Answer:
8.5cm
Step-by-step explanation:
convert 3.4metres to cm that is by multiplying by 100
3.4×100=340cm
1rep 40
?rep 340
that is 340/40
=8.5cm
Answer:
8.5 cm
Step-by-step explanation:
Scale = 1:40
Length of the room = 3.4 meters
3.4 meters =3.4 X 100 =340 cm
Since 1 unit on the diagram represents 40 units
The length of the diagram
[tex]=\dfrac{340}{40}\\\\=8.5$ cm[/tex]
The length of the room on the diagram is 8.5 cm.
how many two third ounce slice of cheese in twenty four ounce package
Answer: 36
Step-by-step explanation:
Simply do 24/(2/3) to get 36 2/3 ounce slices.
Hope it helps <3
If four times the brother's age is subtracted from three times the sister's age, the difference is 17. Give an equation that represents this statement using bbb as the age of the brother and s as the age of the sister.
Answer:
3s-4bbb=17
Step-by-step explanation:
brother=4bbb
sister=3s
3s-4bbb=17
PLEASE HELP Which ordered pair is a solution to the system of inequalities?
y< 3x
y< 5
Answer:
I am pretty sure that it is C
Step-by-step explanation:
A 1,3 so 3 < 3 no not true
x,y
B -12,50 50< -36 Also not true
x , y
C 9 , 4 4<27 Yes 4< 5 YEPPP
D 4,10 10<12 Yes 10<5 NOOPPPPPEEEE
Witch table represents a linear function ?
Answer:
If you compute the slope between any two points that must be the same, that's how you can tell if a table represents a linear function.
Remember that the slope between any two points (x1,y1), (x2,y2) is
slope = ( y2 - y1 ) / (x2 - x1)
Step-by-step explanation:
If you compute the slope between any two points that must be the same, that's how you can tell if a table represents a linear function.
Remember that the slope between any two points (x1,y1), (x2,y2) is
slope = ( y2 - y1 ) / (x2 - x1)
What is the next number in the series: 4, 5, 9, 25, 89, ___
Answer:
345
Step-by-step explanation:
1 + 4 = 5
4 + 5 = 9
16 + 9 = 25
64 + 25 = 89
1, 4, 16, and 64 are powers of 4. The next power of 4 is 256.
256 + 89 = 345
The answer is 345 (don’t ask why)
The height of a projectile launched upward at a speed of 32 feet/second from a height of 128 feet is given by the function h(t) = -16t^2 + 32t +128. How long will it take the projectile to hit the ground?
Answer:
It takes 4 seconds for the projectile to hit the ground
Step-by-step explanation:
The height of the projectile after t seconds is given by the following equation:
[tex]h(t) = -16t^{2} + 32t + 128[/tex]
How long will it take the projectile to hit the ground?
It happens when [tex]h(t) = 0[/tex]
So
[tex]h(t) = -16t^{2} + 32t + 128[/tex]
[tex]-16t^{2} + 32t + 128 = 0[/tex]
Solving a quadratic equation:
Given a second order polynomial expressed by the following equation:
[tex]ax^{2} + bx + c, a\neq0[/tex].
This polynomial has roots [tex]x_{1}, x_{2}[/tex] such that [tex]ax^{2} + bx + c = a(x - x_{1})*(x - x_{2})[/tex], given by the following formulas:
[tex]x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}[/tex]
[tex]x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}[/tex]
[tex]\bigtriangleup = b^{2} - 4ac[/tex]
In this question:
[tex]-16t^{2} + 32t + 128 = 0[/tex]
So [tex]a = -16, b = 32, c = 128[/tex]
[tex]\bigtriangleup = 32^{2} - 4*(-16)*(128) = 9216[/tex]
[tex]t_{1} = \frac{-32 + \sqrt{9216}}{2*(-16)} = -2[/tex]
[tex]t_{2} = \frac{-32 - \sqrt{9216}}{2*(-16)} = 4[/tex]
Time is a positive measure, so:
It takes 4 seconds for the projectile to hit the ground
This function to calculate the area of a rectangle is not very readable. Can you refactor it, and then call the function to calculate the area with base of 5 and height of 6? Tip: a function that calculates the area of a rectangle should probably be called rectangle_area, and if it's receiving base and height, that's what the parameters should be called.
Answer:
Here is the refactored function:
def rectangle_area(base, height):
area = base * height
return area
print("The area is ", rectangle_area(5,6))
Step-by-step explanation:
The above program has a function rectangle_area that takes two variables base and height as parameters. The function then computes the area of rectangle by multiplying the values of base and height. The result of the multiplication is assigned to the variable area. Then the function returns the resultant area.
print("The area is ", rectangle_area(5,6)) statement calls rectangle_area() method by passing values of base and height i.e. 5 and 6 to compute the area. The output of this program is:
The area is 30
Note that the use of rectangle_area function name describes what the function does i.e. it computes the area of rectangle. By naming the parameters as base and height that clearly depicts that in order to compute rectangle are we need the base and height of rectangle. So this makes the code readable.
Which pair of non-congruent figures must be similar? two squares two parallelograms (not rectangles) two right triangles two isosceles triangles (not equilateral)
Answer:
The answer is A (Two squares)
Step-by-step explanation:
Any give square will have proportionate side lengths,as they are the same, meaning that if you dilute one square it will always be proportinate
Answer:
it is a
Step-by-step explanation:
the other person is correct. and I did the test
if -2x = -14 what is the value of x
Answer: x= 7
Step-by-step explanation:
-2x= -14 Divide both sides by -2
x= 7
check
-2(7) = -14
-14 = -14
Answer:
x = 7
Step-by-step explanation:
-2x = -14
Divide each side by -2
-2x/-2 = -14/-2
x = 7
Find the probability of picking 1 consonant and 4 vowels when 5 letters are picked (without replacement) from a set of alphabet tiles.
Answer:
Ok, we have a total of 26 letters, and we want to select 5 of them.
Of the 26 letters, 21 are consonants and 5 are vowels.
Suppose that we want to have the consonant in the first selection, so the probability of picking a consonant is equal to the quotient between the number of consonants and the total number of letters.
p = 21/26
now a letter has been selected, so in the set, we have 25 letters left.
In the next 4 selections, we must select vowels.
In the second selection the probability is:
p = 5/25
in the third, the prob is:
p = 4/24 (we already selected one vowel before, so now we only have 4 vowels)
The fourth selection:
p = 3/23
and the last selection:
p = 2/22
The total probability is equal to the product of all the individual proabilities, so we have:
P = (2/22)*(3/23)*(4/24)*(5/25)*(21/26)
Now, remember that we said that the consonant must be in the first place, but it can be in any of the five places, so if we add the permutations of the consonant letter we have:
P = 5*(2/22)*(3/23)*(4/24)*(5/25)*(21/26) = 0.0018
What is the correct slope and y-intercept for the following: y=-3x+8
━━━━━━━☆☆━━━━━━━
▹ Answer
Slope = -3
Y-intercept = 8
▹ Step-by-Step Explanation
y = mx + b
mx represents the slope.
b represents the y intercept.
therefore,
y = -3x + 8
Hope this helps!
CloutAnswers ❁
Brainliest is greatly appreciated!
━━━━━━━☆☆━━━━━━━
Answer:
[tex]\boxed{\mathrm{Slope:}-3 \: \: \: \:\: \mathrm{Y \: intercept:}8}[/tex]
Step-by-step explanation:
The general form of slope-intercept:
[tex]y=mx+b[/tex]
[tex]m:slope\\b:y \: intercept[/tex]
[tex]y=-3x+8[/tex]
[tex]m=-3\\b=8[/tex]
The slope is -3.
The y-intercept is (0, 8) or 8.
BRAINLIEST ANSWER GIVEN Without actually solving the problem, choose the correct solution by deciding which choice satisfies the given conditions. The length of a rectangle is 2 feet longer than the width. The perimeter is 20 feet. Find the dimensions of the rectangle. Length= ?; width=?
Answer:
length = 6 feetwidth = 4 feetStep-by-step explanation:
Perimeter of a rectangle = 2l + 2w
where l is the length
w is the width
The length of the rectangle is 2 feet longer than the width is written as
l = 2 + w
Perimeter = 20feet
So we have
20 = 2( 2 + w ) + 2w
20 = 4 + 2w + 2w
4w = 16
Divide both sides by 4
w = 4
Substitute w = 4 into l = 2 + w
That's
l = 2 + 4
l = 6
length = 6 feetwidth = 4 feetHope this helps you
Answer:
w = 4 and L = 10
Step-by-step explanation:
perimeter of a rectangle = 2(l+w)
p = 20
L = 2 + w
w = ?
20 = 2(2 + w + w)
20 = 2(2 + 2w)
20/2 = 2 + 2w
10 = 2 + 2w
10 - 2 = 2w
8 = 2w
w = 8/2 = 4
L = w + 2
L = 4 +2 = 6
w = 4 and L = 10
which quadratic function in standard form has the value a= -3.5, b=2.7, and c= -8.2?
Answer:
y = -3.5x² + 2.7x -8.2
Step-by-step explanation:
the quadratic equation is set up as a² + bx + c, so just plug in the values
Answer:
[tex]-3.5x^2 + 2.7x -8.2[/tex]
Step-by-step explanation:
Quadratic functions are always formatted in the form [tex]ax^2+bx+c[/tex].
So, we can use your values of a, b, and c, and plug them into the equation.
A is -3.5, so the first term becomes [tex]-3.5x^2[/tex].
B is 2.7, so the second term is [tex]2.7x[/tex]
And -8.2 is the C, so the third term is [tex]-8.2[/tex]
So we have [tex]-3.5x^2+2.7x-8.2[/tex]
Hope this helped!
WHY CAN'T ANYONE HELP ME: ( Two computer disks and three notebooks cost $29. However, five computer disks and four notebooks cost $48. Find the price of each.
Answer:
Disks = $4 each and Notebooks = $7 each
Step-by-step explanation:
-4(2D + 3N = 29)
3(5D + 4N = 48)
-8D - 12N = -116
15D + 12N = 144
7D = 28
D = $4
2(4) + 3N = 29
8 + 3N = 29
3N = 21
N = $7
The resale value of a certain industrial machine decreases over a 8-year period at a rate that changes with time. When the machine is x years old, the rate at which its value is changing is 200(x - 8) dollars per year. By how much does the machine depreciate during the fifth year
Answer: The machine depreciates during the fifth year by $4000.
Step-by-step explanation:
Given: The resale value of a certain industrial machine decreases over a 8-year period at a rate that changes with time.
When the machine is x years old, the rate at which its value is changing is 200(x - 8) dollars per year.
Then, the machine depreciates A(x) during the fifth year as
[tex]A(x) =\int^{5}_1200(x - 8)\ dx\\\\=200|\frac{x^2}{2}-8x|^{5}_1\\\\=200[\frac{5^2}{2}-\frac{1^2}{2}-8(5)+8(1)]\\\\=200 [12-32]\\\\=200(-20)=-4000[/tex]
Hence, the machine depreciates during the fifth year by $4000.
There are 50 mangoes 20 of which are unriped another basket contains 40 mangoes 15 unripe if we take 1 mangoes from each basket Find the probability of getting both are ripe Find the probability of getting both are unripe Find the probability of getting one ripe and one unripe Find the probability of at least one right Find the probability of at least one uripe
Answer:
probability of getting both are unripe
= 0.15
probability of getting both are ripe
= 0.375
Probability of one ripe and one unripe
=0.234375
Probability of at least one unripe
=0.625
Step-by-step explanation:
50 mangoes 20 of which are unriped in the first basket .
Riped = 50-20= 30
Probability of unripe = 20/50
Probability of unripe= 0.4
Probability of ripe = 30/50
Probability of ripe = 0.6
40 mangoes of which 15 are unripe In the second basket
Number of riped= 40-15= 25
Probability of unriped= 15/40
Probability of unriped= 0.375
Probability of riped= 25/40
Probability of riped= 0.625
probability of getting both are unripe
= 0.4*0.375
probability of getting both are unripe
= 0.15
probability of getting both are ripe
= 0.6*0.625
= 0.375
Probability of one ripe and one unripe
= 0.625*0375
= 0.234375
Probability of at least one unripe
= 1- probability of no unripe
= 1 - probability of both ripe
= 1-0.375
= 0.625
Applications of exponential functions
Answer:
a simple interest rate of 4.5%
Find the 10th term of the following geometric sequence.
2, 10, 50, 250, ...
Answer:
3906250
Step-by-step explanation:
We can notice that the ratio is 5. 10/2 = 5
Each term gets multiplied by 5 to get the next term.
250 × 5 = 1250 (5th term)
1250 × 5 = 6250 (6th term)
6250 × 5 = 31250 (7th term)
31250 × 5 = 156250 (8th term)
156250 × 5 = 781250 (9th term)
781250 × 5 = 3906250 (10th term)
The 10th term of the geometric sequence is 3906250.
A business marketing firm specializes in radio advertising. They hope to show there is a linear relationship between sales and the amount of money a client invests in radio advertising. Which hypothesis test would be most appropriate for addressing this question?
Answer: Chi-square test
Step-by-step explanation:
A Chi-square test is a test used or applied to check or see if a relationship between two categorical variables. Example
The marketing firm trying to show their client that there is a linear relationship between sales and the amount of money the client has invested in radio advertisements uses chi-square method by comparing the two variables which are Sales made and Amount spent on advert or promotion on radio.
Points A,B,C and D are midpoints of the sides of the larger square. If the smaller square has area 60, what is the area of the bigger square?
Answer:
80
Step-by-step explanation:
Angle bisectors AX and of triangle ABC meet at point I. Find angle C in degrees, if AIB = 109.
Answer:
angle C = 38 degrees
Step-by-step explanation:
Refer to attached figure (sorry, forgot to attach earlier)
Given
AIB = 109
Let
CAX = XAB = x
CBY = YBA = y
XIB = YIA = x+y ........exterior angles
XIB = YIA = 180-109 = 71 ............ sum of angles on a line
=>
x+y = 71
ACB = 180 - 2x -2y ................. sum of angles of a triangle
= 180 - 2(x+y)
= 180 - 2(71)
= 180 - 142
= 38
A certain brand of automobile tire has a mean life span of 35,000 miles, with a standard deviation of 2250 miles. Assume the life spans of the tires have a bell-shaped distribution.
(a) The life spans of three randomly selected tires are 34,000 miles, 37,000 miles, and 30,000 miles. Find the z-score that corresponds to each life span. Determine whether any of these life spans are unusual.
(b) The life spans of three randomly selected tires are 30,500 miles, 37,250 miles, and 35,000 miles. Using the Empirical Rule, find the percentile that corresponds to each life span.
Answer:
Step-by-step explanation:
From the information given:
mean life span of a brand of automobile = 35,000
standard deviation of a brand of automobile = 2250 miles.
the z-score that corresponds to each life span are as follows.
the standard z- score formula is:
[tex]z = \dfrac{x - \mu}{\sigma}[/tex]
For x = 34000
[tex]z = \dfrac{34000 - 35000}{2250}[/tex]
[tex]z = \dfrac{-1000}{2250}[/tex]
z = −0.4444
For x = 37000
[tex]z = \dfrac{37000 - 35000}{2250}[/tex]
[tex]z = \dfrac{2000}{2250}[/tex]
z = 0.8889
For x = 3000
[tex]z = \dfrac{30000 - 35000}{2250}[/tex]
[tex]z = \dfrac{-5000}{2250}[/tex]
z = -2.222
From the above z- score that corresponds to their life span; it is glaring that the tire with the life span 30,000 miles has an unusually short life span.
For x = 30,500
[tex]z = \dfrac{30500 - 35000}{2250}[/tex]
[tex]z = \dfrac{-4500}{2250}[/tex]
z = -2
P(z) = P(-2)
Using excel function (=NORMDIST -2)
P(z) = 0.022750132
P(z) = 2.28th percentile
For x = 37250
[tex]z = \dfrac{37250 - 35000}{2250}[/tex]
[tex]z = \dfrac{2250}{2250}[/tex]
z = 1
Using excel function (=NORMDIST 1)
P(z) = 0.841344746
P(z) = 84.14th percentile
For x = 35000
[tex]z = \dfrac{35000- 35000}{2250}[/tex]
[tex]z = \dfrac{0}{2250}[/tex]
z = 0
Using excel function (=NORMDIST 0)
P(z) = 0.5
P(z) = 50th percentile
a. The z score of each life span should be -0.4444, 0.889, and 2.2222.
b. The percentile of each life span should be 0.0228, 0.8413 and 0.5000.
Given that,
mean life span of 35,000 miles, with a standard deviation of 2250 miles.The calculation is as follows:(a)
The z score should be
[tex]Z1 = \frac{34000-35000}{2250} = -0.4444\\\\Z2 = \frac{37000-35000}{2250} = 0.8889\\\\Z3 = \frac{30000-35000}{2250} = -2.2222\\\\[/tex]
The tire with life span of 30000 miles would be considered unusual
(b)
The percentile should be
[tex]Z1 = \frac{30500-35000}{2250} = -2[/tex]
p(Z1 < -2) = NORMSDIST(-2) = 0.0228
[tex]Z2 = \frac{37250-35000}{2250} = 1[/tex]
p(Z2 < 1) = NORMSDIST(1) = 0.8413
[tex]Z3 = \frac{35000-35000}{2250} = 0[/tex]
p(Z3 < 0) = NORMSDIST(0) = 0.5000
Find out more information about standard deviation here:
https://brainly.com/question/12402189?referrer=searchResults
4, 12, 36,what is 3 other remaining sequence
Answer:
108, 324, 972
Step-by-step explanation:
This sequence is multiplying by ✖️3.
4✖️3=12✖️3=36✖️3=108✖️3=324✖️3=972
Hope this helps!
The volume of a rectangular prism is (x4 + 4x3 + 3x2 + 8x + 4), and the area of its base is (x3 + 3x2 + 8). If the volume of a rectangular prism is the product of its base area and height, what is the height of the prism?
Answer:
[tex]Height = x \frac{x^3+3x^2+4}{x^3+3x^2+8}[/tex]
Step-by-step explanation:
[tex]Volume = Base \ Area\ * Height[/tex]
[tex]Height = \frac{Volume}{Base \ Area}[/tex]
Where [tex]Volume = x^4+4x^3+8x+4[/tex] and [tex]Area = x^3+3x^2+8[/tex]
Putting in the formula
[tex]Height = \frac{x^4 + 4x^3 + 3x^2 + 8x + 4}{x^3 + 3x^2 + 8}[/tex]
Doing long division, we get
[tex]Height = x + \frac{x^3+3x^2+4}{x^3+3x^2+8}[/tex]
[tex]Height = x \frac{x^3+3x^2+4}{x^3+3x^2+8}[/tex]
This is the simplifies form and it can't be further simplified.
Answer:
[tex]x +1 - \frac{4}{x^3 + 3x^2 + 8}[/tex]
Step-by-step explanation:
[tex]volume=base \: area \times height[/tex]
[tex]height=\frac{volume}{base \: area}[/tex]
[tex]\mathrm{Solve \: by \: long \: division.}[/tex]
[tex]h=\frac{(x^4 + 4x^3 + 3x^2 + 8x + 4)}{(x^3 + 3x^2 + 8)}[/tex]
[tex]h=x + \frac{x^3 + 3x^2 + 4}{x^3 + 3x^2 + 8}[/tex]
[tex]h=x +1 - \frac{4}{x^3 + 3x^2 + 8}[/tex]
A father is 60 years old and his son is half his age. How old was the boy when his father was four times his age?
Hey there! I'm happy to help!
We see that the father is 60 years old, and the son is half of that age, so this means that the son is 30 years old.
We want to see the age the son was at when the father was four times his age. We know that the father is thirty years older than him, so we can write this equation with s representing the age of the son.
s+30=4s (30 years older than the son is equal to to four times the son's age at the time)
We subtract 30 from both sides.
s=4s-30
We subtract 4s from both sides.
-3s=-30
We divide both sides by -3.
s=10
Therefore, the boy was 10 when his father was four times his age. This is because his father would have been 40 because that is 30 more years than 10, and it is four times ten!
Have a wonderful day! :D
Explain how to find the range of a data set. What is an advantage of using the range as a measure of variation? What is a disadvantage?
Answer:
The range is found by subtracting the minimum data entry from the maximum data entry.
Step-by-step explanation:
The range is found by subtracting the minimum data entry from the maximum data entry.
It is easy to compute.
It uses only two entries from the data set.
which is bigger 4 or
[tex] \frac{12}{7} [/tex]
obviously 4 is bigger coz 12/7 will yeild you 1.71
You are mandated to pick 45 units per hour. You work 8.5 hours a day (minus a 1/2 hour lunch), Monday to Friday. How many units should you be picking each week?
Answer:
1912.5 unitsStep-by-step explanation:
Firstly let us calculate the amount of hours you will have to work in a week.
Since you will have to work Mondays through Fridays, hence you will be working 5 days in a week.
Hence in a week you will work 8.5*5= 42.5 hours in a week
Since in 1 hours you are mandated to pick 45 units
Hence in 42.5 hours you will pick 42.5*45= 1912.5 units
Please help!! Over several years, Stephon gathered data about his age and the time it took him to run two laps on the school track. The scatter plot shows the data he gathered and the line of best fit. The equation of the line of best fit is y = -2.1x + 565.6. Based on the line of best fit, approximately how long will it take Stephon to run two laps on the track when he is 192 months old?
Answer:
It will take Stephon about A: 163 seconds to run two laps when he is 192 months old.
Step-by-step explanation:
To find 163 seconds all I did was eyeball where 192 months is going to be on the x-axis and lined it up with the provided line of fit, then I ran it across the x-axis to the y-axis and I got around 163 seconds.
Given line of best fit is y = -2.1x + 565.6, where x is age in months and y is time in seconds, it take Stephon 162.4 seconds to run two laps on the track when he is 192 months old
A line of best fit is a straight line that minimizes the distance between it and some data. The line of best fit is used to express a relationship in a scatter plot of different data points.
Given in the question,
x = age in months
y = time in seconds
Here, age of child is independent and time taken to run two laps is dependent variable.
given line of best fit : y = -2.1x + 565.6
given y = 192 months
finding the value of y :
y = -2.1x + 565.6 = -2.1 * 192 + 565.6 = 162.4
Learn more about line of best fit here
https://brainly.com/question/29250235
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A particle is moving with the given data. Find the position of the particle. a(t) = 2t + 5, s(0) = 6, v(0) = −5
Answer:
The position of the particle is described by [tex]s(t) = \frac{1}{3}\cdot t^{3} + \frac{5}{2}\cdot t^{2} - 5\cdot t + 6,\forall t \geq 0[/tex]
Step-by-step explanation:
The position function is obtained after integrating twice on acceleration function, which is:
[tex]a(t) = 2\cdot t + 5[/tex], [tex]\forall t \geq 0[/tex]
Velocity
[tex]v(t) = \int\limits^{t}_{0} {a(t)} \, dt[/tex]
[tex]v(t) = \int\limits^{t}_{0} {(2\cdot t + 5)} \, dt[/tex]
[tex]v(t) = 2\int\limits^{t}_{0} {t} \, dt + 5\int\limits^{t}_{0}\, dt[/tex]
[tex]v(t) = t^{2}+5\cdot t + v(0)[/tex]
Where [tex]v(0)[/tex] is the initial velocity.
If [tex]v(0) = -5[/tex], the particular solution of the velocity function is:
[tex]v(t) = t^{2} + 5\cdot t -5, \forall t \geq 0[/tex]
Position
[tex]s(t) = \int\limits^{t}_{0} {v(t)} \, dt[/tex]
[tex]s(t) = \int\limits^{t}_{0} {(t^{2}+5\cdot t -5)} \, dt[/tex]
[tex]s(t) = \int\limits^{t}_0 {t^{2}} \, dt + 5\int\limits^{t}_0 {t} \, dt - 5\int\limits^{t}_0\, dt[/tex]
[tex]s(t) = \frac{1}{3}\cdot t^{3} + \frac{5}{2}\cdot t^{2} - 5\cdot t + s(0)[/tex]
Where [tex]s(0)[/tex] is the initial position.
If [tex]s(0) = 6[/tex], the particular solution of the position function is:
[tex]s(t) = \frac{1}{3}\cdot t^{3} + \frac{5}{2}\cdot t^{2} - 5\cdot t + 6,\forall t \geq 0[/tex]
Answer:
Position of the particle is :
[tex]S(t)=\frac{1}{3}.t^3+\frac{5}{2}.t^2-5.t+6[/tex]
Step-by-step explanation:
Given information:
The particle is moving with an acceleration that is function of:
[tex]a(t)=2t+5[/tex]
To find the expression for the position of the particle first integrate for the velocity expression:
AS:
[tex]V(t)=\int\limits^0_t {a(t)} \, dt\\v(t)= \int\limits^0_t {(2.t+5)} \, dt\\\\v(t)=t^2+5.t+v(0)\\[/tex]
Where, [tex]v(0)[/tex] is the initial velocity.
Noe, if we tale the [tex]v(0) =-5[/tex] ,
So, the velocity equation can be written as:
[tex]v(t)=t^2+5.t-5[/tex]
Now , For the position of the particle we need to integrate the velocity equation :
As,
Position:
[tex]S(t)=\int\limits^0_t {v(t)} \, dt \\S(t)=\int\limits^0_t {(t^2+5.t-5)} \, dt\\S(t)=\frac{1}{3}.t^3+\frac{5}{2}.t^2-5.t+s(0)[/tex]
Where, [tex]S(0)[/tex] is the initial position of the particle.
So, we put the value [tex]s(0)=6[/tex] and get the position of the particle.
Hence, Position of the particle is :
[tex]S(t)=\frac{1}{3}.t^3+\frac{5}{2}.t^2-5.t+6[/tex].
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