Answer:
The answer is below
Step-by-step explanation:
The corresponding data are missing, which are the following:
Strikes (pre):
29
32
44
34
19
Strikes (post):
51
45
68
92
64
We have to say the difference between the post-pre values of the strike. The d will be the average of the differences between the post and pre values. If Kara is to show improvement, her post-workout attacks should be more than the pre-workout values. Let m be the population mean of the difference:
H0: m = 0 the mean difference in Strikes between post and pre is zero.
H0: m>0, the mean difference in strikes between post and pre is more than zero.
The surface area of a given cone is 1,885.7143 square inches. What is the slang height?
Answer:
If [tex]r >> h[/tex], the slang height of the cone is approximately 23.521 inches.
Step-by-step explanation:
The surface area of a cone (A) is given by this formula:
[tex]A = \pi \cdot r^{2} + 2\pi\cdot s[/tex]
Where:
[tex]r[/tex] - Base radius of the cone, measured in inches.
[tex]s[/tex] - Slant height, measured in inches.
In addition, the slant height is calculated by means of the Pythagorean Theorem:
[tex]s = \sqrt{r^{2}+h^{2}}[/tex]
Where [tex]h[/tex] is the altitude of the cone, measured in inches. If [tex]r >> h[/tex], then:
[tex]s \approx r[/tex]
And:
[tex]A = \pi\cdot r^{2} +2\pi\cdot r[/tex]
Given that [tex]A = 1885.7143\,in^{2}[/tex], the following second-order polynomial is obtained:
[tex]\pi \cdot r^{2} + 2\pi \cdot r -1885.7143\,in^{2} = 0[/tex]
Roots can be found by the Quadratic Formula:
[tex]r_{1,2} = \frac{-2\pi \pm \sqrt{4\pi^{2}-4\pi\cdot (-1885.7143)}}{2\pi}[/tex]
[tex]r_{1,2} \approx -1\,in \pm 24.521\,in[/tex]
[tex]r_{1} \approx 23.521\,in \,\wedge\,r_{2}\approx -25.521\,in[/tex]
As radius is a positive unit, the first root is the only solution that is physically reasonable. Hence, the slang height of the cone is approximately 23.521 inches.
Player A finished first in a tournament at a golf club with a score of −9, or nine strokes under par. Tied for 46th place was player B, with a score of +9, or 9 strokes over par. What was the difference in scores between Player A and Player B?
Answer:
18
Step-by-step explanation:
since you want the difference in scores, you want to take the absolute value of the difference
9 - (-9) = 9+9 = 18
The difference in scores between Player A and Player B is 18.
How do we calculate the difference?The difference between two numbers is found by subtracting the smaller number from the greater number.
How do we solve the given question?We are informed that Player A finished first in a tournament at a golf club with a score of −9 or nine strokes under par. Tied for 46th place was player B, with a score of +9, or 9 strokes over par.
We are asked for the difference in scores between Player A and Player B.
The score of Player A = -9.
The score of Player B = 9
Since Player B's score > Player A's score,
To calculate the difference in their scores, we subtract player A's score from player B's score.
∴ Difference = 9 - (-9)
or, Difference = 9 + 9
Difference = 18.
∴ The difference in scores between Player A and Player B is 18.
Learn more about the difference at
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A deck of cards contains RED cards numbered 1,2,3, BLUE cards numbered 1,2,3,4, and GREEN cards numbered 1,2. If a single card is picked at random, what is the probability that the card is BLUE OR has an ODD number?
Answer:
7/9
Step-by-step explanation:
P(blue or odd) = P(blue) + P(odd) − P(blue and odd)
P(blue or odd) = 4/9 + 5/9 − 2/9
P(blue or odd) = 7/9
Alternatively:
P(blue or odd) = 1 − P(not blue and not odd)
P(blue or odd) = 1 − 2/9
P(blue or odd) = 7/9
A statement which checks to see if the value of the expression on the left side is the same as the value of the expression on the right side is an example of the use of the
Answer:
A relational statementStep-by-step explanation:
In computer programming relational operators are used to check conditions, that is if one conditions matches another and returns true if the condition is met or satisfied.
David says he has 2/3 of a pipe length left, while Don says he has 11/16 of a length left. Which person has the longest section left?
Answer:
Don
Step-by-step explanation:
1. We make the fractions have common denominators so it is easier to compare them. We can do this buy multiplying 2/3 by a factor of 16, so it becomes 32/48. For 11/16, we multiply by a factor of 3 so it becomes 33/48. It is now apparent that Don has the longer pipe.
Don has the longest section of pipe because the fraction number 11/16 is greater than the fraction number 2/3.
What is Algebra?Algebra is the study of abstract symbols, while logic is the manipulation of all those ideas.
The decimal number is the sum of a whole number and part of a fraction number. The fraction number is greater than zero but less than one.
David says he has 2/3 of a line length left, while Wear says he has 11/16 of a length left.
Convert the fraction numbers 2/3 and 11/16 into the decimal number. Then we have
2/3 = 0.6667
11/16 = 0.6875
The decimal number 0.6875 is greater than 0.6667. Then the fraction number 11/16 is greater than the fraction number 2/3.
Don has the longest section of pipe because the fraction number 11/16 is greater than the fraction number 2/3.
More about the Algebra link is given below.
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PLEASE HELP QUICK!!! In how many ways can you put seven marbles in different colors into two jars? Note that the jars may be empty.
Answer: 14384 ways
Step-by-step explanation:
With 0 identical marbles permitted to be included in any of the jars, An expression can be developed to determine the total of marbles in jar arrangements, which is:
E = [(n+j -1)!]*{1/[(j-1)!]*[(n)!]}, where n = number of identical balls and j =number of distinct jars, the contents of all of which must sum to n for each marbles in j jars arrangement. With n = 7 and j = 4. E = 10!/(3!)(7!) = 120= number of ways 7 identical marbles can be distributed to 4 distinct jars such that up to 3 boxes may be empty and the maximum to any box is 7 balls.
The marble arrangements are: (7,0,0,0) in 4!/3! = 4 ways, (6,1,0,0) in 4!/2! = 12 ways, (5,2,0,0) in 4!/2! = 12 ways, (5,1,1,0) in 4!/2! = 12 ways, (4,3,0,0) in 4!/2! = 12 ways, (4,2,1,0) in 4! = 24 ways, (4,1,1,1) in 4!/3! = 4 ways, (3,3,1,0) in 4!/2! = 12 ways, (3,2,2,0) in 4!/2! = 12 ways, (3,2,1,1) in 4!/2! = 12 ways, (2,2,2,1) in 4!/3! = 4 ways.
Total of ways = 4+12+12+12+12+24+4+12+12+12+4 = 120 as previously determined above for identical marbles and distinct jars.
Taking into account distinct colored marbles, the number of ways of marble distribution into 4 jars becomes as follows:
For (7,0,0,0) = 4*(7!/7!) =4. For (6,1,0,0) = 12*[7!/(6!)(1!)] = 84. For (5,2,0,0) =
12*[7!/(5!)(2!)] = 252. For (5,1,1,0) = 12*[7!/(5!)(1!)(1!)] = 504. For (4,3,0,0) =
12*[7!/(4!)(3!)] = 420. for (4,2,1,0) = 24*[7!/(4!)(2!)(1!)] = 2,520. For (4,1,1,1) =
4*7!/(4!)(1!)(1!)(1!)] = 840. For (3,3,1,0) = 12*]7!/(3!)(3!)(1!) = 1,680. For (3,2,20) = 12*]7!/(3!)(2!)(2!) = 2,520. For (3,2,1,1) = 12*]7!/(3!)(2!)(1!)(1!) = 5,040. For (2,2,2,1) = 4*]7!/(2!)(2!)(2!)(1!) = 2,520.
Total of ways as requested for distinct colored marbles and distinct jars = 4+84+252+504+420+2,520+840+1,680+2,520+5,040+2,520 = 14,384.
A group of 59 randomly selected students have a mean score of 29.5 with a standard deviation of 5.2 on a placement test. What is the 95% confidence interval for the mean score, , of all students taking the test
Answer:
The 95% confidence interval for the mean score, , of all students taking the test is
[tex]28.37< L\ 30.63[/tex]
Step-by-step explanation:
From the question we are told that
The sample size is [tex]n = 59[/tex]
The mean score is [tex]\= x = 29.5[/tex]
The standard deviation [tex]\sigma = 5.2[/tex]
Generally the standard deviation of mean is mathematically represented as
[tex]\sigma _{\= x} = \frac{\sigma }{\sqrt{n} }[/tex]
substituting values
[tex]\sigma _{\= x} = \frac{5.2 }{\sqrt{59} }[/tex]
[tex]\sigma _{\= x} = 0.677[/tex]
The degree of freedom is mathematically represented as
[tex]df = n - 1[/tex]
substituting values
[tex]df = 59 -1[/tex]
[tex]df = 58[/tex]
Given that the confidence interval is 95% then the level of significance is mathematically represented as
[tex]\alpha = 100 -95[/tex]
[tex]\alpha =[/tex]5%
[tex]\alpha = 0.05[/tex]
Now the critical value at this significance level and degree of freedom is
[tex]t_{df , \alpha } = t_{58, 0.05 } = 1.672[/tex]
Obtained from the critical value table
So the the 95% confidence interval for the mean score, , of all students taking the test is mathematically represented as
[tex]\= x - t*(\sigma_{\= x}) < L\ \= x + t*(\sigma_{\= x})[/tex]
substituting value
[tex](29.5 - 1.672* 0.677) < L\ (29.5 + 1.672* 0.677)[/tex]
[tex]28.37< L\ 30.63[/tex]
The Hudson Record Store is having a going-out-of-business sale. CDs normally sell for $18.00. During the first week of the sale, all CDs will sell for $15.00. Written as a fraction, what is the rate of discount? What is this rate expressed as a percent? Round your answer to the nearest hundredth of a percent. During the second week of the sale, the same CDs will be on sale for 25% off the original price. What is the price of a CD during the second week of the sale?What is this rate expressed as a percent? Round your answer to the nearest hundredth of a percent. During the second week of the sale, the same CDs will be on sale for 25% off the original price. What is the price of a CD during the second week of the sale?
Answer:
The Hudson Record Store
1. As a fraction, discount rate = $3/$18 = 0.167
2. As a percentage, discount rate = 16.67%
3. Selling price during 2nd week = $13.50
4. The rate of the new selling price to the old is $13.50/$18 = 75%
Step-by-step explanation:
Selling price of CDs = $18
1st Week, sold CDs at $15
Discount = $3 ($18 - $15)
As a fraction, discount rate = $3/$18 = 0.167
As a percentage, discount rate = 16.67%
2nd Week, sold CDs at $13.50 ($18 - (25% of $18))
Discount = $4.50 ($18 - $13.50)
Price during the second week of the sale = $13.50
The rate of discount = $4.50/$18 = 25%
select the inequality that represents the relationship desribed below the sum of three times a number and seven is greater than four times the number
Answer:
There are many combinations based on the number you chose to subtract from both sides.
Step-by-step explanation:
Let the number be x.
According to the question,
3 x+7 > 4 x
We get, 3 x+1=4 x-6, after subtracting 6 from both sides.
3 x+1=4 x-6
4 x- 3 x=6+1
x=7
You will get the same answer if you subtract 3 x or 7 or any other number from both sides.
Thank you!
Find C and round to the nearest tenth.
Answer:
29.4 degrees
Step-by-step explanation:
i divided sin by 55 degrees
In the United States, the mean age of men when they marry for the first time follows the normal distribution with a mean of 24.7 years. The standard deviation of the distribution is 2.8 years. For a random sample of 60 men, what is the likelihood that the age when they were first married is less than 25.2 years
Answer:
The likelihood is [tex]P(X < 25.2) = 0.91668[/tex]
Step-by-step explanation:
From the question we are told that
The population mean is [tex]\mu = 24.7 \ years[/tex]
The standard deviation is [tex]\sigma = 2.8 \ years[/tex]
The sample size is [tex]n = 60 \ men[/tex]
The consider random value is x = 25.2 years
Given that mean age is normally distributed, the likelihood that the age when they were first married is less than x is mathematically represented as
[tex]P(X < x) = P( \frac{X - \mu }{\sigma_{\= x }} < \frac{x - \mu }{\sigma_{\= x }} )[/tex]
Generally [tex]\frac{X - \mu }{ \sigma_{\= x}} = Z (The \ standardized \ value \ of \ X )[/tex]
So
[tex]P(X < x) = P(Z< \frac{x - \mu }{\sigma_{\= x }} )[/tex]
Where [tex]\sigma_{\= x }[/tex] is the standard error of the sample mean which mathematically evaluated as
[tex]\sigma_{\= x } = \frac{ \sigma }{\sqrt{n} }[/tex]
substituting values
[tex]\sigma_{\= x } = \frac{ 2.8 }{\sqrt{ 60 } }[/tex]
[tex]\sigma_{\= x } = 0.3615[/tex]
So
[tex]P(X < 25.2) = P(Z< \frac{ 25.2 - 24.7 }{0.3615} )[/tex]
[tex]P(X < 25.2) = P(Z< 1.3831 )[/tex]
From z-table the value for P(Z< 1.3831 ) is [tex]P(Z < 1.3831 ) = 0.91668[/tex]
So
[tex]P(X < 25.2) = 0.91668[/tex]
Rafael made 20,000 in taxable income last year. Suppose the income tax rate is 15% for the first 8000 plus 17% for the amount over 8000. How much must Rafael pay in income tax for the last year?
The answer is 3,240
Explanation:
To calculate the total income tax, it is necessary to calculate what is the 15% of 8000, and 17% for the remaining money, which is 12.000 (20,000 - 8,000= 12,000). Considering the statement specifies the 15% is paid for the first 8,000 and from this, the 17% is paid. Now to know the percentages you can use a simple rule of three, by considering 8000 and 12000 as the 100%. The process is shown below:
1. Write the values
[tex]8000 = 100[/tex]
[tex]x = 15[/tex] (the percentage you want to know)
2. Use cross multiplication
[tex]x =\frac{8000 x 15 }{100}[/tex]
[tex]x = 1200[/tex]
This means for the first 8000 the money Rafael needs to pay is 1,200
Now, let's repeat the process for the remaining money (12,000)
[tex]12000 = 100\\\\[/tex]
[tex]x = 17[/tex]
[tex]x = \frac{12000 x 17}{100}[/tex]
[tex]x = 2040[/tex]
Finally, add the two values [tex]1200 + 2040 = 3240[/tex]
Which statement about the following equation is true?
2x2-9x+2-1
Complete Question:
Which statement about the following equation is true?
[tex]2x^2-9x+2 = -1[/tex]
A) The discriminant is less than 0, so there are two real roots
B) The discriminant is less than 0, so there are two complex roots
C) The discriminant is greater than 0, so there are two real roots
D) The discriminant is greater than 0, so there are two complex roots
Answer:
C) The discriminant is greater than 0, so there are two real roots
Step-by-step explanation:
The given equation is [tex]2x^2-9x+2 = -1[/tex] which by simplification becomes
[tex]2x^2 - 9x + 3 = 0[/tex]
For a quadratic equation of the form [tex]ax^2 + bx + c = 0[/tex], the discriminant is given by the equation, [tex]D = b^2 - 4ac[/tex]
If the discriminant D is greater than 0, the roots are real and different
If the discriminant D is equal to 0, the roots are real and equal
If the discriminant D is less than 0, the roots are imaginary
For the quadratic equation under consideration, a = 2, b = -9, c = 3
Let us calculate the discriminant D
D = (-9)² - 4(2)(3)
D = 81 - 24
D = 57
Since the Discriminant D is greater than 0, the roots are real and different.
Answer:
Step-by-step explanation:
C) The discriminant is greater than 0, so there are two real roots
URGENT!! The quotient of the rational expressions
Answer:
[tex] \frac{2 {x}^{2} }{3 {x}^{2} - 7x + 2 } [/tex]Option C is the correct option
Step-by-step explanation:
[tex] \frac{x}{3x - 1} \div \frac{x - 2}{2x} [/tex]
To divide by a fraction, multiply by the reciprocal of that fraction
[tex] \frac{x}{3x - 1} \times \frac{2x}{x - 2} [/tex]
Multiply the fractions
[tex] \frac{2 {x}^{2} }{(3x - 1)(x - 2)} [/tex]
Multiply the parentheses
[tex] \frac{2 {x}^{2} }{3x(x - 2) - 1(x - 2)} [/tex]
[tex] \frac{2 {x}^{2} }{3 {x}^{2} - 6x - x + 2 } [/tex]
Collect like terms
[tex] \frac{2 {x}^{2} }{3 {x}^{2} - 7x + 2 } [/tex]
Hope this helps...
Best regards!!
The Highway Safety Department wants to study the driving habits of individuals. A sample of 121 cars traveling on the highway revealed an average speed of 60 miles per hour with a standard deviation of 11 miles per hour. Determine a 95% confidence interval estimate for the speed of all cars.
Answer:
{58.02007 , 61.97993]
Step-by-step explanation:
Data are given in the question
Sample of cars = n = 121
Average speed = sample mean = 60
Standard deviation = sd = 11
And we assume
95% confidence t-score = 1.97993
Therefore
Confidence interval is
[tex]= [60 - \frac{1.97993 \times 11}{\sqrt{121} }] , [60 + \frac{1.97993 \times 11}{\sqrt{121} }][/tex]
= {58.02007 , 61.97993]
Basically we applied the above formula to determine the confidence interval
Please help!!! match the system of equations
Answer:
1 ): 3x-2y=-1,-x+2y=3 (1,2)
2): 4x-3y=-1 , -3x+4y=6 (2,3)
3x+6y=6, 2x+4y=-4 ( no solution)
-3x+6y=-3, 5x-10y=5 infinite
Step-by-step explanation:
4x-3y=-1
-3x+4y=6 ( multiply first by 3 and second equation by 4)
12x-9y=-3
-12x+16y=24 subtract
7y=21
y=21/7=3
x=2, y=3 (2,3)
3x-2y=-1
-x+2y=3
solve by addition/elimination ( same as other equation):
multiply second equation by 3
3x-2y=-1
-3x+6y=9
4y=8
y=2
x=1
3x+6y=6, 2x+4y=-4 ( no solution)
-3x+6y=-3, 5x-10y=5 infinite
Suppose that the probability distribution below shows the number of colleges that children of celebrities applied to in 2018. Compute the standard deviation for the number of college applications.
x 0 2 4 6
P(x) 0.4 0.3 0.2 0.1
Complete Question
The complete question is shown on the first uploaded image
Answer:
The standard deviation is [tex]\sigma = 2.45[/tex]
Step-by-step explanation:
From the given data we can compute the expected mean for each random values as follows
[tex]E(X) = \sum [ X * P(X = x )]\\\\ X \ \ \ \ \ \ X* P(X =x )\\ 0 \ \ \ \ \ \ \ \ \ \ 0* 0.4 = 0 \\ 2 \ \ \ \ \ \ \ \ \ \ 2 * 0.3 = 0.6 \\ 4 \ \ \ \ \ \ \ \ \ \ 4 * 0.2 = 0.8\\ 6 \ \ \ \ \ \ \ \ \ \ 6* 0.1 = 0.6[/tex]
So
[tex]E(x) = 0 + 0.6 + 0.8 + 0.6[/tex]
[tex]E(x) = 2[/tex]
The
[tex]E(X^2) = \sum [ X^2 * P(X = x )]\\\\ X \ \ \ \ \ \ \ \ \ \ X^2 * P(X=x ) \\ 0 \ \ \ \ \ \ \ \ \ \ 0^2 * 0.4 = 0 \\ 2 \ \ \ \ \ \ \ \ \ \ 2^2 * 0.3 = 12 \\ 4 \ \ \ \ \ \ \ \ \ \ 4^2 * 0.2 = 3.2 \\ 6 \ \ \ \ \ \ \ \ \ \ 6^2 * 0.1 = 3.6[/tex]
So
[tex]E(X^2) = 0 + 1.2 + 3.2 + 3.6[/tex]
[tex]E(X^2) = 8[/tex]
Now the variance is mathematically evaluated as
[tex]Var (X) = E(X^2 ) -[E(X]^2[/tex]
Substituting value
[tex]Var (X) = 8-4[/tex]
[tex]Var (X) = 6[/tex]
The standard deviation is mathematically evaluated as
[tex]\sigma = \sqrt{Var(x)}[/tex]
[tex]\sigma = \sqrt{4}[/tex]
[tex]\sigma = 2[/tex]
You will note the wheel has 38 slots. There are two green slots (labeled
0,00) and 36 slots which alternate red/black and are numbered 01-36. A
player participates by tossing a small ball around the wheel as the wheel
spins, and the ball lands in one of the 38 slots. The goal is for the ball to
land in a slot that the player predicted it would, and bet money on
happening. Define the following events:
E = The ball lands in an even numbered slot
M = The ball lands in a slot that is numbered a multiple of three (3,6,9,
12, etc...)
Use the given information to calculate the conditional probability M|E.
Round your answer to four decimal places.
Answer:
~0.3158
Step-by-step explanation:
Number of even numbers in the range of 1 - 38 is 38/2 = 19
=> P(E) = 19/38 = 1/2
Having: 38 = 3 x 12 + 2, then the number of numbers that is a multiple of 3 in the range of 1 - 38 is 12
=> P(M) = 12/38 = 6/19
Having: 38 = 6 x 6 + 2, then the number of numbers that is a multiple of 6 (or multiple of 2 and 3) is 6
=> P(E and M) = 6/38 = 3/19
Applying the conditional probability formula:
P(M|E) = P(E and M)/P(E) = (3/19)/(1/2) = 6/19 = ~0.3158
Two professors in the mathematics building have offices that are consecutive odd numbers with a sum of 14,600. What are the official numbers of these two professors?
Answer: 7299, 7301
Step-by-step explanation:
x + x + 2= 14,600
2x = 14,598
x = 7,299
Therefore, the office numbers are 7299 and 7301
Need Answers ASAP!!!! (due today)
Answer:
1.
a. 20 m²: barn door is 5m x 4m
b. 468 m²:surface area of barn
i. left and right barn walls: 2(15 x 7) = 210
ii. back wall: 7 x 8 = 56
iii. front wall: (7 x 8) - 20* = 36
*20 for the barn door
iv. front of roof: (4 x 4) / 2 = 8 x 2* = 16
*I split the triangle into 2 smaller triangles
v. sides of roof: 2(5 x 15) = 150
2.
a. 15 m²: silo door is 3m x 5m
b. 244.18 m²: surface area of silo
i. SA(silo)=2πrh+2πr²
ii. SA(silo) = 2π(2.5)(14) + 2π(2.5)²
iii. SA(silo) = 259.18
iv. SA(silo - door) = 259.18 - 15
v. SA(silo - door) = 244.18
3.
a. 712.18 m²: total surface area painted red
i. add both surface areas: 468 + 244.18 = 712.18 m²
hope this helps :)
Global Airlines operates two types of jet planes: jumbo and ordinary. On jumbo jets, 25% of the passengers are on business while on ordinary jets 30% of the passengers are on business. Of Global's air fleet, 40% of its capacity is provided on jumbo jets. (Hint: The 25% and 30% values are conditional probabilities stated as percentages.) What is the probability a randomly chosen business customer flying with Global is on a jumbo jet?
Answer:
Answer:
The probability is [tex]P(J|B) = 0.36[/tex]
Step-by-step explanation:
B =business
J=jumbo
Or =ordinary
From the question we are told that
The proportion of the passenger on business in the ordinary jet is [tex]P(B| Or) = 0.25[/tex]
The proportion of the passenger on business in the jumbo jet is [tex]P(B|J) = 0.30[/tex]
The proportion of the passenger on jumbo jets is [tex]P(j) = 0.40[/tex]
The proportion of the passenger on ordinary jets is evaluated as
[tex]1 - P(J) = 1- 0.40 = 0.60[/tex]
According to Bayer's theorem the probability a randomly chosen business customer flying with Global is on a jumbo jet is mathematically represented as
[tex]P(J|B) = \frac{P(J) * P(B|J)}{P(J ) * P(B|J) + P(Or ) * P(B|Or)}[/tex]
substituting values
[tex]P(J|B) = \frac{ 0.4 * 0.25}{0.4 * 0.25 + 0.6 * 0.3}[/tex]
[tex]P(J|B) = 0.36[/tex]
Step-by-step explanation:
Given that (-7,-7) is on the graph of f(x), find the corresponding point for the function f(x-5)
Answer: (-2,-7)
Step-by-step explanation:
A function f(x-c) , where c>0 , represents the horizontal shift of original function to the right c units.
The function f(x-c) is going to add c to the x value, while keeping the y value the same.
Similarly,
The function f(x-5) is going to add 5 to the x value, while keeping the y value the same.
So, the corresponding point to (-7,-7) on f(x-5) = (-7+5,-7)
= (-2,-7)
hence, the corresponding point to (-7,-7) on f(x-5) = (-2,-7)
Based on past experience, it is estimated that a restaurant will serve 122 guests on a weekday evening. This is an example of which type of probability
Answer: Experimental probability.
Step-by-step explanation:
This starts as "based on past experience."
So we can suppose that this estimation is obtained by looking at the mean of the number of guests on the past N weekday evenings. (With N a large number, as larger is N, more data points we have, and a better estimation can be made)
Then, this would be an experimental probability, because it is obtained by repeating an experiment (counting the number of guests on weekday evenings) and using that information to make an estimation.
a perfect_____ is a number or expression that can be written as a sqaure of an expression
Answer:
A perfect square
Answer:
square
Step-by-step explanation:
An example of a perfect square is 9.
9 squared is 3.
The state of CT claims that the average time on death row is 15 years. A random survey of 75 death row inmates revealed that the average length of time on death row is 17.8 years with a standard deviation of 5.9 years. Conduct a hypothesis to test the state of CT's claim. What type of test should be run? t-test of a mean z-test of a proportion The alternative hypothesis indicates a right-tailed test left-tailed test two-tailed test Calculate the p-value. What is the decision? We reject the claim that the average time on death row is 15 years We fail to reject the claim that the average time on death row is 15 years
Answer:
a)The calculated value t = 4.111 > 1.9925 at 5 % level of significance
Null hypothesis is rejected
The claim that the average time on death row is not 15 years
b) The p-value is 0.000101<0.05
we reject Null hypothesis
The claim that the average time on death row is not 15 years
Step-by-step explanation:
Step(i):-
Sample size 'n' =75
Mean of the sample x⁻ = 17.8
standard deviation of the sample (S) = 5.9
Mean of the Population = 15
Null hypothesis:H₀:μ = 15 years
Alternative Hypothesis :H₁:μ≠15 years
Step(ii):-
Test statistic
[tex]t = \frac{x^{-} -mean}{\frac{S}{\sqrt{n} } }[/tex]
[tex]t = \frac{x^{-} -mean}{\frac{S}{\sqrt{n} } }=\frac{17.8-15}{\frac{5.9}{\sqrt{75} } }[/tex]
t = 4.111
Degrees of freedom
ν = n-1 = 75-1=74
t₀.₀₂₅ = 1.9925
The calculated value t = 4.111 > 1.9925 at 5 % level of significance
Null hypothesis is rejected
The claim that the average time on death row is not 15 years
P-value:-
The p-value is 0.000101<0.05
we reject Null hypothesis
The claim that the average time on death row is not 15 years
Dr. Denscombe randomly assigned 10 participants to drink a caffeinated beverage and another 10 participants to drink a noncaffeinated beverage. He then recorded their average driving speed over a 10-minute period. Caffeinated drivers averaged 50 mph with a variance of 20 and noncaffeinated drivers averaged 30 mph with a variance of 20. What is t
Answer: t = 10
Step-by-step explanation:m
Given that; n₁ = 10, n₂ = 10
ж₁ = 50, ж₂ = 30
Sˣ₁ = 20, Sˣ₂ = 20
Now using TEST STATISTICS
t = (ж₁ - ж₂) / √ ( Sˣ₁/n₁ + Sˣ₂/n₂ )
so we substitute our figures
t = ( 50 - 30 ) / √ ( 20/10 + 20/10 )
t = 20 / √4
t = 10
If the image is blurry the answer choices are -1,0,1,2,and 3. The question says select each correct answer
Answer:
12Step-by-step explanation:
There is no algebraic way to solve such an equation. It can be simplified to ...
[tex]-2x-6=-2^x-6\\\\2x-2^x=0\qquad\text{add $2x+6$}[/tex]
This has solutions at x=1 and x=2 as shown in the attached graph.
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The second attachment shows the functions graphed on the same graph.
Brainliest for the correct awnser!!! The function is not an example of a rational function. True or false?
Answer:
true
Step-by-step explanation:
use what you know about zeros of a function and end behavior of a graph that matches the function f(x) = (x+3)(x+2)(x-1)
Answer:
The zeros are x=-3,-2,1
end behavior is one up one down
Step-by-step explanation:
The zeros are x=-3,-2,1
The end behaviors are one up one down because the function is of degree 3 meaning it is odd function and has opposite end directions.
how could you correctly rewrite the equation 4(5+3)=2(22-6) using the distributive property?
We can correctly rewrite the equation: 4(5+3) = 2(22-6) by distributing each side.
4(5+3) = 2(22-6)
4(8) = 2(16)
32 = 32
Once you finish distributing each side, you can check to see if it is equal on both sides.
In our case it is since they both equal 32 after distributing the terms.