Answer:
The minimum amount of NaOH(aq) solution needed to add is 0.0560 L. This can be calculated by using the following equation:
Moles of Cd2+ = 0.0220 M x 0.300 L = 0.0066 mol
Moles of NaOH = 0.0066 mol x 2 = 0.0132 mol
Volume of NaOH = 0.0132 mol/1.25 M = 0.0560 L
Explanation:
what is the molar mass of barium hydroxide
Answer:
171.34 g/mol
Explanation:
Ba molar mass = 137.328 g/mol
O molar mass = 15.999 g/mol * 2 = 31.9980 g/mol
H molar mass = 1.008 g/mol * 2 = 2.0160 g/mol
137.328 + 31.9980 + 2.0160 = 171.3420 = 171.34 g/mol
QUESTION 54
What is/are the reactant(s) of the chemical reaction shown?
CH4 (g) + 202 (g) → CO2 (g) + 2H20 (g)
O CH4 only
O 02 only
O CH4 and 02
O CO2 and H20
The process above is not a chemical reaction
Answer:
the answer is C.
Explanation:
CH4 and 02
what is the number of moles of water in 100 g of vinegar?
Answer:
The number of moles of water in 100 g of vinegar is 0.47 moles.
Explanation:
Question (1 point)
Given the model, answer the following questions regarding effusion. The orange spheres have a greater root-mean-square speed than the blue spheres. Assume the balloon has a tiny opening for gas molecules to escape.
1st attempt
Part 1 ( 0.5 point)
See Periodic Table See Hint
Which balloon, A or B, most accurately illustrates the effusion of a gas from the central balloon?
Calculate the relative rate of effusion for the orange to blue spheres. The root-mean-square speed for the orange spheres is 495.0m/s. The root-meah-5quare speed for the blue spheres is 380.0m/ s.
According to the claim, Balloon A, which has more blue and less orange, exhibits accurate effusion at a relative effusion rate of 1.303. (orange is 1.303 times more effused than blue).Relative rate of effusion for the orange to blue spheres = 1.531.
What is effusion ?The process of effusion is when a gas escapes from a container through a hole that is significantly smaller in diameter than the molecules' mean free path.
Gas molecules flow through a small opening in one container and into another by effusion. Graham's law allows rates of effusion to be compared at the same temperature. Diffusion is the random molecular motion-based movement of gas molecules through one or more other types of gas.
Rate of effusion of Orange / Rate of effusion of blue
= [Mblue / Morange]^1/2
Vrms = sqrt [(3RT/M)]
Vorange / Vblue = [ Mblue / Morange]^1/2
Rate of effusion of Orange / Rate of effusion of blue
= 565/ 369
= 1.531
Thus, Balloon A, which has more blue and less orange, exhibits accurate effusion at a relative effusion rate of 1.303.
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The volume of a fixed amount of gas is doubled, and the absolute temperature is doubled. According to the ideal gas law, how has the pressure of the gas changed? A. It has stayed the same. B. It has decreased to one-half its original value. C. It has increased to four times its original value. D. It has increased to two times its original value.
Answer:
Option A. It has stayed the same.
Explanation:
To answer the question given above, we assumed:
Initial volume (V₁) = V
Initial temperature (T₁) = T
Initial pressure (P₁) = P
From the question given above, the following data were:
Final volume (V₂) = 2V
Final temperature (T₂) = 2T
Final pressure (P₂) =?
The final pressure of the gas can be obtained as follow:
P₁V₁/T₁ = P₂V₂/T₂
PV/T = P₂ × 2V / 2T
Cross multiply
P₂ × 2V × T = PV × 2T
Divide both side by 2V × T
P₂ = PV × 2T / 2V × T
P₂ = P
Thus, the final pressure is the same as the initial pressure.
Option A gives the correct answer to the question.
Explain how an incorrect of dietary information on high blood sugar could potentially affect the patient’s
Long-term (months or years) high blood sugar levels can cause irreversible harm to organs such the kidneys, blood vessels, eyes, nerves, and nervous system. Speak with your doctor or the diabetes care team if you frequently have hyperglycemia.
What effects could an extremely high blood sugar level have on us?If left untreated, having excessive blood sugar levels for an extended length of time might lead to major health issues. In addition to raising the risk of heart disease, stroke, kidney illness, vision issues, and nerve issues, hyperglycemia can harm the blood arteries that provide blood to essential organs.
What dietary requirements are impacted by diabetes?A high-fat, high-calorie, and high-cholesterol diet
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Which electron configuration represents a transition element?
01s²2s²2p³
01522s22p635²
1s²2s²2p63s²3p64s²3d7
1s22s22p63s23p64s²3d¹04p4
The electronic configuration which represents a transition element is 1s²2s²2p⁶3s²3p⁶4s²3d⁷
What is a transition element?Transition elements are placed between the metallic S-block elements and nonmetallic P-block elements in the periodic table. They are D-block elements and have features similar to both metals and nonmetals, to some extent. This is why they are called transition elements.
One remarkable feature of these elements happens during the addition of electrons to them. Contrary to S and P-block elements, electrons are added to the penultimate shell, not the last shell. These elements often feature partially filled d-orbitals and have multiple oxidation states.
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PLEASE HELP ME ASAP
Which type of muscle is responsible for digestion?
A. smooth muscle
B. tendon muscle
C. skeletal muscle
D. cardiac muscle
Answer:
A
smooth muscle is responsible
WILL MARK BRAINLIEST!
Stoichiometry DBA
1. 33 grams of Calcium Sulfate reacts with 28 grams of Aluminum Phosphate to form Calcium
phosphate and Aluminum Sulfate
Write balanced equation here -
2. Which of the two reactants will limit the production of Calcium Phosphate. Show work here.
3. How much of the Aluminum Sulfate would be produced? Show work here. 4. 44 grams of Zinc Nitrate reacts with 59 grams of Iron(III) Hydroxide to form Zinc Hydroxide
and Iron(III) Nitrate.
Write balanced equation here -
5. Which of the two reactants will limit the production of Iron(III) Nitrate . Show work here.
6. How much excess reactant will you have left over?
Answer:
Ca3(PO4)2..... the formula for Calcium phosphateTwo metals (Metal A and Metal B) are both exposed to a laser which emits photons that have a greater energy than the work function of both metals. Metal A has a smaller work function than Metal B. Therefore, The de Broglie wavelength of the electrons produced from metal A will be ____________ those from metal B.
The number of electrons produced from metal A will be ____________ the number produced from metal B.
Answer:
shorter than
equal to
Explanation:
Let us go back to the Einstein photoelectric equation;
KE = E - Wo
Where
KE = kinetic energy of the photoelectron
E = energy of the incident photon
Wo = work function of the metal
But KE = 1/2mv^2
Thus the velocity of the emitted photoelectron is determined by the kinetic energy of the emitted photoelectron.
Since the work function of metal A is smaller than that of metal B, the kinetic energy of photoelectrons emitted from metal A is greater than that of photoelectrons emitted from metal B . Therefore, the velocity of electrons from metal A is greater than those from metal B.
From de Broglie relation;
λ = h/mv
Where;
λ = de Broglie wavelength
h = Plank's constant
m = mass
v = velocity
Metal A producing electrons with greater velocity will lead to a shorter de Broglie wavelength compared to those from metal B.
The number of photoelectrons ejected is determined by the intensity of the photons and not the energy of the incident photons or the work function of the metals. Since the two metals are exposed to the the same laser, equal number of photoelectrons are produced for metals A and B.
Classify the following amine as 1º, 2º, 3º or 4°
(primary, secondary, tertiary, quaternary).
(CH3)4N+
A. primary
B. secondary
D. quarternary
C. tertiary
Answer:
D. Quaternary
Explanation:
I'm going to attach a picture that can help you understand how amines are classified!
I'll explain how amines are classified below. You can skip it if you feel that you already understand that!
--------------------------------------------------------------------------------------------------------------
So we know that amines are composed of nitrogen, at least one R group, and hydrogens. The way that we categorize amines as primary, secondary, tertiary, or quarternary is by counting the number of R groups.
Now, how do we identify the R groups?
Well, basically anything that isn't a hydrogen. You will see that the nitrogen in an amine standardly only makes 3 bonds. If all those three bonds are with a hydrogen, then it will be ammonia. If it is a primary amine, then one of those hydrogens will be replaced with another compound (like [tex]CH_{3}[/tex] in this case). This other compound is called an R group. R groups will change based on the amine. A secondary amine will have two hydrogens replaced with groups. A tertiary amine will have all three hydrogens replaced with R groups.
--------------------------------------------------------------------------------------------------------------
Now, by this logic, we can just count the number of R groups in [tex](CH_{3} )_{4} N^{+}[/tex] and we should get our answer! We don't see any hydrogens. That means we can immediately rule out both A. and B.
Well, let's see. It looks like [tex]CH_{3}[/tex] is our R group. The subscript for it is also 4.
But we've used up our 3 bond spots, how is a quaternary amine possible? And that is why you see that your nitrogen has a positive charge in [tex](CH_{3} )_{4} N^{+}[/tex]. Since the nitrogen is bonded with more groups than it usually does, the electrons of nitrogen and therefore the electrical charge will be shared between more compounds and elements, leading to less charge for the nitrogen. This will cause it to have a positive charge. Making your amine an ion will allow for 4 bonds.
That is why even though nitrogen usually only has 3 bonds, we can still classify [tex](CH_{3} )_{4} N^{+}[/tex] as a quaternary amine.
--------------------------------------------------------------------------------------------------------------
The last part got a little lengthy, but I hope I was able to explain this question in-depth! If you had any trouble understanding what I wrote, feel free to leave a comment. I will reply as soon as possible!
If cobalt is emitting radiation but there is no change in its atomic number, what type of radiation is being emitted? A. Gamma B. Beta C. Delta D. Alpha
Answer:
(A) Gamma
Explanation:
They are emitted during radioactive decay and have no mass and no electrical charge meaning no change in atomic number or mass number.
Hope it helps :)
Answer:
A. Gamma
Explanation:
Answers Via Educere/Founders Education.
if you answer this correctly ill give you brainliest (HINT IT'S NOT D)
Answer: I believe the answer is A - the total growth of the plants.
Explanation: The total growth of the plants depends on the hours of sunlight. So, this would be your dependent variable, while the hours (amount) of sunlight would be your independent variable.
Answer:
A
Explanation:
since that's what's being measured
iupac name for Ag(S2O3)2
Answer:
Dithiosulfatosilver
Explanation:
The glycerol-3-phosphate shuttle can transport cytosolic NADH equivalents into the mitochondrial matrix (see Fig. 15.11c). In this shuttle, the protons and electrons are donated to FAD, which is reduced to FADH2. These protons and electrons are subsequently donated to coenzyme Q in the electron transport chain. Given that the number of ATP molecules made per NADH and FADH2 oxidation differ by ____? the amount of ATP generated per mole of glucose when the glycerol-3-phosphate shuttle would be ____ instead of 32.
Answer:
The number of ATP molecules made per NADH and FADH2 oxidation differ by 1.
The amount of ATP generated per mole of glucose when the glycerol-3-phosphate shuttle would be 30 instead of 32.
Explanation:
The glycerol-3-phosphate shuttle can transport cytosolic NADH equivalents into the mitochondrial matrix. In this shuttle, the protons and electrons are donated to FAD, which is reduced to FADH2. These protons and electrons are subsequently donated to coenzyme Q in the electron transport chain. Given that the number of ATP molecules made per NADH and FADH2 oxidation differ by 1, the amount of ATP generated per mole of glucose when the glycerol-3-phosphate shuttle would be 30 instead of 32.
FADH2 generates 1.5 ATP per molecule unlike NADH which generates 2.5 ATP per molecule. This is because electron transfer via FADH2 is not coupled to proton pumping unlike electron transfer reactions involving NADH. Thus, two moles of NADH from the oxidation of 2 moles of glyceraldehyde-2-phosophate to two moles of 1,3-bisphosphoglycerate will yield 3 moles of ATP rather than 5 moles when shuttled through the glycerol-3-phosphate shuttle. The glycerol-3-phosphate shuttle of cytosolic NADH shuttling occurs mainly in the brain and skeletal muscles and does not involve membrane transporters.
3.523 x 10^24 molecules of Mg(OH2) will need how many grams of H3PO4 in the reaction below
H=1.01 g/mol
P=30.97 g/mol
O=16.00 g/mol
3 Mg(OH)2 + 2 H3PO4 --------> 1 Mg3 (PO4 )2 + 6 H2O
Answer:
382.2g of H3PO4 are needed
Explanation:
Based on the reaction, 3 moles of Mg(OH)2 react with 2 moles of H3PO4.
To solve this question we must find the moles of Mg(OH)2 using Avogadro's number. Then, using the reaction we can find the moles of H3PO4 and its mass as follows:
Moles Mg(OH)2:
3.523x10²⁴ molecules * (1mol / 6.022x10²³ molecules) = 5.850 moles Mg(OH)2
Moles H3PO4:
5.850 moles Mg(OH)2 * (2 mol H3PO4 / 3 mol Mg(OH)2) = 3.90 moles H3PO4
Mass H3PO4:
Molar mass:
3H = 1.01g/mol*3 = 3.03
P = 30.97g/mol*1 = 30.97
4O = 16.00g/mol*4 = 64.00g/mol
3.03 + 30.97 + 64.00 = 98.00g/mol
3.90 moles H3PO4 * (98.00g / mol) =
382.2g of H3PO4 are neededWhich statement accurately depicts the mass and volume of a gas according to the kinetic molecular theory?
O Gases have no defined volume but a defined mass.
O Gases have no defined volume and no defined mass.
O Gases have a defined volume but no defined mass.
O Gases have a defined volume and a defined mass.
Answer: The statement, gases have no defined volume but a defined mass accurately depicts the mass and volume of a gas according to the kinetic molecular theory.
Explanation:
According to the kinetic molecular theory there exists constant motion between the particles of gas and perfectly elastic collisions also exist there between these particles.
Some postulates of Kinetic molecular theory are as follows.
1). The exists constant random motion in the particles of a gas.
2). There is negligible combined volume but a definite mass.
3). There exists no force of attraction between the particles of a gas.
4). Collisions which take place are completely elastic in nature.
Thus, we can conclude that the statement, gases have no defined volume but a defined mass accurately depicts the mass and volume of a gas according to the kinetic molecular theory.
The statement that accurately depicts the mass and volume of a gas according to the kinetic molecular theory is that gases have no defined volume but a defined mass.
WHAT IS KINETIC MOLECULAR THEORY?The kinetic molecular theory of gases states constant motion exists between the particles of gas and perfectly elastic collisions also exist there between these particles.
The postulates of the kinetic molecular theory are as follows:
The exists constant random motion in the particles of a gas.There is negligible combined volume but a definite mass.There exists no force of attraction between the particles of a gas.Collisions which take place are completely elastic in nature.Based on these postulates, it can be said that gases have no defined volume but a defined mass.
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pls i need help with this
Answer:
C
Explanation:
A physical change is one in which no new substance is formed. The moistening of food by saliva is purely a physical change because no new substance is formed in the process.
A chemical change leads to the formation of a new substance. The action of the enzyme converts starch into sugar which means that a new substance is formed. This is a chemical change.
Need help ASAP 100 points!
How many molecules are in 2.3 moles of Oxygen?
Question 1 options:
2.06 x 1023 molecules
6.02 x 1023 molecules
1.4 x 1023 molecules
3.8 x 1023 molecules
1.4 x 1023 molecules are present in 2.3 moles of oxygen.
How many molecules will be in the 2.3 moles of oxygen?We know that if we multiply the 2.3 moles of oxygen with Avogadro's number which is 6.023 x 1023 then this will give us the number of molecules which is present in the 2.3 moles of oxygen and which is 13.85 x 1023.
Mole is a standard scientific unit for measuring large quantities of very small entities like atoms, molecules, or other specific particles. The mole entitles an extremely large number of units about 6.02214076 × 1023.
So we can conclude that by multiplying Avogadro's number with the 2.3 moles of oxygen then it will give us 1.4 x 1023 molecules.
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10 points
label the variables you used in your equation to solve the last problem (i.e. all Ps, Vs, or Ts).
use these labeled variables to explain, using Charles' Law theory/concept why your chosen answer to the last problem makes sense.
Calculate the new temperature when a 2.0 L of a gas at 220 K is compressed to 1.0 L.
Answer:
Eventually, these individual laws were combined into a single equation—the ideal gas ... We find that temperature and pressure are linearly related, and if the ... then P and T are directly proportional (again, when volume and moles of gas are ... of the variables, and they are more difficult to use in fitting theoretical equations ...
Explanation:
Name three different properties you can test before and after a chemical reaction
Answer:
reactivity, flammability, and if they rust
What is the first quantum number of the 3p¹ electron in aluminum,
1s²2s²2p63s²3p¹?
A. n=0
B. n = 1
C. n=3
D. n = 2
Quantum number of the 3p¹ electron in aluminum is n=3.
What is the quantum number?Quantum numbers in quantum physics and chemistry explain the values of conserved quantities in a quantum system's dynamics. Quantum numbers are quantities that can be precisely known at the same time as the system's energy and are related to the eigenvalues of operators that commute with the Hamiltonian and their corresponding eigenspaces. A base state of a quantum system is fully described by the specification of all of its quantum numbers, which can theoretically be measured collectively.
The quantization of numerous interesting observable quantities is a crucial component of quantum physics.
This specifically results in quantum numbers, though they may occasionally reach infinity, that take values in discrete sets of integers or half-integers. This sets quantum mechanics apart from conventional mechanics.
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Calculate the hydrogen ion concentration in a 3.4 x 10-3 M
solution of KOH.
Explanation:
[tex]KOH→K {}^{ + } + OH {}^{ - } \\ [OH {}^{ - } ] = 3.4 \times {10}^{ - 3} \\ k _{w} = [OH {}^{ - } ] [H {}^{ + } ] \\ 1 \times {10}^{ - 14} = 3.4 \times {10}^{ - 3} \times [H {}^{ + } ] \\ [H {}^{ + } ] = 2.94 \times {10}^{ - 12} \: M[/tex]
Answer:
2.9 X 10^-12 M
Explanation:
In a nuclear fission reaction, a freely moving neutron is introduced to a
nuclear fuel, such as uranium-235. What happens next?
O A. A neutron is absorbed by an atom's nucleus.
B. The neutron breaks apart.
O C. Heat is released by the neutron.
D. The nucleus becomes unstable.
The nucleus becomes unstable when a freely moving neutron is introduced to a nuclear fuel.
What is Nuclear fission?This is a reaction in which the nucleus of an atom splits into two or more smaller nuclei.
This reaction produces more neutrons and the nucleus becomes unstable when a freely moving neutron is introduced to a nuclear fuel to form fission fragments.
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Every day, each person in Canada throws out about 2.2 kg of garbage. If the population of Canada is 31 900 000, the total mass of garbage that all Canadians throw out each day is
Answer:
70 180 000 kg
Explanation:
We can solve this problem by multiplying the amount of garbage each Canadian throws out each day (2.2 kg) by the number of Canadians:
2.2 kg/person * 31 900 000 persons = 70 180 000Thus according to this problem, all Canadians throw out 70 180 000 kg of garbage each day.
1. what are the methods of vegetative propagation
2.give examples of organisms exihibiting each type
3.tubers-definitio example potatoes
science subject
Natural vegetative propagation uses bulbils, aerial shoots, roots, underground stems, and subaerial stems. Utilizing unique vegetative components, artificial vegetative propagation is accomplished.
What is vegetative propagation, and how does it work?The production and growth of a new plant through asexual means or from a plant fragment is known as vegetative propagation. There is no gamete production or fertilization throughout the process of propagation.
What are some instances of vegetative tuber propagation?In this procedure, tubers—modified roots—grow into new plants. In some plant species, adventitious buds even grow on the roots. If the correct circumstances are present, these buds develop into new plants or sprouts. Sweet potato and dahlia are two examples.
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17. A balloon contains 4.50 X 1022 atoms of helium gas. Calculate the mass of helium in
grams.
Answer:
1.08 grams
Explanation:
first, we need to find the number of moles
we divide 12.1/22.4=0.54 moles
we multiply the number of moles with the molecular mass 0.54x2=1.08g
The mass of the helium will be 0.296 g He.
What is mass?
The quantity of matter in a thing is measured by its mass. Grams (g) or kilograms (kg) are the most common units of mass measurement (kg).The quantity of matter is measured in terms of mass, regardless of where it is in the universe or the gravitational force acting on it.
Calculation of mass of helium:
It is given that, atom of He = 4.50 X [tex]10^{22}[/tex] , mass of He = 4 g.
4.50 X [tex]10^{22}[/tex] atoms He × 1 mole He / 6.02 × [tex]10^{23}[/tex] atom He = 0.0914 mol He.
Now, apply the conversion formula:
Moles He × grams He / 1 mole He = grams He.
Put the value of given data in above formula.
0.0914 mol He × 4 g / 1 mol He = 0.296 g He.
Therefore, the mass of the helium will be 0.296 g He.
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For the reaction H2(g) +O2(g) — H2O (g) how many liters of water can be made from 5 L of oxygen gas at 37.0 Celsius, 1.76atm and an excess of hydrogen?
Answer:
12.5 L
Explanation:
Part 1 - Finding Number of moles
First thing we need to find out is number of moles of oxygen gas. We can achieve this using the formula: PV=nRT
Pressure (Pa) x Volume (cubic meters) = no. moles x gas constant (8.31 J/K*mol) x Temperature (K)
We can rearrange this formula to solve for no. moles:[tex]n=\frac{PV}{RT}[/tex] and plug in the values to solve.
1 atm = 1.01325 x 10^5 Pa, therefore 1.76atm = [tex]1.76*1.01325*10^{5} =178332Pa[/tex]
1 L = 1 x 10^-3 m^3, therefore 5L = [tex]5*1*10^{-3}=5*10^{-3}m^{3}[/tex]
Finally Kelvin = Celsius + 273.15, therefore 37.0C = [tex]37.0+273.15=310.15K[/tex]
Substituting this all back into the formula we get:
[tex]n=\frac{(178332)(5*10^{-3})}{(8.31)(310.15)}[/tex]
[tex]n=\frac{891.66}{2577.3465}[/tex]
[tex]n=0.346[/tex] moles (3.s.f)
Part 2 - Balancing Equation
The equation given is not balanced so we need to balance it to find the correct molar ratio. We can start by balancing the oxygens as there are less of them. We can see that there are 2 oxygen atoms on the left as denoted by 'O2' but only one on the right in 'H2O', therefore we can add a two in front of the H2O on the right side to balance the oxygen atoms:
[tex]H_{2(g)} +O_{2(g)} - > 2H_{2} O_{(g)}[/tex]
Now we have four hydrogens on the right side so we have a 2 in front of H2 on the left hand side to balance the hydrogens:
[tex]2H_{2(g)} +O_{2(g)} - > 2H_{2} O_{(g)}[/tex]
And voila! The equation is balanced and shows the correct molar ratio.
Part 3 - Calculating moles of water
As we can see from the molar ratio in the balanced equation, every mole of O2 will produce two moles of H2O- the ratio is 1:2. As we have an excess of hydrogen, we only need to worry about the amount of oxygen we have. Therefore to calculate the number of moles of water that can be made we simply need to multiple by the ratio:
[tex]0.346*2=0.692[/tex] moles of water
Part 4 - Converting to Liters
Finally, to convert our amount of moles into volume, we can use water's molecular mass to find the mass and then its density to find its volume. Water's molecular mass is 18.02gmol^-1 (2x1.01+16.00) and its density is 997kg/m^3.
m=nM (mass = no. moles x molecular mass): m=[tex]0.692*18.02=12.46984g[/tex]
rho = m/v (density = mass/volume): [tex]997=12.46984/v[/tex], therefore [tex]v=0.0125m^{3}[/tex]
Finally as mentioned above, 1 L = 1 x 10^-3 m^3, therefore the volume of water that can be made is 12.5 Liters.
what do animals use for energy in food
A. GROWTH
B. REPAIR
C. MOTION
D. PHOTOSYNTHESIS
name one solid that can be used in place of candle wax while will give the same result
Answer:
Paraffin Wax
Explanation:
Paraffin wax is one of the most widely used waxes for candle making. A cheaper alternative, it is a derivable from petroleum, coal or oil. This wax is white and odorless and will keep a consistent appearance throughout your candle's life.