water, H₂O?
The correct answer is option c) Three moles of sodium, Na.
We know that
18g of H₂O = 1 mol
So, no. of atoms in H₂O = 3 x 6.022 x 10²³
= 1.81 x 10²⁴ atoms(both H&O atoms combined)
Now,
No. of atoms in 1 mol of H₂ = 2 x 6.022 x 10²³
= 1.2044 x 10²⁴ atoms.
No. of atoms in 2 mol of NaCl = 2 x 6.022 x 10²³
= 1.2044 × 10²⁴ atoms.
No. of atoms in 2 mol of O₂ = 2 x 6.022 x 10²³
= 1.2044 × 10²⁴ atoms.
No. of atoms in 3 mol Na = 3 x 6.022 x 10²³
= 1.81 x 10²⁴ Na atoms.
Therefore, 3 mol of Na contains as many atoms as 18g of H₂O i.e., 1.81 x 10²⁴ atoms.
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Which Of The Following Contains As Many Atoms As 18 G Of Water, H2O?
a) One mole of hydrogen, H₂
b) Three moles of sodium, Na
c) Two moles of sodium chloride, NaCl
d) Two moles of oxygen, O₂
Write 3.0 x 108 in standard form.
A) 30000000
B) 300000000
C) 3000000000
D) 3000000
a piece of magnesium in the shape of a cube measures with a height of 5.62 cm. If the magnesium sample has a mass of 14.1 g, what is the density of the sample
A piece of magnesium in the shape of cube measuring with height of 5.62 cm, and this magnesium sample having mass of 1.41 g has a density of 1.78 g/cm³.
What is Density?
Density is known as the mass of substance per unit volume. Density is denoted by a Greek symbol ρ. Density is equal to the mass substance divided by its volume. The SI unit of Density is g/cm ³or kg/m³.
ρ = m
v
where,
ρ = density
m = mass
v = volume
Given :
Height of the cylinder is 5.62 cm ,
Diameter of the cylinder is 1.34 cm
Radius = D/2 = 1.34/2 cm
Radius = 0.67 cm
Volume of cylinder = πr²h
Volume of cylinder = 3.14 × (0.67)² × 5.62
= 7.92 cm³
Density = Mass
Volume
Density = 14.1
7.92
Density = 1.78 g/cm³
Hence, the density of sample = 1.78 g/cm³ .
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State how are the elements of a period arranged in the modern periodic table, from left to right.
a:In order of increasing atomic mass
b:In order of increasing atomic number
c:In order of decreasing atomic mass
Answer: B
Explanation:
The atomic number of an element is the number of protons in the nucleus of an atom of that element. Changing the number of neutrons means you get an isotope of the same element. Changing the number of electrons does not affect the atom but affects the charge of the atom. So the periodic table is arranged by increasing the number of protons or atomic numbers.
You have a solution of 0.250 M NaCl. If you boil away 2/3 of the volume of water, what is the concentration of this solution in moles?
The concentration of this solution in moles is 0.75 M.
What is concentration of a solution?
The concentration of a solution is a measure of the amount of solute that has been dissolved in a given amount of solvent or solution.
Mathematically. concentration is given as;
C = n/V
where;
n is the number of molesV is the volume of the solutionC is concentrationAt a constant number of moles;
C1V1 = C2V2
When you boil away 2/3 volume, the new volume becomes 1/3
So V1 = V
V2 = 1/3V = 0.3333V
Substitute the given parameters and solve for the new concentration.
C2 = (C1V1)/V2
C2 = (0.25 x V) / (0.3333V)
C2 = 0.75 M
Thus, the concentration of this solution in moles is 0.75 M.
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o Convert 6.49 x 10-3 m to the equivalent length in nanometers.
Remember that 1 nanometer is equal to 1 x 109, therefore multiply 6.49 x 10-3 m by 1 x 109 to get the answer. The correct response is 6.49 x 10-3 m = 6.49 x 106 nm.
What are nanometers used for?
The measuring unit known as a nanometer (NM) is one billionth of a meter. It is frequently used as a scale for creating intricate, atomic-scale parts, particularly in nanotechnology.
What dimension does a nanometer have?
How tiny is "nano" exactly? One nanometer is one billionth of a meter since the prefix "nano" in the International System of Units refers to one billionth, or 10-9. Here are some samples to help you visualize how little that is: About 100,000 nanometers make up a sheet of paper.
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Select all that are "exact numbers" and therefore have an unlimited number of significant figures
A)
12 inches= 1 foot
B)
60 min= 1 hour
C)
1 pig= 88 kg
D)
my car speed= 55 mi per hour
E)
pie= 3.14
Answer:
b.
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Which of the following is NOT a way that chemists use to measure that a reaction has taken place?
Select one:
a.
Changes in the concentrations of reactants and products.
b.
Color change.
c.
By manually counting the actual atoms and molecules in the reaction.
d.
Change in pH.
Answer: a
Explanation:
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What is the mass grams that are in 2.57 × 10¹⁵ molecules of CO?
A reaction vessel contains 4.800 g of CO and 4.800 g of O2. What is the maximum number of moles of CO2 recovered, based on the number of moles of the given reactants?
The maximum number of moles of [tex]CO_2[/tex] that can be recovered from the reaction vessel would be 0.17 moles.
Stoichiometric calculationThe reaction vessel contains:
4.800 g CO4.800 g [tex]O_2[/tex]The equation of the reaction would be as follows:
[tex]2CO + O_2 --- > 2CO_2[/tex]
The mole ratios of the reactants to the product are as follows:
CO to [tex]CO_2[/tex] = 1:1[tex]O_2[/tex] to [tex]CO_2[/tex] = 1:24.800 g of CO = 4.8/28
= 0.17 moles
4.800 g of [tex]O_2[/tex] = 4.8/32
= 0.15 moles
Since the mole ratio of CO to [tex]O_2[/tex] is 2 to 1, 0.17 of CO is limiting.
The mole ratio of CO to [tex]CO_2[/tex] is 1 to 1. Thus, the equivalent mole of [tex]CO_2[/tex] that can be recovered is also 0.17.
In other words, the maximum number of moles of [tex]CO_2[/tex] that can be recovered from the reaction vessel is 0.17 moles.
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To create water from its component atoms, a bond must form between each of the hydrogens and the oxygen. Given that hydrogen is not able to donate its single electron, how does the water molecule form? Could u simple it after you explain it?
Given that hydrogen is not able to donate its single electron, the water molecule forms by the sharing of electrons between two hydrogen atoms and an oxygen atom.
What is Covalent bond?This is the type of bond which occurs when the electrons of an atom are shared unlike electrovalent bond which is formed when the electrons are transferred from one atom to another.
In this case, since hydrogen can't transfer electron and oxygen needs two electrons to achieve its stable configuration then two hydrogen atoms will share one electron each with the oxygen atom which results in the formation of water.
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20 g of sugar is there than to 150 g of 50 what is the mass of the solution formed
The mass of the solution formed when 20 g of sugar dissolved in 150 g of tea is 170 g.
The net mass of solution is calculated as the algebraic addition of the mass of the solute which is stirred into the mass of the solvent.
During the formation of solution, the sugar molecules are dissolved into tea in which sugar molecules fitted into the intermolecular spaces present between the water molecules of the tea and form a homogenous mixture.
What is solvent?Solvent is the substance or mixture which present in large amount in the solution.
What is solute?Solute is the substance or mixture which present in small amount in the solution.
Given,
Mass of solute (sugar) = 20g
Mass of solvent (tea) = 150g
Total mass of solution = 20 + 150
= 170g.
Thus we concluded that the mass of the solution formed when 20 g of sugar dissolved in 150 g of tea is 170 g.
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