In the following figure, if AB ǁ CD, then find the measure of PCD and CPD.​

Answer:

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Answer:

112.5 J

Explanation:

I calculated it by K/G BY M/S TO POTENTIAL ENERGY.

Given values are:

The change in Potential energy is:

→ [tex]\Delta PE = mgh[/tex]

By substituting the values, we get

            [tex]= 1.0\times 9.8\times 15[/tex]

            [tex]= 147 \ J[/tex]

Thus the above response is correct.  

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Answer:

a) [tex]F_{x} = 58.2 N[/tex]

[tex] F_{y} = 48.9 N [/tex]

b) a = 1.5 m/s²

Explanation:

a) The horizontal and vertical components of Emily's force can be found knowing the angle and the exerted force.

Since the handle is inclined at 40.0° below the horizontal we have:

[tex] F_{x} = |F|*cos(\theta) = 76.0 N*cos(40) = 58.2 N [/tex]

[tex] F_{y} = |F|*sin(\theta) = 76.0 N*sin(40) = 48.9 N [/tex]

b) The acceleration of the car can be calculated as follows:

[tex] F_{x} = ma [/tex]        

We used the horizontal component of the force because the cart is moving in that direction.

[tex] a = \frac{F_{x}}{m} = \frac{58.2 N}{38.8 kg} = 1.5 m/s^{2} [/tex]

Hence, the acceleration of the car is 1.5 m/s².    

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1) The longitudinal waves move in parallel direction to the source of vibration. The transverse waves move in perpendicular direction to the source of vibration . They are similar in the sense that energy is transferred in the form of waves.

2) Reflection occurs when waves bounce from a surface back toward the source. Refraction is when waves are deflected when the waves go through a substance.

3) The Law of Conservation of Energy

states that energy can neither be created

nor destroyed, it can only be transferred or

changed from one form to another.

Answer:

25 N

If you’re doing ck-12

The object may be swung with maximum velocity of 7.07 m/s without breaking the string.

The centripetal force definition states that: The force applied to an item in curved motion that is pointed toward the axis of rotation or the centre of curvature is known as a centripetal force.

Newtons are used to measure centripetal force.

Given that:

mass of the object = 0.500 kg.

The length of the string = 1.00 m.

If the maximum speed of the object be v,

maximum centripetal force be = 0.5v²/1.0 N = v²/2 N.

As the maximum force the string can withstand without breaking is 25.0 N,

25.0 = v²/2

⇒ v = 5√2 m/s = 7.07 m/s.

Hence,   the object may be swung with maximum velocity of 7.07 m/s without breaking the string.

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Answer:

Work done = 1/2 × Ne

Explanation:

Given that if  a force of N stretches a spring m beyond its natural​ length, how much work does it take to stretch the spring m beyond its natural​ length

Using Hook's law

Force = N

Let the extension = e

Work done in stretching spring m beyond its natural length will be

Workdone = 1/2 × Ne

Or

From Hook law,

N = Ke

Work done = 1/2 × Ke^2

Answer:

1.791 MN

Explanation:

Thrust of the rocket can be found using the relation

T = v.dm/dt, where

T = thrust off the rocket

v = speed of the rocket, 9 km/s = 9000 m/s

dm/dt = rate at which fuel burns, 199 kg/s

Substituting the values into the formula, we have

T = 9000 * 199

T = 1791000 N

T = 1.791*10^6 N

Since 1 MN = 10^6, thus

T = 1.791 MN

The thrust of the rocket in units of MN is 1.71 Meganewton.

Given the following data:

Conversion:

Relative speed = 9 km/s to m/s = 9000 m/s

To determine the thrust of the rocket in units of MN:

Mathematically, the thrust of an object is given by this formula:

[tex]Thrust = V\frac{dm}{dt}[/tex]

Substituting the given parameters into the formula, we have;

[tex]Thrust = 9000 \times 199[/tex]

Thrust = 1,791,000 Newton

In units of MN:

1 MN = [tex]1 \times 10^6\;N[/tex]

Thrust = 1.71 MN

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Answer:

The time spent in air by the rock before it returns to the thrower is 4.5 s

Explanation:

Given;

initial velocity of the rock, u = 22 m/s

Neglecting air resistance, the time it takes the rock to go up equals the time it takes it to return to the thrower. This is also called time of flight.

The time to go up is calculated as;

v = u - gt

where;

v is the final velocity at the maximum height

0 = u - gt

gt = u

t = u / g

t = 22 / 9.8

t = 2.245 s

thus time to go up = 2.245 s

and time to return to the thrower = 2.245s

The total time spent in air by the rock before it returns to the thrower

 = 2.245 s + 2.245s

 = 4.5 s

Answer:

0 m/s^2

Explanation:

If you're driving at constant speed in the same direction, your acceleration is always 0 m/s^2. acceleration is a vector, so any change in speed or direction would result in acceleration.

Answer:

L/E =de/dl so dl is 10m de=4m E=5N

Explanation:

L=(de x E)/dl = 2N

so when load is < effort it is speed multiplayer

Answer:

Given = 55kg, 4.5 m

Unknown = Work done

Formula = (mg) × d

Solution = 2425.5 J

Answer = 2425.5 J

Explanation:

Formula we use,

→ W = (mg) × d

Then the value of work done is,

→ (55 × 9.8) × 4.5

→ 539 × 4.5

→ 2425.5 J

Hence, the work done is 2425.5 J.

Answer:

0.56 km/s

Explanation:

We will define a single system of units for measurement, for this case meters per second [m/s]. That is, we must convert the rest of units such as centimeters per second and kilometers per second to meters per second.

[tex]560[\frac{cm}{s}]*(\frac{1m}{100cm} )=5.6[m/s]\\0.56[\frac{km}{s}]*(\frac{1000m}{1km} )=560[m/s][/tex]

Therefore the speed of 0.56 [km/s] is the greatest of all

Answer:

c) Aeroplane

Explanation:

The aeroplane has the greatest mass than the other three objects, so it experiences the greatest gravitational force. Hence, the option (c) is the answer.

Answer:

Explanation:

The velocity of sound wave is expressed using the formula;

[tex]v = f \lambda[/tex] where

f is the frequency

[tex]\lambda\\[/tex] is the wavelength

Given

f = 1300Hz

v = 38m/s

Required

wavelength [tex]\lambda\\[/tex]

From the formula;

[tex]\lambda\\[/tex] = v/f

[tex]\lambda\\[/tex] = 38/1300

[tex]\lambda\\[/tex] = 0.0292m

Hence the required value of the wavelength is 0.0292m

The wavelength of a stationary listener is 0.029 m.

The given parameters;

The wavelength of a stationary listener is calculated as follows;

[tex]v = f\lambda[/tex]

where;

λ is the wavelength of the sound wave

The value of the wavelength is determined as;

[tex]\lambda = \frac{v}{f} \\\\\lambda = \frac{38}{1300} \\\\\lambda = 0.029 \ m[/tex]

Thus, the wavelength of a stationary listener is 0.029 m.

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Answer:

Humans can detect sounds in a frequency range from about 20 Hz.

Answer:

a spring scale

Explanation:

i think it is correct

Answer:

The heat absorbed in each cycle is 9,234.286 J

Explanation:

Given;

power output, P = 5 kW = 5,000 W

efficiency of the engine, e = 30 % = 0.3

thermal heat expelled, [tex]Q_c[/tex] = 6464 J

let the heat absorbed = [tex]Q_h[/tex]

The efficiency of the engine is given as;

[tex]e = \frac{W}{Q_h} = \frac{Q_h-Q_c}{Q_h} = \frac{Q_h}{Q_h} - \frac{Q_c}{Q_h} = 1-\frac{Q_c}{Q_h}\\\\e = 1-\frac{Q_c}{Q_h}\\\\0.3 = 1-\frac{Q_c}{Q_h}\\\\\frac{Q_c}{Q_h} = 1-0.3\\\\\frac{Q_c}{Q_h} = 0.7\\\\Q_h = \frac{Q_c}{0.7} \\\\Q_h = \frac{6464}{0.7} = 9,234.286 \ J.[/tex]

Therefore, the heat absorbed in each cycle is 9,234.286 J.

Answer:

The inertia of an object does not change as the objects velocity changes because the inertia will remain the same as long as the mass is the same.

:

Solution :

The expression for the intensity of light is given by :

[tex]$I=I_{max}\left(\frac{\sin \frac{\pi a \sin \theta}{\lambda}}{\frac{\pi a \sin \theta}{\lambda} }\right)^2$[/tex]

For a small angle, θ

sin θ = tan θ

        [tex]$=\frac{y}{L}$[/tex]

Therefore the above equation becomes,

[tex]$I=I_{max}\left(\frac{\sin \frac{\pi a y}{\lambda L}}{\frac{\pi a y}{\lambda L} }\right)^2 $[/tex]

The given data is

λ = 546.1 nm

L = distance between the slit and the screen = 140 cm

  = 1.40 m

a = width of the slit

  = [tex]$0.50 \times 10^{-3} \ m$[/tex]

Therefore,

[tex]$I=I_{max}\left(\frac{\sin \frac{\pi \times 0.50 \times 10^{-3} \times 4.10 \times 10^{-3}}{546.1 \times 10^{-9} \times 1.20}}{\frac{\pi \times 0.50 \times 10^{-3} \times 4.10 \times 10^{-3}}{546.1 \times 10^{-9} \times 1.20} }\right)^2 $[/tex]

  [tex]$=\left(\frac{0.170}{9.82}\right)^2$[/tex]

 [tex]$= 2.89 \times 10^{-4} \ I_{max}$[/tex]

Therefore the fractional intensity is   [tex]$\frac{I}{I_{max}}= 2.89 \times 10^{-4} $[/tex]

Answer:

It is a value that reading in the galvanometer must be multiplied with to get the ordinary unit

Explanation:

What is a galvanometer?

A galvanometer is an electromechanical instrument used for detecting and indicating an electric current.

A Number by which a certain function of the reading of a galvanometer must be multiplied to obtain the current value in ordinary units is a galvanometer constant

heat and thermal energy can be differentiated as is that thermal energy is not actually transferred. It is not moving, but remains part of the system's internal energy. Heat, on the other hand, is a passing energy. H. Energy transferred from a hotter system.

In summary, thermal energy is the energy hipster. As such, it cannot be converted into other types of energy. Only the difference in thermal energy can be converted/used to do work. Such processes are never 100% efficient. Every energy form that cannot be recovered.

Thermal energy transfer occurs in three ways: convection, conduction and radiation. When heat energy is transferred between adjacent molecules that are in contact with each other, it is called conduction

Thermal energy and temperature are closely related. However, temperature is the average kinetic energy of matter particles and thermal energy is the total kinetic energy of matter particles.

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Answer:

its it filled with energy

Answer:

The light slows down.

Explanation:

velocity of the train is same so acceleration of the train is zero.

Acceleration of an object is known as change in velocity of the object. For a given interval of time.

Distance travelled by the train in first second is, d₁ = 6m

Distance travelled by the train in the 2nd second is, d₂ = 6m

Distance traveled by the train in 3rd second, d₃ = 6m

Formula for the velocity of the train.

v= d/t

where v is velocity

d is distance travelled

t is time taken

For first second velocity is

v₁ = d₁/t₁

v1 = 6/1s = 6m/s

for 2nd second velocity is

v₂= d₂/t₂

v₂ = 6/1 = 6m/s

for 3rd second velocity is

v₃ = d₃/t₃

v₃ = 6/1 = 6m/s

here we saw that the speed of train remains constant for each interval of time. So change of velocity is zero.

velocity of the train is same so acceleration of the train is zero.

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Answer:

[tex]t = 0.55[/tex]

Explanation:

Given

[tex]Height, s = 1.5m[/tex]

[tex]Velocity, v = 70m/s[/tex]

Required

Determine the time to hit the ground

Using free fall formula:

[tex]S = \frac{1}{2}gt^2[/tex]

Take g as 9.8 and substitute value for S

[tex]1.5 = \frac{1}{2} * 9.8 * t^2[/tex]

[tex]1.5 = 4.9 * t^2[/tex]

Make t^2 the subject

[tex]t^2 = \frac{1.5}{4.9}[/tex]

[tex]t^2 = 0.30612244898[/tex]

Solve for t

[tex]t = \sqrt{0.30612244898[/tex]

[tex]t = 0.55[/tex] -- approximated

Answer:

3.33s

Explanation:

Given parameters:

Acceleration  = 15m/s²

Initial velocity  = 0m/s

Final velocity  = 50m/s

Unknown:

Time taken for the acceleration  = ?

Solution:

To solve this problem, we must understand that acceleration is the rate of change of velocity with time.

Mathematically;

           a  = [tex]\frac{v - u}{t}[/tex]  

a is the acceleration

v is the final velocity

u is the initial velocity

t is the time taken

     So;

          15  = [tex]\frac{50 - 0}{t}[/tex]  

           15t  = 50

              t  = 3.33s

Answer:

The frequencies the other string could have are 258.4 Hz and 261.6 Hz.

Explanation:

Given;

beat frequency, Fb = 1.60 Hz

frequency of the first string, F₁ = 260.00 Hz

frequency of the second string, F₂ = ?

Beat frequency is given as;

Fb = F₂ - F₁     or      Fb = F₁ - F₂

Fb + F₁ = F₂    or      F₂ = F₁ - Fb

1.6 + 260 = F₂   or   F₂ = 260 - 1.6

261.6 Hz = F₂  or   F₂ = 258.4 Hz

Therefore, the frequencies the other string could have are 258.4 Hz and 261.6 Hz.

Answer:

The image formed by a convex mirror will always have its smaller than the size of the object no matter what the position of the object.

Explanation:

The image formed by a convex mirror will always have its smaller than the size of the object no matter what the position of the object.

Also notice that convex mirror always makes virtual images.

Another feature of the convex mirror is that an upright image is always formed by the convex mirror.

An important mirror formula to remember which is applicable for both convex and mirrors

Here:

'u' is an object which gets placed in front of a spherical mirror of focal

length 'f' and image 'u' is formed by the mirror.

Answer:

right side up

Explanation:

Ranking Earthquake Intensity

Magnitude Average number per year Modified Mercalli Intensity

2.0 – 2.9 >1 million I

3.0 – 3.9 about 100,000 II – III

4.0 – 4.9 about 10,000 IV – V

5.0 – 5.9 about 1,000 VI – VII

Explanation:

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Explanation:

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