least common multiple of 2 and 3?i forgot how to do this completly over the summer lol

Hi! I'm happy to help!

To first solve this, we need to know what is going on. In the order of operations, everything inside of the parenthesis happens first. Since 4 and m are being multiplied inside of the parenthesis, that would happen before being moved to the fifth power. Since m is unknown, we make everything inside of the parenthesis to the fifth power, and make sure they are multiplied together as they are inside of the parenthesis. (Everything inside of the parenthesis applies to the raising to the fifth power.)

[tex]4^{5}[/tex]·[tex]m^{5}[/tex]

From here, we can simplify [tex]4^{5}[/tex] to 1024.

1024·[tex]m^{5}[/tex]

We don't need the multiplication sign because it is a variable.

1024[tex]m^{5}[/tex]

Since we cannot simplify m, this is our most simplified form: 1024[tex]m^{5}[/tex]

I hope this was helpful, keep learning! :D

Answer:

focus is (-5, 0)

Step-by-step explanation:

[tex] {y}^{2} = 4ax \\ 4a = 20 \\ a = 5[/tex]

Answer:

Step-by-step explanation:Draw a straight line using the protractor. This will be the center line of your circle (dividing it into semi-circles).Align the protractor so that both 0° and 180° lie on the center line. Mark the center point.Trace the semicircle along the protractor from 0 ° to 180°.

Put the protractor on the other side of the center line, again with both the 0°and 180° marks on the center line.[1]Complete the circle by tracing along the protractor.

Calculate the angle between adjacent vertices, α. Since a circle has 360°, divide 360° by n, the number of vertices (or sides) to get α.[2]

α=360°/n

α is the measured angle between lines drawn from the center of the circle to adjacent vertices.

For a dodecagon, n=12. A dodecagon has 12 sides and 12 vertices, so 360° divided by 12 is 30°, and α=30°.

Mark a point for each of the successive angles. Using the protractor, mark on the circumference of the circle all the multiples of angle α calculated above.[3]

Join the points marked on the circle with a line segment.[4] For a dodecagon there should be 12 marks and 12 sides, because it has 12 vertices. Don’t overlap the line segments.

If your points are outside of the circle, then simply mark another point along the radial line from the center onto the circle for each point and then join them.

Check to see that the sides are the same length. If they are, you can erase the circumscribed circle.Finished.

Answer:

0.448

Step-by-step explanation:

i used a calculator

Answer:

perimeter is 20 cm

Answer:

5

Step-by-step explanation:

a² + b² = c²

4² + 3² = c²

16 + 9 = c²

c = √25

c = 5

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

Answer:

2n+8

Step-by-step explanation:

"eight more than twice a number" so twice a number would be 2n because its 2×n (double/twice a number) and eight more would be +8

Answer:

[tex] {x}^{ \frac{1}{2} } \times {x}^{ \frac{2}{3} } [/tex]

[tex] {x}^{ \frac{3 + 4}{6} } [/tex]

[tex] {x}^{ \frac{7}{6} } [/tex]

1 to 5 - 3

6 to 10 - 4

11 to 15 - 1

16 to 20 - 2

The students must make use of varying string lengths in his experiment in other to make string length the independent quantity.

In the first first scenario,

The number of swings made by each pendulum is the dependent variable, as it is the variable which is measured in the experiment. While ;

The different pendulum masses tested are the Independent variable as it is the variable which is manipulated in other to cause changes to the measured variable.

In other make the string length the independent quantity, the student will need to use strings of different length and not just a string of 27 cm in other to be used as the independent variable. This will enable manipulation of the independent quantity to other to cause changes to the measured variable.

Learn more: https://brainly.com/question/1479694

Hello there!

Law of Exponent

[tex] \displaystyle \large{ {a}^{ \frac{m}{n}} = \sqrt[n]{ {a}^{m} } }[/tex]

The first problem asks us to write the cube root of 17 in exponential form. Refer the exponent's law above.

[tex] \displaystyle \large{ \sqrt[3]{17} = \sqrt[n]{ {a}^{m} } }[/tex]

Compare the terms.

Hence,

[tex] \displaystyle \large{ \sqrt[3]{17} = {17}^{ \frac{1}{3} } }[/tex]

The second problem asks us to write 13^{1/2} in radical form. Refer the law above.

[tex] \displaystyle \large{ {13}^{ \frac{1}{2} } = {a}^{ \frac{m}{n} } }[/tex]

Compare the terms.

Hence,

[tex] \displaystyle \large{ {13}^{ \frac{1}{2} } = \sqrt{13} }[/tex]

Conclusion

Let me know if you have any questions!

Topic: Exponent / Fractional Exponent and n-th root /

Answer:The solution is in the attached file

Step-by-step explanation:

Step-by-step explanation:

1. √47 => E

2. √27 => D

3. √11 => A

Answer:

A (-5,3)

B (3,4)

C (2,-1)

D (3,-5)

E (-3,-4)

F (-2,1)

Answer:

I hope it will helpful.

Step-by-step explanation:

I hope it will help you.

Answer:

40

Step-by-step explanation:

let the number be 'x'

95 % of x = 38

(95 / 100)x =38

x = 38 × 100 / 95

x = 2 × 100 / 5

x = 2 × 20

x = 40

Answer:

x^2-9x-8

Step-by-step explanation:

=x^2-(3)^2-(2)^3

=2(x-3-4)

=2(x-(-1))

=2(x+1)#

Answer:

2/12 the answer

9514 1404 393

Answer:

  -2 7/8

Step-by-step explanation:

The usual recommendation is to convert the mixed numbers to improper fractions before multiplying.

  [tex]-2\dfrac{5}{9}\times1\dfrac{1}{8}=-\dfrac{9\cdot2+5}{9}\times\dfrac{8\cdot1+1}{8}\\\\=-\dfrac{23\cdot9}{9\cdot8}=-\dfrac{23}{8}=\boxed{-2\dfrac{7}{8}}[/tex]

__

Note the factors of 9 cancel in the first expression on the last line, leaving -23/8.

Answer:

[tex]\frac{23}{8}=2\frac{7}{8}[/tex]

Step-by-step explanation:

[tex]-2\frac{5}{9}\times \:1\frac{1}{8}[/tex]

Step 1: Convert into an improper fraction

[tex]2\frac{5}{9}=\frac{2\times 9+5}{9}\\\\=\frac{23}{9}[/tex]

[tex]-\frac{23}{9}\times \:1\frac{1}{8}[/tex]

[tex]1\frac{1}{8}=\frac{1\times 8+1}{8}\\\\=\frac{9}{8}[/tex]

[tex]-\frac{23}{9}\times \frac{9}{8}[/tex]

Step 2: Cross-cancel 9

[tex]=-\frac{23}{8}[/tex]

Step 3: Convert to an improper fraction

[tex]\frac{23}{8}=2\frac{7}{8}\\\\2\frac{7}{8}[/tex]

Answer:

Hence the smallest natural number by which 392 should be multiplied to make a perfect cube is 7.

Answer:

392 should be multiplied by 7 to make a perfect cube

Step-by-step explanation:

Step-by-step explanation:

[tex]5(m - 6) = 5(7m = 6)[/tex]

[tex]5m - 30 = 35m - 30[/tex]

[tex]5m = 35m[/tex]

[tex]30m = 0[/tex]

[tex]m = 0[/tex]

Answer:

Natural Numbers are basically "counting numbers". If I ask you to start counting, you'll start at 1, then 2, then 3, and so on. It doesn't include 0 or any negative numbers because you wouldn't start from -10 when asked to count.

Answer:

-7 is negative so it cannot be a natural number, but it is an integer. An integer is a whole number, this means that it does not have any decimal places or fractions. However, a natural number must be a whole non-zero number and positive. This is because natural numbers are numbers found naturally in measurements or in counting. Additionally, all natural numbers are integers but not all integers are natural numbers. For example, -3 would be an integer, 9 would be an integer and a natural number, and 7.6 would be neither.

(7 + y) - 6 = 8

If you also need the correct number its 7

(7 + 7) - 6 = 8

Answer:

∴ The greatest number that divides 210, 252 and 294 is 42.

Step-by-step explanation:

We have to find the LCM of the given rows 12, 15 and 40. (Taking Highest Powers). Therefore, least number of saplings that can be arranged in given rows are 120.

Step-by-step explanation:

since you understood 1a, I honestly do not understand what's the problem with 1b.

this works exactly the same way. only this time it is x+0 and y changes. that is all.

(x, y) -> (x+0, y-5)

A" = (-6. 2)

B" = (-4, -3)

C" = (-8, -3)

Answer:

i got u c

Step-by-step eplanation:

Answer:

9

Step-by-step explanation:

(3)^2((-1)-2)/3(-1)

=9(-3)/-3

=-27/-3

=9

Answer:

[tex]\huge\boxed{\sf 9}[/tex]

Step-by-step explanation:

[tex]\displaystyle = \frac{x^2(y-2)}{3y} \\\\Put \ x = 3, \ y = -1\\\\= \frac{(3)^2(-1-2)}{3(-1)}\\\\= \frac{9(-3)}{-3} \\\\= 9 \\\\ \rule[225]{225}{2}[/tex]

Hope this helped!