is it
A) M T L
B)M T P
C)L || M
D)N || P

Answer:

I think it's 27

Step-by-step explanation:

because if she picked 2/5 of the flowers if u divide 18 by 2 u get 9 so that's 1/5 I think and then if u times that by 3 u get 27 and like that's the 3/5

Answer:

y coordinate: 8

Step-by-step explanation:

middle of the two areas have the y as 8

Answer:

x=9

Step-by-step explanation:

1. Combine like terms

2. Add 6 to both sides

3. Simplify

Answer:

what do you need help with?

Step-by-step explanation:

Answer:

2)  Lyn has 42, and Jo has 21

4)  320 women

6) 12 miles

Step-by-step explanation:

2) Divide 63 by 3 and get 21. 21 + 21 = 42 for Lyn, and leave 21 for Jo.

4) Subtract 20 from 620, and get 600. Divide 600 into 2 and get 300. 300 +20 = 320

6) Divide 24 into 2, and get 12. Multiply 12 by 3 and get 36. Divide 36 by 3 and get 12. 12 is your answer.

Hope this helps!

-kiniwih426

Answer:

A slope of -1

Step-by-step explanation:

use the slope formula

Answer:

JNM=42

Step-by-step explanation:

JNM is equal to LNK so you can set the equations equal to each other.

7x-21=4x+6, subtract 4x from both sides

3x-21=6, add 21 to both sides

3x=27, divide by 3

x=9, then you plug it into an equation

4 times 9 + 6

36+6

42

<JNM = [tex]42[/tex] degrees.

The angle made by two ground lines is measured horizontally , and is called a horizontal angle.

According to the question

Line J L and line M K slightly inclined with horizontal intersects at N.

<JNM = <LNK

[tex]4x + 6 = 7x - 21[/tex]

Subtract 4x from both sides

[tex]6 = 3x -21[/tex]

[tex]3x=27[/tex]

Divide by 3

[tex]x=\frac{27}{3}[/tex]

[tex]x =9[/tex]

<JNM = [tex]4x+6[/tex]

<JNM = [tex]4(9)+6[/tex]

<JNM = [tex]42[/tex] degrees

Find out more information about horizontal angle here

https://brainly.com/question/13667035

#SPJ2

Step-by-step explanation:

We have,

[tex]\displaystyle\sf{\,^{n}C_{n-1}+\,^{n}C_{n-2}}[/tex]

[tex]\displaystyle\sf{=\dfrac{n!}{(n-1)!(n-(n-1))!}+\dfrac{n!}{(n-2)!(n-(n-2))!}}[/tex]

[tex]\displaystyle\sf{=\dfrac{n!}{(n-1)!(n-n+1)!}+\dfrac{n!}{(n-2)!(n-n+2)!}}[/tex]

[tex]\displaystyle\sf{=\dfrac{n!}{(n-1)!(1)!}+\dfrac{n!}{(n-2)!(2)!}}[/tex]

[tex]\displaystyle\sf{=\dfrac{n(n-1)!}{(n-1)!(1)!}+\dfrac{n(n-1)(n-2)!}{(n-2)!(2)!}}[/tex]

[tex]\displaystyle\sf{=\dfrac{n}{1}+\dfrac{n(n-1)}{2}}[/tex]

[tex]\displaystyle\sf{=n+\dfrac{n^2-n}{2}}[/tex]

[tex]\displaystyle\sf{=\dfrac{2n+n^2-n}{2}}[/tex]

[tex]\displaystyle\sf{=\dfrac{n^2+n}{2}}[/tex]

[tex]\displaystyle\sf{=\dfrac{n(n+1)}{2}}[/tex]

Using the combination formula, it is found that the value of the expression is given by:

(b) n(n + 1)/2

[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by:

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

In this problem:

[tex]C_{n, n-1} = \frac{n!}{(n-1)!(n - n + 1)!} = \frac{n(n-1)!}{(n-1)!} = n[/tex]

[tex]C_{n, n-2} = \frac{n!}{(n-2)!(n - n + 2)!} = \frac{n(n-1)(n-2)!}{(n-2)!2!} = \frac{n(n-1)}{2}[/tex]

Then, adding these values:

[tex]n + \frac{n(n-1)}{2} = \frac{2n + n^2 - n}{2} = \frac{n(n + 1)}{2}[/tex]

Hence option b is correct.

More can be learned about the combination formula at https://brainly.com/question/25821700

Answer:

The thing is I don't know if like is will put fractions or decimals so I guess try both if u can if not I would go for decimals first because that is more probable.

Midpoint of some points

AB midpoint = -1,1.5

BC midpoint = -2.5,2

CA midpoint = -2.5,1.5

Midpoint of DE = -3,0

Midpoint of FG = 3,-1

Sorry that it took some time

Answer:

1800

Step-by-step explanation:

Answer:

b

Step-by-step explanation:

Total hours for biweek or 2 weeks

Hourly pay=$18.25

Total home pay

Atleast $255 per week you can easily acquire 1000 also by toil

Answer:

D

Step-by-step explanation:

1+3=4

1 out of 4 =1/4

remember x is bigger than y

Answer:

516,154 here you goooooooooooi

Answer:

c) 516154

Step-by-step explanation:

Q) 893 × 578 = ?

→ 893 × 578

→ 516154 is the answer.

Answer:

55

Step-by-step explanation:

m< PTS = m< RTQ since they are vertical angles

11(y-10) = 4y-5

Distribute

11y - 110 = 4y-5

Subtract 4y from each side

11y-110-4y = 4y-5-4y

7y-110 = -5

Add 110 to each side

7y-110+110 = -5+110

7t = 105

Divide by 7

7y/7 = 105/7

y =15

We want to find m<PTS

m< PTS = 11( y-10) = 11(15-10) = 11(5) = 55

Answer:

[tex] \frac{1}{x} + \frac{2}{x} + 10 = \frac{1}{3} ) \times3 x \\ 3 + 6 +30x = x \\ 30x - x = - 9 \\ 29x = - 9 \\ x = - \frac{9}{29} [/tex]

Answer:

i have the second part!

Step-by-step explanation:

the equation will have 2 valid solutions

Answer:

3 and 5 are prime twin?

Huh?

Step-by-step explanation:

[tex]\large\underline{\sf{Solution-}}[/tex]

Given that,

Further given that,

It means

We know,

[tex] \purple{\rm :\longmapsto\:\boxed{\tt{ Perimeter_{[square]} \: = \: 4 \times side \: }}}[/tex]

So, using this, we have

[tex]\rm :\longmapsto\:4x + 4y = 52[/tex]

[tex]\rm :\longmapsto\:4(x + y) = 52[/tex]

[tex]\rm\implies \:\boxed{\tt{ x + y = 13}} - - - - (1)[/tex]

Now, Further given that,

If square EFGH is cutting out from square ABCD, the area of remaining part is 91 square cm.

It means

[tex]\rm :\longmapsto\:Area_{[ABCD]} - Area_{[EFGH]} = 91[/tex]

We know,

[tex] \purple{\rm :\longmapsto\:\boxed{\tt{ Area_{[square]} = 4 \times side}}}[/tex]

So, using this, we get

[tex]\rm :\longmapsto\: {x}^{2} - {y}^{2} = 91[/tex]

can be further rewritten as using algebraic Identity,

[tex]\rm :\longmapsto\:(x + y)(x - y) = 91[/tex]

[tex]\rm :\longmapsto\:13(x - y) = 91[/tex]

[tex]\red{ \bigg\{  \sf \: \because \: using \: equation \: (1) \bigg\}}[/tex]

[tex]\rm\implies \:\boxed{\tt{ x - y = 7}} - - - - (2)[/tex]

On adding equation (1) and (2), we get

[tex]\rm :\longmapsto\:2x = 13 + 7[/tex]

[tex]\rm :\longmapsto\:2x = 20[/tex]

[tex]\rm\implies \:\boxed{ \: \bf \: \: x \: = \: 10 \:cm \: \: }[/tex]

On substituting the value of x in equation (1), we have

[tex]\rm :\longmapsto\:10 + y = 13[/tex]

[tex]\rm :\longmapsto\:y = 13 - 10[/tex]

[tex]\rm\implies \:\boxed{ \: \bf \: \: y \: = \: 3 \:cm \: \: }[/tex]

So,

[tex]\rm\implies \:\boxed{Side_{[square \: EFGH]} = y \: = 3 \: cm}[/tex]

and

[tex]\rm\implies \:\boxed{Side_{[square \: ABCD]} = x \: = 10 \: cm}[/tex]

Also,

[tex]\rm :\longmapsto\:\boxed{Area_{[square \: ABCD]} = {10}^{2} = 100 \: {cm}^{2} }[/tex]

[tex]\rm :\longmapsto\:\boxed{Area_{[squareEFGH] }\: = {3}^{2} = 9 \: {cm}^{2} }[/tex]

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬

[tex]\begin{gathered}\begin{gathered}\boxed{\begin {array}{cc}\\ \dag\quad \Large\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Breadth\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}d\sqrt {4a^2-d^2}\\ \\ \star\sf Parallelogram =Breadth\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {array}}\end{gathered}\end{gathered}[/tex]

Answer:

D.

Step-by-step explanation:

Answer:

[tex]\frac{35}{2}[/tex] - [tex]7n[/tex]

Step-by-step explanation:

7/1 − 3( 7/3n − 7/2 )

Anything divided by one gives itself.

7 - 3 ( [tex]\frac{7}{3}n - \frac{7}{2}[/tex])

Use the distributive property to multiply −3 by  [tex]\frac{7}{3}n - \frac{7}{2}[/tex])

7 - 3 × ([tex]\frac{7}{3}[/tex][tex]n[/tex] - 3 (-[tex]\frac{7}{2}[/tex])

Multiply −3 times [tex]\frac{7}{3}[/tex]

7 - 7n - 3 (-[tex]\frac{7}{2}[/tex])

Express -3 (-[tex]\frac{7}{2}[/tex]) as a single fraction.

7 - 7n + [tex]\frac{-3(-7)}{2}[/tex]

Multiply −3 and −7 to get 21.

7 - 7n + [tex]\frac{21}{2}[/tex]

Convert 7 to fraction [tex]\frac{14}{2}[/tex]

[tex]\frac{14}{2}[/tex] - 7n +  [tex]\frac{21}{2}[/tex]

Since [tex]\frac{14}{2}[/tex] and [tex]\frac{21}{2}[/tex] have the same denominator, add them by adding their numerators.

[tex]\frac{14 + 21}{2} - 7n[/tex]

Add 14 and 21 to get 35.

[tex]\frac{35}{2} - 7n[/tex]

Answer:

Identifying the problem

Answer:

son: 12 daniel: 32

Step-by-step explanation:

daniel is 26 in 6 years he would be 32

son is 3x younger in 6 years so 32 divided by 3 would be 10.6 (11 if estimated)

Answer:

Step-by-step explanation:

27^x = 9÷(3^x)

So (3^3)^x = (3^2)÷(3^x)

So 3^3x = 3^(2-x)

Comparing powers on both sides,

3x = 2 - x

So, 4x = 2

So, x = 1/2

Given ( 27 ) ^ x = 9 / 3 ^x

⇒ ( 3 × 3 × 3 )^x = ( 3 × 3 ) / 3^x

⇒ ( 3 ³ )^x = 3² / 3^x

⇒  3 ^ 3x × 3^x = 3²            [ since  ( a ^m)^n = a ^mn ]

⇒ 3^ (3x +x) = 3²                [ since a^m × a^n = a ^m+n ]

⇒ 3^4x = 3²

⇒4x = 2                      [ since  If a ^m = a ^n then m = n ]

⇒ x = 2 / 4

 ∴ x = 1 / 2

I hope this helps you.

Answer:

C.

Step-by-step explanation:

She needs 160 for a free ticket and get 85 for signing up.

Every time she goes, she get 12.5 points

160=85+12.5v

The answer would be C

Reason:

We eliminate B and D as they do not have a total of 160 points.

We are now left with A and C

A shows that she would need to earn 85 points three times which is incorrect as she receives 85 points 1 time after signing up. Therefore we eliminate A.

We are now left with C

C shows that the total amount of points she would need to earn a free ticket are 160 points.

It also shows that she would receive 85 points 1 time after signing up.

It also shows that the remaining points she would get are from strictly visiting the movie theater.

C is your answer

Answer:

y-0.22%=x+0.06%

Step-by-step explanation:

Answer:

N.ice I.ndividual G.iven G.ood A.spects S.eriously was in paris

Step-by-step explanation:

Answer:

the French

Step-by-step explanation:

Answer:

1.  16 ft

[tex]\sf 2.\quad \dfrac{29}{99}[/tex]

Step-by-step explanation:

Formula

Area of a square = s²  (where s is the side length)

Given:

Substitute the given area into the formula and solve for s:

[tex]\sf \implies 256=s^2[/tex]

[tex]\sf \implies \sqrt{256}=\sqrt{s^2}[/tex]

[tex]\sf \implies s=\pm 16[/tex]

As distance is positive, the length of one side of Keisha's kitchen is 16 ft.

Converting a recurring decimal to a fraction

Let x equal the recurring decimal:

[tex]\implies \sf x=0.292929...[/tex]

Create another number with recurring 29s by multiplying the above by 100:

[tex]\implies \sf 100x=29.292929...[/tex]

To solve these two equations and write x as a fraction, subtract the first equation from the second to remove all the recurring digits after the decimal point:

[tex]\begin{array}{r r c l}& \sf 100x &= &\sf 29.292929...\\- & \sf x&=& \sf \phantom{..}0.292929...\\\cline{1-4} & \sf 99x&=& \sf29\\\cline{1-4}\end{array}[/tex]

Therefore:

[tex]\implies \sf 99x=29[/tex]

[tex]\implies \sf x=\dfrac{29}{99}[/tex]

Therefore:

[tex]\sf \implies 0.\overline{29}=\dfrac{29}{99}[/tex]

Learn more about converting recurring decimals to fractions here:

https://brainly.com/question/27788661

https://brainly.com/question/27643441

Answer:

d 2.5

Step-by-step explanation:

|-2|-1/-2

2+1/2

2.5