Let a,b,c and d be distinct real numbers. Show that the equation (3 – b)(x – c)(x – d) + (x – a)(x – c)(x – d) + (x – a)(x – b)(x – d) + (x – a) (x – b)(– c) = 0 (1) has exactly 3 distinct real solutions. (Hint: Let p(x) = (x – a)(x – b)(c – c)(x – d). Then p(x) = 0 has how many distinct real solutions? Then use logarithmic differentiation to show that p' (2) is given by the expression on the left hand side of (1). Now, apply Rolle's theorem. )

The area of the kitchen that Carolyn needs to tile is A = 248 feet²

Given data ,

Let the area of the kitchen that Carolyn needs to tile is A

Now , the figure consists of a rectangle and a trapezoid

Now , the area of rectangle is R = 8 x 16

R = 128 feet²

Now , the area of the remaining trapezoidal figure is T

T = ( 8 + 16 ) ( 18 - 8 ) ( 1/2 )

T = 120 feet²

Now , the total area of the kitchen A = R + T

A = 128 feet² + 120 feet²

A = 248 feet²

Hence , the area of the tile is A = 248 feet²

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The complete question is attached below :

Carolyn wants to tile her kitchen the layout of her kitchen is shown What area does Carolyn need to tile

The approximate value of 6.032 + 5.982 + 6.992 using the linear approximation is 121.22.

To find the linear approximation of the function f(x, y, z) = x² + y² + z² at (6, 6, 7), we need to calculate the partial derivatives of f with respect to x, y, and z at the given point. Then we can use these derivatives to form the equation of the tangent plane, which will serve as the linear approximation.

Let's start by calculating the partial derivatives:

∂f/∂x = 2x

∂f/∂y = 2y

∂f/∂z = 2z

Now, we can evaluate the partial derivatives at (6, 6, 7):

∂f/∂x = 2(6) = 12

∂f/∂y = 2(6) = 12

∂f/∂z = 2(7) = 14

The equation of the tangent plane can be written as:

f(x, y, z) ≈ f(a, b, c) + ∂f/∂x(a, b, c)(x - a) + ∂f/∂y(a, b, c)(y - b) + ∂f/∂z(a, b, c)(z - c)

Plugging in the values from the given point (6, 6, 7) and the partial derivatives we calculated:

f(x, y, z) ≈ f(6, 6, 7) + 12(x - 6) + 12(y - 6) + 14(z - 7)

≈ 6² + 6² + 7² + 12(x - 6) + 12(y - 6) + 14(z - 7)

≈ 36 + 36 + 49 + 12(x - 6) + 12(y - 6) + 14(z - 7)

≈ 121 + 12(x - 6) + 12(y - 6) + 14(z - 7)

Now, let's use this linear approximation to approximate the value of f(6.03, 5.98, 6.99):

f(6.03, 5.98, 6.99) ≈ 121 + 12(6.03 - 6) + 12(5.98 - 6) + 14(6.99 - 7)

≈ 121 + 12(0.03) + 12(-0.02) + 14(-0.01)

≈ 121 + 0.36 - 0.24 - 0.14

≈ 121 + 0.22

≈ 121.22

Therefore, the approximate value of 6.032 + 5.982 + 6.992 using the linear approximation is 121.22.

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Therefore, the weight of the blood is approximately 53.96 N. False.

The volume of blood that circulates within a person varies according to their size and weight, but an adult human has around 5 liters of blood in circulation on average. A newborn weighing around 8 pounds will have roughly 270 mL, or 0.07 gallons, of blood in their body.

Children: An 80-pound youngster on average will have 0.7 gallons, or 2,650 mL, of blood in their body. Adults: The amount of blood in the body of a typical adult weighing 150 to 180 pounds should be between 1.2 and 1.5 gallons.

The weight of the blood can be calculated using the formula W = m*g, where m is the mass of the blood and g is the acceleration due to gravity.

In this case, the mass of the blood is 5.5 kg (not liters, as mass is measured in kg), so we can calculate the weight as:

W = 5.5 kg * 9.81 m/s = 53.9555 N

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Correct Question:

State true or false: Considering that an adult woman weighing 70 kg has 5.5 liters of blood, approximately Mind determines the weight of the blood. W=57. 13 N​

S is not a basis for P_2.

The coordinate vector of 2 - 3t with respect to the basis B is [2, -3, 0].

The subset { -3 + 4t + 2t², 2 - 3t } is a basis for P_2.

We have,

(a)

The set S is a set of four polynomials in P_2, which is a vector space of polynomials with degree at most 2.

Each polynomial in S has a degree 2 or less, so we can express each polynomial as a linear combination of the standard basis {1, t, t²} for P_2. Therefore,

S is a subset of the three-dimensional vector space P_2, and since S has more than three elements, it must be linearly dependent by the dimension theorem.

Therefore, S is not a basis for P_2.

(b)

To calculate the coordinate vectors of the vectors in S with respect to the basis B, we need to express each vector in S as a linear combination of the basis vectors {1, t, t²}.

For the first polynomial in S, 5t + t².

5t + t² = 0(1) + 5(t) + 1(t²)

Therefore,

The coordinate vector of 5t + t² with respect to the basis B is [0, 5, 1].

For the second polynomial in S, 1 - 8t - 2t².

1 - 8t - 2t² = 1(1) - 8(t) - 2(t²)

Therefore, the coordinate vector of 1 - 8t - 2t² with respect to the basis B is [1, -8, -2].

For the third polynomial in S, -3 + 4t + 2t².

-3 + 4t + 2t² = -3(1) + 4(t) + 2(t²)

Therefore, the coordinate vector of -3 + 4t + 2t² with respect to the basis B is [-3, 4, 2].

For the fourth polynomial in S, 2 - 3t.

2 - 3t = 2(1) - 3(t) + 0(t²)

Therefore, the coordinate vector of 2 - 3t with respect to the basis B is

[2, -3, 0].

(c)

To find a subset of S that is a basis for P_2, we need to find a linearly independent subset of S that spans P_2.

From part (b), we know that the vectors in S do not form a basis for P_2 because S is linearly dependent.

However, we can still find a subset of S that is a basis for P_2.

We can see that the third and fourth polynomials in S, -3 + 4t + 2t² and

2 - 3t, respectively, are linearly independent because they do not have any terms in common.

Additionally, we can verify that they span P_2 by checking that any polynomial of degree at most 2 can be written as a linear combination of these two polynomials.

Therefore, the subset { -3 + 4t + 2t², 2 - 3t } is a basis for P_2.

Thus,

S is not a basis for P_2.

The coordinate vector of 2 - 3t with respect to the basis B is [2, -3, 0].

The subset { -3 + 4t + 2t², 2 - 3t } is a basis for P_2.

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The number 8007 is congruent to 7 modulo 8, so it cannot be written as the sum of three perfect squares, the equation: x^2 + y^2 + z^2 = 8007 has no solutions.

We can prove this by working modulo 8. Any perfect square is congruent to either 0, 1, or 4 modulo 8. Therefore, the sum of three perfect squares is congruent to either 0, 1, 2, 3, 4, or 5 modulo 8. However, 8007 is congruent to 7 modulo 8, so it cannot be written as the sum of three perfect squares.

Therefore, the equation x^2 + y^2 + z^2 = 8007 has no solutions.

To demonstrate that there are infinitely many positive integers which cannot be expressed as the sum of three squares, we can use a similar argument. If n is a positive integer such that n is congruent to 7 modulo 8, then n cannot be written as the sum of three perfect squares, as shown above.

Since there are infinitely many positive integers congruent to 7 modulo 8, there must be infinitely many positive integers which cannot be expressed as the sum of three squares. This is a consequence of the fact that the sum of three squares is a quadratic form, and the theory of quadratic forms tells us that there are only finitely many positive integers which cannot be expressed as the sum of three squares.

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Complete question:

8. Prove that the equation x2 + y2 + z2 = 8007 has no solutions.

(HINT: Work Modulo 8.) Demonstrate that there are infinitely many positive integers which cannot be expressed as the sum of three squares.

The correct answer is a. single-factor, independent groups design. In this design, there is one independent variable with two or more levels, and participants are randomly assigned to these levels, making the groups independent.

A t test for independent groups is specifically used to compare the means of two independent groups in an experimental design, where participants are randomly assigned to either a control or treatment group. This design is also known as a between-subjects design, as participants are only exposed to one level of the independent variable (the treatment or control condition). The other options listed - matched groups design and nonequivalent groups design - both involve some form of matching or pairing of participants, which would require a different type of statistical test (e.g. a paired t test or ANOVA). This t-test compares the means of the experimental conditions to determine if there is a significant difference between them.

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The parametric equations and symmetric equations of the line are:

(x, y, z) = (-2, 3, 5) + t(u, v, w)

(x + 2) / u = (y - 3) / v = (z - 5) / w

Let's first consider the case where the line is parallel to a given vector.

If the line is parallel to a vector v = (a, b, c), then any point on the line can be represented as:

(x, y, z) = (x₀, y₀, z₀) + t(a, b, c)

where (x₀, y₀, z₀) is a point on the line and t is a parameter that varies over all real numbers.

Now, suppose we want the line to pass through a point P = (-2, 3, 5) and be parallel to a vector v = (u, v, w). Then we can choose P as our point on the line and write:

(x, y, z) = (-2, 3, 5) + t(u, v, w)

These are the parametric equations of the line.

To find the symmetric equations of the line, we can eliminate the parameter t by solving for it in each equation:

x + 2 = tu

y - 3 = tv

z - 5 = tw

Then, we can eliminate t by setting the ratios of these equations equal to each other:

(x + 2) / u = (y - 3) / v = (z - 5) / w

These are the symmetric equations of the line.

Alternatively, if the line is parallel to another line L that passes through a point Q = (x₁, y₁, z₁) and has direction vector d = (d₁, d₂, d₃), then any point on the line can be represented as:

(x, y, z) = (x₁, y₁, z₁) + t(d₁, d₂, d₃)

where t is a parameter that varies over all real numbers.

To find the parametric equations and symmetric equations of the line that passes through P and is parallel to L, we can set Q = P and d = v, giving:

(x, y, z) = (-2, 3, 5) + t(u, v, w)

(x + 2) / u = (y - 3) / v = (z - 5) / w

These are the parametric equations and symmetric equations of the line.

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The final hash table with collisions resolved by chaining looks like this:

0: 36
1: 10 -> 1
2: (empty)
3: 12 -> 21
4: 22
5: (empty)
6: 6 -> 15 -> 33
7: (empty)
8: 35

To insert the keys into a hash table with 9 slots using the hash function h(k) = k mod 9 and resolving collisions by chaining, follow these steps:

1. Initialize an empty hash table with 9 slots.

2. Calculate the hash values for each key using the hash function h(k) = k mod 9:

- 10 mod 9 = 1
- 22 mod 9 = 4
- 35 mod 9 = 8
- 12 mod 9 = 3
- 1 mod 9 = 1
- 21 mod 9 = 3
- 6 mod 9 = 6
- 15 mod 9 = 6
- 36 mod 9 = 0
- 33 mod 9 = 6

3. Insert the keys into the hash table according to their hash values, using chaining to resolve collisions:

- Slot 0: 36
- Slot 1: 10 -> 1
- Slot 2: (empty)
- Slot 3: 12 -> 21
- Slot 4: 22
- Slot 5: (empty)
- Slot 6: 6 -> 15 -> 33
- Slot 7: (empty)
- Slot 8: 35

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To factor the denominator, we need to find the roots of the quadratic equation 2x^2 + x - 1 = 0.

The quadratic equation can be factored as follows:

2x^2 + x - 1 = (2x - 1)(x + 1)

So, the denominator can be written as:

2x^2 + x - 1 = (2x - 1)(x + 1)

Now we can express the fraction as partial fractions:

(2+x)/(2x^2+x-1) = A/(2x - 1) + B/(x + 1)

To find the values of A and B, we need to find a common denominator:

(2+x)/(2x^2+x-1) = (A(x + 1) + B(2x - 1))/(2x^2 + x - 1)

Now we equate the numerators:

2 + x = A(x + 1) + B(2x - 1)

Expanding the right side:

2 + x = Ax + A + 2Bx - B

Grouping like terms:

2 + x = (A + 2B)x + (A - B)

By comparing the coefficients of x and the constant term on both sides, we get the following system of equations:

A + 2B = 1

A - B = 2

Solving this system of equations, we find A = 3/5 and B = -7/5.

Therefore, we can write the partial fraction decomposition as:

(2+x)/(2x^2+x-1) = 3/5/(2x - 1) - 7/5/(x + 1)

The coefficient of x^r is determined by the constant term in the expansion of the numerator in the series form. Since the numerator is 2 + x, the coefficient of x^r is 0 when r is not equal to 0. When r is equal to 0, the coefficient is 2.

So, the coefficient of x^r in the series representation of the given generating function is 2 when r = 0.

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The number that both Julie and Liam wrote down is 8/17.

Let's start by using algebra to solve the problem. Let x be the number that both Julie and Liam wrote down.

Julie's answer: 5x + 4

Liam's answer: 10 - x

We know that Julie's answer is two-thirds of Liam's answer, so:

5x + 4 = (2/3)(10 - x)

Multiplying both sides by 3, we get:

15x + 12 = 20 - 2x

Adding 2x to both sides, we get:

17x + 12 = 20

Subtracting 12 from both sides, we get:

17x = 8

Dividing both sides by 17, we get:

x = 8/17

Therefore, the number that both Julie and Liam wrote down is 8/17.

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The recurrence relation for the number of ways to arrange cars in a row with n parking spaces if we can use Cadillacs, Hummers, or Fords can be written as: A(n) = 3A(n-1) .

Let A(n) be the number of ways to arrange cars in a row with n parking spaces. We can place either a Cadillac, Hummer, or Ford in the first parking space. If we place a Cadillac, then we have A(n-1) ways to arrange the remaining (n-1) parking spaces.

Similarly, if we place a Hummer or a Ford in the first parking space, we have A(n-1) ways to arrange the remaining parking spaces. Therefore, the recurrence relation can be written as: A(n) = 3A(n-1)

with initial condition A(1) = 3. This recurrence relation tells us that the number of ways to arrange cars in a row with n parking spaces is three times the number of ways to arrange cars in a row with (n-1) parking spaces.

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The correct equation to find the number of miles Alberto is running after training for w weeks is B. M= 2w + 5.

We know that Alberto starts with running 5 miles, and increases his distance by 2 miles each week. So after w weeks, he would have run 5 + (2 x w) miles.

Therefore, the equation that represents the number of miles, M, run by Alberto after training for w weeks would be:

M = 2w + 5

To verify this, we can substitute different values of w in the equation to calculate the corresponding value of M. For example, if w=3, then:

M = 2(3) + 5

M = 11

So after training for 3 weeks, Alberto will be running 11 miles. Similarly, we can check for other values of w to see that the equation holds true.

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If square based pyramid's perimeter is 18.5 ft and it's height is 7.6 ft, then volume of that pyramid is 54.4 cubic foot.

The "Volume" of a square pyramid is known as the space which is occupied by pyramid, and it is represented as : V = (1/3) × B × h, where V is volume, B is area of base, and h is height of pyramid,

The shape of "base-of-pyramid" is a square,

So, we find "base-area" by dividing perimeter by 4 and squaring it;

⇒ Perimeter of base of pyramid = 18.5 ft,

⇒ Length of "one-side" of base = 18.5/4 = 4.625 ft,

So, ⇒ Base area = (4.625 ft)² = 21.390625 sq ft,

Now, using the formula to find volume;

⇒ Volume = (1/3) × 21.390625 × 7.6 ,

⇒ Volume = 54.384375 cubic feet,

Rounding volume to "nearest-tenth" of a cubic foot,

We get,

⇒  Volume ≈ 54.4 ft³.

Therefore, Volume of pyramid is 54.4 ft³.

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The given question is incomplete, the complete question is

Find the volume of a pyramid with a square base, where the perimeter of the base is 18.5 ft and the height of the pyramid is 7.6 ft. Round your answer to the nearest tenth of a cubic foot.

The sum of the polynomials 4x³ + 6x²+ 2x - 3 and 3x³ + 3x² - 5x - 5 is 7x³ + 9x² - 3x - 8.

Given are two polynomials.

4x³ + 6x²+ 2x - 3 and 3x³ + 3x² - 5x - 5

We have to find the sum of these polynomials.

These have to be added operating the like terms.

Here 4x³ and 3x³ are the like terms.

6x² and 3x² are the like terms.

2x and -5x are the like terms.

-3 and -5 are like terms.

(4x³ + 6x² + 2x - 3) + (3x³ + 3x² - 5x - 5) = (4x³ + 3x³) + (6x² + 3x²) + (2x - 5x) + (-3 - 5)

= 7x³ + 9x² - 3x - 8

Hence the sum of the polynomials is 7x³ + 9x² - 3x - 8.

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To solve this problem, we first need to find the total number of marbles in the goblet. Adding up the number of red, green, and blue marbles, we get a total of 2 22 + 6 66 + 4 44 = 13 32 marbles, Next, we need to find the probability of choosing a green marble on the first draw.

There are 6 66 green marbles out of 13 32 total marbles, so the probability is 6 66 / 13 32, Since we didn't put the first marble back in the goblet, there are now 13 31 marbles left in the goblet and one less green marble. So, the probability of choosing a green marble on the second draw, given that we already chose a green marble on the first draw, is 5 65 / 13 31.

To find the probability of both events happening together (choosing a green marble on the first draw and another green marble on the second draw), we multiply the probabilities of each event: (6 66 / 13 32) * (5 65 / 13 31) = 0.073 or approximately 7.3%.


To find the probability of picking two green marbles one after another without replacement, we can use the following steps:

1. Calculate the total number of marbles in the goblet:
Total marbles = 22 red marbles + 6 green marbles + 4 blue marbles = 32 marbles

2. Find the probability of picking a green marble on the first draw:
P(Green1) = (number of green marbles) / (total number of marbles)
P(Green1) = 6/32

3. Update the number of marbles after the first green marble is drawn:
Total marbles remaining = 32 - 1 = 31 marbles
Green marbles remaining = 6 - 1 = 5 marbles

4. Find the probability of picking a green marble on the second draw:
P(Green2) = (number of green marbles remaining) / (total number of marbles remaining)
P(Green2) = 5/31

5. Calculate the probability of both events occurring:
P(Green1 and Green2) = P(Green1) * P(Green2)
P(Green1 and Green2) = (6/32) * (5/31)

6. Simplify the probability:
P(Green1 and Green2) = 30/992

So, the probability of picking two green marbles consecutively without replacement is 30/992.

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The simplified form of expression [tex]5\sqrt[3]{4x^2y} \times 2\sqrt[3]{6xy^4}[/tex] is [tex]20xy\sqrt[3]{3y^2}[/tex]

The correct answer is an option (C)

We know that the rule of exponents.

[tex](ab)^m=a^mb^m[/tex]

[tex](a^m)^n=a^{m\times n}[/tex]

consider an expression,

[tex]5\sqrt[3]{4x^2y} \times 2\sqrt[3]{6xy^4}[/tex]

We need to simplify this expression.

[tex]5\sqrt[3]{4x^2y} \times 2\sqrt[3]{6xy^4}[/tex]

[tex]=10(4x^2y)^{\frac{1}{3} }\times (6xy^4)^{\frac{1}{3} }[/tex]            ........(write radical form to exponent form)

[tex]=10\times 4^{\frac{1}{3} }\times (x^2)^{\frac{1}{3} }\times y^{\frac{1}{3} }\times 6^{\frac{1}{3} }\times x^{\frac{1}{3} }\times (y^4)^{\frac{1}{3} }[/tex]    ..........(seperate the exponents)

[tex]=20\times \sqrt[3]{3}\times x^{\frac{2}{3} }\times y^{\frac{1}{3} }\times x^{\frac{1}{3} }\times y^{\frac{4}{3} }[/tex]             ..............(simplify)

We know that the exponent rule while multiplying the two numbers if the base of exponents is same then we add the powers.

i.e., [tex]a^m\times a^n=a^{m+n}[/tex]

So our expression becomes,

[tex]=20\times \sqrt[3]{3}\times x^{(\frac{2}{3} + \frac{1}{3} )}\times y^{(\frac{1}{3} + \frac{4}{3} )}[/tex]

[tex]=20\times \sqrt[3]{3}\times x^{\frac{3}{3}}\times y^{\frac{5}{3} }[/tex]              ...............(simplify)

[tex]=20x\times \sqrt[3]{3}\times y^{(\frac{2}{3} +\frac{3}{3} )}[/tex]            .........(exponent rule [tex]a^m\times a^n=a^{m+n}[/tex])

[tex]=20xy\times \sqrt[3]{3}\times \sqrt[3]{y^2}[/tex]          

Here, the powers of [tex]\sqrt[3]{3}[/tex] and [tex]\sqrt[3]{y^2}[/tex] are same.

This means that we can write the product [tex]\sqrt[3]{3}\times \sqrt[3]{y^2}[/tex] as [tex]\sqrt[3]{3y^2}[/tex]

So our expression becomes,

[tex]=20xy\times \sqrt[3]{3y^2}[/tex]

[tex]=20xy\sqrt[3]{3y^2}[/tex]

This is the simplified form of expression [tex]5\sqrt[3]{4x^2y} \times 2\sqrt[3]{6xy^4}[/tex]

Therefore, the correct answer is an option (C)

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Answer: 3 6 11

Step-by-step explanation:

Answer: 3:6:11

Step-by-step explanation: did the question and got this

The expression  x² + x ‐ 6 factors as (x - 2)(x + 3) and the expression x² + 49  has factors (x + 7i)(x - 7i)

The given expression is x² + x ‐ 6

We need to find two numbers whose product is -6 and whose sum is 1. Those numbers are 3 and -2.

We can rewrite the expression as:

x² + x ‐ 6

=x² + 3x - 2x - 6

=(x² + 3x) - (2x + 6)

= x(x + 3) - 2(x + 3)

= (x - 2)(x + 3)

Therefore, x² + x ‐ 6 factors as (x - 2)(x + 3).

x² + 49:

This expression cannot be factored using real numbers because there are no two real numbers whose product is 49 and whose sum is 0. However, if we allow for complex numbers, we can factor x² + 49 as:

x² + 49 = (x + 7i)(x - 7i)

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a) The approximate value of cos(1/2) using the linear approximation is 0.877.

b) The length of the person's shadow is decreasing at a rate of 1.8 m/s when the person is 3 m from the post.

a) To find the linear approximation to f(x) = cos(2x) at x = π/6, we need to use the formula:

L(x) = f(a) + f'(a) * (x - a)

where a is the point of approximation, in this case a = π/6, and f'(x) is the derivative of f(x).

So, first we calculate the derivative of f(x):

f'(x) = -2sin(2x)

Then, we plug in the values for a, f(a), and f'(a):

L(x) = cos(π/3) + (-2sin(π/3))*(x - π/6)

Simplifying:

L(x) = 1/2 - √3/2 * (x - π/6)

Now, to approximate cos(1/2) using this linear approximation, we plug in x = 1/4 (since π/6 is approximately 0.524, and 1/4 is approximately 0.785, which is closer to 1/2):

L(1/4) = 1/2 - √3/2 * (1/4 - π/6) ≈ 0.877

So, the approximate value of cos(1/2) using the linear approximation is 0.877, to three significant digits.

b) We can use similar triangles to find the relationship between the length of the person's shadow and the distance from the post. Let L be the length of the person's shadow, and let x be the distance from the person to the post. Then, we have:

L/x = 6/2

Simplifying:

L = 3x

Now, we take the derivative of both sides with respect to time t:

dL/dt = 3(dx/dt)

We are given that dx/dt = -0.6 m/s (since the person is walking towards the post), and we want to find dL/dt when x = 3. Plugging in these values:

dL/dt = 3(-0.6) = -1.8 m/s

So, the length of the person's shadow is decreasing at a rate of 1.8 m/s when the person is 3 m from the post.

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The total price after applying the 10% discount of two $10 items and one $5 item is $40.50.

Let's calculate the original price of our items,

Two $20.00 items,

$20.00 x 2 = $40.00,

One $5.00 item, $5.00,

The total original price of our items is,

$40.00 + $5.00 = $45.00,

For finding the amount of the discount that we have to make, we just do the product of the percentage of the discount to total original amount of the items,

$45.00 x 10% = $4.50

So, the amount discounted is $4.50.

To find the amount after the discount, we subtract the discounted price from the original amount.

$45.00 - $4.50 = $40.50

Hence, the total price of the items will be $40.50.

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The probability that team A wins the best-of-three series over team B can be found using the binomial distribution formula. Let X be the number of games team A wins in the series.

Since team A has a probability of 1/4 of winning each game, the probability of winning exactly k games in a three-game series is given by the formula P(X=k) = (3 choose k) * (1/4)^k * (3/4)^(3-k), where (3 choose k) is the number of ways to choose k games out of three.

To find the probability that team A wins the series, we need to sum up the probabilities of winning two or three games, i.e., P(X=2) + P(X=3). Using the formula, we get P(X=2) = 9/64 and P(X=3) = 1/64, so the probability that team A wins the best-of-three series over team B is P(X=2) + P(X=3) = 10/64 = 5/32, or approximately 0.15625.

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The point estimate is 0.2468 and the sample standard deviation is 0.7452.

The point estimate for the proportion of students who work full-time while going to school is the sample proportion, which is:

p = 170/689 ≈ 0.2468 (rounded to four decimal places)

To find the sample standard deviation, we first need to find the standard error of the proportion, which is given by:

SE = √[p(1 - p)/n]

where n is the sample size. Substituting the given values, we get:

SE = √[(0.2468)(1 - 0.2468)/689] ≈ 0.0196

The sample standard deviation is then obtained by multiplying the standard error by the square root of the sample size:

s = SE × √n ≈ 0.0196 × √689 ≈ 0.7452

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The reduced normal form of the expression is (x y z) (x y z).

To reduce the expression to normal form, we need to apply beta-reductions until we cannot apply any more.

The first step is to apply the function (ax.Ay.xy z) to the argument (Ac.c):

(ax.Ay.xy z) (Ac.c)

=> A(Ac.c)y.(xy z)[x:=Ax.Ay.xy z]

=> A(Ac.c)y.(Ay.xy z)c

=> A(Ac.c)(Az.yz)c

=> Ac

Next, we apply the function ((a.a) b) to the argument Ac:

((a.a) b) Ac

=> (a.a) (b Ac)

=> a[b:=b Ac].a[b:=b Ac]

=> b Ac b Ac

Finally, we apply the function b to the argument (x y) z:

b ((x y) z)

=> ((x y) z) ((x y) z)

=> (x y z) (x y z)

Therefore, the reduced normal form of the expression is (x y z) (x y z).

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Answer:

9b² + 3b - 6

Step-by-step explanation:

(3b + 3)(3b - 2)

each term in the second factor is multiplied by each term in the first factor, that is

3b(3b - 2) + 3(3b - 2) ← distribute parenthesis

= 9b² - 6b + 9b - 6 ← collect like terms

= 9b² + 3b - 6 ← in standard form

All the solutions are,

45) s(- 1/6) ≠ 0

Hence, x = - 1/6 is not a factor of s (x).

46) All the roots are,

⇒ x = 5

⇒ x = ±2i

47) q (- 5/2) ≠ 0

Given that;

45) s(-1/6)=0, factor as completely as possible:

⇒ s(x) = 36x³ +36x² -31x - 6

Here, plug x = -1/6

We get;

s(- 1/6) ≠ 0

Hence, x = - 1/6 is not a factor of s (x).

46) P (x) = x³ - 5x² + 4x - 20

Plug x = 5;

P (5) = (5)³ -  5 (5)² + 4×5 - 20

P (5) = 125 - 125 + 20 - 20

P (5) = 0

Other roots are,

P (x) = x³ - 5x² + 4x - 20

P (x) = x² (x - 5) + 4 (x - 5)

P (x) = (x² + 4) (x - 5)

Hence, All the roots are,

⇒ x² = - 4

⇒ x = ±2i

And, ⇒ x = 5

47) q(x) = 3x³ -3x² - 10x + 25

Plug x = - 5/2;

q (x) = 3 (- 5/2)³ - 3 (- 5/2)² - 10 (- 5/2) + 25

q (x) = - 375/8 - 75/4 + 25 + 25

q (x) = - 375/8 - 150/8 + 50

q (x) = - 525/8 + 50

q (- 5/2) ≠ 0

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The exact function values are:

(a) sin 2t = -4/5

(b) cos 2t = -3/5

(c) tan 2t = 4/3

In Quadrant II, the sine of the t is positive and the cosine of the t is negative. After Using the double angle formulas, we can easily find the values of sin 2t, cos 2t, and tan 2t.

(a) sin 2t = 2sin t cos t = 2(-2/5)(-3/5) = -4/5

(b) cos 2t = cos² t - sin² t = (-3/5)² - (-2/5)² = -9/25 - 4/25 = -3/5

(c) tan 2t = (2tan t)/(1-² t) = (2(-2/5))/(1-(-2/5)²) = 4/3.

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The given statement "the understanding of percent requires no new skills or concepts beyond those used in mastering fractions, decimals, ratios, and proportions." is generally true.

Understanding percentages involves converting a proportion or ratio to a fraction with a denominator of 100. For example, 75% is equivalent to 75/100 or 3/4. Converting between percentages, fractions, and decimals requires a solid understanding of the relationships between these different forms of numbers, which are based on the same underlying concepts of part-whole relationships.

To convert a percentage to a decimal, you can divide by 100 or move the decimal point two places to the left. To convert a decimal to a percentage, you can multiply by 100 or move the decimal point two places to the right. To convert a fraction to a percentage, you can first convert it to a decimal and then multiply by 100.

Understanding percentages is also important for many real-world applications, such as calculating discounts, interest rates, and taxes. It is therefore important to have a strong foundation in fractions, decimals, ratios, and proportions in order to fully grasp the concept of percentages.

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Using Lagrange multiplier method, g(x,y) = [tex]xy^2[/tex], and the local extrema occur at (2√3, √6) and (-2√3, -√6).

To find the local extrema of [tex]xy^2[/tex] subject to xty=4, we can use the method of Lagrange multipliers. First, we set up the Lagrangian function L(x,y,λ) = [tex]xy^2[/tex] + λ(xty-4).

Then, we find the partial derivatives of L with respect to x, y, and λ and set them equal to zero:

∂L/∂x = [tex]y^2[/tex] + λty = 0
∂L/∂y = 2xy + λxt = 0
∂L/∂λ = xty - 4 = 0

Solving these equations simultaneously, we get:

x = 2t/3
y = ±√(8/3t)
λ = -4/9[tex]t^2[/tex]

Substituting these values back into the original function [tex]xy^2[/tex], we get:

g(x,y) = (2t/3)(8/3t) = 16/9

Therefore, the function we would call g(x,y) in the Lagrange multiplier method is g(x,y) = [tex]xy^2[/tex], and the local extrema occur at (2√3, √6) and (-2√3, -√6).

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The height of the building is approximately 554.26 feet.

To find the height of the building, you can use the tangent formula in trigonometry. The formula you need is:
height = distance × tan(angle)
where "height" is the height of the building, "distance" is the distance from the base of the building, and "angle" is the angle of elevation.
In this case, the distance is 2 miles and the angle of elevation is 3 degrees. First, convert the angle to radians:
angle (in radians) = angle (in degrees) × (π/180)
angle (in radians) = 3 × (π/180) ≈ 0.05236 radians
Now, plug the values into the formula:
height = 2 miles × tan(0.05236 radians)
To get the height in feet, convert miles to feet (1 mile = 5280 feet):
height = (2 × 5280) × tan(0.05236 radians) ≈ 554.26 feet

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The check number in the image is 403 based on the image of cheque and associated information.

The cheque is a piece of paper utilised in banks for transaction. It is also a valid proof of money exchange and is exchanged among people and buisness to transfer the money. There are different numbers on cheque representing crucial information.

The number 856425785 is the routing number, 2146578212 is the account number and 403 si the cheque number. $204.67 is the amount of transaction. The top left corner indicates money sender's credential while the hand written information is of the receiver. The date of writing cheque is used to calculate the validity of cheque.

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