Answer:
Yes it is matter
Explanation:
In physics, usually the word "electricity" isn't really used. "Electric current" is more common, and is defined as the flow of charges, where the charges are held by particles (electrons). Electrons have mass, so they are definitely matter.
g the space in between two glass sheets has a volume of 0.025 m3. If the temperature of the gas is 290 K, what is the rms speed of the gas atoms
Complete Question
Argon gas (a monatomic gas) is sometimes used to insulate a double-pane window for purposes of insulation. In a particular window, the space in between two glass sheets has a volume of [tex]0.025 \ m^3[/tex]. If the temperature of the gas is 290 K. what is the rms speed of the gas atoms? The atomic mass of Argon is 39.9 u.(l u= 1.66x10-27 kg) Enter your answer in m/s
Answer:
The value is [tex]V_{rms} = 425.75 \ m/s[/tex]
Explanation:
From the question we are told that
The volume of the space in between the two glass sheet is [tex]a = 0.025 \ m^3[/tex]
The temperature of the gas is [tex]T = 290 \ K[/tex]
The atomic mass of Argon is [tex]m = 39.9 \ u = 39.9 * 1.66 *10^{-27} = 6.623 *10^{-26} \ kg[/tex]
Generally the root mean square velocity is mathematically represented as
[tex]V_{rms} = \sqrt{\frac{3 K T}{ m } }[/tex]
Here K is the Boltzmann constant with value [tex]k = 1.38 *10^{-23} \ m^3 \cdot kg \cdot s^{-2} \cdot K^{-1}[/tex]
So
[tex]V_{rms} = \sqrt{\frac{3 * 1.38 *10^{-23} * 290 }{ 6.6234*10^{-26} } }[/tex]
=> [tex]V_{rms} = 425.75 \ m/s[/tex]
PLEASE HELP ME!!!1
Differentiate between the distance and displacement for an object that started at point A and traveled as shown to point B.
Distance: _____ units and Displace: _____ units to the left.
"Distance" here is the total distance traveled along the red path (see attached) from point A to point B. Just count how many how sides of each square in the grid are touched by the path. Then distance = 24 units.
"Displacement" is the net distance covered by moving from point A to point B, or the length of the green path. So displacement = 2 units to the right. Of course, your question seems to ask for the displacement in terms of units to the left, in which you could say -2 units to the left.
Discuss the relationship between size and wieght of an object and the amount
Which statements describe processes involved in the accretion of planetesimals and protoplanets
The statements that describe the processes involved in the accretion of planetesimals and protoplanets are :
II. Both processes involve nebular materials becoming solid particles.
IV. In both cases, masses of stuff are clumped together and gases are trapped.
Accretion basically involves the accumulation of particles into a massive object by gravitationally attracting more matter, mainly the gaseous matter, in an accretion disk.
A protoplanet is basically a large planetary embryo that has originated within a protoplanetary disc and which also has undergone internal melting to produce a differentiated interior.
Planetesimals are known to be small rock-type objects which are
formed by collisions with other objects present in the solar system.
Hence, the statements that describe the processes involved in the accretion of planetesimals and protoplanets are :
Both processes involve nebular materials becoming solid particles.In both cases, masses of stuff are clumped together and gases are trapped.Learn more about Planetesimals and Protoplanets here:
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The complete question is mentioned below:
Which statements describe processes involved in the accretion of planetesimals and protoplanets?
( I ) Both involve the melting of solid materials in the nebula.
( II ) Both involve the formation of solid particles from nebular materials.
( III ) Both involve the work of the gravitational push on nebular materials.
( IV ) Both involve the trapping of gases and the clumping of masses of matter.
( V ) Both involve the growing of gas grains with the addition of atoms and molecules.
At 3.00 m from a source that is emitting sound uniformly in all directions, the sound level (b) is 60.0 dB.
How many meters from the source would the sound level be one-fourth the sound level at 3.00 m?
Given that,
At 3.00 m from a source that is emitting sound uniformly in all directions, the sound level is 60.0 dB.
To find,
The distance from the source would the sound level be one-fourth the sound level at 3.00 m.
Solution,
The intensity from a source is inversely proportional to the distance.
Let I₁ = 60 dB, r₁ = 3 m, I₂ = 60/4 = 15 dB, r₂ =?
Using relation :
[tex]\dfrac{I_1}{I_2}=\dfrac{r_2^2}{r_1^2}\\\\r_2^2=\dfrac{I_1r_1^2}{I_2}\\\\r_2^2=\dfrac{60\times (3)^2}{15}\\\\r_2=6\ m[/tex]
So, at a distance of 6 m the sound level will be one fourth of the sound level at 3 m.
You push a permanent magnet with its north pole away from you toward a loop of conducting wire in front of you. Just before the north pole enters the loop, the current in the loop is: zero clockwise counterclockwise
Answer:
Counter clockwise
Explanation:
A futuristic train rushes past you at an incredible, relativistic speed such that it appears to only be 80% as long as you know it to be. At what speed is that train traveling from the point of view of your reference frame
Answer:
v = 0.6c = 1.8 x 10⁸ m/s
Explanation:
From Einstein's theory of relativity, we know that the length of an object contracts while traveling at a speed relative to speed of light. The contraction is according to following equation:
[tex]L = L_{0}\sqrt{1 - \frac{v^2}{c^2}}[/tex]
where,
L = Relative Length
L₀ = Rest Length
According to given:
L = 0.8 L₀
c = speed of light = 3 x 10⁸ m/s
v = relative speed of train = ?
Therefore,
[tex]0.8L_{0} = L_{0}\sqrt{1 - \frac{v^2}{c^2} } \\\\0.8 = \sqrt{1 - \frac{v^2}{c^2} }[/tex]
squaring on both sides:
[tex]0.64 = 1-\frac{v^2}{c^2}\\\\\frac{v^2}{c^2} = 1-0.64 \\v^2= 0.36c^2\\[/tex]
taking square root on both sides:
v = 0.6c = 1.8 x 10⁸ m/s
Which statement is NOT part of the Cell theory? All cells come from other cells. All cells come from other cells., All organisms are composed of cells. All organisms are composed of cells., Cells are the basic living units of organization in all organisms. Cells are the basic living units of organization in all organisms., EndFragment, All the cells in an organism have exactly the same function
Answer:
All the cells in an organism have exactly the same function
Solenoid 2 has twice the radius and six times the number of turns per unit length as solenoid 1. The ratio of the magnetic field in the interior of 2 to that in the interior of 1 is: 1/3 1 2 4 6
Answer:
6
Explanation:
The magnetic field inside a solenoid is given by the following formula:
[tex]B = \mu_{0}nI[/tex]
where,
B = Magnetic Field Inside Solenoid
μ₀ = permittivity of free space
n = No. of turns per unit length
I = Current Passing through Solenoid
For Solenoid 1:
[tex]B_{1} = \mu_{0}n_{1}I ------------------- equation 1[/tex]
For Solenoid 2:
n₂ = 6n₁
Therefore,
[tex]B_{1} = \mu_{0}n_{2}I\\B_{1} = 6\mu_{0}n_{1}I ----------------- equation 2[/tex]
Diving equation 1 and equation 2:
[tex]\frac{B_{2}}{B_{1}} = \frac{6\mu_{0}nI}{\mu_{0}nI}\\\\\frac{B_{2}}{B_{1}} = 6[/tex]
Hence, the correct option is:
6
The ratio of the magnetic fields in interior 2 to interior 1 will be
[tex]\dfrac{B_2}{B_1} =\dfrac{6}{1}[/tex]
What will be the ratio of the magnetic fields?The formula for the magnetic fields inside the solenoid will be given:
[tex]B=\mu_onI[/tex]
here,
B = Magnetic Field Inside Solenoid
μ₀ = permittivity of free space
n = No. of turns per unit length
I = Current Passing through Solenoid
For the first Solenoid
[tex]B_1=\mu_on_1I[/tex]..................(1)
For the second solenoid
[tex]n_2=6n_1[/tex]
Now
[tex]B_2=\mu_on_2I[/tex]
[tex]B_2=\mu_o(6n_1)I[/tex]..................(2)
Diving equation 1 and equation 2:
[tex]\dfrac{B_2}{B_1} =\dfrac{\mu_o(6n_1)I}{\mu_on_2I}[/tex]
[tex]\dfrac{B_2}{B_1} =6[/tex]
Thus the ratio of the magnetic fields in interior 2 to interior 1 will be
[tex]\dfrac{B_2}{B_1} =\dfrac{6}{1}[/tex]
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An object undergoing simple harmonic motion completes one cycle of motion in 1.7 seconds. Determine the angular frequency (rad/s) of the motion.
Answer:
3.69 rad/s
Explanation:
From the question given above, the following data were obtained:
Period (T) = 1.7 s
Angular frequency (ω) =?
Thus, we can obtain the angular frequency (ω) by applying the following formula:
ω = 2π/T
Period (T) = 1.7 s
Pi (π) = 3.14
Angular frequency (ω) =?
ω = 2π/T
ω = 2 × 3.14 / 1.7
ω = 6.28 / 1.7
ω = 3.69 rad/s
Thus, the angular frequency of the motion is 3.69 rad/s
What is an induction?
Answer:
An induction is the process a new recruit goes through to be introduced to the company and their new role. ... Beyond the initial days, the induction programme continues for many months, so that the new employee can fully integrate into life in the company and settle into their role to become a valuable member of staff.
Explanation:
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You select a rental package that includes a car with an average consumption of 6.00 litersliters of fuel per 100 kmkm. Considering that in Europe the average fuel cost is 1.063 euros/litereuros/liter, how much (in US dollars) will you spend in fuel on your trip
Answer:
Cost = $ 7.72
Explanation:
Considering the trip of 100 km, the cost spent on the fuel during the trip can be calculated by the following formula:
[tex]Cost = Average Fuel Consumption\ x\ Unit Fuel Cost\ x\ Distance[/tex]
where,
Average Fuel Consumption = 6 liter/100 km
Unit Fuel Cost = (1.063 euros/liter)($ 1.21/1 euro) = $ 1.29/liter
Distance = 100 km
Therefore,
[tex]Cost = (6\ liter/100\ km)(\$\ 1.29/liter)(100\ km)\\[/tex]
Cost = $ 7.72
It takes light 4 hours and 10 minutes to travel from the sun to the Planet Neptune. How far is Neptune from the sun?
a. 1.2 × 10^8 km
b. 4.5 × 10^9 km
c. 12 × 10^8 km
d. 45 × 10^9 km
Answer:b) 4.5×10^9km
Explanation:use s= vt/1000 here, v= speed of light which is 3×10^8m/s
t= time in second
How much force is required to accelerate a 5 kg mass at 20 m/s^2
Hello!
[tex]\large\boxed{F = 100N}[/tex]
Use the equation F = m · a (Newton's Second Law) to solve. Substitute in the given values:
F = 5 · 20
F = 100N
A force of 16 N is applied to a 5 kg block that is at rest on a smooth, horizontal surface. What is the velocity of the
block at time t = 5 seconds?
Answer:
16m/s
Explanation:
Given the following data;
Force, F = 16N
Mass, m = 5kg
Time, t = 5 seconds.
First of all, we would find the acceleration of the object.
Force is given by the multiplication of mass and acceleration.
Mathematically, Force is given by the formula;
[tex] F = ma[/tex]
Where;
F represents force.m represents the mass of an object.a represents acceleration.Making acceleration (a) the subject, we have;
[tex]Acceleration, a = \frac{F}{m}[/tex]
Substituting into the equation;
[tex]Acceleration, a = \frac{16}{5}[/tex]
Acceleration, a = 3.2 m/s²
Now, to find velocity;
We would use the first equation of motion given by the formula;
[tex] V = U + at[/tex]
Where;
V is the final velocity. U is the initial velocity. a is the acceleration. t is the time measured in seconds.We know that acceleration due to gravity is 9.8m/s² and initial velocity (U) is 0 since the object is at rest.
Substituting into the equation, we have;
[tex] V = 0 + 3.2*5[/tex]
[tex] V = 0 + 16[/tex]
Velocity, V = 16m/s.
when a horse pulls a cart, the horse move forward due to?
Answer:
The horse moves due to kinetic energy and is walking balanced because of the gravitational energy
Explanation:
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A force F=9 N acting on a tooth is not in the direction of the tooth axis and runs at a distance L=1 mm from the axis. Find the torque on the tooth about point C
Answer:
τ = 0.009 Nm
Explanation:
The torque applied on the tooth can be given by the following formula:
[tex]\tau = Fd[/tex]
where,
τ = Torque on the tooth= ?
F = Force acting on tooth = 9 N
d = distance between force and tooth axis = 1 mm = 0.001 m
Therefore, using these values in the equation, we get:
[tex]\tau = (9\ N)(0.001\ m)[/tex]
τ = 0.009 Nm
As fuel is burned in an electrical generator, the chemical energy of the fuel is converted into thermal energy that is used to boil water. after the steam from the boiling water moves through the pipe, what sequence of energy transformation best describes what happens?
Answer choices:
A:mechanical ----> electrical ---> light
B: light ----> electrical----> mechanical
C: Electrical---> Mechanical----> light
D: Mechanical----> light ----> electrical
Answer: A
Explanation:
A bowling ball results in ______ friction compared to a sliding bowling ball.
A bowling ball results in kinetic friction compared to a sliding bowling ball.
What is the Conservation of momentum?According to Conservation of momentum, if a bowling ball hits some pins, the momentum that lost by the bowling ball is known to be equal to the momentum obtained by the pins.
The friction that is used in bowling is kinetic friction because the more oil that is placed down, the lower the friction that is found between the ball and that of the lane surface. The little friction, the stronger it is for the bowler to be able to send the ball in a curved path and thus the formula to find the kinetic friction is know to be : µk=F k/mg.
Therefore, A bowling ball results in kinetic friction compared to a sliding bowling ball.
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A 12 V battery applies a potential difference to three resistors in series. If the potential at point P is 0.0 V, the potential at point B is:
This question is incomplete, the complete question is on the image uploaded along this answer.
Answer:
the potential at point B is 5 V, Option d) is the correct answer
Explanation:
Given that;
from the image;
R = 3 + 4 + 5 = 12 Ω
so I = 12/12 = 1 A
Q = 0 + 12 = 12 V
now
VA - VQ = - I × 3 = -3 V
VA = VQ - 3 = 12 - 3 = 9 V
VB - VA = - I × 4Ω = - 4 V
⇒VB = VA - 4 = 9 V - 4 V = 5 V
Therefore the potential at point B is 5 V
Option d) is the correct answer
Some students are jumping rope which travels at a speed of 2 m/s. The distance from the top of the swing to the bottom is 2 m. What is the frequency l of the rope
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When a moving object reduces its speed, what happens to the object's acceleration in relation to its velocity?
Answer:
When speed reduces, acceleration decreases
Explanation:
From first equation of motion;
[tex]{ \tt{v = u + at}}[/tex]
When time is constant:
[tex]{ \tt{v = 0 + kt}} \\ { \tt{v = kt}} \\{ \tt{v \: \alpha \: \: a}}[/tex]
When speed is decreasing, velocity and acceleration are in opposite directions.
A penny is dropped from the top of the
Chrysler Building (320 m high). How fast
is it moving when it hits the ground?
Answer:
-79
Explanation:
because I know because that's what the answer is because it is -79 when it hits the ground
a waterwheel built in Hamah, Syria, has a radius of 20 m . If the tangential velocity at the wheels edge is 7.85 m/s , what is the centripetal acceleration of the wheel?
Answer:
3.08m/s²
Explanation:
Given parameters:
Radius = 20m
Tangential velocity = 7.85m/s
Unknown:
Centripetal acceleration = ?
Solution:
Centripetal acceleration is the acceleration of a body along a circular path.
it is mathematically given as;
a = [tex]\frac{v^{2} }{r}[/tex]
v is the tangential velocity
r is the radius
a = [tex]\frac{7.85^{2} }{20}[/tex] = 3.08m/s²
A car is traveling at a constant speed of 14. It tires have a diameter of 0.91
30.76/s is the angular speed of the car traveling at a constant speed of 14m/s and having a tire of diameter of 0.91m
The rate of change of angular displacement is known as Angular velocity . The unit of angular velocity is radians/second. The same formula describes both angular velocity and angular velocity. Angular velocity is a vector quantity that expresses both direction and magnitude, but angular velocity expresses only magnitude. Angular velocity (ω) is a scalar measure of rotational speed. The angular distance traveled in one full rotation is 2π and the time is duration (T).
here from the given data that is a constant speed of 14. It tires have a diameter of 0.91
ω=θ/t
V=2πr/t
=14m/s
ω=v/r
=14/0.45
=30.76
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the question you provided was incomplete and I have added the incomplete part that is to find the angular speed of the given data.
en the current in one coil changes at a rate of 3.2 A/s, an emf of 5.7 is induced in a second, nearby coil. What is the magnitude of the mutual inductance of the two coils
Given that,
The rate of change of current = 3.2 A/s
Emf induced in the coil = 5.7 V
To find,
The magnitude of the mutual inductance of the two coils.
Solution,
The mutual inductance between the coils is given by the formula as follows :
[tex]\epsilon=M\dfrac{dI}{dt}\\\\M=\dfrac{\epsilon}{\dfrac{dI}{dt}}\\\\M=\dfrac{5.7}{3.2}\\\\=1.78\ H[/tex]
So, the mutual inductance of the two coils is 1.78 H.
Which of the following will have the least effect on the motion of a ball? A the mass of the ball B the direction of the force C the strength of the force D the weather conditions
Answer:
letter B..
Explanation:
because pinililit you direction pina force nyang itulak
The ball encounters resistance as it travels through the air. Drag is the term for the air's resistance to the ball. Drag slows down the baseball because it is applied against the direction of the ball's flight. Thus, option B is correct.
What the least effect on the motion of a ball?When two objects rub against one another, a force known as friction is applied. Friction force often works to prevent an object from moving. For instance, friction between a ball and carpet when rolling a ball across it causes the ball to move more slowly.
A baseball in flight is impacted by three forces. The three forces are lift, drag, and weight. Actually, the aerodynamic force exerted on the ball is made up of two parts: lift and drag. Lift acts perpendicular to the motion, and drag acts in the direction opposite to the motion.
Therefore, the direction of the force the least effect on the motion of a ball.
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Does Light Transmission in oxygen ?
A stretched string is 1.95 m long and has a mass of 19.1 g. When the string oscillates at 440 Hz, which is the frequency of the standard A pitch, transverse waves with a wavelength of 16.7 cm travel along the string. Calculate the tension T in the string.
T= ________ N
Answer:
The tension in the string is 52.89 N.
Explanation:
Given;
mass of the string, m = 19.1 g = 0.0191 kg
length of the string, L = 1.95 m
⇒mass per unit length, μ = 0.0191 / 1.95 = 0.009795 kg/m
Also Given;
frequency of the string, F = 440 Hz
wavelength of the sound wave, λ = 16.7 cm = 0.167 m
⇒the speed of the wave, v = Fλ = 440 x 0.167 = 73.48 m/s
The tension T in the string is calculated as;
[tex]v = \sqrt{\frac{T}{\mu} } \\\\v^2 = \frac{T}{\mu}\\\\T = v^2 \mu\\\\T = (73.48)^2 (0.009795)\\\\T = 52.89 \ N[/tex]
Therefore, the tension in the string is 52.89 N.
1. An electrical current is flowing through a circuit at a rate of 25 m/s and then decelerates
when it passes through the resistor and reaches a velocity of 13 m/s within 5 seconds.
What is the electrical current's acceleration?
The acceleration of the electrical current is -2.4 m/s².
What is acceleration?Acceleration can be defined as the rate of change of velocity.
To calculate the acceleration of the electric current, we use the formula below.
Formula:
a = (v-u)/t........... Equation 1Where:
a = Acceleration of the currentv = Fianl velocityu = Initial velocityt = TimeFrom the question,
Given:
v = 13 m/su = 25 m/st = 5 secondsSubstitute these values into equation 1
a = (13-25)/5a = -12/5a = -2.4 m/s²Hence, the acceleration of the electrical current is -2.4 m/s².
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