_______is the resistance to motion offered by an object sliding over a surface

Answer:

I have no clue I'm just trying to get points

Explanation:

:) sorry

Answer:

False - Electromagnetic waves are transverse waves - they do not need a particular medium for transmission - as sound waves in air (longitudinal waves)

Answer:

I think this is the answer

Explanation:

Answer:

see below

Explanation:

Kind of like when yo open a warm soda .....excess gas is released

Answer:

when a medium begins to vibrate

The boat will swing back and forth about the same location, never reaching the land. Due to which the boaters plan will not help him reach shore.

The ship rocks back and forth as the wind and waves press against it. Similar to swiveling on a chair, yaw spins the ship on an unseen central line.

Waves travelling perpendicular to the ship's motion might create this, changing the ship's heading or direction.

The motion of the motor will be identical to that of water molecules. Because there is a wave on the water surface,The motor will move in lockstep with the water particle.

The particles of the medium only vibrate perpendicular to the wave propagation as the wave travels through the water surface, but they are not moved from their initial position.

As a result, the boat will swing back and forth about the same location, never reaching the land.

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Answer:

The quantity and quality of sleep both impact memory.

Explanation:

true

Explanation:

It has friction when objects move through it.

Answer: You take the biggest number and subtract it from the smallest number.

Explanation: Hope this helps.

Answer:

Subtract the minimum data value from the maximum data value to find the data range.

Explanation:

[tex]Hope[/tex] [tex]this[/tex] [tex]helps![/tex]

Kinematics is the branch of physics and a subdivision of classical mechanics concerned with the geometrically possible motion of a body or system of bodies without consideration of the forces involved. :)

Answer:

Kinematics is a branch of mechanics that deals with pure motion, without reference to the masses or forces involved in it.

Explanation:

Ex. X=2t+1 here x is related to t which is time(function of time)

Answer:

sorry im not good at math so sorry i cant help

Explanation:

Answer:

M g = M a = a (9 - 7) kg      with the two masses going in different directions

(7 + 9) kg * g = a * 2 kg       2 kg effective in prducing acceleration

a = 16 / 2 * g = 9.8 m/s^2 / 8 = 1.23 m/s^2

M1 a = T - M1 * g        T producing upward acceleration of 1.23 m/s^2

T = 7 (a + g) = 7 * 11 = 77 N

Check:

M2 a =  M2 * g - T          M2 producing downward acceleration

T = M2 (g - a) = 9 * (9.8 - 1.23) = 77 N

Answer:

ivory. ..................

For  the potential energy is converted to kinetic energy is mathematically given as

n=24.44%

Generally, the equation for the  potential energy  is mathematically given as

Ei=mgh

Ei=49.0\*9.81* 1.8

Ei=865.24J

Final total energy

K.E=0.5mv^2

K.E=0.5*49.0* (3.00)^2

K.E=211.5J

In conclusion, efficiency

n=Ef/Ei*100
n=211.5*865.24*100

n=24.44%

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Answer:

9 x 10^1  km/hr  

Explanation:

25 m/s   x  3600 sec / hr   x  1km / 1000 m = 90 km/hr

For an airplane of mass 270,000 kg , the magnitude of the force exerted is mathematically given as

N2=1584431.13N

N1=1061568.87N

Generally, the equation for the Force balance is mathematically given as

N1+N2=270000*g

Therefore

N2*10=N1*15

N1=10N2/15

N1=0.67N2

Hence

0.67N2+N2=270000*g

N2=1584431.13N

N1=1061568.87N

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Answer:

Like a galvanometer, an electric motor contains (a switch, an electromagnet) that is free to rotate between the poles of a permanent, fixed magnet. 9.

Answer:

A 1.56    see below

Explanation:

I will assume the 45 degree force is upward

vertical component =   600 sin 45 = 424.26 N

 added to the other vertical force will total 824.26 N

    F = ma

   824.26 = 100 * a    shows a = 8.24 m/s upward

Now we have to assume the mass is ALSO acted on by gravity and this value is given as  9.8  ( so downward is positive)

9.81 -   8.24      =  1.56 m/s^2

Answer:

A burning candle emits radiation in the form of heat and light. The Sun emits radiation in the form of light, heat, and particles. Uranium-238 decaying into Thorium-234 emits radiation in the form ofalpha particles.

Answer:

the sun

Explanation:

the sun emits radiation

For a particle that has a velocity that is 70 % of the speed of light and weighs 206.8 times the mass of an electron, the wavelength of this particle is mathematically given as

W= 739.47

Generally, the equation for the 70 % of the speed of light  is mathematically given as

70% of 3x10^8 = 2.1x10^8 m/s

Therefore

206.8*9.11x10^-31 = 1.88x10^-28 kg

In conclusion, The wavelength equation isTThe

wavelength= plancks constant / (mass*velocity)

Where

Plancks constant = 6.62x10^-34 m^2 kg/s

W=6.62x10^-34 / (1.88x10^-28/2.1x10^8)

W= 739.47

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Let's see

[tex]\\ \rm\Rrightarrow x=Asin(\omega t)\dots(1)[/tex]

Now we know the formula of acceleration

[tex]\\ \rm\Rrightarrow \alpha=-A\omega^2sin(\omega t)[/tex]

[tex]\\ \rm\Rrightarrow \alpha=-Asin(\omega t)\times \omega^2[/tex]

[tex]\\ \rm\Rrightarrow \alpha=-x\omega^2[/tex]

Or

[tex]\\ \rm\Rrightarrow \alpha=-\omega^2x[/tex]

Given that the position x of a particle along X-axis varies with time t by the equation:

[tex]{:\implies \quad \sf x=A\sin (\omega t)}[/tex]

As it defines the position, so x is just displacement here, and we need to find the acceleration first for telling with what if varies, so by definition, the second differential coefficient of displacement is acceleration, so differentiating both sides w.r.t.x of the above equation in accordance with chain rule we have:

[tex]{:\implies \quad \sf \dfrac{dx}{dt}=A\cos (\omega t)\cdot \omega \cdot \dfrac{dt}{dt}}[/tex]

[tex]{:\implies \quad \sf \dfrac{dx}{dt}=A\omega \cos (\omega t)}[/tex]

Differentiating both sides w.r.t.x by chain rule again to get the 2nd order derivative

[tex]{:\implies \quad \sf \dfrac{d^{2}x}{dt^{2}}=-A\omega \sin (\omega t)\cdot \omega \dfrac{dt}{dt}}[/tex]

[tex]{:\implies \quad \sf \dfrac{d^{2}x}{dt^{2}}=-A\omega^{2}\sin (\omega t)}[/tex]

Re-write as :

[tex]{:\implies \quad \sf \dfrac{d^{2}x}{dt^{2}}=-\omega^{2}\{A\sin (\omega t)\}}[/tex]

Can be further written as

[tex]{:\implies \quad \sf \dfrac{d^{2}x}{dt^{2}}=-x\omega^{2}}[/tex]

This is the Required answer

If they ask you the differential equation for the acceleration of a wave (as the given equation was general equation of a wave), you can simply write:

[tex]{:\implies \quad \sf \dfrac{d^{2}x}{dt^{2}}+x\omega^{2}=0}[/tex]

Answer:

B according to the picture

Explanation:

Star of 3 stellar masses => red supergiant=>supernova=>neutron star

Star of three stellar masses, red supergiant, supernova, neutron star are the star life cycle that is accurate. Therefore, the correct option is option B.

A star's life cycle is as follows: star formation inside a nebula, evolution into a sequence star, sustained nuclear fusion for a long time, exhaustion of fuel at some point, and gravitational core collapse with resulting high pressures and temperatures.

They typically consist of heated plasma held together by a strong gravitational force and are self-luminous. The thermonuclear process between helium and hydrogen that takes place in a star's core causes it to glow brilliantly. Star of three stellar masses, red supergiant, supernova, neutron star are the star life cycle that is accurate.

Therefore, the correct option is option B.

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Answer:

30 seconds

Explanation:

The formula for calculating acceleration is

( final velocity - inital velocity) ÷ time

If we enter the values, it would be (250 - 100) ÷ t = 5m/s^2

Now we need to know 't'

So we rearrange the equation to make t the subject.

(250-100) ÷ 5 = 30s

Answer:

7.07 radians per second

Answer:

Here, m=10 kg

The resultant force acting on the body is

F=(98N)2+(6N)2=10N

Let the resultant force F makes an angle θ w.r.t. 8N force.

From figure, tanθ=8N6N=43

The resultant acceleration of the body is 

a=mF=10kg10N=1ms−2

The resulatnt acceleration is along the direction of the resulatnt force.

Hence, the resultant acceleration of the body is 1 ms−2 at an angle of tan−1(43) w.r.t. 8N force.