Note that the probability that a student chosen at random will play an instrument besides the guitar is 29/45.
How can you determine this?
To derive the probability, that a chosen at random will play an instrument other than guitar , we have to first find the sum total of all students who can play an instrument that is not a guitar.
From the table, we can se that this is:
3 + 10 + 5 = 18 on the 7th grade
while the 8th grade we have 3 + 6 + 2 = 11
18 + 11 = 29
So that total students in the middle school is
12 + 3 + 10 +5 + 4 + 3 + 6 + 2 = 45
hence the probability that a student chosen at random will play an instrument other than guitar as a fraction in simplest form is 29/45
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Which answers describe the shape below? Check all that apply.
31
A
A. Quadrilateral
B. Rhombus
C. Trapezoid
D. Parallelogram
E. Rectangle
F. Square
Answer:
A and D are correct. This is a parallelogram, which is a quadrilateral. B is not correct because not all the sides are congruent. C is not correct. E and F are not correct because this parallelogram does not have any right angles.
Peter’s teacher says he may have his report card percentage based on either the mean or the median and he can drop one test score if he chooses.
84%, 71%, 64%, 90%, 75%, 44%, 98%
Which measure of center should Peter choose so he can have the highest percentage possible?
Peter should choose the mean after dropping one test score.
Peter should choose the mean without dropping one test score.
Peter should choose the median after dropping one test score.
Peter should choose the median without dropping one test score.
Answer:
A.
Step-by-step explanation:
Peter should choose to base his report card percentage on the median if he wants to have the highest percentage possible. To calculate the median, Peter would first order the scores from lowest to highest: 44%, 64%, 71%, 75%, 84%, 90%, 98%. Then, he would select the middle score as the median, which is 75%. If Peter drops his lowest score (44%), his percentage based on the median would be 80% ((64%+71%+75%+84%+90%+98%)/6). If he were to choose the mean, his percentage would also be 80%. However, since the median is not affected by extreme values like the 44% score, it is a more reliable measure of central tendency in this case.
I did this on homework b4 and got It right so this Is 100 percent right.
Answer:
Peter should choose the median after dropping one test score so he can have the highest percentage possible.
If we calculate the mean of all seven test scores, we get:
(84+71+64+90+75+44+98)/7 = 73.14%
If we calculate the median of all seven test scores, we get:
Arrange the scores in ascending order:
44, 64, 71, 75, 84, 90, 98
The median is 75.
If we drop the lowest score (44) and calculate the mean of the remaining six test scores, we get:
(84+71+64+90+75+98)/6 = 80.5%
If we drop the lowest score (44) and calculate the median of the remaining six test scores, we get:
Arrange the scores in ascending order:
64, 71, 75, 84, 90, 98
The median is 79.5%.
Therefore, Peter should choose the median after dropping one test score to have the highest possible percentage.
35 fluid ounces equals how many cup and ounces
Answer: 4.375 Cups and 35 Ounces.
Step-by-step explanation:
The amount of fluid ounces in 1 cup is 8, meanwhile the amount of fluid ounces in an ounce is 1.
Hope that helps
Find the minimum and maximum values of the objective function, and the points at which these values occur subject to the given constraints. Round your answers to the
nearest hundredth.
The minimum value of the objective function is 47, which occurs at the point (3,2), and the maximum value is 117, which occurs at the point (0,9).
To solve this linear programming problem, we need to first graph the feasible region defined by the given constraints:
The first constraint, x ≥ 0, represents the non-negative values of x along the x-axis.
The second constraint, 4x + 8y ≥ 32, can be rewritten as y ≥ -(1/2)x + 4, which is a line with a y-intercept of 4 and a slope of -(1/2). The feasible region is above this line.
The third constraint, 10x - y ≤ 30, can be rewritten as y ≥ 10x - 30, which is a line with a y-intercept of -30 and a slope of 10. The feasible region is above this line as well.
The fourth constraint, x + 6y ≤ 54, can be rewritten as y ≤ -(1/6)x + 9, which is a line with a y-intercept of 9 and a slope of -(1/6). The feasible region is below this line.
The feasible region is therefore the polygon bounded by the lines y = -(1/2)x + 4, y = 10x - 30, y = -(1/6)x + 9, and x = 0. To find the minimum and maximum values of the objective function f(x,y) = 11x + 13y, we need to evaluate this function at each corner of the feasible region and compare the results.
The corners of the feasible region are (0,4), (3,2), (5,4), and (0,9). Evaluating the objective function at these corners, we get:
f(0,4) = 52
f(3,2) = 47
f(5,4) = 89
f(0,9) = 117
Therefore, the minimum value of the objective function is 47, which occurs at the point (3,2), and the maximum value is 117, which occurs at the point (0,9).
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Solve for b:
-3(3+6b) = 36 - 3b
Show your work.
At what values of x does f(x)=0?
Answer:
f(x) = 0 at x = -2, 1, 3
A, B, and D are the correct choices.
Triangle ABC has vertices at A(−3, 3), B(0, 7), and C(−3, 0). Determine the coordinates of the vertices for the image if the preimage is translated 3 units up.
A′(−3, 0), B′(0, 4), C′(−3, −3)
A′(−3, 6), B′(0, 10), C′(−3, 3)
A′(−6, 3), B′(−3, 7), C′(0, 0)
A′(0, 3), B′(3, 5), C′(0, 0)
Answer:
To translate triangle ABC 3 units up, we need to add 3 to the y-coordinate of each vertex:
A' = (-3, 3 + 3) = (-3, 6)
B' = (0, 7 + 3) = (0, 10)
C' = (-3, 0 + 3) = (-3, 3)
Therefore, the coordinates of the vertices for the image triangle A'B'C' are A'(-3, 6), B'(0, 10), and C'(-3, 3).
So the correct answer is: A′(−3, 6), B′(0, 10), C′(−3, 3).
Help with this question.
The contrapositive statement is option D
What is contrapositive statement?If the hypothesis and conclusion of an earlier conditional statement are reversed, a contrapositive statement is produced.
Technically speaking, the contrapositive of a conditional statement that starts with "If p, then q" is "If not q, then not p." The initial assertion and its contrapositive, then, are both true because they are logically equivalent.
Thus the contrapositive statement as shown is the statement ~q ~p
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A lodestone is a natural magnet that attracts iron and steel the force required to pull a magnet free from steel plate is called pull force certain magnet has a pull force of 2.2 pounds right this pull force as a mixed number
We can write the pull force of the magnet as [tex]2 \frac{1}{5} pounds[/tex].
What is the mixed number representation of the pull force?A mixed number refers to number that contains both an integer (whole number) and a proper fraction (a fraction whose numerator is less than its denominator).
To represent the pull force as a mixed number, we must to convert the decimal 0.2 to a fraction. Since 0.2 is equal to 1/5, we can write it as 2 and 1/5 pounds/ Therefore, the mixed number representation of the magnet's pull force of 2.2 pounds is 2 1/5 pounds.
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PQRS is a rhombus. ∠ SPQ = 120° and SP = 8.
Find each of the following.
20). ∠ SPO
21). ∠ POS
22). ∠ PSO
23). ∠ PO
24). ∠ SO
25). ∠ The area of PQRS
In the rhombus PQRS, if angle ∠ SPQ = 120° then ∠SPO is 30°
∠POS is 90° and ∠PSO is 60 degrees, ∠PO is 90° and ∠SO is 150°
PQRS is a rhombus.
∠ SPQ = 120° and SP = 8.
We have to find angles,∠SPO = (180° - ∠SPQ) / 2
= (180° - 120°) / 2
= 30°
∠POS = 90°
Now we have to find angle PSO
∠PSO+∠SPO+∠POS =180
30+90+∠PSO=180
120+∠PSO=180
∠PSO=180-120
∠PSO=60 degrees
∠PO = 360° / 4 = 90°
∠SO = 180° - ∠POS = 180° - 30°
= 150°
The area we find by using formula diagonal 1 × diagonal 2/2
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you complete your math homework 25 out of 25 school days in April. Describe the likelihood of you completing your math homework.
For each of the shapes below, state whether it is a regular polygon, an
irregular polygon or neither.
ASAAP NEED HELLPPP
Answer:
regular: Eirregular: A, B, Dneither: CStep-by-step explanation:
You want to identify the given shapes as a regular or irregular polygon, or neither.
Regular polygonA regular polygon is one that has all sides congruent, and all interior angles congruent. Polygon E is marked as having congruent sides and congruent angles.
Polygon E is a regular polygon.
PolygonA polygon is a closed figure formed by line segments connected end-to-end. A simple polygon is one that has no intersecting line segments. A convex polygon is one that has all interior angles measuring 180° or less.
Any simple polygon that is not a regular polygon is an irregular polygon.
Polygons A, B, D are irregular polygons.
CircleA circle is not a polygon. Figure C is neither a regular polygon nor an irregular polygon.
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Question 14(Multiple Choice Worth 5 points)
(07.02 MC)
A system of inequalities is shown.
Which system is represented in the graph?
Oy
y
Oy2x² - 2x+4
y<-x² + 4
Oyzx² - 2x+4
ys-x² +4
Oy>x² - 2x +4
y≤ x² + 4
The system of inequalities that represents the graph is
y ≥ x² - 2x + 4 and y < -x² + 4 is the
Option B is the correct answer.
We have,
The inequality y ≥ x² - 2x + 4 represents a parabola that opens upwards and has a vertex at (1,3) as shown below:
The inequality y < -x² + 4 represents an inverted parabola that opens downwards and has a vertex at (0,4) as shown below:
Therefore,
The system of inequalities that represents the graph is
y ≥ x² - 2x + 4 and y < -x² + 4 is the
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The maker of a cell phone screen protector would like to estimate the proportion of customers who file a warranty claim. To do so, they select a random sample of 200 customers and determine that the 96% confidence interval for the true proportion of customers who file a warranty claim to be 0.15 to 0.28. Which of the following would decrease the margin of error?
selecting another sample
decreasing the sample size
increasing the confidence level
decreasing the confidence level
In order to decrease the margin of error, the best option in this instance is by decreasing the confidence level would make the interval to be narrower.
The correct option is D.
What is the margin of error?The margin of error, also known as the confidence interval, provides information on how closely your survey results will likely reflect the opinions of the general community.
The margin of error is a measure of the potential uncertainty in your survey results. It is more likely that the results will deviate from the "true figures" for the entire population the wider the margin of error.
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riangle NMO is drawn with vertices N(−5, 2), M(−2, 1), O(−3 , 3). Determine the image vertices of N′M′O′ if the preimage is reflected over x = −2.
N′(5, −2), M′(2, 1), O′(3, 3)
N′(−2, 2), M′(1, 1), O′(0, 3)
N′(1, 2), M′(−2, 1), O′(−1, 3)
N′(−5, −2), M′(−2, −1), O′(−3, −3)
The vertices after transformation are N′(1, 2), M′(−2, 1), O′(−1, 3).
We have,
N(−5, 2), M(−2, 1), O(−3 , 3).
We know the rule to reflect over a vertical line x =a is
(x, y) --> (-x-2a, y)
So, for x=2 the rule will be
(x, y) --> (-x-4, y)
Now, the vertices after transformation are
M(-2, 1) -> M'(-2, 1)
N(-5, 2) -> N'(1, 2)
O(-3, 3) -> O'(-1, 3)
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27. The side length of a cube is (b+7). What is its volume?
HELP WHICH INE IS IT CORRECTT ITS DUE TODAY
Answer:
Step-by-step explanation:
Solve for x. 3x2−6x+2=0
x=3±23√3
x=3±3√3 x equals fraction numerator 3 plus or minus square root 3 end root end numerator over 3 end fraction x=6±43√3 x equals fraction numerator 6 plus or minus 4 square root 3 end root end numerator over 3 end fraction x=6±23√3 x equals fraction numerator 6 plus or minus 2 square root 3 end root end numerator over 3 end fraction
The solution of "quadratic-equation" , 3x² - 6x + 2 = 0 is (b) x = (3 ± √3)/3.
A "Quadratic-Equation" is defined as a second-degree polynomial equation of the form : ax² + bx + c = 0,
where x = variable, and "a", "b", and "c" are constants, with a ≠ 0.
We use the "quadratic-formula" to solve : which is ⇒ x = (-b ± √(b²-4ac))/(2a),
In the quadratic equation "3x² - 6x + 2 = 0", We get , a = 3, b = -6, and c = 2.
Substituting the values,
we get,
⇒ x = (-(-6) ± √((-6)²-4(3)(2)))/(2×3),
⇒ x = (6 ± √(36-24))/6,
⇒ x = (6 ± √12)/6,
⇒ x = (6 ± 2√3)/6,
⇒ x = (3 ± √3)/3,
So the two roots of the quadratic equation 3x² - 6x + 2 = 0 are : x = (3 + √3)/3 and x = (3 - √3)/3.
Therefore, the correct option is (b).
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The given question is incomplete, the complete question is
Find the solution of the given quadratic equation , 3x² - 6x + 2 = 0.
(a) x = 3 ± 23√3
(b) x = (3 ± √3)/3
(c) x = 6 ± 43√3
(d) x = 6 ± 23
What are a) the ratio of the perimeters and b) the ratio of the areas of the larger figure to the smaller figure? The figures are not drawn to scale.
A. 5/2 and 25/4
B. 5/2 and 7/4
C. 7/2 and 25/4
D. 7/2 and 7/4
SOMEONE PLEAS HELP!
Answer:
The answer to your problem is, A. 5/2 and 25/4
Step-by-step explanation:
In the problem the two similar figures, with side lengths 30 yds and 12 yds.
In order to solve the problem we need to find the ratio of the perimeters and the ratio of the areas of the larger figure to the smaller figure.
Using this information we know the the ratio of the perimeter of similar figure is equal to the scale factor and the ratio of the areas equal to the square of the scale factor.
the scale factor = 30/12 = 5/2
the ratio of the perimeter = 5/2
the ratio of the areas = (5/2)² = 25/4
Thus the answer to your problem is, A. 5/2 and 25/4
The height and radius of a cone are each multiplied by 3.
What effect does this have on the volume of the cone?
The volume of the cone is multiplied by
Please helpppppppppp k12and only give an accurate answer
With Geico you get a discount for being a good driver of 10%. You have a six month policy for 1,025. If you pay it in full, you get another 10% discount.
How much would you pay per month if you choose to not pay in full?
Round your answer to the nearest cent and do not put a dollar sign.
$138.38 you pay per month if you choose to not pay in full
If you pay in full, you get a 10% discount on the six-month policy, which means you would pay:
1,025 - 0.1(1,025) = 922.50
If you choose to not pay in full, you would not get the 10% discount for paying in full.
We get the 10% discount for being a good driver, which would be applied to each monthly payment.
This means that each monthly payment would be:
(1 - 0.1)(922.50) / 6 = 138.38
we get a monthly payment of $138.38.
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Please answer these 3 questions
The Volume of the box is 12 cubic unit.
We have,
Height = 1 unit
Width = 2 unit
Length = 6 unit
So, Volume of box
= l w h
= 1 x 2 x 6
= 12 cubic unit
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a+b-c
a + b is equal to what
The expression a + b cannot be added/evaluated because 2.00x and 1.50y are not like terms
Evaluating the expressionFrom the question, we have the following parameters that can be used in our computation:
a + b is equal to what
The above statement is an addition expression that adds the values of a and b
However, the terms of the expression are not like terms
i.e. a and b are not like terms
This means that the expression cannot be added/evaluated
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A Circle has a radius of 6cm, an arc AB of the circle is 9cm calculate this angle subtended by AB
The angle subtended by the arc AB in the circle is 68.75 degrees.
We have,
We know that the circumference of a circle is given by 2πr,
where r is the radius of the circle.
The circumference of the circle with a radius of 6 cm is.
C = 2πr = 2π(6) = 12π cm
Since the arc AB of the circle is 9 cm, we can find the angle subtended by this arc using the formula:
angle = (arc length / circumference) x 360°
Plugging in the values we have:
angle = (9 / 12π) x 360°
angle = 68.75°
Therefore,
The angle subtended by the arc AB is 68.75 degrees.
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Triangle ABC is congruent to triangle DEF.
Which statement must be true about the triangles?
Responses
AC, = , EF
m∠B=m∠F
m∠A=m∠D
BC = DE
Answer:
the third one: m<a = m<d
Determine how many liters a right circular cylindrical tank holds if it is 6 m long and 13 m in diameter.
The tank holds approximately 994,040 liters.
To solve this problem
The volume of a right circular cylinder is given by the formula:
V = πr^2h
Where
r is the radius of the cylinderh is its height π is a mathematical constant approximately equal to 3.14159The cylinder's diameter is specified as 13 m, hence the radius may be computed using the formula: r = d/2 = 13/2 = 6.5 m
The cylinder is described as having a 6 m length.
These values are substituted into the volume calculation to produce the following result:
V = π(6.5)^2(6)
V ≈ 994.04 cubic meters
Since 1 cubic meter equals 1000 liters, we can convert the volume to liters by multiplying by 1000.
V = 994.04 cubic meters x 1000 liters/cubic meter
V = 994,040 liters
Therefore, the tank holds approximately 994,040 liters.
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What is an equation of the line that passes through the points (0,-8) and (4, -3)?
=00
Hello!
To find the equation of the line that passes through the points (0,-8) and (4,-3), we can use the slope-intercept form of the equation:
y = mx + b
where m is the slope of the line and b is the y-intercept.
First, find the slope (m) of the line using the formula:
m = (y2 - y1)/(x2 - x1)
where (x1, y1) = (0,-8) and (x2, y2) = (4,-3).
m = (-3 - (-8))/(4 - 0) = 5/4
Now that we have the slope (m), we can use the point-slope form of the equation to find the equation of the line:
y - y1 = m(x - x1)
where (x1, y1) = (0,-8) and m = 5/4.
y - (-8) = (5/4)(x - 0)
Simplify the equation to get the slope-intercept form:
y + 8 = (5/4)x
y = (5/4)x - 8
Therefore, the equation of the line that passes through the points (0,-8) and (4,-3) is y = (5/4)x - 8.
26). Is Δ EFG ≅ Δ HIJ?
27). What is the scale factor of Δ EFG to Δ HIJ?
28). What is the ratio of their perimeters?
29). What is the ratio of their areas?
The triangles are not congruent.
Given that, two triangles, EFG and HIJ are similar,
So,
Since, the triangles are similar, but according to the definition of similarity, two objects that are similar are not necessarily congruent,
so the Δ EFG is not congruent to Δ HIJ.
Cos 30° = HI / HJ
√3/2 = 3/HI
HI = 3.5
Therefore, the scale factor Δ EFG to Δ HIJ = EF / HI = 10/3.5 = 2/0.7
The ratio of perimeter of similar objects are same as the scale factor,
so, the ratio of their perimeters = 2/0.7
The ratio of the areas of the similar objects are the ratios of the squares of the scale factor.
So, the ratio of their areas = 4/0.49
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Fill in the missing purchase prices and selling prices for stock trades in the table.
Number
of Shares
Selling Price
per Share
Capital Gain
or Loss
500
100
650
1,300
Purchase Price
per Share
$54
C.
g.
$31
$62
$12
$23
a.
f.
$700
-$7,800
Percent Gain or Loss
(nearest tenth of a percent)
b.
d.
h.
15% (gain)
The blanks will be -
(a) Capital Gain = $4000
(b) Percent of Capital Gain = 14.8%
(c) Purchase price per share = $5
(d) Percent of capital gain = 140%
(e) The selling price per share = $35.65
(f) Capital Gain = $3022.5
(g) Purchase price per share = $29
(h) Percent of capital loss = 20.7%
(i) Purchase price per share $54 and selling price per share $62.
The number of shares is 500.
So, Capital Gain = (500*62 - 500*54) = $4000
Percent of Capital Gain = (4000/(500*54))*100% = 14.8% (rounding to nearest tenth)
(ii) Number of shares = 100 and selling price of per share = $12 and capital gross = $700.
Purchase price per share = (12*100 - 700)/100 = 500/100 = $5
So the percent of capital gain = (700/(5*100))*100% = 140%
(iii) Number of shares = 650 and purchasing price per share = $31 and percent of capital gain = 15%
The selling price per share = 31*(100+15)/100 = $35.65
Capital Gain = (31*650)*15% = $3022.5
(iv) Number of shares = 1300 and selling price of per share = $23 and capital loss = - $7800
Purchasing price per share = $ (23*1300+7800)/1300 = $29
Percent of capital loss = (7800/(29*1300))*100% = 20.7% (rounding to nearest tenth)
Hence, (a) $4000; (b) 14.8% (gain); (c) $5; (d) 140% (gain); (e) $35.65; (f) $3022.5; (g) $29; (h) 20.7% (loss).
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Instructional Item 2
Use the properties of exponents to create an equivalent expression for the given expression
shown below with no variables in the denominator.
(64x²)-^-1/6(32x^5)^-2/5
Solve for x:
3x - 3 = 4(x-9)
Show your work
Answer:
[tex]\Huge \boxed{\bf{x = 33}}[/tex]
Step-by-step explanation:
To solve for x in the equation [tex]3x - 3 = 4(x - 9)[/tex], we will follow these steps:
1. Distribute the 4 on the right-hand side of the equation:
[tex]3x - 3 = 4x - 36[/tex]2. To isolate x, subtract 3x from both sides:
[tex]-3 = x - 36[/tex]3. Lastly, add 36 to both sides of the equation to solve for x:
[tex]x = 33[/tex]So, the solution to the equation [tex]3x - 3 = 4(x-9)[/tex] is [tex]x = 33[/tex].
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