In the coordinate plane, the point A (0, 0) is translated to the point A '(1, 3). Under the same translation, the points B (-3, -2) and C (3, 3) are translated to B' and C', respectively. What are the coordinates of B' and C'?

The answers are:
a. \( \mathbf{v}=\overrightarrow{P Q} = (4, 4) \)
b. \( \|\mathbf{v}\| = 4\sqrt{2} \)
c. \( \overrightarrow{P Q}+\overrightarrow{Q P} = (0, 0) \)

The given points are point \( P \) be \( (-1,3) \) and point \( Q \) be \( (3,7) \).

a. To find \( \mathbf{v}=\overrightarrow{P Q} \), we subtract the coordinates of point \( P \) from the coordinates of point \( Q \):

\( \mathbf{v}=\overrightarrow{P Q} = (3-(-1), 7-3) = (4, 4) \)

b. To find \( \|\mathbf{v}\| \), we use the distance formula:

\( \|\mathbf{v}\| = \sqrt{(4-0)^2 + (4-0)^2} = \sqrt{16 + 16} = \sqrt{32} = 4\sqrt{2} \)

c. To find \( \overrightarrow{P Q}+\overrightarrow{Q P} \), we add the coordinates of \( \overrightarrow{P Q} \) and \( \overrightarrow{Q P} \):

\( \overrightarrow{P Q}+\overrightarrow{Q P} = (4, 4) + (-4, -4) = (0, 0) \)

Therefore, the answers are:

a. \( \mathbf{v}=\overrightarrow{P Q} = (4, 4) \)

b. \( \|\mathbf{v}\| = 4\sqrt{2} \)

c. \( \overrightarrow{P Q}+\overrightarrow{Q P} = (0, 0) \)

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Answer:

Below

Step-by-step explanation:

4 outlets/ 1.5 hr     *    7.5 hr = 20 outlets   ( see how 'hr' cancels out and you are left with 'outlets ?)

Answer: 20

Step-by-step explanation:

In 1.5 hours, the no. of electrical outlets rewired = 4

Then, in 1 hour the no. of electrical outlets rewired = 4/1.5

So, in 7.5 hours the no. of electrical outlets rewired =( 4/1.5 ) × 7.5 = 20.

McKenzie would take 6 hours to complete the landscaping job alone if Lindy calls in sick.

If McKenzie and Lindy can complete the landscaping job in 4 hours working together, it means their combined work rate is 1/4 of the job per hour. Let x be the number of hours it takes Lindy to complete the job alone, then McKenzie can complete the job in x-6 hours.

Using the formula for their individual work rates, we have:

[tex]1/x + 1/(x-6) = 1/4[/tex]

Multiplying both sides by [tex]4x(x-6)[/tex], we get:

[tex]4(x-6) + 4x = x(x-6)[/tex]

Expanding and simplifying, we get:

[tex]2x^2 - 12x - 48 = 0[/tex]

Dividing both sides by 2 and using the quadratic formula, we get:

[tex]x = (12 ± \sqrt{12^2 + 4248}) / (2*2)[/tex]

x = (12 ± 18) / 4

x = 7.5 or -1.5

Since we cannot have a negative time, the answer is that it would take Lindy 7.5 hours to complete the job alone, and McKenzie would take 1.5 hours less, or 6 hours, to complete the job alone if Lindy calls in sick.

Therefore, McKenzie would take 6 hours to complete the landscaping job alone if Lindy calls in sick.

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Answer:

The discount on the skateboard is 12% of its original price, so the discounted price is:

Discounted price = $79.28 - 0.12($79.28) = $69.78

Now we need to calculate the sales tax on the discounted price. The sales tax rate is 8.25%, so the amount of sales tax is:

Sales tax = 0.0825($69.78) = $5.76

Adding the discounted price and the sales tax, we get the total cost of the skateboard:

Total cost = $69.78 + $5.76 = $75.54

Therefore, the total cost of the skateboard, including the discount and sales tax, is $75.54.

The simplified expressions are: (a) z = 1/4, (b) 3z^2, (c) -4z, and (d) 3z^2.

To simplify each expression by performing the indici, we need to follow the order of operations and combine like terms. Here are the steps for each expression:

(a) z + 3z = 1
First, we need to combine the like terms on the left side of the equation. Since both terms have the variable z, we can add them together:
4z = 1
Next, we need to solve for z by isolating the variable on one side of the equation. We can do this by dividing both sides of the equation by 4:
z = 1/4

(b) z * 3z
To simplify this expression, we just need to multiply the two terms together:
3z^2

(c) -z - 3z
To simplify this expression, we need to combine the like terms. Since both terms have the variable z, we can add them together:
-4z

(d) (-z)(-3z)
To simplify this expression, we just need to multiply the two terms together. Remember that a negative times a negative is a positive:
3z^2

So the simplified expressions are: (a) z = 1/4, (b) 3z^2, (c) -4z, and (d) 3z^2.

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The mechanic must mix 12 gallons of a 40% antifreeze solution with 4 gallons of an 80% antifreeze solution to create 16 gallons of a 50% antifreeze solution.

To find out how much of a 40% antifreeze solution must be mixed with an 80% antifreeze solution to create 16 gallons of a 50% antifreeze solution, we can use the following equation:

40% x + 80% y = 50% (16)

Where x is the amount of 40% antifreeze solution and y is the amount of 80% antifreeze solution.

We can also use the fact that the total amount of solution must equal 16 gallons:

x + y = 16

Now we can solve for one variable in terms of the other. Let's solve for x in the second equation:

x = 16 - y

And substitute this value of x into the first equation:

40% (16 - y) + 80% y = 50% (16)

Simplifying:

[tex]6.4 - 0.4y + 0.8y = 8[/tex]

0.4y = 1.6

y = 4

Now we can substitute this value of y back into the equation for x:

x = 16 - 4

x = 12

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a sample size of approximately 246 U.S. adults would be required to reduce the standard deviation of the sampling distribution to one-half the original value.

The standard deviation is a metric that reveals how much variance from the mean there is, including spread, dispersion, and spread. A "typical" variation from the mean is shown by the standard deviation. Because it uses the data set's original units of measurement, it is a well-liked measure of variability.

from the question:

Assuming a 95% confidence interval and an error rate equal to half the initial standard deviation, or E = 0.5, the following results are obtained:

[tex]n = [(1.96 / 0.5σ) / 0.70(1 - 0.70)]^2[/tex]

The population's standard deviation must be known in order to solve for n; however, this information is not provided in the problem description. Based on prior research or experience, we may substitute a standard deviation of 0.05 into the following formula:

[tex]n = [(1.96 / 0.5(0.05)) / 0.70(1 - 0.70)]^2 ≈ 246[/tex]

Hence, to cut the standard deviation of the sampling distribution to half its initial value, a sample size of about 246 American adults would be needed.

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The equation of the line through the point (3, -7) that is parallel to the line 4x + 7y - 10 = 0 is y = (-4/7)x - (37/7) in the point-slope form

To find the equation of the line through the point (3, -7) that is parallel to the line 4x + 7y - 10 = 0, we first need to find the slope of the given line. We can do this by rearranging the equation to the slope-intercept form, y = mx + b, where m is the slope.

4x + 7y - 10 = 0

7y = -4x + 10

y = (-4/7)x + (10/7)

The slope of the given line is -4/7. Since we want a line that is parallel to this one, the slope of our new line will also be -4/7.

Now we can use the point-slope form of a line, y - y1 = m(x - x1), to write the equation of the new line. We plug in the given point (3, -7) for (x1, y1) and the slope -4/7 for m.

y - (-7) = (-4/7)(x - 3)

y + 7 = (-4/7)x + (12/7)

y = (-4/7)x + (12/7) - 7

y = (-4/7)x - (37/7)

So the equation of the line through the point (3, -7) that is parallel to the line 4x + 7y - 10 = 0 is y = (-4/7)x - (37/7) in the point-slope form.

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Answer:

Representation B does not show the amount of time Kaleigh spent watching TV at this rate. Representation B only shows the total time she would have spent based on the number of episodes watched, assuming each episode is 30 minutes long. It does not take into account the actual time it took for Kaleigh to watch the episodes, which may have varied depending on how quickly she watched them.

Step-by-step explanation:

The expression √1−x^2, with the substitution x=cos(θ), can be simplified to sin(θ).

To write the expression as a trigonometric expression using the suggested substitution, we will replace x with cos(θ) in the expression. This gives us:

√1−cos^2(θ)

Now, we can use the Pythagorean identity, sin^2(θ) + cos^2(θ) = 1, to simplify the expression further. Rearranging the identity, we get:

sin^2(θ) = 1 - cos^2(θ)

Substituting this back into our original expression, we get:

√sin^2(θ)

Taking the square root of both sides, we get:

sin(θ)

Therefore, the expression √1−x^2, with the substitution x=cos(θ), can be simplified to sin(θ).

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The given conditions imposed on the variables \( a, b, c, d \) and \( x \) are:

To determine if the statements in Exercises 1-12 are true or false, use the given conditions to evaluate the expressions in the statement. If the statement matches the conditions, it is true; if it does not, it is false. For example, if the statement is: " \( a + b = d \) ", then this is false, as \( a + b \neq d \).

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Hello there! To find f ∘ g, g ∘ f, and g ∘ g, let's first recall the definition of function composition: given two functions f and g, their composition f ∘ g is defined as the function that results from applying g to the result of applying f to its argument. Specifically, for a given input x, we can express the composition f ∘ g as follows: (f ∘ g)(x) = f(g(x)).

Given f(x) = x4 and g(x) = 1/x, we can find each composition as follows:

(a) f ∘ g = f(g(x)) = f(1/x) = (1/x)4

(b) g ∘ f = g(f(x)) = g(x4) = 1/(x4)

(c) g ∘ g = g(g(x)) = g(1/x) = 1/(1/x) = x

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The functions are continuous at all points except where the denominator of a fraction is equal to zero. This is because division by zero is undefined and causes a discontinuity in the function.

(a) f(x)=(9x^(2)-4)/(3x-2): This function is continuous everywhere except where 3x-2=0, which is when x=2/3. Therefore, the function is continuous at all points except x=2/3.

(b) f(x)=x2^(sinx): This function is continuous everywhere because there are no denominators that could equal zero.

(c) f(x)=sin(1)/(2x): This function is continuous everywhere except where 2x=0, which is when x=0. Therefore, the function is continuous at all points except x=0.

(d) f(x)={(x^(2)-1,x>3),(8,n=3),(2^(x),x<3):} This function is continuous for x>3 and x<3, but there is a discontinuity at x=3 because the function is not defined for x=3. Therefore, the function is continuous at all points except x=3.

In conclusion, the functions are continuous at all points except where the denominator of a fraction is equal to zero, causing a discontinuity. The functions are continuous at all other points.

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The continuity of a function can be determined by examining the values of the function at different points in its domain. If the function is continuous at a point, it means that the limit of the function as it approaches that point from both the left and the right is equal to the value of the function at that point. A function is continuous over an interval if it is continuous at every point in that interval.

(a) The function f(x)=(9x^(2)-4)/(3x-2) is continuous everywhere except at x = 2/3, where the denominator is equal to zero and the function is undefined.

(b) The function f(x)=x2^(sinx) is continuous everywhere. The exponential function 2^(sinx) is continuous for all values of x, and the product of two continuous functions is also continuous.

(c) The function f(x)=sin(1)/(2x) is continuous everywhere except at x = 0, where the denominator is equal to zero and the function is undefined.

(d) The function f(x)={(x^(2)-1,x>3),(8,n=3),(2^(x),x<3):} is continuous for x > 3 and x < 3, but it is not continuous at x = 3, where there is a jump discontinuity from 8 to 2^(3).

In conclusion, the functions are continuous at the following points:
(a) f(x)=(9x^(2)-4)/(3x-2): continuous everywhere except at x = 2/3
(b) f(x)=x2^(sinx): continuous everywhere
(c) f(x)=sin(1)/(2x): continuous everywhere except at x = 0
(d) f(x)={(x^(2)-1,x>3),(8,n=3),(2^(x),x<3):}: continuous for x > 3 and x < 3, but not continuous at x = 3

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$\lambda - s$ is an eigenvalue of W – s$\lambda$ and $\mathbf{v}$ is the corresponding eigenvector.

Linear Algebra: Let W $\in$ $\mathbb{R}^{n \times n}$, s $\in$ $\mathbb{R}$, and $\lambda$ an eigenvalue of W. To prove that $\lambda$ – s is an eigenvalue of W – s$\lambda$, we will use the definition of eigenvalues and eigenvectors:

An eigenvalue $\lambda$ of a square matrix A $\in$ $\mathbb{R}^{n \times n}$ is a scalar such that there exists a nonzero vector $\mathbf{v} \in \mathbb{R}^n$ for which the following equation holds:

A$\mathbf{v}$ = $\lambda \mathbf{v}$

Therefore, we can rearrange the equation to show that W – s$\lambda$ $\mathbf{v}$ = $(\lambda -s) \mathbf{v}$, which implies that $\lambda - s$ is an eigenvalue of W – s$\lambda$ and $\mathbf{v}$ is the corresponding eigenvector.

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In response to the supplied query, we may state that Therefore, the Pythagorean theorem length of the hypotenuse is approximately 25.5 inches.

The Pythagorean Theorem, often known as the Pythagorean Theorem, is the fundamental Euclidean geometry relationship between the three sides of a right triangle. The area of a square with the hypotenuse side equals the sum of the areas of squares with the other two sides, according to this rule. The Pythagorean Theorem says that the square that spans a right triangle's hypotenuse opposite the right angle equals the sum of the squares that span its sides. It is sometimes written as the general algebraic notation a2 + b2 = c2.  

The Pythagorean theorem may be used to calculate the hypotenuse's length. According to the Pythagorean theorem, the square of the length of the hypotenuse (c) in a right triangle equals the sum of the squares of the lengths of the legs (a and b):

[tex]c^2 = a^2 + b^2[/tex]

[tex]c^2 = 19^2 + 17^2\\c^2 = 361 + 289\\c^2 = 650\\c =\sqrt(650)\\c = 25.5\\c = 25.5 inches[/tex]

Therefore, the length of the hypotenuse is approximately 25.5 inches.

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Answer:

A. 3/2

Step-by-step explanation:

what is a dilation? a dilation can make objects bigger or smaller.

10 times [tex]\frac{3}{2}[/tex] is 15

4 times [tex]\frac{3}{2}[/tex] is 6

8 times [tex]\frac{3}{2}[/tex] is 12

therefore the answer is A.. [tex]\frac{3}{2}[/tex]

Answer:

A. 3/2

Step-by-step explanation:

What is dilation?

The original image is DEFG. It is called the pre-image

The dilated image is D'E'F'G' and is called image

A transformed image has the coordinates labeled with a '

In this case the transformed image is a dilation of the original pre-image. A dilated image is a cop.y of the pre-image but with either an expansion or a compression

If the image is larger than the pre-image it is an expansion, if smaller than the pre-image then it is a compression

With dilation, comes a scale factor which indicates how much a pre-image has been expanded or compressed

Solution

If you look at the two images, take any side in the pre-image and compare its length with the corresponding side you can find the scale factor

Here if you take a side, say DE = 4 and look at the corresponding side D'E' = 6you see that the DE side has been expanded with a scale factor of 6/4 = 3/2

This scale factor applies to all sides, so you need to take only one side to find the scale factor

Answer: Scale Factor of dilation = 3/2

This is option A

Answer:

Step-by-step explanation:

For any cube the total edge length is equal to 12n, with n being the length of an edge side. Knowing this:

Cube A - Total edge length = 12(3) or 36

Cube B - 12(5) or 60

Cube C - 12(9.5) or 114

If any cube has edge length s, the total edge length is 12s

Hope this helps!

To prove that T is a linear transformation, we need to show that T(c~u + ~v) = cT(~u) + T(~v) for any scalar c and any vectors ~u and ~v in R2.

Let ~u = (u1, u2) and ~v = (v1, v2) be two vectors in R2 and let c be any scalar. Then,

T(c~u + ~v) = T(cu1 + v1, cu2 + v2) = (3(cu1 + v1) - 2(cu2 + v2), 2(cu2 + v2))

= (3cu1 + 3v1 - 2cu2 - 2v2, 2cu2 + 2v2)

= (3cu1 - 2cu2, 2cu2) + (3v1 - 2v2, 2v2)

= c(3u1 - 2u2, 2u2) + (3v1 - 2v2, 2v2)

= cT(~u) + T(~v)

Therefore, T is a linear transformation.

To find the standard matrix A of T, we can use the fact that T(~e1) and T(~e2) are the first and second columns of A, respectively, where ~e1 = (1, 0) and ~e2 = (0, 1) are the standard basis vectors of R2.

T(~e1) = T(1, 0) = (3(1) - 2(0), 2(0)) = (3, 0)

T(~e2) = T(0, 1) = (3(0) - 2(1), 2(1)) = (-2, 2)

Therefore, the standard matrix A of T is:

A = [ 3  -2 ]
     [ 0   2 ]

To determine if T is one-to-one, we can use the fact that a linear transformation is one-to-one if and only if its standard matrix A has linearly independent columns. In this case, the columns of A are linearly independent because they are not scalar multiples of each other. Therefore, T is one-to-one. Alternatively, we can use the fact that a linear transformation is one-to-one if and only if its standard matrix A has a nonzero determinant. In this case, the determinant of A is (3)(2) - (0)(-2) = 6, which is nonzero. Therefore, T is one-to-one.

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The straight line that is parallel to 3x + y = -3 and passes through point (3,2) is  y = -3x + 11.

We find the slope of the given line: 3x +  y= -3 can be rearranged to y = -3x - 3, which is in the slope-intercept form y = mx + b. The slope of this line is -3.

Since parallel lines have the same slope, the slope of the line we are looking for is also -3.

We use the point-slope form of an equation, y - y₁ = m(x - x₁), where m is the slope and (x₁, y₁) is the point the line passes through.

Plug in the values we have: y - 2 = -3(x - 3)

We simplify the equation: y - 2 = -3x + 9 => y = -3x + 11

Therefore, the equation of the line parallel to 3x +y=-3 through the point (3,2) is y = -3x + 11.

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Answer:

The equation that represents a linear function is:

y equals one half times x minus 5

This is a linear equation because it has a constant rate of change, or slope, of one half. This means that for every increase of 1 in x, y will increase by 1/2. The equation is also in the standard form of a linear equation, y = mx + b, where m is the slope and b is the y-intercept.

The other equations are not linear functions:

x = 3 is a vertical line, which is not a function because it fails the vertical line test.

y equals three fourths times x squared is a quadratic function because it includes an x-squared term.

3x − 6 = 4 is a linear equation, but it is not in the standard form of y = mx + b. It can be rearranged to y = (3/1)x - 2, which is a linear equation in slope-intercept form.

According to the given information product of (3x - 2) and (2z + 6) is 6xz + 18x - 4z - 12.

In mathematics, expressions are also combinations of constants, variables, operators, and function calls that represent mathematical operations or relationships.

Let's start with distributing the first term of the first expression to both terms of the second expression, then distributing the second term of the first expression to both terms of the second expression:

(3x - 2)(2z + 6)

= 3x(2z + 6) - 2(2z + 6)

= 6xz + 18x - 4z - 12

Now, let's use the FOIL method to find the same product:

(3x - 2)(2z + 6)

= 3x(2z) + 3x(6) - 2(2z) - 2(6)

= 6xz + 18x - 4z - 12

As you can see, both methods result in the same product: 6xz + 18x - 4z - 12.

Therefore, according to the given information product of (3x - 2) and (2z + 6) is 6xz + 18x - 4z - 12.

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Yes, Tanner has enough spray paint for his arrow.

What is an Area?

The amount of space occupied by a flat (2-D) surface or an object's shape is known as its area. A planar figure's area is the area that its perimeter encloses. The quantity of unit squares that completely encircle the surface of a closed figure is its area. Square measurements for area include cm2 and m2.

Given : paint available in can = 12 ft²

We know that the arrow is comprised of a triangle and a rectangle.

So, the area of given arrow = area of rectangle + area of triangle

Now, area of triangle = 1/2 ×base × height

                                   = 1/2 × 3 × (6 - 5 1/3)

                                   = 3/2 × ( 6 - 16/3)

                                   = 3/2 × ( 18-16)/3

                                   = 3/2 × 2/3

                                    = 1 ft²

Similarly, area of rectangle =  length × breadth

                                            = 5 1/3 × 2

                                            = 16/3 × 2

                                            = 32/3 ft²

Hence, area of arrow = area of triangle +area of rectangle

                                   = 1 + 32/3

                                   = 35/3 ft²

                                   = 11.67 ft²

So, he has sufficient paint to cover the arrow.

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Answer:

Step-by-step explanation:

The slope is 2 so rise / run = 2 / 1, or up two right one.

Answer:

y = 36

x = 12

Hope it helps!

There are 27720 different arrangements possible.

The number of different arrangements possible can be found using the formula for permutations with repetition:

n! / ([tex]p{1}[/tex]! * [tex]p{2}[/tex]! * ... *[tex]p_{k}[/tex]!)

where n is the total number of items, and [tex]p{1}[/tex], p2, ..., pk are the number of times each item is repeated.

In this case, n = 12 (the total number of balls), [tex]p{1}[/tex] = 5 (the number of yellow balls), [tex]p{2}[/tex] = 4 (the number of green balls), and [tex]p{3}[/tex] = 3 (the number of black balls).

So the number of different arrangements possible is:

12! / (5! * 4! * 3!)

= 479001600 / (120 * 24 * 6)

= 27720

Therefore, number of different arrangements possibleis 27720.

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Answer: C

Step-by-step explanation: Just replace x=1,2,3,4 to see which answers satisfy the given conditions

Answer:

m= 3/4

Step-by-step explanation:

hope this helps

Answer:

area = (1/2) · (p + q) · h

Step-by-step explanation:

The Integer Root Theorem states that the possible integer roots of a polynomial are the divisors of the constant term (100). Therefore, the candidate integer roots for the polynomial [tex]f(x) = -x^5 + 22x^4 - 8x^3 - 8x^2 + 5x + 100[/tex] are: 1, -1, 2, -2, 4, -4, 5, -5, 10, -10, 20, -20, 25, -25, 50, and -50.

According to the integer root theorem, the possible integer roots of a polynomial f(x) are the factors of the constant term divided by the factors of the leading coefficient. In the case of f(x)=-x^(5)+22x^(4)-8x^(3)-8x^(2)+5x+100, the constant term is 100 and the leading coefficient is -1.

The factors of 100 are: 1, 2, 4, 5, 10, 20, 25, 50, and 100. The factors of -1 are: 1 and -1.

Therefore, the possible integer roots of f(x) are: ±1, ±2, ±4, ±5, ±10, ±20, ±25, ±50, and ±100.

So, the candidate integer roots of  [tex]f(x) = -x^5 + 22x^4 - 8x^3 - 8x^2 + 5x + 100[/tex]  are: 1, -1, 2, -2, 4, -4, 5, -5, 10, -10, 20, -20, 25, -25, 50, -50, 100, and -100.
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Answer:

Solve for the first variable in one of the equations, then substitute the result into the other equation.

Point Form:

(

0

,

−

3

)

Equation Form:

x

=

0

,

y

=

−

3

Step-by-step explanation:

Answer:

x=0 y=3

Step-by-step explanation:

3(0) + 5(3) = 15

0 + 15 = 15

15=15