In which quadrant or on which axis do each of the points (2, 3 ), ( 5, -6 ), ( 2,0 ) , ( -5, 2 ), (-2,-4), (0,-2).

Answer:

greater than

Step-by-step explanation:

An exponential growth function has a base that is__greater than__one.

If the base is less than one, it will be a decay function.

Note: the above assumes an exponent greater than one as well.

Range = max - min

Visually the min and max are the leftmost and right most points on the whiskers. This is assuming we don't have outliers in either direction. The range represents the total width of the box and whisker plot. For movie B, it is wider, so therefore it has a larger range of ages.

We could compute the ranges numerically and compare to see which is bigger, or we could align one endpoint (say the right endpoints) to see that movie B has a wider range.

Answer:

The fact that shows that p+q+r=1 is at most 2/3 is well explained from what we have below.

Step-by-step explanation:

Given that:

The maximum of function P = 2pq+2pr+2rq is at most 2/3.

where ;

p+q+r=1

From  p+q+r=1

Let make r the subject ; then r = 1 - p - q

If we replace the value for r into the given function; we have:

P = 2pq+2pr+2rq

P = 2pq+2p(1 - p - q)+2(1 - p - q)q

P = 2pq + 2p - 2p² - 2pq + 2q -2pq -2q²

P = 2p - 2p² + 2q -2pq -2q²

By applying the standard method for determining critical points we obtain:

[tex]P_p[/tex] = -4p - 2q + 2 = 0

[tex]P_q[/tex] = -4q - 2p + 2 = 0

Divide all through by 2

[tex]P_p[/tex] = -2p - q + 1 = 0

[tex]P_q[/tex] = -2q - p + 1 = 0

[tex]P_p[/tex] = -2p - q  = - 1

[tex]P_q[/tex] = -2q - p  = - 1

Multiplying both sides by - ; we have:

[tex]P_p[/tex] = 2p + q  =  1   ----- (1)

[tex]P_q[/tex] = 2q + p  =  1    ------(2)

From equation (1) ; let make q the subject ; then

2p + q = 1

q = 1 - 2p

Now; let us replace the value of q = 1-2p into equation (2) , we have:

2q + p  =  1  

2(1-2p)+ p = 1

2 - 4p+p = 1

2 - 3p = 1

3p = 2-1

p = 1/3

Replacing the value of p = 1/3 into equation (1) ; we have :

2p + q  =  1  

2(1/3) + q = 1

2/3 + q = 1

q = 1 -2/3

q = 1/3

Taking the second derivative D; we have

[tex]D = P_{pp}P_{qq}-p^2_{pq}[/tex]

D = -4 × -4 - (2²)

D = 16 - 4

D = 12

This implies that the given function has a minimum or maximum at its critical point for which  12 > 0

Therefore , the value for function p = q = r  since  p, q, and r are the proportions of A, B, and O in the  population.

Hence r = 1/3

P=2pq+2pr+2rq

P = 2(1/3)(1/3) + 2(1/3)(1/3) + 2(1/3)(1/3)

P = 6/9

P = 2/3

Answer:

9

Step-by-step explanation:

We can use the distance formula

d = sqrt (   ( y2-y1)^2 + ( x2-x1) ^2)

d = sqrt (   ( 4- -3)^2 + ( -4 -2) ^2)

   = sqrt (  ( 7^2  + ( -6)^2)

   = sqrt( 49+ 36)

   = sqrt(85)

      9.219544457

Rounding to the nearest whole number

 = 9

Answer:

g(x)=6 when x=-4

g(x)=-2 when x=3

Answer:

g(x) = 6 when x=-4

g(x)= -2 x=3

Step-by-step explanation:

plz check the graph of g(x) ,

when x= -4, the value of y = 6

when x=3, the value of y =-2

Answer:

0.142

Step-by-step explanation:

From the question, we identify the following parameters;

n = 49

p = 82% = 82/100 = 0.82

alpha, α = 1-0.99 = 0.01

Zα/2 = Z_0.005 = 2.575

margin of error = Zα/2 * √( p(1-p)/n)

Margin of error = 2.575 * √(0.82)(1-0.82)/49

Margin of error =0.1416005 which is approximately 0.142

Answer:

2.25 x 10

Step-by-step explanation:

In the above question, we were given :

The weight of the Elephant = 9 × 10³ pounds

The weight of the African Lion = 4 × 10² pounds

We would compare both weights to determine which size is bigger

Weight of Elephant : Weight of Lion

9× 10³ : 4 × 10²

= 9 × 10³/4 × 10²

= 2.25 × 10¹

= 2.25 × 10

The weight of the elephant is 2.25 × 10 times greater than the weight of the lion.

Answer:

[tex]y > \frac{2x}{3} + 1[/tex]

Step-by-step explanation:

Given:

The graph in the attachment where the coordinates are (3,3) and (-3,-1)

Required:

Which inequality represent the graph

The first step is to determine the slope of the graph

[tex]m = \frac{y_2 - y_1}{x_2 - x_1}[/tex]

Where m represents the slope, [tex](x_1, y_1) = (3,3)[/tex] and [tex](x_2, y_2) = (-3,-1)[/tex]

[tex]m = \frac{-1 - 3}{-3 - 3}[/tex]

[tex]m = \frac{-4}{-6}[/tex]

Simplify to lowest term

[tex]m = \frac{2}{3}[/tex]

Next is to determine the equation of the line using the slope formula

[tex]m = \frac{y - y_1}{x - x_1}[/tex], [tex](x_1, y_1) = (3,3)[/tex]  and [tex]m = \frac{2}{3}[/tex]

[tex]\frac{2}{3} = \frac{y - 3}{x - 3}[/tex]

Cross multiply

[tex]2 * (x - 3) = 3 * (y - 3)[/tex]

Open both brackets

[tex]2 x - 6 = 3y -9[/tex]

Collect like terms

[tex]2 x - 6 +9= 3y[/tex]

[tex]2 x+3= 3y[/tex]

Divide through by 3

[tex]\frac{2x}{3} + \frac{3}{3} = \frac{3y}{3}[/tex]

[tex]\frac{2x}{3} + 1 = y[/tex]

Reorder

[tex]y = \frac{2x}{3} + 1[/tex]

Next is to determine the inequality sign

The inequality becomes

[tex]y > \frac{2x}{3} + 1[/tex]

Answer:

the probability that the first groupmate you meet has studied some statistics is 0.45

Step-by-step explanation:

From the information given :

A professor divided the students in her business class into three groups

Let consider then to be :

Group            Statistics Class

A                    Never taken a statistics class

B                    Taken one statistics class

C                     Taken two or more statistics class.

If 55% of the students have never taken a statistics class,

Then ;

P(A) = 0.55

25% have taken only one semester of a statistics class

Then P(B) = 0.25

and the rest have taken two or more semesters of statistics

Then P(C) = 1 - 0.55 -0.25

P(C) = 1 - 0.80

P(C) = 0.20

The objective is to determine the probability that the first groupmate you meet has studied some statistics

The probability of the first groupmate you meet has studied some statistics = 1 - P(never taken a statistics course)

Let the  probability of the first groupmate you meet that  has studied some statistics be P(D)

Then P(D) = 1 -  P(A)

P(D) = 1 - 0.55

P(D) = 0.45

the probability that the first groupmate you meet has studied some statistics is 0.45

Answer:

Step-by-step explanation:

identitiy property

Answer:

(f-g)(x)= -x-4

(f.g)(x)= 2x^2 -2x-4

(f+g)(-1) = 3(-1) = -3

Step-by-step explanation:

Hi, to answer this question we have to solve the expressions:

(f-g)(x) =  x-2 -(2x+2)

(f-g)(x)= x-2 -2x-2

(f-g)(x) = -2x+x-2-2

(f-g)(x)= -x-4

(f.g)(x) =  x-2 (2x+2)

(f.g)(x)= 2x^2 +2x-4x-4

(f.g)(x)= 2x^2 -2x-4

(f+g)(x)= x-2 +2x+2

(f+g)(x) = x+2x-2+2

(f+g)(x)= 3x

(f+g)(-1) = 3(-1) = -3

Feel free to ask for more if needed or if you did not understand something.

Answer:

work is shown and pictured

Answer:

The answer is C

Step-by-step explanation:

Answer:

0.2

Step-by-step explanation:

it works out to be 0.2 as a decimal and 20% as a percentage.

Answer:

.2

Step-by-step explanation:

Answer:

It is a trapezoid because it has exactly one pair of opposite sides that is parallel.

Step-by-step explanation:

D

dont worry its right

happy learning

D. The line is perpendicular to the plane determined by the two lines.

Remember how you get to 3D space?

You take one axis called x and perpendicularly intersect it with y axis and you get a 2D plane. Now take a 2D plane and perpendicularly intersect it with an axis z and you get 3D euclidean space.

Hope this helps.

Answer:

3x+7=10x+17

Step-by-step explanation:

1.9

10x

27x

Answers:

Equation is  3x+7 + 10x+17 = 180 (there are infinitely many other ways to write the equation)

x = 12

Angles are 43 and 137

==========================================================

Explanation:

The horizontal lines are parallel, so the same side interior angles marked are supplementary. The angles add to 180

(3x+7) + (10x+17) = 180 is the equation, or one variation of such

13x+24 = 180

13x = 180-24

13x = 156

x = 156/13

x = 12 is the value of x

Use this x value to find the measure of each angle

3x+7 = 3*12+7 = 43

10x+17 = 10*12+17 = 137

The two angles are 43 and 137 degrees

Note how 43 and 137 add to 180.

Answer:

For sample size n = 39 ; P(X < 31.6) = 0.9756

For sample size n = 76 ; P(X < 31.6) = 0.9970

Step-by-step explanation:

Given that:

population mean μ = 31

standard deviation σ = 1.9

sample mean  [tex]\overline X[/tex] = 31.6

Sample size n                 Probability

39

76

The probabilities that the sample mean is less than 31.6 for both sample size can be computed as  follows:

For sample size n = 39

[tex]P(X < 31.6) = P(\dfrac{\overline X - \mu}{\dfrac{\sigma }{\sqrt{n}}}< \dfrac{\overline X - \mu}{\dfrac{\sigma }{\sqrt{n}}})[/tex]

[tex]P(X < 31.6) = P(\dfrac{31.6 - \mu}{\dfrac{\sigma }{\sqrt{n}}}< \dfrac{31.6 - 31}{\dfrac{1.9 }{\sqrt{39}}})[/tex]

[tex]P(X < 31.6) = P(Z< \dfrac{31.6 - 31}{\dfrac{1.9 }{\sqrt{39}}})[/tex]

[tex]P(X < 31.6) = P(Z< \dfrac{0.6}{\dfrac{1.9 }{6.245}})[/tex]

[tex]P(X < 31.6) = P(Z< 1.972)[/tex]

From standard normal  tables

P(X < 31.6) = 0.9756

For sample size n = 76

[tex]P(X < 31.6) = P(\dfrac{\overline X - \mu}{\dfrac{\sigma }{\sqrt{n}}}< \dfrac{\overline X - \mu}{\dfrac{\sigma }{\sqrt{n}}})[/tex]

[tex]P(X < 31.6) = P(\dfrac{31.6 - \mu}{\dfrac{\sigma }{\sqrt{n}}}< \dfrac{31.6 - 31}{\dfrac{1.9 }{\sqrt{76}}})[/tex]

[tex]P(X < 31.6) = P(Z< \dfrac{31.6 - 31}{\dfrac{1.9 }{\sqrt{76}}})[/tex]

[tex]P(X < 31.6) = P(Z< \dfrac{0.6}{\dfrac{1.9 }{8.718}})[/tex]

[tex]P(X < 31.6) = P(Z< 2.75)[/tex]

From standard normal  tables

P(X < 31.6) = 0.9970

Step-by-step explanation:

To find the area of the circle we must first find the radius using the formula

radius = diameter / 2

From the question

diameter = 21 ft

The radius is

21/2 = 10.5 ft

Area of a circle = πr²

where r is the radius

Area = π(10.5)²

= 110.25π

Circumference of a circle = πd

where d is the diameter

Circumference = π(21)

Hope this helps you

Answer:

[tex]\huge\boxed{Answer\hookleftarrow}[/tex]

Given,

Diameter of the ⭕ (d) = 21 ft

So, radius of the ⭕ (r) = ?

[tex]r = \frac{d}{2} \\ r = \frac{21}{2} \\ r = 10.5 \: \: ft[/tex]

[tex]\boxed{Radius \ = \ 10.5 \ ft}[/tex]

____________________

a) Find the area of the ⭕.

[tex]\boxed{Area \ (a) \ = \ πr^{2}}[/tex]

[tex]a = \pi \: r ^{2} \\ a = \pi(10.5) {}^{2} \\ a = 110.25 \: \pi \\ a = 110.25 × 3.14 \\ a = 346.18 \ ft^{2}[/tex]

[tex]\boxed{Area \ = \ 346.18 \ ft^{2}}[/tex]

____________________

b) Find the circumference of the ⭕.

[tex]\boxed{Circumference \ (c) \ = \ \pi \:d}[/tex]

[tex]c = \pi \: d \\ c = \pi(21) \\ c = 21\pi \\ c = 21 × 3.14 \\ c = 65.94 \ ft[/tex]

[tex]\boxed{Circumference \ = \ 65.94 \ ft}[/tex]

____________________

Value of [tex]\pi [/tex]is taken as 3.14

____________________

ʰᵒᵖᵉ ⁱᵗ ʰᵉˡᵖˢ

╭═══════ღ❦ღ══╮

[tex] ღRainbowSalt2^{2}2^{2} [/tex]

╰══ღ❦ღ═══════╯

Answer:

Arc BD is 6.1 degrees

Step-by-step explanation:

So if 5.7 is in miles, the observer is 30096 feet above sea level, cruising height.

Solution.

Segment BC and DC are tangent to the circle,

so angles CBA and CDA are 90 degrees, hence

Triangles CBA and CDA are right triangles,

with

AC = 4005.7 miles

cos CAB = AB/AC = 4000/4005.7 = 0.9985770

angle BCA = arc cos(0.9985770) = 3.057 degrees

Arc BD = central angle BAD = 2*angle BCA = 6.114 degrees

Answer:

Step-by-step explanation:

i really just need points on my thingy so eh bye

Answer:

The answer is C.

Step-by-step explanation:

The formula to find equation is y - y1 = m(x - x1).

Let (x1,y1) be (6,2) and m is -5/7.

So the equation is,

y - 2 = -5/7(x - 6)

Answer:

b    y = 9sin(36)

Step-by-step explanation:

sin A = opp/hyp

for the 36-deg angle, opp = y, and hyp = 9.

sin 36 = opp/hyp

sin 36 = y/9

y = 9 * sin 36

Answer: b   y = 9sin(36)

x = 65° and y = 77.5°.

The triangle with the 50 degree angle and x, is an isosceles triangle. That means that the other unlabeled angle is also equal to x degrees.

x + x + 50 = 180

2x + 50 = 180

2x = 130

x = 65°.

Since x = 65 degrees, and the two angles make a 90 degree angle, the other unlabeled angle will be 90 - 65 = 25 degrees.

Since the other triangle is also isosceles, that triangle has two angles that measure y degrees and one angle measuring 25 degrees.

y + y + 25 = 180

2y + 25 = 180

2y = 155

y = 77.5°.

Answer:

x= 20      x =-5

Step-by-step explanation:

x^2 – 15x – 100 = 0.

What two numbers multiply to -100 and add to -15

-20 * 5 = -100

-20 +5 = -15

(x-20) (x+5) =0

Using the zero product property

x-20 =0     x+5 = 0

x= 20      x =-5

x = 20 and x = -5

Step-by-step explanation:

x² – 15x – 100 = 0

First, find factors that multiply to get -100 and add to -15.

These factors are -20 and 5.

So we have (x - 20)(x + 5) = 0.

Now use the zero product property to get x - 20 = 0 or x + 5 = 0.

Solving from here, we get x = 20 or x = -5.

Answer:

3 3/4

Step-by-step explanation:

(4x+3)(x-8)+(x-1)(4x+3)=0

Factor out 4x+3

(4x+3)( x-8+x-1) =0

Combine terms

(4x+3) ( 2x-9) =0

Using the zero product property

4x+3 = 0    2x-9 =0

4x=-3         2x = 9

x = -3/4       x = 9/2

Sum the solutions

-3/4 + 9/2

-3/4 + 18/4

15/4

3 3/4

Answer:

x=6 and x=5.1

Step-by-step explanation:

Answer: $8

Step-by-step explanation: $120+10%=$132. $140-$132=$8.

Answer: $466

Step-by-step explanation:

Answer:

b.$466

Step-by-step explanation:

Answer:

Step-by-step explanation:

We will start with the angle that measures 57 degrees. This angle is supplementary to the one next to it coming off the straight line. 180 - 57 = 123.

The rule for quadrilaterals is that same side angles are supplementary, so the angle next to the 123-degree angle (to the immediate left of that angle 123) is 57. THAT 57-degree angle is supplementary to angle b, so angle b = 180 - 57 which is 123. So C is your answer.

Answer:

do you think you can send me the work for the program

Step-by-step explanation:

i got 1 day left and im not close to finishing it please help me out please respond with any way to contact you thanks

Answer:

y+0

As y=0 represent x-axis whose slope is 0 and intersects y-axis at the origin.

Answer:

16.4

Step-by-step explanation:

The interquartile range is the difference between the upper and lower quartiles.

Given the five figure summary, then

upper quartile = 28.8

lower quartile = 12.4

interquartile range = 28.8 - 12.4 = 16.4

The Interquartile range is 16.4.

When values are ranked from lowest to highest, the Interquartile range designates the middle 50% of those values.

Find the median (middle value) of the bottom half and upper half of the data before calculating the interquartile range (IQR). Quartile 1 (Q1) and Quartile 3 are these values (Q3).

The interquartile range represents the variation between Q3 and Q1.

The interquartile range is calculated as follows:

The upper quartile is 28.8

The lower quartile is 12.4

The interquartile range is,

= 28.8 - 12.4

= 16.4

The value of the interquartile range is 16.4.

To know more about the Interquartile range

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