In the diagram above, where is light energy converted to chemical energy?
A. Sun
B. Grass
C. Grasshopper
B. Hawk

Answer:

you could put the iron filings on the peace of paper and hover a magnet over top of the paper and the iron filings would stand up, or even stick to the magnet

Explanation:

Answer:

Explanation:

Initial velocity in y direction Vy = 22.3 m /s

initial acceleration in x direction ax = .203 m /s ²

time of acceleration t = 56.7 s

final velocity in x direction

v  = u + a t

Vx = 0 + .203 x 56.7 = 11.51 m /s

Final velocity in y direction will remain same as initial velocity in y direction = 22.3 m /s because there is no acceleration in y direction .

Magnitude of final velocity

= √ ( Vx² + Vy²)

= √ (22.3² + 11.51² )

= √ ( 497.29 + 132.48)

= 25.1 m /s

Direction of final velocity  from y direction be Ф

TanФ = Vx / Vy = 11.51 / 22.3 = .516

Ф = 27.3° .

Answer:

Explanation:

The attraction weakens. Two objects that are farther apart are not drawn together as strongly as if they were close together.

Answer:

d I think? not sure I don't know much abt the ocean

Answer:

g₂ = 39 m / s²

Explanation:

Mass is the amount of matter that a body has, so it does not change, but the weight is the force with which the planet attracts this matter, this value does change

           W = m g

let's use subscript 1 for the first planet and subscript 2 for the second planet

           W₁ = m₁ g₁

           W₂ = m₂ g₂

They give us the values ​​of the masses and the value of g₁ = 7.0 m / s, let's find the value of the acceleration of gravity on Planet 2

They tell us that the weight of the two astronauts is the same therefore

          W₁ = W₂ = W

let's match the expressions

             m₁ g₁ =m₂ g₂

             g₂ = [tex]\frac{m_1}{m_2} \ g_1[/tex]

let's calculate

              g₂ = [tex]\frac{70}{80} \ 7.0[/tex]      

              g₂ = 39.2 m / s²

              g₂ = 39 m / s²

Answer:

She changed a closed circuit to an open circuit

Explanation:

This means that she has changed from a short circuit to an open circuit. Then the correct option is C.

The stream of positive charges which flow from the positive terminal to the negative terminal of the battery attached in a circuit.

An interrupted consistency in an electrical circuit prevents current from flowing, which is what the term "OPEN CIRCUIT" refers to.

A closed circuit is comparable to a road that uses a bridge to cross a stream.

An electrical circuit in a gadget with a current rating than a typical circuit, particularly one created by unintentional component engagement and subsequent current misdirection.

In a movie, the heroine saves the day by cutting a wire before the time runs out on a timer.

This means that she has changed from a short circuit to an open circuit.

Then the correct option is C.

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Air masses from the tropics and the equator are warm as they form over lower latitudes. The major causes for moving air masses North America exists jet storm.

An air mass is a volume of air that in meteorology is identified by its temperature and humidity. Many hundreds or thousands of square miles are covered by air masses, which adjust to the properties of the land underneath them. Latitude and their continental or maritime source regions are used to categories them.

Warmer air masses are referred to as tropical, whilst colder air masses are referred to as polar or arctic. Superior and maritime air masses are moist, whereas continental and superior air masses are dry. Air masses with various densities are divided by weather fronts. Once an air mass has left its original location, nearby plants and bodies of water can quickly change the way it behaves. Classification systems address both the properties and modification of an air mass.

Air masses from the tropics and the equator are warm as they form over lower latitudes. They move poleward along the southern edge of the subtropical ridge and are drier and hotter than those that originate over seas. Trade air masses are another name for tropical maritime air masses. The Caribbean Sea, southern Gulf of Mexico, and tropical Atlantic Oceans, east of Florida via the Bahamas, are the origins of maritime tropical air masses that have an impact on the United States.

Monsoon air masses are moist and unstable. Rarely do dry superior air masses touch the ground. A trade wind inversion, which is a warmer and drier layer over the more moderately moist air mass below, is typically created over maritime tropical air masses when they are located above them.

Therefore, the correct answer is option C. jet storm.

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Answer:

B Decrease

Explanation:

ik im right cuz i looked up the answer

Answer:

the child's mass is 33.1 kg

Speed = (distance covered) / (time took)

Answer:

A)  Propagation of pressure fluctuations in a medium

B) air is the medium in which the wave is transported,

Explanation:

Part A.

A sound wave is a longitudinal oscillation of the molecules that forms in a material medium, they can be solid, liquid or gases, therefore the wave propagates in the same direction as the oscillation of the particles.

The most correct answer is:

* Propagation of pressure fluctuations in a medium

Part b

air is the medium in which the wave is transported, otherwise it cannot propagate

Answer:

the number density of the protons in the beam is 3.2 × 10¹³ m⁻³

Explanation:

Given that;

diameter D = 2.0 mm

current I = 1.0 mA

K.E of each proton is 20 MeV

the number density of the protons in the beam = ?

Now, we make use of the relation between current and drift velocity

I = MeAv ⇒ 1 / eAv

The kinetic energy of protons is given by;

K = [tex]\frac{1}{2}[/tex][tex]m_{p}[/tex]v²

v = √( 2K / [tex]m_{p}[/tex] )

lets relate the cross-sectional area A of the beam to its diameter D;

A = [tex]\frac{1}{4}[/tex]πD²

now, we substitute for v and A

n = I / [tex]\frac{1}{4}[/tex]πeD² ×√( 2K / [tex]m_{p}[/tex] )

n = 4I/π eD² × √([tex]m_{p}[/tex] / 2K )

so we plug in our values;

n = ((4×1.0 mA)/(π(1.602×10⁻¹⁹C)(2mm)²) × √(1.673×10⁻²⁷kg / 2×( 20 MeV)(1.602×10⁻¹⁹ J/ev )

n =  1.98695 × 10¹⁸ × 1.6157967  × 10⁻⁵

n = 3.2 × 10¹³ m⁻³  

Therefore, the number density of the protons in the beam is 3.2 × 10¹³ m⁻³

Answer:

Explanation:

Increases. The force of gravity is distance dependent. Therefore, a smaller 'r' value will result in a larger force. Net force is proportional to the acceleration, so the planet will increase its speed.

Answer:

Explanation:

Angle of incidence at the longer face = 45⁰ ( see the figure in the attached file )

For total reflection from longer face

i = C where C is critical angle .

And relation between critical angle and refractive index is as follows .

μ = 1 / sinC

= 1 / sin45

= √2

= 1.414 .

Answer:

The distance from the positive plate at which the two pass each other is 0.0023 cm.

Explanation:

We need to find the acceleration of each particle first. Let's use the electric force equation.

[tex]F=Eq[/tex]

[tex]ma=Eq[/tex]

For the proton

[tex]m_{p}a_{p}=Eq_{p}[/tex]

[tex]a_{p}=\frac{Eq_{p}}{m_{p}}[/tex]

[tex]a_{p}=\frac{646*1.6*10^{-19}}{1.67*10^{−27}}[/tex]

[tex]a_{p}=6.19*10^{10}\: m/s^{2}[/tex]

For the electron

[tex]m_{e}a_{e}=Eq_{e}[/tex]

[tex]a_{e}=\frac{Eq_{e}}{m_{e}}[/tex]

[tex]a_{e}=\frac{646*1.6*10^{-19}}{9.1*10^{−31}}[/tex]  

[tex]a_{e}=1.14*10^{14}\: m/s^{2}[/tex]

Now we know that the plate separation is 4.26 cm or 0.0426 m. The travel distance of the proton plus the travel distance of the electron is 0.0426 m.

[tex]x_{p}+x_{e}=0.0426[/tex]

Both of them have an initial speed equal to zero. So we have:

[tex]\frac{1}{2}a_{p}t^{2}+\frac{1}{2}a_{e}t^{2}=0.0426[/tex]

[tex]t^{2}(a_{p}+a_{e})=2*0.0426[/tex]

[tex]t^{2}=\frac{2*0.0426}{a_{p}+a_{e}}[/tex]

[tex]t=\sqrt{\frac{2*0.0426}{6.19*10^{10}+1.14*10^{14}}}[/tex]

[tex]t=2.73*10^{-8}\: s[/tex]    

With this time we can find the distance from the positive plate (x(p)).

[tex]x_{p}=\frac{1}{2}a_{p}t^{2}[/tex]

[tex]x_{p}=\frac{1}{2}6.19*10^{10}*(2.73*10^{-8})^{2}[/tex]

[tex]x_{p}=0.0023\: cm[/tex]

Therefore, the distance from the positive plate at which the two pass each other is 0.0023 cm.

I hope it helps you!

Answer:

(A)  the acceleration  experienced by the proton 2.821 x 10¹² m/s²

(B) the speed of the proton is 2.67 x 10⁵ m/s

Explanation:

Given;

electric field experienced by the proton, E = 2.95 x 10⁴ N/C

charge of proton, Q = 1.6 x 10⁻¹⁹ C

mass of proton, m = 1.673 x 10⁻²⁷ kg

distance moved by the proton, d = 1.26 cm = 0.0126 m

(a)

The force experienced by the proton is calculated as;

F = ma = EQ

where;

a is the acceleration  experienced by the proton

[tex]a = \frac{EQ}{m} \\\\a = \frac{2.95\times 10^4 \ \times \ 1.6\times 10^{-19}}{1.673 \times 10^{-27}} \\\\a = 2.821 \times 10^{12} \ m/s^2[/tex]

(b) the speed of the proton is calculated;

v² = u² + 2ad

v² = 0 + (2 x 2.821 x 10¹² x 0.0126)

v² = 7.109 x 10¹⁰

v = √7.109 x 10¹⁰

v = 2.67 x 10⁵ m/s

Answer:

c

Explanation:

Answer:

Explanation:

The acceleration up the incline is 1.00 m/s²

Net force acting on two masses = total mass x acceleration

= 350 x 1 = 350 N

weight acting down the plane = m g sinФ

= 350 x 9.8 x sin30 = 1715 N

Friction force acting down the plane = mg cosФ x μ where μ is coefficient of friction

= 350 x 9.8 x cos30 x .2 = 594N

Net force acting on total mass

= F - 1715 - 594 = 350 , where F is required force

F = 2659 N .

Answer:

a) 36°

b) 0.109 kg

Explanation:

Heat flows from brass to copper with the brass having its temperature

Length of brass = 0.4

Length of copper = 0.8

Temperature of = 36.15

See attachment for calculation

The temperature at the joint is 36.15°C

The amount of ice melted is 1.086 kg

The rate of transfer of thermal energy,

   H = Q/t = KAΔT/L

  where, K is the thermal conductivity of the substance, A is cross-sectional area, ΔT is temperature difference at the ends and L is the length

As given in the question,

  the length of the brass section   [tex]L_{1}[/tex] = 0.4 m

  it's thermal conductivity      [tex]K_{b}[/tex] = 109 J[tex]s^{-1}m^{-1}K^{-1}[/tex]

  the temperature at the brass end  [tex]T_{1}[/tex] = 373K

  the length of the copper section [tex]L_{2}[/tex] = 0.8 m

  it's thermal conductivity      [tex]K_{c}[/tex] = 385 J[tex]s^{-1}m^{-1}K^{-1}[/tex]

  the temperature at the brass end  [tex]T_{1}[/tex] = 273K

 cross-sectional area of both the substance is same A = 0.007 [tex]m^{2}[/tex]

  Let the temperature at the joint be T

The rate of heat flow must be constant across the whole length of the setup.

Hence at the joint,

   [tex]\frac{K_{b}A(T_{1}-T) }{L_{1} } =\frac{K_{c}A(T-T_{2}) }{L_{2} }[/tex]

⇒ [tex]\frac{ 109*A*(373-T)}{0.4} =\frac{385*A(T-273)}{0.8}[/tex] ⇒ T=309.15 K

⇒ T = 36.15°C is the temperature at the joint.

Now we have to calculate the equivalent thermal conductivity K of the setup in order to calculate the amount of heat transfer.

considering equivalent thermal conductivity K throughout the setup we can form the following equation to calculate its value

   [tex]\frac{KA(T_{1}-T_{2} ) }{L_{1}+L_{2} } =\frac{K_{c}A(T-T_{2}) }{L_{2} }[/tex]

   ⇒   [tex]\frac{ K*A*(100)}{1.2} =\frac{385*A(36.15)}{0.8}[/tex]

   ⇒  K = 208.76 J[tex]s^{-1}m^{-1}K^{-1}[/tex]

the amount of heat transferred at the copper end in ice-water mixture in 5 minutes(300 seconds) :

        Q = [tex]\frac{KA(T_{1}-T_{2} ) }{L_{1}+L_{2} }[/tex] × t =  [tex]\frac{208.76*0.007*100}{1.2}[/tex] × 300 = 36533 J

        latent heat of fusion of ice [tex]L_{f}[/tex] = 33600 J/kg

         [tex]Q=mL_{f}[/tex]

         [tex]m=\frac{Q}{L_{f} }[/tex]

         [tex]m=\frac{36533}{33600}[/tex] ⇒ m = 1.086 kg of ice is melted in 5 minutes

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Answer:

c heats up cancer cells and weakens them.

Answer:

I think it is C

Explanation:

because

Answer:

21 hours

Explanation:

well 30 x 20 = 600 than 21 = 630

Answer:

- the Thevenin equivalent circuit for the battery is uploaded below

- the battery delivered 117 watts of power to the starter motor

Explanation:

Given the data in the equation

diagram of the Thevenin equivalent circuit for the battery is uploaded below.

Current I = 10 A

Voltage 1 = 12 V

voltage 2 = 11.7 v

R = (V1 - V2) / I

R = (12-11.7)/10

R = 0.3 / 10

R = 0.03Ω

Thevenin equivalent circuit

[tex]R_{L}[/tex] = V2 / I = 11.7 / 10

[tex]R_{L}[/tex] = 1.17Ω

so, power delivered to the starter motor will be;

p = (V2)² / [tex]R_{L}[/tex]

P = ( 11.7 V )² / 1.17Ω

p =  136.89 / 1.17

p =  117 watts

Therefore, the battery delivered 117 watts of power to the starter motor

Answer:

Center of solar system

Explanation:

Answer: b

Explanation:

Answer:

i Believe the correct answer is "An open circuit being changed into a closed circuit"

Explanation:

Answer:

a) a = - 1.76 m / s²,  b)   F = 20.5 N, c)  w = 3.55 rad / s

Explanation:

a) a simple harmonic motion is described by the expression

          x = A cos (wt + Ф)

in this case they give us the frequency

         w = 2π f

         w = 2π 0.40

         w = 2.51 rad / s

as the maximum elongation is 0.65 m this corresponds to the amplitude of the movement

         A = 0.65 m

to find the phase constant (Ф) we use the initial condition that for t = 0 v = 0 and x = A, we substitute

          A = A cos (0+ Ф)

         cos Ф = 1

         Ф = 0

the resulting equation is

         x = 0.65 cos (2.51 t)

Let's find the time it takes to get to x = 0.28 m

         0.28 = 0.65 cos 2.51 t

          2.51 t = cos-1 (0.28 / 0.65)

remember angles are in radians

          t = 1.1254 / 2.51

          t = 0.448 s

the acceleration is

         [tex]a = \frac{dv}{dt} = \frac{d^2x}{dt^2}[/tex]

         a = -A w² cos wt

we subtitle

         a = - 0.65 2.51² cos (2.51  0.448)

         a = - 1.76 m / s²

b) the maximum acceleration occurs when the cosine is ±1

        a = A w²

        a = 0.65  2.51²

        a = 4.10 m / s²

Let's use Newton's second law

        F = m a

        F = 5 4.1

        F = 20.5 N

c) The angular velocity is given by

          w² = k / m

let's find the spring constant

          k = m w²

          k = 5 2.51²

          k = 31.5 N / m

therefore if the block is exchanged for another with mass m'= 2.5 kg

         w = √(31.5 / 2.5)

         w = 3.55 rad / s

Answer:

Explanation:

For range o a projectile , the formula is as follows

R = u² sin2Ф / g where u is initial velocity of throw , Ф is angle of throw and g is acceleration due to gravity .

Here u = 14 m /s

R = 14² sin2Ф  / 9.8

R = 20 sin2Ф

Now R will have maximum value when sin2Ф has maximum value .

Maximum value of sin2Ф = 1

sin2Ф = 1  = sin 90°

Ф = 45°

So when throw is aimed at 45° , range will be maximum .